The lines intersect at the point (3,-2,10).
To determine whether the lines intersect, we need to find out whether there exists values of t and s that make the x, y,
and z values equal for both lines.
Setting the x-values equal, we get:
2t + 1 = 2s - 1
Solving for t in terms of s:
t = (2s - 2)/2 = s - 1
Setting the y-values equal, we get:
t - 2 = s - 3
Solving for t in terms of s:
t = s - 1
Since we get the same expression for t in terms of s when setting the x-values and y-values equal, we can substitute
that expression for t into the z-values for both lines and set them equal:
9t + 1 = s
Substituting t = s - 1:
9(s - 1) + 1 = s
Simplifying:
8s - 8 = 0
Solving for s:
s = 1
Substituting s = 1 into the expression for t, we get:
t = s - 1 = 0
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What is the value of ( h o k ) (2)
a -5
b 1
c -2
d -3
Answer:
-3
Step-by-step explanation:
h(k(2)) = h(k(x=2)) = h(-2) = h(x= -2)= 3/( -2+1) = 3/-1= -3
sorry if I'm wrong.
Write the equation in Standard Form. y = -2x + 5*
0 2x + y = 5
O 2x + y = -5
O 2x - y = 5
O-2x + y = 5
Answer:
2x + y = 5Step-by-step explanation:
Standard form is:
ax + by = cGiven
y = -2x + 5Converting to standard form
y = -2x + 5 2x + y = 2x - 2x + 52x + y = 5Correct option is the first one
in example 4.3, gary is currently in a cheerful mood. what is the probability that he is not in a glum mood on any of the following three days?
In example 4.3, the probability that Gary is not in a glum mood on any of the following three days is 0.729.
How to find the probabilityThe probability of an event occurring is given by:
P(event) = number of favorable outcomes / total number of possible outcomesIn this case, the probability that Gary is not in a glum mood on any of the following three days is the same as the probability that he is in a cheerful mood for all three days.
Since the probability of Gary being in a cheerful mood on any given day is 0.9, the probability that he is in a cheerful mood for all three days is:
P(all 3 days) = 0.9 x 0.9 x 0.9 = 0.729
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What will be the default location of the click point of the cursor if no coordinates have been assigned to it?a. (x, 0)b. (0, 0)c. (0, y)d. (x, y)
However, in some cases, the default location of the click point may be set by default to the top-left corner of the screen or window, which would correspond to the coordinate (0, 0) in a Cartesian coordinate system.
If no coordinates have been assigned to the cursor, the default location of the click point will depend on the program or application being used. In most cases, the default location will be the center or starting position of the screen or window in which the program is running, which could be any location on the screen. Therefore, none of the options provided is necessarily correct.
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Are the following lines parallel, perpendicular, or neither? -4x-5y=-4 and 10x-8y=-1
Answer:
perpendicular
They are neither parallel nor perpendicular as they have different slopes.
First line equation in form of y = mx +c is:
y = (4x-4)/5
and second line equation is :
y= -((10x+1)/8)
pla
help with this
Which of the following functions are concave down over the set of non-negative real numbers? Of(x) = 2 f(x) = x² Of(x) = 3x + 2 Of(x) = x³ None of the above
Based on the analysis, none of the given functions are concave down over the set of non-negative real numbers.
To determine which of the given functions are concave down over the set of non-negative real numbers, we need to examine the second derivative of each function.
Let's calculate the second derivative for each function:
Of(x) = 2:
The second derivative of Of(x) = 2 is zero because it is a constant. Therefore, it is neither concave up nor concave down.
f(x) = x²:
The second derivative of f(x) = x² is f''(x) = 2, which is a positive constant. Therefore, it is concave up, not concave down.
Of(x) = 3x + 2:
The second derivative of Of(x) = 3x + 2 is zero because it is a linear function. Therefore, it is neither concave up nor concave down.
Of(x) = x³:
The second derivative of Of(x) = x³ is f''(x) = 6x, which is positive for x > 0. Therefore, it is concave up, not concave down.
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Some animals on farms eat hay to get energy. A cow can eat 24 pounds of hay each day. Write and evaluate an expression to find how many pounds a group of 22 cows can eat in two weeks.
Answer:
7392 pounds
Step-by-step explanation:
22x24x14
multiplication my friend
Jennifer went to a farm and bought tomatoes
for $2 per pound and garlic for $3 per pound.
If Jennifer spent $72 on tomatoes and garlic,
how many pounds can she buy if she buys
only garlic?
Answer:
24 pounds of garlic
Step-by-step explanation:
if she spends 3$ per pound, you divide 72 by 3. the answer to that is 24, so if she spends 72 dollars on only garlic, she can buy 24 pounds.
Jennifer can buy 24 pounds of garlic
we see here, that if she spends 3$ per pound, you divide 72 by 3.
The answer would be 24, so if she spends 72 dollars on only garlic,
she can buy 24 pounds.
What is a pound defined as?1: any of various units of mass and weight specifically: a unit now in general use among English-speaking peoples equal to 16 avoirdupois ounces or 7000 grains or 0.4536 kilogram — see Weights and Measures Table
2: the basic monetary unit of the United Kingdom.
What is a division example?In maths, a division is a process of splitting a specific amount into equal parts. For example, we can divide a group of 20 members into 4 groups of 5 members each or 5 groups of 4 members each
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PLS HELP! WILL MARK BRAINLYIST!!
1. What do you know about the trigonometric ratios for similar triangles?
2. What is the relationship between the sine and cosine of complementary angles, and why is this relationship true?
3. How do you use trigonometric ratios to solve for a missing side or angle of a right triangle?
Possible answers??
2. The relationship between the sine and cosine of complementary angles is that they are equal. Angles A and B are complementary if: A+B=90.
3. Sineθ=opposite/hypotenuse, cosθ=adjacent/hypotenuse, tanθ=opposite/adjacent.
PLEASE HELP, I DON'T KNOW IF THESE ARE RIGHT
1) Trigonometric ratios for similar triangles state that the ratios of corresponding sides of similar triangles are equal. 2) The sine and cosine of complementary angles have the property of being not only equal but also complementary to one another. 3) trigonometric ratios can be used to solve for a missing side or angle of a right triangle.
What are trigonometric ratios?1. Trigonometric ratios for similar triangles state that the ratios of corresponding sides of similar triangles are equal. Therefore, the ratios of the sine, cosine, and tangent of the corresponding angles in similar triangles will also be equal.
2. The sine and cosine of complementary angles have the property of being not only equal but also complementary to one another. This means that the sine of an angle is equal to its complement's cosine, and vice versa.
3. Using the appropriate formula based on the given information, trigonometric ratios can be used to solve for a missing side or angle of a right triangle.
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15 men can build a wall in 42 hours, how many men will be required for the same work in 30 hours
Answer:
This question can be solved using direct and inverse variation. Direct variation can be solved using unitary method that is common sense like if you buy 10 chocolates for 100 rupees how many rupees would you pay for 20 - this is simple as if 10 chocolates is 100 then 20 would be 200. HOWEVER, Inverse Variation is when one value increase the other value decreases and they are proportional. They have a formula called x1/x2 = y2/y1.
In this problem we can use this formula, x1/x2 = 15/42 and y2/y1 = 30/x
so hence 15/42 = 30/x
= 15x = 30*42
x= 1260/15
= 84
Therefore 84 is the answer.
Neglecting air resistance, the distance s(t) in feet traveled by a freely falling object is given by the function s(t)=16t squared, where t is time in seconds. The height of a certain tower is 986 feet. How long would it take an object to fall to the ground from the top of the building?
Answer: t = 7.85seconds
Step-by-step explanation:
Given that :
Height of tower = 986 Feets
Function s(t) = 16t^2
To find the time t 8 in Seconds taken for an object to fall to the ground from the top of the building
16t^2 = 986
t^2 = 986/16
t ^2 = 61.625
Take the square root of both sides
t = sqrt(61.625)
t = 7.85seconds
Answer:
7.85sec
Step-by-step explanation:
Given that,
s(t)=16t squared, where t is time in seconds. The height of a certain tower is 986 feet.
s(t) = 16t²
so when s = 986feet
16t² = 986 feet
t² = 986 / 16
t² = 61.625
t = √61.625
t= 7.85 seconds
Enter an inequality that represents the description, and then solve.
Dave has $11 to spend on an $8 book and two birthday cards (c) for his friends. How much can he spend
on each card if he buys the same card for each friend?
Answer:
$6
Step-by-step explanation:
Ruby’s homework covers multiplication with the powers of 10 the first question on her homework is 82.6 x 10 to the power of 2 what is the value of expression?
Answer:
826
Step-by-step explanation:
82.6 x 10 to the power of 2 :
8.26 * 10^2
8.26 * (10 * 10)
8.26 * (100)
= 826
if y = 1x + 0 then what i the slope?
The square has sides of length 3 cm and the arcs
have centres at the corners. Find the shaded area.
Answer:
Shaded area= 5.14 cm² (3 s.f.)
Step-by-step explanation:
Please see the attached picture for the full solution.
Help me I need pls pls pls
Answer:
$2278.50
Step-by-step explanation:
What is 10/50 x 14/30 as a percentage?
Answer:
9.3%
Step-by-step explanation:
10/50= 0.20 or 20%
14/30= 0.4667 or 46.6%
0.20•0.4667=0.09333 or 9.3%
Consider the following LP problem. Maximize z=−2x1−x2+x3 subject to x1+x2+x3≤3x2+x3≥2x1+x3=1x1,x2,x3≥0 (i) Find the dual of this LP problem. [5] (ii) After adding a slack variable s1, subtracting an excess variable e2, and adding artificial variables a2 and a3, Row 0 of the LP problem's optimal tableau is found to be z=4x1+e2+(M−1)a2+(M+2)a3=0 Find the optimal solution to the dual of this LP problem. [3]
(i) The dual of the given LP problem can be found by following these steps:
1. For each constraint in the primal problem, create a dual variable. In this case, we have three constraints, so we'll have three dual variables: y1, y2, and y3.
2. The objective function of the dual problem will be the sum of the products of the primal variables and their corresponding dual variables. So, the dual objective function is:
Maximize w = 3y1 + 2y2 + y3.
3. For each primal variable x, create a constraint in the dual problem with the coefficient of the corresponding dual variable equal to the coefficient of x in the primal objective function. So, the dual constraints are:
y1 + 2y2 - y3 ≤ -2
y1 + y2 + y3 ≤ -1
y1, y2, y3 ≥ 0.
(ii) To find the optimal solution to the dual problem, we need to solve the optimal tableau of the dual problem. From the given information, we know that Row 0 of the optimal tableau is:
w = 4x1 + e2 + (M-1)a2 + (M+2)a3 = 0.
However, the given information does not provide any details about the values of x1, e2, a2, or a3. Therefore, without this information, we cannot determine the specific optimal solution to the dual problem.
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Pls let me see the work!!
The recipe for the waffles presented using rational numbers are as follows;
1. The recipe for 2 waffles is as follows;
\( \displaystyle \frac{3}{5} \) cups of flour
\( \displaystyle \frac{2}{15} \) teaspoon of salt
\( \displaystyle \frac{4}{5} \) teaspoons of baking powder
\( \displaystyle \frac{7}{20} \) Cups of milk
\( \displaystyle \frac{1}{15} \) Cup of butter
2. The recipe for 5 waffles is as follows;
\( \displaystyle 1\frac{1}{2} \) cups of flour
\( \displaystyle \frac{1}{3} \) teaspoon of salt
\( \displaystyle 2 \) teaspoons of baking powder
\( \displaystyle \frac{7}{8} \) Cups of milk
\( \displaystyle \frac{1}{6} \) Cup of butter
3. The recipe for 300 waffles is as follows;
900 cups of flour
200 teaspoon of salt
1200 teaspoons of baking powder
525 Cups of milk
100 Cup of butter
4. The required number of waffle irons is 50
5. It would take approximately 6 servers
It would take 34 trips
What is a rational number?A rational number is one that can be expressed as a fraction.
From the given table, we have;
The recipe for 10 waffles includes;
3 cups of flour
\( \displaystyle \frac{2}{3} \) teaspoon of salt
4 teaspoons of baking powder
\( \displaystyle 1\frac{3}{4} \) Cups of milk
\( \displaystyle \frac{1}{3} \) Cup of butter
1. To make 2 waffles, we have;
\( \displaystyle 2 = \frac{10}{5} \)
Dividing each of the quantities required to make 10 waffles by 5 gives;
\( \displaystyle \frac{3}{5} \) cups of flour
\( \displaystyle \frac{2}{3 \times 5} = \frac{2}{15} \) teaspoon of salt
\( \displaystyle \frac{4}{5} \) teaspoons of baking powder
\( \displaystyle \frac{1\frac{3}{4}}{5} = \frac{7}{20} \) Cups of milk
\( \displaystyle \frac{\frac{1}{3}}{5} = \frac{1}{15} \) Cup of butter
2. If each person gets 1 waffle, we have;
Number of waffles = 1 + 4 = 5
\( \displaystyle 5 = \frac{10}{2} \)
Dividing the recipe for 10 waffles by 2 gives;
\( \displaystyle \frac{3}{2} = 1\frac{1}{2} \) cups of flour
\( \displaystyle \frac{2}{3 \times 2} = \frac{1}{3} \) teaspoon of salt
\( \displaystyle \frac{4}{2} = 2 \) teaspoons of baking powder
\( \displaystyle \frac{1\frac{3}{4}}{2} = \frac{7}{8} \) Cups of milk
\( \displaystyle \frac{\frac{1}{3}}{2} = \frac{1}{6} \) Cup of butter
3. When each of 300 people can have one, the number of waffles is 300, which gives;
30 × 10 = 300
Multiplying the quantity of each ingredients required to make 10 waffles by 300 gives;
300× 3 = 900 cups of flour
\( \displaystyle 300 \times \frac{2}{3} = 200 \) teaspoon of salt
300 × 4 = 1200 teaspoons of baking powder
\( \displaystyle 300 \times 1\frac{3}{4} = 525 \) Cups of milk
\( \displaystyle 300 \times \frac{1}{3} = 100 \) Cup of butter
4. Time it takes to cook a waffle = 10 minutes
Number of waffles required = 300
Time allowed = 1 hour = 60 minutes
The number of waffle iron is therefore;
\( \displaystyle {n = \frac{300 \times 10}{60} = 50} \)
The number of waffle irons required is 50 waffle irons
5. Number of waffles each server can deliver = 9 waffles
The time it takes each server per trip = 10 minutes
Number of waffles to be delivered = 300
Time in which to deliver the 300 waffles = 1 hour
The number of servers is therefore;
\( \displaystyle {n = \frac{300}{9 \times 6} = 5. \overline 5 \approx 6} \)
The number of trips is therefore;
5 servers will deliver 5×9×6 = 270
The sixth server will deliver the remaining 300 - 270 = 30 waffles in 30 ÷ 9 = 3.3 ≈ 4
The number of trips all together is therefore; 5×6 + 4 = 34 trips
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How much chuck would a chuckwood wood if a chuckwood would wood chuck?
Two circles with unequal radii are extremely tangent. If the
length of a common external line tangent to both circles is 8. What
is the product of the radii of the circles?
The product of the radii of two circles tangent to a common external line can be determined from the length of the line.
Let the radii of the two circles be r1 and r2, where r1 > r2. When a common external line is tangent to both circles, it forms two right triangles with the radii of the circles as their hypotenuses. The length of the common external line is the sum of the hypotenuse lengths, which is given as 8. Therefore, we have r1 + r2 = 8.
To find the product of the radii, we need to eliminate one of the variables. We can square the equation r1 + r2 = 8 to get (r1 + r2)^2 = 64. Expanding this equation gives r1^2 + 2r1r2 + r2^2 = 64.
Now, we can subtract the equation r1 * r2 = (r1 + r2)^2 - (r1^2 + r2^2) = 64 - (r1^2 + r2^2) from the equation r1^2 + 2r1r2 + r2^2 = 64. Simplifying, we get r1 * r2 = 64 - 2r1r2.
Therefore, the product of the radii of the circles is given by r1 * r2 = 64 - 2r1r2.
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Sam has a collection of stamps. He adds 4/5 of a new set of stamps to his collection. If his collection initially had 3/5 of the new set, what fraction of the new set does Sam have?
Answer:
7/5
Step-by-step explanation:
If he starts with 3/5 of the new set, then he begins with 3/5
After adding 4/5 of the new set, you add his current stamps with the new stamps, 3/5 + 4/5 , which results in 7/5
\( \bf{ {15}^{2} \times {3}^{2} \div \sqrt[3]{125} + {9}^{3} = ....} \)
\(\\ \tt\Rrightarrow 15^2\times 3^2\div \sqrt[3]{125}+9^3\)
\(\\ \tt\Rrightarrow 3^25^2\times 3^2\div 5^1+3^33^3\)
\(\\ \tt\Rrightarrow 3^45^1\div 3^6\)
\(\\ \tt\Rrightarrow 3^{-2}5\)
\(\\ \tt\Rrightarrow \dfrac{1}{3^2}5\)
\(\\ \tt\Rrightarrow \dfrac{5}{9}\)
Find equations of the normal plane and osculating plane of the curve at the given point.
X= sin 2t, y=-c0s 2t, z =(0, 1, 2x)
N(x, y, z) = [-1, √3, 2] . [x - √3/2, y + 1/2, z - √3] = 0and O(x, y, z) = [-2√3, -2, 4√3] . [x - √3/2, y + 1/2, z - √3] = 0 respectively.
The equations of the normal plane and osculating plane of the curve at the given point are given by N = 0 and O = 0.
Here is the step-by-step explanation for finding equations of the normal plane and osculating plane of the curve at the given point for X= sin 2t, y=-c0s 2t, z =(0, 1, 2x) and 150:
Given that X= sin 2t, y=-c0s 2t, z =(0, 1, 2x) and t = 150.
Let us first find the first derivative of the given function.
f (t) = [X(t), Y(t), Z(t)] = [sin 2t, -cos 2t, 2 sin 2t]f'(t) = [2 cos 2t, 2 sin 2t, 4 cos 2t]
Again, let us find the second derivative of the given function.
f''(t) = [-4 sin 2t, 4 cos 2t, -8 sin 2t]At t = 150, we have
f'(t) = [2 cos 300, 2 sin 300, 4 cos 300] = [-1, √3, 2]f''(t) = [-4 sin 300, 4 cos 300, -8 sin 300] = [-2 √3, -2, 4 √3]
At the given point [X(150), Y(150), Z(150)] = [sin 300, -cos 300, 2 sin 300] = [√3/2, -1/2, √3]
The equation of the normal plane can be found as
N(x, y, z) = [f'(150)] . [x - X(150), y - Y(150), z - Z(150)] = 0[-1, √3, 2] . [x - √3/2, y + 1/2, z - √3] = 0
The equation of the osculating plane can be found as
O(x, y, z) = [f''(150)] . [x - X(150), y - Y(150), z - Z(150)] = 0[-2√3, -2, 4√3] . [x - √3/2, y + 1/2, z - √3] = 0
Hence, the equations of the normal plane and osculating plane of the curve at the given point are given by
N(x, y, z) = [-1, √3, 2] . [x - √3/2, y + 1/2, z - √3] = 0and O(x, y, z) = [-2√3, -2, 4√3] . [x - √3/2, y + 1/2, z - √3] = 0 respectively.
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Jasmine's bank statement showed the following deposits and withdrawals during a 30-day
month: $2400, $385, -$940.
Part A
What was the average change per day in Jasmine's account during this month?
Answer:
part A . 61.5$
Step-by-step explanation:
total amount = $2400+$385-$940
= 1845$
average change per day = 1845÷
30
answer is 61.5
How many litres can be held by a cylindrical can 14cm in diameter and 20cm hight?
Answer:
about 3.08 L
Step-by-step explanation:
You want the number of litres in the volume of a cylindrical can 14 cm in diameter and 20 cm high.
LitersA litre is a cubic decimeter, 1000 cubic centimeters. As such, it is convenient to perform the volume calculation using the dimensions in decimeters:
14 cm = 1.4 dm . . . . . . diameter20 cm = 2.0 dm . . . . . heightVolumeThe volume of the cylinder is given by the formula ...
V = (π/4)d²h . . . . . . . where d is the diameter and h is the height
V = (π/4)(1.4 dm)²(2.0 dm) ≈ 3.079 dm³ ≈ 3.08 L
The cylindrical can will hold about 3.08 litres.
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Find the nth term rule for the sequence -0. 6,-2. 4,-4. 2,-6
The nth term rule for the given sequence is -2n - 0.6.
In the given sequence, we observe that each term is decreasing by 1.8 as we move from one term to the next. The common difference between consecutive terms is -1.8.
To find the nth term rule, we can express the general term as a function of n. Let's denote the nth term as Tn. We can express the relationship between the term number (n) and the value of the term (Tn) as:
Tn = an + b
Since the common difference between consecutive terms is -1.8, we have a = -1.8. To determine the value of b, we can substitute any term from the sequence. Let's use the first term (-0.6):
-0.6 = -1.8 * 1 + b
Solving for b, we find b = 1.2.
Therefore, the nth term rule for the given sequence is Tn = -1.8n + 1.2, which can be simplified as -2n - 0.6.
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"Glenn has 4 less than twice as many hats as Mia."
1. 2h - 4
2. 2h <4
3. h² – 4
4. 4 - 2h
12. Suppose U= {1, 2, 3, 4, 5, 6, 7, 8} is the universal set and P= {1, 2, 3, 4]. What is P'? (1 point)
O {5, 6, 7, 8}
O {1, 2, 3, 4, 5, 6, 7, 8}
O {1, 2, 3, 4}
O cannot be determined
Answer:
o {5, 6, 7, 8}
Step-by-step explanation:
To find P'
P' = U - P
P' = {1, 2, 3, 4, 5, 6, 7, 8} - {1, 2, 3, 4}
P' = {5, 6, 7, 8} ANS.
if a and b are independent events with p(a) = 0.65 and p(a ∩ b) = 0.26, then, p(b) =
The chance of the event B is 0.4 when using the probability for the two independent two event formula.
In the given question, if a and b are independent events with p(a) = 0.65 and p(a ∩ b) = 0.26, then we have to find the value of p(b).
Events classified as independent do not depend on other events for their occurrence.
Event A's likelihood of happening is P(A)=0.65.
The likelihood of the two events A and B intersecting is P(A∩B)=0.26.
Given that the likelihood of the two independent events is:
P(A∩B) = P(A)⋅P(B)
Then the probability of the event B will be,
P(B) = P(A)/P(A∩B)
P(B) = 0.65/0.26
P(B) =0.4
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