Determine the equations you would use to represent the situation.
You sold 27 tickets total. Some of the tickets were student tickets and the rest were adult tickers.
You collected $170 selling the tickets. If the student tickets cost $5 and the adult tickets cost $10.
how many student tickets did you sell?

Answer it should be 72° as the figure is a 5 fold.

360/5 = 72

Angle of rational symmetry is 72°

Must click thanks and mark brainliest

Depending on what class you're in, the answer would be different.  if you've talked about tangent lines, then you look for where you'd have the tangent line with the steepest slope.  

Answer:-14

Step-by-step explanation:

(1-√-4)(-3-√-25)

[(1*-3)-(1*√-25)-(√-4*-3)-(√-4*√-25)]

(-3)-(-5)-(6)-(10)

-14

Answer:

\(-13+i\)

Step-by-step explanation:

\((1-\sqrt{-4} )(-3-\sqrt{-25} )\)

\(\left(1-2i\right)\left(-3-5i\right)\)

\(\left(1\times \left(-3\right)-\left(-2\right)\left(-5\right)\right)+\left(1\times \left(-5\right)+\left(-2\right)\left(-3\right)\right)i\)

\(=-13+i\)

Assuming that the bacteria population doubles every 15 minutes, it will take around 70.6 minutes for the population to increase from 100 to 12,800.

If the population of bacteria doubles every 15 minutes, it means that the growth rate is exponential. The initial population is 100, and we want to find the time it takes for the population to reach 12,800.

To solve this problem, we can use the exponential growth formula:

N(t) = N0 * 2⁽ᵗ/ᵀ⁾

where:

N0 = initial population (100 bacteria)

N(t) = population at time t

t = time elapsed

T = time it takes for the population to double (15 minutes)

We want to find the time it takes for the population to reach 12,800 bacteria, so we can set N(t) to 12,800:

12,800 = 100 * 2⁽ᵗ/¹⁵⁾

Dividing both sides by 100:

128 = 2⁽ᵗ/¹⁵⁾

Taking the logarithm (base 2) of both sides:

log2(128) = t/15

t = 15 * log2(128)

Using a calculator, we can solve for t:

t ≈ 70.6 minutes

Therefore, it will take approximately 70.6 minutes for the population of bacteria to reach 12,800, if the population doubles every 15 minutes.

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The area of the region bounded by the given curves. y = 6x2 ln(x), y = 24 ln(x) is 2.85 sq.units.

In this question we need to find the area of the region bounded by the given curves. y = 6x^2 ln(x), y = 24 ln(x)

Equating both the equations of the curve,

6x^2 ln(x) = 24 ln(x)

24 ln(x) - 6x^2 ln(x) = 0

x = 1, 2

This means,  the curves intersect at x = 1 and x = 2.

So, the required area would be,

A = ∫[1 to 2] [24 ln(x) - 6x^2 ln(x)] dx

First we find the indefinite integral ∫[24 ln(x) - 6x^2 ln(x)] dx

= -6  ∫[-4 ln(x) + x^2 ln(x)] dx

= -6 ∫ln(x) (x^2 - 4) dx

= -6 ln(x) (1/3 x^3 - 4x) + 2/3 x^3 - 24x

So,  ∫[1 to 2] [24 ln(x) - 6x^2 ln(x)] dx

= [-6 ln(x) (1/3 x^3 - 4x) + 2/3 x^3 - 24x] _(x = 1 to x = 2)

= 32 ln(2) - 58/3

= 22.18 - 19.33

= 2.85 sq.units.

Therefore, the area of the region is 2.85 sq.units.

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Answer:

15.4 lbs

Step-by-step explanation:

Since the average of the top five is 13.3 this says that:

total weight of all the fish / 5 = 13.3 lbs

Therefore, the total weight of all five fish is equal to:

13.3 * 5 = 66.5

With this number, I subtracted all the other weights and found that the missing weight was:

15.4lbs.

Therefore, Wayne S. had the biggest fish weighing 15.4lbs

Answer:

15.4

Step-by-step explanation:

(14.2 + 13.4 + 12.1 + 11.4 + X) / 5 = 13.3

(51.1 + X) / 5 = 13.3

Cross:

51.1 + X = 66.5

then X = 66.5 - 51.1

= 15.4

Answer:

You're asked to find the cube root of 125.

That is,to cancel the power of y, you'd have to cube root both sides.

answer is 5

Answer:

4

Step-by-step explanation:

Given,

\(6+log\frac{3}{2} (\frac{1}{3\sqrt{2} } \sqrt{4-\frac{1}{3\sqrt{2} }\sqrt{4-\frac{1}{3\sqrt{2} } ...} }\)

Let,

\(x= \sqrt{4-\frac{1}{3\sqrt{2} }\sqrt{4-\frac{1}{3\sqrt{2} }\\\)

By this we get

\(x=\sqrt{4-\frac{1}{3\sqrt{2} }(x) } }\)

On squaring both sides,

\(x^{2} =4-\frac{1}{3\sqrt{2} }(x) } }\\\\x^{2} -4+\frac{x}{3\sqrt{2} } =0\\\\3\sqrt{2} x^{2} -12\sqrt{2} +x=0\\\\x=\frac{-1+\sqrt{1-(-12\sqrt{2})*(3\sqrt{2})*4 } }{2*3\sqrt{2} } \\\\x=\frac{-1+\sqrt{289} }{6\sqrt{2} } \\\\x=\frac{-1+17}{6\sqrt{2} } \\\\x=\frac{8}{3\sqrt{2} }\)

Now,

\(6+log\frac{3}{2} [\frac{1}{3\sqrt{2} } *\frac{8}{3\sqrt{2} } ]+log\frac{3}{2} *[\frac{8}{9*2} ]\\\\6+log\frac{3}{2}(\frac{4}{9} )\\\\6-log\frac{3}{2}(\frac{9}{4} )\\\\6-log\frac{3}{2} (\frac{3}{2})^2 \\\\6-2=4\)

\(\sqrt{4 - \dfrac1{3\sqrt2} \sqrt{4 - \dfrac1{3\sqrt2} \sqrt{4 - \dfrac1{3\sqrt2} \sqrt{\cdots}}}}\)

Starting from the identity

\((x - y)^2 = x^2 - 2xy + y^2\)

take the positive square root on both sides.

\(x - y = \sqrt{x^2 - 2xy + y^2}\)

Note that we must have \(x\ge y\). Rewrite the radicand and substitute \(x-y\).

\(x - y = \sqrt{x^2 - xy - y (x - y)} \\\\ ~~~~ = \sqrt{x^2 - xy - y \sqrt{x^2 - xy - y (x - y)}} \\\\ ~~~~ = \sqrt{x^2 - xy - y \sqrt{x^2 - xy - y \sqrt{x^2 - xy - y (x - y)}}} \\\\ ~~~~ \vdots \\\\ ~~~~ = \sqrt{x^2 - xy - y \sqrt{x^2 - xy - y \sqrt{x^2 - xy - y \sqrt{\cdots}}}}\)

Let \(y=\frac1{3\sqrt2}\). Solve for \(x\).

\(x^2 - \dfrac x{3\sqrt2} = 4 \\\\ x^2 - \dfrac x{3\sqrt2} + \dfrac1{72} = \dfrac{289}{72} \\\\ \left(x - \dfrac1{6\sqrt2}\right)^2 = \dfrac{289}{72} \\\\ x - \dfrac1{6\sqrt2} = \pm \dfrac{17}{6\sqrt2} \\\\ x = \dfrac{18}{6\sqrt2} \text{ or } x = -\dfrac{16}{6\sqrt2} \\\\ x = \dfrac3{\sqrt2} \text{ or } x = -\dfrac8{3\sqrt2}\)

Take the positive solution to ensure \(x>y\). Then the infinitely nested root expression in the logarithm converges to

\(x - y = \dfrac3{\sqrt2} - \dfrac1{3\sqrt2} = \dfrac{4\sqrt2}3\)

and the overall expression has a value of

\(6 + \log_{\frac32} \left(\dfrac1{3\sqrt2} \times \dfrac{4\sqrt2}3\right) = 6 + \log_{\frac32} \left(\dfrac49\right) \\\\ ~~~~ = 6 + \log_{\frac32} \left(\dfrac23\right)^2 \\\\ ~~~~ = 6 - 2 \log_{\frac32} \left(\dfrac32\right) \\\\ ~~~~ = 6 - 2 = \boxed{4}\)

the area of the region. 2y =4√x ; y = 5 ; and 2y+4x = 8 is 9, using the concept of area under the curve.

The region between a curve and the -axis is referred to as the "area under a curve." This region may be wholly above the -axis, entirely below the -axis, or somewhere in between. The area under a curve in calculus is a picture of an integral.

The region enclosed by the curve, the axis, and the boundary points is referred to as the "area under the curve." Using the coordinate axes and the integration formula, the area under the curve has been determined as a two-dimensional area. The area of the asymmetric plane form in a two-dimensional array is provided by the region beneath the curve.

The region bounded by the lines y = 5 and 2y + 4x = 8 and the curve

2y = 4√x

Now, finding the intersecting point between 2y + 4x = 8 and 2y = 4√x

so, 4√x + 4x = 8

or,  √x + x = 2

or, √x = (2 - x)

or, x = (2 - x)²

or, x = x² - 4x + 4

or, x² - 5x + 4 = 0

or, ( x - 4) ( x - 1) = 0

or, x = 4, 1

when x = 4 then y = 2√4 = 4

when x = 1 then y = 2 √1 = 2

when y = 4 and x = 4 then equation 2y + 4x = 8 is not satisfied.

Thus, only intersection point is: (1,2)

This is the type (II) region.

So, integrate the region with respect to y.

Now, area =

= \(\int\limits^5_2 {(y/2)^2 - ((8-2y) / 4)} \, dy\)

= \(\int\limits^5_2 {[(y^2/4) -2 + (y/2)]} \, dy\)

= \(\frac{1}{4} [y^3/3]^5_2 - 2 [y]^5_2 + \frac{1}{2} [y^2/2]^5_2\)

= \(\frac{117}{12} - 6 + \frac{21}{4}\)

= \(\frac{108}{12}\)

= 9

Thus, area = 9 of the region. 2y =4√x ; y = 5 ; and 2y+4x = 8.

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The rate of change of the volume when radius of sphere is 11 inch is 2904π inch³/minutes

According to the question,

The radius r of a sphere is increasing at a rate of 6 inches per minutes

Volume of sphere is 4/3 πr³

We have to find Rate of change of volume when r = 11 inch

Differentiating volume of sphere w.r.t time

V = 4/3 πr³

=> dV/dt = 4 πr² . dr/dt ---------(1)

As it is given that ,

dr/dt = 6

Substituting the value in equation (1)

=>  dV/dt = 4 πr² . 6

=> dV /dt = 24 πr²

r = 11

=> dV /dt = 24 π(11)²

=> 2904 π inch³/minutes is rate of change of volume

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Answer:

5 months

Step-by-step explanation:

9/3=3

15/3=5

Answer:

mijjujihnnijnihnknijnlkuhiy7g7ygi7yygub7tgiuhguyg

Step-by-step explanation:

Answer:

6 hours - 5 = 2, so 15 = 6 , as its constant

The dimensions of the room will be 12m x 6m.

So, now calculate the dimensions of the room as follows:

Solve as shown:

Therefore, 12m x 6m will be the dimensions of the room.

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Answer:

m = 14

Step-by-step explanation:

(-20 - 8 ) / ( 3 - 5)

-28/-2

28/2

14

Answer:

Nine and 35 hundredths of water

Step-by-step explanation:

Answer:

9.35 --->  Nine and thirty-five hundredths

The given statement, "We can use the normal distribution to approximate the sampling distribution of the average (\(\bar X\)) for a small sample (n<30) even if our sample has clear outliers." is false.

Several random samples of a predetermined size are taken from the same population to generate a sampling distribution, which is a sort of probability distribution. You can better understand how a sample statistic fluctuates from sample to sample by using these distributions.

The given statement is false because when the sample size is small (n < 30) and the data have clear outliers, the normal distribution may not be a suitable approximation for the sampling distribution of the average (\(\bar X\)). In such cases, the presence of outliers can significantly affect the distribution, causing it to deviate from a normal distribution.

For small samples with outliers, it is generally recommended to use alternative methods or non-parametric tests that do not assume a specific distribution. These methods take into account the non-normal nature of the data and provide more robust and reliable results.

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Answer: 2x = $90

Step-by-step explanation:

From the question, we are informed that Brady is selling candy bars for a school fundraiser to help pay for new sports uniforms and that he gets paid $2 for every candy bar he sells, and he made a total of $90 on Saturday.

The equation showing the number of candy bars Brady sold on Saturday goes thus:

Let the number of candy bars sold on Saturday be x.

Since each candy bar is sold for $2 and he made a total of $90, this means that the $90 gotten is the product of each candy bar and the amount sold which we represented by x. Therefore the equation will be:

2 × x = $90

2x = $90

We can further solve to get x.

2x = 90

x = 90/2

x = 45

That means 45 candy bars were sold.

Answer:

hi, so i belive the correct option to your question is:

2x = 90

Step-by-step explanation:

it just makes the most sense to me because 2x which could mean two times which in the equation it says he makes to dollars per candy bar sold, so it makes more sence for it to be 2x rather than 90x. and then it says he made a total of ninty dollars on saturday which is a key factor in solving this equation so think it would be 2x = 90$.

im really not sure if this logic makes sence, im not super good with algebra but i hope this helps you out.

ANSWER

y = -1.2x - 2

EXPLANATION

We want to find the equation of the line that passes through points (-5, 4) and (5, -8).

To do this, we use the formula:

From the question:

x1 = -5

y1 = 4

x2 = 5

y2 = -8

Therefore:

That is the equation of the line that passes through those points.

Answer:

0.45

Step-by-step explanation:

You divided 2.25 by 5

hope it's helpful °w°

THANK YOU

Answer:

y = 13

Step-by-step explanation:

First, find the value of x.

The 2 other angles with x values are alternate exterior angles, meaning they are congruent. Set up an equation setting them equal to each other:

10x - 17 = 8x + 1

Solve for x:

2x - 17 = 1

2x = 18

x = 9

Then, plug in 9 as x into the angle measure next to the one with y values:

8x + 1

8(9) + 1

72 + 1

= 73

This angle and the one with the y value will be supplementary. To find the measure of the angle with the y value, subtract 73 from 180:

180 - 73

= 107

So, it is equal to 107. Lastly, set the angle measure equal to 107 and solve for y:

6y + 29 = 107

6y = 78

y = 13

Answer:

1000

Step-by-step explanation:

The modifications to the ScoreCalculator exercise involve changing the storage of scores from an array to a List<int>, removing the score count variable, and updating the Add and Display Scores button event handlers accordingly. These changes demonstrate the benefits and differences between using a list and an array for storing data.

Based on your instructions, here's an example implementation of the Score Calculator exercise using C#:

```csharp

using System;

using System.Collections.Generic;

using System.Linq;

using System.Windows.Forms;

namespace ScoreCalculator

{

   public partial class ScoreForm : Form

   {

       private List<int> scores = new List<int>();

       public ScoreForm()

       {

           InitializeComponent();

       }

       private void AddButton_Click(object sender, EventArgs e)

       {

           int score;

           if (int.TryParse(scoreTextBox.Text, out score))

           {

               scores.Add(score);

               UpdateScoreStatistics();

               scoreTextBox.Clear();

               scoreTextBox.Focus();

           }

           else

           {

               MessageBox.Show("Invalid score. Please enter a valid integer value.", "Error",

                   MessageBoxButtons.OK, MessageBoxIcon.Error);

           }

       }

       private void ClearScoresButton_Click(object sender, EventArgs e)

       {

           scores.Clear();

           UpdateScoreStatistics();

           scoreTextBox.Clear();

           scoreTextBox.Focus();

       }

       private void ExitButton_Click(object sender, EventArgs e)

       {

           Close();

       }

       private void DisplayScoresButton_Click(object sender, EventArgs e)

       {

           List<int> sortedScores = scores.OrderBy(s => s).ToList();

           string scoresText = string.Join(Environment.NewLine, sortedScores);

           int scoresCount = sortedScores.Count;

           MessageBox.Show($"Sorted Scores ({scoresCount} scores):{Environment.NewLine}{scoresText}",

               "Sorted Scores", MessageBoxButtons.OK, MessageBoxIcon.Information);

           scoreTextBox.Focus();

       }

private void UpdateScoreStatistics()

       {

           int scoreTotal = scores.Sum();

           int scoresCount = scores.Count;

           double averageScore = scoresCount > 0 ? (double)scoreTotal / scoresCount : 0;

           scoreTotalLabel.Text = $"Score Total: {scoreTotal}";

           scoresCountLabel.Text = $"Scores Count: {scoresCount}";

           averageScoreLabel.Text = $"Average Score: {averageScore:F2}";

       }

       private void ScoreForm_KeyDown(object sender, KeyEventArgs e)

       {

           if (e.KeyCode == Keys.Enter)

           {

               AddButton_Click(sender, e);

               e.Handled = true;

               e.SuppressKeyPress = true;

           }

           else if (e.KeyCode == Keys.Escape)

           {

               ClearScoresButton_Click(sender, e);

               e.Handled = true;

               e.SuppressKeyPress = true;

           }

       }

   }

}

```

In this implementation, I've created a Windows Forms application with a form containing labels, text boxes, and buttons as described in the exercise. The event handlers for the buttons and key events are implemented to perform the required actions.

Note that this code assumes you have created a Windows Forms application project named "ScoreCalculator" and have added the necessary controls to the form.

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The complete question is:

In this exercise, you’ll create a form that accepts one or more scores from the user. Each time a score is added, the score total, score count, and average score are calculated and displayed.

Start a new project named ScoreCalculator..

Declare two class variables to store the score total and the score count.

Create an event handler for the Add button Click event. This event handler should get the score the user enters, calculate and display the score total, score count, and average score, and reset the focus to the Score text box. You can assume that the user will enter valid integer values and that they will be positive.

Create an event handler for the Click event of the Clear Scores button. This event handler should set the two class variables to zero, clear the text boxes on the form, and move the focus to the Score text box.

Create an event handler for the Click event of the Exit button that closes the form.

Go ahead and declare a class variable myData for an array that can hold up to 20 scores.

Modify the Click event handler for the Add button so it inserts each score that is entered by the user into the next element in the array. To do that, you can use the score count variable to refer to the next element.

If you have not done so already, add a Display Scores button that with a Click event that sorts the scores in the array (using a separate method), displays the scores in a dialog box (such as the one shown below), and moves the focus to the Score text box. Be sure that only the array elements that contain scores are displayed.

Test the application to be sure it works correctly.

Answer:

Every day the lake drops approximately 0.11 feet

Every week the lake drops 0.75 feet

Every month the lake drops 3 feet

Step-by-step explanation:

Daily rate 11/100

Weekly rate 0.75/100

Monthly rate 300/100

Answer:

The slope othe line is - 1

Answer:

-1/4

Step-by-step explanation:

The gas used by Abby while travelling in her pizza delivery route is 1/4.

As per the given question here we have to implement the basic principles of subtraction along with application of LCM.

The total amount of gas that Abby had in her car = 11/12

After coming to pizzeria the amount of gas left in her tank = 3/4

Here, we have to perform Subtraction to find out the amount of gas used for travelling. Therefore,

= 11/12 - 3/4

performing the LCM, we get

= 11 - 9/12

= 3/12 => 1/4

The gas used by Abby while travelling in her pizza delivery route is 1/4.

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The angle (in radians) between vectors u and v is approximately 1.66 radians, rounded to two decimal places.

To find the angle between two vectors, we can use the dot product formula and the magnitudes of the vectors. Let's calculate the angle between vectors u and v:

Given:

u = 4i - 6j

v = 5i + 4j

Step 1: Calculate the dot product of u and v.

The dot product of two vectors u and v is given by:

u · v = |u| |v| cosθ

where |u| and |v| are the magnitudes of vectors u and v, respectively, and θ is the angle between them.

To calculate the dot product, we multiply the corresponding components of u and v and sum them:

u · v = (4 * 5) + (-6 * 4) = 20 - 24 = -4

Step 2: Calculate the magnitudes of vectors u and v.

The magnitude of a vector is given by:

|u| = √(u₁² + u₂²)

For vector u:

|u| = √((4)² + (-6)²) = √(16 + 36) = √52 ≈ 7.21

For vector v:

|v| = √((5)² + (4)²) = √(25 + 16) = √41 ≈ 6.40

Step 3: Calculate the angle θ.

Using the dot product formula mentioned earlier, we have:

-4 = (7.21)(6.40)cosθ

Solving for cosθ:

cosθ = -4 / (7.21 * 6.40) ≈ -0.086

To find θ, we can take the inverse cosine (arccos) of cosθ:

θ ≈ arccos(-0.086) ≈ 1.66 radians

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