Do u know this? Answer if u do

Step-by-step explanation:

Variable n = number

7(n - 8) + 2 = 36

If the resistance is 0.1 ohm, the impressed voltage is e(t) = 5, and i(0) = 0. The current i(t) is 50t.

The equation of the circuit is given as;v = L di/dt + R iThe initial current is zero, and the capacitor has no charge. As a result, the total voltage is equal to the impressed voltage.

e(t) = L di/dt + R i

Differentiate both sides with respect to time.

t(e(t)) = d(L di/dt)/dt + d(R i)/dt

t(e(t)) = L d²i/dt² + R di/dt + i(dR/dt)

Substituting the given values,R = 0.1, L = 0.02

Therefore;e(t) = 0.02(d²i/dt²) + 0.1(di/dt)

The equation is a second-order linear homogeneous differential equation. The auxiliary equation is given by;0.02m² + 0.1m = 0m(0.02m + 0.1) = 0m = 0 or -5

Taking m = 0;

Let i(t) = A + Bt

Substituting in equation (1);

e(t) = 0.02(d²i/dt²) + 0.1(di/dt)0 = 0.02d²i/dt² + 0.1di/dt

Substituting i(t) = A + Bt0 = 0.02B0 + 0.1A5 = 0.1B0.1B = 5B = 50

Using the values of A and B, i(t) can be calculated as;i(t) = 50t

Hence, the current i(t) is 50t.

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Answer:

2 is great common factor in both

Answer:

is it radius or diameter?

Answer:

x^2+(4-1)x-4=0

x^2+4x-x-4=0

x(x+4)-1(x+4)=0

(x-1)(x+4)=0

either (x-1)=0                                   Or,(x+4)=0

x-1=0

x=0+1

x=1

x+4=0

x=0-4

x=-4

therefore x=-4,1

Step-by-step explanation:

The required solutions for x are x₁= 1 and x₁= -4, and we can write them from least to greatest as -4, 1.

A number or algebraic expression that evenly divides another number or expression—i.e., leaves no remainder—is referred to as a factor.

To solve for x in the quadratic equation x² + 3x - 4 = 0, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation (ax² + bx + c = 0).

In this case, a = 1, b = 3, and c = -4, so we have:

x = (-3 ± √(3² - 4(1)(-4))) / 2(1)

x = (-3 ± √(25)) / 2

x = (-3 ± 5) / 2

x₁ = (-3 + 5) / 2 = 1

x₂ = (-3 - 5) / 2 = -4

Therefore, the solutions for x are x₁= 1 and x₁= -4, and we can write them from least to greatest as -4, 1.

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Answer:

105 degrees

Step-by-step explanation:

You first add 5 and 7 which gives you 12. Then, since two supplementary angles add up to 180, you divide 180 by 12 which gives you 15. Next, since 7 is the larger of the two, multiply 7 by 15 giving you 105. To check your work, subtract 105 from 180 giving you 75. Next, put this as a fraction- 75/105 and simplify giving you 5/7 which can also be written as 5:7.

Answer:

I believe the answer is 161616

Answer:

202020 hours

Step-by-step explanation:

So, if it took Mabel 444 hrs. to edit a 333 min. video, then we need to link that up to 151515. Let's start by dividing 333 into 151515.

151515 / 333 = 455.

If that's the case, then it should take her x455 more hours to edit that longer video of 151515 min.

444 x 455 = 202020.

Hope this helps. (PS that's a long time, oh snap.)

A process is said to be out of control if proportion of defective lies outside the control limits. Since 8% and 7% are outside our upper control limit (UCL) So, 2 batches are defective.

Given that,

100-piece batches of canned soup are produced by Company X. They estimate that there are 2% faulty soup cans in circulation.

We have to find how many of the 3%, 8%, 1%, 2%, and 7% defective can percentages in the five batches fell beyond the higher or lower control limits for the percentage of defective soup cans in the batch.

We know that,

LCL= p-3√(p(1-p)/n)

=0.02-3√(0.02(1-0.02)/100)

=-0.022

Since probability can not be negative.

LCL=0

UCL= p-3√(p(1-p)/n)

=0.02-3√(0.02(1-0.02)/100)

=0.062

Therefore. A process is said to be out of control if proportion of defective lies outside the control limits. Since 8% and 7% are outside our upper control limit (UCL) So, 2 batches are defective.

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To find the commission and fees the insurance agent has earned, we need to first calculate the 3% commission from the $89,000 in sales. This is equal to $2,670. Next, we need to calculate the additional fees from the 8 home policies sold. This is equal to $128. Thus, the total commission and fees the agent has earned this month is $2,798 ($2,670 + $128).

This commission and fees amount is in addition to the base salary of $32,000. Thus, the total earned this month by the insurance agent is $34,798 ($32,000 + $2,798). This figure is obtained by adding the base salary and the commission and fees. Note that this figure does not include any bonuses or other incentives that the agent may receive.

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Dée Trader's rate of return on her investment in Internet Dreams, considering the share price decrease and the interest expense, is 8.5%.

Dée Trader purchased 300 shares of Internet Dreams at $40 per share, resulting in an initial investment of $12,000 (300 shares * $40). However, since she borrowed $4,000, her out-of-pocket investment is $8,000 ($12,000 - $4,000).

At the end of the year, the share price falls to $30 per share. The market value of her investment is now 300 shares * $30, which equals $9,000.

Now, let's calculate the interest expense on the borrowed amount. The interest rate is 8%, so the interest expense for the year is 8% of $4,000, which equals $320.

To determine the net profit or loss, we subtract the initial investment and the interest expense from the market value of the investment. In this case, the net profit is ($9,000 - $8,000) - $320, which equals $680.

Finally, we can calculate the rate of return by dividing the net profit by the initial investment and expressing it as a percentage. The rate of return is ($680 / $8,000) * 100, which equals 8.5%.

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0.955900 is the probability that one or more of the servers is operational.

To find the probability that one or more of the servers is operational, we can calculate the complement of the event that both servers fail, and then subtract it from 1.

Let's denote:

P(A) = probability of the first server failing = 0.21

P(B) = probability of the second server failing = 0.21

Since the failure of one server is independent of the other server, the probability of both servers failing can be calculated as the product of their individual failure probabilities:

P(A and B) = P(A) * P(B) = 0.21 * 0.21 = 0.0441

The complement of this event (at least one server is operational) is 1 - P(A and B). Therefore, the probability that one or more of the servers is operational is:

P(at least one server operational) = 1 - P(A and B) = 1 - 0.0441 = 0.9559

Rounded to 6 decimal places, the probability is approximately 0.955900.

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We need to find the area. So we multiply the dimensions.

3x1/2=1.5

1.5x4 1/2=6.75

Decimal was my go-to so we need to convert back to a fraction.

6.75= 6 3/4

So the answer is B.

---

hope it helps

The missing premise is "all dogs are non-cats." Therefore, the argument is true.

The given information and analyze the argument step-by-step.

1. Some non-poodles are not non-cats: This statement means that there are some animals that are not poodles and are also cats.

2. No cats are dogs: This statement means that there is no overlap between cats and dogs.

Now, let's try to determine if "some poodles are dogs" can be concluded from these premises:
Since no cats are dogs, it doesn't matter whether some non-poodles are not non-cats. Poodles are a breed of dog, so it's already a fact that poodles are dogs.

So, the answer is True: some poodles are dogs.

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To prove that T is surjective, we need to show that for every v in V, there exists a w in V such that T(w) = v.

Let's start by considering an arbitrary v in V. Since V = P3​(R), we can write v as a polynomial \(v = a3x^3 + a2x^2 + a1x + a0,\) where a3, a2, a1, and a0 are real numbers.

Now, we need to find a w in V such that T(w) = v.

Let's assume\(w = b2x^2 + b1x + b0\), where b2, b1, and b0 are real numbers.

We can now compute T(w):
\(T(w) = 3D^2(w) + 2I(w)      = 3D^2(b2x^2 + b1x + b0) + 2(b2x^2 + b1x + b0)      = 3(2b2) + 2(b2x^2 + b1x + b0)      = 6b2 + 2b2x^2 + 2b1x + 2b0\)

To make T(w) = v, we need to equate the coefficients of corresponding powers of x in both expressions. Comparing the coefficients, we get:
\(2b2 = a32b1 = a22b0 = a16b2 = a0\)

Now, we have a system of equations that we can solve to find the values of b2, b1, and b0.

Once we have found the values of b2, b1, and b0, we can substitute them back into w = b2x^2 + b1x + b0 to find the specific w that satisfies T(w) = v.

Since we have shown that for every v in V, there exists a w in V such that T(w) = v, we have proven that T is surjective.

To show that the differential equation \(3p′′ + 2p = q\)as a solution for every q in P3​(R), we can use the fact that T is surjective.

Let p be the solution to the differential equation, and let v = p′′. We can then rewrite the differential equation as \(3v + 2p = q.\)

Since T is surjective, for every q in P3​(R), there exists a w in V such that T(w) = q. \

Let \(w = 3v + 2p.\)

Now, we can apply T to both sides of the equation:
\(T(w) = T(3v + 2p)      = 3T(v) + 2T(p)      = 3v + 2p\)
Therefore, we have shown that the differential equation 3p′′ + 2p = q has a solution for every q in P3​(R).

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Answer:

Step-by-step explanation:

Answer:

What image?

Step-by-step explanation:

Thanks? :)

Lerchs-Grossman algorithm is a pit optimization software that helps in the determination of the most profitable final pit outline. The section of a copper porphyry ore body given has a cut-off grade of 0.45% Cu. Each block has dimensions of 16m x 16m x 16m (HxLxW).

The cost of mining a block of waste is $50, and the value of a block of ore is approximated to be $100 x (grade expressed in %). Firstly, we have to calculate the net present value (NPV) for all the blocks that are above the cut-off grade. NPV is calculated using the formula given below:

NPV = ((grade*100)*100)-50

Here, the cost of mining a block of waste is $50 and the value of a block of ore is approximated to be $100 x (grade expressed in %).

1. Firstly, the net present value (NPV) of each block above the cutoff grade is calculated.2. The blocks are then sorted in descending order of their NPVs.

3. Next, the algorithm calculates the limits of the pit at a sequence of levels, starting with the block of highest NPV.

4. It is assumed that the pit will extend downwards through the blocks from the highest NPV downwards.

5. If the pit reaches the edge of the ore body before reaching a certain level, it is truncated and the lower level is tried.

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Using the volume of the rectangular prisms, it is found that there is 1.5 times more sunscreen in Bottle B than in Bottle A.

The volume of a rectangular prism of dimensions l, w and h is given by:

V = lwh.

For bottle A, we have that, in inches, l = 1, w = 2, h = 6, hence the volume in cubic inches is given by:

Va = 1 x 2 x 6 = 12 in³.

For bottle B, we have that, in inches, l = 1.5, w = 3, h = 4, hence the volume in cubic inches is given by:

Vb = 1.5 x 3 x 4 = 18 in³.

The ratio between the volumes is given by:

r = Vb/Va = 18/12 = 1.5.

Hence, there is 1.5 times more sunscreen in Bottle B than in Bottle A.

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Answer:

Flipping a coin to determine which participants in a study are in the control group versus the treatment group is a form of: blinding.

Step-by-step explanation:

Answer:

  119 cm²

Step-by-step explanation:

The area of a composite shape can be found by dividing it into shapes whose area formulas you know.

__

Here, the shape can be divided into 3 rectangles by extending the vertical lines through the figure. Left to right, those rectangles are ...

  2 wide × 17 hign ⇒ area = (2 cm)(17 cm) = 34 cm²

  10 wide × 7 high ⇒ area = (10 cm)(7 cm) = 70 cm²

  5 wide × 3 high ⇒ area = (5 cm)(3 cm) = 15 cm²

Then the total area is ...

  (34 +70 +15) cm² = 119 cm²

The ratio of the number of female attendants to the number of male attendants is 21/17

let

900 = 1200x + 800y / (x + y)

900x + 900y = 1200x + 800y

900x + 1200x = 800y + 900y

2100x = 1700y

x : y = 2100 / 1700

x : y = 21 ; 17

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You write f (-2) = 3 as (-2, 3) and f (5) = 7 as (5, 7).

The answer for the graph is \(\mathbf{\frac{4}{3}}\textbf{\textit{x}}\mathbf{+\frac{1}{3}}\).

Answer:

250 hamburgers were sold on monday.

Step-by-step explanation:

were going to subtract 70 from 500 leaving us with 500 and then divide it by 2 (hamburger and cheeseburger). so we have 250 now. then were going to add 70 to 250 and we'd get 320. so there were 320 cheeseburgers sold on monday and 250 hamburgers sold on monday. to check our work, 250+320=570. 570-320=250.

Answer:

215 hamburgers

Step-by-step explanation:

First, you need to find out what 570 divided by 2 is. It's 285 (570/2=285)

Next, you need to add 70 to 285. It's 355 (285+70=355)

Lastly, you need to subtract 355 from 570. It's 215 (570-355=215)

Thus, the were 215 hamburgers sold on Monday.

Hope this is right and helps!

Answer:

B

Step-by-step explanation:

Answer:

161ft^2 is answer

Step-by-step explanation:

area of rectangle = l ×b

=7ft ×23ft

=161ft^2

Franco can read approximately 1.875 chapters of his history book in 1 hour, assuming his reading rate remains constant.

Franco read 3/8 of a chapter in 1/5 of an hour. To find out how many chapters he can read in 1 hour, we need to first determine his rate of reading.

To do this, we can set up a proportion:

3/8 of a chapter = x chapters
1/5 of an hour = 1 hour

Cross-multiplying, we get:

3/8 * 1 hour = x * 1/5

Simplifying:

3/8 = x/5

Cross-multiplying again:

15/8 = x

So Franco can read 15/8 or 1 7/8 chapters in 1 hour.

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Triangles that are similar are A and C because they have equal angles and the sides have the same scale dimensions.

To identify equal triangles we must look at the dimensions of the triangles, especially their angles and the lengths of their sides. Based on the above, we can infer that the triangles that are similar are triangle A and triangle C.

This is because both triangles have angles of 23°, 67°, and 90°. Additionally, a scale is stored between the length of its sides.

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1) Since R is reflexive, symmetric, and transitive, it is an equivalence relation. 2) here are a total of 8 distinct equivalence classes, which correspond to the 8 possible truth tables for statement forms in three variables.

To prove that the relation R is an equivalence relation, we need to show that it is reflexive, symmetric, and transitive.

1) Reflexive: To show that R is reflexive, we need to prove that every statement form in A has the same truth table as itself. This is true because every statement form is logically equivalent to itself. Therefore, P R P for all P in A.

2) Symmetric: To show that R is symmetric, we need to prove that if P R Q, then Q R P. This is true because if P and Q have the same truth table, then Q and P must also have the same truth table. Therefore, if P R Q, then Q R P for all P and Q in A.

3) Transitive: To show that R is transitive, we need to prove that if P R Q and Q R S, then P R S. This is true because if P and Q have the same truth table and Q and S have the same truth table, then P and S must also have the same truth table. Therefore, if P R Q and Q R S, then P R S for all P, Q, and S in A.

Since R is reflexive, symmetric, and transitive, it is an equivalence relation.

2) The distinct equivalence classes of R are sets of statement forms that have the same truth table. For example, one equivalence class contains all statement forms that are logically equivalent to p ∧ q ∧ r. Another equivalence class contains all statement forms that are logically equivalent to p ∨ q ∨ r. There are a total of 8 distinct equivalence classes, which correspond to the 8 possible truth tables for statement forms in three variables.

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Answer:

Show a photo

Step-by-step explanation:

Answer:

322

Step-by-step explanation:

area of a rhombus is the diaganol* diaganol ÷ 2 = 23x28/2 =322 in ^2

Answer:

22, 25, 28

Step-by-step explanation:

10 + 3 = 13

13 + 3 = 16

16 + 3 = 19

19 + 3 = 22

22 + 3 = 25

25 + 3 = 28.

all numbers go up by three points