Determine the exact values of the six trigonometric ratios for the given angle. Reduce fractions and simplify radicals (Hint: the hypotenuse length isn't a perfect square, but the radical does simplif

2.5 seconds  long will it take the boat to cross the river and 2m  far downstream does it land from its starting point.

Velocity is the pace and direction of an item's motion, whereas speed is really the time rate at which a object is travelling somewhere along route. In other words, velocity is a vector, whereas speed is a numerical number.

We may simply utilize the boat's velocity along the vector perpendicular to the river in this section of the issue, which is

\($v_x=8.0 \mathrm{~m} / \mathrm{s}$\)

The distance d between the river's two sides is 20.0 meters.

Consequently, the duration of the river crossing is

\($t=\frac{d}{v_x}=\frac{20.0 \mathrm{~m}}{8.0 \mathrm{~m} / \mathrm{s}}=2.5\mathrm{~s}$\)

We must take into account the boat's motion along the direction of the stream, which happens at a velocity of to determine how far the boat will land downstream.

\($v_y=5.0 \mathrm{~m} / \mathrm{s}$\)

According to a prior calculation, it takes 2.5 seconds to traverse the river.

Consequently, the boat will land a distance of

\($d=v_y t=(5.0 \mathrm{~m} / \mathrm{s})(2.5 \mathrm{~s})=2 \mathrm{~m}$\)

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The angle of attack is approximately 4 degrees.

A more detailed explanation of the answer.

To find the angle of attack for a NACA 4415 airfoil with a 2m chord in an airstream with a velocity of 50 m/s and a lift per unit span of 1,595 N, follow these steps:

1. Calculate the dynamic pressure (q):
q = 0.5 * ρ * V^2
where ρ is the air density at standard sea-level conditions (1.225 kg/m³) and V is the airstream velocity (50 m/s).

q = 0.5 * 1.225 * (50)^2 = 1,531.25 N/m²

2. Calculate the lift coefficient (Cl):
Lift per unit span (L') = Cl * q * chord (c)
1,595 N = Cl * 1,531.25 N/m² * 2m

Now, solve for Cl:
Cl = 1,595 / (1,531.25 * 2) = 0.5208

3. Refer to a NACA 4415 lift coefficient vs angle of attack graph or data table to determine the angle of attack corresponding to the calculated Cl value. Since the Cl value is 0.5208, the angle of attack is approximately 4 degrees.

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Using a saltwater aquarium to model the ocean has limitations, such as showing only a small part of the actual ocean and being unable to replicate the vastness and complexity of the ocean ecosystem.

One limitation of using a saltwater aquarium to model the ocean is that it can only show a small part of the actual ocean. Since an aquarium is confined and limited in size, it cannot realistically replicate the vastness and complexity of the ocean ecosystem. For example, it may not have the space to accommodate large marine animals like whales or the turbulent currents that exist in the open ocean. Therefore, it is important to recognize that while a saltwater aquarium can provide some insights into the ocean, it cannot fully capture the dynamic nature and diverse interactions found within the entire ocean ecosystem.

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The steel tank can be able to take in a greater air pressure than the balloon.

We have to know that air is a compressible fluid. We must also know that the balloon is an elastic material. The fact is that as you add more air to the balloon the material of the elastic would continue to be stretched.

On the other hand, the steel tank is not elastic but can be able to withstand a greater pressure as you add more air to the tank. The balloon would burst but the tank would not burst.

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Without additional information, it is not possible to rank the stars according to size based solely on their apparent magnitude.

The apparent magnitude of a star refers to its brightness as observed from Earth. However, the apparent magnitude does not directly provide information about the size or physical dimensions of the star.

Therefore, without additional information about the stars' sizes or other properties, it is not possible to rank them according to size from largest to smallest based solely on their apparent magnitude.

Without additional information regarding the stars' sizes or physical properties, it is not possible to rank them according to size from largest to smallest solely based on their apparent magnitude.

Apparent magnitude is a measure of how bright a star appears from Earth, but it does not directly indicate the star's size. The size of a star is determined by its radius or diameter, which is not related to its apparent magnitude.

To determine the size of stars, additional measurements such as their luminosity, distance, or spectral type would be needed.

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Solutions to the following equations are as follows:

a. 7700−9100  is bigger.

b. The magnitude of 7.7−9.1 is 1.4.

c. The driver use 0.0357 gallons per mile.

d. 72053/1000 written as a decimal 7.2053.

e. 7.2053 can be written as  72053/1000.

f. 72053 as a percent is 7205300%.

g. 3.21 as a percent is 321%.

h. 06\% as a decimal is 0.0006.

i. 6% of .01 million is 600.

j.  6% of 5000 is 300.

k. 0.64 is within 25% of 0.72053.

Exercise 1:

Which is bigger, 7700−9100 or −(7700−9100)?

Given,7700−9100 = -1400-(7700−9100) = 1400∴ 1400 > -1400.

Hence 1400 is greater than -1400.

Exercise 2:

What is the magnitude of 7.7−9.1?

Magnitude of 7.7−9.1 = |7.7−9.1| = |-1.4| = 1.4.

Exercise 3:

In the example of the previous section, a driver uses 15 gallons of gas to drive 420 miles.

Gallons per mile = 15/420 = 0.0357.

Exercise 4:

What is 72053/1000, written as a decimal?

72053/1000 = 72.053.

Exercise 5:

What is 7.2053 written as a fraction with whole numbers as numerator and denominator?

7.2053 = 72053/10000.

Now, we can simplify this fraction.72053/10000 = 36027/5000 (Dividing both the numerator and denominator by 2)

Exercise 6:

Write 72053 as a percent.

72053 = 72053/1 * 100% = 7205300%.

Exercise 7:

Write 3.21 as a percent.

3.21 = 3.21/1 * 100% = 321%.

Exercise 8:

What is 6% of 100? What is 6% of 100 million?

6% of 100 = 6/100 * 100 = 6.6% of 100 million = 6/100 * 100000000 = 6000000.

Exercise 9:

Write .06\% as a decimal.

.06\% = 0.0006.

Exercise 10:

What is 6% of .01? What is 6% of .01 million?

6% of 0.01 = 6/100 * 0.01 = 0.00066% of 0.01 million = 6/100 * 0.01 * 1000000 = 600.

Exercise 11:

What is 6% of 5000?

6% of 5000 = 6/100 * 5000 = 300.

Exercise 12:

Is .64 within 25% of .72053?

We can find the limits by adding and subtracting 25% of 0.72053 from 0.72053.

Lower limit = 0.72053 - 0.1801325 = 0.5404

Upper limit = 0.72053 + 0.1801325 = 0.9006

Now, 0.64 lies within the above limits. Hence, 0.64 is within 25% of 0.72053.

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Answer: 78m/s  =A

u=0 ,a=3m/sec^2 ,t=25sec

v=u+at

=0+25×3

=75m/s

after 1sec

v=u+at+75

=0+3×1+75

=78m/s

Explanation:

u=0 ,a=3m/sec^2 ,t=25sec

v=u+at

=0+25×3

=75m/s

after 1sec

v=u+at+75

=0+3×1+75

=78m/s

Reduce the volume: Reducing the volume is one of the simplest ways to lessen the sound intensity coming a speaker. As you move farther away from the source of the sound, the intensity of the sound also diminishes.

Nonetheless, regardless of the location, a rock concert can be quite loud. Decibel levels during rock concerts often range from 90 to 120 dB. This decibel level is alarming since it could endanger your ability to hear.

The intensity of the sound is proportional to the square of the distance from the source of the sound wave. The strength of a sound wave depends on whether it travels through a two-dimensional or three-dimensional medium to carry its energy.

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\(\\ \bull\tt\longmapsto Volume=LBH\)

\(\\ \bull\tt\longmapsto Volume=8(4)(3)\)

\(\\ \bull\tt\longmapsto Volume=96m^3\)

Answer:

Formular:

\({ \boxed{ \bf{v = length \times width \times height}}}\)

» length, l = 8m

» width, w = 4m

» height, h = 300cm = 3 m

\({ \tt{• Therefore :→}} \: { \sf{ volume = (8 \times 4 \times 3)}} \\ → { \sf{ \underline{ \: \: volume = 96 \: {m}^{3} \: \: }}}\)

The energy emitted per minute by the blackbody at the given area is 170,724.8 J/min.

The energy emitted per minute at the given area is calculated as follows;

P = σAT⁴

P = (5.67 x 10⁻⁸) x (2) (398)⁴

P = 2845.41 W = 2845.41 J/s

Convert energy emitted per second to per minutes

P = 2845.41 J/s x (60 s / min) = 170,724.8 J/min

Thus, the energy emitted per minute by the blackbody at the given area is 170,724.8 J/min.

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The one and only way to ensure that power off in a system, circuit, or piece of equipment is to measure the voltage with a known working meter.

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Answer:

There are a few possible reasons why the plot of absorbance vs the amount of nitrite was not linear.

The concentration of the nitrite solutions was not accurately measured. If the concentrations of the solutions were not accurately measured, then the plot of absorbance vs concentration would not be linear.

The absorbance readings were not accurate. If the absorbance readings were not accurate, then the plot of absorbance vs concentration would not be linear.

The reaction between the nitrite and the reagent was not stoichiometric. If the reaction between the nitrite and the reagent was not stoichiometric, then the plot of absorbance vs concentration would not be linear.

The instrument was not calibrated properly. If the instrument was not calibrated properly, then the plot of absorbance vs concentration would not be linear.

It is important to troubleshoot the problem to determine the cause of the non-linearity. Once the cause is known, the problem can be corrected and a linear plot of absorbance vs concentration can be obtained.

Explanation:

Answer:

4.d 5.c

Explanation:

Answer:

Explanation:

static friction = 0.34

Acting force = 50N

mass = 12 kg

g = 9.81

a = acceleration after box moves against friction.

Acting force - Frictional Force = m * a

Frictional Force = mu*Normal

Normal = m * g

Normal = 12 * 9.81 = 117.72

Frictional Force = Normal * 0.34

Frictional Force = 117.72 * 0,34

Frictional Force = 40.02

50 - 40.02 = 12 *a

9.98 = 12*a

a = 0.8317 m/s^2

Answer:

Radio waves are used for wireless transmission of sound messages, or information, for communication, as well as for maritime and aircraft navigation. The information is imposed on the electromagnetic carrier wave as amplitude modulation (AM) or as frequency modulation (FM) or in digital form (pulse modulation).

Explanation:

It is true that the accuracy of parallax measurements improves as the distance of the object from the observer increases.

As the distance between the object and the observer increases, the angle of parallax also increases. This means that there is a larger difference in the apparent position of the object when viewed from different positions on Earth's orbit. Therefore, the accuracy of parallax measurements improves as the distance of the object from the observer increases.

The accuracy of parallax measurements actually decreases as the distance of the object from the observer increases. Parallax is a technique used to measure the distance of nearby objects in space by observing their apparent shift in position as seen from different viewpoints (such as Earth at different times of the year). As the distance to the object increases, the apparent shift in position becomes smaller and more difficult to measure accurately.

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The star is bigger than our sun. The correct option is 1.

The flow chart of the life cycle of a star indicates that the star starts as a nebula, which is a cloud of gas and dust. The nebula can collapse due to gravitational forces and form a protostar. The protostar can then continue to contract and heat up until it reaches a temperature and density at which nuclear fusion can occur, leading to the star entering the main sequence phase.

The size of a star is determined by its mass, and the more massive a star is, the bigger it will be. Based on this information, we can infer that if a star follows the life cycle shown in the flow chart, starting from a nebula and eventually reaching the main sequence, it must be at least as massive as our sun or even more massive, since only stars with sufficient mass can become main sequence stars.

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Answer:

22

Explanation:

Answer:

20N

Explanation:

10kg=mass 2m/s²= Acceleration

Force=?

the equation is;

Force(N)=Mass(kg) × Acceleration(m/s²)

10×2=20

Answer:

HEAR WE CAN SAY THAT VEGITERIAN INVOKE THE SECOND LOW OF THERMODYNAMICS

Explanation:

According to the second law, entropy always rises in closed systems. Let's use the growing of a leaf as an example. The sun emits low-entropy radiation that the leaf absorbs and then emits higher-entropy radiation into its surroundings. The leaf is encouraged to reduce its own entropy in order to sustain the overall process's required increase in entropy as a result of this significant entropy increase. Using this illustration, we can draw the conclusion that living things adhere to the second law of thermodynamics.

second law of thermodynamics

A process that exchanges or transfers heat can result in a certain amount of useful work, according to the second law of thermodynamics.

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The device that converts chemical energy into electrical energy is a battery.

On the other hand, the resistor is a passive element that is mainly used to limit the current in a circuit.

A resistor doesn't convert chemical energy into electrical energy.

Therefore, we can conclude that the given statement is false

Aristarchus of Samos was the Greek scientist who made the claim that the sun is at the center of the solar system and that the earth revolves around it.

Aristarchus was undoubtedly both a mathematician and an astronomer, but he is best known for being the person who initially suggest that the universe is centered around the sun. He is renowned for his groundbreaking work on calculating the sizes and distances of the sun and moon.

While Pythagoreanism made the idea of a moving Earth at least as early as the fourth century BC, Aristarchus of Samos created the first fully developed heliocentric model in the third century BC.

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When the light source is changed from red light to violet light in an interference pattern formed by passing light through a pair of narrow slits, the bright spots in the interference pattern will be closer together.

Interference patterns occur when light waves from different sources or parts of the same source interfere with each other constructively or destructively. In the case of a pair of narrow slits, the light passing through the slits diffracts and creates a pattern of bright and dark spots on a screen.

The spacing between the bright spots in the interference pattern is determined by the wavelength of the light used. The wavelength of light is inversely proportional to its color, with violet light having a shorter wavelength than red light.

When the light source is changed from red light to violet light, the wavelength of the light is decreased. As a result, the bright spots in the interference pattern will be closer together.

This is because the shorter wavelength of the violet light causes the wavefronts to compress, resulting in a smaller distance between adjacent bright spots.

In summary, changing the light source from red to violet light in an interference pattern formed by passing light through a pair of narrow slits will cause the bright spots in the interference pattern to be closer together.

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The average electric power consumption of a machine is 29.4 watt.

Kinetic Energy is defined as the object which has because of its motion.

It is represented as

K = 1/2 mv²

where,

K = Kinetic Energy

m = mass

V = Velocity

Now by putting the value we get the kinetic energy as

K = 1/2 mv²

= 0.5 × 0.3 × (7)²

= 7.35 J

It is given in the question that the machine throws 2 snowballs per second.

Poutput = 2 × 7.35

= 14.7 J/s

= 14.7 watt

According to the question the efficiency is given as 50%. So average electric power is

Avg. Electric power = 2 × 14.7

= 29.4 watt

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The system will complete one full oscillation in 0.63 seconds.

Simple Harmonic Motion, also known as SHM, is a motion in which the restoring force is inversely correlated with the body's deviation from its mean position. The mean position is the constant direction of this restorative force.

With two extreme points, it is a particular kind of periodic motion. Simple harmonic motion, also known as oscillatory motion, is an oscillatory motion in which the acceleration and force of a particle are directly proportional to the distance of the particle from the mean position at each point. It is an instance of oscillatory motion specifically.

The expression for period of a body in simple harmonic motion is

T = 2 × pi√m/k

The period is where T is.

K is the spring constant, and m is the body's mass.

given data

m = 7.5kg

e = 15cm

k = 750j/m2

Using our data to change the expression

T = 2 × 3.142 √ 7.5/750

T = 6.284 × 0.1

T = 0.63sec

The complete question is:

A 7.5 kg block is attached to a horizontally mounted spring with a spring constant of 750 J/m2 . The block is released from rest with the spring extended by 15 cm from its normal length. The block then oscillates back and forth along a horizontal and frictionless surface. How long will it take this system to complete one full oscillation?

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The weight of the book is being pulled down by gravity, and it is being propelled up by friction from the table.

Unbalanced force, however, is not entirely clear. Unbalanced force: what is it?

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Answer:

Capacitor

Explanation:

Capacitor ; A capacitor is a passive two-terminal electrical component that can store energy in an electric field electrostatically. It works as a small rechargeable battery that stores electricity. However, unlike a battery, it can charge and discharge in the split of a second. Capacitors are widely used to build different types of electronic circuits.

Answer: No, the block will not be lifted.

Explanation: The block weighs 147 N (15 kg multiplied by 9.8 m/s2/2). The force vector's y-component has the formula 500 N * cos(50 degrees) = 250 N. The block won't be lifted because the force vector's y-component is less than the block's weight.

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The wavelengths of the signals of AM radio ranging between 550 kHz to 1600 kHz are 5.5 × 102 m to 1.9 × 102 m.

Given, AM radio signals have frequencies between 550 kHz and 1600 kHz and travel with a speed of 3.0 x 108 m/s.

The formula relating the speed of light to wavelength and frequency is given by: c = fλ

Where, c = speed of light = 3.0 x 108 m/sλ = wavelength

f = frequency

Using the formula, we get;

The lower frequency of AM radio signals is 550 kHz and the upper frequency is 1600 kHz.

Lower frequency λ1 = c/f1 = 3.0 x 108 m/s / 550 x 103 Hz = 545.4545454... m = 545.45 m (2 decimal places)

Upper frequency λ2 = c/f2 = 3.0 x 108 m/s / 1600 x 103 Hz = 187.5 m

As we know that the wavelengths for lower frequency and upper frequency are respectively 545.45m and 187.5m, but we need to express our answer using two significant figures.

Therefore, the answer will be,

Lower frequency λ1 = 5.5 x 102 m

Upper frequency λ2 = 1.9 x 102 m

Therefore, the wavelengths of the signals of AM radio ranging between 550 kHz to 1600 kHz are 5.5 × 102 m to 1.9 × 102 m.

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If heavier cars were used, the barricade would need to be designed to absorb more kinetic energy. In order to design a barricade that can absorb more kinetic energy from heavier cars, the design of the barricade must be modified. The key to designing a barricade that can absorb more kinetic energy is to use a material that can do so.

In addition, the barricade would need to be designed in such a way that it would be able to absorb as much kinetic energy as possible. One way to do this is to make the barricade thicker and heavier. This would increase its mass, which would increase the amount of kinetic energy that it could absorb. The design of the barricade would also need to take into account the work that would be required to stop the car.

The work required to stop a car is directly proportional to the kinetic energy of the car. Therefore, in order to stop a heavier car, more work would need to be done. In order to minimize the work required to stop the car, the barricade would need to be designed in such a way that it can absorb the kinetic energy of the car with minimal work.

This could be achieved by using materials that are able to absorb large amounts of energy without breaking or deforming too much. By using such materials, the barricade would be able to absorb more energy with less work.

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