By carefully following these steps and recording the necessary measurements, you can estimate the magnetic force due to the external uniform magnetic field using magnets and a scale.
To measure the magnetic force due to an external uniform magnetic field using magnets and a scale, you can perform the following experiment:
Materials needed:
1. Two magnets (with known magnetic field strengths)
2. A scale (preferably a sensitive one)
3. Non-magnetic support or stand
4. String or thread
5. Ruler or measuring tape
Procedure:
1. Set up the experiment by attaching one of the magnets to a non-magnetic support or stand so that it is suspended freely.
2. Tie a string or thread to the magnet in such a way that it hangs vertically down.
3. Place the scale underneath the magnet, making sure it is directly below the magnet's center of gravity.
4. Record the initial position of the magnet on the scale.
5. Bring the other magnet, which has a known magnetic field strength, close to the suspended magnet.
6. Gradually increase the distance between the two magnets while observing any movement of the suspended magnet.
7. Take note of the position of the magnet on the scale when it reaches equilibrium (where the magnetic force and gravitational force balance out).
8. Measure the distance between the magnets using a ruler or measuring tape.
9. Repeat the experiment several times with different distances between the magnets, ensuring that the magnets and the scale are in the same orientation each time.
10. Calculate the magnetic force between the magnets using the equation for the magnetic force between two magnets, which is given by the product of their magnetic field strengths divided by the square of the distance between them.
11. Plot a graph of the magnetic force against the distance between the magnets.
12. Using the graph, extrapolate the magnetic force for a distance of 0 (when the magnets are in direct contact) to determine the magnetic force due to the external uniform magnetic field.
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The nucleus of an atom is
charged.
Positively
Liquid
Variably
Negatively
A stonecutter's chisel has an edge area of 1.0 cm 2 . if the chisel is struck with a force of 50 n, what is the pressure exerted on the stone?
The pressure exerted on the stone by the stonecutter's chisel can be calculated using the formula:
Pressure = Force / Area
In this case, the force applied to the chisel is 50 N and the edge area of the chisel is 1.0 cm^2. However, it is important to convert the area to square meters to ensure consistent units.
To convert the area from cm^2 to m^2, we need to divide it by 10,000 since there are 10,000 square centimeters in a square meter. So, the area in square meters would be 1.0 cm^2 / 10,000 = 0.0001 m^2.
Now we can calculate the pressure:
Pressure = 50 N / 0.0001 m^2
Pressure = 500,000 N/m^2
Therefore, the pressure exerted on the stone by the chisel is 500,000 N/m^2.
It is worth noting that this is a relatively high pressure value. Pressure is a measure of the force applied over a given area, and in this case, the small area of the chisel's edge results in a high pressure on the stone when struck with a force of 50 N. This high pressure allows the chisel to effectively cut through the stone.
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The pressure exerted on the stone by the chisel is 500,000 pascals.
Explanation :
The pressure exerted on the stone can be calculated by dividing the force applied by the area over which the force is distributed. In this case, the force applied is 50 N and the edge area of the chisel is 1.0 cm^2.
To find the pressure, we need to convert the area to square meters since the SI unit for pressure is pascals (Pa), which is equivalent to N/m^2.
1 cm^2 is equal to 0.0001 m^2.
Now, we can calculate the pressure by dividing the force by the area:
Pressure = Force / Area
Pressure = 50 N / 0.0001 m^2
Pressure = 500,000 N/m^2 or 500,000 Pa
In summary, when a force of 50 N is applied to a stonecutter's chisel with an edge area of 1.0 cm^2, the pressure exerted on the stone is 500,000 pascals.
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Please help asdfghjkll=
Answer:
Oh god
i have nooooo idea
Suppose a 1,500 kg speedboat is traveling with a velocity of 13 m/s. what is the speedboat’s momentum? 115 kg • meters per second 1,513 kg • meters per second 19,500 kg • meters per second
The speedboat momentum is 19,500 kg.m/s.
We need to know about momentum to solve this problem. Momentum can be defined as the degree of difficulty to stop a moving object. It can be determined by
P = m . v
where P is momentum (kgm/s), m is mass (kg) and v is velocity (m/s).
From the question above, we know that:
m = 1500 kg
v = 13 m / s
By substituting the given parameters, we can calculate the momentum
P = m . v
P = 1500 . 13
P = 19,500 kg . m / s
Hence, the speedboat momentum is 19,500 kg.m/s.
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Answer:19,500 kg
Explanation:your welcome!:)
What is the average velocity of an object that moves from 7.3 cm to 4.1 cm relative to the origin in 2.5 s
PLEASE HELP ME I DONT WANT TO FAIL
Answer:1 7/25
Explanation:take the total distance7.3-4.1 then divide by the total time taken
The average velocity of the object is equal to -1.28m/s relative to the origin when it moves for 2.4 seconds.
What is average velocity?Average velocity is a vector quantity and is defined as the change in position (∆x) divided by the time intervals (∆t) in which it occurs. The average velocity can be positive or negative and the S.I. unit of average velocity is m/s.
The average velocity of an object = ∆x/∆t
The average velocity of an object involves only the displacement of the object. However, the magnitude of the displacement of an object can be different from the actual path length.
Given, the displacement of the object = final position - initial position
∆x = 4.1 - 7.3 = -3.2m
The time, ∆t = 2.5 - 0 = 2.5 s
The average velocity of the object = ∆x/∆t = -3.2/2.5 = -1.28 m/s
Therefore, the average velocity of the object is -1/28 m/s relative to origin.
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Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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as light moves from air (n 1.00) to amber, it deviates 18 degrees from its 45 degrees angle of incidence. what is the speed of light in amber? express your answer as a fraction of the speed of light, c: for example, 1.50 x 108 m/s
Fraction of the speed of light v = 1.93*108 m/s.
Using the given information,
Angle of refraction, = Angle of incidence - deviation = 45 - 18 = 27
Using snell's law for refractive index of amber
\(nairSin\thetaair = namberSin\thetaamber\)
1*SIn45o = nSin27o
n = 1.56
Now , Find the speed,
velocity = c/n where c = 3*108 m/s. speed of light
velocity = 3* \(10^{8}\) /1.56
v = 1.93* \(10^{8}\) m/s.
In several branches of physics, the speed of light in a vacuum, typically abbreviated as c, plays a crucial role. Exactly 299,792,458 meters per second is the speed of light, or c. (approximately 300,000 kilometres per second; 186,000 miles per second; 671 million miles per hour). The speed at which common matter or energy (and hence any signal conveying information) may move across space is limited by the special theory of relativity, and this speed is given by the constant c.
The speed of light is the same for all types of electromagnetic radiation, including visible light. Light and other electromagnetic waves appear to propagate instantly for many purposes in practice, but their limited speed has dramatic consequences over large distances and for experiments requiring high sensitivity. saw the stars
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a ground-based telescope to observe x-rays would group of answer choices a. give astronomers the chance to study the insides of stars and planets. b. be worthless because no astronomical objects emit x-rays. c. be worthless because x-rays cannot pass through the earth's atmosphere. d. be worthless because astronomers have not yet devised detectors for x-rays.
A ground-based telescope to observe x-rays would: option(C)- be worthless because x-rays cannot pass through the earth's atmosphere.
X-rays are high-energy electromagnetic radiation with a wavelength of approximately 10 to 0.01 nanometers. They are produced by accelerating electrons with extreme energy, such as those produced by nuclear reactions or in the case of the sun or other stars.
X-rays cannot pass through the earth's atmosphere, unlike visible light or radio waves. They are usually absorbed by the atmosphere's molecules, making it difficult to examine the universe in the x-ray region of the spectrum from the ground. Therefore, ground-based telescopes for observing x-rays are worthless due to the fact that they cannot pass through the earth's atmosphere.
However, X-ray telescopes in space, such as the Chandra X-ray Observatory, are specifically designed to detect X-rays. These space telescopes are equipped with detectors that are sensitive to X-rays and are orbiting outside of Earth's atmosphere where X-rays can pass without interference.
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PLEASE HELP ME
A/An _____ is a material in which charges will not move easily, whereas a/an _____ is a material that allows charges to move about easily. Question 3 options: conductor, insulator insulator, conductor electroscope, conductor insulator, electroscope
Answer:
The answer is Insulator, Conductor
Explanation:
A/An Insulator is a material in which charges will not move easily, whereas a/an Conductor is a material that allows charges to move about easily
what has to increase in order for an object to accelerate?
Answer:
Answer: B. Explanation: For an object to accelerate the force on it must be increased. According to Newton's second law of motion.
Explanation:
I do Accelerate to good luck
Suppose a mass of 0.500 kg falls from 3050m. What potential energy is associated with the coin when its speed is 30.0 m/s?
Answer:
14945 J
Explanation:
Glad you asked this question!
The speed is irrelevant in this question. It perhaps was put out to throw you off.
P.E = mgh = (0.5 * 9.8 * 3050) = 14945 Joules
a window-mounted air conditioner removes 3.5 kj from the inside of a home using 1.75 kj work input. how much energy is released outside and what is its coefficient of performance?
The amount of heat released outside is 3.5 kJ and the coefficient of performance is 2.
What is efficiency of a machine?The efficiency of the a machine or any device is the measure of effectiveness of the device. Efficiency describes how a machine converts input energy to output energy without wasting much of the input energy.
Mathematically, efficiency of a machine is given as;
E = output energy / input energy x 100%
The coefficient of performance (COP) of a heat pump, refrigerator or air conditioning system is a ratio of useful heating or cooling provided to work required.
The energy released outside = 3.5 kJ
COP = 3.5 kJ / 1.75 kJ
COP = 2
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Consider the measurement 6.5 Newtons. This picture shows the measure of the ____________________ or the ________________ of the object. A) size; mass B) volume; weight C) force of gravity; mass D) force of gravity; weight
Answer:
force of gravity; weight
Explanation:
Weight is the force of gravity on an object and it is measured in Newtons. On this spring scale, each line equals one Newton.
For this experiment, the x-coordinate of the cart is defined as Group of answer choices the length of the cart. the location of the end of the cart furthest from the motion sensor read from a tape measure attached to the track. the distance the cart moves in one second. the location of the end of the cart closest to the motion sensor read from a tape measure attached to the track. all of these.
The x-coordinate of the cart is defined as the location of the end of the cart closest to the motion sensor read from a tape measure attached to the track. In this experiment, the distance the cart moves in one second is also considered as the x-coordinate.
Therefore, the direct answer is: the x-coordinate of the cart is defined as all of these - the length of the cart, the location of the end of the cart furthest from the motion sensor read from a tape measure attached to the track, and the distance the cart moves in one second. The x-coordinate of the cart in this experiment is determined by multiple factors. It includes the length of the cart, the position of the end of the cart farthest from the motion sensor measured by a tape measure, and the distance the cart moves within a one-second interval. All of these elements contribute to defining the x-coordinate of the cart.
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A car's horn produces a constant frequency of 350 Hz as it passes by Suzy. What is the best estimate of the
frequency Suzy hears after the car passes her?
330 Hz
350 Hz
360 Hz
700 Hz
Answer:
330 Hz
Explanation:
edg2020
The best estimate of the frequency Suzy hears after the car passes her is govern by doppler effect and it is 330 Hz.
What is frequency?Frequency is the number of occurrences of a repeating event per unit of time.
What is Doppler EFFECT?
The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source.
According to the Doppler Effect, the frequency observed by an observer decreases for source going away.
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d What should be done to make a simple machine more efficient?
Answer:
the main cause of decreasingthe efficient of simple machine is the effect of friction so, indoder to increase efficiency of a simple machine we should remove the friction using lubricants, decreasing the overload in machine,replacing sliding friction with rolling friction etc,
we should do thses all to increase efficiency of a simple machine.
hope u get it..
1. Which of the following statements is false? A) During a reaction, electrons move from an electrophile to a nucleophile B) Homolytic bond cleavage yields neutral radicals in which each atom gains on
The false statement is B) Homolytic bond cleavage yields neutral radicals in which each atom gains one electron.
In homolytic bond cleavage, each atom retains one electron from the shared pair of electrons, resulting in the formation of two neutral radicals, where each atom retains its original number of electrons.
No atoms gain or lose electrons in this process.
In a homolytic bond cleavage, a covalent bond is broken, and the shared pair of electrons is split equally between the two atoms involved in the bond.
This results in the formation of two neutral radicals, with each atom retaining one of the electrons from the shared pair.
A radical is a chemical species characterized by the presence of an electron that is unpaired, meaning it does not have a partner electron with which it forms a complete pair. When a covalent bond is homolytically cleaved, each atom involved in the bond gains one electron, resulting in the formation of two radicals.
These radicals are highly reactive due to the presence of the unpaired electron, which makes them prone to participate in further chemical reactions.
It's important to note that in homolytic bond cleavage, there is no transfer of electrons from one atom to another.
Instead, the bond is broken in a way that allows each atom to retain one of the electrons, leading to the formation of two neutral radicals.
Therefore, statement B, which suggests that each atom gains one electron, is false.
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True or false, galaxies look the same whether viewed in visible or x-ray wavelengths.
False.
Galaxies do not look the same when viewed in visible or X-ray wavelengths. The electromagnetic spectrum consists of various wavelengths, including visible light and X-rays, each carrying different types of information about celestial objects.
When observing galaxies in visible light, we primarily see the light emitted by stars within the galaxies. This provides information about the distribution of stars, their colors, and the overall structure of the galaxy. Visible light observations are commonly used to study the morphology and stellar populations of galaxies.
On the other hand, X-ray observations reveal a different aspect of galaxies. X-rays are produced by extremely energetic processes, such as accretion onto black holes, supernova remnants, and hot gas in galaxy clusters. By observing galaxies in X-ray wavelengths, we can study active galactic nuclei, high-energy phenomena, and hot gas properties within galaxies and galaxy clusters.
Visible light observations provide insights into the stellar content and structure of galaxies, while X-ray observations give us information about the energetic processes and hot gas within galaxies. Therefore, galaxies can appear different when viewed in visible or X-ray wavelengths.
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Chet plans an experimental investigation to see how well a new fertilizer works on daisies. The fertilizer must be dissolved in water and delivered to the plants by spraying it onto the leaves and stems.
To set up his control group for the experiment, Chet should leave out what
Answer:
The answer is D or Fertilizer, sorry for the late answer
Explanation:
Answer:
D Fertilizer hope this helps ..
Explanation:
Use the position function s(t) = -4.9²2+1 meters to find the velocity at time t = 3 seconds.
O -44.1 m/sec
O-43.1 m/sec
O-29.4 m/sec
O-28.4 m/sec
The velocity function v(t) is given by`v(t) = -9.8t`. To find the velocity at time `t=3 seconds`, we substitute `t=3` into the velocity function `v(3) = -9.8 * 3` `= -29.4 meters/second`
Thus, the velocity at time `t=3 seconds` is `-29.4 m/sec`.
Given position function s(t) = -4.9t²+1 meters
We have to find the velocity at time t = 3 seconds.
Step 1: Differentiate the position function to get velocity function. Differentiating the position function with respect to time t, we get;
`v(t) = s'(t) = d/dt[-4.9t²+1]`
Differentiating `(-4.9t²)` with respect to time t, we get `-9.8t`
Therefore, the velocity function v(t) is given by`v(t) = -9.8t`
Step 2: Put `t = 3` in the velocity function `v(t) = -9.8t` to get the velocity at time t = 3 seconds.v(3) = -9.8 x 3= -29.4 meters/second
Therefore, the velocity at time t = 3 seconds is `-29.4 m/sec`.
Hence, option (C) is the correct answer.
More Detailed Explanation: The velocity of an object is the rate at which an object changes its position in a given time. Velocity can be expressed as the change in position over time, so we can use the position formula to calculate the velocity at a given moment.
The given position function is `s(t) = -4.9t²+1 meters`
We are to find the velocity at time t = 3 seconds. We will use the formula for velocity as follows:`v(t) = s'(t)`Where `s'(t)` is the derivative of the position function with respect to t.
Differentiating the position function s(t) with respect to t, we get the velocity function v(t)`v(t) = s'(t) = d/dt[-4.9t²+1]`
We can apply the power rule for derivatives to `s'(t)`, which is given by:`d/dx(x^n) = n*x^(n-1)
`Differentiating `(-4.9t²)` with respect to time t, we get`d/dt[-4.9t²] = -9.8t`
Therefore, the velocity function v(t) is given by`v(t) = -9.8t
`To find the velocity at time `t=3 seconds`, we substitute `t=3` into the velocity function`v(3) = -9.8 * 3` `= -29.4 meters/second`
Thus, the velocity at time `t=3 seconds` is `-29.4 m/sec`.
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A car goes into a skid and comes to a gradual stop, accelerating at a constant rate to do so. At the midpoint of the skid, how much of its kinetic energy has the car lost (as a percentage, give % as the units)?
The percentage of the lost kinetic energy of the car, at the midpoint of the skid, is 50%.
In physics, work is the measurement of the energy used to move objects. When you are walking, you're using energy to move your body so the work done would be greater than zero.
According to work-energy theorem, work is equal to force times displacement (W = F · x).
A type of energy is kinetic energy, which is the energy of a moving object. If an object is at rest, its kinetic energy is zero. Kinetic energy is equal to one half of a mass times velocity squared (KE = 0.5 · m · v²).
When a car goes into a skid and comes to a gradual stop, at the midpoint of the skid the car has spend 50% its kinetic energy. This is simply because the velocity of the car at the midpoint of the skid is half the velocity of the car when the car starts going into a skid, assuming constant acceleration.
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if the motorcyclist applies the front brake too hard, the
If the motorcyclist applies the front brake too hard, the front wheel may lock and the motorcycle may flip over, causing a dangerous situation.
When a motorcyclist applies the front brake too hard, the front wheel may lock up due to a loss of traction, causing the motorcycle to flip over and resulting in a hazardous scenario. This is known as a front wheel lockup, and it can occur if the motorcyclist is going too fast or if there is insufficient weight on the front wheel
When the front wheel of a motorcycle stops spinning abruptly and the motorcycle flips forward, it is known as a front wheel lockup. This occurs because the motorcyclist applies the front brake too hard, causing the front wheel to lose traction and lock up. When a motorcyclist applies the front brake too hard, the motorcycle's weight shifts forward and places more weight on the front wheel, causing it to lose traction and lock up.
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When you lift a book from the ground to your desk, what kind of work do you do, negative or positive? By lifting the book, what do you change? Does the book gain or lose energy? What kind of energy?
Answer: You do negative work, since you're using your strength. When lifting the book, your muscles contract. When you lift the book, it gains energy.
Energy: Gravitational Potential Energy
Explanation:
Answer:
When you lift a book from the ground to your desk it would be called potential energy. If a book weighs 15 Newtons (N) then it takes a force of 15 Newtons (N) to pick it up. In other words it would be positive work. When you move the book you are giving it energy. The energy will turn into kinetic if you put the book back down. You would be changing it’s position and it’s energy.
The desired overall magnification of a compound microscope is
138✕. The objective alone produces a lateral magnification of
12.0✕. Determine the required focal length of the eyepiece.
The required focal length of the eyepiece is 126 times the focal length of the objective.
To determine the required focal length of the eyepiece in a compound microscope, we can use the formula for the overall magnification of a compound microscope:
Overall Magnification = Objective Magnification × Eyepiece Magnification
Given that the overall magnification is 138x and the objective magnification is 12x, we can substitute these values into the formula:
138x = 12x × Eyepiece Magnification
To solve for the eyepiece magnification, we divide both sides of the equation by 12x:
Eyepiece Magnification = 138x / 12x
Eyepiece Magnification = 11.5
The eyepiece magnification is 11.5x.
Now, to determine the required focal length of the eyepiece, we can use the formula for magnification in a simple microscope:
Magnification = 1 + (Focal Length of the Eyepiece / Focal Length of the Objective)
Given that the objective magnification is 12x and the eyepiece magnification is 11.5x, we can substitute these values into the formula and solve for the focal length of the eyepiece:
11.5x = 1 + (Focal Length of the Eyepiece / 12x)
11.5x - 1 = Focal Length of the Eyepiece / 12x
(11.5x - 1) × 12x = Focal Length of the Eyepiece
138x - 12x = Focal Length of the Eyepiece
126x = Focal Length of the Eyepiece
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A satellite is in circular orbit around a planet with a known radius. What information do you need to calculate the speed of the spacecraft? (check all that apply)
To calculate the speed of a satellite in circular orbit around a planet with a known radius is the radius of the planet and the mass of the planet.
What data is required to determine satellite speed around a planet?The speed of a satellite in a circular orbit is determined by the gravitational pull of the planet it orbits. In this case, the radius of the planet is essential because it helps determine the distance between the satellite and the planet's center.
The mass of the planet is also crucial because it affects the strength of the gravitational force acting on the satellite. By combining these two pieces of information, you can calculate the speed of the satellite using the formula for centripetal acceleration, which relates the gravitational force to the satellite's speed and the radius of its orbit.
Calculating the speed of a satellite requires understanding the principles of gravitational force and circular motion. In a circular orbit, the gravitational force acting on the satellite provides the centripetal force needed to keep it moving in a curved path.
The magnitude of the centripetal force is determined by the mass of the planet and the distance between the satellite and the planet's center, which is equivalent to the sum of the planet's radius and the satellite's altitude above the planet's surface.
Using Newton's law of universal gravitation, which states that the gravitational force is proportional to the product of the masses and inversely proportional to the square of the distance between them, you can derive the formula for the speed of the satellite.
By equating the gravitational force to the centripetal force and solving for the satellite's speed, you can express it in terms of the radius of the planet and the mass of the planet.
This calculation assumes a circular orbit, neglecting any atmospheric drag or other external forces acting on the satellite. It also assumes that the mass of the satellite is insignificant compared to the mass of the planet.
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briefly explain distribution of charges on conductors
Answer:
The distribution of charge is the result of electron movement. Since conductors allow for electrons to be transported from particle to particle, a charged object will always distribute its charge until the overall repulsive forces between excess electrons is minimized.
Answer:
This is simply the movement and transportation of electrons
a disk, with radius 0.25 m and mass 4 kg, lies flat on a smooth horizontal tabletop. a string wound about the disk is pulled with a force of 8n. what is the angular acceleration of the disk?
A disk, with radius 0.25 m and mass 4 kg, lies flat on a smooth horizontal tabletop. A string wound about the disk is pulled with a force of 8n. The angular acceleration of the disk is 4 rad/s².
The angular acceleration of a disk can be determined using Newton's second law for rotational motion, which states that the torque acting on an object is equal to its moment of inertia multiplied by its angular acceleration.
In this case, the torque (τ) is caused by the force (F) acting on the string, and the moment of inertia (I) of the disk is given by the formula I = (1/2)MR², where M is the mass and R is the radius of the disk.
Given the values:
- Radius (R) = 0.25 m
- Mass (M) = 4 kg
- Force (F) = 8 N
First, calculate the moment of inertia (I):
I = (1/2) * 4 kg * (0.25 m)² = 0.5 kg m²
Next, determine the torque (τ) caused by the force (F):
τ = F * R = 8 N * 0.25 m = 2 N m
Now, use Newton's second law for rotational motion to find the angular acceleration (α):
τ = I * α => α = τ / I = 2 N m / 0.5 kg m² = 4 rad/s²
So, the angular acceleration of the disk is 4 rad/s².
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Assume two waves of light in air, of wavelength 681 nm, are initially in phase. One travels through a glass layer of index of refraction n1 = 1.58 and thickness L. The other travels through an equally thick plastic layer of index of refraction n2 = 1.38. What is the smallest value L in meters should have if the waves are to end up with a phase difference of 6.42 rad?
To end up with a phase difference of 6.42 rad, the smallest value L in meters should be 7.69×10⁻⁷ m.
Waves are characterized by the wavelength, frequency, and amplitude. Waves can be classified as longitudinal waves and transverse waves. Sound waves and seismic waves are examples of longitudinal waves.
Transverse waves are exemplified by electromagnetic waves.Let's solve the question given above. The smallest value L in meters should have if the waves are to end up with a phase difference of 6.42 rad.
Wavelength of light in air, λ = 681 nm = 681×10⁻⁹ mIndex of refraction of glass layer, n1 = 1.58 Index of refraction of plastic layer, n2 = 1.38
For the given condition, the phase difference between the two waves can be calculated using the formula:Phase difference = 2πΔx/λ
Here, Δx = (n1 - n2)LThe phase difference should be 6.42 rad.6.42 = 2π(n1 - n2)L/λ
On substituting the given values, we have6.42 = 2π(1.58 - 1.38)L/681×10⁻⁹
Multiplying and rearranging givesL = 7.69×10⁻⁷ mHence, the smallest value L in meters should have if the waves are to end up with a phase difference of 6.42 rad is 7.69×10⁻⁷ m.
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define from which of Earth's systems are mineral resources obtained?
Sources of mineral resources are most commonly magma, sediments, or hydrothermal fluids.
Examples of mineral resources are iron, diamond, gold, silver, copper, aluminum, granite, marble, clay, salt, rare earths or fossil fuels.
What are mineral resources?
A mineral resource is a concentration of natural solid inorganic or fossilized organic matter, including metals, coal and minerals, in sufficient quantity and quality to have reasonable prospects for economic exploitation. This definition has a broader scope than mineral reserves that are likely to be economically recovered based on consideration of technical, economic, and legal concerns.
Mineral resources means minerals, naturally occurring solid inorganic substances, or naturally occurring solid fossilized organic substances (including base metals, precious metals, coal and industrial minerals), in or on the earth's crust, such Means concentrated or occurring in form and quantity and in its grade or quality. There are reasonable prospects for economic development. The location, quantity, grade, geological features and continuity of Mineral Resources are known, estimated or interpreted on the basis of specific geological evidence and knowledge.
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please answer the question
Answer:
A safest device
Explanation:
it's meant to operate safe and provide over current protection of an electrical circuit