Does a compound with high molar absorbtivity have a higher or lower limit of detection than a compound with low molar absorbtivity?.

We have that  the the physical properties we use to classify metals are  Reactivity, Smell, and Density

Metals

Metals are materials that are higher conductors of heat and electricity the have free talent electrons that aids in conductivity

Nonmetals

These are materials that have a low conductivity of heat and electricity

Metalloids

These are the material that are found baring metal and non-metal properties mostly used as semi conductor

Generally,  

Metals,Non Metals and Metalloids are classified on the basis of their chemical properties.

Therefore

Reactivity, Smell, and Density are the the physical properties we use to classify metals

In conclusion

Reactivity, Smell, and Density are the the physical properties we use to classify metals

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Answer:

If half-life is 2.7 days then 8.1 days is three half-lives. 12.5%, or 12.5g, of AU-198 would remain.

Explanation:

Answer:Question

Select the correct answer. Sami was blowing soap bubbles in his room where the temperature was 23 °C and the pressure was constant. He blew a soup bubble of volume 45 mL. The bubble suddenly escaped from the window where the temperature outside was 12 °C. Explain what will happen to the soap bubble? The volume of the soap bubble will increase to 46.73 mL. The volume of the soap bubble will increase to 86.25 mL. The volume of the soap bubble will decrease to 23.47 mL. The volume of the soap bubble will decrease to 43.33 mL.​

Explanation:

Question

Select the correct answer. Sami was blowing soap bubbles in his room where the temperature was 23 °C and the pressure was constant. He blew a soup bubble of volume 45 mL. The bubble suddenly escaped from the window where the temperature outside was 12 °C. Explain what will happen to the soap bubble? The volume of the soap bubble will increase to 46.73 mL. The volume of the soap bubble will increase to 86.25 mL. The volume of the soap bubble will decrease to 23.47 mL. The volume of the soap bubble will decrease to 43.33 mL.​

Answer:

110.21 g/mol

............................

Answer:

110.22 g in 2.75 moles of calcium

Explanation:

to convert moles to grams

moles (g/mol)

2.75 mol Ca (40.08 (atomic weight) g Ca/1 mol Ca)= 110.22

The percent yield of Mg(ClO3)2 is 90.4%. Chemistry judges the effectiveness of a chemical process using percent yield.

The real yield is calculated as the theoretical yield divided by the theoretical yield multiplied by 100. Several factors, which will be covered in later chapters of the course, can cause a chemical reaction's actual yield to be lower than its theoretical yield.

2 Mg(NO3)2 + Na2ClO3 → 2 Mg(ClO3)2 + 2 NaNO3

The molar mass of Mg(ClO3)2 is:

Mg(ClO3)2 = 1 x Mg + 2 x Cl + 6 x O

Mg(ClO3)2 = 24.31 g/mol + 2(35.45 g/mol) + 6(16.00 g/mol)

Mg(ClO3)2 = 223.21 g/mol

The number of moles of Mg(NO3)2 can be calculated using its molar mass:

moles of Mg(NO3)2 = mass / molar mass

moles of Mg(NO3)2 = 5.00 g / 148.31 g/mol

moles of Mg(NO3)2 = 0.0337 mol

So, the theoretical yield of Mg(ClO3)2 can be calculated as:

theoretical yield of Mg(ClO3)2 = moles of Mg(NO3)2 x (2 moles Mg(ClO3)2 / 2 moles Mg(NO3)2) x molar mass of Mg(ClO3)2

theoretical yield of Mg(ClO3)2 = 0.0337 mol x (2/2) x 223.21 g/mol

theoretical yield of Mg(ClO3)2 = 7.52 g

If the actual yield of Mg(ClO3)2 obtained in the laboratory is 6.80 g,

percent yield = actual yield / theoretical yield x 100%

percent yield = 6.80 g / 7.52 g x 100%

percent yield = 90.4%

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NaHCO3(s) + HC2H3O2(aq) → CO2(g) + H2O(l) + NaC2H3O2(aq)

This equation represents the reaction of baking soda (sodium bicarbonate) with vinegar (acetic acid) to generate carbon dioxide gas, water, and sodium acetate.

The balanced equation for the reaction of NaHCO3(s) with HC2H3O2(aq) including phase symbols is

NaHCO3(s) + HC2H3O2(aq) → CO2(g) + H2O(l) + NaC2H3O2(aq)

Baking soda, also known as sodium bicarbonate, is a white, crystalline powder with the chemical formula NaHCO3. It is an alkaline substance that neutralizes acids.

Vinegar is mostly composed of acetic acid, HC2H3O2, which is a weak acid. Vinegar has a sour flavor and a strong smell due to the presence of acetic acid.

NaHCO3(s) + HC2H3O2(aq) → CO2(g) + H2O(l) + NaC2H3O2(aq)  This equation represents the reaction of baking soda (sodium bicarbonate) with vinegar (acetic acid) to generate carbon dioxide gas, water, and sodium acetate. When the baking soda and vinegar are combined, a chemical reaction occurs, causing carbon dioxide gas bubbles to form. This is due to the reaction between the acid and base in the mixture, which generates carbon dioxide gas as a byproduct. This reaction is commonly used in baking as a leavening agent to make cakes, muffins, and other baked goods rise.

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Answer:

neon

Explanation:

it comes in different colours

Answer:

3.07g of NaCl are present in the solution

Explanation:

A 1.05 M NaCl solution means you have 1.05 moles of NaCl per liter of solution. In 50.0mL = 0.0500L you will have:

0.0500L * (1.05mol / L) = 0.0525 moles of NaCl.

To convert these moles to grams you must use molar mass of the compound (Molar mass NaCl: 58.44g/mol). In 0.0525 moles of NaCl you will have:

0.0525mol * (58.44g / mol) =

Answer:

The atomic radius (r) of an atom can be defined as one half the distance (d) between two nuclei in a diatomic molecule. Atomic radii have been measured for elements. The units for atomic radii are picometers, equal to 10−12 meters

Answer:

solute and solvent

Explanation:

Answer:

If you take 4 apples and divide them by 2 there will be 2 apples in each set so if you add both sets of apples which is 2+2 there would be 4 apples

Approximately 0.3306 Faradays are needed to deposit 10.5g of copper onto the electrode surface from a solution of Cu2+.

To calculate the number of Faradays needed to deposit 10.5g of copper onto the surface of an electrode from a solution of Cu2+, we need to consider the molar mass of copper and the charge of the copper ion.

1. Find the molar mass of copper (Cu) from the periodic table: 63.55 g/mol.
2. Determine the number of moles of copper using the equation:

moles = mass / molar mass.
moles = 10.5g / 63.55 g/mol

moles = 0.1653 mol.
3. Since the copper ion (Cu2+) has a 2+ charge, each mole of copper requires 2 Faradays to deposit.
4. Calculate the number of Faradays needed using the equation:

Faradays = moles x charge.
Faradays = 0.1653 mol x 2

Faradays = 0.3306 Faradays.

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Answer:

i think B

Explanation:

B b b b b b b b b b b b b b b b b b b b b b b b b b b  b b b b b b  bb bb b b b b b b b b b b

Answer:  A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen \((O_2)\) if it occupies 31.6 mL at \(91^{o}C\).

Explanation:

Given : Mass of oxygen = 0.023 g

Volume = 31.6 mL

Convert mL into L as follows.

\(1 mL = 0.001 L\\31.6 mL = 31.6 mL \times \frac{0.001 L}{1 mL}\\= 0.0316 L\)

Temperature = \(91^{o}C = (91 + 273) K = 364 K\)

As molar mass of \(O_2\) is 32 g/mol. Hence, the number of moles of \(O_2\) are calculated as follows.

\(No. of moles = \frac{mass}{molar mass}\\= \frac{0.023 g}{32 g/mol}\\= 0.00072 mol\)

Using the ideal gas equation calculate the pressure exerted by given gas as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the value into above formula as follows.

\(PV = nRT\\P \times 0.0316 L = 0.00072 mol \times 0.0821 L atm/mol K \times 364 K\\P = \frac{0.00072 mol \times 0.0821 L atm/mol K \times 364 K}{0.0316 L}\\= 0.681 atm\)

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen \((O_2)\) if it occupies 31.6 mL at \(91^{o}C\).

Activated carbon, also known as charcoal, is commonly used in recrystallization because it is highly porous and has a large surface area that can effectively trap impurities.

This makes it an excellent adsorbent for organic contaminants, residual solvents, and other unwanted substances in the recrystallization solution. The addition of activated carbon to the solution prior to recrystallization helps to purify the desired compound and improve the overall yield of the reaction. Additionally, activated carbon is a highly effective filter that can remove any discoloration, odors, or other impurities that may be present in the solution. By improving the purity of the recrystallization solution, activated carbon can help to ensure that the final product is of a higher quality and has more consistent properties.

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If the amount of \(CO_{2}\) in solution decreases, the concentration of \(H_{2}CO_{3}\) in the solution would also decrease.

Dissolved \(CO_{2}\) concentration drops as solution \(CO_{2}\) decreases. \(CO_{2}\) combines with water to generate carbonic acid (\(H_{2}CO_{3}\)), therefore less \(CO_{2}\) means less carbonic acid in the solution.

The equilibrium reaction between dissolved \(CO_{2}\) and carbonic acid is:

\(CO_{2}\) (g) + \(H_{2}O\) (l) = \(H_{2}CO_{3}\) (aq)

Le Chatelier's principle states that an equilibrium system will change to mitigate stress. A reduction in \(CO_{2}\) in solution stresses equilibrium. To reduce stress, the equilibrium will shift left, lowering carbonic acid (\(H_{2}CO_{3}\)) concentration.

Thus, \(H_{2}CO_{3}\) concentration decreases with \(CO_{2}\) concentration.

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The enthalpic term is favorable, while the entropic term is unfavorable for the formation of secondary structure motifs.

In the context of secondary structure motifs like α-helices or β-sheets, the enthalpic term refers to the energy changes associated with the formation of hydrogen bonds and other stabilizing interactions within the motif.

The enthalpic term is generally favorable for the formation of secondary structures since the establishment of these interactions contributes to the stability and structural integrity of the motif.

On the other hand, the entropic term relates to the changes in molecular freedom or disorder upon the formation of secondary structure motifs.

When a protein adopts a specific secondary structure, there is a reduction in conformational flexibility, resulting in a decrease in entropy.

This entropic term is typically unfavorable for the formation of secondary structures since it restricts the range of accessible conformations for the protein.

Overall, the enthalpic term, driven by favorable interactions, promotes the formation of secondary structure motifs, while the entropic term, driven by reduced conformational flexibility, poses an unfavorable contribution to the process.

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Answer:

here is where you can buy it

https://www.walmart.com/ip/Product-Of-Hunts-Tomato-Paste-Can-Count-1-Tomato-Paste-Grab-Varieties-Flavors/850453511?wmlspartner=wlpa&selectedSellerId=4648&&adid=22222222228000000000&wl0=&wl1=g&wl2=m&wl3=42423897272&wl4=aud-430887228898:pla-51320962143&wl5=9012391&wl6=&wl7=&wl8=&wl9=pla&wl10=115056687&wl11=online&wl12=850453511&veh=sem&gclid=Cj0KCQjw9ZGYBhCEARIsAEUXITUEOCgO6I5Xsg6DjNJSFFzf6pLMzFzhjW7WipqMInuuYo8EfjNoRAkaAp17EALw_wcB&gclsrc=aw.ds

False. The leveling effect refers to the tendency of strong acids to behave as weaker acids in highly polar solvents, such as water.

This effect is caused by the solvation of the proton in the solvent, which reduces its acidity. In the case of sulfuric acid, this effect can prevent the use of sulfuric acid as an acid in some cases, as it may not exhibit its full strength in highly polar solvents. However, it is still commonly used as an industrial strong acid due to its strong acidity and low cost. The leveling effect is a phenomenon observed in Nucleophilic Aromatic Substitution (S N Ar) reactions. It refers to the reduction in the reactivity of a strong electrophile, such as a strong acid, in highly polar solvents. The highly polar solvent can solvate the electrophile, reducing its acidity and reactivity.

In the case of sulfuric acid, the leveling effect can cause it to behave as a weaker acid in highly polar solvents, reducing its ability to function as a strong acid in some cases. However, despite the leveling effect, sulfuric acid is still widely used as an industrial strong acid due to its strong acidity, low cost, and versatility. In less polar solvents, the leveling effect is reduced, and sulfuric acid can exhibit its full strength as a strong acid.

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The pair of molecules described are enantiomers.

The pair of molecules described are enantiomers.

Enantiomers are stereoisomers that are non-superimposable mirror images of each other. In this case, the two cyclohexane molecules have the same connectivity of atoms (constitutional isomers) but differ in their spatial arrangement due to the presence of chiral centers.

In compound one, the equatorial chlorine on carbon 1 is replaced by an axial chlorine in compound two, and vice versa. The flip in the chair conformation results in the interchange of axial and equatorial positions for the chlorine atoms. This change in spatial arrangement creates a pair of enantiomers.

Enantiomers have identical physical and chemical properties in an achiral environment but differ in their interaction with chiral environments, such as with other chiral molecules or chiral catalysts.

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Answer:

The answer to the question is option D

Hydrogen iodide (HI)  is a diatomic molecule belonging to the hydrogen halide family. It exists as a colorless gas with a pungent odor at room temperature.

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The correct order of decreasing acid strength for the acids lactic acid (LA), oxalic acid (OA), and malic acid (MA) is option B: LA > MA > OA.

The acid strength of an acid is determined by its tendency to donate a proton (H+ ion). The pKa value is a measure of the acidity of an acid, with lower pKa values indicating stronger acids.

In this case, the given pKa values for lactic acid (LA), oxalic acid (OA), and malic acid (MA) are LA = 3.88, OA = 1.23, and MA = 3.40.

Comparing the pKa values, we see that OA has the lowest pKa value (1.23), indicating that it is the strongest acid among the three. LA has a higher pKa value (3.88), making it weaker than OA but stronger than MA. Finally, MA has the highest pKa value (3.40), making it the weakest acid among the three.

Therefore, the correct order of decreasing acid strength is LA > MA > OA, as stated in option B.

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Answer:

nitric acid + iron=iron+[nitric acid ] 2 hydrogen

The net ionic equation will be Fe → \(Fe^{2+}\).

The net ionic equation would be a chemical equation which only indicates the elements, compounds, as well as ions instantly involved in a chemical reaction.

The given chemical equation is:

HNO3+Fe → Fe(HNO3)2 +H2​

It can be written in term of ionic equation.

\(H^{+}\) + \(NO_{3}^{-}\)+Fe → \(Fe^{2+}\) + \(H^{+}\) + \(NO_{3}^{-}\)

Hydrogen ion and nitrate ion will be canceled each other.

Hence, the net ionic equation will be

Fe → \(Fe^{2+}\)

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The number of moles of FADH₂ required to produce a proton gradient is 0.17 mol. This can be calculated through the free energy and potential difference. Thus, the correct option is D.

There are 6.022 × 10²³ protons per mole of H⁺. Therefore, one mole of H⁺ contains 1 mole of protons.

The change in potential between FADH₂ and O₂ is: ΔE°' = E°'(O₂) - E°'(FADH₂)

ΔE°' = 0.81 - 0.10

ΔE°' = 0.71 V

ΔG for electron transfer from FADH₂ to O₂ is: ΔG°' = -nFΔE°'

where, n = number of electrons, F = Faraday's constant (96,500 J/V), and ΔE°' is the change in potential between the two half-cells.

We know that n = 2 (since FADH₂ transfers two electrons to O₂).

ΔG°' = -2 × (96,500) × (0.71)

ΔG°' = -137,860 J/mol

ΔG° = -nFΔΨ

where, n = number of protons, F = Faraday's constant (96,500 J/V), and ΔΨ is the change in potential across the membrane. We know that n = 1 (since we want to pump one mole of H⁺ across the membrane).

ΔΨ = ΔG°/(nF)

ΔΨ = (-137,860)/(1 × 96,500)

ΔΨ = -1.43 V

ΔG = ΔG° + RTlnQ

where, R = gas constant (8.31 J/molK), T = temperature in Kelvin (298 K), and Q = reaction quotient.

Since the reaction is at standard conditions, Q = 1 (since all the reactants and products are in their standard states).

ΔG = ΔG°

ΔG = -137,860 J/mol

ΔG = -137.86 kJ/mol

23.3 kJ/mol = n × (1.43 V)

n = 0.17

Therefore, 0.17 mol of FADH₂ is required.

Therefore, the correct option is D.

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Answer:

Well what are the numbers but ik that it ius 5

Explanation: