Determine whether the functions y1 and y2 are linearly dependent. 1. yı(t) = sin^2 t + cos^2 t, ya(t) = 3 2. y1(t) = e^t , y2(t) = e^{3t}
Answers
To determine whether the functions y1 and y2 are linearly dependent, we need to check if one of them can be expressed as a linear combination of the other.
For the first pair of functions, y1(t) = sin^2 t + cos^2 t and y2(t) = 3, it is clear that they are not linearly dependent. There is no way to express y2(t) as a linear combination of y1(t) or vice versa.
For the second pair of functions, y1(t) = e^t and y2(t) = e^{3t}, we can check if one can be expressed as a constant multiple of the other. If we multiply y1(t) by e^{-2t}, we get y1(t) = e^{-t}.
Now, we can see that y2(t) = e^{3t} can be expressed as e^{3t} = (e^{2t})(e^t) = (y1(t))^3. Therefore, y1(t) and y2(t) are linearly dependent.
In summary, the functions y1(t) = sin^2 t + cos^2 t and y2(t) = 3 are not linearly dependent, while the functions y1(t) = e^t and y2(t) = e^{3t} are linearly dependent as y2(t) can be expressed as a constant multiple of y1(t).
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Related Questions
Find the slope of each line.
Answers
Answer:
2/2
Rise/run of the two dots
Given the situation: Nick takes 7 steps up the stairs of the Tanjay City Science High School and then 5 steps to a landing area. Write an expression the represents the number of steps nick has taken.
Answers
Answer:
7 + 5 = 12
Step-by-step explanation:
7 steps plus 5 steps equals 12 steps
rachel built a rectangular prism that has a volume of 24 cubic inches. what are five possible length, width, and height dimensions for ther prism?
Answers
Answer:
idontknow
Step-by-step explanation:
bro
An 8 feet 3 inches long slide makes an angle
of 34° with the ground. How tall is the ladder
leading to the top of the slide (in feet)?
Answers
Answer:
Step-by-step explanation:
To solve the problem, we can use trigonometry and set up a right triangle with the ladder being the hypotenuse, the height being the opposite side, and the slide being the adjacent side. Then, we can use the tangent ratio to find the height of the ladder.
First, we need to convert the length of the slide from feet and inches to just feet. There are 12 inches in a foot, so 8 feet 3 inches can be written as:
8 + 3/12 feet = 8.25 feet
Next, we can use the tangent ratio:
tan(34°) = opposite/adjacent
where the opposite side is the height of the ladder, and the adjacent side is the length of the slide.
Plugging in the values we get:
tan(34°) = height/8.25
Solving for height, we get:
height = 8.25 x tan(34°)
Using a calculator, we can find that:
height ≈ 5.21 feet
Therefore, the height of the ladder leading to the top of the slide is approximately 5.21 feet.
5. Solve the system using the method of elimination: 4x - 5y = 3x+5y = 37 TAI 0, [C] -4, 16 [B] (4, 5) [D] no solution
Answers
Answer: The elimination method is a technique for solving systems of linear equations. Let's walk through a couple of examples.
Example 1
We're asked to solve this system of equations:
\begin{aligned} 2y+7x &= -5\\\\ 5y-7x &= 12 \end{aligned}
2y+7x
5y−7x
=−5
=12
We notice that the first equation has a 7x7x7, x term and the second equation has a -7x−7xminus, 7, x term. These terms will cancel if we add the equations together—that is, we'll eliminate the xxx terms:
\begin{aligned} 2y+\redD{7x} &= -5 \\ +~5y\redD{-7x}&=12\\ \hline\\ 7y+0 &=7 \end{aligned}
2y+7x
+ 5y−7x
7y+0
=−5
=12
=7
Solving for yyy, we get:
\begin{aligned} 7y+0 &=7\\\\ 7y &=7\\\\ y &=\goldD{1} \end{aligned}
7y+0
7y
y
=7
=7
=1
Plugging this value back into our first equation, we solve for the other variable:
\begin{aligned} 2y+7x &= -5\\\\ 2\cdot \goldD{1}+7x &= -5\\\\ 2+7x&=-5\\\\ 7x&=-7\\\\ x&=\blueD{-1} \end{aligned}
2y+7x
2⋅1+7x
2+7x
7x
x
=−5
=−5
=−5
=−7
=−1
The solution to the system is x=\blueD{-1}x=−1x, equals, start color #11accd, minus, 1, end color #11accd, y=\goldD{1}y=1y, equals, start color #e07d10, 1, end color #e07d10.
We can check our solution by plugging these values back into the original equations. Let's try the second equation:
\begin{aligned} 5y-7x &= 12\\\\ 5\cdot\goldD{1}-7(\blueD{-1}) &\stackrel ?= 12\\\\ 5+7 &= 12 \end{aligned}
5y−7x
5⋅1−7(−1)
5+7
=12
=
?
12
=12
Yes, the solution checks out.
If you feel uncertain why this process works, check out this intro video for an in-depth walkthrough.
Example 2
We're asked to solve this system of equations:
\begin{aligned} -9y+4x - 20&=0\\\\ -7y+16x-80&=0 \end{aligned}
−9y+4x−20
−7y+16x−80
=0
=0
We can multiply the first equation by -4−4minus, 4 to get an equivalent equation that has a \purpleD{-16x}−16xstart color #7854ab, minus, 16, x, end color #7854ab term. Our new (but equivalent!) system of equations looks like this:
\begin{aligned} 36y\purpleD{-16x}+80&=0\\\\ -7y+16x-80&=0 \end{aligned}
36y−16x+80
−7y+16x−80
=0
=0
Adding the equations to eliminate the xxx terms, we get:
\begin{aligned} 36y-\redD{16x} +80&=0 \\ {+}~-7y+\redD{16x}-80&=0\\ \hline\\ 29y+0 -0&=0 \end{aligned}
36y−16x+80
+ −7y+16x−80
29y+0−0
=0
=0
=0
Solving for yyy, we get:
\begin{aligned} 29y+0 -0&=0 \\\\ 29y&=0 \\\\ y&=\goldD 0 \end{aligned}
29y+0−0
29y
y
=0
=0
=0
Plugging this value back into our first equation, we solve for the other variable:
\begin{aligned} 36y-16x+80&=0\\\\ 36\cdot 0-16x+80&=0\\\\ -16x+80&=0\\\\ -16x&=-80\\\\ x&=\blueD{5} \end{aligned}
36y−16x+80
36⋅0−16x+80
−16x+80
−16x
x
=0
=0
=0
=−80
=5
The solution to the system is x=\blueD{5}x=5x, equals, start color #11accd, 5, end color #11accd, y=\goldD{0}y=0y, equals, start color #e07d10, 0, end color #e07d10.
Want to see another example of solving a complicated problem with the elimination method? Check out this video.
Practice
PROBLEM 1
Solve the following system of equations.
\begin{aligned} 3x+8y &= 15\\\\ 2x-8y &= 10 \end{aligned}
3x+8y
2x−8y
Step-by-step explanation:
Question two, please help
2/10
Answers
Answer:
C,D
Step-by-step explanation:
Of all the numbers whose difference is 10, find the two that have the minimum product
Answers
Answer: -9
Step-by-step explanation: You might think that the smallest two numbers are 11 and 1 but there are negative numbers. 1 - (-9) is equal to 10. 1 x (-9) is -9.
Can someone please help me with this
Answers
Answer:
A = 22.5 sq units
Step-by-step explanation:
A = 1/2h(sum of bases)
A = 1/2(5)(3+6)
A = 2.5(9)
A = 22.5
in each of problems 6 through 7, use the linearity of the laplace transform to find the laplace transform of the given function; a and b are real constants. 6. f (t) = cohs(bt)
Answers
The laplace transform of the given function where a and b are real constants is \(= \frac{s}{s^2-b^2}\).
In each of problems 6 through 7 By using the linearity of the laplace transform.
To find the laplace transform of the given function:
Given f(t) = cosh(bt)
\(= \frac{e^{bt}+e^{-bt}}{2} \\\\L[e^{bt}] = \frac{1}{s-b} \\\\L[e^{bt}] = \frac{1}{s+b} \\\\\\f(s) = \frac{1}{2} [\frac{1}{s-b}+ \frac{1}{s-b} ]\\\\= \frac{1}{2}[\frac{s+b+s-b}{s^2 - b^2} ]\)
By simplifying, we get
\(= \frac{s}{s^2-b^2}\)
Hence the answer is the laplace transform of the given function where a and b are real constants is \(= \frac{s}{s^2-b^2}\).
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Fahima buys
2 packets of bread rolls costing £1.50 for each packet
1 bottle of ketchup costing £1.60
3 packets of sausages
Fahima pays with a £10 note
she gets 30p change
fahmia works out that one packet of sausages costs £2.30
is fahima right?
you must show how you get you answer
Answers
reduce to the simplest form\(\frac{286}{858}\)
Answers
Answer:
143 over 428
Step-by-step explanation:
Can someone solve this?
Answers
Answer:
Jake is 13 years oldStep-by-step explanation:
D - age of Dani
J = D+2 - age of Jake
E = 2J = 2(D+2) = 2D+4 - age od Ethan
Z = 2E = 2(2D+4) = 4D+8 - age of Zoe
The sum of their ages is 102:
D + J + E + Z = 102
D + D+2 + 2D+4 + 4D+8 = 102
8D + 14 = 102
-14 -14
8D = 88
÷8 ÷8
D = 11
J = 11+2 = 13
If the limit definition of a derivative can be used to find f^ prime (x) , then what is the purpose of using other rules to find f^ prime (x) ^ primeChoose the correct answer below.A. The other rules for derivatives are easier to use and may take less time than the limit definition.B. f(x) = x/n The limit definition cannot be used to find the derivative of a function of the form n ne0.C. The other rules for derivatives can be used to check the answer found by using the limit definition.D. The limit definition cannot be used to find the derivative of a function of the form f(x) = nx
Answers
The other rules for derivatives can be used to check the answer found by using the limit definition. To find the derivative of a function, like f(x) = x/n, where n ≠ 0, using the limit definition of a derivative, we must take the limit of the quotient f(x+h) - f(x) / h as h approaches 0.
However, other rules for derivatives, like the power rule, can also be used to find the derivative of f(x) = x/n and can be used to check the answer found by using the limit definition.
Power law:
According to the derivative power rule, d/dx (xn) = n xn - 1.
Rule of sum and difference
This rule states that when there is a sum or difference, the differentiation process can be dispersed to the functions. d/dx (f(x) g(x)) = d/dx (f(x)) d/dx (g(x)), for example.
Product law:
To determine the derivative of the product of two functions, apply the product rule. It states that f(x) d/dx (g(x)) + g(x) d/dx (f(x)) = d/dx (f(x)) (f(x)) g(x)). It can be expressed mathematically as (uv)' = u v' + v u'.
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Solve the triangle for the missing pieces (round to two decimal places).
Answers
The unknown values in the triangles are:
H = 88°
h ≈ 3.35
g ≈ 7.25
What is the law of sines?
The law of sine or the sine law states the ratio of the side length of a triangle to the sine of the opposite angle, which is the same for all three sides.
To find the unknown value of H, we can use the fact that the sum of the angles in a triangle is 180 degrees. We have:
∠F + ∠G + ∠H = 180°
25 + 67 + ∠H = 180°
∠H = 180 - 25 - 67
∠H = 88°
Therefore, the unknown value of H is 88°.
To find the unknown values of h and g, we can use the law of sines, which states that in any triangle ABC:
a/sin(A) = b/sin(B) = c/sin(C)
Let's use this formula to find the values of h and g:
h/sin(25) = 7/sin(67) (using angle G and side GH)
h = (7/sin(67)) * sin(25)
h ≈ 3.35
g/sin(88) = 7/sin(67) (using angle G and side GH)
g = (7/sin(67)) * sin(88)
g ≈ 7.25
Therefore, the unknown values in the triangles are:
H = 88°
h ≈ 3.35
g ≈ 7.25
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If someone answers this you getting 25 points and brainliest :D
Answers
the answer Is 0.24
Step-by-step explanation:
2.1 times 4.4 is
9.24
3.6 divided by 0.4 is
9
9.24 - 9
= 0.24
Remeber guys, we need to use pemdos. In this case we need to do 1. Multiplication
2. Division
3. Subtraction
We cannot do subtraction or division first. We need to go by order.
farmer has 200 feet of fencing to build rectangular chicken pen along side of barn, what is largest area possible
Answers
The largest area possible is when the length and width of the chicken pen are both 100 feet. In that case, the area of the chicken pen would be 10,000 square feet.
We are given that the farmer has 200 feet of fencing to build a rectangular chicken pen along the side of a barn. We need to find the largest possible area the chicken pen can have.
To do this, we need to find the length and width of the chicken pen such that the total amount of fencing used is 200 feet.
Since the total amount of fencing needed is 200 feet, the length and width of the chicken pen must both be 100 feet. In this case, the area of the chicken pen would be 10,000 square feet.
Therefore, the largest area possible is 10,000 square feet when the length and width of the chicken pen are both 100 feet.
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Given a normal distribution with μ=46 and σ=5, complete parts (a) through (d). Click here to view page 1 of the cumulative standardized normal distribution table. Click here to view page 2 of the cumulative standardized normal distribution table. a. What is the probability that X>37 ? P(X>37)= (Round to four decimal places as needed.) b. What is the probability that X<41 ? P(X<41)= (Round to four decimal places as needed.) c. For this distribution, 10% of the values are less than what X-value? X= (Round to the nearest integer as needed.) d. Between what two X-values (symmetrically distributed around the mean) are 60% of the values? For this distribution, 60% of the values are between X= and X= (Round to the nearest integer as needed.)
Answers
a.The probability that X > 37, P(X > 37) = 0.9641
b. P(X < 41) = 0.1587
c. X = 39
d. X = 42 and X = 50 (symmetrically distributed around the mean)
a. To find the probability that X > 37, we need to calculate the area under the normal distribution curve to the right of 37. Using the z-score formula:
z = (X - μ) / σ
where X is the given value, μ is the mean, and σ is the standard deviation, we can calculate the z-score:
z = (37 - 46) / 5 = -1.8
Using the cumulative standardized normal distribution table, we can find the corresponding probability. The table indicates that P(Z < -1.8) = 0.0359.
Since we are interested in P(X > 37), which is the complement of P(X ≤ 37), we subtract the obtained value from 1:
P(X > 37) = 1 - 0.0359 = 0.9641 (rounded to four decimal places)
b. To find the probability that X < 41, we calculate the z-score:
z = (41 - 46) / 5 = -1
From the cumulative standardized normal distribution table, we find that P(Z < -1) = 0.1587.
Therefore, P(X < 41) = 0.1587 (rounded to four decimal places).
c. To find the X-value for which 10% of the values are less, we need to find the corresponding z-score. From the cumulative standardized normal distribution table, we find that the z-score for a cumulative probability of 0.10 is approximately -1.28.
Using the formula for the z-score:
z = (X - μ) / σ
we rearrange it to solve for X:
X = μ + (z * σ)
X = 46 + (-1.28 * 5) ≈ 39 (rounded to the nearest integer)
Therefore, 10% of the values are less than X = 39.
d. To find the X-values between which 60% of the values are located, we need to determine the z-scores corresponding to the cumulative probabilities that bracket the 60% range.
Using the cumulative standardized normal distribution table, we find that a cumulative probability of 0.20 corresponds to a z-score of approximately -0.84, and a cumulative probability of 0.80 corresponds to a z-score of approximately 0.84.
Using the z-score formula:
X = μ + (z * σ)
X1 = 46 + (-0.84 * 5) ≈ 42 (rounded to the nearest integer)
X2 = 46 + (0.84 * 5) ≈ 50 (rounded to the nearest integer)
Therefore, 60% of the values are between X = 42 and X = 50.
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A circular clock has a circumference of 48.5 meters. What the measurement of the radius, in meters, of the clock?
Answers
Answer:
The radius of the clock is 7.72 meters
Step-by-step explanation:
Here, we want to calculate the radius of a clock which has a circumference of 48.5 m
Mathematically;
Circumference C = 2 * pi * r
48.5 = 2 * 22/7 * r
7 * 48.5 = 44r
r = (7 * 48.5)/44
r = 7.72 meters
A 90% confidence interval for the proportion of Americans with cancer was found to be (0.185,0 210). The point estimate for this confidence interval is. a. 00125 b.1645 c. 0.1975 d.0.395
Answers
The point estimate for the confidence interval (0.185, 0.210) representing the proportion of Americans with cancer is 0.1975 (option c).
The point estimate for the confidence interval (0.185, 0.210) representing the proportion of Americans with cancer is 0.1975 (option c). The point estimate is the midpoint of the confidence interval and provides an estimate of the true proportion.
In this case, the midpoint is calculated as the average of the lower and upper bounds: (0.185 + 0.210) / 2 = 0.1975. Therefore, 0.1975 is the best estimate for the proportion of Americans with cancer based on the given confidence interval.
To obtain the point estimate, we take the average of the lower and upper bounds of the confidence interval. In this case, the lower bound is 0.185 and the upper bound is 0.210.
Adding these two values and dividing by 2 gives us 0.1975, which represents the point estimate. This means that based on the data and the statistical analysis, we estimate that approximately 19.75% of Americans have cancer.
It's important to note that this point estimate is subject to sampling variability and the true proportion may differ, but we can be 90% confident that the true proportion lies within the given confidence interval.
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the lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min. if one such class is randomly selected, find the probability that the class length is more than 51.7 min.
Answers
The probability that the class length is more than 51.7 min is 0.3 or 30%.
To solve the problem, we first need to find the total possible outcomes, which is the range of class lengths between 50.0 min and 52.0 min, which is 2.0 min. Since the distribution is uniform, each possible class length within this range is equally likely.
Next, we need to find the favorable outcomes, which is the range of class lengths that are more than 51.7 min. This range is 52.0 min minus 51.7 min, which equals 0.3 min.
To find the probability, we divide the number of favorable outcomes by the total number of possible outcomes:
Probability = (favorable outcomes) / (total outcomes) = 0.3 min / 2.0 min = 0.15 or 15%.
Therefore, the probability of a randomly selected class length being more than 51.7 min is 0.3 or 30%.
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Using the order of operations, what should be done first to evaluate 12 divided by (negative 6) (3) + (negative 2)? Divide 12 by 5. Multiply –6 and 3. Divide 12 by –6. Add 3 and –2
Answers
12 / (-6)(3) + (-2)
First divide 12 by -6
Answer:
divide 12 by -6
Step-by-step explanation:
exponents, parenthesis, divide, miltiplied
subtract, add
Find the indicated term of the arithmetic sequence with the given description.
The 100th term is - 1240, and the common difference is -25. Find the fifth term.
as = ?
Answers
The fifth term of the arithmetic sequence is -1190.
How to find the arithmetic sequence?An arithmetic sequence is a sequence of numbers in which the difference between consecutive terms remains constant. To find the fifth term, we can use the formula for the nth term of an arithmetic sequence:
aₙ = a₁ + (n - 1) * d
where aₙ represents the nth term, a₁ is the first term, n is the position of the term, and d is the common difference.
Given that the 100th term is -1240 and the common difference is -25, we can substitute these values into the formula.
Since the fifth term corresponds to n = 5, we can calculate:
a₅ = -1240 + (5 - 1) * (-25)
= -1240 + 4 * (-25)
= -1240 - 100
= -1340
Therefore, the fifth term of the arithmetic sequence is -1190.
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what is a factor of 8
Answers
the smallest natural number that 360 must be multiplied by to get a square number
Answers
Answer:
10
Step-by-step explanation:
Step 1: do prime factorisation of 360
360=2 ×2×2×3×3×5
Step 2: make pair of 2 same digits
Step 3: now multiply unpaired no.
5×2=10
so your answer is 10
A line passes through the point (10,-9) and has a slope of -5/2. Write an equation in slope-intercept form for this line.
Answers
Answer:
Step-by-step explanation:
y + 9 = -5/2(x - 10)
y + 9 = -5/2x + 25
y = -5/2x + 16
If the following fraction is reduced, what will be the exponent on the p? - 5p*5 q*4/8p*2 q*2
Answers
The requried, exponent of the p in the simplified expression is 3.
To reduce the fraction, we can cancel out any common factors in the numerator and denominator.
So the fraction becomes:
(-5p⁵ q⁴) / (8p² q²)
To simplify this fraction further, we can cancel out a factor of p in the numerator and denominator.
This leaves us with:
-5/8 * p³q²
Now we can see that the exponent on the remaining p is 3 because we canceled out one factor of p from the denominator.
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A pallet of floor tiles contains 60 cases of tiles, and the yard has 10 complete pallets of tile. If you remove 180 cases for one customer how many cases of tiles will be remaining in the yard?
Answers
Total cases = total pallets x cases per pallet
Total cases = 60 x 10 = 600 cases
600 cases - 180 cases = 420 cases left
Answer: 420 cases
1.
a)To test the hypothesis that the population standard deviation sigma=4. 1, a sample size n=25 yields a sample standard deviation 3. 841. Calculate the P-value and choose the correct conclusion.
Your answer:
The P-value 0. 028 is not significant and so does not strongly suggest that sigma<4. 1.
The P-value 0. 028 is significant and so strongly suggests that sigma<4. 1.
The P-value 0. 020 is not significant and so does not strongly suggest that sigma<4. 1.
The P-value 0. 020 is significant and so strongly suggests that sigma<4. 1.
The P-value 0. 217 is not significant and so does not strongly suggest that sigma<4. 1.
The P-value 0. 217 is significant and so strongly suggests that sigma<4. 1.
The P-value 0. 365 is not significant and so does not strongly suggest that sigma<4. 1.
The P-value 0. 365 is significant and so strongly suggests that sigma<4. 1.
The P-value 0. 311 is not significant and so does not strongly suggest that sigma<4. 1.
The P-value 0. 311 is significant and so strongly suggests that sigma<4. 1.
b)
To test the hypothesis that the population standard deviation sigma=9. 1, a sample size n=15 yields a sample standard deviation 5. 506. Calculate the P-value and choose the correct conclusion.
Your answer:
The P-value 0. 305 is not significant and so does not strongly suggest that sigma<9. 1.
The P-value 0. 305 is significant and so strongly suggests that sigma<9. 1.
The P-value 0. 189 is not significant and so does not strongly suggest that sigma<9. 1.
The P-value 0. 189 is significant and so strongly suggests that sigma<9. 1.
The P-value 0. 003 is not significant and so does not strongly suggest that sigma<9. 1.
The P-value 0. 003 is significant and so strongly suggests that sigma<9. 1.
The P-value 0. 016 is not significant and so does not strongly suggest that sigma<9. 1.
The P-value 0. 016 is significant and so strongly suggests that sigma<9. 1.
The P-value 0. 021 is not significant and so does not strongly suggest that sigma<9. 1.
The P-value 0. 021 is significant and so strongly suggests that sigma<9. 1
Answers
a) To test the hypothesis that the population standard deviation σ = 4.1, with a sample size n = 25 and a sample standard deviation s = 3.841, we need to calculate the P-value.
The degrees of freedom (df) for the test is given by (n - 1) = (25 - 1) = 24.
Using the chi-square distribution, we calculate the P-value by comparing the test statistic (χ^2) to the critical value.
the correct conclusion is:
The P-value 0.305 is not significant and so does not strongly suggest that σ < 9.1. The test statistic is calculated as: χ^2 = (n - 1) * (s^2 / σ^2) = 24 * (3.841 / 4.1^2) ≈ 21.972
Using a chi-square distribution table or statistical software, we find that the P-value corresponding to χ^2 = 21.972 and df = 24 is approximately 0.028.
Therefore, the correct conclusion is:
The P-value 0.028 is not significant and so does not strongly suggest that σ < 4.1.
b) To test the hypothesis that the population standard deviation σ = 9.1, with a sample size n = 15 and a sample standard deviation s = 5.506, we follow the same steps as in part (a).
The degrees of freedom (df) for the test is (n - 1) = (15 - 1) = 14.
The test statistic is calculated as:
χ^2 = (n - 1) * (s^2 / σ^2) = 14 * (5.506 / 9.1^2) ≈ 1.213
Using a chi-square distribution table or statistical software, we find that the P-value corresponding to χ^2 = 1.213 and df = 14 is approximately 0.305.
Therefore, the correct conclusion is:
The P-value 0.305 is not significant and so does not strongly suggest that σ < 9.1.
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The _________ setting in the option profile automatically closes any open vulnerabilities on ports that are no longer targeted in your scan job.
Answers
The name which is given to the setting in the option profile which automatically closes any open vulnerabilities on ports that are no longer targeted in your scan job is:
Vulnerability DetectionBased on the given question, we can see that in network security, there are certain protocols which has to be followed to ensure that there is security and that unauthorised access does not occur.
As a result of this, the Vulnerability Detection is used to set in the option profile to help to close the open vulnerability on the ports which are not targeted in the scan job.
Therefore, the correct answer is Vulnerability Detection
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In the 2017 national Youth Risk Behavior Survey, 16.5% of high school students had ridden with a driver who had been drinking alcohol within the previous month. This data came from an SRS of 14,500 students. Find the probability of selecting an SRS of 14,500 students in which less than 15% had ridden with a driver who had been drinking alcohol within the previous month.