Determine whether each pair of lines are parallel, perpendicular, or neither. Select the correct answer for each lettered part.

The y is a constant function, since its derivative is 0, Therefore, y(64) = 1

To solve this problem, we need to use implicit differentiation. First, we differentiate both sides of the equation VI + Vy = 9 with respect to x (since y is a function of x) using the chain rule:

d/dx(VI) + d/dx(Vy) = d/dx(9)

Since VI is a constant, its derivative is 0, and we can simplify to:

V d/dx(y) = 0

Now we can solve for d/dx(y):

d/dx(y) = 0/V = 0

This tells us that y is a constant function, since its derivative is 0. Therefore, y(64) = 1 is the only possible value for y(64), since it is given in the problem.

So, to answer the question, y(64) = 1.

To learn more about derivative  click here

brainly.com/question/25324584

#SPJ11

\(\qquad\) ☀️So First – we have to find the perimeter of the frame on which the glue is applied and the length of the ribbon used by Miguel. The perimeter of the frame is the total length of ribbon Miguel uses.

\(\qquad\)____________________

According to the question:-

\(\qquad\)\( \pink{\bf\longrightarrow Perimeter _{(The \:frame) }= The\: total\: length\: of \:ribbon}\)

\(\qquad\)\( \purple{\bf \longrightarrow Perimeter _{(The \:frame) } = 2 ( length\: of\: the \:frame + breadth \:of \:the\: frame )}\)

\(\qquad\)\( \sf \longrightarrow Perimeter _{(The\: frame) } = 2 ( 5 + 8 ) \)

\(\qquad\)\( \sf \longrightarrow Perimeter _{(The \:frame) }= 2 ( 5 ) + 2 ( 8 ) \)

\(\qquad\)\( \sf \longrightarrow Perimeter _{(The\: frame) }= 10 + 16 \)

\(\qquad\)\( \purple{\bf \longrightarrow Perimeter _{(The \:frame) }= 26\: inch} \)

Therefore,

\(\qquad\)____________________

The Answer will be 26 inch

Answer:

From left to right:

The first one is 2

The second one is 1/2

The third one is 2

The fourth one is 1

Step-by-step explanation:

Answer:

x<5/2

Step-by-step explanation:

We have

2x−3<2

Add 3 to both sides.

2x−3 +3 <2 +3

which makes

2x<5

Divide both sides by 2.

2x/2 < 5/2

x<5/2

There are a total of 32768 (8) 5-letter "words" made from the letters a through h when all possible combinations are considered.

Consider all 5-letter "words" made from the letters A through H. There are a total of 8 unique letters, and since repetition is allowed, you can form 8 different possibilities for each of the 5 positions in the word. To calculate the total number of these words, simply multiply the possibilities for each position: 8 * 8 * 8 * 8 * 8 = 32,768. So, there are 32,768 possible 5-letter "words" using the letters A through H.

Know more about combinations here:

https://brainly.com/question/19692242

#SPJ11

Step-by-step explanation:

A) The amount is taken during the first dose is - 500 mg

In 10 days, she will take the drugs for 240/12 = 20 times

After 12 hours, 4.5 % of drugs remain in the blood therefore

after the first dose = 500

second dose, 4.5% of  500 + 500 = 22.5 +500 = 522.5 mg

third dose, 4.5 % of 522. 5 + 500 = 523.51 mg

Forth dose, 4. 5% of 523.51 + 500 = 523.55 mg

B) Highest amount will be found on 20th dose.

= 500 x (1-0.045^20/ 1- 0.045)

= 523.55 mg

C) The highest amount in the body is near to 523.55 mg therefore after 10 days also, the amount of drug will remain near the value of 523.55 mg.

The sample mean of 5.2 hours represents the average sleep duration observed in the sampled group of 29 students, while the claimed population mean of 6.2 hours represents the average sleep.

In the context of statistical inference, the term "sample mean" refers to the average of a subset of data taken from a larger population, while the "population mean" represents the average of the entire population.

In this scenario, the value 6.2 hours represents the claimed population mean. This is the average sleep duration stated in the college newspaper article,

which claims to represent the average sleep time of all college students. It is an estimate of the population mean based on available information.

On the other hand, the value 5.2 hours represents the sample mean. It is the average sleep duration observed from a randomly sampled group of 29 students.

The student who conducted the survey wanted to test the claim made in the newspaper article by collecting data from a smaller subset of the population.

The sample mean serves as an estimate of the population mean. By calculating the average sleep duration from the sampled students, the student aimed to make an inference about the larger population of college students.

The sample mean provides insight into the sleep habits of the sampled students, but it may or may not accurately reflect the population mean.

In summary, the sample mean of 5.2 hours represents the average sleep duration observed in the sampled group of 29 students,

while the claimed population mean of 6.2 hours represents the average sleep duration stated in the college newspaper article for all college students.

To know more about statistical refer here:

https://brainly.com/question/32201536#

#SPJ11

Step-by-step explanation:

hope it helps.

No, a fraction is not a term. The distributive property can be applied to fractions because it is a general mathematical principle.

A fraction is not considered a term in the traditional sense. It is a mathematical expression that represents division. However, the distributive property can still be applied to fractions because the property itself is a fundamental rule of arithmetic that extends beyond specific types of expressions.

The distributive property states that for any real numbers a, b, and c:

a × (b + c) = (a × b) + (a × c).

When working with fractions, we can apply the distributive property as follows:

Let's consider the expression: a × (b/c).

We can rewrite this as: (a × b)/c.

Now, let's distribute the 'a' to 'b' and 'c':

(a × b)/c = (a/c) × b.

In this step, we applied the distributive property to the fraction (a/c) by treating it as a whole.

Although fractions represent division, we can still use the distributive property because it is a general mathematical principle that allows for manipulating expressions involving addition, subtraction, multiplication, and division.

For more such question on fraction

https://brainly.com/question/17220365

#SPJ8

The value of p is 2 and q is either 7 or 13 and their sum is either 9 or 15.

It is given that the value of p and q is a prime number, and p<q.

But it is also given that the value of both should be less than 18 as well as a prime number.

Therefore the value of both should be 2, 3, 5, 7, 11, 13, and 17.

And it is also given that p<q.

Now we have to find the value of p + q which is odd but not a prime number.

To have a sum as an odd number one number should be even and as it is given that p<q, therefore p=2, and q = 3, 5, 7, 11, 13, 17.

So

p + q = 2 + 5 = 7, which is odd but it is prime

Now again, q = 7

p + q = 2 + 7 = 9 , which is odd as well as not prime.

Again take q = 11

p + q = 2 + 11 = 13, which is odd but prime

Now take q = 13

p + q =  2 + 13 = 15, which is odd as well as not prime.

Now take q = 17

p + q = 2 + 17 = 19, which is odd and prime.

Therefore we have p =2 and q = 7 or 13 and sum p + q =9 or 15 which is odd but not prime.

To know more about the prime number refer to the link given below:

https://brainly.com/question/792663

#SPJ1

Answer:

B.   3,158

Step-by-step explanation:

h(x) = -49x − 125

Let x = -67

h(-67) = -49(-67) − 125

          =3283-125

          = 3158

Answer:

Answer B

Step-by-step explanation:

To find the value of h(-67) for the function h(x) = -49x - 125,

we substitute -67 for x in the function and evaluate it.

h ( - 67 ) = - 49 ( - 67 ) - 125

Now we can simplify the expression:

h ( -67 ) = 3283 - 125

h ( -67 ) = 3158

Step-by-step explanation:

100℅=1225

43℅=x

criss cross

100℅x=526.75

100℅ 100℅

x=526.75 are studing science or engineering

100℅=1225

7%=x

do it like this

527 students at a university college  are studying science or engineering, 86 students own a car and 1005 students say it is a good college.

percentage, a relative value indicating hundredth parts of any quantity.

There are 1225 students at a university college.

43% are studying science or engineering

43/100×1225

0.43×1225

526.75

527

Hence 527 students at a university college  are studying science or engineering.

7% own a car

7/100×1225

0.07×1225

85.75=86

86 students at a university college own a car.

82% say it is a good college.

82/100×1225

0.82×1225

1004.5=1005

Hence, 1005 students at a university college say it is a good college.

Therefore, 527 students at a university college  are studying science or engineering, 86 students own a car and 1005 students say it is a good college.

To learn more on Percentage click:

https://brainly.com/question/28269290

#SPJ2

Answer:

18cm

Step-by-step explanation:

Find the image to the question attached.

From the ruler, we are to find the distance between R and S i.e RS

From the ruler, R is on 8 and S is on 26.

Initial point R = 8

Final point S = 26

Length of RS = Final point S - initial point R

RS = 26 - 8

RS = 18

Hence the length of RS is 18cm

Three examples of errors that would not be detected by the checksum of the GTIN number 978-0-7356-1967-8 are:

1. Transposing two adjacent digits: 978-0-7356-1976-8.

2. Substituting one digit with another: 978-0-7356-1867-8.

3. Swapping two non-adjacent digits: 978-0-7536-1967-8.

The checksum in a GTIN number is calculated using a formula that assigns weights to each digit and performs a modulo 10 operation. In this case, the formula used is called the GTIN-13 algorithm, which calculates the 13th digit (checksum) based on the first 12 digits. The checksum is designed to detect common errors, such as transpositions, substitutions, and swaps, by ensuring that the resulting sum is divisible by 10.

However, there are certain errors that can occur and still result in a valid checksum. For example, transposing two adjacent digits (e.g., switching 6 and 7 in 1967) would not be detected because the individual digit weights cancel each other out. Similarly, substituting one digit with another (e.g., replacing 9 with 8) may also go undetected because the sum remains the same. Additionally, swapping two non-adjacent digits (e.g., exchanging the positions of 5 and 7) does not affect the checksum either.

Learn more about: checksum of the GTIN

brainly.com/question/31386808

#SPJ11

The solution is:  The required value of x is - 2.

We are given the following two functions :

f(x)=x^2-2x and g(x)=6x=4

We are to find the value of x for which (f + g)(x) = 0.

We know that for any two functions p(x) and q(x), the following property holds true :

p(x) + q(x) = (p+q)x

We have

(f + g)(x) = 0

x^2 - 2x + 6x + 4 = 0

x^2 + 4x + 4 = 0

(x + 2)^2 = 0

x + 2 = 0

x = -2

Thus, the required value of x is - 2.

To learn more on function click:

brainly.com/question/21145944

#SPJ1

complete question:

If f(x)=x2-2x and g(x)=6x=4, for which value of x does (f+g)(x)=0

Answer:

B. Bread ingredients

Step-by-step explanation:

I took the test on Edge 2021 :p

Answer:

B

Step-by-step explanation:

Bread ingredients

Answer:

A and B

Step-by-step explanation:

Please let me know if you want an explanation for why this is the answer (comment on this answer). A lot of people don't actually read the explanations, so I wouldn't want to waste my time. However, if you would like it I would be more than happy to type one out for you. Thanks!

The probability that the sum of the three recorded numbers is less than 6 is 19/27

To find the probability that the sum of the three recorded numbers is less than a certain value, we can use the technique of generating functions.

Let's first write the generating function for one draw from the bag. Each ball has a 1/3 probability of being drawn, and the number on the ball contributes that amount to the sum. So the generating function for one draw is

g(x) = (1/3)x + (1/3)x^2 + (1/3)x^3

To find the generating function for the sum of three draws, we can cube the generating function for one draw

g(x)^3 = [(1/3)x + (1/3)x^2 + (1/3)x^3]^3

Expanding this expression using the binomial theorem, we get

g(x)^3 = (1/27)x^3 + (1/9)x^4 + (5/27)x^5 + (5/18)x^6 + (5/27)x^7 + (1/9)x^8 + (1/27)x^9

The coefficient of each term tells us the number of ways to get that sum. For example, there is only one way to get a sum of 3 (draw 1, 1, and 1), but there are five ways to get a sum of 5 (draw 1, 1, 2; 1, 2, 1; 2, 1, 1; 1, 3, 1; and 3, 1, 1).

Now, we want to find the probability that the sum of the three recorded numbers is less than s. We can do this by finding the sum of the coefficients of the terms with exponents less than or equal to s

P(sum < s) = [coefficient of x^0 + coefficient of x^1 + ... + coefficient of x^(s-1)] / 27

For example, if we want to find the probability that the sum is less than or equal to 6, we need to find the sum of the coefficients of x^0 through x^5:

P(sum ≤ 6) = (1/27) + (1/9) + (5/27) + (5/18) + (5/27) + (1/9) = 19/27

Learn more about probability here

brainly.com/question/11234923

#SPJ4

To find the probability that the diameter of a selected ball bearing is greater than 127 millimeters, we can use the normal distribution.

Given that the diameter of ball bearings is normally distributed with a mean of 133 millimeters and a variance of 16, we can calculate the probability using the standard normal distribution table or a statistical calculator.

Since the diameter of ball bearings is normally distributed, we can standardize the value 127 using the formula z = (x - μ) / σ, where x is the given value, μ is the mean, and σ is the standard deviation. In this case, the standard deviation is the square root of the variance, which is 4.

Plugging in the values, we get z = (127 - 133) / 4 = -1.5. Now, we can find the probability using the standard normal distribution table or a statistical calculator. The probability of the diameter being greater than 127 millimeters is equal to 1 minus the cumulative probability up to -1.5.

By looking up the cumulative probability for -1.5 in the standard normal distribution table or using a calculator, we find that the cumulative probability is approximately 0.0668. Therefore, the probability that the diameter of a selected ball bearing is greater than 127 millimeters is approximately 0.0668 or 6.68% (rounded to four decimal places).

To learn more about diameter click here:

brainly.com/question/31445584

#SPJ11

Percent counts the number of a quantity compared to another quantity's 100 amount. The amount each person would pay is given by: Option D: $9. 75

Suppose the value of which a thing is expressed in percentage is "a'

Suppose the percent that considered thing is of "a" is b%

Then since percent shows per 100 (since cent means 100), thus we will first divide the whole part in 100 parts and then we multiply it with b so that we collect b items per 100 items(that is exactly what b per cent means).

Thus, that thing in number is

\(\dfrac{a}{100} \times b\)

For the given case,

Bill for lunch = $32.50

Tip  = 20% of bill = \(\dfrac{32.50}{100} \times 20 = \dfrac{32.50}{5} = 6.50\) (in dollars)

Total amount = Bill + Tip = $39

This amount has to be divided in 4 equal part.

Thus, each part of those 4 parts would be \(\dfrac{39}{4} = 9.75\) (in dollars).

Thus, the amount each person would pay is given by: Option D: $9. 75

Learn more about percentage here:

https://brainly.com/question/11549320

Answer:

I think option D is the correct answer

Answer:

x=34

Step-by-step explanation:

x+(x+12)+100=180

2x+12=80

2x=68

x=34

USE SUPPLEMENTARY!! STRAIGHT LINE= 180 degrees! :))

Answer:

\( \boxed{x \degree = 34\degree} \)

Step-by-step explanation:

\( = > (x + 12) \degree + 100 \degree + x \degree = 180 \\ \\ = > x \degree + 12 \degree + 100 \degree + x \degree = 180 \degree \\ \\ = > 2x \degree + 112 \degree = 180 \degree \\ \\ = > 2x \degree = 180 \degree - 112 \degree \\ \\ = > 2x \degree = 68 \degree \\ \\ = > x \degree = \frac{68}{2} \degree \\ \\ = > x \degree = 34\degree\)

These standardization methods are crucial in chromatography to ensure accurate quantification and comparability of results.

In chromatography, standardization methods are used to ensure accurate and reliable results by establishing reference points or calibration standards. Here are three common methods of standardization in chromatography: External Standardization: In this method, a set of known standard samples with known concentrations or properties is prepared separately from the sample being analyzed. These standards are then analyzed using the same chromatographic conditions as the sample. By comparing the response of the sample to that of the standards, the concentration or properties of the sample can be determined. Internal Standardization: This method involves the addition of a known compound (internal standard) to both the standard solutions and the sample. The internal standard should ideally have similar properties to the analyte of interest but be different enough to be easily distinguished. The response of the internal standard is used as a reference to correct for variations in sample preparation, injection volume, and instrumental response. Internal standardization helps improve the accuracy and precision of the analysis. Standard Addition: This method is useful when the matrix of the sample interferes with the analysis or when the analyte concentration is unknown. It involves adding known amounts of the analyte of interest to different aliquots of the sample. The response of the analyte is then measured, and the concentration is determined by comparing the response with that of the standards. The difference in response between the sample and the standards allows for the determination of the analyte concentration in the original sample.

Learn more about chromatography here:

https://brainly.com/question/31309579

#SPJ11

Answer:60

Step-by-step explanation:20x6=120 120/2=60

Answer:

200 cubic centimetres

Step-by-step explanation:

Length = \(20 \: cm\)

Width = \(6 \: cm\)

Height = \(5 \: cm\)

Volume = \( \frac{1}{3} \times w \times l \times h\)

\( = \frac{1}{3} \times 20 \times 6 \times 5\)

\( = \frac{20}{3} \times 6 \times 5\)

\( = \frac{20}{3} \times (3(2)) \times 5\)

\( = 20 \times 2 \times 5\)

\( = 40 \times 5\)

\( = 200 \: {cm}^{2} \)

a)  Every point in the output of g lies on the hyperbola x² - y² = 1.

b)  This is not possible since the range of g is [1,∞) and hence there is no t for which g(t) = 2, 1. Therefore, the point (2, 1) is not in the output of g.

(a) Let us substitute x = cosh(u) and y = sinh(u) into the equation x² - y² = 1, then we get:

cosh²(u) - sinh²(u) = 1

Using the identity cosh²(u) - sinh²(u) = 1, we get:

g(t) = cosh(t) · cosh(t) - sinh(t) · sinh(t) = cosh(2t) - sinh²(t) = 1

Therefore, every point in the output of g lies on the hyperbola x² - y² = 1.

(b) No, not all points in the hyperbola {(x,y) € R² : x² - y² = 1} are in the output of g. For example, consider the point (2, 1) on the hyperbola. Then we would need to find some value t such that g(t) = 2, 1. However, this is not possible since the range of g is [1,∞) and hence there is no t for which g(t) = 2, 1. Therefore, the point (2, 1) is not in the output of g.

Learn more about output here:

https://brainly.com/question/13736104

#SPJ11

Answer:

If im not mistaking its b

Step-by-step explanation:

you gotta divide the nubers inside the box thing  with then numbers outside it then multiply

Answer:

X =20

X+24=2(x+22)

X+24=2x+44

X=44-24

X=20