describe the role of electron-electron repulsion in determining the trend in atomic radius and ionic radius

Answer:

4. A concentration of a trace mineral was found to be 2.53 ppb in an aqueous solution. A. What mass of solution contains 2.53 g of the mineral? (1 point - Knowledge, 2 points - Inquiry, 1 point - Communication) m=? C = 2.53 ppm or 2.53X106 n = Con ܗ B. What volume of solution contains 2.53 g of the mineral? (1 point - Knowledge, 2 points - Inquiry, 1 point - Communication) VE? C: 2,53 ppm ns Cen

Answer:

It is equal to Avogadro's number (NA), namely 6.022 x1023.

Answer:

It is equal to Avogadro's

number (NA), namely 6.022×1023

Shortly after AD 1000, Biruni, an Arabic physician, composed a pharmacology book with the first written description of various drugs and their uses.

This book provided detailed information on the effects and side effects of different medicines, as well as instructions on how to prepare and administer them. Biruni's work laid the foundation for modern pharmacology and greatly contributed to the development of medicine as a science.
Biruni, an Arabic physician, composed a pharmacology book shortly after AD 1000. This book contained the first written description of various medicinal substances, their properties, and their uses in treating diseases. By incorporating detailed information on pharmacology, Biruni's work significantly contributed to the understanding and advancement of medical knowledge during that time period.

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It is believed that the pharmacology book composed by Biruni shortly after AD 1000 contained the first written description of the process of distillation.

This technique involves heating a liquid mixture to vaporize certain compounds, which are then condensed back into a liquid form and collected separately.

Biruni's description of distillation is considered significant because it paved the way for the development of many important chemical processes, such as the production of essential oils, perfumes, and alcoholic beverages.

Additionally, distillation has played a key role in the development of modern chemistry and is still widely used today in a variety of industries, including pharmaceuticals, petroleum refining, and food and beverage production.

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The principle of faunal succession is a key concept in the study of prehistoric life and the age of sedimentary rocks. It is based on the idea that the fossilized remains of different species of animals and plants found in sedimentary rocks can be used to infer the relative age of the rocks and the conditions that existed when they were formed.

The principle of faunal succession states that over time, the species of animals and plants that lived in a particular area changed and evolved. As a result, the fossilized remains of different species found in sedimentary rocks can be used to infer the relative age of the rocks.

This principle is based on the idea that the fossil record is a record of the evolution of life on Earth. In addition, the principle of faunal succession also provides insight into the ancient environment and climate. For example, the presence of certain types of fossils, such as coral reefs or tropical plants, may indicate that the area was once a warm, shallow sea.

In all, the principle of faunal succession is a powerful tool that connects prehistoric life to the age of sedimentary rocks. By studying the fossilized remains of different species found in sedimentary rocks, scientists can infer the relative age of the rocks and the conditions that existed when they were formed.

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The oxidation of a tertiary alcohol will produce a(n) d. no reaction.

Tertiary alcohols cannot be oxidized under normal conditions because they do not have a hydrogen atom attached to the carbon atom that is bonded to the hydroxyl (-OH) group. This means that there is no place for the oxygen atom from the oxidizing agent to attach, and therefore no reaction will occur. In contrast, primary alcohols can be oxidized to aldehydes and then to carboxylic acids, and secondary alcohols can be oxidized to ketones. However, tertiary alcohols cannot undergo oxidation reactions under normal conditions.

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Answer:

Explanation:An age-structure diagram provides a snapshot of the current population and can represent information about the past and give potential clues about future problems. When you are interpreting age-structure diagrams, it is important to compare the width of the base to the rest of the population

The pH of a solution prepared by diluting 3.0 mL of 2.5 M HCl to a final volume of 100 mL with H₂O is 1.12.

Given data :

Original concentration of HCl before dilution (C₁) = 2.5 M

Volume of HCl to be diluted (V₁) = 3.0 mL

Final volume of HCl after diluting (V₂) = 100 mL

Final concentration of HCl after dilution (C₂) = ?

To Calculate the final concentration of solution, equation used is -

                               C₁.V₁ = C₂.V₂

Putting values in equation,

2.5 M x 3.0 mL = C₂ x 100 mL

C₂ = 2.5 M x 3.0 mL

             100 mL

C₂ = 0.075 M

When HCl is diluted with H₂O, it dissociates. The chemical equation of dissociation reaction of HCl is -

                       HCl(aq) ⇄ H⁺(aq) + Cl⁻(aq)

Concentration of HCl = concentration of H⁺ = 0.075 M

Using equation of pH,

                       pH = -log[H⁺]

pH = -log[0.075]

pH = 1.12

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The order of oxidizing strength for the given metal ions can be determined based on their standard reduction potentials (E°) or their tendency to undergo oxidation.

The higher the standard reduction potential, the stronger the oxidizing strength. Here is the order of oxidizing strength from strongest to weakest for the given metal ions:

1. Al3+ (Aluminum ion)

2. Pb2+ (Lead ion)

3. Cu2+ (Copper ion)

4. Sn2+ (Tin ion)

5. Zn2+ (Zinc ion)

6. Mg2+ (Magnesium ion)

7. Ca2+ (Calcium ion)

It's important to note that this order is approximate and can vary depending on the specific conditions and experimental setup. Additionally, other factors such as pH, concentration, and presence of complexing agents can also influence the oxidizing strength.

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The structure that best fits the given data is 1,4-dibromobenzene.

The presence of two methyl singlets in the proton NMR spectrum indicates the presence of two methyl groups in the compound. This suggests the presence of a substituent attached to the benzene ring.

The proton-decoupled 13C NMR spectrum displays six peaks, indicating the presence of six distinct carbon environments. In 1,4-dibromobenzene, there are two carbon atoms attached to the methyl groups, which gives two peaks. The benzene ring itself has four unique carbon environments, each with a different chemical shift, resulting in four additional peaks.

The structure of 1,4-dibromobenzene matches the data because it contains two methyl groups and displays a total of six peaks in the proton-decoupled 13C NMR spectrum, consistent with the given information.

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Answer: If a pinch of mercury is consumed you will die from it so using a mercury thermometer is very unsafe if its breaks and a child consumes that mercury.

Explanation:

Don't use one

If the glass breaks and the mercury is not properly cleaned up, the little silvery ball within a mercury thermometer might be hazardous. As the mercury evaporates, it may pollute the air around and turn dangerous to both people and animals.

Children that have been exposed to mercury have lower IQs, hearing impairments, and worse coordination.

Long-term exposure worsens and exacerbates symptoms, which may lead to personality changes or even coma.

Mercury thermometers can be replaced by a number of things:

These non-mercury fever thermometers are significantly safer and equally accurate as mercury thermometers.

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The sign of ΔH and ΔS can be determined by looking at the direction of the phase change and the molecular behavior of the substance.

a. Sublimation:
ΔH: Positive (endothermic process, energy is absorbed)
ΔS: Positive (increase in entropy, as a solid transitions to a gas)

b. Freezing:
ΔH: Negative (exothermic process, energy is released)
ΔS: Negative (decrease in entropy, as a liquid becomes a solid)

c. Boiling:
ΔH: Positive (endothermic process, energy is absorbed)
ΔS: Positive (increase in entropy, as a liquid transitions to a gas)

d. Deposition:
ΔH: Negative (exothermic process, energy is released)
ΔS: Negative (decrease in entropy, as a gas becomes a solid)

e. Melting:
ΔH: Positive (endothermic process, energy is absorbed)
ΔS: Positive (increase in entropy, as a solid transitions to a liquid)

f. Condensation:
ΔH: Negative (exothermic process, energy is released)
ΔS: Negative (decrease in entropy, as a gas becomes a liquid)

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Answer:

6

Explanation:

if there is 10n and the friction is 4n on the table then it is 6n.

i hope this helps you! :)

The heat of combustion per mol of the glucose is 2840 kJ.

A reaction that involves the burning of a compound in the presence of air or oxygen is called combustion. In the absence of oxygen combustion of a compound cannot take place.

It is given that the combustion of glucose produces carbon dioxide and water. The balanced chemical reaction for the given process is expressed as:

C6H12O6 (s) + 6O2 (g) ------> 6CO2 (g) + 6H2O (l)

The energy released from this reaction is -2840 kJ. The above equation clearly shows that 1 mol of glucose is used during the reaction and the energy produced is -2840 kJ.

Therefore, the heat of combustion per mol of the glucose is 2840 kJ.

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Answer: In this chemical process, we are given a system with a separator that recovers 96% of N2 and H2 for recycling. The concentration of NH3 in the recycle stream is 2%. To complete the material balance, we need to consider the stoichiometry of the reaction, the recovery specifications, and the ratio of recycle to fresh feed. However, without additional information, the overall conversion of N2 to NH3 cannot be determined precisely.

Explanation:

Based on the given recovery specification, 96% of the N2 and H2 fed are recovered. This leads to a recycle-to-fresh-feed ratio of 0.96, indicating that a large portion of the reactants is recycled for further use in the process.

The balanced equation for the reaction is:

N2 + 3H2 -> 2NH3

b. The sketch of the system would typically include the reactor, separator, and recycle stream. However, as a text-based interface, I cannot provide visual sketches.

c. Let's label the streams and enter the given data:

Fresh Feed (FF): Contains N2 and H2 in stoichiometric ratio

Recycle (R): Contains NH3, N2, and H2

Product (P): Contains NH3

- Concentration of NH3 in the recycle stream = 2%

- Recovery of N2 and H2 in the separator = 96%

d. Write down the conversion and recovery specifications as equations:

Conversion of N2 = (moles of N2 consumed) / (moles of N2 fed)

Recovery of N2 = (moles of N2 recovered) / (moles of N2 fed)

Recovery of H2 = (moles of H2 recovered) / (moles of H2 fed)

e. The overall conversion can be calculated as the ratio of moles of NH3 produced to the moles of N2 fed. However, since the conversion is not specified in the given data, we cannot determine it precisely without additional information.

To determine the ratio of recycle to fresh feed, we need to consider the recovery specifications and the stoichiometry of the reaction. Since the recovery of N2 is given as 96%, we can assume that 96% of the N2 fed is recovered and recycled back. The fresh feed contains 100 mol of N2, so the moles of N2 recycled would be 0.96 * 100 mol.

The stoichiometry of the reaction tells us that for every 1 mol of N2, 3 mol of H2 are required. Therefore, the fresh feed would contain 300 mol of H2 to maintain the stoichiometric ratio.

The ratio of recycle to fresh feed can be calculated as:

Ratio = (moles of N2 recycled) / (moles of N2 in fresh feed)

Ratio = (0.96 * 100 mol) / (100 mol)

This simplifies to:

Ratio = 0.96

Therefore, the ratio of recycle to fresh feed is 0.96.

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A. H₂ and N₂ would react produce more NH₃

Given

Reaction

3H₂ + N₂ ⇔ 2NH₃

Required

The effect of removing NH₃

Solution

If the concentration of one component is enlarged, the system reaction is to reduce the component, and vice versa, if the concentration of one component is reduced, the reaction system is to add to the component  

When NH₃ is taken from the system, then

The system will react by increasing the concentration of products by moving to the right ⇒ Shift in the direction of the product

Answer:

A. Hz and N2 would react to produce more NH3.

Explanation:

Answer:

true

Explanation:

because they dies in external area

Answer:

1) 1.6 moles of HCl

Explanation:

1) 1.6 moles of HCl

2) 7.0 moles of HCl

3) 2.4 moles of hydrogen

4) 0.96 moles of HCl

Explanation:

The balanced chemical equation is:

According to stoichiometry :

1 mole of  require = 2 moles of  

0.8 moles of  will require=  of  

3.5 moles of  will require=  of  

According to stoichiometry :

2 moles of  produce = 1 mole of  

4.8 moles of  will require=  of  

According to stoichiometry :

1 mole of  are produced by = 2 moles of  

0.48 moles of  are produced by =  of

Answer:

Element      Symbol Mass percent

Carbon          C            93.7088

Hydrogen  H             6.2912

Answer:

change in composition

a substance decomposing

burning

Explanation:

A chemical change is one in which a new kind of matter is formed. It is always accompanied by energy changes (evolution or absorption of energy in form of heat or light or both).

This process is often irreversible.

Now, processes such as burning and decomposition are chemical changes and are not easily reversible.

Since new kind of matter is formed, there is a change in composition.

Melting is a physical change that is easily reversed.

Other examples of chemical changes are rusting of iron, precipitation and souring of milk.

Answer: 1 change in composition 2 a subtance decomposing 3 burning

Answer:

Las botellas de alcohol vienen en una variedad de tamaños. El estándar es de 750 ml, que también se conoce como "un quinto" porque es 1/5 de galón. Otros tamaños comunes de botellas de alcohol son 50ml, 100ml, 200ml, 375ml, 1L y 1.75L.

Explanation:

Answer: 2400kg/m3

Explanation:  p=m/3   m over 3

                       33.6g/14cm3

                       2.4g/cm3

                       2400kg/m3                        

Answer:

O2 in edge

Explanation:

Answer:

Coffee Filter.

Tea-bags.

Water Filters.

Sand Filtration.

HEPA Air Filters.

Automotive Filters.

Belt Filters.

Dialysis.

Explanation:

Note that the total number of kilojoules required to boil 100 Grams of water at 100°C and 1 atmosphere is 2.26kJ.

The heat of vaporization for water at its boiling point of 100°C is 2260J g-1. This indicates that in order to transform 1 g of water at 100°C to 1 g of steam at 100°C, the water must absorb 2260 J of heat.

Hence, since we are dealing with Kilojoules,

1 Joules = 0.001 Kilojoule; hence,

2260 joules = 2.26kJ

Kilojoules are the units of energy that humans obtain from food and drink (kJ). A calorie is a metric word for energy. Kilojoules and calories are interchangeable terms. A calorie is equal to four kilojoules. Calories may be readily converted to kilojoules and vice versa.

A kiloJoule (kJ) is 1000 Joules, and a megaJoule (MJ) is one million Joules. A related unit is the Watt, which is a power unit. Energy units can be converted to power units by multiplying them by seconds [s], hours [h], or years [yr].

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Answer:

6.82 Mol CO2

Explanation:

The compound that has ionic bonds is KBr (potassium bromide). Therefore the correct option is Option E.

Ionic bonds develop when two atoms with significantly differing electronegativities create a bond in which one atom (the metal) contributes electrons to the other atom (the non-metal). Potassium (K) is a metal in KBr, while bromine (Br) is a nonmetal. The electronegativity of K is low, whereas that of Br is high. When K and Br bond, K contributes its valence electron to Br, resulting in an ionic bond.

The other chemicals listed, on the other hand, have covalent bonding. When atoms with similar electronegativities share electrons in order to produce a more stable electron configuration, covalent bonds occur.

a. H2O has covalent bonds;

b. O2 contains covalent bonds; and

c. Ne is a noble gas that does not create bonds.

d. CO contains covalent bonds.

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The technique used to separate calcium carbonate from a mixture of calcium carbonate and water is called filtration.

This method involves pouring the mixture through a porous substance, such as filter paper, to keep the solid calcium carbonate in place while allowing water to pass through. After being collected and dried, the resultant residue on the filter paper can be used to make pure calcium carbonate.

Decantation and sedimentation are other potential methods. In this method, the mixture is left to remain for a while, during which the calcium carbonate particles gravitationally sink to the bottom. The calcium carbonate sediment can then be removed by carefully pouring out or decanting the clear water at the top.

Keep in mind that the technique used will rely on the unique characteristics of the combination and the desired level of calcium carbonate purity. Depending on the circumstances, other methods may also be utilized, such as evaporation or centrifugation.

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In the reaction between antimony trisulfide (Sb2S3) and iron (Fe), 10.0 g of antimony trisulfide is treated with excess iron to produce iron(II) sulfide (FeS) and antimony (Sb). The mass of iron required to produce all of the antimony is 4.95 g, and the mass of antimony obtained is 7.19 g.

To determine the number of moles of antimony trisulfide (Sb2S3), we divide the given mass (10.0 g) by the molar mass of Sb2S3 (339.6 g/mol), which gives us 0.0295 mol.

Using the stoichiometry of the balanced equation, we can determine the moles of iron required. For every 1 mole of Sb2S3, 3 moles of Fe are needed. Therefore, multiplying the moles of Sb2S3 (0.0295 mol) by the ratio of Fe to Sb2S3 (3 mol Fe/1 mol Sb2S3), we find that 0.0886 mol of iron is required.

To calculate the mass of iron required, we multiply the moles of iron (0.0886 mol) by the molar mass of iron (55.85 g/mol), resulting in 4.95 g of iron.

According to the stoichiometry of the reaction, 1 mole of Sb2S3 produces 2 moles of antimony (Sb). Thus, multiplying the moles of Sb2S3 (0.0295 mol) by the ratio of Sb to Sb2S3 (2 mol Sb/1 mol Sb2S3), we find that 0.059 mol of antimony is produced.

Finally, to determine the mass of antimony obtained, we multiply the moles of antimony (0.059 mol) by the molar mass of antimony (121.75 g/mol), resulting in 7.19 g of antimony.

In the given reaction between antimony trisulfide and iron, 4.95 g of iron is required to produce all of the antimony, and the mass of antimony obtained is 7.19 g. These calculations are based on the stoichiometry of the reaction and the given mass of antimony trisulfide.

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Answer:

i think its A but im not sure. Hope this helps