describe the three kinds of stellar spectra. what kinds of objects create each kind? what can we learn from each type?

Answer:

It has to do with the polairity of said molelule. If you have vegetable oil, for example, it will not disolve in water because the oil is a non-polar compound, unlike water which is polar. The bond dipoles and differences in electronegetivity in the molecule results in this.

 The charge Q is uniformly distributed throughout the sphere. The correct answer is (B)

When a solid conducting sphere is given a positive charge Q, the charge will distribute itself evenly throughout the surface of the sphere due to the repulsion of like charges. This is known as the "Faraday's ice pail experiment".

According to the principle of electrostatics, the charge on a conductor always resides on its surface and distributes itself in a way that the electric field inside the conductor is zero. Since the charge on a conductor always resides on its surface, it follows that the charge Q in this case must be uniformly distributed throughout the surface of the sphere.

Option (A) is not true because the charge is not concentrated at the center of the sphere. If the charge was concentrated at the center of the sphere, the electric field would not be zero inside the conductor, which contradicts the principle of electrostatics.

Option (C) and (D) are not true because the density of the charge does not change radially outward from the center. If the density decreased or increased radially outward, the electric field inside the conductor would not be zero, which again contradicts the principle of electrostatics.

Option (E) is not true because the charge is distributed throughout the entire volume of the sphere, not just on its surface. A solid conductor has free charges that can move throughout its entire volume, so the charge will distribute itself throughout the entire volume of the sphere until the electric field inside the conductor is zero.

Therefore, the correct answer is (B) it is uniformly distributed throughout the sphere.

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We can use the formula:

P = VI

where P is the power in watts, V is the voltage in volts, and I is the current in amperes.

For a 75-watt lightbulb,

75 = 120 × I

I = 0.625 A

To find out how many bulbs can be used without blowing a 17 A fuse, we divide the maximum current by the current for one bulb:

17 A / 0.625 A = 27.2

Therefore, we can use 27 75-watt lightbulbs without blowing a 17 A fuse.

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We've put together a step-by-step explanation of how people hear—from the moment sound waves arrive to the outer ear, then travel through the middle and inner ear and transform into meaningful signals sent on to the brain. Our brain uses these signals to organize and communicate with the external world.

Taking into account the definition of wavelength, frecuency and propagation speed, the wavelength of a wave with a frequency of 4.3 Hz and a velocity of 24 m/s is 5.581 m.

Wavelength is the distance between two points corresponding to the same phase in two consecutive waves. It is expressed in units of length (m).

Frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

The propagation speed is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.

The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f×λ

In this case, you know:

Replacing in the definition of propagation speed:

24 m/s= 4.3 Hz× λ

Solving:

λ= 24 m/s÷ 4.3 Hz

λ= 5.581 m

In summary, the wavelength of the wave is 5.581 m.

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We have:

vi = initial speed = 4 m/s

vf = final speed = 25 m/s

t= time = 5 s

a = acceleration = ?

Apply:

Replace with the values given:

Answer: 4.2 m/s^2

The Acceleration of the car is 4.2 m/s.

We will use the formula of acceleration.

a = vu - vi / t

Given:

vi = initial speed = 4 m/s

vu = final speed = 25 m/s

t= time = 5 s

a = acceleration = ?

Now, we will put the given values in the formula,

a = vu - vi / t

a = 25 - 4 / 5

a = 21 / 5

a = 4.2 m/s

Therefore, the Acceleration of the car is 4.2 m/s.

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The length of the vector is proportional to the size of the force.

The wheelchair is not accelerating, so the forces on it are balanced.

In a free-body diagram of the wheelchair, force due to gravity points down,  normal force points up, force pushing the wheelchair points forward, friction resisting the motion points backward.

For the force diagram:

Forces are a push or pull agents that causes a change in the state of a body when they are applied to the body.

Unbalanced forces cause acceleration of a body.

In a free-body diagram, the mass (force) on an object is represented by a vector.

The length of the vector is proportional to the size of the force. Suppose you push a wheelchair forward at constant velocity. The wheelchair is not accelerating, so the forces on it are balanced. In a free-body diagram of the wheelchair, the vector for the force due to gravity points down, the vector for the normal force points up, the vector for your force pushing the wheelchair points forward, and the vector for the force of friction resisting the motion points backward.

Considering the picture visual representation of the forces between many interacting objects or the force diagram:

In picture 1: F gravity points down; F normal points up

In picture 2: F gravity points down; F tension points up

In picture 3: F gravity points down; F spring points up.

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Answer:

-30N to the left

Explanation:

Step one:

Given data

the mass of the monkey is 50N

Step two:

Required is the net force acting on the monkey

Now to the right Bunny is applying 95N,

Deer pushes on Monkey Tom Lee

with a 75N the net force acting on the monkey to move it is

= 95-50-75= -30N to the left

the other user said:

Answer:

positive acceleration: releasing an object from a height - acceleration due to the force of gravity, the speed of the object will increase as it falls

negative acceleration: applying breaks on the tires to slow down the car - deceleration due to frictional forces

The branch of science studied by both Albert Einstein and Isaac Newton is physics. Physics is the scientific study of matter, energy, and the interactions between them.

Both Einstein and Newton made significant contributions to our understanding of the physical world and the laws that govern it. Isaac Newton, a physicist and mathematician, is known for formulating the laws of motion and universal gravitation. His work laid the foundation for classical mechanics and revolutionized our understanding of motion and the forces acting on objects.

Albert Einstein, a theoretical physicist, is best known for his theory of relativity, which encompasses both special relativity and general relativity. His theories revolutionized our understanding of space, time, gravity, and the behavior of matter and energy at high speeds and in extreme conditions.

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Complete Sentence : Albert Einstein and Isaac newton studied this branch of science. Name it.

Answer:

4. The choose b. 0.000355

Ans; 3.55× 10-⁴ = 0.000355

5. The choose C. 80600

Ans; 8.06 ×10⁴= 806×10² = 80600

I hope I helped you^_^

Answer:

A Van Allen radiation belt is a zone of energetic charged particles, most of which originate from the solar wind, that are captured by and held around a planet by that planet's magnetosphere. Earth has two such belts, and sometimes others may be temporarily created

The net force on particle q1 to the right is 3.6 x 10⁻⁴ N.

These connections are summarized by Newton's second law of motion. Net Force = Mass Acceleration, or F = m a, can be derived from the following equation for acceleration to solve for net force.

We must get the vector sum of the forces resulting from q2 and q3 in order to determine the net force acting on particle q1:

F_net = F_1,2 + F_1,3

The force between two point charges q1 and q2, which are separated by a distance r, can be calculated using Coulomb's Law as follows:

F = k×(q1 * q2) / r²

Using Coulomb's Law, the force on q1 due to q2 is:

F_1,2 = k * (q1 * q2) / r²

where q1 = 2 x 10⁻⁶ C, q2 = -4 x 10⁻⁶ C, and r = 0.10 m (distance between q1 and q2).

Substituting the values, we get:

F_1,2 = (9.0 x 10⁹ N m² / C²) * (2 x 10⁻⁶ C * -4 x 10⁻⁶₈ C) / (0.10 m)²

F_1,2 = -7.2 x 10⁻⁴ N (repulsive force)

Using Coulomb's Law, the force on q1 due to q3 is:

F_1,3 = k * (q1 * q3) / r²

where q1 = 2 x 10⁻⁶ C, q3 = 3 x 10⁻⁶ C, and r = 0.05 m (distance between q1 and q3).

Substituting the values, we get:

F_1,3 = (9.0 x 10⁹ N m² / C²) * (2 x 10⁻⁶ C * 3 x 10⁻⁶ C) / (0.05 m)²

F_1,3 = 1.08 x 10⁻³ N (attractive force)

the following is the net force acting on particle q1:

F_net = F_1,2 + F_1,3

F_net = (-7.2 x 10⁻⁴ N) + (1.08 x 10⁻³ N)

F_net = 3.6 x 10⁻⁴ N (to the right)

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The weight of traveler on the another planet whose radius is 2 times that of earth and whose mass is 4 times that of earth is found as 102 N.

For the stated question-

W = gMm/ r²

wherein G is a gravitational constant, M is indeed the planet's mass, m is the traveler's mass, and r is the planet's radius.

By finding an expression that is comparable to the traveler's weight on Earth, we may solve for the weight of a traveler on another planet, W'.

W' = GM'm / r'²

    = G (3Me).m/ (4re)²

    = 3/16 GMe. m/ re²

    = 3/16. We

    = 3/16 . 544

W = 102 N

Thus, the weight of the traveler on the another planet whose radius is 2 times that of earth and whose mass is 4 times that of earth is found as 102 N.

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Answer:

answer choice 3.

Explanation:

The movement occurs as . Each orbit has a different energy, and electrons can move to other orbits by emitting or absorbing energy, which is also quantized.

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The effective collecting area of this radio telescope with a sensitivity of 1 \(\frac{K}{Jy}\) is 2761 square meters.

Given the following data:

In Science, the sensitivity of a radio telescope is its sensitivity and it is usually expressed by using a convenient parameter in units of \(\frac{K}{Jy}\).

Mathematically, an antenna temperature produced by an unpolarized point source with respect to flux density is given by this formula:

\(T_A=\frac{SA_e}{2k}\)

Making effective area the subject of formula, we have:

\(A_e=\frac{2kT_A}{S}\)

Substituting the given parameters into the formula, we have;

\(A_e=\frac{2 \times 1.38065 \times 10^{-23} \times 1}{10^{-26}}\\\\A_e= 2761 \;m^2\)

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Answer:

20.4 cm; 2.4 cm  

Explanation:

The formula for the pressure p exerted by a column of a liquid with density ρ and height h is

p = ρgh

where h = the acceleration due to gravity

If you have two liquids balancing each other in a U-tube

     p₁ = p₂

ρ₁gh₁ = ρ₂gh₂

 ρ₁h₁ = ρ₂h₂

Data:

ρ₁ = 1010 kg/m³; h₁ = 18 cm

ρ₂ = 890 kg/m³; h₂ = ?          

1. Height of oil column

We measure from the horizontal red line.

\(\begin{array}{rcl}\rho_{1}h_{1} & = &\rho_{2}h_{2}\\\text{1010 kg/m}^{3} \times \text{18 cm} & = & \text{890 kg/m}^{3} \times h_{2}\\\text{18 180 cm} & = & 890h_{2}\\h_{2} & = & \dfrac{\text{18180 cm}}{890}\\\\ & = & \text{20.4 cm}\\\end{array}\\ \text{The height of the oil column is $\textbf{20.4 cm}$}\)

2. Height of oil above water

h₂ - h₁ = 20.4 cm – 18 cm = 2.4 cm

Answer:2 seconds

Explanation:

g=10m/s2

h=20m

t=h/g

t=20/10

t=2s

Answer:

could you probably expand on the question?

Explanation:

Temperature inversion leads to an increase in temperature as altitude increases.

The term temperature inversion refers to a situation in which a layer of warm air lies over a layer of cool air. This is also referred to as thermal inversion. This occurs when the air below to loose heat rapidly.

One of the effects of temperature inversion is reduction in visibility. So, thermal inversion leads to an increase in temperature as altitude increases.

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The quantization of energy levels and the restrictions on electron transitions in quantum mechanics ensure the stability of atoms. Electrons occupy specific energy levels and are confined to certain orbits around the nucleus, maintaining a balance between the attractive force of the nucleus and the centrifugal force of their motion.

In classical mechanics, atoms are described as miniature solar systems with electrons orbiting around the nucleus.

According to classical electromagnetic theory, an accelerated charged particle emits electromagnetic radiation.

Therefore, in the classical view, orbiting electrons would continuously lose energy and eventually spiral into the nucleus, causing atoms to collapse.

Quantum mechanics, on the other hand, provides a different perspective on the stability of atoms.

It introduces the concept of wave-particle duality, where particles like electrons can exhibit both particle-like and wave-like behavior.

In quantum mechanics, electrons are described by wave functions, which represent the probability distribution of finding the electron in different regions around the nucleus.

The key idea in quantum mechanics is that electrons can only occupy specific energy levels, or quantized states, within the atom. These energy levels are distinct and separated by energy gaps.

Electrons can transition between these energy levels by absorbing or emitting discrete amounts of energy, corresponding to the emission or absorption of photons.

The stability of atoms in quantum mechanics arises from the concept of the ground state.

The ground state is the lowest energy level that an electron can occupy, and it represents the most stable configuration for the atom. In this state, the electron does not emit any radiation and does not spiral into the nucleus.

The quantization of energy levels and the restrictions on electron transitions in quantum mechanics ensure the stability of atoms.

Electrons occupy specific energy levels and are confined to certain orbits around the nucleus, maintaining a balance between the attractive force of the nucleus and the centrifugal force of their motion.

Overall, quantum mechanics resolves the classical problem of instability in atoms by introducing the concept of quantized energy levels, which govern the behavior of electrons and prevent their collapse into the nucleus.

This understanding of atomic stability forms the basis for our modern understanding of the structure of matter and the functioning of atoms in chemical reactions.

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A 1.7 m tall weightlifter holds a 780 n barbell above their head. 1326 J work is being done on the bar .

work done = force * displacement

force = 780 N

displacement  = 1.7 m

work = 780 * 1.7 = 1326 J

1326 J work is being done on the bar

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Answer:

1 2 3 and thats it

Explanation:

The span of the simply supported beam is approximately 17.32 meters.

To determine the span of the simply supported beam, we can use the formula for maximum bending stress in a rectangular section subjected to a uniformly distributed load (UDL):

σ_max = (w * L^2) / (8 * I)

Where:

σ_max is the maximum bending stress

w is the UDL (40 kNm = 40,000 N/m)

L is the span of the beam (unknown)

I is the moment of inertia of the rectangular section

Depth of the rectangular section (d) = 500 mm = 0.5 m

Maximum stress (σ_max) = 120 N/mm² = 120 MPa = 120 * 10^6 N/m²

Moment of inertia (I) = (b * d^3) / 12, where b is the breadth of the section (unknown)

We can rearrange the equation for maximum bending stress to solve for the span L:

L = √((8 * I * σ_max) / w)

Substituting the given values:

L = √((8 * (b * 0.5^3) / 12) * (120 * 10^6) / (40,000))

Simplifying:

L = √((2 * b * 0.5^3 * 3 * 10^6) / (4 * 10^4))

L = √((b * 0.5^3 * 3 * 10^6) / (2 * 10^4))

Squaring both sides:

L^2 = (b * 0.5^3 * 3 * 10^6) / (2 * 10^4)

L^2 = (b * 0.5^3 * 3 * 10^6) / (2 * 10^4)

Simplifying further:

L^2 = (b * 3 * 10^3) / 2

L^2 = (1.5 * b * 10^3)

Assuming a breadth of 200 mm (0.2 m) for the rectangular section, we can substitute this value into the equation:

L^2 = (1.5 * b * 10^3)

L^2 = (1.5 * 0.2 * 10^3)

L^2 = 300

Taking the square root of both sides:

L = √300

L ≈ 17.32 m

Therefore, assuming a breadth of 200 mm for the rectangular section, the span of the simply supported beam is approximately 17.32 meters.

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Elastic energy of rubber straps is converted into the kinetic energy of the capsule which is converted into  gravitational potential energy as capsule.

In accordance with the law of energy conservation, energy is neither created nor destroyed but can be converted from one form to another. This implies that energy is not lost and continues to exist.

The energy conversion that takes place as the 'rider' is strapped in is fired high into the sky by rubber straps is elastic energy of rubber straps is converted into the kinetic energy of the capsule which is converted into  gravitational potential energy as capsule.

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Explanation:

TRUE - Two colliding objects will exert equal forces upon each other. If the objects have different masses, then these equal forces will produce different accelerations. ... FALSE - In any collision, the colliding objects exert equal and opposite forces upon each other as the result of the collision interaction.

Answer:

please help

Explanation:

Answer:

Explanation:

We can use the Pythagorean theorem to find the resultant velocity of the passenger:

Resultant velocity = sqrt((8 m/s)^2 + (4 m/s)^2)

Resultant velocity = sqrt(80) m/s

Resultant velocity ≈ 8.94 m/s

To find the direction of the resultant velocity, we can use trigonometry. The angle between the north direction and the direction of the resultant velocity is given by:

theta = arctan(4/8)

theta = arctan(0.5)

theta ≈ 26.57 degrees

So the passenger's resultant velocity is 8.94 m/s at an angle of approximately 26.57 degrees east of north.

The object would be moving at a speed of 1.9 x 10⁶ m/s if it fell from rest through a distance of 2.0 m on such a star.

The gravitational acceleration is given by the formula:g=GM/r²where G is the gravitational constant, M is the mass of the object, and r is the distance between the centers of the two objects, in this case, the object and the star.The gravitational acceleration on the surface of the neutron star is 8.7 x 10¹² m/s². Therefore, if an object falls from rest through a distance of 2.0 meters, then the final velocity can be determined using the kinematic equation given by:v² = u² + 2aswherev is the final velocityu is the initial velocitya is the acceleration dueto gravitys is the distance fallenSubstituting the known values,v² = 0 + 2(8.7 x 10¹²)(2)v² = 3.5 x 10¹³v = √(3.5 x 10¹³)v = 1.9 x 10⁶ m/s. Therefore, the object would be moving at a speed of 1.9 x 10⁶ m/s if it fell from rest through a distance of 2.0 m on such a star.

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