Determine whether the integral is divergent or convergent. If it is convergent, evaluate it. If not, state your answer as divergent.

The method that determines the volume of the prism is simply multiply the area of the base by the height, and the result is 12.5 cm³. (option-a)

To determine the volume of the prism shown in the diagram, we need to multiply the area of the base by the height.

The base of the prism is a rectangle with dimensions 5 cm by 2 cm. Therefore, the area of the base is:

A = length x width = 5 cm x 2 cm = 10 cm²

The height of the prism is 2-¹ cm, which is equivalent to 5/4 cm.

Therefore, the volume of the prism is:

V = A x h = 10 cm² x 5/4 cm = 12.5 cm³

The expressions involving unit cubes and one-quarter cubes are not relevant to this problem and do not provide a method for finding the volume of the prism.

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Answer: Pick a Reporting Period. ...

Generate a Trial Balance Report. ...

Calculate Your Revenue. ...

Determine the Cost of Goods Sold. ...

Calculate the Gross Margin. ...

Include Operating Expenses. ...

Calculate Your Income. ...

Include Income Taxes.

Answer:

  -8/3

Step-by-step explanation:

You want the slope of the line shown in the graph.

Whether counting grid squares on the graph, or using the slope formula, it is convenient to choose two points on the grid where the line crosses the intersection of grid lines.

It appears, the line passes through grid points (1, 4) and (4, -4). Using the slope formula, we find the slope of the line to be ...

  m = (y2 -y1)/(x2 -x1)

  m = (-4 -4)/(4 -1) = -8/3

The slope of the line is -8/3.

The slope is the ratio of "rise" to "run" for the line. From the two points we see where the line crosses grid intersections, we have a "rise" of -1 from y=4 to y=-4, and a "run" of 3 from x=1 to x=4.

  rise/run = -8/3 = slope of the line

Answer:

33.30 units²

Step-by-step explanation:

Central angle = m<BCD = 106°

Radius (r) = 6 units

Area of sector BCD = central angle/360° × πr²

Plug in the values into the formula

Area of sector BCD = 106/360 × π × 6²

Area of sector BCD = 106/360 × π × 36

Area of sector BCD = 33.3008821

Area of sector BCD = 33.30 units² (nearest hundredth)

5x = 2x + 30

5x - 2x = 30

3x = 30

3x/3 = 30/3

x = 10

~Tulpe ⚘

Answer:

Step-by-step explanation:

5x=2x+30 what does x equal

5x=2x+30

5x-2x=30

3x=30

x=30:3

x=10

-------------------

check

5*10=2*10+30

50=50

the answer is good

This is a special triangle.

the two bases are always equal, so a is also 12. To get to the hypotenuse, you must multiply either side by rad2.

a= 12

b= 12rad2

comment if you have any more questions

given that m is parallel to n,

the angle opposite (2x + 16)° is also (2x + 16)° as vertically opposite angles are equal.

using the corresponding angle rule we know that:

2x + 16 = 96

2x = 80

so x = 40

Therefore , the solution of the given problem of fraction comes out to be  1 5/6.

An whole can be represented by any set of related sums or fractions. In standard English, a percentage is used to represent the quantity of a specific size. 8, 3/4. Also wholes are fractions. Numbers are expressed in mathematics using the ratio of it's own portion to the bottom. These fractions are all made up of basic numbers. Due to variances in actual percentage calculations, numerators, and numerators, a difficult fraction contains a fraction.

Here,

To subtract mixed numbers, we first subtract the whole numbers and then subtract the fractions separately.

4 1/2 - 2 2/3

Subtracting the whole numbers:

4 - 2 = 2

Now, let's subtract the fractions.

1/2 - 2/3

To subtract fractions, we need to have a common denominator. In this case, the least common multiple of 2 and 3 is 6.

1/2 = 3/6

2/3 = 4/6

Now we can subtract:

3/6 - 4/6 = -1/6

Putting it all together:

4 1/2 - 2 2/3 = 2 - 1/6

The answer in mixed number form is:

1 5/6

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Answer:

for first one

total area =l×b+1/2×b×h=6×4+1/2×2×6=30cm²

Step-by-step explanation:

for second one

total area =l×b+1/2×b×h=7×5+1/2×7×2=35+7=42m²

Answer:

(x+4)/3. When x is 5 the answer is 3

Step-by-step explanation:

The equation of the line that passes through the point (7, 6) with slope 0 is y = 6

Given,

The points which the line passes, (x₁, y₁) = (7, 6)

Slope of the line, m = 0

We have to find the equation of the line:

We know that,

y - y₁ = m(x - x₁)

So,

y - 6 = 0(x - 7)

y - 6 = 0

y = 6

That is,

The equation of the line that passes through the point (7, 6) with slope 0 is y = 6

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Answer:

The minimum exam score to be awarded an A is about 8.52.

Step-by-step explanation:

Let X represent the scores on a common final exam.

It is provided that X follows a normal distribution with mean, μ = 71 and standard deviation, σ = 9.

It is provided that according to the department policy is that the top 10% of students receive an A.

That is, P (X > x) = 0.10.

⇒ P (X < x) = 0.90

⇒ P (Z < z) = 0.90

The corresponding z-score is:

z = 1.28

Compute the value of x as follows:

\(z=\frac{x-\mu}{\sigma}\\\\1.28=\frac{x-71}{9}\\\\x=71+(1.28\times 9)\\\\x=82.52\)

Thus, the minimum exam score to be awarded an A is about 8.52.

Answer:

12     3

24    6

36    9

48    12

Step-by-step explanation:

a. FPCF for this sample is FPCF = √(199/24) = 2.89.

b. The population cannot be considered effectively infinite, so the answer is no.

When the sample size is significant compared to the size of the community, the Finite Population Correction Factor, also known as the FPC factor, is applied. The population in most cases is so vast that typical sample sizes are insufficient to raise concerns about the need for the FPC.

The recommendation is to use the FPC when the sample size to population size ratio is higher than 5%. The FPCF must be used, for instance, if the population number is 300 and the sample size is 30, which results in a ratio of 10%.

a. To calculate the FPCF (finite population correction factor) for this sample, we can use the formula:

FPCF = √(N/n)

where N is the population size, and n is the sample size.

In this case, N = 199 (the number of blood samples in the racks), and n = 24 (the number of samples selected every seventh blood sample).

FPCF = √(199/24) = 2.89 (rounded to two decimal places)

b. To determine whether the population should be considered effectively infinite, we need to compare the sample size to the population size. A general rule of thumb is that the population can be considered effectively infinite if the sample size is less than 5-10% of the population size.

In this case, the sample size is 24, which is approximately 12% of the population size of 199. Therefore, the population cannot be considered effectively infinite, and the FPCF should be applied to adjust for the finite population size.

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The total height of the building would be nh + 30.

Option (B) is correct.

What is a simplification in mathematics?

In mathematics, simplification refers to the process of making an expression or equation simpler or easier to understand or work with. This can involve combining like terms, removing unnecessary terms or factors, or rearranging the order of the terms.

The building's total height in feet is represented by the sum of the height of each floor plus the height of the spire.

So if the height of each floor is h, and there are n floors in the building and the building's spire is 30 feet, the total height of the building is:

= n * h + 30

=nh + 30

This is because the height of each floor is h, and there are n floors, so the total height of the floors is n * h. Adding the height of the spire, 30 feet, to the total height of the floors gives nh + 30.

Hence, the total height of the building would be nh + 30.

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Answer:

The range of the function is the set of all possible outputs, that is, the set of all values obtained by applying the function to elements of the domain. So the set of all values which can be obtained by applying h(x) to an element of its domain is {−4,0,5,60} , and thus that is the range of h(x)

Step-by-step explanation:

GOOD LUCK

Answer:

  (a)  $479.50

Step-by-step explanation:

You want to know how much the friend with the smaller bedroom will pay for rent if they split the $975 cost based on the square footage of each bedroom. The two bedrooms in the 1225 square foot property are 130 and 150 square feet.

Apparently, the cost of the non-bedroom area is to be split evenly. That common area is ...

  1225 ft² -(150 +130) ft² = 945 ft²

Then the proportion due from the occupant of the smaller bedroom is ...

  (945/2 +130)/1225 = 241/490 ≈ 0.49184

That fraction of the rent is ...

  0.49184 · $975 = $479.54

The nearest answer choice is $479.50.

__

Additional comment

If we were to assume the split is based only on bedroom size, then the rent paid for the 130 ft² space would be (13/28)($975) ≈ $452.68. This would be equivalent to splitting the rent for the common area in the same proportion as for the bedrooms.

We note that half the rent is $487.50, a number less than either of the last two answer choices. Those can be rejected for that reason. (The smaller bedroom is expected to pay less than half of the rent.)

After simplifying the given equation the answer will be -2tanx.

What is identity?

An equation is referred to as an identity if it has one or more variables and is true for all alternate values of the variables for which both sides of the equation are defined.

Sine, cosine, tangent, cosecant, secant, and cotangent are some of their names. The adjacent side, opposite side, and hypotenuse side of the right triangle are used to define each of these trigonometric ratios. The six trigonometric ratios are the source of all fundamental trigonometric identities.

Given: \(\frac{cosx}{1+sinx}-\frac{cosx}{1-sinx}\)

We have to solve this.

Take cross multiplication.

\(= \frac{cosx - cosxsinx-cosx-cosxsinx}{(1-sin^2x)}\\= \frac{-2cosxsinx}{(1-sin^2x)}\)

Since,

\(1-sin^2x=cos^2x\)

\(= \frac{-2sinx}{cosx}\)

Since, \(\frac{sinx}{cosx} = tanx\)

\(= -2tanx\)

Hence, after simplifying the given equation the answer will be -2tanx.

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Answer:

24

Step-by-step explanation:

Since we know what the variables are, we can substitute them. So, you’ll get 3 x 6 + 6. Next, do 3 x 6, which equals 18. Then add the 6, which finally equals 24.

Hope this helps! :)

Answer: If order does not matter then we can use following formula to find different combinations of 6 numbers out of 46 numbers

Step-by-step explanation: Use following Combination formula

nCr = n! / r!(n-r)!

n=46

r=6

=46!/6!(46-6)!

=46!/[6!(40)!]

=(46*45*44*43*42*41*40!)/(6*5*4*3*2*1)(40!)

Cancel out 40!

=46*45*44*43*42*41/(6*5*4*3*2*1)

=6744109680/720

=9366819

Hello,

x = departure's sallary

x*1,1*0,9 = 0,99x

the net change in my salary is 1%

A survey of 135 freshmen business students at a local university. So, many students took English and science, but not music is 39.

These are the specified parameters:

English = 26

Science = 24

Music = 25

English but not science = 17

Science and music = 11

English and music = 14

Took all theree = 4

Lots of students took English and science

Look at the venn diagram in the attachment.

26 + 24 + 25 + x - 4 + 4 + 10 + 7 = 135

x + 92 = 135

x = 135 - 92

x = 43

Lots of students took English and science, but not music

= x - 4

= 43 - 4

= 39

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Answer:

Protons are electrochemically positive in charge and the Neutrons are electrochemically neutral in charge. ... Electrons are electrochemically negatively charged particles that move random around the nucleus. They have a relatively small mass compared to Protons and Neutrons.

Step-by-step explanation:

Answer:

(a) Sample Standard Deviation approximately to the nearest whole number = 6

(b) The use of Empirical Rule to make any general statements about the length of eruptions is empirical rules tell us about how normal a distribution and gives us an idea of what the final outcome about the length of eruptions is.

(c) The percentage of eruptions that last between 92 and 116 seconds using the empirical rule is 95%

(d) The actual percentage of eruptions that last between 92 and 116 seconds, inclusive is 95.45%

(e) The percentage of eruptions that last less than 98 seconds using the empirical rule is 16%

(f) The actual percentage of eruptions that last less than 98 seconds is 15.866%

Step-by-step explanation:

(a) Determine the sample standard deviation length of eruption.

Express your answer rounded to the nearest whole number.

Step 1

We find the Mean.

Mean = Sum of Terms/Number of Terms

= 90+ 90+ 92+94+ 95+99+99+100+100, 101+ 101+ 101+101+ 102+102+ 102+103+103+ 103+103+103+ 104+ 104+104+105+105+105+ 106+106+107+108+108+108 + 109+ 109+ 110+ 110+110+110+ 110+ 111+ 113+ 116+120/44

= 4582/44

= 104.1363636

Step 2

Sample Standard deviation = √(x - Mean)²/n - 1

=√( 90 - 104.1363636)²+ (90-104.1363636)² + (92 -104.1363636)² ..........)/44 - 1

= √(199.836777 + 199.836777 + 147.2913224+ 102.7458678+ 83.47314049+ 26.3822314+ 26.3822314+ 17.10950413+17.10950413+ 9.836776857+ 9.836776857, 9.836776857+9.836776857+ 4.564049585+ 4.564049585+ 4.564049585+ 1.291322313+ 1.291322313+ 1.291322313+ 1.291322313+ 1.291322313+ 0.01859504133+ 0.01859504133+ 0.01859504133+ 0.7458677685+ 0.7458677685+ 0.7458677685+ 3.473140497+ 3.473140497+ 8.200413225+ 14.92768595+ 14.92768595+ 14.92768595+ 23.65495868+ 23.65495868+ 34.38223141+ 34.38223141+34.38223141+ 34.38223141+ 34.38223141+47.10950414+ 78.56404959+ 140.7458677+ 251.6549586) /43

= √1679.181818/43

= √39.05073996

= 6.249059126

Approximately to the nearest whole number:

Mean = 104

Standard deviation = 6

(b) On the basis of the histogram drawn in Section 3.1, Problem 28, comment on the appropriateness of using the Empirical Rule to make any general statements about the length of eruptions.

The use of Empirical Rule to make any general statements about the length of eruptions is empirical rules tell us about how normal a distribution and gives us an idea of what the final outcome about the length of eruptions is .

(c) Use the Empirical Rule to determine the percentage of eruptions that last between 92 and 116 seconds.

The empirical rule formula states that:

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ

Mean = 104, Standard deviation = 6

For 68% μ - σ = 104 - 6 = 98, μ + σ = 104 + 6 = 110

For 95% μ – 2σ = 104 -2(6) = 104 - 12 = 92

μ + 2σ = 104 +2(6) = 104 + 12 = 116

Therefore, the percentage of eruptions that last between 92 and 116 seconds is 95%

(d) Determine the actual percentage of eruptions that last between 92 and 116 seconds, inclusive.

We solve for this using z score formula

The formula for calculating a z-score is is z = (x-μ)/σ

where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean = 104, Standard deviation = 6

For x = 92

z = 92 - 104/6

= -2

Probability value from Z-Table:

P(x = 92) = P(z = -2) = 0.02275

For x = 116

z = 92 - 116/6

= 2

Probability value from Z-Table:

P(x = 116) = P(z = 2) = 0.97725

The actual percentage of eruptions that last between 92 and 116 seconds

= P(x = 116) - P(x = 92)

= 0.97725 - 0.02275

= 0.9545

Converting to percentage = 0.9545 × 100

= 95.45%

Therefore, the actual percentage of eruptions that last between 92 and 116 seconds, inclusive is 95.45%

(e) Use the Empirical Rule to determine the percentage of eruptions that last less than 98 seconds

The empirical rule formula:

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ

For 68% μ - σ = 104 - 6 = 98,

Therefore, 68% of eruptions that last for 98 seconds.

For less than 98 seconds which is the Left hand side of the distribution, it is calculated as

= 100 - 68/2

= 32/2

= 16%

Therefore, the percentage of eruptions that last less than 98 seconds is 16%

(f) Determine the actual percentage of eruptions that last less than 98 seconds.

The formula for calculating a z-score is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

For x = 98

Z score = x - μ/σ

= 98 - 104/6

= -1

Probability value from Z-Table:

P(x ≤ 98) = P(x < 98) = 0.15866

Converting to percentage =

0.15866 × 100

= 15.866%

Therefore, the actual percentage of eruptions that last less than 98 seconds is 15.866%

The value of f'(x) at x = 1 is 1 for first order derivative of x^x^3.

A derivative in calculus is the rate of change of a quantity y with respect to another quantity x. It is also termed the differential coefficient of y with respect to x. Differentiation is the process of finding the derivative of a function.

Given that, x^x^3 and we have to find the first order derivative with respect to x and then find the value at x = 1.

Let's proceed to solve this question accordingly.

let f(x) = x^x^3

The first order derivative = f'(x) = d/dx(x^x^3)

First apply the generalized power rule, then we have

= x^x^3.d/dx(ln(x)x^3)

Applying the power rule, we get

= x^x^3 (d/dx(x^3).ln(x)+x^3.d/dx(ln(x)))

= x^x^3 (3x^2 ln(x) +x^3.1/x)

= x^x^3 (3x^2ln(x) +x^2)

On simplifying, we will get

= x^x^3+2(3ln(x)+1)

f'(x) = d/dx(x^x^3) = x^x^3+2(3ln(x)+1)

Now, at x = 1, we get

f'(x) = d/dx(x^x^3) = x^x^3+2(3ln(x)+1) = 1

Therefore, f'(x) = d/dx(x^x^3) = x^x^3+2(3ln(x)+1) = 1 is the required answer.

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Answer:θ ≈ 2.57 radians

θ ≈ 0.58 radians

Step-by-step explanation:We can solve this quadratic equation in sin(θ) by factoring:

4sin^2(θ) + 7sin(θ) - 5 = 0

(4sin(θ) - 1)(sin(θ) + 5) = 0

Therefore, either:

4sin(θ) - 1 = 0

sin(θ) = 1/4

or:

sin(θ) + 5 = 0

sin(θ) = -5 (not possible, since sin(θ) is between -1 and 1)

So, we have sin(θ) = 1/4. Since 0 ≤ θ < 2π, we can find the two solutions in the interval [0, 2π) by using the inverse sine function:

θ = arcsin(1/4)

Using a calculator, we find:

θ ≈ 0.2531 or θ ≈ 2.8887

Therefore, in radians, the solutions for θ are approximately:

0.2531 (which is less than 2π)

2.8887 (which is greater than 2π)

So the only answer that satisfies 0 ≤ θ < 2π is:

To find the approximate P-value for a given X² value and degrees of freedom (df),

we need to use a chi-square distribution table or calculator. Here are the approximate P-values for the given values of X² and df, rounded to three decimal places:

(a) X² = 6.62, df = 3

The P-value is 0.084.

(b) X² = 17.44, df = 10

The P-value is 0.076.

(c) X² = 28.94, df = 1

The P-value is < 0.001 (less than 0.001).

Note that the "<" symbol indicates that the P-value is very small and cannot be accurately calculated using the table.

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Answer:

maximum is 81.50

minimum is 68.50

Step-by-step explanation:

1m-751=6.50

m-75=6.50

m=81.50

/m-75=-6.5

m=68.50

The maximum and minimum amounts that Victor might have made last month are $81.5 and $68.5, respectively.

The addition is one of the four fundamental mathematical operations, the others being subtraction, multiplication, and division. When two whole numbers are added together, the total quantity or sum of those values is obtained.

Given that Victor has a goal of making $75 per week at his after-school job. and Last month he was within $6.50 of his goal. Therefore, the maximum and minimum amounts that Victor might have made last month are,

Maximum and minimum amount = $75 ± $6.50

                                                      = $75+$6.50 , $75-$6.50

                                                      = $81.5 , $68.5

Hence, the maximum and minimum amounts that Victor might have made last month are $81.5 and $68.5, respectively.

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