Answer:
No, I do not agree with Diego's statement. The formula provided by Diego is incorrect for finding the arc length of a circle. To find the arc length of a circle, you need to use a different formula.
The correct formula to find the arc length of a circle is:
Arc Length = (Central Angle / 360) × (2πr),
where "Central Angle" is the measure of the central angle subtended by the arc, "r" is the radius of the circle, and "π" is a mathematical constant approximately equal to 3.14159.
The formula Diego provided, which suggests multiplying the measure of the central angle by the area of the circle, is not applicable for finding the arc length. The area of a circle and the arc length are different measurements and cannot be calculated using the same formula.
Need geometry help
Solve for x.
Answer:
your answer should be 15
Step-by-step explanation:
in need of help plz
Find the ∠VXW and ∠XVW
Answer:
∠VXW = 57°
∠XVW = 56°
Step-by-step explanation:
Firstly, we need to remember the sum of a triangle's angle ALWAYS equals 180°.
Next, we see that two angles of △XYZ are given to us; 58° and 65°. Adding these two numbers would give us 123°. Now we need to subtract 123 from 180 to find the ∠YXZ; 180° - 123° = 57°.
Once we have this number, we need to remember a straight line also measures 180°. Line YW is important to find our answer, but first we need to find the answer to ∠WXZ. Since ∠YXZ and ∠WXZ come together and create the line YW, we can easily find the answer to ∠WXZ by subtracting ∠YXZ with 180; 180° - 57° = 123°
Now we need to find ∠VXW keeping the previous things I mentioned in mind; 180° - 123° = 57°. This is the answer to our first angle ∠VXW.
Since a triangle's angles always equal to 180° and we have the answer to two angles in △XVW, all we need to do is add then subtract;
67° + 57° = 124°
180° - 124° = 56°
And that is your answer!
∠VXW = 57°
∠XVW = 56°
i need to get a good score! plss help!!!!
Answer:
82 is your answer
Step-by-step explanation:
3x6 = 18
8x8=64
18+64=82
Answer:
82 m²
Step-by-step explanation:
The blue figure is composed of a square ( on the right ) and a rectangle on the upper left )
Area of blue figure is the sum of the 2 areas , that is
Area = (8 × 8) + (6 × 3) = 64 + 18 = 82 m²
if someone knows how to do this please help !
h = 15
just plug in the numbers for the corresponding letters and then solve to get h by itself
What is the result of adding 3 to–3?
A)–6
B)–3
C) 0
D) 6
Answer:
c 0
Step-by-step explanation:
3+-3=0
who is galactus devourer of worlds
Answer:
Galactus is far and away the more powerful villain in Marvel lore. They don't call him the Devourer of Worlds for nothing. He's a cosmic villain who literally eats planets to sustain himself. He first appeared in Marvel's Fantastic Four comics in the late 60's and is still one of the brand's toughest villains.
Step-by-step explanation:
How many solutions does the equation below have?
5
(
�
−
2
)
=
8
+
5
�
5(x−2)=8+5x
no solution
one solution
two solutions
infinitely many solutions
Answer:
It has no solution.
Step-by-step explanation:
5(x - 2) = 8 + 5x
5x - 10 = 8 + 5x
5x = 18 + 5x
0 = 18
The variable cancels out, so there is no solution to substitute it for.
There are 170 deer on a reservation. The deer population is increasing at a rate of 30% per year
A function \(P(t) = 170.(1.30)^t\) that gives the deer population P(t) on the reservation t years from now
We were told there were 170 stags on reservation. The number of deer is increasing at a rate of 30% per year.
We could see the deer population grow exponentially since each year there will be 30% more than last year.
Since we know that an exponential growth function is in form:
\(f(x) = a*(1+r)^x\)
where a= initial value, r= growth rate in decimal form.
It is given that a= 170 and r= 30%.
Let us convert our given growth rate in decimal form.
\(30 percent = \frac{30}{100} = 0.30\)
Upon substituting our given values in exponential function form we will get,
\(P(t) = 170.(1+0.30)^t\)
⇒ \(P(t)= 170.(1.30)^t\)
Therefore, the function \(P(t) = 170.(1.30)^t\) will give the deer population P(t) on the reservation t years from now.
Complete Question:
There are 170 deer on a reservation. The deer population is increasing at a rate of 30% per year. Write a function that gives the deer population P(t) on the reservation t years from now.
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ignore the scribble but could somebody please help me?
Answer:
Below in bold.
Step-by-step explanation:
To get a stratified sample you work out the proportion of girls from each school.
From school A we take: (126/461) * 80 = 22 girls.
From B :- (82/461) * 80 = 14 girls.
From C :- (201/461)*80 = 35 girls
From CD :- (52/461)*80 = 9 girls.
the surface area of a sphere is 1. what is the surface area (including the base area) of a hemisphere with the same radius?
If the surface area of a sphere is 1, then its radius is √(1/4π) = 0.2821 (approximate to four decimal places).
The surface area of a hemisphere with the same radius is half that of the sphere since it only covers half of the surface area.
So, the surface area (including the base area) of the hemisphere would be:
2π(0.2821)^2 + π(0.2821)^2 = 0.5 + 0.25π = 0.7854 (approximate to four decimal places).
Therefore, the surface area (including the base area) of the hemisphere with the same radius is approximately 0.7854 square units.
Hi! To find the surface area of a hemisphere with the same radius as a sphere, we'll first determine the radius using the sphere's surface area formula, and then apply the hemisphere's surface area formula.
1. Sphere's surface area formula: A = 4πr²
Given surface area A = 1, we'll solve for radius r:
1 = 4πr²
Divide both sides by 4π:
1 / 4π = r²
2. Find r:
r = √(1 / 4π)
3. Hemisphere's surface area formula (including base area): A_hemisphere = 3πr²
Substitute r with the value we found:
A_hemisphere = 3π(√(1 / 4π))²
4. Simplify the expression:
A_hemisphere = 3π(1 / 4π)
A_hemisphere = (3/4)π
So, the surface area (including the base area) of the hemisphere with the same radius as the given sphere is (3/4)π.
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Which comparison is true ?
3/4 > 7/8
1/2 < 5/8
2/3 < 3/8
7/8 > 9/10
Answer:
B
Step-by-step explanation:
Answer: 1/2<5/8
Step-by-step explanation:
Change denominator of 1/2 to 8 and the fraction would be 4/8 now which is less than 5/8
A speedboat moving at 30 m/s approaches a no-wake buoy marker 100 m ahead. The pilot slows the boat with a constant acceleration of 3.0 m/s
2
by reducing the throttle. What is the velocity of the boat when it reaches the buoy?
The velocity of the boat when it reaches the buoy is approximately 17.32 m/s. This is found using the equation v² = u² + 2as, where u is the initial velocity, a is the acceleration, and s is the displacement.
To solve this problem, we can use the equations of motion. The initial velocity of the boat, u, is 30 m/s, the acceleration, a, is -3.0 m/s² (negative because the boat is slowing down), and the displacement, s, is 100 m. We need to find the final velocity, v, when the boat reaches the buoy.
We can use the equation: v² = u² + 2as
Substituting the given values, we have:
v² = (30 m/s)² + 2(-3.0 m/s²)(100 m)
v² = 900 m²/s² - 600 m²/s²
v² = 300 m²/s²
Taking the square root of both sides, we find:
v = √300 m/s
v ≈ 17.32 m/s
Therefore, the velocity of the boat when it reaches the buoy is approximately 17.32 m/s.
The problem provides the initial velocity, acceleration, and displacement of the boat. By applying the equation v² = u² + 2as, we can find the final velocity of the boat. This equation is derived from the kinematic equations of motion. The equation relates the initial velocity (u), final velocity (v), acceleration (a), and displacement (s) of an object moving with uniform acceleration.
In this case, the boat is decelerating with a constant acceleration of -3.0 m/s². By substituting the given values into the equation and solving for v, we find that the velocity of the boat when it reaches the buoy is approximately 17.32 m/s.
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If the terminal side of angle θ is in the first quadrant and cos(θ)=3√2, what is the exact measure of θ?
There is no exact measure of θ that satisfies the condition cos(θ) = 3√2 in the first quadrant.
Given that the terminal side of angle θ is in the first quadrant and cos(θ) = 3√2, we can determine the exact measure of θ by using the inverse cosine function, also known as arccosine.
Since cos(θ) = adjacent/hypotenuse, we can set up a right triangle in the first quadrant with the adjacent side as 3√2 and the hypotenuse as 1. The opposite side of the triangle can be found using the Pythagorean theorem.
Let's calculate the length of the opposite side:
opposite^2 + adjacent^2 = hypotenuse^2
opposite^2 + (3√2)^2 = 1^2
opposite^2 + 18 = 1
opposite^2 = 1 - 18
opposite^2 = -17
Since the length of a side cannot be negative, we see that there is no real solution for the length of the opposite side. Therefore, the given cosine value of 3√2 does not correspond to an angle in the first quadrant.
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Mary cut a wire into 7 equal pieces. The wire was originally 7.84 meters long. How long is each piece?
Answer:
Each piece is 1.12 meters long
Step-by-step explanation:
7 equal pieces = divide x by 7
equation: 7.84 / 7
question if a polygon has 5 sides, then it is a pentagon. write the inverse of the conditional statement and determine whether it is true or false. responses
The given conditional statement is True since all polygons with 5 sides are pentagons. The inverse statement is also true as all other polygons (that don't have 5 sides) will not be pentagons.
The given conditional statement is: If a polygon has 5 sides, then it is a pentagon.
The inverse of the given conditional statement is:
If a polygon does not have 5 sides, then it is not a pentagon.
The inverse statement of the given statement can be determined by negating the hypothesis and conclusion of the original statement and interchanging them with "if" and "then".
The given conditional statement is True since all polygons with 5 sides are pentagons.
The inverse statement is also true as all other polygons (that don't have 5 sides) will not be pentagons.
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Write an equation in point-slope form for each line.
questions 40 and 42.
20 points!!!!
Answer:
40) y=2x+1
42) y=-4/3x-2
Step-by-step explanation:
let r be a ring and r1,...,rn ∈ r. prove that the subset ⟨r1,...,rn⟩={λ1r1 ··· λnrn |λ1,...,λn ∈ r} is an ideal in r
(1) (λ1-μ1),...,(λn-μn) ∈ r, (a-b) is in ⟨r1,...,rn⟩. Also, the additive inverse of each element exists in r, so ⟨r1,...,rn⟩ is a subgroup under addition.
(2) cλ1,...,cλn ∈ r, both (ca) and (ac) are in ⟨r1,...,rn⟩.
Since ⟨r1,...,rn⟩ is a subgroup under addition and closed under ring multiplication, it is an ideal in the ring r
To prove that the subset ⟨r1,...,rn⟩ is an ideal in r, we need to show that it satisfies two properties: closure under addition and multiplication by any element in r.
First, let's show that it's closed under addition. Let a, b be arbitrary elements in ⟨r1,...,rn⟩. Then, there exist λ1, ..., λn and μ1, ..., μn in r such that a = λ1r1 + ... + λnrn and b = μ1r1 + ... + μnrn. Then, we have:
Let a = λ1r1 + ... + λnrn and b = μ1r1 + ... + μnrn be two elements in ⟨r1,...,rn⟩. We need to show that (a-b) is also in ⟨r1,...,rn⟩.
(a-b) = (λ1r1 + ... + λnrn) - (μ1r1 + ... + μnrn) = (λ1-μ1)r1 + ... + (λn-μn)rn
Since (λ1-μ1),...,(λn-μn) ∈ r, (a-b) is in ⟨r1,...,rn⟩. Also, the additive inverse of each element exists in r, so ⟨r1,...,rn⟩ is a subgroup under addition.
Since r is a ring, λi + μi is also in r for i = 1, ..., n. Therefore, a + b is in ⟨r1,...,rn⟩, and the subset is closed under addition.
Next, let's show that it's closed under multiplication by any element in r. Let a be an arbitrary element in ⟨r1,...,rn⟩, and let r be an arbitrary element in r. Then, there exists λ1, ..., λn in r such that a = λ1r1 + ... + λnrn. Then, we have:
Let c ∈ r and a ∈ ⟨r1,...,rn⟩, i.e., a = λ1r1 + ... + λnrn. We need to show that (ca) and (ac) are in ⟨r1,...,rn⟩.
(ca) = c(λ1r1 + ... + λnrn) = (cλ1)r1 + ... + (cλn)rn
(ac) = (λ1r1 + ... + λnrn)c = (λ1c)r1 + ... + (λnc)rn
Since r is a ring, rλi is also in r for i = 1, ..., n. Therefore, ra is in ⟨r1,...,rn⟩, and the subset is closed under multiplication by any element in r.
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A clerk counted 13 small baseball caps, 36 medium baseball caps, and 27 large baseball caps on the store shelves. She also counted 10 small baseball caps and 15 medium baseball caps in the stockroom.
Organize the data in a matrix. Name the matrix B. Label the rows and columns.
Each baseball cap sells for $19. Create the matrix that shows the total value of each cap size in each location. Show your work.
The matrix B that organizes the data is given as follows:
B = [13, 36, 27,
10, 15, 0,
23, 51, 27].
The matrix that shows the total value of each cap size in each location is given as follows:
C = [247, 684, 513,
190, 285, 0,
437, 969, 513].
How to define the matrix B?The matrix B is defined considering that it will have three rows and three columns, as follows:
Row 1: Number of each type of cap on the store shelves.Row 2: Number of each type of cap on the stockroom.Row 3: Total number of each type of car -> Row 1 + Row 2.Column 1: Small caps.Column 2: Medium caps.Column 3: Large caps.Then the matrix B is defined as follows:
B = [13, 36, 27,
10, 15, 0,
23, 51, 27].
The cost of each baseball cap is of $19, thus the cost matrix is obtained multiplying the matrix B by the constant of 19.
When a matrix is multiplied by a constant, all the elements of the matrix are multiplied by the constant, hence the cost matrix is given as follows:
C = [247, 684, 513,
190, 285, 0,
437, 969, 513].
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a baker sell bread for 3$ a loaf and roll for 1$ each. the baker needs to sell 24$ worth of baked good by the end of the day. write a linear equation that describes the problem
According to the problem, the baker needs to sell $24 worth of baked goods. The equation can be written as:
3x + 1y = 24
Let's define two variables to represent the quantities of loaves of bread and rolls sold by the baker. Let's use 'x' to represent the number of loaves of bread and 'y' to represent the number of rolls.
The cost of one loaf of bread is $3, so the total value of the loaves of bread sold can be expressed as 3x.
The cost of one roll is $1, so the total value of the rolls sold can be expressed as 1y.
According to the problem, the baker needs to sell $24 worth of baked goods. Therefore, the equation can be written as:
3x + 1y = 24
This equation represents the total value of the baked goods sold, where 3x represents the value of the loaves of bread sold, 1y represents the value of the rolls sold, and 24 represents the target value of $24 that needs to be achieved by the end of the day.
By solving this linear equation, we can find the possible combinations of loaves of bread and rolls that will meet the requirement of selling $24 worth of baked goods.
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solve the inequality |x +4|-4>0
The inequality form of the given expression is:
x < -8 or x > 0
The interval notation is : (−∞,−8)∪(0,∞)
Given, the expression is |x + 4| - 4 > 0
An inequality is a relationship that shows a non-equal comparison between two numbers or mathematical expressions.
Isolate the variable by dividing each side by factors that don't contain the variable.
⇒ |x + 4| - 4 > 0
⇒ |x + 4| > -4
Remove mod.
⇒ x + 4 > -4 or x - 4 > -4
⇒ x > -4 -4 or x > -4 +4
⇒ x <-8 or x > 0
Hence the internal notation is :
(−∞,−8)∪(0,∞)
The required graph is plotted.
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solve the equation 4x^3 + 32x^2 + 42x - 16 = 0, given that one root is equal to the sum of the other two roots
The solutions to the equation are x = -1, x = -8, and x = 1/2.
How to calculate the valueThe equation 4x³ + 32x² + 42x - 16 = 0 can be divided throuh by 2 as follows:
2x³ + 16x² + 21x - 8 = 0
We can test each of these possible roots by substituting them into the equation and seeing if we get 0. When we substitute -1, we get 0, so -1 is a root of the equation. We can then factor out (x + 1) from the equation to get:
(x + 1)(2x² + 15x - 8) = 0
We can then factor the quadratic 2x² + 15x - 8 by grouping to get:
(x + 8)(2x - 1) = 0
This gives us two more roots, x = -8 and x = 1/2.
Therefore, the solutions to the equation are x = -1, x = -8, and x = 1/2.
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aley took her science test and got 35 correct and 5 incorrect answers. What was the percentage of correct answers?
Answer:
88%
Step-by-step explanation:
A total of 40 questions.
35 divided by 40 = .88 or 88%
the body mass of a man is xkg.thebody mass of his two children are five-sixth and four_fifths of their father5 x over 6 + 4 x over 5 5 x over 6 + 4 x over 5
56/120
Step-by-step explanation:
The body masses of the two children in terms of their father's body mass, x, are:
First child's body mass = 5x/6 kg
Second child's body mass = 4x/5 kg
To express the body mass of the man's two children in terms of their father's body mass, we can use the given ratios.
Let the body mass of the man be x kg.
The first child's body mass is five-sixths of their father's body mass:
Body mass of the first child = (5/6) * x
= 5x/6 kg.
The second child's body mass is four-fifths of their father's body mass:
Body mass of the second child = (4/5) * x
= 4x/5 kg.
Therefore, the body masses of the two children in terms of their father's body mass, x, are:
First child's body mass = 5x/6 kg
Second child's body mass = 4x/5 kg
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suppose lengths of text messages are normally distributed and have a known population standard deviation of 3 characters and an unknown population mean. a random sample of 22 text messages is taken and gives a sample mean of 31 characters. what is the correct interpretation of the 90% confidence interval?
Answer: The 90% confidence interval for the population mean of the length of text messages is a range of values that is likely to contain the true population mean with a probability of 0.90 (or 90%). Based on the given information, we can calculate the confidence interval as follows:
Standard error of the mean (SE) = σ / sqrt(n)
where σ is the population standard deviation, n is the sample size, and sqrt denotes the square root.
SE = 3 / sqrt(22) ≈ 0.639
Margin of error (ME) = t(α/2, df) × SE
where t(α/2, df) is the critical value from the t-distribution with df degrees of freedom, and α is the level of significance (1 - confidence level).
For a 90% confidence level and 21 degrees of freedom (df = n - 1), the critical value is approximately 1.717.
ME = 1.717 × 0.639 ≈ 1.098
The confidence interval can be calculated as:
CI = sample mean ± ME
= 31 ± 1.098
= (29.902, 32.098)
Therefore, we can say that we are 90% confident that the true population mean of the length of text messages falls between 29.902 and 32.098 characters. In other words, if we were to repeat the sampling process many times and construct a 90% confidence interval for each sample, we would expect 90% of the intervals to contain the true population mean. Additionally, we can interpret the margin of error as the maximum amount that the sample mean is expected to differ from the true population mean, with a probability of 90%.
Step-by-step explanation:
Find the transition matrix from B to B', the transition matrix from given the coordinate matrix [x]B. B = {(-2, 1), (1, -1)}, B' = {(0, 2), (1, 1)}, [x]B = [8 -4]^ T (a) Find the transition matrix from B to B'. p^-1 =
To find the transition matrix from B to B', we need to find the matrix P that transforms coordinates from the B basis to the B' basis.
Given:
B = {(-2, 1), (1, -1)}
B' = {(0, 2), (1, 1)}
[x]B = [8, -4]^T
To find the transition matrix P, we need to express the basis vectors of B' in terms of the basis vectors of B.
Step 1: Write the basis vectors of B' in terms of the basis vectors of B.
(0, 2) = a * (-2, 1) + b * (1, -1)
Solving this system of equations, we find a = -1/2 and b = 3/2.
(0, 2) = (-1/2) * (-2, 1) + (3/2) * (1, -1)
(1, 1) = c * (-2, 1) + d * (1, -1)
Solving this system of equations, we find c = 1/2 and d = 1/2.
(1, 1) = (1/2) * (-2, 1) + (1/2) * (1, -1)
Step 2: Construct the transition matrix P.
The transition matrix P is formed by arranging the coefficients of the basis vectors of B' in terms of the basis vectors of B.
P = [(-1/2) (1/2); (3/2) (1/2)]
So, the transition matrix from B to B' is:
P = [(-1/2) (1/2); (3/2) (1/2)]
Answer:
The transition matrix from B to B' is:
P = [(-1/2) (1/2); (3/2) (1/2)]
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in using the standard normal distribution to establish a confidence interval for the average time to complete a stock trade, what is the appropriate z-value to use for a 98.54% level of confidence.
2.18 is the right z-value to utilize for a level of confidence of 98.54%.
Assuming a two-sided confidence interval,
(100-98.54)/2 = 1.46
Lower percentile = 1.46%
In terms of the information that is provided, we have that the percentile is the 3-th percentile.
We need to find the z-score associated to this percentile. How do you we do so? We need to find the
value z* that solves the equation below.
P(Z < z*) = 0.0146
The value of z" that solves the equation above cannot be made directly, it solved either by looking at
a standard normal distribution table or by approximation (the way Excel or this calculator does)
Then, it is found that that the solution is z* = -2.18
Therefore, it is concluded that the corresponding z-score associated to the given 2nd percentile is
Z =-2.18
The results found above are depicted graphically as follows:
The Z-score z = -2.18 is associated to the 2nd percentile
Hence, lower interval Z-score =-2.18
Since the standard normal distribution is symmetric around 0,
Therefore, upper interval Z-score = 2.18
Appropriate z-value =2.18
Hence, the appropriate z-value to use for a 98.54% level of confidence is 2.18
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WILL MARK BRAINLIEST HELP ASAP ASAP
Answer:
ASA
Step-by-step explanation:
you can see there is 1 marking of (A)ngle and 1 marking of (S)ide in the middle they share that angle and they don't mark it
at this point you are down to 2 options AAS ASA
and you just look at witch order makes more since and ASA does because there is a S in the "middle" of the angles.
Answer:
SAS
hope u get this right
hope this helped
don't want mark brainliest just here to help
Step-by-step explanation:
Explain how y=|x+3|-6 is translated form y=|x|
The kind of transformation which translates y = |x| to |x + 3| - 6 is vertical shrink .
What is transformation of a function?
A function transformation is a procedure that modifies an existing function to create different version of the following function.
It is given that there are two functions.
Let's assume :
y = y2 = |x+3| - 6
y = y1 = |x|
Let's compare the function to the parent function to identify the transformation and then look to determine what kind of transformation has taken place.
The parent function is y = |x| . We know that if we perform transformation that meant the parent function is transformed into another function.
y1 = |x|
y1 = ± x
Let's add 6 and then subtract 6 in RHS :
y1 = ± x + 6 - 6
So , there can be two values which are :
y1 = x + 3 + 3 - 6
or
y1 = -x + 3 + 3 - 6
Now , we can rewrite y1 in form of y2 as follows :
y1 = ± x + 3 + 3 - 6
or
y1 = |x + 3| - 6 + 3
y1 = y2 + 3
or
y2 = y1 - 3
So , as we are subtracting y1, this suggests that the transformation is one of the vertical shrink type.
Therefore, the kind of transformation which translates y = |x| to |x + 3| - 6 is vertical shrink .
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Help me. The question is giving me problems help.
D/3
The real world situation that can be modelled with the given expression can be modelled as shown below.
What is expression?In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.Given is the expression as -
D/3
A real world situation that can be modelled with this expression can be written as follows -
Amanda has a total of {D} bananas. She divides the bananas into 3 of her childrens equally. Write an expression that would represent the amount of bananas recieved by each of her child.
Therefore, the real world situation that can be modelled with the given expression can be modelled as shown above.
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Identify the percent of change 12 inches to 36 inches How much percent increased?
The percent change is given by:
\(Percent_{\text{ }}change=\frac{New_{\text{ }}value-Old_{\text{ }}value}{Old_{\text{ }}value}\times100\)Where:
New value = 36in
Old value = 12 in
Therefore:
\(\begin{gathered} Percent_{\text{ }}change=\frac{36-12}{12}\times100 \\ Percent_{\text{ }}change=2\times100 \\ Percent_{\text{ }}change=200 \end{gathered}\)Answer:
200%