displacement vector points due east and has a magnitude of 2.00 km. displacement vector points due north and has a magnitude of 3.75 km. displacement vector points due west and has a magnitude of 2.50 km. displacement vector points due south and has a magnitude of 3.00 km. find the magnitude and direction (relative to due west) of the resultant vector

The correct statement of Newton's Second Law is: An object's acceleration is inversely proportional to its mass and proportional to the net force acting on it.

Newton's Second Law of Motion states that the force acting on an object is directly proportional to the mass of the object and its acceleration. In other words, the greater the force applied to an object, the greater its acceleration, and the greater the object's mass, the less it will accelerate for a given force.

This law is often expressed mathematically as F = ma, where F is the force applied to an object, m is the object's mass, and a is its acceleration.

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The magnification is approximately 0.1047 or 0.105, given an object 1.60 cm high is held 3.00 cm from a person's cornea, and its reflected image is measured to be 0.167 cm high.

The magnification is the ratio of the height of the image to the height of the object. In this case, the height of the object is 1.60 cm and the height of the image is 0.167 cm. Therefore, the magnification can be calculated as:

Magnification = height of image / height of object
Magnification = 0.167 cm / 1.60 cm

Simplifying this fraction gives a magnification of approximately 0.1047 or 0.105, to three significant figures.

This means that the image appears smaller than the actual object, as the magnification is less than 1. In other words, the image is reduced in size when it is reflected off the cornea.

It is worth noting that this question relates to the field of optics, which involves the study of light and how it interacts with different materials. The measurement of the reflected image in this question is an example of how light can be reflected off surfaces and used to create images, which is a key concept in optics.

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Hope you could understand.

If you have any query, feel free to ask.

Answer:

440

Explanation:

1 mile =1760 yards

0.25 miles =?

\( \frac{0.25 \times 1760}{1} \)

=440 yards

the self-inductance of the given inductor is 0.4455 H.

Given data:

The current in an inductor is changing at 110 A/s

Inductor emf is 49 V

We know that the self-inductance of an inductor can be calculated using the formula:

Self-inductance, L = ε/I

where ε is the induced emf and I is the current in the inductor.

Therefore,Substitute the given values in the above equation:

L = ε/IL = 49/110L = 0.4455 H

Thus, the self-inductance of the given inductor is 0.4455 H.

The unit of inductance is Henry (H).Answer: L = 0.4455 H.

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The elapsed time when the particle returns to the origin is determined from the ratio of initial velocity and acceleration of the particle.

The time of motion of the particle is calculated by applying Newton's second law of motion.

F = ma

F = m(v)/t

where;

a = v - u/t

v = u + at

when the particle returns to the origin, direction of u, = negative.

final velocity = 0

0 = -u + at

at = u

t = u/a

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The radius of the cylindrical barrel is 0.78 m.

The circular area of the cylindrical barrel is calculated as follows;

P = F/A

A = F/P

where;

A = mg/P

A = (50 x 9.8) / (260)

A = 1.885 m²

A = πr²

r² = A/π

r = √(A/π)

r = √(1.885/π)

r = 0.78 m

Thus, the radius of the cylindrical barrel is 0.78 m.

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The net force on the sled is 400 N.

The net force on the sled is the sum of all the forces acting on the sled. In this case, the only forces acting on the sled are the horizontal force of 200 N applied by the athlete and the force of friction acting on the sled.

The force of friction is given by the equation:

F_friction = μ × F_normal

where F_friction is the force of friction, μ is the coefficient of friction between the sled and the surface it is on, and F_normal is the normal force acting on the sled.

The normal force is the force exerted on an object by a surface that is perpendicular to the surface. For an object at rest, the normal force is equal to the weight of the object. In this case, the weight of the sled is 50 kg × 9.8 m/s² = 490 N.

Plugging the values for the coefficient of friction, the normal force, and the applied force into the equation gives us the following:

F_friction = μ × F_normal = μ × 490 N = 200 N

The net force on the sled is the sum of the horizontal force applied by the athlete and the force of friction:

F_net = F_horizontal + F_friction = 200 N + 200 N = 400 N

Therefore, the net force on the sled is 400 N.

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Answer:

\(\lambda=25\times 10^6\ m\)

Explanation:

Given that,

The frequency of the light wave, f = 12 Hz

We need to its wavelength. The wavelength of the wave can be calculated as follows :

\(\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{12}\\\\\lambda=25\times 10^6\ m\)

So, the wavelength of the light wave is equal to \(25\times 10^6\ m\).

Answer:

180 [J].

Explanation:

1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;

2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;

3) then the required work [W]:

W=mg*(h₂-h₁)=30*6=180 [J].

Answer:

See below

Explanation:

Force X distance = work

 200 N * 240 m = 48 000 N-m = 48 000 j

F = ma

200 = 800 a

a = 1/4 m/s^2

d = v t  + 1/2 a t^2

12 m/s t  + 1/2  1/4 m/s^2  t^2 = 240

                shows t = 17 sec  (via Quadratic Formula)

final velocity = 12 + at = 12 + 1/4(17) = 16.26 m/s

We can visually understand the changes in these parameters as water flows from the upstream reservoir to the downstream reservoir.

To determine the slope type, we must compare the channel slope (S) with the critical slope (Sc). If S < Sc, it is a mild slope; if S = Sc, it is a critical slope; if S > Sc, it is a steep slope. By calculating the critical slope using Manning's roughness coefficient (n) and the flow velocity, we can determine the slope type. To sketch the flow profile variation along the channel, we need to consider the depth of flow at various locations. Starting from the vena-contractor, we can calculate the flow depth using the flow rate and channel properties, such as cross-sectional area and hydraulic radius. By tabulating the flow depth at each changing location, we can sketch the flow profile variation. For the hydraulics jump, we can calculate the specific energy (Es) and the Froude number (F) at each flow-changing location. The specific energy is calculated using the flow depth, velocity, and gravitational acceleration. The Froude number is calculated by dividing the flow velocity by the square root of the gravitational acceleration times the flow depth. By tabulating the values of Es and F at each flow-changing location, we can analyze the behavior of the hydraulics jump, additionally by plotting the variation of flow depth, Es, and F along the channel.

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If carotenoids were capable of energizing electrons for photosynthesis in the same manner as chlorophyll, they would best perform photosynthesis in wavelengths of light greater than 700 nm. Option D is the answer.

Carotenoids are pigments found in photosynthetic organisms that are involved in absorbing light energy and protecting the photosynthetic apparatus from damage by excess light.

However, unlike chlorophyll, carotenoids cannot directly energize electrons for photosynthesis. They can, however, transfer their absorbed energy to chlorophyll molecules, which can then energize electrons.

The absorption spectra of carotenoids show that they absorb light in the blue and green regions of the visible spectrum (450-550 nm) as well as in the ultraviolet region (less than 400 nm).

Therefore, they would not perform photosynthesis in wavelengths less than 450 nm (option A) or in the narrow range of 450-500 nm (option B). Chlorophyll, on the other hand, absorbs light in the red and blue regions of the spectrum (approximately 400-700 nm), making option C a possible answer.

However, carotenoids are not capable of directly energizing electrons, so option D, which includes wavelengths outside the range of chlorophyll absorption, is the most accurate answer.


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Answer:

1.25m/s

Explanation:

Average speed = distance / time elapsed

= 100/80

=1.25m/s

The earth tilt about 23 degrees which leads to the formation of seasons on earth.

This is tilted at 23 degrees from the vertical. The northern hemisphere is in the winter season.

This is the path as the earth revolves around the sun. It takes 1 year to complete this path.

This is the path as the earth rotates around its.

So we can conclude that the earth tilt about 23 degrees which leads to the formation of seasons on earth.

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According to the given data  the frequency of the pendulum is 0.595 Hz.

Frequency is defined as the rate of changes in current direction per second. It is given in hertz (Hz), an internationally recognised unit of measurement. One cycle per second is equal to one hertz. Cycles per second are represented by the unit hertz (Hz). A cycle is a full cycle of an opposing current or voltage wave.

The time rate of change observed in cyclical and periodic phenomena, such as mechanical motion, audio signals (sound), radio waves, and light, is specified by the frequency, an essential parameter in science and engineering.

Calculate the period of oscillations formula is

T = 2π√(L/g)

T = 2 * π * √(0.7/9.80665)

T= 1.678 s

Then the frequency as the reciprocal of the period

f = 1/T

f =1/1.678

f = 0.595 Hz.

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voltage (potential difference) always drops across a resistor along the direction of current.

In a circuit, voltage (potential difference) always drops- across a resistor along the direction of current.Group of answer choicesremains the sameeither drops or increases, depends on the value of resistanceincreasesdrops

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Answer:

speed is increasing.

this is because the graph has a positive slope (due to it going up ), if it were decreasing, the graph would be going down

The speed of the object in the graph over the four seconds is increasing.

Speed is distance travelled by an object in unit time. A distance-time graph, also known as a distance-travel graph, is a graph that shows how an object's distance changes over time.A speed-time graph, often known as a speed curve, is a graph that shows how an object's speed changes over time.

Examining the speed-time and distance-time graphs for an entity that is at rest when time is zero and does not change speed will be our first step. The ensuing figure given in the question.

Given that in the question the graph has a positive slope as the line in graph is going up , if it were decreasing, the graph would be going down from this we conclude that speed of the object in the graph over the four seconds is increasing.

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A powerful motorcycle can accelerate from rest to 26.8 m/s in only 3.90s.  It will go 52.3 m in that time.

According to the Question,

It is given that,

Initial velocity of motorcycle is zero and,

Final velocity is 26.8m/s and,

it's acceleration during a time of 3.90s

Now, The end position is equal to the initial position plus the average velocity times time, according to the formula for average velocity that we plug in here.

In other words, the distance travelled will be equal to 0 meters (the initial position), plus 0 meters per second (the initial velocity), plus 26.8 meters per second (the final velocity), divided by 2 times 3.90 seconds, or 52.3 meters.

Therefore,0+0+26.8/2x3.90=52.3m

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The force of the SUV's bumper on the truck's bumper would be 18,000 N.

The bumper on the truck is pushing the bumper of the SUV, which is acting as a reaction force back on the truck's bumper. According to Newton's Third Law, if the truck applies a forward force to the SUV, the SUV will apply an equal and opposite force back on the truck. Therefore, at this acceleration the force of the SUV's bumper on the truck's bumper would be the same as the forward force applied by the truck, which is 18,000 N.This is because the two vehicles are in contact with each other, so the force applied by one is equal and opposite to the force applied by the other.

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Answer:

Sound waves have a low speed of 330 m/s

Sound waves are mechanical waves

Electromagnetic waves have a greater speed of 3.0×10^8 m/s

Electromagnetic waves are due to disturbance of electromagnetic objects.

12 × sin50 = 9.192533317........

Answer:

Explanation:

This is a recoil problem, which is just another application of the Law of Momentum Conservation. The equation for us is:

\([m_av_a+m_ev_e]_b=[m_av_a+m_ev_e]_a\) which, in words, is

The momentum of the astronaut plus the momentum of the piece of equipment before the equipment is thrown has to be equal to the momentum of all that same stuff after the equipment is thrown. Filling in:

\([(90.0)(0)+(.50)(0)]_b=[(90.0)(v)+(.50)(-4.0)]_a\)

Obviously, on the left side of the equation, nothing is moving so the whole left side equals 0. Doing the math on the right and paying specific attention to the sig fig's here (notice, I added a 0 after the 4 in the velocity value so our sig fig's are 2 instead of just 1. 1 is useless in most applications).

0 = 90.0v - 2.0 and

2.0 = 90.0v so

v = .022 m/s This is the rate at which he is moving TOWARDS the ship (negative was moving away from the ship, as indicated by the - in the problem). Now we can use the d = rt equation to find out how long this process will take him if he wants to reach his ship before he dies.

12 = .022t and

t = 550 seconds, which is the same thing as 9.2 minutes

To convert the thrust force from pounds-force (lbf) to kilonewtons (kN), we can use the conversion factor of 4.44822 N = 1 lbf and 1000 N = 1 kN. First, let's convert pounds-force (lbf) to newtons (N):
318,000 lbf * 4.44822 N/lbf = 1,414,782.36 N
Next, we can convert newtons (N) to kilonewtons (kN):
1,414,782.36 N / 1000 N/kN = 1414.78 kN
Therefore, the equivalent force in kilonewtons (kN) is approximately 1414.78 kN.

To convert the thrust force of a rocket engine from pounds-force (lbf) to kilonewtons (kN), you can use the following conversion factor: 1 lbf = 0.00444822 kN. Given the thrust force of 318,000 lbf, you can calculate the equivalent force in kilonewtons as follows: Equivalent Force (kN) = 318,000 lbf × 0.00444822 kN/lbf = 1,414.73 kN

So, the equivalent force in kilonewtons for a rocket engine producing a thrust force of 318,000 lbf is approximately 1,414.73 kN.

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The duration, frequency, and intensity are increased in an exercise program during the progression phase.

A program's progression phase is a key time for developing strength, flexibility, and endurance. In order to keep the body challenged and encourage new adaptations, the duration, frequency, and intensity of the workouts are increased during this phase. People can prevent hitting a plateau and advance towards their fitness objectives by progressively increasing the demands placed on their bodies. To prevent injury or overtraining, it's crucial to approach this phase cautiously and to gradually and carefully increase these factors. An effective progression plan can assist people in achieving their fitness objectives, whether they are to increase their overall health and wellness, lose weight, or gain muscle.
In an exercise program, duration, frequency, and intensity are typically increased during the "progression" phase. This phase focuses on gradually increasing the workload to improve physical fitness and adapt to the exercise routine.

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Answer:

Metals

Explanation:

Usually, electrical conductors have loosely bound electrons. Materials that conduct heat are thermal conductors. Metals typically conduct both heat and electricity.

The laser pulse with a wavelength of 533 nm containing 1.83 mJ of energy has 3.44 x 10^18 photons.

The energy of a photon is given by E=hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Rearranging this formula, we get λ=hc/E.

Substituting the given values, we get λ=3.31 x 10^-19 J s x 3 x 10^8 m/s / 1.83 x 10^-3 J = 5.46 x 10^-7 m or 533 nm.  

Now, we can calculate the number of photons by dividing the total energy of the laser pulse by the energy of a single photon.

N= E/Ephoton= 1.83 x 10^-3 J / (hc/λ) = 3.44 x 10^18 photons.

Finally, we round off the answer to three significant figures, which gives us the answer of 3.44 x 10^18 photons.

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