Standardizing 10 and 12 gives us Z = (10 - 11) / 1.50 = -0.6667 and Z = (12 - 11) / 1.50 = 0.6667, respectively. Using the standard normal curve table or SALT, we find P(-0.6667 ≤ Z ≤ 0.6667) = 0.4972. Therefore, P(|X - 11| ≤ 1) = 0.4972.
(a) P(X ≤ 11) 0.5000The given normal distribution has a mean value of μ=11 kips and a standard deviation of σ=1.50 kips. To standardize X, we use the formula
Z = (X - μ) / σ = (X - 11) / 1.50.(a) P(X ≤ 11)
represents the probability that X is less than or equal to 11. The Z-score corresponding to
X = 11 is Z = (11 - 11) / 1.50 = 0.
Hence,
P(X ≤ 11) = P(Z ≤ 0) = 0.5000. (b) P(X ≤ 12.5) 0.8413(b) P(X ≤ 12.5)
represents the probability that X is less than or equal to 12.5. The Z-score corresponding to
X = 12.5 is Z = (12.5 - 11) / 1.50 = 0.8333
Using the standard normal curve table or SALT, we find
P(Z ≤ 0.8333) = 0.7977.
Therefore
, P(X ≤ 12.5) = 0.7977. (c) P(X ≥ 3.5) 1(c) P(X ≥ 3.5)
represents the probability that X is greater than or equal to 3.5. Any value less than 3.5 would be many standard deviations away from the mean. Therefore,
P(X ≥ 3.5) = 1, or 100%. (d) P(9 ≤ x ≤ 14) 0.8855(d) P(9 ≤ X ≤ 14)
represents the probability that X is between 9 and 14 (inclusive). To standardize 9 and 14, we use the formula
Z = (X - μ) / σ.
The Z-score corresponding to
X = 9 is Z = (9 - 11) / 1.50 = -1.3333.
The Z-score corresponding to
X = 14 is Z = (14 - 11) / 1.50 = 2.
This gives us P(-1.3333 ≤ Z ≤ 2) = 0.8855 using the standard normal curve table or SALT.
(e) P(|X-11| ≤ 1) 0.4972(e) P(|X - 11| ≤ 1)
represents the probability that X is within 1 kip of the mean value 11 kips. We can write this as P(10 ≤ X ≤ 12). Standardizing 10 and 12 gives us
Z = (10 - 11) / 1.50 = -0.6667 and Z = (12 - 11) / 1.50 = 0.6667
, respectively. Using the standard normal curve table or SALT, we find
P(-0.6667 ≤ Z ≤ 0.6667) = 0.4972.
Therefore,
P(|X - 11| ≤ 1) = 0.4972.
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The value of a certain investment over time is given in the table below. Answer the questions below to explain what kind of function would better model the data, linear or exponential. Number of Years Since Investment Made, x 1 2 3 4 Value of Investment ($), f(x) 16,890.32 14,259.09 12,001.57 10,051.16 function would better model the data because as x increases, the y values change . The of this function is approximately .
f(x) is an exponential function with an initial value of 33,966.17 and a decay rate of 0.310, which matches the trend of the data.
What is a scatter plot?We can plot the data points and look for a pattern to see if an exponential or linear function better fits the provided data.
The provided data point can first be plotted as a scatter plot.
(1, 16890.32) (2, 14259.09) (3, 12001.57) (4, 10051.16)
To find the specific exponential function that would fit this data, we can use the formula for exponential decay:
f(x) = a * \(e^(-bx)\)
where f(x) is the value of the investment at time x, a is the initial value of the investment, and b is the decay rate.
Using the given data, we can plug in the values for f(x) and x to solve for a and b. Here is the calculation:
16,890.32 = a * \(e^(-b1)\)
14,259.09 = a * \(e^(-b2)\)
12,001.57 = a * \(e^(-b3)\)
10,051.16 = a * \(e^(-b4)\)
Dividing the second equation by the first, and the third equation by the second, and so on, we can get rid of the constant a:
14,259.09/16,890.32 = \(e^(-b)\)
12,001.57/14,259.09 = \(e^(-b)\)
10,051.16/12,001.57 = \(e^(-b)\)
Taking the natural logarithm of both sides, we get:
ln(14,259.09/16,890.32) = -b
ln(12,001.57/14,259.09) = -b
ln(10,051.16/12,001.57) = -b
Simplifying these equations, we get:
b ≈ 0.310
a ≈ 33,966.17
So the exponential function that best models this data is:
f(x) = 33,966.17 * \(e^(-0.310x)\)
This function has an initial value of 33,966.17 and a decay rate of 0.310, which matches the trend of the given data.
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Complete question:
The value of a certain investment over time is given in the table below. Answer the questions below to explain what kind of function would better model the data, linear or exponential.
Number of Years Since Investment Made,
x 1 2 3 4
Value of Investment ($),
f(x) 16,890.32 14,259.09 12,001.57 10,051.16
the function would better model the data because as x increases, the y values change. The of this function is approximate.
Macy's was also having a sale. All kitchen items were 50% off. Ms. M bought a Keurig that originally cost $129.00. How much did she pay for the keurig with the discount?
the answer is $64.50 hope it helps
Find smallest number which on adding to 19 it is exactly divisible by 28,36 and 45 (LCM).
Answer:
1241
Step-by-step explanation:
∴
L.C.M. of 28, 36 and 45 = 2 × 2 × 3 × 3 × 5 × 7 = 1260
∴
the required number is 1260 - 19 = 1241
Hence, if we add 19 to 1241 we will get 1260 which is exactly divisible by 28, 36 and 45.
Write an equation of a line parallel to the given equation through the given point
Given the equation of the line :
\(y=-\frac{1}{4}x-6\)It is required to write the equation of the line parallel to the given line and pass through the point ( 12 , 4 )
The general equation of the line in slope - intercept form is :
\(y=m\cdot x+b\)Where m is the slope and b is y - intercept
As the line are parallel , so, the slope of the required line will be equal to the slope of the given line
So, the slope = m = -1/4
So, the equation of the line will be :
\(y=-\frac{1}{4}x+b\)Using the given point ( 12 , 4 ) to find b
so, when x = 12 , y = 4
\(\begin{gathered} 4=-\frac{1}{4}\cdot12+b \\ \\ 4=-3+b \\ 4+3=b \\ b=7 \end{gathered}\)So, the equation of the required line is :
\(y=-\frac{1}{4}x+7\)
I will solve by SUBSTITUTION/ELIMINATION
10x8y = -16
5x - 4y=+5)
The solution to the system of equations is x = -3/10 and y = -13/8
How to solve the system of equations?The system of equations is given as
10x + 8y = -16
5x - 4y = 5
Multiply through the equation 5x - 4y = 5 by 2
So, we have
10x - 8y = 10
Add this equation to the first equation to eliminate (y)
So, we have
20x = -6
Divide both sides
x = -3/10 = -0/3
Substitute x = -0.3 in 10x + 8y = -16
-10 x 0.3 + 8y = -16
Evaluate
-3 + 8y = -16
So, we have
y = -13/8
Hence, the solution is x = -3/10 and y = -13/8
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what is another name for proportional relationships?
Answer:
equivalent i think
Step-by-step explanation:
Find weights wo and wi, and node, x1, k = 1, 2, so that the quadrature formula L se f(x) dx = wof(-1) + wif(x1), is exact for polynomials of degree 2 or less.
To find the weights wo and wi and the node x1 that make the quadrature formula L se f(x) dx = wof(-1) + wif(x1) exact for polynomials of degree 2 or less, a system of equations needs to be set up and solved using the values of the monomials at the nodes (-1 and x1).
In Gaussian quadrature, the weights and nodes are chosen in such a way that the quadrature formula is exact for polynomials up to a certain degree. In this case, we want the formula to be exact for polynomials of degree 2 or less.
For a quadrature formula with two weights and two nodes, we can represent it as follows:
L se f(x) dx = wof(-1) + wif(x1)
To make this formula exact for polynomials of degree 2 or less, we need it to integrate exactly the monomials 1, x, and x².
By setting up a system of equations using the values of the monomials at the nodes (-1 and x1) and solving for the weights and node, we can find the specific values that make the formula exact.
The explanation would require further mathematical calculations and solving the system of equations to find the values of wo, wi, and x1 that satisfy the condition. However, without specific numerical values or additional constraints, it is not possible to provide the exact solution.
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describe a dataset where defining a confidence interval would be important for testing validity of data
The sample's data values ought to be unrelated to one another. The sample data need to be consistent. Data from the quantitative ordered pair sample should be gathered at random or in a way that is representative of the overall population. The sample's data values ought to be unrelated to one another.
A confidence interval is a much better tool to use if we wish to communicate the level of uncertainty surrounding our point estimate (CI). A confidence interval (CI) is a symmetrical range of values where the results of repeated, related experiments are likely to fall. The middle of this range corresponds to our point estimate.
Confidence intervals, which describe how closely study results match reality or how dependable they are based on statistical theory, are regularly mentioned in scientific publications.
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Which polynomial function has x-intercepts –1, 0, and 2 and passes through the point (1, –6)
Answer:
y=3x(x+1)(x-2)=3x^3-3x^2-6x
Step-by-step explanation:
The polynomial function can be written in the form:
y=a(x-x1)(x-x2)(x-x3)
where
x1=-1
x2=0
x3=2
Therefore
y=a(x+1)(x-0)(x-2)=a(x^2+x)(x-2)=a(x^3-x^2-2x)
To find the value for "a" we use the info about the line passing in (1,-6):
-6=a(1-1-2)
a=3
y=3x(x+1)(x-2)=3x^3-3x^2-6x
Answer:
f(x) = 3x3 - 3x2 - 6x
Good luck! :D
Step-by-step explanation:
Find the surface area of the cylinder.
Answer:
1188 inches
Step-by-step explanation:
Answer:
The surface area of the cylinder with a radius of 7 and height of 20 would be 1186.92.
Step-by-step explanation:
The formula as given by the image is
h=20, r=7.
Substitute your radius and height as follows:
SA=\(SA=2*pi*r^2+2pi*r*h\\(2*3.14*7^2)+(2*3.14*7*20)\)
And now solve!
307.72+879.2=1186.92
The answer would be 1186.92
the average height of students at uh from an srs of 19 students gave a standard deviation of 3.2 feet. construct a 95% confidence interval for the standard deviation of the height of students at uh. assume normality for the data. a) (1.418, 10.732) b) (1.918, 5.732) c) (2.418, 4.732) d) (6.418, 11.732) e) (5.418, 9.732) f) none of the above
The 95% confidence interval for the standard deviation of the height of students at UH is (1.918, 5.732), which corresponds to option b.
To construct a 95% confidence interval for the standard deviation of the height of students at UH, we will use the Chi-square distribution. Given the sample standard deviation (s) of 3.2 feet, a sample size (n) of 19 students, and assuming normality for the data, we can find the confidence interval as follows:
1. Determine the degrees of freedom: df = n - 1 = 19 - 1 = 18
2. Identify the Chi-square values for the confidence level (95%): χ²_lower = 7.632, χ²_upper = 32.852 (using a Chi-square table or calculator)
3. Calculate the lower and upper bounds of the confidence interval:
Lower bound = sqrt((n - 1) * s² / χ²_upper) = sqrt(18 * (3.2)² / 32.852) ≈ 1.918
Upper bound = sqrt((n - 1) * s² / χ²_lower) = sqrt(18 * (3.2)² / 7.632) ≈ 5.732
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The 95% confidence interval for the standard deviation of the height of students at UH is approximately (1.918, 5.732), Option B.
Construct a 95% confidence interval for the standard deviation of the height of students at UH, we'll use the given data and the Chi-Square distribution.
Here's a step-by-step explanation:
SRS (simple random sample) of 19 students, which means the degrees of freedom (df) = n - 1 = 19 - 1 = 18.
The sample standard deviation (s) is given as 3.2 feet.
Assume normality for the data.
A 95% confidence interval, we'll use the Chi-Square distribution table to find the critical values.
The two tail probabilities are 0.025 and 0.975, so we'll look up the Chi-Square values for 18 degrees of freedom and these probabilities:
\(- X^2_{0.025} = 30.191 (upper limit)\)
\(- X^2_{0.975} = 8.231 (lower limit)\)
Calculate the confidence interval for the population standard deviation (σ):
\(\((\sqrt((n - 1) \times s^2 / X^2_{upper}), \sqrt((n - 1) \times s^2 / X^2_{lower}))\)\)
Plug in the values:
\(- n = 19\)
\(- s = 3.2\)
\(- df = 18\)
\(\(- X^{2} _{upper} = 30.191\)\)
\(\(- X^2_{lower} = 8.231\)\)
Calculate the confidence interval:
\((√((18 \times 3.2^2) / 30.191), \sqrt((18 \times 3.2^2) / 8.231)) \approx (1.918, 5.732)\)
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1. The table shows the minimum wage rates for the United States during different years.
Year 1978 1979 1980 1990 1991 1996 1997 2007 2008 2009
Minimum hourly wage 2.65 2.90 3.35 3.80 4.25 4.75 5.15 5.85 6.55 7.25
(a) Write the least squares regression equation that models the data. Let x = time in years since 1900 and let y = minimum hourly wage.
(b) Use the equation to estimate the minimum hourly wage of a U.S. worker in 2025. Show your work.
PLS ANSWER CORRECTLY WITH AN EXPLANATION
Answer:
y = 0.126X - 7.119
8.63
Step-by-step explanation:
X = year, we subtract the year in the data from 1900 ;
So for the years we have :
78,79,80,90,91,96,97,107,108,109
Using technology to fit the data above, the regression model obtained is ;
y = 0.126X - 7.119
Where x = years
y = minimum hourly wage
The minimum hourly wage in 2025
Year = x = 2025 - 1900 = 125 years
y = 0.126(125) - 7.119
y = 8.631
Predicted Minimum hourly wage = 8.63
The estimated minimum wage for 2025 is $ 13.75.
Taking into account the wage data, to determine the equation that models the wage increase and estimate the minimum hourly wage of a U.S. worker in 2025 the following calculations must be performed:
1978 = $ 2.65 1979 = $ 2.90 1980 = $ 3.35 1990 = $ 3.80 1991 = $ 4.25 1996 = $ 4.75 1997 = $ 5.15 2007 = $ 5.85 2008 = $ 6.55 2009 = $ 7.25
2.65 = 100 7.25 = X 725 / 2.65 = 273.58
173.58 / (2009-1978) = X 173.58 / 31 = X 5.6 = X
(2025 - 2009) x 5.6 = 89.6 100 = 7.25 189.6 = X 189.6 x 7.25 / 100 = X 13.75 = X
Therefore, the estimated minimum wage for 2025 is $ 13.75.
Lines AB and CD (if shown) are straight lines. Find x. Give reasons to justify your solutions. PLS HELP! WILL GIVE BRAINLIEST!!
Answer:
Step-by-step explanation:
m∠DOB = m∠DOE + m∠BOE
m∠DBO = 90 + x
m∠DOB = m∠AOC {Vertically opposite angles}
110 = 90 +x
x = 110 - 90 = 20
Answer:
x=20
Step-by-step explanation:
m∠DOB = m∠DOE + m∠BOE . parts whole postulate
m∠DBO = 90 + x subs
m∠DOB = m∠AOC verticle angles
110 = 90 +x . subs
x = 110 - 90 = 20 alg
1. A tortoise is running on a long, moving sidewalk. Her pedometer doesn't report her speed, but she knows that—since she got on—she's been running for 40 minutes and that she's traveled 3 kilometers. Unfortunately, she realizes she left her suitcase on the ground just before she got on the sidewalk. Since she's too short to climb over the handrails, she decides to turn around and run at the same speed back to her suitcase. If it takes her 2 hours to return to her suitcase, how fast (in kilometers per hour) was the moving sidewalk moving? How fast (in kilometers per hour) was the tortoise running?
Answer:
the sidewalk speed q = 3km/hr
the tortoise speed p is 1.5 km/hr
Step-by-step explanation:
From the given information:
let the speed of the tortoise be p & the speed of the sidewalk be q
she's been running for 40 minutes (40/60 = 2/3) and that she's travelled 3 kilometres
Thus,
p + q = \(\dfrac{3}{\dfrac{2}{3}}\)
p + q = 9/2
p + q = 4.5 ----- (1)
when returning, she travelled 3km in 2 hours
i.e. -p + q = 3/2
-p + q = 1.5 ----- (2)
Thus, by using the elimination method for equation (1) and (2)
p + q = 4.5 ----- (1)
-p + q = 1.5 ----- (2)
2q = 6
q = 6/2
q = 3 km/hr
From equation (1)
p + q = 4.5
p + 3 = 4.5
p = 4.5 - 3
p = 1.5 km/hr
Therefore, the sidewalk speed q = 3km/hr and the tortoise speed p is 1.5 km/hr
Help me please ASAP
Answer: 150?
Step-by-step explanation:
please help making brainliest if correct
Answer:
SAS CONGRUENCYStep-by-step explanation:
HOPE IT HELPSWith the markings on each triangle you are being told 2 sides are identical and that 1 angle is identical.
You would use B. SAS
what is the sum of the following equation? 16/100
a. 10/100
b. 22/100
c. 36/100
d. 76/100
Answer:
0.76
\(\frac{19}{25}\)
Step-by-step explanation:
Answer:
D) 76/100
Step-by-step explanation:
16/100 + 6/10 = ?
16/100 + 60/100 = ?
16/100 + 60/100 = 76/100
A point is represented in 3D Cartesian coordinates as (5, 12, 6). 1. Convert the coordinates of the point to cylindrical polar coordinates [2 marks] II. Convert the coordinates of the point to spherical polar coordinates [2 marks] III. Hence or otherwise find the distance of the point from the origin [1 mark] Enter your answer below stating your answer to 2 d.p. b) Sketch the surface which is described in cylindrical polar coordinates as 1
The answer based on the cartesian coordinates is (a) (13, 1.1760, 6). , (b) (17.378, 1.1760, 1.1195). , (c) 17.38 (to 2 d.p.). , (d) the surface is a cylinder of radius 1, whose axis is along the z-axis.
Given: A point is represented in 3D Cartesian coordinates as (5, 12, 6)
To convert the coordinates of the point to cylindrical polar coordinates, we can use the following formulas.
r = √(x²+y²)θ
= tan⁻¹(y/x)z
= z
Here, x = 5, y = 12 and z = 6.
So, putting the values in the above formulas:
r = √(5²+12²) = 13θ
= tan⁻¹(12/5) = 1.1760z
= 6
Thus, the cylindrical polar coordinates of the point are (13, 1.1760, 6).
To convert the coordinates of the point to spherical polar coordinates, we can use the following formulas.
r = √(x²+y²+z²)θ
= tan⁻¹(y/x)φ
= tan⁻¹(√(x²+y²)/z)
Here, x = 5, y = 12 and z = 6.
So, putting the values in the above formulas:
r = √(5²+12²+6²)
= 17.378θ = tan⁻¹(12/5)
= 1.1760φ
= tan⁻¹(√(5²+12²)/6)
= 1.1195
Thus, the spherical polar coordinates of the point are (17.378, 1.1760, 1.1195).
The distance of the point from the origin is the value of r, which is 17.378.
Hence, the distance of the point from the origin is 17.38 (to 2 d.p.).
To sketch the surface which is described in cylindrical polar coordinates as 1, we can use the formula:
r = 1
Thus, the surface is a cylinder of radius 1, whose axis is along the z-axis.
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Company A has a risk percentage of 55% and a return of 14%. Company B has a risk percentage of 3% and a return of 14%. Compute the Coefficient of Variation for each company. Which company is riskier? Why?
Company A has a higher risk percentage (55%) compared to Company B (3%).
To compute the Coefficient of Variation (CV) for each company, we need to use the formula:
CV = (Standard Deviation / Mean) * 100
Let's calculate the CV for each company:
For Company A:
Risk Percentage = 55%
Return = 14%
For Company B:
Risk Percentage = 3%
Return = 14%
Since we don't have the standard deviation values for each company, we cannot calculate the exact CV. However, we can still compare the riskiness of the two companies based on the provided information.
The Coefficient of Variation measures the risk relative to the return. A higher CV indicates higher risk relative to the return, while a lower CV indicates lower risk relative to the return.
In this case, Company A has a higher risk percentage (55%) compared to Company B (3%), which suggests that Company A is riskier. However, without the standard deviation values, we cannot make a definitive conclusion about the riskiness based solely on the provided information. The CV would provide a more accurate measure for comparison if we had the standard deviation values for both companies.
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the mean of 3,7,8,10 and x is 6 find x
Answer:
x = 2
Step-by-step explanation:
The mean is
3 + 7 + 8 + 10 + x
------------------------- = 6
5
Multiplying both sides by 5, we get:
3 + 7 + 8 + 10 + x = 30
Then 28 + x = 30, so that x must be 2
x = 2
what's the mass of an apple
In a survey, 400 people were asked to choose one card out of five cards labeled 1 to 5. The results are shown in the table. Compare the theoretical probability and experimental probability of choosing a card with the number 2.
Cards Chosen
Number
1
2
3
4
5
The theoretical probability of choosing a card with the number is
nothing%. The experimental probability of choosing a card with the number is
nothing%. The theoretical probability is
the experimental probability.
(Type integers or decimals.)
Answer:
25
Step-by-step explanation:
the length and width of a rectangle are measured as 52 cm and 35 cm, respectively, with an error in measurement of at most 0.1 cm in each. use differentials to estimate the maximum error in the calculated area of the rectangle.
The maximum error in the calculated area of the rectangle is approximately 8.7 square centimeters.
To estimate the maximum error in the calculated area of the rectangle, we can use differentials. The formula for the area of a rectangle is A = length * width.
Given:
Length (L) = 52 cm (with a maximum error of 0.1 cm)
Width (W) = 35 cm (with a maximum error of 0.1 cm)
We want to find the maximum error in the calculated area (dA) when the length and width have a maximum error of 0.1 cm.
Using differentials, we have:
dA = (∂A/∂L) * dL + (∂A/∂W) * dW
Let's calculate the partial derivatives (∂A/∂L) and (∂A/∂W):
∂A/∂L = W (since the width is constant when differentiating with respect to L)
∂A/∂W = L (since the length is constant when differentiating with respect to W)
Substituting the values:
∂A/∂L = 35 cm
∂A/∂W = 52 cm
Now we can calculate the maximum error in the calculated area (dA) using the given maximum errors in length (dL) and width (dW):
dA = (35 cm * 0.1 cm) + (52 cm * 0.1 cm)
dA = 3.5 cm + 5.2 cm
dA = 8.7 cm
Therefore, the maximum error in the calculated area of the rectangle is approximately 8.7 square centimeters.
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The weights of cars passing over a bridge have a mean of 3,550 pounds and standard deviation of 870 pounds.Assume that the weights of the cars passing over the bridge are normally distributed. What is z-score corresponding to a car that weighs 2800 pounds?
The z-score corresponding to a car that weighs 2800 pounds is approximately -0.86.
We have,
We can find the z-score corresponding to a car that weighs 2800 pounds using the formula:
z = (x - μ) / σ
where x is the weight of the car, μ is the mean weight, and σ is the standard deviation.
Substituting the given values, we get:
z = (2800 - 3550) / 870
z = -0.86
Therefore,
The z-score corresponding to a car that weighs 2800 pounds is approximately -0.86.
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Alexandria has $50 that their parents gave them to go to a soccer game with. The game cost $22 to get in, how much more money can they spend?
I think I understand what you mean. If Alex got $50 and already spent 22 to get into the actual game, then they would have $28 after getting into the actual game.
So $28 dollars.
(Hope that's what you meant.)
What type of transformation can be defined as moving a figure to a new location with no change to the size or shape of the figure?
Translation type of transformation can be defined as moving a figure to a new location with no change to the size or shape of the figure.
Now, According to the question:
Type of Transformation:
There are four types of transformation in geometry, namely translation, reflection, rotation, and dilation. In translation, it slides the figure in any direction while in reflection, it flips the figure over a point or a line. Also, in rotation the figure turns, while in dilation the figure is either enlarged or reduced.
The type of transformation can be defined as moving a figure to a new location, without any change in the figure's size or shape being called translation. In translation, the figure merely slides or moves in the same direction and distance.
Therefore, the answer is Translation.
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Which of the following set of coordinate pairs represent a function?
1. (-5, 3), (-1, 0), (3,-4), (-1,2)
2. (0,-4), (5,3), (-4,3), (3,2)
3. (1,5), (-1, 3), (3, 4), (1, 2)
4. (4, 4), (4, 3), (4, 2), (4, 1)
I'm absolutely certain that the answer is 2. (0,-4), (5,3), (-4,3), (3,2) because in a function, x does not repeat
I hope this helps, love!
Finding the side length of a cube from its Volume in liters A technical machinist is asked to build a cubical steel tank that will hold 275 L of water. Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest 0.001 m. X 5 ?
The smallest possible inside length of the cubical steel tank that can hold 275 liters of water is approximately 0.640 meters.
The side length of the cube is found by converting the volume of water from liters to cubic meters, as the unit of measurement for the side length is meters.
Given that the volume of water is 275 liters, we convert it to cubic meters by dividing it by 1000 (1 cubic meter = 1000 liters):
275 liters / 1000 = 0.275 cubic meters
Since a cube has equal side lengths, we find the side length by taking the cube root of the volume. In this case, we find the cube root of 0.275 cubic meters:
∛(0.275) ≈ 0.640
Rounded to the nearest 0.001 meters, the smallest possible inside length of the tank is approximately 0.640 meters.
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Tyler has two cube-shaped storage spaces in his apartment, one large and one big. the small on is 12 with a exponent of 3. what is the volume for both?
Answer: 19
Step-by-step explanation:
2+1+1+12+3=19
1. In the following diagram, UW bisects XV at Y. Which of the
following statements must be true?
U
(1) The length of UW is twice the length of YW
(2) The length of UY equals the length of YV
(3) Y is the midpoint of UW.
I
(4) Y is the midpoint of XV.
X
Answer:
Statement 4 is correct
Step-by-step explanation:
Here, we want to select which statement is true based on the given diagram;
The statement that must be true is that Y is the midpoint of XV
This is because, by bisection , we mean dividing into 2 equal parts
The line UW has divided the line XV into two equal parts
So this mean that Y is the midpoint of the line XV