did the astronauts on the challenger die instantly

Answers

Answer 1

Unfortunately, the astronauts on the Challenger did not die instantly.

On January 28, 1986, the Space Shuttle Challenger exploded 73 seconds after liftoff, resulting in the deaths of all seven crew members on board.

Despite initial hopes that they had died instantly,

later investigations showed that the astronauts likely survived the initial explosion and were conscious and aware as their cabin plunged into the ocean.

However, they were unable to activate the emergency oxygen supply, and likely lost consciousness due to a lack of oxygen within minutes.

The Challenger disaster remains one of the worst tragedies in NASA's history, and prompted a reevaluation of the agency's safety protocols.

The astronauts on the Challenger did not die instantly, and likely survived the initial explosion but lost consciousness due to a lack of oxygen within minutes.

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Related Questions

please help me!!!!!! :)

please help me!!!!!! :)

Answers

Answer:

The president is permitted to veto specific legislative acts, but Congress has ... and judicial appointments and on the approval for ratification of treaties. ... State shall have the Qualifications requisite for Electors of the most numerous Branch of the State Legislature. ... No Bill of Attainder or ex post facto Law shall be passed.

Explanation:

Which of the following industries is the largest producer of primary air pollutants in the United States?

Answers

The largest producer of primary air pollution in the United States is what? electricity producing plants.

Answer:

electricity production

Explanation:

Which of the following is associated correctly?
1. San Andreas Fault--Normal Fault
2. Hawaii--Divergent Plate Boundary
3. Mid-Atlantic Ridge--Convergent Plate Boundary
4. West Coast of North America--Submergent Coastline
5. Brackish Water--Trophic Cascade
6. None of these is associated correctly

Answers

San Andreas Fault--Normal Fault is associated correctly.

This is option 1.

What is San Andreas Fault?

San Andreas Fault is a right-lateral strike-slip fault that runs approximately 800 miles (1,300 km) through California in the western United States. It forms the boundary between the Pacific Plate and the North American Plate, extending from the San Francisco Bay Area to the Salton Sea near the Mexico–United States border. It is one of the most significant geological features on the planet, and it is also one of the most active, with frequent earthquakes of varying sizes being reported in the region.

A normal fault is a type of fault that occurs when the rocks in the Earth's crust are pulled apart by tension. A normal fault occurs when the block of rock above the fault line falls downwards relative to the block of rock below the fault line, which is raised upwards.

So, the correct answer is option 1

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What happens to distance and velocity if the time to fall increases or decreases?

Answers

In free-fall motion the velocity is given by the following equation of motion:

\(v=v_0-gt\)

Where:

\(\begin{gathered} v=\text{ velocity} \\ g=\text{ acceleration of gravity} \\ t=\text{ time} \end{gathered}\)

Therefore, the velocity increases linearly with time. This happens if the object encounters no air resistance. In the case that there is air resistance the object will reach a terminal velocity.

In the case of distance, this is given by the following equation:

\(s=v_0t-\frac{1}{2}gt^2_{}\)

This means that the distance increases with time following a parabolic function.

A ball is thrown directly upward into the air. The graph below shows the vertical position of the ball with respect to time

Answers

.Explanation:

.......................................................

An identical book is dropped on four planets of unknown gravity. The book is thrown down on planets W and X, and released from rest on planets Y and Z. The velocity is recorded for some time intervals on each planet, but not all. The missing velocities are blocked out with a gray box. Which of the following lists the planets in order from the greatest acceleration of gravity to the least acceleration of gravity?

An identical book is dropped on four planets of unknown gravity. The book is thrown down on planets W

Answers

We want to compare the gravitational acceleration of different planets by using the given table. The correct option is the last one, so we have:

Planet Y, planet W, planet Z, planet X.

First, we know that the velocity equation is written as:

V(t) = a*t + v₀

Where a is the acceleration and v₀ is the initial velocity.

With this equation, we can find the acceleration in each planet.

Planet W

The initial velocity is v₀ = -3m/s

V(t) = a*t - 3m/s

And we know that at t = 2s, the velocity is -22m/s.

v(2s) = -22m/s = a*2s - 3m/s

           -22m/s + 3m/s = a*2s

           -19 m/s = a*2s

           (-19 m/s)/2s = a = -9.5m/s^2

Now we just do the same thing for each planet.

Planet X:

v₀ = -0.5 m/s

v(1s) = -4.2 m/s = a*1s - 0.5 m/s

          -4.2 m/s + 0.5 m/s = a*1s

          -3.8 m/s^2 = a

Planet Y:

v₀ = 0 m/s

v(2s) = -21 m/s = a*2s

           (-21 m/s)/2s = a = -10.5 m/s^2

Planet Z:

v₀ = 0 m/s

v(1s) = -8 m/s = a*1s

          (-8 m/s)/1s = a = -8m/s^2

Then the order from greatest to least is:

Y, W, Z, X

So the correct option is the last one.

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The lava lamp has a light bulb as a heat source at its base. The lamp contains a colored, waxy fluid that can be observed moving in clumps through a clear liquid. A lava lamp filled with orange blobs lit from below. As the clump of colored fluid at the bottom of the lava lamp reaches the top, which has increased? its density its temperature the kinetic energy of its molecules the space between its molecules.

Answers

As the clump of colored fluid at the bottom of the lava lamp reaches the top, Its temperature increases. Temperature directs to the hotness or coldness of a body.

What is temperature?

Temperature directs to the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles more the temperature.

Temperature is essential in all areas of Science right from Physics to Geology and also it is important in most parts of our everyday life.

The clump of colorful fluid at the bottom of the lava lamp rises to the top because the clump, as the heavier liquid, absorbs heat and expands, becoming less dense and rising.

Due to this the temperature is increasing.Hence As the clump of colored fluid at the bottom of the lava lamp reaches the top, Its temperature increases

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Answer:

A density

Explanation:

all the others were wrong smh had to redo quiz after all

What type of system would allow light to enter and exit, but would keep any
additional atoms out?

Answers

An isolated system , it does not allow any matter or energy to be exchanged

Answer: it’s closed

Explanation: a pex

rank the time required for the crates to return to their initial positions from largest to smallest.

Answers

To rank the time required for the crates to return to their initial positions from largest to smallest, you first need to calculate the time taken for each crate to return to its original position. This can be done using the formula:

Time = (2 × Length of Spring) ÷ (Acceleration due to Gravity × Mass of Crate)

Once you have the time taken for each crate to return to its original position, you can rank them from largest to smallest.

Compare the values in the list and rank them from largest to smallest. The highest value in the list will be the first, followed by the second highest value, and so on.

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rank the time required for the crates to return to their initial positions from largest to smallest.
rank the time required for the crates to return to their initial positions from largest to smallest.

______ enables digital computers to communicate across different media, including telephone wires, cable lines, and radio waves.

Answers

Modem enables digital computers to communicate across different media, including telephone wires, cable lines, and radio waves.

A modulator-demodulator or modem is a computer hardware device that converts data from a digital format into a format suitable for an analog transmission medium such as telephone or radio. Modems converts or modulates the analog signals coming from telephone wire into digital form for example in form of 0 s and 1 s.

To transmit digital data, the sending modem must first modulate, or encode, a computer's digital signal into an analog signal that can travel over the phone line. The receiving modem must then demodulate, or decode, the analog signal back into a digital signal recognizable to a computer.

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Particles q1 = -20.5 UC, q2 = -9.30 uC, and q3 = -31.6.0 uC are in a line. Particles q, and q2 are separated by 0.980 m and particles q2 and q3 are separated by 0.750 m. What is the net force on particle q2?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right

Answers

The net force on particle q2 can be calculated by finding the net electric force acting on it. The net electric force acting on a particle is the vector sum of the forces exerted by all the other charges on it.

The electric force between two charges q1 and q2 is given by Coulomb's law: F = k * (q1 * q2)/r^2, where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.

The force on particle q2 due to q1 will be:

F1 = k * (q1 * q2) / (0.980m)^2

The force on particle q2 due to q3 will be:

F2 = k * (q2 * q3) / (0.750m)^2

The net force acting on q2 will be the vector sum of F1 and F2.

Keep in mind, q1 and q3 have opposite charges, so they attract each other, while q2 has the same charge as q1, so they repel each other.

Note: The unit of charge is Coulomb (C), but in this problem you are given the charges in microCoulomb (uC) so you need to convert it to Coulomb.

The specific heat capacity of liquid mercury is 0.14 J/gK. How many joules of heat are needed to raise the temperature of 5.00 g of mercury from 15.0 ∘
C to 36.5 ∘
C ? A) 7.7×10 2
J B) 15 J C) 36 J D) 0.0013 J E) 1.7 J

Answers

To increase the temperature of 5.00 g of mercury from 15.0°C to 36.5°C, 15 Joules of heat energy are required. Hence, option B aligns well with the answer.

Specific heat capacity is the amount of heat that needs to be added or taken from a unit mass of a substance to alter its temperature by one degree. Heat energy is the total energy of all particles in a substance. Heat is the process of energy transfer between objects that occurs due to a disparity in temperature between them.

Heat capacity is a measure of the amount of heat energy needed to raise the temperature of an object by one degree Celsius (or Kelvin). It indicates the capacity or ability of a substance to store and hold heat. The information given is as follows:

Mass of liquid mercury, m = 5.00 g

Specific heat capacity of liquid mercury, c = 0.14 J/g.

K Initial temperature, T1 = 15.0 °C

Final temperature, T2 = 36.5 °C

We will apply the formula of the heat (Q) energy required to raise the temperature of a substance Q = m x c x ΔT,

Q is the heat energy in joules (J) required to raise the temperature of the substance.

m is the mass of the substance in grams (g)

c is the specific heat capacity of the substance in joules per gram per degree Celsius (J/g.K)

ΔT is the temperature change in degrees Celsius (°C).

ΔT = T2 − T1 = 36.5 °C - 15.0 °C= 21.5 °C

Substitute the given values into the formula:

Q = m x c x ΔT

Q = 5.00 g x 0.14 J/g.K x 21.5°C

Q = 15.05 J

Thus, the correct option is (B) 15 J.

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A generalization that uses logical reasoning to make sense of observations is..

Answers

Answer:

hiatory

Explanation:

In the one pully system when you move the mass from the 20 cm mark to the 15 cm mark, it moves 5 cm. How far did you pull the string. Question 1 options: 5 cm 10 cm 15 cm 20 cm

Answers

Answer:

5 cm

Explanation:

If opposing forces acting on an object are equal, the net force is
N. (Enter your answer in the numerical form)

help me please

If opposing forces acting on an object are equal, the net force isN. (Enter your answer in the numerical

Answers

Answer:

0 N

Explanation:

suppose, you push a box with 5 N, and another person pushes the box on the opposite side of the box with 5 N, the net force (resultant ) is 0 N, the box will not move if it wasn't moving

hope this helps

during summer months, in hot regions of the united states, some homes run air conditioners continuously. how many homes can the same power plant support if average electricity usage increases to 1,200 kwh/month during summer months?

Answers

The same power plant could supply approximately 270,000 homes if the average electricity consumption rises to 1,200 kWh/month in the summer.

This is due to the fact that there is now a significant increase in the demand for electricity, which must be met by power plants.

500 mW x 24 hours/day x 30 days/month x 0.9 = 324,000 MWh/month.

The number of homes that the same power plant can serve, however, may vary based on how much electricity each household has.

324,000 mWh/month x 1,000 kWh/MWh = 324,000,000 kWh/month.

324,000,000 kWh/month/1,200 kWh/month/home = 270,000 homes.

The number of homes that can be served by the same power plant in hotter parts of the United States may rise significantly if air conditioning is kept up.

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please help! easy science! second pic is the question and possible answers (A B C or D) its one question! brainliest promised!

please help! easy science! second pic is the question and possible answers (A B C or D) its one question!
please help! easy science! second pic is the question and possible answers (A B C or D) its one question!

Answers

Answer:

Please do not take my word for this at all, but this is what I found, "When the pendulum swings back down, the potential energy is converted back into kinetic energy. At all times, the sum of potential and kinetic energy is constant." So I think the answer is B also you are anime fan too lol :DD I love hinata

Explanation:

A ball is dropped from a 20.0 m high tower.

a. How long will it take the ball to reach the ground?

b. What is the velocity of the ball just before it hits the ground?

Answers

Hi there!

We can begin by using the derived kinematic equation:

\(t = \sqrt{\frac{2h}{g}\)

Plug in the given values and let g = 9.8 m/s²:

\(t = \sqrt{\frac{2(20)}{g}} = \boxed{2.02 s}\)

Now, we can solve for its final velocity using the equation:

\(v_f = v_i + at\)

It is dropped from rest, so vi = 0 m/s.

\(v_f = at\)

\(v_f = 9.8(2.02) = \boxed{19.796 m/s}\)

Answer:

a. The ball would reach the ground in approximately \(2.02\; \rm s\).

b. The velocity of the ball right before landing would be approximately \(19.8\; \rm m\cdot s^{-1}\).

(Assumptions: the ball was dropped with no initial velocity; air resistance on the ball is negligible; \(g = 9.81\; \rm m\cdot s^{-2}\).)

Explanation:

Under these assumptions, the acceleration of this ball would be constantly \(a = g = 9.81\; \rm m\cdot s^{-2}\) (same as the gravitational field strength) during the descent.

Displacement of the ball: \(x = 20.0\; \rm m\).

Initial velocity of the ball: \(v_{0} = 0\; \rm m\cdot s^{-1}\).

Let \(t\) denote the duration of this descent.

The SUVAT equation \(x = (1/2)\, a\, t^{2} + v_{0}\, t\) relates the known quantities \(a\), \(x\), and \(v_{0}\) to the unknown \(t\).

Substitute the known quantities into this equation and solve to find the value of \(t\!\):

\(\displaystyle 20.0\; {\rm m} = \frac{1}{2}\times 9.81\; {\rm m\cdot s^{-2}} \times t^{2} + 0\; {\rm m \cdot s^{-1}} \times t\).

\(\displaystyle 20.0\; {\rm m} = \frac{1}{2}\times 9.81\; {\rm m\cdot s^{-2}} \times t^{2}\).

\(\displaystyle t^{2} = \frac{20.0\; \rm m}{(1/2) \times 9.81\; \rm m\cdot s^{-2}}\).

Since \(t > 0\):

\(\begin{aligned}t &= \sqrt{\frac{20.0\; \rm m}{(1/2) \times 9.81\; \rm m\cdot s^{-2}}} \\ &\approx 2.01928\; \rm s\\ &\approx 2.02\; \rm s \\ & (\text{Rounded to 2 sig. fig.})\end{aligned}\).

Since the acceleration of this ball is constant, the velocity of the ball right before landing would be:

\(\begin{aligned}v_{1} &= a\, t \\ &\approx 9.81\; \rm m\cdot s^{-2} \times 2.01928\; \rm s \\ &\approx 19.8\; \rm m \cdot s^{-1} \end{aligned}\).

PLS HELP I NEED THIS BY TONIGHT PLS

PLS HELP I NEED THIS BY TONIGHT PLS

Answers

Answer:

GET GOOD

Explanation:

Girl we can’t even read that

A railway wagon of mass 100 kg is pulled with a force of 1000 N. what is its Acceleration ?​

Answers

Solution,

Mass(m)= 100kgForce(F)= 1000NAcceleration (a)=?

We know that,

\(f = ma \\ \frac{f}{m} = a \\ \frac{1000}{100} = a \\ 10 = a\)

Therefore,

Acceleration produced will be 10m/.

in aviation a standard rate turn proceeds at an angular speed of per minute. what is the radius of a standard rate turn for a plane moving at 240 m/s?

Answers

The radius of a standard rate turn for a plane moving at 240 m/s  is approximately 933 meters.

A standard rate turn in aviation refers to a turn in which an aircraft completes a full 360-degree rotation in 2 minutes, resulting in an angular speed of 3 degrees per second (180 degrees per minute). To calculate the radius of a standard rate turn for a plane moving at 240 m/s, we can use the formula:

Radius = V / (G × Tan(Bank Angle))

where:
- V is the velocity of the plane (240 m/s)
- G is the gravitational constant (approximately 9.81 m/s²)
- Bank Angle is the angle at which the aircraft is tilted during the turn.

First, we need to find the bank angle. Since we know that the angular speed is 3 degrees per second, we can use the following formula to find the bank angle:

Bank Angle = Arc Tan((V² × Angular Speed) / (G × 180))

Bank Angle = Arc Tan((240² × 3) / (9.81 × 180))
Bank Angle ≈ 14.7 degrees

Now that we have the bank angle, we can calculate the radius of the turn:

Radius = 240 / (9.81 × Tan(14.7))
Radius ≈ 933 meters

So, the radius of a standard rate turn for a plane moving at 240 m/s is approximately 933 meters.

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a decent satellite camera can distinguish objects that subtends angles of little as 0.5 x 10-6 rad. how small an object could such a device detect from 250 km away?

Answers

The smallest object that a decent satellite camera can detect from a distance of 250 km is about 0.125 m in size.

A decent satellite camera can distinguish objects that subtend angles as small as 0.5 x 10-6 rad.

A subtended angle is an angle formed by two lines that are extended from the edges of the object to the observer's eye. It is also known as an angular size.

The following formula may be used to find the size of a subtended angle:

\($$\theta =\frac{S}{D}$$\)

where:θ = subtended angleS = size of the object

D = distance between the observer and the object

We can rearrange the formula above to solve for S.

\($$S =\theta D$$\)

Substituting the given values, we get:

\($$S = (0.5 \times 10^{-6})(250,000)$$\)

\($$S = 0.125$$\)

Therefore, the smallest object that a decent satellite camera can detect from a distance of 250 km is about 0.125 m in size.

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A 57 kg pole vaulter running at 11 m/s vaults over the bar. Her speed when she is above the bar is 1.1 m/s. The acceleration of gravity is 9.8 m/s 2 . Find her altitude as she crosses the bar. Neglect air resistance, as well as any energy absorbed by the pole. Answer in units of m.

Answers

Answer:

Her altitude as she crosses the bar, h₂ is approximately 6.1 m

Explanation:

The given parameters of the motion of the pole vaulter are;

The mass of the pole vaulter, m = 57 kg

The speed with which the pole vaulter is running, u = 11 m/s

The speed of the pole vaulter when she crosses the bar, v = 1.1 m/s

The acceleration due to gravity, g = 9.8 m/s²

From the total mechanical energy, M.E. equation, we have;

M.E. = P.E. + K.E.

Where;

P.E. = The potential energy of the motion = m·g·h

K.E. = The kinetic energy of the motion = 1/2·m·v²

By the principle of conservation of energy, we have;

The change (loss) in kinetic energy, ΔK.E. = The change (gain) in potential energy, ΔP.E.

ΔK.E. = 1/2·m·(v² - u²)

ΔP.E. = m·g·(h₂ - h₁)

Where;

h₁ = The ground level = 0 m

h₂ = The altitude with which she crosses the bar

∴ 1/2·m·(v² - u²) = m·g·(h₂ - h₁)

(h₂ - h₁) = (v² - u²)/(2·g) = (11² - 1.1²)/(2·9.8) = 6.11173469388

h₂ = 6.11173469388 + h₁ = 6.11173469388 + 0 = 6.11173469388

h₂ = 6.11173469388

Her altitude as she crosses over the bar, h₂ ≈ 6.1 m.

White light can be separated into SIX main colors (although colors are continuously blended). List these SIX colors from MOST energetic to least energetic.

Answers

Answer:

Violet, blue, green, yellow, orange, red

Explanation:

I just took the astronomy quiz, I got it right

In reality, the Earth is not a perfect sphere, but rather an oblate spheroid (a type of ellipsoid) with the polar radius less than the equatorial radius. Because of this, the acceleration of gravity is not strictly a constant, but rather is a function of latitude (φ). Moreover, in the free atmosphere above the Earth, the gravitational acceleration is also a function of the height above mean sea level (Z). Combining these, the acceleration of gravity (cmsec −2) can be written as a function of the two variables, latitude (degrees, positive/negative in the northern/southern hemisphere) and height above mean sea level (meters) in the following form: g(φ,Z)=980.6160(1−0.0026373cos2φ+5.9×10 −6cos 2 2φ)−(3.085462×10 −4 +2.27×10 −7 cos2φ)Z+(7.254×10 −11+1.0×10 −18cos2φ)Z 2−(1.517×10 −17+6×10 −20cos2φ)Z 3
Compute the acceleration of gravity at the following locations, rounding your answers to eight (8) decimal places. A spreadsheet or a short computer script should be used to make the computations (a) Baseline Road (latitude 40 ∘
North), at an elevation of one mile above mean sea level. (b) 10 km above the North Pole. (c) Halfway between the equator and the North Pole at mean sea level. (d) 10,000 feet above mean sea level at the Antarctic Circle (≈66.5) degrees South latitude. Note that latitudes south of the equator are negative.) (e) For a particular Z, is the value of g obtained from this model the same at latitude φ as at latitude −φ ? Why?

Answers

A. spreadsheet or computer script, we can calculate the value, which is 9.80651834 m/s^2. B. the value gives g(90°, 10,000) ≈ 9.81937375 m/s^2. C. the value gives g(45°, 0) ≈ 9.80666553 m/s^2. D. the value gives: g(-66.5°, 3,048) ≈ 9.83065116 m/s^2. E. the cosine function is an even function (cos(-θ) = cos(θ)), the value of g will be different for φ and -φ, except when φ = 0 (equator) where cos(0) = cos(0) = 1.

To compute the acceleration of gravity at the given locations, we'll substitute the values of latitude (φ) and height above mean sea level (Z) into the formula for g(φ, Z).

(a) Baseline Road (latitude 40° North), at an elevation of one mile above mean sea level:

Latitude (φ) = 40°

Height (Z) = 1 mile = 1,609.34 meters

Substituting these values into the formula, we have:

g(40°, 1609.34) = 980.6160(1 - 0.0026373cos^2(40°) + 5.9×10^(-6)cos^2(2 * 40°)) - (3.085462×10^(-4) + 2.27×10^(-7)cos^2(40°)) * 1609.34 + (7.254×10^(-11) + 1.0×10^(-18)cos^2(40°)) * (1609.34)^2 - (1.517×10^(-17) + 6×10^(-20)cos^2(40°)) * (1609.34)^3

Using a spreadsheet or computer script, we can calculate the value, which is approximately: g(40°, 1609.34) ≈ 9.80651834 m/s^2.

(b) 10 km above the North Pole:

Latitude (φ) = 90° (North Pole)

Height (Z) = 10,000 meters

Substituting these values into the formula, we have:

g(90°, 10,000) = 980.6160(1 - 0.0026373cos^2(90°) + 5.9×10^(-6)cos^2(2 * 90°)) - (3.085462×10^(-4) + 2.27×10^(-7)cos^2(90°)) * 10,000 + (7.254×10^(-11) + 1.0×10^(-18)cos^2(90°)) * (10,000)^2 - (1.517×10^(-17) + 6×10^(-20)cos^2(90°)) * (10,000)^3

Calculating the value gives: g(90°, 10,000) ≈ 9.81937375 m/s^2.

(c) Halfway between the equator and the North Pole at mean sea level:

Latitude (φ) = 45°

Height (Z) = 0 meters

Substituting these values into the formula, we have:

g(45°, 0) = 980.6160(1 - 0.0026373cos^2(45°) + 5.9×10^(-6)cos^2(2 * 45°)) - (3.085462×10^(-4) + 2.27×10^(-7)cos^2(45°)) * 0 + (7.254×10^(-11) + 1.0×10^(-18)cos^2(45°)) * (0)^2 - (1.517×10^(-17) + 6×10^(-20)cos^2(45°)) * (0)^3

Calculating the value gives: g(45°, 0) ≈ 9.80666553 m/s^2.

(d) 10,000 feet above mean sea level at the Antarctic Circle (≈66.5 degrees South latitude):

Latitude (φ) = -66.5°

Height (Z) = 10,000 feet = 3,048 meters

Substituting these values into the formula, we have:

g(-66.5°, 3,048) = 980.6160(1 - 0.0026373cos^2(-66.5°) + 5.9×10^(-6)cos^2(2 * -66.5°)) - (3.085462×10^(-4) + 2.27×10^(-7)cos^2(-66.5°)) * 3,048 + (7.254×10^(-11) + 1.0×10^(-18)cos^2(-66.5°)) * (3,048)^2 - (1.517×10^(-17) + 6×10^(-20)cos^2(-66.5°)) * (3,048)^3

Calculating the value gives: g(-66.5°, 3,048) ≈ 9.83065116 m/s^2.

(e) For a particular Z, the value of g obtained from this model is not the same at latitude φ as at latitude -φ. This is because the formula for g takes into account the latitude (φ) as a trigonometric term, specifically cos^2(φ). Since the cosine function is an even function (cos(-θ) = cos(θ)), the value of g will be different for φ and -φ, except when φ = 0 (equator) where cos(0) = cos(0) = 1.

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PLZ ANSWER NOW WILL MARK BRANILESTY
Which scientist first discovered DNA?
Maurice Wilkins
Rosalind franklin
Friedrich Miescher

Answers

Answer:

Friedrich Miescher was the scientist who first discovered DNA.

Answer:

b

Explanation:

how much time will it take for a bug to travel 55 M across the floor if it's traveling by 1.1 m / s​

Answers

Answer:

The bug will take 50 seconds to travel 55 m across the floor if it's traveling by 1.1 m / s​.

Explanation:

Given

Distance covered by bug = d = 55 m

The speed = s = 1.1 m/s

To determine

Time the bug will take to cover the distance = t = ?

Using the formula to determine the time the bug will take to travel 55 m across the floor if it's traveling by 1.1 m/s​.

Distance = Speed x Time

d = s x t

t = d/s

t = 55/1.1

t = 50 s

Therefore, the bug will take 50 seconds to travel 55 m across the floor if it's traveling by 1.1 m / s​.

Describe what sandpaper does to wood to make it smoother, and explain why.

Answers

Answer it scapes away loose anf rough pieces of wood

Explanation:

Answer:

To achieve a nice smooth finish, it's essential to sand to help prepare the area for painting application, by sanding you are removing imperfections (also known as pimples), creating a nice smooth finish while at the same time adding adhesion by developing small, rough ridges for the paint to stick to.

Using the right sandpaper can make all the difference in a woodworking, painting, or finishing project; but choosing between the many different types of sandpaper that are available can be a challenge. Here are some tips on how to choose the best sandpaper for your next project.

Explanation:

Sry if this is wrong :(

Starting from 15 m/s, a certain vehicle can accelerate to 60 m/s at a rate of 6 m/s2. What time is required to make this acceleration?

Answers

Explanation:

v = u + a * t

60 = 15 + 6 * t

t = 7.5 seconds

The apparent pitch of the source is higher than the actual pitch of the source. (True or False)

Answers

The statement "The apparent pitch of the source is higher than the actual pitch of the source" is true in situations where the source and observer are moving towards each other, leading to a higher observed frequency due to the Doppler effect.

The apparent pitch of a source can be higher than the actual pitch due to the Doppler effect. The Doppler effect occurs when a source of sound (or any wave) and an observer are in relative motion. As the source and observer move closer together, the observed frequency (or pitch) increases, making the apparent pitch higher than the actual pitch.
To understand this phenomenon, consider a sound source emitting waves at a constant frequency. When the source is stationary relative to the observer, the observer perceives the actual pitch.

However, when the source moves towards the observer, the sound waves in front of the source get compressed, leading to an increased frequency of the waves reaching the observer. This increased frequency translates to a higher apparent pitch.
Conversely, when the source moves away from the observer, the sound waves in front of the source get stretched, causing the frequency reaching the observer to decrease, and resulting in a lower apparent pitch. The same effect can also occur if the observer is moving towards or away from the stationary source.

Hence we can say that the given statement is true.
For similar question on Doppler effect.

https://brainly.com/question/3841958

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