Disk a has a mass of 6 kg and an initial angular velocity of 360 rpm clockwise; disk b has a mass of 3 kg and is initially at rest. the disks are brought together by applying a horizontal force of magnitude 20 n to the axle of disk a. knowing that μk = 0.15 between the disks and neglecting bearing friction, determine (a) the angular acceleration of each disk, (b) the final angular velocity of each disk
Answers
(a) The angular acceleration of disk A is approximately -4.76 rad/s² (clockwise) and the angular acceleration of disk B is approximately 9.52 rad/s² (clockwise).
(b) The final angular velocity of disk A is approximately -125.66 rad/min (clockwise) and the final angular velocity of disk B is approximately 251.33 rad/min (clockwise).
Determine how to find the angular acceleration and angular velocity also?To solve this problem, we can use the principles of rotational dynamics and Newton's laws of motion. We start by calculating the torque exerted on disk A due to the applied force.
The torque can be found using the equation τ = Fr, where F is the force applied and r is the radius of the disk. Since the force is applied at the axle, the radius is equal to half the diameter of the disk.
Thus, the torque on disk A is τ = 20 N * (0.5 m) = 10 Nm.
Next, we can calculate the moment of inertia of each disk using the formula I = 0.5 * m * r², where m is the mass of the disk and r is the radius. The moment of inertia of disk A is approximately 0.5 * 6 kg * (0.15 m)² = 0.0675 kgm², and the moment of inertia of disk B is approximately 0.5 * 3 kg * (0.15 m)² = 0.03375 kgm².
Using Newton's second law for rotation, τ = Iα, where α is the angular acceleration, we can calculate the angular acceleration of each disk. For disk A, α = τ / I = 10 Nm / 0.0675 kgm² ≈ -4.76 rad/s² (clockwise).
For disk B, since it is initially at rest, the torque exerted by the friction force is μk * N * r, where μk is the coefficient of kinetic friction, N is the normal force, and r is the radius.
The normal force N is equal to the weight of the disk, N = mg, where g is the acceleration due to gravity.
Thus, the torque on disk B is τ = μk * m * g * r = 0.15 * 3 kg * 9.8 m/s² * 0.15 m = 0.2055 Nm.
The angular acceleration of disk B is α = τ / I = 0.2055 Nm / 0.03375 kgm² ≈ 9.52 rad/s² (clockwise).
Finally, we can calculate the final angular velocities of the disks using the equation ω = ω₀ + αt, where ω is the final angular velocity, ω₀ is the initial angular velocity, α is the angular acceleration, and t is the time.
Since the time is not given, we assume that both disks reach their final angular velocities at the same time.
For disk A, ω = 360 rpm * (2π rad/1 min) + (-4.76 rad/s²) * t. For disk B, since it is initially at rest, ω = 0 + (9.52 rad/s²) * t. Solving for t and substituting it back into the equations, we can find the final angular velocities of the disks.
Disk A: ω = 360 rpm * (2π rad/1 min) + (-4.76 rad/s²) * [360 rpm * (2π rad/1 min) / (9.52 rad/s²)] ≈ -125.66 rad/min (clockwise).
To know more about acceleration, refer here:
https://brainly.com/question/2303856#
#SPJ4
Related Questions
7. A sprinter accelerates from rest to a velocity of 12 m/s in the first 6
seconds of the 100-meter dash.
What is the acceleration in the first 6 seconds?
b. How far does the sprinter travel during the first 6 seconds?
Answers
Answer: a) 36 m/s
B) 64 m
Explanation:
A) d= ½ (Vi+Vf)t
d= ½ (0+12)6
d= 36 m/s
B) 100 – 36 = 64
If a species experiences a helpful mutation, like camouflage, explain how that mutation would help the species to better survive and flourish. Again, be sure to explain how and why that mutation would be helpful.
Help me please I need it fast, I’ll give b if correct!!!
Links = reported
Wrong answer= report (depends if it’s a whole different answer)
Answers
Answer:
A helpful mutation like camoflage would immensely help a species survive and flourish. The reason being the appliances of such a mutation. Camoflage is one of the most apllicable of abilities. It can be used as a defense mechanism, to hide in plain sight, it can be used offensively to avoid being seen while hunting and it can even be used as a form of communication between the species. All of these appliances would greatly benefit the species and would most definitely help it survive and flourish.
use the worked example above to help you solve this problem. a typical jetliner lands at a speed of 143 mi/h and decelerates at the rate of (10.8 mi/h)/s. if the jetliner travels at a constant speed of 143 mi/h for 1.1 s after landing before applying the brakes, what is the total displacement of the jetliner between touchdown on the runway and coming to rest?
Answers
The displacement due to the constant speed and the displacement due to the deceleration gives a total displacement of 238.5 mi.
What is displacement?Displacement is the measurement of how far an object has moved from its initial position. It is commonly expressed in terms of distance and direction, and is often measured in terms of meters or kilometers. Displacement is a vector quantity, meaning it has both magnitude and direction.
The total displacement of the jetliner between touchdown and coming to rest can be calculated by adding the displacement due to the constant speed for 1.1 seconds and the displacement due to the deceleration over the same time period.
The displacement due to the constant speed of 143 mi/h for 1.1 s is found by multiplying the speed (143 mi/h) by the time (1.1 s) to get 159.3 mi.
The displacement due to the deceleration is found by calculating the average speed of the jetliner between touchdown and coming to rest, then multiplying this average speed by the time (1.1 s). The average speed of the jetliner is found by taking the difference between its initial speed (143 mi/h) and its final speed (0 mi/h) and dividing it by 2. This gives an average speed of 71.5 mi/h. Multiplying this average speed by the time (1.1 s) gives a displacement due to deceleration of 79.2 mi.
Adding the displacement due to the constant speed and the displacement due to the deceleration gives a total displacement of 238.5 mi.
To learn more about displacement
https://brainly.com/question/28370322
#SPJ4
explain why energy bonds for utilities tied to bakken shale oil are especially risky.
Answers
Energy bonds for utilities tied to Bakken shale oil are especially risky because of the volatile nature of the oil industry and because their oil is expensive to extract due to its geographic location.
The Bakken shale oil fields in North Dakota and Montana have been a major source of oil production in the United States, but the industry has seen a lot of ups and downs in recent years. This volatility can make it difficult for utilities to accurately predict their revenues and expenses, which can make it difficult to repay the bonds.
Additionally, the Bakken shale oil fields are subject to a number of environmental and regulatory risks, which can also impact the profitability of the utilities. As a result, energy bonds for utilities tied to Bakken shale oil are considered to be especially risky investments.
Learn more about shale oil at https://brainly.com/question/13689453
#SPJ11
Heyyy can someone help me plz
The mass of the hammer is 0.454 kg.
(i) Calculate the weight of the hammer.
Answers
Explanation:
W = mg
= (0.454 kg)(9.8 m/s^2)
= 4.45 N
Please help me........
Answers
Answer:
.
Explanation:
Answer:
the pelvice
Explanation:
A ball is thrown horizontally at a height of 1.6 metres above the ground, with initialspeed 14 m s^-1a)Find the time of flight of the ball, giving the answer as a fraction.b)Find the range of the ball.
Answers
Given:
The initial height of the ball, h=1.6 m
The initial speed of the ball, u=14 m/s
To find:
a) The time of flight of the ball.
b) The range of the ball.
Explanation:
As the ball is thrown horizontally, the ball will have no vertical component of the initial velocity. The velocity of the ball is completely horizontal.
Thus the vertical component of the initial velocity of the ball is u_y=0 m/s.
The horizontal component of the initial velocity of the ball is u_x=u=14 m/s.
a)
From the equation of motion,
\(h=u_yt+\frac{1}{2}gt^2\)Where g is the acceleration due to gravity and t is the time of flight of the ball.
On substituting the known values,
\(\begin{gathered} 1.6=0+\frac{1}{2}\times9.8\times t^2 \\ \implies t=\sqrt{\frac{2\times1.6}{9.8}} \\ =0.57\text{ s} \end{gathered}\)b)
The range of the ball is given by,
\(R=u_xt\)On substituting the known values,
\(\begin{gathered} R=14\times0.57 \\ =7.98\text{ m} \end{gathered}\)Final answer:
a) The time of flight of the ball is 0.57 s
b) The range of the ball is 7.98 m
Consider a long, uniformly charged, cylindrical insulator of Radius R with charge density 1.0uC/m^3. What is the magnitude of the electric field inside the insulator at a distance 1cm form the axis
Answers
Consider a long, uniformly charged, cylindrical insulator of Radius R with charge density 1.0uC/m^3. the magnitude of the electric field inside the insulator at a distance of 1 cm from the axis is approximately 1.13 x 10^10 N/C.
To determine the magnitude of the electric field inside the uniformly charged cylindrical insulator at a distance of 1 cm from the axis, we can apply Gauss's law. Gauss's law states that the electric field through a closed surface is directly proportional to the total charge enclosed by that surface. In this case, we consider a cylindrical Gaussian surface with a radius of 1 cm and height L, centered on the axis of the cylinder. The charge enclosed within this Gaussian surface is the volume integral of the charge density multiplied by the volume of the Gaussian surface.
Since the charge density is given as 1.0 μC/m³, the charge enclosed can be calculated as Q = (1.0 μC/m³) * (π * (0.01 m)² * L). However, since the insulator is uniformly charged, the electric field is radial and its magnitude is constant throughout the Gaussian surface. By applying Gauss's law, we find that the magnitude of the electric field (E) inside the insulator is given by E = Q / (ε₀ * A), where ε₀ is the permittivity of free space and A is the area of the Gaussian surface. In this case, A = π * (0.01 m)².
Therefore, the magnitude of the electric field inside the insulator at a distance of 1 cm from the axis is E = Q / (ε₀ * π * (0.01 m)²).
To calculate the magnitude of the electric field inside the uniformly charged cylindrical insulator at a distance of 1 cm from the axis, we need the value of the permittivity of free space (ε₀). The value of ε₀ is approximately 8.854 x 10^(-12) C²/(N·m²).
Let's assume the height of the cylinder is L = 1 m for simplicity. We can now calculate the charge enclosed within the Gaussian surface:
Q = (1.0 μC/m³) * (π * (0.01 m)² * 1 m)
Q = 1.0 μC * π * 0.0001 m³
Using this charge value, we can determine the magnitude of the electric field:
E = Q / (ε₀ * π * (0.01 m)²)
E = (1.0 μC * π * 0.0001 m³) / (8.854 x 10^(-12) C²/(N·m²) * π * (0.01 m)²)
E = (1.0 μC * 0.0001 m³) / (8.854 x 10^(-12) C²/N)
E = 1.13 x 10^10 N/C
Therefore, the magnitude of the electric field inside the insulator at a distance of 1 cm from the axis is approximately 1.13 x 10^10 N/C.
Learn more about Gauss's law here:
https://brainly.com/question/30490908
#SPJ11
Physical units in mechanics are usually some combination of the dimensions time T, mass M, and length L. Consider the physical quantities m,r,v,a, and t with dimensions [m]=M,[r]=L,[v]=LT−1 ,[a]=LT ^−2 , and [t]=T. Enter the dimensional expression of the quantity on the right-hand side of each equation. Your answers may contain only M, L, T, and exponents. Assume that each of the following equations is dimensionally consistent. L 0 =mvr [L1 W=mar k=− rma
Answers
The dimensional expressions for the quantities on the right-hand side of the given equations are ML²T⁰, ML²T⁻¹, and MLT⁻², corresponding to different physical quantities involved in the equations.
Physical quantities are m, r, v, a, and t with dimensions [m] = M, [r] = L, [v] = LT⁻¹, [a] = LT⁻², and [t] = T. The dimensional expression of the quantity on the right-hand side of each equation is given below:
L0 = mvr
where [L0] = L1[L] = [M]a[L]b[T]c = MaLbTc
By equating the dimensions on both sides, we get
LHS = RHS.
LHS = L0 = L¹
RHS
mvr = [M][L][LT⁻¹] = MaL²T⁻¹
Comparing the exponents of M, L, and T on both sides, we get
M : 1 = aL : 2 = bT : -1 + 1 = c⇒ a = 1, b = 2, and c = 0.
So, the dimensional expression of the quantity on the right-hand side of L0 = mvr is MaL²T⁰ = ML²T⁰W = mar
where [W] = [F][d] = MLT⁻²LT = ML²T⁻¹
By equating the dimensions on both sides, we get
LHS = RHS.
LHS = W = ML²T⁻¹
RHS
mar = [M][LT⁻²][L] = ML²T⁻¹
Comparing the exponents of M, L, and T on both sides, we get
M : 1 = 1
L : 2 = 1
T : -1 - 2 = -3⇒ the dimensional expression of the quantity on the right-hand side of W = mar is ML²T⁻¹.
K = -rma
By equating the dimensions on both sides, we get
LHS = RHS.
LHS = K = [M][L²][T⁻²]
RHS
-rma = -[L][M][T⁻²] = MLT⁻²
Comparing the exponents of M, L, and T on both sides, we get
M : 1 = 1
L : 2 = -1
T : -2 = -2⇒ the dimensional expression of the quantity on the right-hand side of K = -rma is MLT⁻².
Hence, the dimensional expression of the quantity on the right-hand side of each equation is
ML²T⁰, ML²T⁻¹, and MLT⁻².
To know more about dimensional expression, refer to the link below:
https://brainly.com/question/32658827#
#SPJ11
Why does the sky change colors at sunset?
Answers
Answer: When a beam of sunlight strikes a molecule in the atmosphere, what's called "scattering" occurs, sending some of the light's wavelengths off in different directions.
Explanation:
How dose a scientific theory differ from a hypothesis?
Answers
Answer:This is the Difference Between a Hypothesis and a Theory. ... In scientific reasoning, a hypothesis is an assumption made before any research has been completed for the sake of testing. A theory on the other hand is a principle set to explain phenomena already supported by data.
Explanation:
A car runs 4200m on a straight path in 40 minute. find its velocity?
Answers
Answer:
velocity = displacement/time
= 4200m/ 2400s
= 1.75 m/s
Explanation:
40 minutes × 60 = 2400 seconds
Can someone explain what ice jacking is and how it can cause structures to fail?
Answers
Answer: Rock slope failures can occur due to the presence of water; ice jacking occurs when water between joint or fissure surfaces freezes and expands. This type of failure is progressive, resulting in incremental weakening over time, often requiring several cycles before failure. Ice jacking is one form of rock erosion.
solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid are called ________.
Answers
Concentrated solar power facilities are solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid .
What is solar power?Solar power refer to electric power or electricity that is generated from sun rays or radiations while using solar panels and other technologies.
Therefore, Concentrated solar power facilities solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid.
Learn more about solar power below
https://brainly.com/question/17711999
#SPJ12
what percentage of semiconductors are made in taiwan
Answers
At a particular temperature, the speed of sound is 330 m/s and its frequency is 990 Hz. Choose the correct wavelength of this sound wave.
m
Answers
Answer:
1/3 M
I hope this helps :) sorry its late
Answer:
1/3 m
Explanation:
Changes in cardiovascular function that accompany mild upright exercise like jogging include ______.
Answers
Changes in cardiovascular function that accompany mild upright exercise like jogging include increased heart rate, increased cardiac output, increased blood flow to the working muscles.
Additionally, mild upright exercise can lead to increased blood pressure and improved cardiovascular fitness over time with regular exercise.
Increased heart rate: During exercise, the heart rate increases to meet the increased demand for oxygenated blood by the working muscles. This elevated heart rate helps deliver oxygen and nutrients to the muscles and remove metabolic waste products.
Increased stroke volume: Stroke volume refers to the amount of blood ejected by the heart with each contraction. During exercise, stroke volume increases as a result of enhanced cardiac output, allowing more blood to be pumped to the muscles.
Increased blood pressure: Mild upright exercise like jogging can lead to a temporary increase in blood pressure. This response is a result of the increased cardiac output and peripheral vasoconstriction that occurs during exercise.
Increased oxygen uptake: During exercise, oxygen uptake by the lungs increases to meet the higher demand for oxygen required by the muscles. This increased oxygen uptake supports aerobic energy production and helps sustain the exercise.
To know more about cardiac output, visit:
https://brainly.com/question/13064857
#SPJ11
What will happen if we increase the friction on a roller coaster?
A. The speed of the roller coaster will increase.
B. The speed of the roller coaster will decrease
C. The speed of the roller coaster will remain constant.
D. The roller coaster will fly away
Answers
Answer: B. The speed will decrease.
Explanation:
When you ride a roller coaster, the wheels rub/scrape the rails, creating heat as a result of friction. And friction will slow you down. So increasing the friction on a roller coaster would slow it down.
Answer:
B
Explanation:
Friction opposes motion therefore reducing motion
3. Why did Mendeleev have problems arranging the
elements Te and I?
Answers
seawater velocity = 1478 m/s water depth = 509 m sandstone velocity = 2793 m/s thickness=1003 m mudstone velocity= 2240 m/s thickness = 373 m Air Gun Energy Source Note: Illustration is not to scale. Hydrophone Receivers seafloor sand/mud 2. In the marine seismic acquisition example shown, you are interested in two events observed in the seismic trace that is recorded at the first hydrophone. One is a first-order multiple (double bounce) off the seafloor. The other is a primary reflection from the sand/mud interface for which the energy ray-path has a takeoff angle of 9 degrees from vertical as shown. Assume horizontal rock layers and isotropic velocities. Which of the two events arrives at the hydrophone first-the primary or the multiple? Clearly show your calculations and include a simple drawing of the two- event seismic trace. 3. How long does it take for energy to travel directly from the air gun to the first hydrophone (no bounces)? 4. What is the maximum takeoff angle at which seismic energy can reflect from the sand/mud interface? Explain what happens to the energy for larger angles. 5. Explain the relative direction of travel for energy that is transmitted into the mudstone.
Answers
2. The primary reflection from the sand/mud interface will arrive first at the hydrophone. To determine which event arrives first, we need to calculate the two-way travel times (TWTT) for each event. The TWTT for the primary reflection from the sand/mud interface is:
TWTT = (2 × depth × sin (angle of incidence)) / velocity
TWTT = (2 × 509 × sin (9)) / 1478TWTT = 0.317 s
The TWTT for the double bounce off the seafloor is:TWTT = (2 × depth) / velocityTWTT = (2 × 509) / 1478TWTT = 0.689 s
Therefore, the primary reflection arrives first at the hydrophone. Here is a simple drawing of the two-event seismic trace:
3. To calculate the time it takes for energy to travel directly from the air gun to the first hydrophone, we need to determine the distance between them and divide it by the velocity of sound in seawater. Using the given values, we have:
Distance = depth + (thickness of sand/mud) + (thickness of mudstone)
Distance = 509 + 1003 + 373
Distance = 1885 m
Velocity of sound in seawater = 1478 m/s
Time = Distance / VelocityTime = 1885 / 1478Time = 1.276 s
Therefore, it takes 1.276 seconds for energy to travel directly from the air gun to the first hydrophone.
4. The maximum takeoff angle at which seismic energy can reflect from the sand/mud interface is called the critical angle. This angle can be calculated using Snell's law:
n1 × sin (angle of incidence) = n2 × sin (angle of refraction)
where n1 and n2 are the velocities of the two materials and the angle of refraction is 90 degrees (since seismic energy travels along a horizontal path once it reaches the interface).
For the sand/mud interface, the critical angle is:
n1 × sin (critical angle) = n2 × sin (90)n1 / n2 = cos (critical angle)critical angle = cos^-1 (n1 / n2)
Using the given values:
n1 = 2793 m/s (sandstone velocity)n2 = 2240 m/s (mudstone velocity)critical angle = cos^-1 (2793 / 2240)
critical angle = 35.9 degrees
Seismic energy cannot reflect from the sand/mud interface at angles greater than the critical angle. For larger angles, the energy will be transmitted into the mudstone.
5. When seismic energy is transmitted into the mudstone, it travels in all directions away from the source. However, the energy will be attenuated (reduced in amplitude) as it travels through the mudstone due to its relatively low velocity compared to the sandstone and seawater.
As a result, the mudstone acts as a barrier that blocks or reduces the energy that would otherwise be transmitted deeper into the subsurface.
learn more about hydrophone here
https://brainly.com/question/2189435
#SPJ11
a 0.20-kg object is traveling to the right (in the positive direction) with a speed of 3.0 m/s. after a 0.20 s collision, the object is traveling to the left at 1.0 m/s. what is the magnitude of the impulse (in n-s) acting on the object? the answer must be positive (never include units in the answer to a numerical question.)
Answers
The magnitude of the impulse acting on the object having a mass of 0.2 kg is 0.8 Ns
The mass of the object = 0.2 kg
The initial velocity of the object = 3 m/s(\(\hat i\)) (in the positive direction)
The final velocity of the object = 2 m/s(\(- \hat i\)) (in the negative direction)
The impulse acting on the object is just the change in momentum of the object due to the collision.
I = Δp
where I is the impulse acting on the object
Δp is the change in momentum of the object.
\(\displaystyle \Delta p = mv_{f} - mv_{i}\)
\(\displaystyle \Delta p = m(v_{f} - v_{i})\)
where m is the mass of the object
\(v_{f}\) and \(v_{i}\) are the final and initial velocity of the object respectively.
Let us substitute the known values in the above equation, we get
\(\Delta p = 0.2 [ 1(- \hat i) - 3 (\hat i)]\)
\(= 0.2 [ 4 (- \hat i)]\)
\(= 0.8 ( - \hat i)\) N.s
We know that
I = Δp
\(= 0.8 ( - \hat i)\) N.s
Therefore, the magnitude of the impulse is 0.8 Ns
Learn more about the impulse in
https://brainly.com/question/904448
#SPJ4
A 2.99 x 10-6 C charge is moving in a
direction 10.0° from the Earth's
magnetic field (5.00 x 10-5 T). If the
force on it is 2.14 x 10-8 N, how fast is
it moving?
[?] m/s
No links please
Answers
another answer for acellus is 143 m/s it worked for me
The speed of the charge is approximately 2.857 m/s.
To find the speed of the charge, we can use the formula for the magnetic force on a charged particle moving through a magnetic field:
Force (F) = q * v * B * sin(θ)
Where:
F is the force on the charge (given as 2.14 x \(10^-8\) N),
q is the charge of the particle (given as 2.99 x \(10^-6\)C),
v is the speed of the charge (what we want to find),
B is the magnitude of the magnetic field (given as 5.00 x \(10^-5\) T),
θ is the angle between the direction of motion and the magnetic field (given as 10.0°).
First, we need to convert the angle from degrees to radians:
θ (in radians) = 10.0° * (π / 180°) ≈ 0.174532925 radians
Now, we can rearrange the formula to solve for the speed (v):
v = F / (q * B * sin(θ))
Substitute the given values into the equation:
v = 2.14 x \(10^-8\) N / (2.99 x \(10^-6\) C * 5.00 x \(10^-5\) T * sin(0.174532925))
v ≈ 2.857143 m/s
Therefore, the speed of the charge is approximately 2.857 m/s.
To know more about speed here
https://brainly.com/question/17661499
#SPJ2
A ball is tossed with enough speed straight up so that it is in the air several seconds. Assume upward direction is positive and downward is negative. Part A What is the velocity of the ball when it reaches its highest point?
Answers
Answer:
Answer:
The velocity of the ball when it reaches its highest point is 0
Explanation:
The velocity of the ball when it reaches its highest point is 0
Once the ball is tossed into the air, as it goes up, the initial velocity with which it was thrown, reduces, as the motion of the ball is hindered by several forces such as gravity and air resistance. This slows down the velocity of the ball, up until it reaches a point, where the upwards velocity of the ball becomes zero. at this point, the ball begins to fall back to the ground.
Calculate acceleration of a turtle going from 0.3 m/s to 0.7 m/s in 30 seconds.
Answers
Answer:
acceleration = 0.013 m/s²
Explanation:
formula for acceleration is
a = (v-u) / t
a= (0.7-0.3) / 30
= 0.013
The acceleration of a turtle going from 0.3 m/s to 0.7 m/s in 30 seconds is 0.0133m/s²
Acceleration is defined as the change in velocity of a body with respect to time. Mathematically:
\(a=\frac{v-u}{t}\)
v is the final speed = 0.7m/s
u is the initial speed = 0.3m/s
t is the time taken = 30seconds
Substitute the given values into the formula:
\(a=\frac{0.7-0.3}{30}\\a=\frac{0.4}{30}\\a = 0.0133m/s^2\)
Hence the acceleration of a turtle going from 0.3 m/s to 0.7 m/s in 30 seconds is 0.0133m/s²
Learn more here: https://brainly.com/question/20982904
which of the following is the equation to determine current using resistance and voltage?
1) current = voltage + resistance
2) current = voltage × resistance
3) current = voltage - resistance
4) current = voltage / resistance
Does anyone know?
Answers
Answer:
Current =voltage /resistance.
energy is the ability to___or___ matter
Answers
Energy is defined in science as the ability to move matter or change matter in some other way.
considering the rotation of the earth, what is your angular velocity in mrad/s? the earth's radius is 6371 km. assume you are on the equator.
Answers
The angular velocity of the Earth at the equator is approximately 7.2921159 × 10⁻⁵ rad/s.
Determine the angular velocity?The angular velocity of a rotating object is defined as the change in angle over time. In this case, we consider the Earth's rotation. The Earth completes one full rotation in approximately 24 hours, which is equivalent to 86,400 seconds.
To calculate the angular velocity, we divide the angle traversed by the time taken. The angle traversed in one rotation is 2π radians, and the time taken is 86,400 seconds. Therefore, the angular velocity can be calculated as:
Angular velocity = (2π radians) / (86,400 seconds)
≈ 7.2921159 × 10⁻⁵ rad/s
Hence, the angular velocity of the Earth at the equator is approximately 7.2921159 × 10⁻⁵ rad/s.
To know more about angular velocity, refer here:
https://brainly.com/question/31655589#
#SPJ4
please help me with this question: Tamika is babysitting and wants to make jello with the kids. She has to heat the water before adding the jello mix, If she heats the mixture to 50°C, how do the molecules move? Select ALL that apply.
A.
The hotter molecules move faster than the colder molecules.
B.
The hotter molecules move towards the surface of the mixture.
C.
The hotter molecules move towards the bottom of the mixture.
D.
The hotter molecules move slower than the colder molecules.
E.
The colder molecules move towards the surface of the mixture.
F.
The colder molecules move towards the bottom of the mixture.
Answers
Answer:
B f
Explanation: hop it helps
What is the weight of a box with a mass of 150 kg on Earth?
N
Use g= 9.81 m/s2 and do not include units in your answer.
Answers
Answer:
W = M g = 150 kg * 9.81 m/s^2 = 1470 N
You were only given 3 significant figures in the question.
The weight of the box is 1471.5 N.
What is weight?In science and engineering, an object's weight is defined as the force of gravity acting on the thing. Weight is sometimes described as a vector quantity in common textbooks, denoting the gravitational force acting on the item.
Given parameters:
Mass of the box, m = 150 kg.
Acceleration due to gravity, g = 9.8 m/s².
Hence, weight of the box is, W = mg = 150 kg × 9.81 m/s² =1471.5 N.
SO, weight of the box with a mass of 150 kg on Earth is 1471.5 N.
Learn more about weight here:
https://brainly.com/question/10069252
#SPJ2
LaCie kicks a football from the ground level at a velocity of 13.9 m/s and at angle of 25 degrees to the ground. You have determined that the football would travel 15.1 m before landing. How would this value change if the football was kicked at an angle of 35 degrees? Complete all equations without rounding and then round to the nearest tenth at the end
Answers
The ball will travel more distance when projected or kicked at an angle of 35 degrees.
What is the range of projectile?
The range of the projectile or the horizontal distance traveled by the ball is calculated by applying the following kinematic equation as shown below.
R = ( u² sin (2θ ) ) / g
where;
u is the initial velocity of the ballg is the acceleration due to gravityThe horizontal distance traveled by the ball when projected at 35 degrees is calculated as;
R = ( 13.9² x sin ( 2 x 35 ) ) / ( 9.8 )
R = 18.53 m
Learn more about horizontal distance here: https://brainly.com/question/24784992
#SPJ1