The Binding Energy Per Nucleon for ²³⁸U₉₂ is 1.11 MeV / nucleon (rounded to three significant figures).
The Binding Energy Per Nucleon can be determined using the formula: Binding Energy Per Nucleon = Binding Energy/Number of Nucleons.
Binding energy of a nucleus is defined as the amount of energy required to break up a nucleus into its individual nucleons. It is calculated as the difference between the mass of the nucleus and the mass of its individual nucleons.
Binding Energy Per Nucleon of a nucleus is an important physical quantity as it determines the stability of the nucleus and its ability to undergo nuclear reactions.
Let's calculate the Binding Energy Per Nucleon for ²³⁸U₉₂: Nuclear mass of ²³⁸U₉₂ = 238.050788 u
Binding energy of ²³⁸U₉₂ = 4.25 x 10⁻¹¹ J / nucleon (given) = 4.25 x 10⁻¹¹ J / 1.602 x 10⁻¹³ MeV (1 MeV = 1.602 x 10⁻¹³ J) = 264.96 MeV
Total number of nucleons in ²³⁸U₉₂ = 238
Binding Energy Per Nucleon = Binding Energy / Number of Nucleons = 264.96 MeV / 238= 1.11 MeV / nucleon
Therefore, the Binding Energy Per Nucleon for ²³⁸U₉₂ is 1.11 MeV / nucleon (rounded to three significant figures).
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c) A thin plano-convex lens is made of glass of refractive index 1.5 when an object is set
up 10 cm from the lens, a virtual image ten times its size is formed. What is: i) focal
length of lens? ii) the radius of curvature of the lens surface? (Ans: f=11.1 cm, R= 55.6
cm)
Answer:
i) The focal length of the lens is 11.1 cm. ii) The radius of curvature of the lens surface is 55.6 cm.
Explanation:
Given: refractive index of glass = 1.5, object distance u = -10 cm, image distance v = 100 cm (since the image is virtual and ten times the size of the object), and the thickness of the lens t is small.
i) To find the focal length f, we can use the lens formula:
1/f = 1/v - 1/u
Substituting the given values, we get:
1/f = 1/100 - 1/-101/f = 0.01 + 0.11/f = 0.11f = 1/0.11f = 9.09 cm
However, this is the focal length of the lens surface. Since the lens is thin, we can assume that the thickness is negligible compared to the focal length.
Therefore, the focal length of the lens is approximately equal to the focal length of the lens surface, which is 9.09 cm.
The focal length of the thin plano-convex lens is -11.1 cm and the radius of curvature of the lens surface is 55.6 cm. These values are obtained by applying the lens-maker formula and considering the given conditions.
Explanation:In this question, a thin plano-convex lens made of glass with a refractive index of 1.5 is described. An object is placed 10 cm from this lens and a virtual image ten times the size of the object is formed. We are required to find the focal length of the lens and the radius of curvature of the lens surface.
Using the lens-maker formula, 1/f = (n-1)(1/R1 - 1/R2 ), and considering the object distance (u) as -10 cm (the negative sign is due to the convention for virtual images), and the image distance (v) as -100 cm (ten times the object size), we find that the focal length (f) of the lens is -11.1 cm.
Next, applying the lens-maker formula again, but this time for the radius of curvature (R) of the lens surface. Since one surface of the lens is plane (R1 = ∞), the radius of curvature is that of the convex side (R2), we obtain R = 55.6 cm.
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Did it seem the Law of Reflection held for planar waves? How could you check to be sure?
The Law of Reflection held for planar waves due to partial transmission of the wave.
What is a Planar wave?This is a wave which has a constant physical quantity which is perpendicular to the direction of wave travel.
These type of wave has normal wave characteristics such as frequency and is partially transmitted through reflection.
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If a 0.3% decrease in the price of a good causes its quantity supplied to decrease by 1%, then the supply is: A. Unit elastic B. Elastic C. Inelastic D. Perfectly inelastic
If a 0.3% decrease in the price of a good causes its quantity supplied to decrease by 1%, then the supply is C. Inelastic.
In this scenario, the supply of the good is considered inelastic. The elasticity of supply measures the responsiveness of the quantity supplied to changes in price. When the price of a good decreases, and the quantity supplied decreases by a larger percentage, it indicates that the supply is relatively unresponsive to price changes.
To determine the elasticity of supply, we compare the percentage change in quantity supplied to the percentage change in price. In this case, a 0.3% decrease in price results in a 1% decrease in the quantity supplied. Since the percentage change in quantity supplied (1%) is greater than the percentage change in price (0.3%), the supply is considered inelastic.
Inelastic supply means that producers are less responsive to price changes, and a small change in price leads to a proportionally smaller change in quantity supplied. In such cases, producers may find it challenging to adjust their output levels quickly in response to price fluctuations.
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1. If a wagon has a mass of 8 kg and it is accelerating
at 0.5 m/s2, what is the force pulling the wagon?
Answer:
The force is equal to the mass times acceleration:
F = m•a
F = 8•0.5
F = 4 N
What are the similarities between the compass needle (magnetism) and a charge to probe the electric field (electricity)?
Similarities between the compass needle (magnetism) and a charge to probe the electric field (electricity) is that Electric fields are produced by two kinds of charges, positive and negative similarly Magnetic fields are associated with two magnetic poles
Magnetic Field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts. A pictorial representation of the magnetic field which describes how a magnetic force is distributed within and around a magnetic material.
Electric field, an electric property associated with each point in space when charge is present in any form. The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field.
Electric fields are produced by two kinds of charges, positive and negative. Magnetic fields are associated with two magnetic poles, north and south, although they are also produced by charges (but moving charges).
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The linear speed of a rotating wheel of radius 2 feet is 200f(t)/(m)in. What is the angular speed of the wheel in radians per minute? Round your answer to two decimal places. i
The angular speed of the wheel is **100π** radians per minute.
The linear speed of a rotating wheel is the distance traveled by a point on the circumference of the wheel per unit time. In this case, the linear speed is given as 200f(t)/(m)in, where f(t) represents an arbitrary function of time and m represents an arbitrary unit of measurement.
To find the angular speed of the wheel, we need to convert the linear speed into angular speed. Angular speed is defined as the rate at which an object rotates or travels around a circular path. It is measured in radians per unit time.
To convert the linear speed into angular speed, we need to relate the linear speed to the circumference and radius of the wheel. The circumference of a circle is given by 2π times the radius. In this case, the radius of the wheel is given as 2 feet.
Since the linear speed is the distance traveled per unit time, we can calculate the distance traveled in one minute by multiplying the linear speed by 60. Dividing this distance by the circumference of the wheel gives us the number of revolutions per minute. To convert this into radians per minute, we multiply the number of revolutions by 2π.
In summary, to calculate the angular speed of the wheel, we take the given linear speed and convert it into the number of revolutions per minute. We then multiply this value by 2π to obtain the angular speed in radians per minute.
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A moving object has a kinetic energy of 150J and a momentum of 20.3kgxm/s find the speed of the object in m/s
Answer:
\(v = 14.78m/s\)
Explanation:
Given
\(KE = 150J\)
\(p = 20.3kgm/s\)
Required
Determine the object's speed
Kinetic Energy is calculated as:
\(KE = \frac{1}{2}mv^2\)
Make m the subject
\(m = \frac{2KE}{v^2}\)
Momentum is calculated as:
\(p = mv\)
Make m the subject
\(m = \frac{p}{v}\)
So, we have:
\(m = \frac{p}{v}\) and \(m = \frac{2KE}{v^2}\)
Equate both expressions: \(m = m\)
\(\frac{2KE}{v^2} = \frac{p}{v}\)
Multiply both sides by v
\(v * \frac{2KE}{v^2} = \frac{p}{v}*v\)
\(\frac{2KE}{v} = p\)
Make v the subject
\(v = \frac{2KE}{p}\)
Substitute \(KE = 150J\) and \(p = 20.3kgm/s\)
\(v = \frac{2 * 150}{20.3}\)
\(v = \frac{300}{20.3}\)
\(v = 14.78m/s\)
Tidal power can only be generated a in locations with a large difference between high and low tides. b if there is a technological breakthrough. c when the Moon is directly overhead. d during the day. e in locations with high radioactivity.
a) Tidal power can only be generated in locations with a large difference between high and low tides.
Tidal power is generated by controlling the kinetic energy of tidal currents, which are caused by the interactivity of the gravity between the Moon, Sun, and Earth. The tides play an important role in determining the potential for tidal power generation.
Technologies trying to improve the quality and effectiveness of tidal power generation but the basic requirements remain necessary such as the sun, moon, and the earth and the presence of radioactivity does not affect the generation of tides.
Hence the conclusion is that tidal power can only be generated in locations with a large difference between high and low tides.
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someone please answer this, ill give you brainliest and your getting 100 points.
Answer:
B
Explanation:
Here .
B is denoted to asthenosphere
E is Mantal section which consists of semifluid magma or lava .this problem refers to questions 1, 2 and 3.two students 1 and 2 are holding a long spring made of two springs a and b connected at point j (see figure). student 2 creates a pulse having a displacement only on one side of the spring (either y > 0 or y < 0). some time later (not necessarily at the same time), the students receive pulses that are on the same side of the spring (i.e. if student 1 receives a pulse with y > 0, then student 2 receives a pulse with y > 0).
The pulses received by students 1 and 2 are on the same side of the spring due to the conservation of wave properties.
When student 2 creates a pulse with a displacement on one side of the spring, it sets off a wave that travels through the spring. This wave carries energy and momentum, and it causes the particles of the spring to oscillate. As the wave travels, it transfers its energy and momentum to the neighboring particles, causing them to oscillate as well.
When student 1 receives the pulse, it means that the wave has reached the end of the spring where student 1 is located. At this point, the wave has traveled a certain distance and undergone multiple reflections and interactions with the particles of the spring.
Since the pulses received by students 1 and 2 are on the same side of the spring, it indicates that the wave has not encountered any boundary or obstacle that would cause it to change its direction or flip to the opposite side of the spring. This is because the spring is continuous and the waves propagate without any interruptions or reflections that would invert their displacement.
In other words, the wave created by student 2 travels through the spring and maintains its original orientation until it reaches student 1. This behavior can be explained by the principle of superposition, which states that when two waves overlap, the resulting wave is the sum of their individual displacements. Therefore, if student 2 creates a pulse with a positive displacement, student 1 will also receive a pulse with a positive displacement.
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A student rings a brass bell with a frequency of 200 Hz. The sound wave
travels through brass, air, and glass. What is the wavelength of the wave in
brass?
Medium
Wave speed
(m/s)
Brass
4,700
Air
346
Glass
5,640
A. 2.3 m
B. 0.43 m
C. 0.043 m
D. 23.5 m
Answer:
Option D. 23.5 m
Explanation:
From the question given above, the following data were obtained:
Frequency = 200 Hz
Speed of sound in brass = 4700 m/s
Wavelength of sound in brass =?
We can obtain the wavelength of the sound in the brass by using the following formula as illustrated below:
Wave speed = wavelength × frequency
4700 = wavelength × 200
Divide both side by 200
Wavelength = 4700 / 200
Wavelength = 23.5 m
Thus, the wavelength of the sound in the brass is 23.5 m
the block of mass m in the following figure slides on a frictionless surface
For the right block to balance the forces and remain steady, it needs to weigh 7.9 kg.
The force is an external agent which is applied to the body or an object to move it or displace it from one position to another position.
When there is no net force acting on the system, the two blocks stay in place. In this instance, the strain in the rope holding the two blocks together balances the pull of gravity on them. The sine of the angles, along with the masses of the blocks, can be used to calculate the tension in the rope.
\(T= (m_1 \times g) \times sin(\theta_1) + (m_2\times g) \times sin(\theta_2)\)
Substituting the known values:
\(T = (10 \times 9.8 )\times sin(23^o) + (m_2\times 9.8 )\times sin(40^o)\)
Solving for m₂:
\(m_2= \dfrac{(T- (10 \times 9.8 )\times sin(23^o)} { (9.8\times sin(40^o))}\)
The mass of the right block must be 7.9 kg for the two blocks to remain stationary.
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The question is -
Two blocks in the Figure below are at rest on frictionless surfaces What must be the mass of the right block so that the two blocks remain stationary? 4.9kg 6.1kg 7.9kg 9.8kg
When electricity to an electromagnet is stopped, what happens to the strength of the magnet?.
When electricity to an electromagnet is stopped the magnetic strength of the magnet will be lost.
What is electromagnet and what happens to the strength of the magnet?An electromagnet is a device consisting of a core made up of magnetic material surrounded by a coil through which electric current can pass.So electricity is essential to the wire for the electromagnet to work in a proper manner.In the electromagnet the magnetic flux is varied , sometimes it is switched on and sometimes off.Inside the electromagnet moving charges create magnetic fields, when coil have the current passing through it. Hence the magnet will lose the magnetic strength when electricity to an electromagnet is stopped.To know more about electromagnet visit:
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What is the biker’s momentum when his mass is 75 kg and moves along the path with a constant velocity of 5m/s?
The momentum of the bike moving along the path with a constant velocity is 375 kgm/s.
What is momentum?
The momentum of an object is the effect experienced by a moving object when a certain force acts on it. It is the product of mass and velocity.
The momentum of the bike is calculated as follows;
P = mv
P = 75 x 5
P = 375 kgm/s
Thus, the momentum of the bike moving along the path with a constant velocity is 375 kgm/s.
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HELP PLEASE (ramadan mubarak)
Redox reactions include which types of reactions?
A.
Acid-base, decomposition, double-replacement, synthesis
B.
Double-replacement, combustion, synthesis, decomposition
C.
Single-replacement, synthesis, decomposition, combustion
D.
Single-replacement, double-replacement, acid-base, synthesis
Answer:
C
Explanation:
five main types of redox reactions: combination, decomposition, displacement, combustion, and disproportion.
synthesis is kinda the same as combination
Is this acceleration away, acceleration back , constant speed back, constant speed away, constant speed (or velocity), or constant negative acceleration (decreasing speed or velocity ) at a constant rate?
Answer:
ya daddy is my zaddy
Explanation:
A 0.05 kg ball moving at 25 m/s
Kinetic energy of the ball is 31.25 J.
Mass of the ball, m = 0.05 kg
Velocity of the ball, v = 25 m/s
Kinetic energy of the ball,
KE = 1/2 mv²
KE = 0.05 x 25²
KE = 31.25 J
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Your question was incomplete, but most probably your question will be:
A 0.05 kg is ball moving at 25 m/s. Calculate its kinetic energy.
a satellite, with a mass of 9.0 x 103 kg, orbits 2.56 x 107 m above earth’s surface. determine its period. group of answer choices 1.1 x 104 s 1.5 x 105 s 4.1 x 104 s 5.7 x 104 s
Based on the given data, the period of the satellite is 5.7 x 104 s.
We can use Kepler's third law to find the period of a satellite. This law states that the square of the period of any planet orbiting around the Sun is proportional to the cube of the semi-major axis of its elliptical orbit. It can also be used for objects orbiting around other celestial bodies such as Earth.
The equation for Kepler's third law is:
T² = (4π²/GM) r³
T is the period
r is the average distance between the satellite and Earth's center (r = 2.56 × 107 m + 6.38 × 106 m)
G is the gravitational constant
M is the mass of Earth (5.98 × 1024 kg)
We can rearrange the equation to solve for T:
T = 2π √(r³/GM)
Substituting the values, we get:
T = 2π √[(2.56 × 107 m + 6.38 × 106 m)³/(6.6743 × 10-11 N m²/kg²) (5.98 × 1024 kg)]
Simplifying the expression,T = 5.68 × 104
So, we round the period of the satellite to 5.7 x 104 s.
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Sunidhi made a study chart about changes in states of
matter.
Which headings best complete the chart?
X
melting
sublimation
Y
freezing
deposition
X: Solid Directly to Liquid
Y: Liquid Directly to Solid
OX: Liquid Directly to Solid
Y: Solid Directly to Liquid
O X: Heat Is Released
Y: Heat Is Absorbed
X: Heat Is Absorbed
Y: Heat Is Released
Answer:
freezing melting sublimating x y
x and
Explanation:
To drop a table of states of matter the best headings must be
table name: matter state
freezing melting sublimation x y
This order goes from the solid state to the gaseous state, which is obtained by introducing heat into the system
Answer: D on edge
X: Heat Is Absorbed
Y: Heat Is Released
Explanation:
sublimation and melting are both absorbing heat(aka getting warmer)as they change state while freezing and deposition are releasing heat(aka getting colder)as they change state
Plz help me with these :)
Astronomers categorize galaxies into a handful of basic shapes. What can you conclude from this fact?
From the that astronomers categorize galaxies into a handful of basic shapes, it can be concluded that the all galaxies are made from the same forces.
Astronomers have categorized galaxies into three main categories,
Elliptical Galaxies:
These galaxies have smooth ellipsoidal shape. They are most abundant type. For example- Messier 49
Spiral galaxies:
These galaxies have a spiral shapes with many hand like structures. For example- Milky way.
Irregular Galaxies:
They do not have any specific shape.
Therefore, from the that astronomers categorize galaxies into a handful of basic shapes, it can be concluded that the all galaxies are made from the same forces.
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You look at a rope coiled on a beach and are able to perceive it as a single strand because of the law of.
You are able to perceive it as a single strand because of the principle of : Good continuation
Principle of good continuationPrinciple of Good continuation states that objects with very smooth edges are easily seen as been continuous ( i.e as a single strand ) rather than objects or materials with rough edges.
The rope coiled on a beach has very smooth edges therefore can be seen as a continuous strand and this is possible due to the principle of good continuation.
Hence we can conclude that You are able to perceive it as a single strand because of the principle of : Good continuation.
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The silica cylinder of a radiant wall heater is 0.6 m long
and has a radius 6 mm. If it is rated at 1.5 kw estimate
its temperature when operating. [The Stefan constant,
6=6 x 10-8 wm-2-4)
The estimated temperature of the radiant wall heater when operating is approximately 257 Kelvin.
To estimate the temperature of the radiant wall heater, we can use the Stefan-Boltzmann law, which relates the power radiated by an object to its temperature.
The formula for power radiated is given by:
P = σ * A * T^4
where P is the power radiated, σ is the Stefan constant (6 x 10^-8 Wm^-2K^-4), A is the surface area of the heater, and T is the temperature in Kelvin.
First, we need to calculate the surface area of the silica cylinder. The formula for the surface area of a cylinder is:
A = 2πrh + 2πr^2
where r is the radius and h is the height (length) of the cylinder.
Given:
Radius, r = 6 mm = 6 x 10^-3 m
Length, h = 0.6 m
Plugging in these values, we can calculate the surface area:
A = 2π(6 x 10^-3 m)(0.6 m) + 2π(6 x 10^-3 m)^2
= 0.072π m^2
Now, we can rearrange the Stefan-Boltzmann law to solve for temperature T:
T^4 = P / (σ * A)
Given:
Power, P = 1.5 kW = 1500 W
Stefan constant, σ = 6 x 10^-8 Wm^-2K^-4
Surface area, A = 0.072π m^2
Plugging in these values, we get:
T^4 = (1500 W) / (6 x 10^-8 Wm^-2K^-4 * 0.072π m^2)
T^4 ≈ 3.1 x 10^9 K^4
Taking the fourth root of both sides, we find:
T ≈ 257 K
Therefore, the estimated temperature of the radiant wall heater when operating is approximately 257 Kelvin.
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You release a pendulum of mass 1 kg from a height of 0.75 m. If there is no air resistance, how fast is the pendulum going when it reaches the bottom
Explanation:
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × 9.8 m/s² × 0.75 m)
v = 3.83 m/s
Two balls, a foam ball and a golf ball, are placed into a pail of water. The golf ball sinks. Why does a foam ball float and a golf ball sink when both are placed into water?
Answer:
The golf ball has a greater mass than the foam ball
Explanation:
A 90kg football receiver named Reggie is running at 6.7m/s to catch a pass. A defensive back (103kg) named
Julio is waiting in position to hit him (standing still). They fall to the ground together after the tackle. How fast
are they going after the collision?
Answer: reciever is going to be going the momentum which is 90 times 6.7, so defensive back who is 103 KG and standing still therefore has no momentum, so the collision is 6.7 m/s against the defense
Explanation:
zero momentum
newton's 1st law of motion, when something is acted upon by an unbalanced force.
plz answer this very soon
Answer:
Im gonna say it is answer A:) Hope this helps!
Explanation:
Which of the following is a way that trees have been negatively impacted by human use? a. Deforestation b. Pollution c. Reduction d. All of the above Please select the best answer from the choices provided A B C D.
Answer:
D
Explanation:
Trees are obviously effected from deforestation.
Pollution effects the things trees need to grow (water, air).
Reduction removes parts of the tree, some parts being needed.
Answer: D
Explanation:Trees are obviously effected from deforestation.
Pollution effects the things trees need to grow (water, air).
Reduction removes parts of the tree, some parts being needed.
at room temperature, what fraction of the nitrogen molecules in the air are moving at less than 300 m/s?
The fraction of nitrogen molecules in the air that are moving at less than 300 m/s is likely to be very high, since this is well below the average speed of nitrogen molecules at room temperature. However, the exact fraction will depend on the specific temperature and pressure conditions.
At room temperature, the majority of nitrogen molecules in the air move at speeds less than 300 m/s. The average speed of nitrogen molecules in the air is around 500 m/s, but the speed distribution follows a bell-shaped curve, with a small fraction of molecules moving much faster and a small fraction moving much slower than the average.
The distribution of molecular speeds is determined by the Maxwell-Boltzmann distribution, which describes how the speeds of gas molecules are related to temperature. The distribution shows that at any given temperature, only a small fraction of molecules have speeds greater than a certain value.
For example, at room temperature (around 25°C or 298 K), only about 2.5% of nitrogen molecules in the air have speeds greater than 500 m/s, while the vast majority (over 97%) have speeds less than this value. Even fewer molecules (less than 0.1%) have speeds greater than 1000 m/s, which is much faster than the speed of sound in air.
Overall, the fraction of nitrogen molecules in the air that are moving at less than 300 m/s is likely to be very high, since this is well below the average speed of nitrogen molecules at room temperature. However, the exact fraction will depend on the specific temperature and pressure conditions.
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HELP PLEASE!
A 700 kg race car makes one lap around a track. It has a velocity of 20 m/s with a centripetal force of 5,600 N. What is the radius of the track?
A speed skater goes around a turn with a 25 m radius. The skater has a velocity of 15 m/s and experiences a centripetal force of 720 N. What is the mass of the skater?
A 900-kg car moving at 5 m/s takes a turn around a circle with a radius of 30 m. Determine the net force acting upon the car.
An 800 kg race car makes one lap around a track. It has a velocity of 40 m/s with a centripetal force of 16,000 N. What is the radius of the track?
PLEASE EXPLAIN AND SHOW WORK!
The centripetal force is the force that keeps a body moving in a circular path.
The centripetal force is given by; F = mv^2/r
1) We have;
F = 5,600 N
v = 20 m/s
r =?
m = 700 kg
Making r the subject of the formula;
r =mv^2/F
r = 700 × (20)^2/5,600
r = 50 m
2) F = mv^2/r
F = 900 × (5)^2/30
F = 750 N
3) Making r the subject of the formula;
r =mv^2/F
r = 800 × (40)^2/ 16,000
r = 80 m
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