Determine whether aqueous solutions of the following salts are acidic, basic, or neutral: (a) FeCl3 (b) K2CO3 (c) NH4Br (d) KClO4

The empirical formula of the compound is C₂H₁₆S₂N₃O.

The moles of each element is as follows::

For CO₂:

Carbon (C) has a molar mass of 12.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of C in CO₂ = 2.08 g / 12.01 g/mol = 0.173 moles

Moles of O in CO₂ = 2.08 g / 16.00 g/mol = 0.130 moles

For H₂O:

Hydrogen (H) has a molar mass of 1.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of H in H₂O = 1.28 g / 1.01 g/mol = 1.27 moles

Moles of O in H₂O = 1.28 g / 16.00 g/mol = 0.080 moles

For SO₃:

Sulfur (S) has a molar mass of 32.06 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of S in SO₃ = 4.77 g / 32.06 g/mol = 0.149 moles

Moles of O in SO₃ = 4.77 g / 16.00 g/mol = 0.298 moles

For HNO₃:

Hydrogen (H) has a molar mass of 1.01 g/mol.

Nitrogen (N) has a molar mass of 14.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of H in HNO₃ = 3.48 g / 1.01 g/mol = 3.45 moles

Moles of N in HNO₃ = 3.48 g / 14.01 g/mol = 0.248 moles

Moles of O in HNO₃ = 3.48 g / 16.00 g/mol = 0.217 moles

The simplest whole-number ratio of the elements will be:

Carbon: 0.173 moles / 0.080 moles ≈ 2.16

Hydrogen: 1.27 moles / 0.080 moles ≈ 15.88

Sulfur: 0.149 moles / 0.080 moles ≈ 1.86

Nitrogen: 0.248 moles / 0.080 moles ≈ 3.10

Oxygen: 0.080 moles / 0.080 moles = 1

Therefore, the empirical formula is C₂H₁₆S₂N₃O.

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Answer:

Manganese(iv)Nitrate and Copper(ii)Chloride

ANSWER: From experience and observation, the pathogen that responds more faster to treatments are PARASITES.

This is because, our body are already used to parasite, as they feed and mostly live inside our body. Parasites becomes harmful to our body, when it is allowed to be much in the body, thereby weakening the immune system of the body. Intake of vaccination reduces the number of parasites in the body, which gives the immune system the chance of recovering and protecting the body.

Parasite does not replicate more faster like viruses and other pathogens. These makes it more easier for treatment to work more faster. They are also easily killed by taking the proper treatment, and the rate of their replications are very slow when compared to the rate of their death when vaccinated.

Some example disease caused by parasites are:

1) Giardiasis

2) Trichomoniasis

3) Malaria

4) Toxoplasmosis

5) Intestinal worms

6) Pubic lice

All this disease above responds very fast to medical treatment, unless when they is complications, which are mostly when the parasite has been allowed to cause more harm and replicate much in the body, without any treatment. This is why doctors advice patients that lives at the tropical regions to periodically vaccinate themselves on parasitic infections.

The Arrhenius equation relates the rate constant of a reaction to the activation energy, the temperature, and a constant known as the pre-exponential factor or frequency factor. The equation is given by:

k = A * exp(-Ea/RT)

where:

k = rate constant

A = pre-exponential factor or frequency factor

Ea = activation energy (in Joules/mol)

R = gas constant (8.314 J/mol-K)

T = temperature (in Kelvin)

We are given that the rate constant at 89.0°C (362.15 K) is 1.9 × 10^7 M^-1s^-1. We want to find the rate constant at 121.0°C (394.15 K).

First, we need to calculate the pre-exponential factor, A. We can do this by rearranging the Arrhenius equation and solving for A:

A = k * exp(Ea/RT)

We can plug in the values we know:

A = (1.9 × 10^7 M^-1s^-1) * exp((5.0 kJ/mol) / (8.314 J/mol-K * 362.15 K))

A = 6.46 × 10^11 M^-1s^-1

Now we can use the Arrhenius equation to calculate the rate constant at 121.0°C:

k = A * exp(-Ea/RT)

k = (6.46 × 10^11 M^-1s^-1) * exp((5.0 kJ/mol) / (8.314 J/mol-K * 394.15 K))

k = 1.9 × 10^9 M^-1s^-1

Therefore, the rate constant at 121.0°C is approximately 1.9 × 10^9 M^-1s^-1.

Answer:

A. Quantitative data.

Explanation:

Quantitative data involves specific numbers, while qualitative verbally describes something.

The amount of precipitate produced in mg/l and kg/day is 57.2753 kg.

Precipitation is the process of changing a dissolved substance from a super-saturated solution to an insoluble solid in an aqueous solution.

Chemical feed rate :

60 mg per liter we need

60 grams per one m3

60 x 3800 grams = 228 kg per 3800 m³

Since the water flow per day is 3800 m³, alum consumption per day is 228 kg

Alkalinity: The alkalinity requirement for alum is 0.49 mole of alkalinity per one mole of alum. The precipitate formed: For one mole of alum, 2 moles of Al(OH)₃ will form.

So 621 g of alum reacts to form

2 x 78 g of Al(OH)₃ precipitate

228 x 1000g will form:

(228 x 1000 x 156)/621 = 57.2753 kg per day precipitate

Therefore, the amount of precipitate produced in mg/l and kg/day is 57.2753 kg.

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The question is incomplete. Your most probably complete question is given below:

Natural water with a flow of 3800 m3/d is to be treated with an alum dose of 60 mg/L.

Answer:

48.4%

Explanation:

Mass percent is calculated by the equation:

mass of element / total mass * 100%

Plugging in the figures of the problem: 242g / 500g * 100% = 48.4% (grams are in the numerator and denominator, so they cancel out)

The mass percent of iron in the ore sample is 48.4 %.

The percentage of an element in a compound can be described as the number of parts by mass of that element present in 100 parts by mass of that compound.

The mass percentage of an element can be evaluated in two steps: First, determine the molecular mass of the given compound by the addition of the atomic masses of the elements. Then, the percentage of the elements can be determined by dividing the total mass of the element present in that compound by the molar mass of the given compound multiplied by 100.

Given, the mass of the iron in sample = 242 g

The total mass of the iron ore sample = 500 g

The mass percentage of the iron = (242/500) × 100 = 48.4 %

Therefore, the mass percentage of the iron in the iron ore sample is equal to 48.4%.

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Explanation: The concentration of a solution helps us to determine the collision speed between particles in a molecule or compound. Knowing the concentrations of components in solutions can help determine the health of the world.

The temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

To determine the temperature of the gas in Kelvin after its volume is reduced, we can use the combined gas law, which relates the initial and final conditions of pressure, volume, and temperature for a given amount of gas.

The combined gas law equation is:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Where P₁ and P₂ are the initial and final pressures, V₁ and V₂ are the initial and final volumes, T₁ is the initial temperature in Kelvin, and T₂ is the final temperature in Kelvin.

Given that the initial volume V₁ is 3,480 mL, the initial temperature T₁ is -70.0 °C (which needs to be converted to Kelvin), and the final volume V₂ is 2,450 mL, we can substitute these values into the equation.

To convert -70.0 °C to Kelvin, we add 273.15 to it, resulting in T₁ = 203.15 K.

Now we can solve for T₂:

(T₂ * V₁) / T₁ = V₂

T₂ = (V₂ * T₁) / V₁ = (2,450 mL * 203.15 K) / 3,480 mL

Simplifying the equation, we find:

T₂ ≈ 143.27 K

Therefore, the temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

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Answer:

E

Explanation:

Not all gases are colourless and odourless at room temperature. Chlorine gas has a characteristic greenish-yellow colour at room temperature, hydrogen sulfide on the other hand has a characteristic pungent odour at room temperature

The molarity of each ion is obtained from the number of moles and volume of solution

From the question, the mass of the solution is 1.00 Kg and the density of the sample is 1.025 g/cm³.

From this, we can calculate the volume of the solution as follows;

D = M/V

V = M/D = 1 × 10^3 g/1.025 g/cm³

V = 976 cm³ or 0.976 L

Recall that number of moles = mass/molar mass

For NaCl = 26.5 g/58.5 g/mol = 0.45 moles

For  MgCl₂ = 2.40 g/95 g/mol = 0.025 moles

For MgSO₄ = 3.35 g/120 g/mol = 0.028 moles

For CaCl₂ = 1.20 g/111 g/mol = 0.011 moles

For KCl = 1.05 g/75 g/mol = 0.014 moles

For NaHCO₃ = 0.315 g/84 g/mol = 0.0038 moles

For NaBr = 0.098 g/103 g/mol = 0.00095 moles

Molarity of each solution = number of moles/volume

For NaCl = 0.45 moles/0.976 L = 0.46 M

For MgCl₂ = 0.025 moles/0.976 L = 0.026 M

For MgSO₄ = 0.028 moles/0.976 L = 0.029 M

For CaCl₂ = 0.011 moles/0.976 L = 0.011 M

For KCl =  0.014 moles/0.976 L = 0.014 M

For NaHCO₃ = 0.0038 moles/0.976 L =0.0039 M

For NaBr = 0.00095 moles/0.976 L = 0.00097 M

The molarity of Na^+ and Cl^- = 0.46 M each

The molarity of Mg^2+ = 0.013 M while the concentration of Cl^- = 0.026 M

The molarity of both Mg^2+ and SO4^2- ions are 0.029 M each

The molarity of Ca^+ is 0.0055 M while the concentration of Cl^- is 0.011 M

The molarity K^+ and Cl^- are both 0.014 M

The molarity of both Na^+ and HCO3^- are both 0.0039 M

The molarity of both Na^+ and Br^- are both 0.00097 M

The total molarity of Na^+ = 0.46 M + 0.0039 M + 0.00097 M = 0.465 M

The total molarity of Ca^+ =  0.0055 M

The total molarity of Mg = 0.013 M + 0.029 M = 0.042 M

The total molarity of K^+ = 0.014 M

The total molarity of Cl^- =  0.46 M + 0.026 M + 0.011 M + 0.014 M = 0.511 M

The total molarity of SO4^- = 0.029 M

The total molarity of HCO3^- = 0.0039 M

The total molarity of Br^- = 0.00097 M

The total molarity of alkali metal ions = 0.465 M + 0.014 M  = 0.479 M

The total molarity of alkaline earth metal ions = 0.0055 M + 0.042 M = 0.0475 M

The total molarity of anions = 0.511 M + 0.029 M + 0.0039 M + 0.00097 M = 0.545 M

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The direction of heat transfer between two samples of carbon depends on their temperature difference, and not solely on their average kinetic energy. While the average kinetic energy of a substance is related to its temperature, it is not the determining factor for the direction of heat transfer.

When two samples of carbon come into contact, a heat transfer will occur between sample A and sample B. The direction of heat transfer is dependent on the temperature difference between the samples. Heat transfer always flows from a hotter object to a cooler object, so if sample A is hotter than sample B, heat will flow from A to B. If sample B is hotter than sample A, heat will flow from B to A.
The average kinetic energy of the molecules in a substance is related to its temperature. The higher the average kinetic energy, the higher the temperature of the substance. However, the average kinetic energy does not determine the direction of heat transfer.
It is possible for a substance with a lower average kinetic energy (and therefore a lower temperature) to transfer heat to a substance with a higher average kinetic energy (and therefore a higher temperature). This can occur if the substance with the lower temperature has a greater heat capacity, which means it can absorb more heat without a significant increase in temperature.

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Answer:

endothermic

Explanation:

Chemical reactions that absorb (or use) energy overall are called endothermic. In endothermic reactions, more energy is absorbed when the bonds in the reactants are broken than is released when new bonds are formed in the products

Brainliest me please

Answer: Photosynthesis

Explanation:

Answer:2

Explanationb

Answer:

Leaches aluminum from the soil.

Explanation:

Answer:

The temperature of the physics book increases as the chemistry book slides across it.

Explanation:

from plato

The temperature of the physics book increasing as the chemistry book slides across it is the difference when motion is faster.

This is defined as the degree of hotness  or coldness of a body and it increases when there is more friction.

When motion is faster , there is an increase in friction and increase in thermal(heat) energy which leads to increase in temperature.

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Copper oxide, CuO has a relative formula mass of 80.

What is the Relative Formula mass?

This refers to the total of the relative atomic masses of the atoms in the numbers seen in the formula.

This refers to the relative mass of atoms when compared with the carbon-12 atoms Ar. Relative formula mass is a measure of relative mass, thus it has no unit.

O=16 and Cu=64

copper oxide, CuO=  (1 * 64) + (1 * 16)

                              = 64      +  16

                               =80

Where,

1 = The subscript value of the element present.

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Answer:

6KCl(aq) +  Mg3(PO4)2(s)  ...  balanced equation

Explanation:

Answer:

Tetrahedral

Explanation:

The molecular geometry of SiCl₄ is a tetrahedral shape. According to the VESPR molecular theory, the compound has a shape of a tetrahedron.

The type of movement that occurs in the plate movement listed above include the following:

These are gigantic pieces of the Earth's crust and uppermost mantle and are made up of oceanic crust and continental crust.

A convergent boundary as the name implies occurs when lithospheric plates are moving towards one another.

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The equation C2H4(g) + H2(g) + C2H6(g) → Caco3(s) + Cao(s) + CO2(g) shows an increase in entropy due to the formation of a gas as a product. Option A

In this equation, the reactants on the left-hand side consist of gases (C2H4 and H2), while the products on the right-hand side include a solid (Caco3) and a gas (CO2).

When a reaction involves a change from gaseous to solid or liquid states, there is typically a decrease in entropy because the particles become more ordered and constrained in the solid or liquid phase.

Conversely, when a reaction involves the formation of gases, there is generally an increase in entropy because gases have higher degrees of molecular motion and greater freedom of movement compared to solids or liquids.

In the given equation, the reactants include three gaseous compounds (C2H4, H2, and C2H6), and one of the products is a gas (CO2). Therefore, the overall entropy of the system increases during this reaction.

The equation Fe(s) + S(s) → FeS(s) does not show an increase in entropy. Both the reactants (Fe and S) and the product (FeS) are solids. Since solids have lower entropy compared to gases or liquids, the entropy of the system does not increase in this reaction. Option A

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Balance the following chemical equations:

1. N2 + 3 H2 → 2 NH3

Ex: Synthesis reaction

2. 2 KClO3 → 2 KCl + 3 O2

Single Replacement reaction

3. 2 NaF + ZnCl2 → ZnF2 + 2 NaCl

Decomposition reaction

4. 2 AlBr3 + 3 Ca(OH)2 → Al2(OH)6 + 6 CaBr2

Double Replacement reaction

5. 2 H2 + O2 → 2 H2O

Combustion reaction

6. 2 AgNO3 + MgCl2 → 2 AgCl + Mg(NO3)2

Synthesis reaction

7. 2 Al + 6 HCl → 2 AlCl3 + 3 H2

Decomposition reaction

8. C3H8 + 5 O2 → 3 CO2 + 4 H2O

Combustion reaction

9. 2 FeCl3 + 6 NaOH → Fe2O3 + 6 NaCl + 3 H2O

Double Replacement reaction

10. 4 P + 5 O2 → 2 P2O5

Synthesis reaction

11. 2 Na + 2 H2O → 2 NaOH + H2

Single Replacement reaction

12. 2 Ag2O → 4 Ag + O2

Decomposition reaction

13. C6H12O6 + 6 O2 → 6 CO2 + 6 H2O

Combustion reaction

14. 2 KBr + MgCl2 → 2 KCl + MgBr2

Double Replacement reaction

15. 2 HNO3 + Ba(OH)2 → Ba(NO3)2 + 2 H2O

Double Replacement reaction

16. C5H12 + 8 O2 → 5 CO2 + 6 H2O

Combustion reaction

17. 4 Al + 3 O2 → 2 Al2O3

Synthesis reaction

18. Fe2O3 + 2 Al → 2 Fe + Al2O3

Single Replacement reaction

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Explanation:

hope these help you answer

Answer:

Answer:

The cause of death is the specific injury or disease that leads to death. The manner of death is the determination of how the injury or disease leads to death.

Explanation:

.

Answer:

A. air pressure,this is answer.

The oxidation number of the atoms in the given compounds are :

K₂O: K = + 1; O = -2;

PO₃⁻³: P = +3; O = -2

NH₃: N = -3; H = +1

Cu(NO₃)₂: Cu = +2; N = +5; O = -2

NO₃⁻¹: N = +5;  O = -2

CO₂: C = +4; O = -2

KClO₃: K = +1; Cl = + 5; O = -2

O₂: O = 0

Ca(ClO₄)₂: Ca = +2; Cl = +7; O = -2

The number of electrons an atom or ion has either gained or lost in comparison to the neutral atom is known as the oxidation number or state of the atom or ion.

Group I, 2, and 3 electropositive metal atoms lose a certain number of electrons, and their positive oxidation numbers remain constant.

The oxidation number of the atoms in the given compounds are as follows:

K₂0

K = + 1

O = -2

Sum is (+1 * 2) + (-2) = 0

PO₃⁻³

P = + 3

O = -2

Sum is (+3) + (-2 * 3) = -3

NH₃

N = -3

H = +1

Sum is (-3) + (+1 * 3) = 0

Cu(NO₃)₂

Cu = +2

N = +5

O = -2

Sum is (+2) + (+5 * 2) + (-2 * 6) = 0

NO₃⁻¹

N = +5

O = -2

Sum is (+5) + (-2 * 3) = -1

CO₂

C = +4

O = -2

Sum is (+4) + (-2 * 2) = 0

KClO₃

K = +1

Cl = + 5

O = -2

Sum is (+1) + (5) + (-2 * 3) = 0

O₂

O = 0

Sum is (0 * 2) = 0

Ca(ClO₄)₂

Ca = +2

Cl = +7

O = -2

Sum is (+2) + (+7 * 2) + (-2 * 8) = 0

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The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.

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Based on the description of the potential energy diagram provided, the diagram made by the student appears to be correct.

The potential energy diagram represents the energy changes that occur during a chemical reaction. In an endothermic reaction, the products have higher potential energy than the reactants, meaning energy is absorbed from the surroundings.

The curve line on the graph indicates the energy changes throughout the reaction pathway. It starts at a higher level, representing the initial potential energy of the reactants. As the reaction progresses, the potential energy decreases, indicating the formation of products with lower potential energy.

The broken horizontal line from point X on the y-axis to the point where the curve begins represents the activation energy (Ea) of the reaction. Activation energy is the energy barrier that must be overcome for the reactants to convert into products.

Point X on the y-axis indicates the potential energy of the reactants at the start of the reaction, and the broken line shows the energy required to initiate the reaction.

The broken horizontal line from point Y on the y-axis to the point where the curve ends represents the potential energy of the products. Point Y represents the potential energy of the products at the end of the reaction.

Overall, the student's diagram correctly represents an endothermic reaction, showing the potential energy changes, the activation energy, and the final potential energy of the products. The curve line starts at a higher level (representing the higher potential energy of the reactants) and ends at a slightly lower level (representing the lower potential energy of the products).

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the pressure required for 1.35 g of oxygen to dissolve in 1.5 L of water is 3.56 atm.

The first step in solving this problem is to identify the relevant equation.

Henry's law is the formula that relates the pressure of a gas above a liquid to the concentration of the gas that dissolves in the liquid.

In mathematical terms, Henry's law can be expressed as follows:P = kH * Cwhere P is the pressure of the gas, kH is Henry's law constant, and C is the concentration of the gas in the liquid.

To solve the problem, we need to first determine the value of kH using the given data.

kH can be calculated using the following formula:kH = P / CSubstituting the values given in the problem into this formula, we get:kH = 1.65 atm / (0.654 g / 1.5 L) = 3.97 atm/(g/L).

Now that we have the value of kH, we can use Henry's law to calculate the pressure required for 1.35 g of oxygen to dissolve in 1.5 L of water.

To do this, we simply rearrange the formula to solve for P:P = kH * CSubstituting the values of kH and C into this formula, we get:P = 3.97 atm/(g/L) * (1.35 g / 1.5 L) = 3.56 atm

Therefore, the pressure required for 1.35 g of oxygen to dissolve in 1.5 L of water is 3.56 atm.

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