Diluting a Stock Solution to a New Concentration Dilutions are prepared by adding extra solvent to a solution of known concentration (also called a stock solution) to reduce the concentration of solute. The amount of stock solution needed is calculated from M,V=M2Vz. Procedure: 1. Obtain a second 100 mL volumetric flask 2. Calculate the volume (ml) of 0.50 M NaCl stock solution needed to make 100 mL of a diluted solution with a concentration of 0.03 M. Show your work in the calculations section. 3. Using a graduated cylinder, measure and pour the appropriate volume of stock solution into the new volumetric flask. Use the funnel to pour your solution into the flask if necessary. 4. Add tap H2O to the marked line on the flask 5. Invert the flask a few times to mix. Double check: see if solution is at the line. Mixing occurs easily since two liquid phases are being combined. 6. Bring BOTH solutions AND your calculations to Mrs. Nielsen for approval. 7. Dispose of the solutions down the sink. Scrub your beakers. Rinse volumetric flasks ree times since they cannot be scrubbed on the inside. Calculations: 1. Calculate the volume (mL) of 0.50 M NaCl stock solution needed to make 100 mL of a diluted solution with a concentration of 0.03 M. (Hint: Use M.Vi=MzV2) Volume = 6ml 2. What is the percent by mass of NaCl in your diluted solution? (Hint: There are 3 steps - first find the #of moles of NaCl, then convert to the number of grams, then find the percent mass. Use the mass of solution = 100.0g)
Answers
To calculate the volume of the 0.50 M NaCl stock solution needed to make 100 mL of a diluted solution with a concentration of 0.03 M, we can use the equation M1V1 = M2V2. The volume of the 0.50 M NaCl stock solution needed to make 100 mL of a diluted solution with a concentration of 0.03 M is 6 mL. The percent by mass of NaCl in the diluted solution is approximately 0.17532%.
Given:
M1 = 0.50 M (concentration of stock solution)
V1 = ?
M2 = 0.03 M (desired concentration of diluted solution)
V2 = 100 mL (volume of diluted solution)
Using the equation, we can solve for V1:
M1V1 = M2V2
0.50 M * V1 = 0.03 M * 100 mL
V1 = (0.03 M * 100 mL) / 0.50 M
V1 = 6 mL
Therefore, the volume of the 0.50 M NaCl stock solution needed to make 100 mL of a diluted solution with a concentration of 0.03 M is 6 mL.
To calculate the percent by mass of NaCl in the diluted solution, we need to determine the mass of NaCl in the solution and then calculate the percentage based on the total mass of the solution.
Given:
Mass of solution = 100.0 g
To find the mass of NaCl, we need to know the molar mass of NaCl, which is approximately 58.44 g/mol.
First, calculate the moles of NaCl in the solution:
Moles = Molarity * Volume
Moles = 0.03 M * 0.1 L (convert 100 mL to liters)
Moles = 0.003 moles
Next, convert moles to grams using the molar mass of NaCl:
Mass = Moles * Molar Mass
Mass = 0.003 moles * 58.44 g/mol
Mass = 0.17532 g
Finally, calculate the percent by mass:
The percent by mass = (Mass of NaCl / Mass of solution) * 100
The percent by mass = (0.17532 g / 100.0 g) * 100
Percent by mass = 0.17532%
Therefore, the percent by mass of NaCl in the diluted solution is approximately 0.17532%.
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Related Questions
Hello guys could you please help me with this ASAP??
PLS BE RELEVANT I REALLY NEED THIS :):
QUESTION:
- Why are placebos useful in human studies?
Answers
Answer:
So that the researchers know how much of the result is a trick of your mind and how much of the result is real.
Explanation:
So first, in order to answer this question we need to know what a placebo is.
Placebo: any treatment that has no active properties, like a sugar pill.
Now we ask ourselves, how could a placebo be something of interest in human studies?
Our brains are amazing things and can connivence themselves many things. Hints the phrase "placebo effect" that is very common in the medical field.
The placebo effect (a positive effect produced by a placebo drug or treatment, which cannot be attributed to the properties of the placebo itself, and must therefore be due to the patient's belief in that treatment) is a really good example as to why they are useful in human studies.
How else could you know was a true effect or just something someone believed would happen anyway?
which of the following information is needed to complete a cms-1500 form?
Answers
The CMS-1500 form requires patient information, provider information, date of service, procedure codes, diagnosis codes, charges, insurance information, and signature.
The CMS-1500 form is a standard document used by healthcare providers to bill for services provided to patients. To complete the form accurately, several pieces of information are required. These include:
Patient information: The patient's name, address, date of birth, and insurance information must be included on the form.
Provider information: The name, address, and National Provider Identifier (NPI) number of the healthcare provider must be included.
Date of service: The date on which the healthcare services were provided to the patient.
Procedure codes: Each healthcare service provided must be assigned a specific procedure code, which is used to identify the service and determine the appropriate payment.
Diagnosis codes: Each medical condition or symptom for which the patient is being treated must be assigned a specific diagnosis code.
Charges: The total charges for the services provided must be listed on the form.
Insurance information: If the patient has insurance, the policy number, group number, and other relevant information must be included on the form.
Signature: The healthcare provider must sign the form to certify that the information provided is accurate and that the services were actually provided to the patient.
All of this information is required to complete a CMS-1500 form accurately and ensure that healthcare providers are properly reimbursed for the services they provide to patients.
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Exercise 2. Consider the discrete-time signal x[n]=−2δ[n]−δ[n−1]+δ[n−3]+2δ[n−4] where δ[n] is the unit impulse function. A) Derive the energy and the time-averaged power of signal x[n] over −[infinity]
Answers
Given, discrete-time signal is as follows; x[n] = -2δ[n] - δ[n-1] + δ[n-3] + 2δ[n-4] The time-averaged power of a signal x(t) is defined as the average of the square of the absolute value of the signal over time T.
It is given by; \(Pav = lim (T → ∞) {1/T ∫[x(t)]^2 dt}\) joules For a discrete-time signal x(n), the power can be defined by replacing the integral with summation as;\(P[n] = 1/N ∑_{n=0}^{N-1} |x(n)|^2\)joules where N is the total number of samples in the signal. Let's find the energy of the given signal;
E[n] = ∑_{n= -∞}^{∞} |x(n)|^2Let's calculate E[n] for \(n=0;x[0] = -2δ[0] - δ[-1] + δ[-3] + 2δ[-4]δ[-1] = 0, δ[-3] = 0\), δ[-4] = \(0x[0] = -2δ[0]x[0]^2 = 4δ[0]^2 = 4E[0] = 4\) joules Let's calculate E[n] for n=1; \(x[1] = -2δ[1] - δ[0] + δ[-2] + 2δ[-3]δ[-2] = 0\), \(δ[-3] = 0x[1] = -δ[0] - 2δ[1]x[1]^2 = δ[0]^2 + 4δ[1]^2 + 4δ[0]δ[1] = 4δ[1]^2E[1] = 4\) joules.
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a police officer may issue a ticket when a vehicle is being operated on a highway using a sound amplification system, radio, or tape player, etc. If this sound amplification can be heard outside the vehicle at a distance of:
Answers
Answer:
50 feet or more
Explanation:
In order to quickly respond to hazardous situation in a timely manner, it is important to be alert with all senses and there are situations such as while driving , the present of an hazard can only be heard, such as when other cars honk their horns
As such a citation can be issued by a police officer when a vehicle travels through the highway while using a sound amplification system which can be heard at a distance of 50 or more ft. outside the vehicle.
A police officer may issue a ticket when a vehicle is being operated on a highway using a sound amplification system, radio, or tape player, etc. If this sound amplification can be heard outside the vehicle at a distance of Fifty (50) feet or more.
Reaching one destination safely without any accidents is largely in the hand of the driver. As the auto vehicle can be a most deadly weapon and highway may be the most dangerous place in the world some of the rules is been implemented to ensure the safety of the people on the highways.
With open senses, the driver prevents any accidents. To prevent any accidents and respond within time. Driver must keep open his ears if any other driver is honking their horns.
Thus, A police officer may issue a ticket when a vehicle is being operated on a highway using a sound amplification system, radio, or tape player, etc. If this sound amplification can be heard outside the vehicle at a distance of Fifty (50) feet or more.
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A barrel ride at an amusement park
starts from rest and speeds up to
0.520 rev/sec in 7.26 s. What is
the angular acceleration during
that time?
Answers
The angular acceleration of the barrel ride at the amusement park during the 7.26 seconds is approximately 0.450 radians/sec².
To determine the angular acceleration of the barrel ride, we need to use the following formula:
angular acceleration (α) = (ω_final - ω_initial) / t
where ω_final is the final angular velocity, ω_initial is the initial angular velocity, and t is the time taken.
In this case, the barrel ride starts from rest, so ω_initial is 0 rev/sec. The final angular velocity, ω_final, is given as 0.520 rev/sec. The time taken, t, is 7.26 seconds.
Before we plug the values into the formula, let's convert the final angular velocity from rev/sec to radians/sec. To do this, we use the conversion factor:
1 rev = 2π radians
So, ω_final = 0.520 rev/sec × 2π radians/rev ≈ 3.265 radians/sec
Now, let's calculate the angular acceleration:
α = (ω_final - ω_initial) / t
α = (3.265 radians/sec - 0 radians/sec) / 7.26 sec
α ≈ 0.450 radians/sec²
Therefore, the angular acceleration of the barrel ride during the 7.26 seconds is approximately 0.450 radians/sec².
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Wong found three unknown substances. He carried out some tests to gather their properties. See his data below. Use his data to classify each substance.
Answers
Based on the properties of the substances:
substance A is a metalloidsubstance B is a non-metalsubstance C is a metal.What are the classification of elements?Elements are substance which can not be split into simpler units by a ordinary chemical process as they consists entirely of the same types of atoms.
Elements are classified into three, namely:
metals,metalloids, andnon-metalsThe three classes of elements have different properties.
The properties of metals include the following:
ShinyMalleableHardGood Conductor of Electricity and HeatExamples are Gold and Iron
The properties of metalloids include the following:
they are semi-conductorsthey are found in Computer ChipsSemi-metalsThe properties of non-metals include the following:
May be BrittlePoor Conductor of Electricity and Heatmay be gases, liquids or solidsTherefore, substance A is a metalloid; substance B is a non-metal; substance C is a metal.
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In an electrical circuit, what happens to the current flowing through the wire if the initial voltage of 18 V is doubled, and the initial resistance of 35 Ohms is reduced by a factor of 4?
ANSWER QUICKLY PLEASE! ITS URGENT!
Answers
The current is increased by a factor of 8.
From 18/35 A. to 144/35 A.
The electric current changes from 0.514 ampere to 4.14 ampere, i.e, electric current flow in the circuit increases 8 times.
What is electric current?A stream of charged particles, such as electrons or ions, travelling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control volume is how it is calculated.
Initial electric current flowing through the circuit = (18 volt ÷ 35 ohms)
= 0.514 ampere.
When the initial voltage of 18 V is doubled, and the initial resistance of 35 Ohms is reduced by a factor of 4, electric current flowing through the circuit will be = (2 × 18 volt )÷ (35 ohms÷4)
= 4.114 ampere.
Hence, electric current changes from 0.514 ampere to 4.14 ampere, i.e., electric current flow in the circuit increases 8 times.
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Hey you know these safety barriers you see on the freeway all the time? Explain the physics behind how the safety barriers help save lives during car accidents.
Answers
In the event of an accident or a car crash, road safety barriers and fences prevent automobiles from running off the road.
Which laws explain the physics behind the safety barriers and their use ?Newton's Three Laws of Physics can help explain what these safety barriers are and how they help to save lives during car accidents :
I. Unless acted upon by an imbalanced force, an object at rest will remain at rest, and an object at constant velocity will remain at constant velocity.
II. If an imbalanced force occurs, a mass will experience acceleration proportional to its magnitude.
III. When you apply a force to an object, you will feel a force that is equal in magnitude but opposite in direction.
What are the reasons for installing road safety barriers ?To protect and prevent out-of-control automobiles from entering other vehicles' lanes. As a result, the safety road barriers are installed in the middle of the road.To keep the automobiles from sliding down an incline. If there is a drop of 5 meters or more along the road, the road safety barriers should be put at one end of the road.To keep an out-of-control car from collapsing and colliding with a roadside obstacle. If there are numerous items along the road, such as large traffic signs, bridge piers, poles, and so on, safety road barriers should be built on one end of the road.Can learn more about safety barriers from https://brainly.com/question/17086354
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The Rodriguez family roasted marshmallows over a campfire one night. They noticed that they all had to help carry the logs to the backyard, but only one of them had to sweep up the ashes and carry them away. In other words, the mass of the ashes was much less than the mass of the original logs. The mass of the logs was 10Kg before burning and after combustion, the ashes had a mass of 1Kg
Write a CER for this please!
Answers
The total mass of the system after combustion is therefore 1Kg (ashes) + 9Kg (gases and water vapor) = 10Kg, which is the same as the total mass before combustion.
What is law of conservation of mass?Therefore, if the mass of the logs before burning was 10Kg, the total mass of the system before combustion was 10Kg (logs) + 0Kg (oxygen) = 10Kg. After combustion, the mass of the ashes was 1Kg, so the mass of the remaining gases and water vapor released into the atmosphere was 10Kg - 1Kg = 9Kg.
What are the three laws of energy conservation?There are three fundamental quantities in mechanics that are conserved. These are power, forward motion, and angular momentum.
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A 20 kg sled stars at the top of a hill which is 10 m above the bottom and slides a distance of 50 m, ending at the bottom of the hill with a speed of 8 m/s. During the slide, the work done by gravity is about
Answers
Answer:
80 Joules.
Explanation:
Given that a 20 kg sled stars at the top of a hill which is 10 m above the bottom and slides a distance of 50 m, ending at the bottom of the hill with a speed of 8 m/s. During the slide, the work done by gravity is about ?
The parameters given are:
Mass M = 20 kg
Height h = 10 m
Velocity V = 8 m/s
The workdone by gravity will be equal to the total energy
At the bottom of the hill, the total energy will be equal to the maximum kinetic energy.
Maximum K.E = 1/2mv^2
K.E = 1/2 × 20 × 8
K.E = 80J
Therefore, the workdone by the gravity is equal to 80 Joules.
please answer this question first one to answer the right answer will be marked brainiest
Answers
Answer: Force per unit area. Explanation: P = 25/20. P = 5/4 Pascal or 1.25 Pascal
Explanation: is this what you were looking for
A person of mass 62 kg walks into an elevator and pushes the "up" button. As the elevator starts wot move, it has an acceleration of magnitude 2.50 m/s . Start each of the following parts with a free-body diagram.
a) Once the elevator begins to accelerate, what is the normal force that the floor or the elevator exerts on the person?
b) If the person is holding a 3.85 kg package by a light vertical string, what is the tension in this string once the elevator begins accelerating?
c) If the person pushed the "down" button instead of the up button, then the elevator will accelerate down with a magnitude of 2.50 m/s What would the normal force on the person be in this case?
Answers
155 N
a) Once the elevator begins to accelerate, the normal force that the floor or the elevator exerts on the person is equal to the person's weight of 62 kg multiplied by the acceleration of the elevator, which is 2.50 m/s2.
This is calculated as F = m*a, where m is the mass of the person and a is the acceleration of the elevator.
Therefore, the normal force is equal to 155 N.
b) If the person is holding a 3.85 kg package by a light vertical string, the tension in the string once the elevator begins accelerating is equal to the mass of the package, 3.85 kg, multiplied by the acceleration of the elevator, which is 2.50 m/s2.
This is calculated as F = m*a, where m is the mass of the package and a is the acceleration of the elevator.
Therefore, the tension in the string is equal to 9.625 N.
c) If the person pushed the "down" button instead of the up button, then the elevator will accelerate down with a magnitude of 2.50 m/s. The normal force on the person in this case is equal to the person's weight of 62 kg multiplied by the acceleration of the elevator, which is 2.50 m/s2. This is calculated as F = m*a, where m is the mass of the person and a is the acceleration of the elevator.
Therefore, the normal force is equal to 155 N.
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Newton's Law of Inertia states that ________.
Answers
Answer: It states that an object in motion will stay in motion, and an object at rest will stay at rest unless acted upon by an unbalanced force.
Explanation:
hope i helped
Answer: A object that is currently in motion will stay at motion. The law of interia is also known as Newton's first law of motion.
Explanation:
Farley Inc. has perpetual preferred stock outstanding that sells for $40 a share and pays a dividend of $3.50 at the end of each year. What is the required rate of return? Round your answer to two decimal places.
Answers
The required rate of return for the Farley Inc. has perpetual preferred stock outstanding that sells for $40 a share is 8.75%.
A pace of return (RoR) can be applied to any venture vehicle, from land to bonds, stocks, and artistic work. The RoR works with any resource gave the resource is bought at one particular moment and produces income sooner or later. Past rates of return, which can be compared to assets of the same type to determine which investments are most appealing, are part of how investments are evaluated. Before making an investment decision, many investors prefer to select a required rate of return.
Stocks and bonds' rate of return calculations are slightly different. Expect a financial backer purchases a stock for $60 an offer, claims the stock for quite a long time, and procures an aggregate sum of $10 in profits. The investor's per-share gain is $20 if the stock is sold for $80. In addition, he has obtained a dividend income of $10, resulting in a total gain of $30, or $20 plus $10. The pace of return for the stock is in this manner a $30 gain for each offer, partitioned by the $60 cost per share, or half.
On the other hand, suppose an investor purchases a $1,000 $1,000 par value 5% coupon bond and pays $1,000 for it. Each year, the investment receives $50 in interest income. The investor's rate of return is the sum of the $100 gain on the sale and the $100 interest income divided by the $1,000 initial cost, or 20%, if the bond is sold for $1,100 at premium value and the investor earns $100 in total interest.
Required rate of return:
Vp = Dp/rp
40 = 3.50/rp
rp = 3.50/40
rp = 0.0875 = 8.75%.
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7. A sprinter accelerates from rest to a velocity of 12 m/s in the first 6
seconds of the 100-meter dash.
What is the acceleration in the first 6 seconds?
b. How far does the sprinter travel during the first 6 seconds?
Answers
Answer: a) 36 m/s
B) 64 m
Explanation:
A) d= ½ (Vi+Vf)t
d= ½ (0+12)6
d= 36 m/s
B) 100 – 36 = 64
can anyone help me with this please
Answers
Answer:0.99 N
Explanation:
1200 N F
|||||||||||| = |||||||||||||||||||
3.2 m2 0.0075m2
F=0.99
A student measured the density of gold to be 18.5 g/c^3. The accepted value of the density of gold is 19.3 g/cm^3. What is the percent error of the student's measurement?
A. 4.15%
B. 2.11%
C. 5.92%
D. 0.60%
Answers
Answer:
A
Explanation:
A metal bar is in the xy-plane with one end of the bar at the origin. A force F=(6. 82)i+ -3. 24j is applied to the bar at the point x=3. 87m , y=3. 21m.
What is the position vector r for the point where the force is applied?
a Express your answer in terms of the unit vectors i and j.
b What are the magnitude of the torque with respect to the origin produced by F?
c What are direction of the torque with respect to the origin produced by F?
Answers
The position vector r for the point where the force is applied is r = 3.87i + 3.21j. The magnitude of the torque produced by the force is 10.345 Nm. The direction of the torque produced by the force F with respect to the origin is given by the right-hand rule.
a) The position vector r for the point where the force is applied is:
r = 3.87i + 3.21j
b) The magnitude of the torque produced by the force F with respect to the origin is given by:
τ = r × F
|τ| = |r||F|sinθ
|τ| = |r||F|sinθ = rxFz = (3.87i + 3.21j) × (-3.24k) = 10.345k
Therefore, the magnitude of the torque produced by the force is 10.345 Nm.
c) The direction of the torque produced by the force F with respect to the origin is given by the right-hand rule. If we curl our fingers in the direction of r and then bend them towards the direction of F, then the direction our thumb points in is the direction of the torque.
Torque refers to the turning or rotational force that causes an object to rotate around an axis or pivot point. It is also known as the moment of force. Torque is a vector quantity and is defined as the product of the force applied and the lever arm or the distance between the axis of rotation and the point of application of the force.
Torque is an important concept in many areas of physics, including mechanics, electromagnetism, and quantum mechanics. It plays a crucial role in the understanding of the behavior of rotating objects, such as wheels, gears, and turbines. The magnitude of the torque determines the rate at which an object rotates, and the direction of the torque determines the direction of the rotation.
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the distance traveled over a period of time is called:
Answers
What is Stefan Boltzmann Law?
Answers
The radiation emitted from an area A of a black body at absolute temperature T is directly proportional to the fourth power of the temperature, according to Stefan Boltzmann's equation.
Mathematically, u/A = σ T⁴
where,
σ is Stefans's constant(5.67 × 10⁻⁸ W/m²k⁴)
According to the equation above, a body that is not a black body receives less radiation and consequently emits less of it.
For such a body, u = e σ A T⁴
where,
e is emissivity(value lies between 0 and 1)
With the surrounding temperature T₀, energy radiated by an area per unit time.
Δu = u - u₀ = e σ A (T⁴ - T₀⁴)
The blackbody's temperature and the quantity of power it emits per unit area are related by Stefan Boltzmann's law. The total energy emitted or radiated by a black body per unit surface area across all wavelengths and per unit time is directly proportional to the fourth power of the black body's thermodynamic temperature, according to the law.
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Suppose Alex is navigating using a compass. She starts walking at an angle of 60° north of east and walks a total of 100 m. How far north is she from the starting point? How far east?
Answers
Answer:
\(50\:\mathrm{m\: North}\\50\sqrt{3}\:\mathrm{m\: East}\)
Explanation:
We can create a 30-60-90 triangle. The distance she walked is then the hypotenuse of the triangle, and using 30-60-90 triangle rules, we have the following:
The North leg is opposite to the \(30^{\circ}\) angle. Therefore, if we call this distance \(y_N\), we have the following:
\(\sin 30^{\circ}=\frac{y_N}{100},\\\frac{1}{2}=\frac{y_N}{100},\\y_N=\fbox{$50\:\mathrm{m}$}\).
The East leg is opposite to the \(60^{\circ}\\\) angle. If we call this distance \(x_E\), we have:
\(\sin 60^{\circ}=\frac{x_E}{100},\\\frac{\sqrt{3}}{2}=\frac{x_E}{100},\\x_E=\fbox{$50\sqrt{3}\:\mathrm{m}$}\).
If military strategists understand wave behavior, what impact could that have on the armed forces?
Answers
Answer:
they may find ways of solving wars without fighting
Explanation:
This is because when the military understand why the other nation is planning a war they can resolve it simply
Which is not an Ultimate Frisbee rule?
Answers
Step by step explanation
18. A vertical spring has a length of 25cm when a 150g mass is hung from its end and its length is 30cm with 250g hanging from it. What is the spring constant? a) 19.6N/cm b) 19.6n/m c) 109.6N/m d) 19.6N/m e) 19.6N/km
Answers
The spring constant of the spring is 19.6 N/m.
The correct answer is option D.
What is the spring constant of the spring?
The spring constant of the spring is calculated by applying the following equation as shown below.
Mathematically, the formula of Hooke's law is given as;
F = kx
where;
F is the applied forcek is the spring constantx is the extension of the springk = F / x
the extension of the spring when the 250 g mass was hung on it is calculated as;
x = 30 cm - 25 cm
x = 5 cm = 0.05 m
The spring constant of the spring is calculated as;
k = ( mg ) / x
where;
m is the additional mass = 250 g - 150 g = 100 gk = ( 0.1 x 9.8 ) / ( 0.05 )
k = 19.6 N/m
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Blank explains why earth's distance from the sun varies over the course of each year.target 1 of 6
Answers
The distance from Sun to Earth varies each year due to the difference in orbits. It is due to Tidal stress.
Earth is pulled along in the Sun's orbit around the galaxy. The motion of the sun causes a slight distortion in the planets' orbits as Earth travels around our star. Earth’s orbit is therefore elliptical, or somewhat egg-shaped. The Moon experiences the same effects due to Earth's motion and the Moon's gravitational pull. It is known as tidal stress.
Earth's orbit is slightly elliptical because it is not a perfect circle. And as a result, Earth is either moving from the perihelion point to the aphelion point (constantly getting closer to the Sun) or from the aphelion point to the perihelion point (constantly getting farther from the Sun).
Thus, the above phenomenon can be explained through tidal stress.
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Which of these describes a real image?
Answers
I have no idea but this is my best guess as a sophomore in college
How is speed related to kinetic energy?
Answers
Answer:
K.E. = 1/2mv^2
Explanation:
v is velocity (a vector) not speed (a scalar) but they have the same magnitude
What exerts pressure in all directions?
Answers
Answer: Gases
Explanation: Gases don't have a certain direction, so they go in all directions.
DC current is less than AC current
true\false
Answers
Answer:
False
Explanation:
.......................
Hope this help you
Students are asked to design an experiment about Newton’s 2nd Law. One student decides to roll a marble down a ramp into a pile of sand to measure the force impact.
Which variable should she manipulate to best exemplify the relationship explained by this law?
A.She should use a heavier marble, because the marbles will roll at the same rate of acceleration but more mass will produce a larger impact force.
B.She should increase the slope of the ramp by propping it up to higher height, because a steeper ramp will cause a greater rate of acceleration and a larger impact force.
C.She should use a heavier marble, because a bigger marble will accelerate more quickly down the ramp and cause a greater impact force.
D.She should decrease the slope of the ramp, because a ramp with a smaller slope will allow the ball more time to build up speed and cause a greater impact force.
Answers
Answer:
A
Explanation:
Trust me I just took it !