Describe the gan Sabana ecosystem

Based on the law of conservation of energy, the student is incorrect because energy is converted from other forms, not created.

When a person throws a ball up into the air, and the ball falls back toward Earth, the speed is lowest when the ball leaves the persons hand.

The law of conservation of energy states that energy is neither created nor destroyed but can be transformed from one form to another.

Based on the law of conservation of energy, the student is incorrect because Energy is converted from other forms, not created.

When an object is falling freely under gravity, it's speed is minimum is lowest when the object leaves the persons hand and is maximum just before the object hits the ground.

Therefore, when a person throws a ball up into the air, and the ball falls back toward Earth, the speed is lowest when the ball leaves the persons hand.

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Exactly 149.6J will raise the temperature of 10.0g of a metal from 25.0C. The specific heat capacity of the metal is 5.984 J/g°C.

The heat capacity of a sample of a substance divided by the mass of the sample yields the specific heat capacity (symbol c), also known as massic heat capacity. Informally, it is the quantity of heat that must be added to one unit of a substance's mass in order to raise its temperature by one unit. The specific heat capacity unit in the SI is the joule per kelvin per kilogram, or Jkg⁻¹K⁻¹. For instance, the specific heat capacity of water is 4184 J kg⁻¹K⁻¹, or the amount of energy needed to raise 1 kilogram of water by 1 K.

The specific heat capacity of the metal can be calculated using the equation Q = m × c ×ΔT.

Q = 149.6J

m = 10.0g

ΔT = (final Temperature - initial Temperature) = (25°C - 0°C) = 25°C

Plugging these values into the equation, we get:

149.6J = 10.0g × c ×25°C

Solving for c, we get:

c =  \(\frac{149.6J}{(10.0g *25C)}\)

c = 5.984 J/g°C

Therefore, the specific heat capacity of the metal is 5.984 J/g°C.

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0.25 Molarity of lead nitrate aqueous solution is there when a solution of nacl is added slowly to  a solution of lead nitrate.

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Answer:

Lithosphere

Explanation:

Answer:

ether the crust or lithosphere

Explanation:

Answer:

..............................

The mass of N₂ in the mixture having a total pressure of 784 torr with an H₂ partial pressure of 124 torr is 1.988 g

We'll begin by calculating the partial pressure of N₂. This can be obtained as follow:

Total pressure = 784 torr

Partial pressure of H₂ = 124 torr

Total pressure = Partial pressure of H₂ + Partial pressure of N₂

784 = 124 + Partial pressure of N₂

Collect like terms

Partial pressure of N₂ = 784 – 124

Pressure of N₂ (P) = 660 Torr

Volume (V) = 2 L

Temperature (T) = 298 K

Gas constant (R) = 62.364 L.Torr/Kmol

PV = nRT

660 × 2 = n × 62.364 × 298

1320 = n × 18584.472

Divide both side by 18584.472

n = 1320 / 18584.472

Mole of N₂ = 0.071 mole

Molar mass of N₂ = 2 × 14 = 28 g/mol

Mass = mole × molar mass

Mass of N₂ = 0.071 × 28

Therefore, the mass of N₂ in the mixture having a total pressure of 784 torr with an H₂ partial pressure of 124 torr is 1.988 g

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Answer:

Explanation:

21

Answer:

A. Chemistry.

Explanation:

Answer:

This question is incomplete

Explanation:

Although, the question above is incomplete, however the correct option can be deduced from the explanation below.

Compounds/chemicals that dissolve in water to conduct electricity are Ionic/electrovalent compounds. Ionic compounds/salts are compounds that are held together by ionic/electrovalent bond. These compounds dissociate in water to form ions; the dissociated ions formed are the carriers of electric charges hence enabling the salt solution conduct electricity. Examples of these electrovalent/ionic compounds include NaCl, CaCl₂, CsF and MgO.

NOTE: Identify the ionic/electrovalent compounds in the options (from the completed question) to get your answer.

Answer:

The order of reactivity towards electrophilic susbtitution is shown below:

a. anisole > ethylbenzene>benzene>chlorobenzene>nitrobenzene

b. p-cresol>p-xylene>toluene>benzene

c.Phenol>propylbenzene>benzene>benzoic acid

d.p-chloromethylbenzene>p-methylnitrobenzene> 2-chloro-1-methyl-4-nitrobenzene> 1-methyl-2,4-dinitrobenzene

Explanation:

Electron donating groups favor the electrophilic substitution reactions at ortho and para positions of the benzene ring.

For example: -OH, -OCH3, -NH2, Alkyl groups favor electrophilic aromatic substitution in benzene.

The -I (negative inductive effect) groups, electron-withdrawing groups deactivate the benzene ring towards electrophilic aromatic substitution.

Examples: -NO2, -SO3H, halide groups, Carboxylic acid groups, carbonyl gropus.

Answer:

Between 4s and 3s orbital , 3s has more energy .

Explanation:

According to the rule , the lower the value of (n+l) for an orbital , the lower is it's energy . And if two orbitals have the same value of (n+l), the orbital with lower value of n will have the lower energy .

The statement " for all atoms of the same element the 4s orbital is larger than the 3s orbital" is definitely true.

An element may be defined as a type of substance that significantly cannot be dilapidated into simpler components by any non-nuclear chemical reaction. It is a type of chemical substance that bears unique properties based on numerous attributes.

The 4s orbital is the outermost and highest energy orbital, as compared to the 3s orbital. The 4s orbital penetrates more into the nucleus. This is because the s-orbital has the highest penetrating effect as compared to other orbitals.

The size of the 4s orbital is usually larger than the 3s orbital for all the atoms of the same element. This is because the electrons are filled in these orbitals systematically in the order s, p, d, and f. In the s-orbital first, 1s, 2s, 3s, 4s, and so on depending on the atomic number of the atom or element.

Therefore, the statement " for all atoms of the same element the 4s orbital is larger than the 3s orbital" is definitely true.

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The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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Answer:

Reduction involves a half-reaction in which a chemical species decreases its oxidation number, usually by gaining electrons. The other half of the reaction involves oxidation, in which electrons are lost. Together, reduction and oxidation form redox reactions (reduction-oxidation = redox).

Explanation:

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The covalent bond is present in the compound C₃H₈. The reactant C is 3, product C is 6, reactant H is 8, product H is 10, Reactant O is 2, product O is 9.

What is covalent bond ?

Atoms share electron pair between them in covalent bonds. H-H or C-H are examples of nonpolar covalent bonds between atoms with similar or identical electronegativity, whereas polar covalent bonds are formed when unequal electronegativity is shared between atoms (e.g., H–O).

What is reactant ?

Raw materials known as reactants combine to create products. When the right factors, such as temperature, time, or pressure, come into play, the chemical bonds between the reactants are broken, allowing the atoms to form new bonds that lead to various combinations.

Therefore, covalent bond is present in the compound C₃H₈. The reactant C is 3, product C is 6, reactant H is 8, product H is 10, Reactant O is 2, product O is 9.

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Answer:

b) Li2S(aq)+Pb(NO3)2(aq)

e) K2S(aq)+Sn(NO3)4(aq)

Explanation:

they are the only two of the options that contain a sulfide ion (S) therefore they are the only ones that could be considered in the question.

b) Li2S(aq)+Pb(NO3)2(aq)

e) K2S(aq)+Sn(NO3)4(aq)

Answer:

Explanation:

Let the final temperature be T .

heat lost by iron = mass x specific heat x decrease in temperature

= 25 x .449 x ( 398 - T  )

Heat applied to increase the temperature of water

= 25 x .449 x ( 398- T  )  x .79  [ 21 % is lost ]

= 8.86775 ( 398 - T  )

heat gained by water = 25 x 4.2 x ( T - 298 )

Both of them are equal

8.86775 ( 398 - T  )  = 25 x 4.2 x ( T - 298 )

8.86775 ( 398 - T  )  = 105 x ( T - 298 )

105 T + 8.86775 T = 105 x 298 + 398 x 8.86775

113.86775 T = 31290 + 3529.36

113.86775 T = 34819.36

T = 305.78 K .

After analysing the given options and data we conclude that the matching of the given options  as  

1) Proposed by Nicolaus Copernicus and Aristarchus - heliocentric model
2) Proposed by Aristotle - 3) geocentric model
3) geocentric model - A) Earth at the center of the universe
4) The universe started from a single point - C) Big Bang Theory
5) Proposed by George Lemaitre - C) Big Bang Theory
6) The sun at the center of the universe - 3) geocentric model
7) heliocentric model - 6) The sun at the center of the universe

The Big Bang Theory is a scientific explanation regarding the original creation of the universe. The theory is based on several key assumptions, one of which is the isotropy of the universe. This assumption projects that the universe, more or less, appears the same in all directions of time and space.

Another key theory is that of cosmic inflation, which projects why the universe is so symmetrical on such a significant scale.
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Answer:

Electron domains in the valence shell of an atom will arrange themselves so as to minimize repulsions

Explanation:

In accordance with VSEPR theory, the electron domains or electron pairs on the valence shell of the central atom in a molecule always position themselves as far apart in space as possible in order to minimize repulsions.

Recall that according to VSEPR theory, the shape of a molecule depends on the number of electron pairs or electron domains on the valence shell of the central atom of the molecule, both lone pairs and bond pairs. Lone pairs are known to cause more repulsions than bond pairs.

Answer:

as when we add 60 ml it removes all the protons it means it is 2nd equivalence point of Ascorbic acid

and we know that pH = pKa1 when moles of NaOH is half of the 1st equivalence point

1st equivalence point = 2nd equivalence point / 2 = 60/2 =30ml

1st half equivalence point = 30/2 = 15ml

so when we add 15ml of NaOH

pH = pKa1 =15mL

Answer:

Fire is the result of applying enough heat to a fuel source, when you've got a whole lot of oxygen around. As the atoms in the fuel heat up, they begin to vibrate until they break free of the bonds holding them together and are released as volatile gases. These gases react with oxygen in the surrounding atmosphere.

Explanation:

Answer:

below the surface

Explanation:

In water, a highly soluble sodium hydroxide compound dissociates to give sodium ion and hydroxide ion as an example of an Arrhenius base.

To enhance the concentration of hydroxide ions, NaOH entirely dissolves in aqueous solution to give hydroxide ion and sodium ion. The Arrhenius theory, proposed in 1887 by the Swedish scientist Svante Arrhenius, states that acids dissolve in water to produce electrically charged atoms or molecules known as ions, one of which is a hydrogen ion (H+), and that bases ionize in water to produce hydroxide ions (OH). As a result, water is a material that dissociates in water to create H+ ions. It also meets the definition of a material that dissociates in water to create OH ions.

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The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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The BaBr₂ will dissolve in water and form its ions according to this equation:

BaBr₂ ----> Ba²⁺ + 2 Br⁻

We have to find the molarity of the solution. The molarity of a solution is calculated using this formula:

Molarity = moles of solute / volume of solution in L

We know the volume of solution (2.00 L) and we know the mass of BaBr₂. To find the molarity of the solution we will have to convert those grams into moles. When we have to convert a mass into moles we use the molar mass. Let's start finding the molar mass of BaBr₂.

atomic mass of Ba: 137.33 amu

atomic mass of Br: 79.90 amu

molar mass of BaBr₂ = 137.33 + 2 * 79.90

molar mass of BaBr₂ = 297.13 g/mol

Now we can find the number of moles of BaBr₂ that we have in 2.38 *10^(-4) g of it.

moles of BaBr₂ = 2.38 *10⁻⁴ g / (297.13 g/mol)

moles of BaBr₂ = 8.01 *10⁻⁷ moles

So we prepared a solution dissolving 8.01 * 10⁻⁷ moles of BaBr₂ in 2.00 L of water. Let's find the molarity:

Molarity of BaBr₂ = moles of BaBr₂ / volume of solution in L

Molarity of BaBr₂ = 8.01 * 10⁻⁷ moles/(2.00 L)

Molarity of BaBr₂ = 4.00 * 10⁻⁷ M

We said that the BaBr₂ will dissolve in water according to this equation:

BaBr₂ ----> Ba²⁺ + 2 Br⁻

If we look at the coefficients we see that 1 mol of BaBr₂ will produce 1 mol of Ba²⁺ ions and 2 moles of Br⁻ ions.

So we can say that:

moles of Ba²⁺ = moles of BaBr₂

moles of Ba²⁺ = 8.01 * 10⁻⁷ moles

moles of Br⁻ = 2 * moles of BaBr₂

moles of Br⁻ = 2 * 8.01 * 10⁻⁷ moles

moles of Br⁻ = 1.60 * 10⁻⁶ moles

Now we can find the molarity of each ion:

Molarity of Ba²⁺ = moles of Ba²⁺ / volume of solution in L

Molarity of Ba²⁺ = 8.01 * 10⁻⁷ moles/(2.00 L)

Molarity of Ba²⁺ = 4.00 * 10⁻⁷ M

Molarity of Br⁻ = moles of Br⁻ / volume of solution in L

Molarity of Br⁻ = 1.60 * 10⁻⁶ moles / (2.00 L)

Molarity of Br⁻ = 8.00 * 10⁻⁷ M

Answer: The concentration of BaBr₂ and the concentration of Ba²⁺ is 4.00 * 10⁻⁷ M. The concentration of Br⁻ is 8.00 * 10⁻⁷ M.

When we express the concentration in ppm we want the concentration in mg/L. We have the concentration in M (moles/L), so to find the concentration in ppm we have to convert moles to mg.

The molar masses of the ions are:

molar mass of Ba²⁺ = 137.33 g/mol

molar mass of Br⁻ = 79.90 g/mol

Let's use them to find the concentration in ppm.

concentration of Ba²⁺ = 4.00 * 10⁻⁷ M = 4.00 * 10⁻⁷ moles/L * 137.33 g/mol

concentration of Ba²⁺ = 5.49 * 10⁻⁵ g/L *1000 mg/g

concentration of Ba²⁺ = 0.0549 mg/L = 0.0549 ppm

concentration of Ba²⁺ = 0.0549 ppm

concentration of Br⁻ = 8.00 * 10⁻⁷ M = 8.00 * 10⁻⁷ moles/L * 79.90 g/mol

concentration of Br⁻ = 6.39 * 10⁻⁵ g/L * 1000 mg/g

concentration of Br⁻ = 0.0639 mg/L = 0.0639 ppm

concentration of Br⁻ = 0.0639 ppm

Answer: the concentration of the ion Ba²⁺ is 0.0549 ppm and the concentration of the ion Br⁻ is 0.0639 ppm.

Balance the half-reactions to guarantee that the number of electrons transferred in both reactions is the same:

NO3- + 8H+ + 10e- N2 + 4H2O H2 2H+ + 2e- NO3- + 8H+ + 10e-

The next step is to figure out how many electrons are moved when 145 molecules of H2 are oxidized. We can see from the balanced equation for the H2 half-reaction that 1 molecule of H2 makes 2 electrons:

2H+ + 2e- → H2

As a result, 145 molecules of H2 will yield:

145 molecular units H2 has two protons per molecule. 290 electrons Equals H2

Finally, we can use the denitrification reaction balanced equation to calculate how many molecules of N2 are created for 290 electrons:

1 molecule of N2 is produced by 10 electrons.

Therefore, 1 molecule N2 290 electrons/10 electrons = 29 molecules N2

29 molecules of N2 gas will be created.

To answer the second query, we must balance the half-reactions:

SO42- + 8H+ + 8e- H2S + 4H2O CO2 + 8H+ + 8e- CH3COO- + 2H2O SO42- + 8H+ + 8e- H2S + 4H2O

The balanced formulae show that 8 electrons are transferred in both half-reactions. As a result, in order to oxidize 48 molecules of CH3COO-, 6 molecules of SO42- must be reduced:

There are 48 nuclei CH3COO- 8 electrons per atom 384 protons = CH3CO-

384 electrons (eight electrons per atom) 48 units of SO42- SO42-

As a result, 48 molecules of CH3COO- reduced to CO2 will yield:

six electrons 4 H2O/molecule SO42- 24 units of SO42- H2O

The answer is that 24 molecules of water will be created.

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No rock candy will be formed, as the solution is already at its maximum saturation point at 20°C.

We can calculate the maximum amount of sucrose that can be dissolved in 1000.0 g of water at this temperature as follows:

The maximum amount of sucrose that can be dissolved = \((230.9 g/100 mL) * (1000.0 mL/1000.0 g) = 2.309 g/g\)

This means that the maximum mass of sucrose that can be dissolved in 1000.0 g of water at 20°C is 2.309 g.

Mass of rock candy = Initial mass of sucrose - Mass of sucrose in solution at 20°C

Therefore, the mass of rock candy that will be formed is:

Mass of rock candy = Initial mass of sucrose - Mass of sucrose in solution at 20°C

\(= 2.309 g - 2.309 g/g * 1.000 kg \\= 0.0 g\)

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