disadvantage of nitrogen cycle​

Answer:

Solution!

Explanation:

Becuase the water didn't change when the sugar was mixed in. :)

This connection produces a characteristic of water molecules called cohesion, which is important. Plants can absorb water at their roots thanks to the cohesion of water molecules.

Cohesion refers to the attraction of water molecules to one another and to other materials, such as the walls of plant xylem. Because they are polar, water molecules behave in this manner. Water from the roots of plants is transferred to the leaves, stem, and other portions of the plant body through vascular tissue known as the xylem. The roots of plants absorb this type of moisture and water from the earth. It has a polar nature. It is a universal solvent. It has a high specific heat as well as a high vaporization temperature. It has properties of adhesion and cohesion. Its solid phase is thinner than its liquid phase.

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I gotta say it's D cause all of those all react differently towards another chemical.

Answer:

Bubbling/Foaming

Heat is produced

Explanation:

A chemical reaction has occurred if

1. There is a change in colour

2. Formation of a precipitate

3. Formation of a gas

4. Change in temperature

5. Change of smell

In the reaction of hydrogen peroxide and potassium iodide, the solution quickly rises which shows the formation of gas. This means it is a chemical reaction.

The beaker/test tube/whatever you used should also become warm because it is an exothermic reaction. This means its a chemical reaction

The pressure in the burette if the atmospheric pressure in the room at that time was 765.0 torr is 915 torr

The pressure in the burette can be obtained by using the following formula:

Pressure of gas = Atmospheric presure + pressure due to height

With the above formula, we can determine the pressure in the burette. This is illustrated below:

Pressure in burette = Atmospheric presure + pressure due to height

Pressure in burette = 765.0 + 150

Pressure in burette = 915 torr

Thus, the pressure in burette is 915 torr

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The type of plot that can be used to determine λ max of a solution is Absorbance vs wavelength.

The correct option is C.

The plot of absorbance vs wavelength is called an absorption spectrum or an absorbance spectrum.

In this plot, the x-axis represents the wavelength of light, usually in nanometers (nm), and the y-axis represents the absorbance of the sample at that particular wavelength. The absorbance is a measure of how much light is absorbed by the sample at a specific wavelength.

The absorption spectrum is used to identify the wavelengths at which a substance absorbs light and can be used to determine the identity or concentration of the substance. The pattern of peaks and troughs in the absorption spectrum is unique to each substance, making it a useful tool in analytical chemistry and biochemistry.

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The concentration of H+ at equilibrium is 1.06 x 10^-4 M.

To determine the concentration of H+ in the weak acid solution at equilibrium, we need to use the percent ionization and the initial concentration of the weak acid.

Let's assume that the weak acid is denoted by HA. Then, we can write the equilibrium equation for the dissociation of HA as:

HA ⇌ H+ + A-

The equilibrium constant expression for this dissociation reaction is:

Ka = [H+][A-]/[HA]

Since the acid is weak, we can assume that the concentration of A- at equilibrium is approximately equal to the initial concentration of HA, since only a small fraction of HA is dissociated. Therefore, we can simplify the equilibrium constant expression to:

Ka = [H+]^2/[HA]

Rearranging this equation, we get:

[H+]^2 = Ka[HA]

Taking the square root of both sides, we get:

[H+] = sqrt(Ka[HA])

Now, we can plug in the values given in the problem:

Ka = unknown

[HA] = 0.00550 M

percent ionization = 8.20%

To find Ka, we can use the percent ionization:

percent ionization = [H+]/[HA] x 100%

8.20% = [H+]/0.00550 M x 100%

[H+] = 0.000451 M

Now, we can use the equation we derived earlier to find [H+] at equilibrium:

[H+] = sqrt(Ka[HA])

0.000451 M = sqrt(Ka x 0.00550 M)

Squaring both sides, we get:

Ka x 0.00550 M = (0.000451 M)^2

Solving for Ka, we get:

Ka = (0.000451 M)^2 / 0.00550 M

Ka = 3.70 x 10^-6 M

Finally, we can use the equation [H+] = sqrt(Ka[HA]) to find the concentration of H+ at equilibrium:

[H+] = sqrt(3.70 x 10^-6 M x 0.00550 M)

[H+] = 1.06 x 10^-4 M

Therefore, the concentration of H+ at equilibrium is 1.06 x 10^-4 M.

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True. Injured individuals can rely on the common law to obtain damages and injunctions against business polluters.

The common law refers to the body of law that is developed through court decisions rather than legislation. In the context of environmental pollution caused by businesses, individuals who have suffered harm or injury due to such pollution may seek remedies under the common law.

Under the common law, individuals have the right to bring lawsuits against polluting businesses and seek damages for the harm caused. Damages can include compensation for medical expenses, property damage, loss of income, and other relevant losses resulting from the pollution. If the court finds the polluting business liable for the harm, it may order the payment of damages to the injured individuals.

Additionally, injunctions can also be sought under the common law. An injunction is a court order that requires the polluting business to stop or limit its harmful activities. In cases where ongoing pollution poses a threat to public health or the environment, injured individuals can seek injunctive relief to prevent further harm.

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Answer:

Temperature

Explanation:

This is because quantitative data include numerical values for example 10 degrees Celsius. However the others are qualitative data because the research can be described but not with numbers like your appearance is very nice.

Hope this helps :P

Answer:

Quantitative data is the type of data whose value is measured in the form of numbers or counts, with a unique numerical value associated with each data set. Also known as numerical data, quantitative data further describes numeric variables (e.g. How many? How often? How much?)

Explanation:

so its temp

Answer: Nitric acid + Hydrogen disulfide

Explanation: To balance HNO3 + H2S = NO + S + H2O you'll need to be sure to count all of atoms on each side of the chemical equation.

Once you know how many of each type of atom you can only change the coefficients (the numbers in front of atoms or compounds) to balance the equation for Nitric acid + Hydrogen disulfide .

Important tips for balancing chemical equations:

Only change the numbers in front of compounds (the coefficients).

Never change the numbers after atoms (the subscripts).

The number of each atom on both sides of the equation must be the same for the equation to be balanced.

Answer:

C) -3063J

Explanation:

multiply m, c, and change in T

Solvent extraction, or liquid-liquid extraction, is a commonly employed technique for separating specific compounds from a mixture.

When conducting experiments involving solvent extraction, it is crucial to include the density of the solvent as a physical property in the pre-lab write-up of your lab notebook.

Solvent extraction, or liquid-liquid extraction, is a commonly employed technique for separating specific compounds from a mixture.

This method involves shaking the mixture containing two immiscible liquids, allowing them to separate into distinct layers, and subsequently isolating the desired compound.

The density of the solvents plays a vital role in solvent extraction experiments. It determines the layer identification after phase separation.

By understanding the relative densities of the two liquids involved, we can predict which liquid will be the top layer and which will be the bottom layer.

The less dense liquid will float on top, while the more dense liquid will sink to the bottom.

This knowledge enables us to determine the layer that contains the target compound of interest.

Including the density of the solvents in the pre-lab write-up ensures accurate layer identification during the solvent extraction process.

It is an essential physical property that aids in the successful isolation of desired compounds.

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Answer:

not goin to be rude but I don't even get the question??

Answer:

Es so es na formula pero te balto la convinasiones de la formula

The exchange capacity of an anion-exchange resin can be measured using a titration method. First, a known weight of the resin is weighed out and suspended in a buffered solution of a known pH.

The resin is then titrated with a standard solution of either sodium hydroxide (NaOH) or hydrochloric acid (HCl) until the pH of the solution reaches a predetermined endpoint. The amount of titrant added during the titration is then used to calculate the moles of charged sites per gram of dry resin.

To calculate the exchange capacity, the following equation can be used:

Exchange Capacity (mol/g dry resin) = (mol titrant added) / (g dry resin)

The mol titrant added is determined from the titration curve, which is constructed by measuring the pH of the solution versus the volume of titrant added. The endpoint of the titration is typically assumed when the pH of the solution reaches a predetermined value.

To ensure accuracy, the titration should be repeated at least three times and the average of the results should be taken. This will ensure that the exchange capacity measured is an accurate representation of the resin.

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Answer:

Explanation:

Enzyme activity is affected by the increase in temperature.

enzyme activity is also affected by the change in ph.

enzyme activity is also affected when substrate concentration is not increased in a chemical reaction.

Based on your observations, enzyme activity is affected by the increase in temperature.Enzyme activity is also affected by the change in pH.

Observations are defined as a set of statements or facts which are recorded while conducting an experiment.Observations are made through sensing changes in the variables of the experiment.

It is specifically defined as an act of knowing or recording the changes in the variables of the experiment.Recording observations holds importance as recording observations avoid the experiment to be repeated over and over again.

It is important to note down observations so that the testing of hypothesis is made easier.There are four types of observations .Observations need to be descriptive and must be written in complete sentences and should include all the numerical data of the experiment.

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Answer:

University of University of South New York Jersey has is a the best in the world the most important most important aspect of aspect of life is life and marriage is in my a lot more of a urban

\(\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}\)

\(\\ \sf\longmapsto Density=\dfrac{0.02}{55}\)

\(\\ \sf\longmapsto Density=0.0003kg/m^3\)

Answer:

Explanation:

B. Cut flowers placed in sugar water stay fresh longer than flowers

placed in regular water.

Answer:

B

Explanation:

Just got question right on quiz!!! <3

The Ka of HCN is \(3.3 * 10^{(-10)}\) with two significant figures.

The Ka of the acid HCN can be determined using the given pH and concentration information. The first step is to calculate the concentration of H3O+ ions in the solution using the pH:

\(pH = -log[H_3O+] \\\\5.02 = -log[H_3O+] \\\\[H_3O+] = 10^{(-5.02) }= 7.94 * 10^{(-6)} M\)

Next, use the balanced chemical equation for the ionization of HCN and the equilibrium expression for Ka to set up an equation to solve for Ka:

\(HCN(aq) + H_2O(l)\) ⇌\(CN-(aq) + H_3O+(aq)\)

\(Ka = [CN-][H_3O+] / [HCN]\)

At equilibrium, the concentration of CN- ions is equal to the concentration of H+ ions, since HCN is a weak acid and does not completely dissociate.

Therefore, [CN-] ≈ \([H_3O+] = 7.94 * 10^{(-6)} M\). The concentration of HCN is given as 0.19 M.

Substituting these values into the expression for Ka:

\(Ka = (7.94 * 10^{(-6)} M)^2 / 0.19 M = 3.3 * 10^{(-10)}\)

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The mass of KF in the solution is 59.3 g. The correct answer is 59.3 g which is in option A as  the formula for calculating the mass of solute in a solution is: mass of solute = molarity × volume × molar mass.

mass of solute = molarity × volume × molar mass

First, one needs to calculate the number of moles of KF in the solution:

molarity = number of moles / volume

Rearranging this equation gives :

number of moles = molarity × volume

number of moles = 2.00 M × 0.510 L

number of moles = 1.02 mol

The molar mass of KF is 58.10 g/mol. Now the mass of KF in the solution is calculated:

mass of KF = 1.02 mol × 58.10 g/mol

mass of KF = 59.3 g

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Baking powder solution has an effect on a diluted hydrochloric acid solution by causing the release of carbon dioxide from sodium bicarbonate, a component of baking soda.

One molecule of backing soda + one molecule of hydrochloric acid yields one molecule of sodium chloride (table salt) + one molecule of carbon dioxide + one molecule of water.

HCl + NaHCO₃=NaCl+H₂CO₃

However, carbonic acid is quite unstable:

H₂CO₃ = CO₂ + H₂O

HCl + NaHCO₃ = NaCl + H₂O (Water) + CO₂.

Effervescence, which is a fast bubble formation, is how liquid releases CO2.

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Answer: myth .

Explanation: traditional story, especially one concerning the early history of a people or explaining a natural or social phenomenon, and typically involving supernatural beings or events.

"ancient Celtic myths"

usually traditional story of ostensibly historical events that serves to unfold part of the world view of a people or explain a practice, belief, or natural phenomenon creation myths. b : parable, allegory Moral responsibility is the motif of Plato's myths.

Answer: Approximate radius of an iron atom ≈ 5.77 × 10^-15m or 0.0577 nm

(a) Impact parameter refers to the perpendicular distance between the path of an incident particle and the center of the target.

Let’s compute the impact parameter using the formula below:

b = cot(θ/2) * (R1 + R2),

where θ = scattering

angle = 95°,

R1 = radius of incident particle,

R2 = radius of target particle

R1 = r, radius of alpha particle

R2 = R, radius of iron atom

R = 1.2 × 10^-10mb = cot(θ/2) * (R1 + R2)

b = cot(95°/2) * (1.2 × 10^-10m + 8.5 × 10^-15m)

b = 3.556 × 10^-15m ≈ 4 μm

Answer: Impact parameter = 4 μm

(b) Scattering occurs when the impact parameter is less than the distance of closest approach (DCA).

Therefore, we need to compute DCA using the formula below:

DCA = 2R(R1 + R2) / (R + R1)sin²(θ/2)

DCA = 2(1.2 × 10^-10m)(17 × 10^-6m + 1.2 × 10^-10m) / (8.5 × 10^-15m + 1.2 × 10^-10m)sin²(95°/2)

DCA = 3.28 × 10^-13m

To determine the fraction of particles scattered at angles greater than 95°,

we need to compute the area of the ring centered at the point of closest approach, but outside of the minimum scattering angle.

The area of this ring is πb² (1 - cos(θ/2)).

Also, the total area of scattering is πDCA² / 4.

Therefore, the fraction of particles scattered at angles greater than 95° is:Fraction = πb² (1 - cos(θ/2)) / πDCA² / 4

Fraction = (4b² / DCA²) (1 - cos(θ/2))

Fraction = (4(4 × 10^-12m²) / (3.28 × 10^-13m)²) (1 - cos(95°/2)) ≈ 0.038

Answer: Fraction of particles scattered at angles greater than 95° ≈ 0.038

(c) To compute the approximate radius of an iron atom, we need to use the formula for the radius of the nucleus of an atom. The Rutherford scattering formula, which is based on Coulomb's law, was used to determine the size of the nucleus of the atom.

Rutherford's formula states that the radius of the nucleus is R = R0A¹/³,

where

A is the mass number of the nucleus,

R0 is the radius of the nucleus of hydrogen (which is about 1.2 × 10^-15m), and

R is the radius of the nucleus of the atom.

Therefore, we need to determine the mass number of iron. The mass number of an atom is equal to the number of protons (atomic number) plus the number of neutrons. The atomic number of iron is 26, and the atomic mass is 56. Thus, the mass number is 56.

R = R0A¹/³R = (1.2 × 10^-15m)(56)¹/³ ≈ 5.77 × 10^-15m

Answer: Approximate radius of an iron atom ≈ 5.77 × 10^-15m or 0.0577 nm

Answer:

Deposition

this is the process of a substance changing its state from gas to solid. Solid to gas is known as sublimation

Answer:

15.27895 x 10⁶kg of chlorine radical is added to the atmosphere in a year due to 100 million MVACs                                                                                              

Explanation:

Chlorofluorocarbons (CF₂Cl₂) from refrigerants produce chlorine radicals according to the following equation

         CF₂Cl₂ → CF2Cl  + Cl ⁻ .........(1)

From equation 1, one mole of CF₂Cl₂ produces one mole of Chlorine radical

From the question,

The emission rate of CF₂Cl₂ is 59.5mg/hour/MVAC

In one day the emission rate would be 59.5 x 24hours

                                                                  = 1428mg/day

In one year, the emission rate would be 1428mg/day x 365days

                                                                 =  521220mg/year

                                                                   = 521.220g/year/MVAC

Therefore the emission rate for 100 million MVAC using CF₂CL₂ in a year is

                                                                    = 52122 x 10⁶g/year/MVAC

                                                                    = 52122 x 10³kg/year/MVAC

The molar mass of CF₂CL₂                       = 120.913g/mol

No of moles  of CF₂CL₂                              = mass/ molar mass

                                                                     = 52122 x 10⁶g / 120.913g/mol

                                                                      = 431 x 10⁶ moles of CF₂Cl₂

From equation 1,  since one mole of CF₂Cl₂ produces one mole of Chlorine radical, it implies that

431 x 10⁶ moles of CF₂Cl₂ would produce 431 x 10⁶ moles of chlorine radical,

Therefore, to find the mass of chlorine radical produced, we use the formula

No of moles of chlorine radical  = mass/ molar mass

431 x10⁶ moles = mass of chlorine radical /molar mass of chlorine radical

431 x 10⁶ moles = mass/ 35.45g/mol

mass of chlorine =  431 x 10⁶ moles x 35.45 g/mol

                            =    15278.95 x 10⁶ g

In Kg, the mass    =   15,278.95 x 10³kg of cholrine radical

                             =   15.27895 x 10⁶ Kg of chlorine radical

Answer:

"After crude oil is removed from the ground, it is sent to a refinery where different parts of the crude oil are separated into useable petroleum products. These petroleum products include gasoline, distillates such as diesel fuel and heating oil, jet fuel, petrochemical feedstocks, waxes, lubricating oils, and asphalt.

A U.S 42-gallon barrel of crude oil yields about 45 gallons of petroleum products in U.S. refineries because of refinery processing gain. This increase in volume is similar to what happens to popcorn when it is popped."

"What are petroleum products, and what is petroleum used for?

Petroleum products include transportation fuels, fuel oils for heating and electricity generation, asphalt and road oil, and feedstocks for making the chemicals, plastics, and synthetic materials that are in nearly everything we use. Of the approximately 7.21 billion barrels of total U.S. petroleum consumption in 2016, 47% was motor gasoline (includes ethanol), 20% was distillate fuel (heating oil and diesel fuel), and 8% was jet fuel."

Solvents Diesel fuel Motor Oil Bearing Grease

Ink Floor Wax Ballpoint Pens Football Cleats

Upholstery Sweaters Boats Insecticides

Bicycle Tires Sports Car Bodies Nail Polish Fishing lures

Dresses Tires Golf Bags Perfumes

Cassettes Dishwasher parts Tool Boxes Shoe Polish

Motorcycle Helmet Caulking Petroleum Jelly Transparent Tape

CD Player Faucet Washers Antiseptics Clothesline

Curtains Food Preservatives Basketballs Soap

Vitamin Capsules Antihistamines

The percent by mass of acetic acid in the vinegar is 2.33%.

Below are the steps to solve the given problem using the data table given below:

Step 1: Calculate the mass of the vinegar. Given,Mass of flask and vinegar solution- 25.17gMass of flask- 15.12gMass of vinegar solution = Mass of flask and vinegar solution - Mass of flask= 25.17 g - 15.12 g= 10.05 g

Step 2: Calculate the moles of NaOH used in the titration.Molarity of NaOH solution is 0.1 M.Moles of NaOH = Molarity × Volume of NaOH usedMoles of NaOH = 0.1 M × 39.00 mL (since the initial volume of NaOH is 0.00 mL)Moles of NaOH = 0.0039 moles

Step 3: Determine the moles of acetic acid used in the reaction.The balanced chemical equation for the reaction between NaOH and acetic acid (the main component of vinegar) is given below:CH3COOH + NaOH → CH3COONa + H2OMoles of NaOH = Moles of CH3COOH (since they react in a 1:1 ratio)Moles of CH3COOH = 0.0039 moles

Step 4: Calculate the mass of acetic acid used in the reaction.Molar mass of acetic acid is 60.05 g/mol.Mass of CH3COOH = Moles of CH3COOH × Molar mass of CH3COOH= 0.0039 moles × 60.05 g/mol= 0.234 gStep 5: Calculate the percent by mass of acetic acid in the vinegar.Percent by mass of acetic acid = (Mass of CH3COOH / Mass of vinegar solution) × 100%= (0.234 g / 10.05 g) × 100%= 2.33%.

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The complete reactions are: 1) As2O3 (s) + 4NO3- (aq) + 4H+ (aq) --> 2H3AsO4 (aq) + 4NO3- (aq)
2) 2AlO2- (aq) + 3PO33- (aq) + 8H+ (aq) --> 2Al (s) + 3PO43- (aq) + 4H2O (l)
3) Cr2O72- (aq) + 3I2 (s) + 14OH- (aq) --> 2Cr(OH)3 (s) + 3IO3- (aq) + 6H2O (l)

1) In the first redox reaction, As2O3 is reduced to H3AsO4, while NO3- is reduced to NO3. Balancing this reaction in acidic solution:
As2O3 + 2NO3- + 10H+ --> 2H3AsO4 + 2NO + 3H2O

2) In the second redox reaction, AlO2- is reduced to Al, while PO33- is oxidized to PO43-. Balancing this reaction in acidic solution:
3AlO2- + 2PO33- + 12H+ --> 3Al + 2PO43- + 6H2O

3) In the third redox reaction, Cr2O72- is reduced to Cr3+, while I2 is oxidized to IO3-. Balancing this reaction in basic solution:
Cr2O72- + 6I- + 14OH- --> 2Cr3+ + 6IO3- + 7H2O

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A backdraft explosion can occur when there is a lack of oxygen in a partially-burned room. This situation can be exacerbated if a door is opened into the room, introducing a sudden supply of oxygen, which then leads to a rapid combustion of the remaining fuel, causing the explosion. A fire being very smoky may also indicate a lack of oxygen, increasing the risk of a backdraft explosion.

A backdraft explosion can occur under certain conditions such as when there is a lack of fuel in a partially-burned room or a lack of oxygen in a partially-burned room. Additionally, if a door is opened into a room instead of opening into a hallway or outside, it can create a draft that can lead to a backdraft explosion. Furthermore, a fire that is very smoky can also lead to a backdraft explosion as the smoke can build up and ignite when oxygen is suddenly introduced. It is important to be aware of these potential dangers and to take necessary precautions to prevent a backdraft explosion from occurring.

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