The expression for the average (rms) distance traveled by a diffusing molecule in 3 dimensions is Rrms = √(6Dt) (Option B).
We are given the 1-dimensional root-mean-square (rms) distance formula, Xrms = √(2Dt). We can find the expression for the average (rms) distance traveled by a diffusing molecule in 3 dimensions.
In 3 dimensions, the rms distance, Rrms, is calculated using the Pythagorean theorem, considering the rms distances in each dimension (X, Y, and Z) as the sides of a right triangle:
Rrms² = Xrms² + Yrms² + Zrms²
Since Xrms = Yrms = Zrms = √(2Dt), we can substitute these into the equation:
Rrms² = (√(2Dt))² + (√(2Dt))² + (√(2Dt))²
Rrms² = 3(2Dt)
Now, take the square root of both sides to find the expression for Rrms:
Rrms = √(6Dt)
So, the average (rms) distance traveled by a diffusing molecule in 3 dimensions is Rrms = √(6Dt).
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at+waht+temperature+must+you+run+this+reaction+to+achieve+97%
Temperature is the degree of hotness or coldness of an object or substance. The SI unit of temperature is Kelvin."97%": The question suggests that a reaction must be run at a specific temperature to achieve 97% yield or completion. Yield refers to the amount of product obtained from a reaction.
To achieve 97% yield or completion, the reaction must be run at a specific temperature. Temperature plays an essential role in chemical reactions since it affects the rate of reaction, activation energy, and equilibrium. The temperature at which a reaction runs optimally, producing the most product, is known as the reaction's optimum temperature. As a result, the temperature must be controlled during a chemical reaction.To achieve 97%, the reaction must be run at a specific temperature.
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what are the invisible forces of nature
Answer:
Gravity, Friction, Air resistance, magnetism, static electricity
Explanation:
Answer:
gravity friction air resistant are a few
(a) calculate the classical momentum of a neutron traveling at 0.999c, neglecting relativistic effects.
The classical momentum of a neutron is given by:p = mv p=mv where $m$ is the mass of the neutron and $v$ is its velocity. Neglecting relativistic effects,
The mass of the neutron remains constant, so we can simply use the classical expression for momentum.The mass of a neutron is approximately $1.675\times 10^{-27}$ kg. The velocity of the neutron is $0.999c$, where $c$ is the speed of light.Momentum is a physical quantity that is defined as the product of an object's mass and its velocity. It is a vector quantity and its direction is the same as that of the object's velocity. The formula for momentum is \vec {p} = m\vec{v}where $\vec{p}$ is the momentum vector, $m$ is the mass of the object, and $\vec{v}$ is its velocity vector. The SI unit of momentum is kg m/s, and it is conserved in isolated systems.
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A heavy ball with a weight of 130 N
is hung from the ceiling of a lecture hall on a 4. 4-m
-long rope. The ball is pulled to one side and released to swing as a pendulum, reaching a speed of 5. 4 m/s
as it passes through the lowest point
221 N is the tension in the rope when the ball reaches a speed of 5.4 m/s as it passes through the lowest point.
The given data is as follows:
Weight of ball = 130N
Hung distance = 4.4 m
Speed = 5. 4 m/s
The tension on the rope as the ball moves via the lowest point of the circular motion because it is a pendulum is calculated as follows:
T - mg = ((mv)^2) / r
T = mg + [(mv)^2] / r
"g" is the acceleration due to gravity and mass "m" is to be calculated by the formula:
W = mg
m = W/g
m = (130)/9.8 = 13.27 kg
The tension on the rope due to the moment in the ball is calculated as;
T = 130 + [13.27* (5.5)^2]/4.4
T = 130 + 91.23
T = 221 N.
Therefore we can conclude that the tension in the rope at that point is 221 N.
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The complete question is-
A heavy ball with a weight of 130 N is hung from the ceiling of a lecture hall on a 4.4-{\rm m}-long rope. The ball is pulled to one side and released to swing as a pendulum, reaching a speed of 5.4 m/s as it passes through the lowest point. What is the tension in the rope at that point?
Can ya pls answer dis rq!
Answer:
For vegetarians beans
Explanation:
Because it's plant protein and very proteinious
After rubbing the hair on your head with a balloon, you determine there are 2.4 x 1018 electrons on your head. What is the charge, in coulombs (C), of your head?
Answer:
q = 0.384 C
Explanation:
The total charge present at the head can be easily found out by multiplying the charge on a single electron with the total number of electrons present on the head:
\(q = ne\)
where,
q = total charge on head = ?
n = total no. of electrons on the head = 2.4 x 10¹⁸
e = charge on 1 electron = 1.6 x 10⁻¹⁹ C
Therefore,
\(q = (2.4\ x\ 10^{18})(1.6\ x\ 10^{-19}\ C)\)
q = 0.384 C
The world’s fastest elevator is in Taipei, Taiwan. It can lift passengers 1,010 m in 39 s. What is the speed of this elevator?
Answer: 25.90 m/sec
Explanation:
Speed = Distance / Time
Speed = 1010 / 39
Speed = 25.90 m/s
Newton's Laws of Motion and Newton's Law of Gravity explain why?
a) the Earth moves around (orbits) the Sun.
b) the Moon moves around Earth
c) an apple from a tree falls down to ground (as opposed to "rising up into the sky")
d) all of the above
Answer:
D all of the above
Explanation:
This is because newtons laws of motion explains movement of a body due to a force applied while that of gravity explains motion of a body under gravity and this captures a, b, and c
All the given options are following the Newton's laws of motion and Newton's law of gravity separately. All of the above options are correct. Hence, option (d) is correct.
The given problem is based upon the Newton's law of motion as well as Newton's law of gravity. So let us analyze each of the given cases as:
(a)
The Earth moves around the Sun : This statement follows the Newton's first law of motion, which says that an object will continue its state of motion, until any external force is being applied on the object. Since, Earth is offered with no net force. Therefore, Newton's law is applicable.
(b)
Moon movers around Earth: This statement also follows the above explanation for the Newton's first law. Which makes moon to revolve around the Earth on an account of no net force. Hence, it will continue its circular motion and hence Newton's law of motion is followed.
(c)
An apple falls from a tree: This statement is based on Newton's law of gravity, which says that every particle in the universe attracts other particles such that the force of attraction is directly proportional to the product of their masses and inversely proportional to square of distance between them. Since, Earth has more mass than apply, therefore Earth will attract the apple downwards.
Thus, we can conclude that all the given options are following the Newton's laws of motion and Newton's law of gravity separately. All of the above options are correct. Hence, option (d) is correct.
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Compared to a cluster containing type O and B stars, a cluster with only type F and cooler stars will be
Compared to a cluster containing type O and B stars, a cluster with only type F and cooler stars will be less luminous and have a lower surface temperature.
Type O and B stars are much hotter and brighter than type F and cooler stars. They have surface temperatures over 10,000 K and are several hundred times more luminous than the Sun. On the other hand, type F and cooler stars have surface temperatures ranging from 6,000 K to less than 3,500 K and are much less luminous than O and B stars.
Therefore, a cluster containing only type F and cooler stars will not shine as brightly and will have a lower surface temperature compared to a cluster with type O and B stars.
Stellar clusters are groups of stars that are gravitationally bound and formed from the same molecular cloud. Stars within these clusters can be of various types, based on their surface temperatures and luminosities, which are classified using the Morgan-Keenan (MK) system. Type O and B stars are hotter, more massive, and more luminous than type F and cooler stars.
Type O and B stars have shorter lifespans due to their higher mass and faster rate of nuclear fusion, while type F and cooler stars have longer lifespans. When a cluster is young, it may have a mix of various star types, including O and B stars. However, as the cluster ages, the O and B stars will exhaust their nuclear fuel and end their lives, leaving behind the longer-lived F and cooler stars.
Therefore, a cluster with only type F and cooler stars indicates that it has evolved for a longer time compared to a cluster containing type O and B stars, making it an older cluster.
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nonmetals and metals do different things when it comes to their valence electrons. one seeks to gain and the other lose. which is which?
Answer:
Nonmetals gain
while metals lose
What are the fastest spinning objects known in the universe?
What keeps you in your seat during a loop-the-loop rollercoaster?
1) neuron stars
2) centrifugal force
What word
When an object is vibrating, we say that it has energy in its kinetic energy___
completes the sentence?
Answer:
that is which produces Sound
Answer:
The right answer is "stores"
Explanation:
All objects that are moving will have some energy in their kinetic energy store.
Discuss how directions fields and Euler's method are related. Draw the direction field and use Euler's method to approximate the solution at t = 10 using step size 1, for the initial value problem y'= -3y, y(0) = 5.
By Using Euler's method with two steps, we can find the approximate value of Y(2) is 2.125. , where Y is the solution of the initial value problem dy/dx = x - y, and Y(1) = 3.
Euler's method is defined as a numerical technique which is used to approximate solutions into ordinary differential equations. The method includes dividing the interval of interest into smaller steps and thereafter approximating the solution at each step by using the derivative of the function.
In this case, we are given the initial value problem dy/dx = x - y, with the initial condition Y(1) = 3. To approximate Y(2) using Euler's method with two steps, we will divide the interval [1, 2] into two equal steps.
Step 1:
We start with the initial condition Y(1) = 3. Using the differential equation dy/dx = x - y, we can approximate the value of Y at the midpoint of the interval [1, 2].
Using the step size h = (2 - 1) / 2 = 0.5, we can calculate Y(1.5) as follows:
Y(1.5) ≈ Y(1) + h × (x - y) = 3 + 0.5 × (1.5 - 3) = 3 + 0.5 × (-1.5) = 2.25
Step 2:
Now, using the value of Y(1.5) as the new approximation, we calculate Y(2) using the same process:
Y(2) ≈ Y(1.5) + h × (x - y) = 2.25 + 0.5 × (2 - 2.25) = 2.25 + 0.5 × (-0.25) = 2.125
Thus, by using Euler's method with two steps, the approximate value of Y(2) is 2.125.
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The complete question is
Use Euler's Method With Two Steps To Approximate Y(2), Where Y Is The Solution Of The Initial Value Problem: Dy : X − Y, Y(1) = 3
As shown in the figure below, Jenna rushes 30 m toward her truck. She notices she forgot her jacket and
returns back to the house. Her total travel time is 75 s.
30 m
30 m
What is Jenna's average velocity over the 75 s period?
What is Jenna's average speed over the 75 s period?
Answer:
Average Velocity: 0
Average Speed 0.8
Explanation:
Velocity - (30-30)/75 = 0
Speed - (30+30)/75 = 0.8
: Prove that the following paraboloid coordinate system (u, v, ϕ):
x = u.v cosϕ
y = u.v sinϕ
z = 1/2 (u2 - v2)
is orthogonal, and then find the following:
1. The scale factors
2. Gradient
3. Divergent
4. Curl
5. Laplacian
The given paraboloid coordinate system (u, v, ϕ) with x = u.v cosϕ,
y = u.v sinϕ , z = 1/2 (u2 - v2) is orthogonal. The gradient is ∇f = (∂f/∂u) e_u + (∂f/∂v) e_v + (∂f/∂ϕ) e_ϕ ; divergent is ∇²f = ∇ · (∇f) ; curl is (∇ x) and laplacian is (∇²).
We can prove that the paraboloid coordinate system (u, v, ϕ) is orthogonal, by computing the dot products of the basis vectors. The basis vectors in this coordinate system are given by:
e_u = (∂x/∂u, ∂y/∂u, ∂z/∂u) = (v cosϕ, v sinϕ, u)
e_v = (∂x/∂v, ∂y/∂v, ∂z/∂v) = (u cosϕ, u sinϕ, -v)
e_ϕ = (∂x/∂ϕ, ∂y/∂ϕ, ∂z/∂ϕ) = (-u.v sinϕ, u.v cosϕ, 0)
By Taking the dot products, we find that e_u · e_v = 0, e_v · e_ϕ = 0, and e_ϕ · e_u = 0. This proves that the basis vectors are mutually perpendicular, and therefore, the coordinate system is orthogonal.
Next, we can calculate the gradient (∇) in this coordinate system. The gradient of a scalar function f(u, v, ϕ) is given by:
∇f = (∂f/∂u) e_u + (∂f/∂v) e_v + (∂f/∂ϕ) e_ϕ
The divergence (∇ ·) and curl (∇ x) can be computed using the standard formulas in terms of the basis vectors. Finally, the Laplacian (∇²) can be obtained by taking the divergence of the gradient:
∇²f = ∇ · (∇f)
Thus, By evaluating these operations in the given coordinate system using the appropriate partial derivatives, we can determine the gradient, divergent, curl, and Laplacian for any scalar function in the (u, v, ϕ) coordinates.
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A calorimeter for which mc = 25 J K−1 contains
140 g of a liquid. An immersion heater is used to
provide energy at a rate of 40 W for a total time of
4.0 min. The temperature of the liquid increases by
15.8 °C. Calculate the specific heat capacity of the
liquid. State an assumption made in reaching this
result.
The liquid's specific heat capacity is 4.2 kJ kg⁻¹ K⁻¹.
In a calorimeter, mc = 25 J K⁻¹.
The calorimeter contains m(l) = 140 g = 140 × 10⁻³ kg of liquid.
The energy is provided at a rate of Q = 40 W for a time of 4 minutes.
The liquid's temperature increases by ΔT = 15.8° C = 15.8° K.
Q = mcΔT
The equation tells you how much heat is given (Q or E), how much of that heat changes the material's temperature T, and how much of that heat is applied to a mass-m material with a specific heat capacity (c).
Now, the heat supplied will be:
Q = mcΔT + m(liquid) c(liquid)ΔT
Q = mcΔT + m(l) c(l)ΔT
c(l) = ( Q - mcΔT ) / m(l)ΔT
Now, the heat supplied is Q = 40 W = 40 J/s = 40 × 4 × 60s = 9600 J
c(l) = { ( 9600 - 25 × 15.8 ) / [ (140 × 10⁻³) × 15.8 ] }
c(l) = ( 9600 - 395 ) / [ 2212 × 10⁻³ ]
c(l) = 9205 / 2212 × 10⁻³
c(l) = 4.1614 × 10³ = 4.2 kJ kg⁻¹ K⁻¹
The specific heat capacity of the liquid is 4.2 kJ kg⁻¹ K⁻¹.
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Water of mass 100 g at a temperature of 100 °C is converted into steam at 100 °C. The specific
latent heat of vaporisation of water is 2300 J/g.
How much thermal energy is absorbed by the water?
0 230 000
0 23 000 000 J
0 230 J
O 23 J
Answer:
The thermal energy absorbed by the water is 230,000 J.
Explanation:
Given;
mass of the water, m = 100 g
The specific latent heat of vaporization of water, L = 2300 J/g
temperature of the steam, θ = 100 °C
The thermal heat capacity or thermal energy absorbed by the water is calculated as follows;
H = mL
H = 100g x 2300J/g
H = 230,000 J
Therefore, the thermal energy absorbed by the water is 230,000 J.
Therefore
A book is at rest on a table. Identify the correct free-body diagram for this situation.
Answer:
the 3rd pic is correct
Explanation:
because the arrows are going away from each other.
What is the kinetic energy of a 200kg boat moving at 2.7m/s?
Answer:
729 JoulesExplanation:
Kinetic energy is 1/2mv²
where m is the mass of the object
v is the velocity
From the question
m = 200kg
v = 2.7m/s
Kinetic energy is
1/2 × 200 × 2.7²
= 729 Joules
Hope this helps you
An electric space heater draws 25.0 A from a 200 V source. It is operated, on the average, for 10.0 h each day.At AED 0.30 per kWh, how much does it cost to operate the heater for 15 days?
The cost of energy consumption to operate the heater for 15 days is $2.25
Voltage (V) = 200 V
Current (I) = 25 A
Power (P) = VI = 200 * 25 = 5,000 W
Now, the calculation of the energy consumption for 15 days in KW/h
We will convert W to kW,
1000 W = 1kW
Therefore,
5,000 W = 5000 W × 1 KW / 1000 W = 5kW
The daily energy consumption will be calculated. This is attainable as follows,
P = 5kW
Time(t) = 10 h
Energy (E) = P/t = 5/10 = 0.5 kW/h per day.
Finally, we will calculate the energy usage for the next 30 days. This is attainable as follows:
1 day = 0.5 kW
Cost of one day = 0.5 * 0.30 = $ 0.15
Now, the cost to operate the heater for 15 days = $ 15 * 0.15 = $2.25
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PLEASE HELPP I NEED TO PASS THIS !!
how many bit strings of length ten are there if the bit strings begin and end with a 1?
The number of bit strings of length ten that begin and end with a 1 can be calculated by considering the remaining eight positions in the string. The answer is 2^8, or 256 possible bit strings.
To determine the number of bit strings of length ten that begin and end with a 1, we can focus on the remaining eight positions in the string. The first position is already determined as 1, and the last position is also fixed as 1. Therefore, we only need to consider the possible configurations for the remaining eight positions.
Each of the eight remaining positions can be either 0 or 1, resulting in two choices for each position. Since the choices for each position are independent, the total number of possible bit strings is obtained by multiplying the number of choices for each position. Thus, the total number of bit strings is 2^8, which is equal to 256.
Therefore, there are 256 possible bit strings of length ten that begin and end with a 1.
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to calculate the value potential of an alliance/jv, we need to calculate
To calculate the value potential of an alliance/JV, factors such as synergies, market opportunities, financial projections, risk assessment, strategic fit, and governance need to be considered.
To calculate the value potential of an alliance or joint venture (JV), several factors need to be considered. These factors typically include:
Synergies: Assessing the potential synergistic effects of combining resources, capabilities, and expertise from the participating entities. This involves evaluating how the alliance or JV can create value that exceeds what each party could achieve individually.
Market Opportunities: Analyzing the market potential and growth prospects that the alliance or JV can tap into. This includes evaluating the target market size, customer demand, competitive landscape, and potential for market expansion.
Financial Projections: Developing financial forecasts and projections to estimate the potential revenue, costs, and profitability of the alliance or JV. This involves considering factors such as revenue streams, cost savings, investment requirements, and expected returns.
Risk Assessment: Identifying and assessing potential risks and uncertainties associated with the alliance or JV. This includes evaluating factors such as market volatility, regulatory changes, operational risks, and potential conflicts between the participating entities.
Strategic Fit: Evaluating the alignment between the participating entities' strategic objectives, core competencies, and business models. This involves assessing how the alliance or JV contributes to the strategic goals and competitive advantage of each party.
Governance and Management: Considering the governance structure, decision-making processes, and management capabilities required for the successful implementation and operation of the alliance or JV. This includes evaluating the roles and responsibilities of each party, communication channels, and conflict resolution mechanisms.
By analyzing these factors and conducting a comprehensive evaluation, stakeholders can calculate the potential value of an alliance or JV and make informed decisions regarding its feasibility, benefits, and risks.
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A charge of 6.0 mc is to be split into two parts that are then separated by 3.0 mm.what is the maximum possible magnitude of the electrostatic force between those two parts?
The electric force between the charges is 9 * 10^9 N.
What is the electrostatic force between those two parts?Let us imagine that the charge was split into two equal parts and we have them as q1 and q2. We can now be able too apply the formula that says;
F = Kq1 q2/r^2
K = electric constant = 9 * 10^9
q1 = 3 * 10^-3 C
q2 = 3 * 10^-3 C
r = 3 * 10^-3 m
We now have;
F = 9 * 10^9 * (3 * 10^-3 )^2/( 3 * 10^-3)^2
F = 9 * 10^9 N
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Problem 50 (8th edition) statement: helium is to be compressed from 105 kpa and 295 k to 700 kpa and 460 k. a heat loss of 15 kj/kg occurs during the compression process. neglecting kinetic energy changes, determine the power input required for a mass flow rate of 60 kg/min.
The input power required for a mass flow rate of 60 kg/min is calculated to be 871.35 kW.
Given that,
Initial temperature T₁ = 295 K
Final temperature T₂ = 460 K
Initial pressure P₁ = 105 k pa
Final pressure P₂ = 700 k pa
The specific heat loss from the compressor Q = 15 kJ/kg
The mass flow rate m = 60 kg/min
Refer to the properties of element to determine the specific heat of helium.
Cp = 5.19 kJ/kg.K
Apply the energy balance equation for calculating the input power.
W - m Q = m h₁ - m h₂
W - m Q = m (h₁ - h₂)
W - m Q = m Cp (T₁ - T₂)
where,
W is the input power
h₁ and h₂ are the initial and final enthalpy
Placing the values in the above expression, we have,
W - 60 kg/min (1 min/60 sec) × (-15 kJ/kg) = 60 kg/min (1 min/60 sec) × 5.19 kJ/kg.K (295 K - 460 K)
W = -871.35 kJ.s (1kW/1kJ) = -871.35 kW
Thus, the input power = 871.35 kW.
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Select the compensator zero to cancel one pole of GHP(z) {other than z=1}. α = Determine 3 based on the angle condition: zeros - 4poles = 180° You need to draw a figure as the Figure below to calculate ß = Im z-plane z = a + ib Zero of GHP(Z) Zzero Zpole(B) 0 B Figure: Determine ß Zpole(1) pole 1 of GHP(z) Re
The angle condition is: Zzero- (pole(1) + 4pole(B))= 180º Zzero = Zpole(1) = Zpole(B) = Determine the compensator gain k based on magnitude condition: z-α Gc (2) GHP (2)|2=a+ jb = 1 → k Ghp(2) = 1 z-ß |z=a+jb 1 k z-α GHP(z) |z-ß |z=a+jb Write down the final compensator (PID Controller) transfer function Gc(z)=kz-a z-ß
Analyze system dynamics and design compensator to achieve desired response by selecting compensator zero and canceling one pole of GHP(z).
How to select the compensator zero cancel one pole of GHP(z)?To select a compensator zero to cancel one pole of GHP(z), we need to use the given angle condition:
Zzero - (pole(1) + Zpole(B)) = 180°
Here, Zzero represents the compensator zero, pole(1) represents the first pole of GHP(z), and Zpole(B) represents the compensator pole.
Let's proceed with the solution step by step:
1. First, we need to determine the value of Zzero. The angle condition states that Zzero = Zpole(1), which means the compensator zero is equal to the first pole of GHP(z).
2. Now, we need to find the value of Zpole(B). We can rewrite the angle condition as follows:
Zpole(B) = Zzero - pole(1) + 180°
Since we already know that Zzero = Zpole(1), we can substitute Zzero in the above equation:
Zpole(B) = Zpole(1) - pole(1) + 180°
Simplifying further:
Zpole(B) = 180°
Therefore, the value of Zpole(B) is 180°.
To summarize, we can select the compensator zero (Zzero) to cancel one pole of GHP(z) as Zpole(1), and the compensator pole (Zpole(B)) is determined to be 180° based on the given angle condition.
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Convert 83 F to Kelvin
Explanation:
Formula:
F*255.92778=K
83 F *255.92778=301.48k
therefore the answer is:
301.48K
how does the buoyant force on block b compare to the buoyant force on block a at the instants they are released from the center of the tank? explain your reasoning.
The buoyant force on block B will be greater than the buoyant force on block A at the instant they are released from the center of the tank.
This is because block B has a greater density than block A, which means it has a greater mass and thus a greater buoyant force. The greater the mass of an object, the greater the buoyant force it experiences. However, according to the Archimedes principle, the buoyant force is really the weight of the fluid displaced. Therefore, the weight of the liquid that has been displaced by a floating object is equal to the weight of the object. Therefore, the buoyant force acting on an object only equals the object's weight in the particular case of floating.
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A large ball of gas that is held together by gravity and that has a core so hot that
nuclear fusion occurs is called a(n)
Based on the information in the table, choose whether the magnetic field is weak or strong
Current Number of Coils Magnetic Field Strength 0. 2 A Many _______________
5. 0 A Many _______________
5. 0 A Few _______________
put weak or strong in the blanks
Answer:
Explanation:
Field characteristics
The strength of the field at the Earth's surface ranges from less than 30 microteslas (0.3 gauss) in an area including most of South America and South Africa to over 60 microteslas (0.6 gauss) around the magnetic poles in northern Canada and south of Australia, and in part of Siberia.