Define & explain tacticity (atactic, isotactic, and syndiotactic)

The acceleration of the object is approximately 2.38 m/s². To find the acceleration of the object, we can use the formula:

acceleration = change in velocity / time

The object goes from rest to a speed of 10 m/s in 4.2 seconds, the change in velocity is:

change in velocity = final velocity - initial velocity

change in velocity = 10 m/s - 0 m/s

change in velocity = 10 m/s

Plugging the values into the formula, we have:

acceleration = change in velocity / time

acceleration = 10 m/s / 4.2 s

acceleration ≈ 2.38 m/s²

Therefore, the acceleration of the object is approximately 2.38 m/s².

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Answer:

0.00377143

Explanation:

You would have to divide to get the frequency.

1.32/350 = 0.00377143

I apologize if it is incorrect-

I hope it helps! Have a great day!

Anygays-

The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.

In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.

The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.

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Answer:

ExplaMeasurements of the height of various plants in an experiment are called (Data).nation:

It is clear that, what would make object B to have a greater work is that a greater force applied to Object B.

We know that in physics, it is common to understand that work is done when the force that has been applied is said to move a distance in the direction of the force.

Now we have see that when force is applied to an object, we expect that the position of the object would change as a result of the fact that work has been done on the object as we can see. Thus by applying a greater force on B it does a greater work.

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The maximum length of foil will be 6732.84 cm or 67.3284 m

To find the maximum length of the foil, the given datas are:

Width of roll of foil = 304 mm

Height or thickness = 0.019 mm

Density of foil = 2.7 g/cm³

Mass of foil = 1.05 Kg

Density is the substance's  mass per unit volume. It can be also described by measuring how the particles in the substances tightly packed together.

                              d = m/ v

v = length (l) × width (w) × height (h)

First of we will convert the Kg into gram and mm into cm.

For 1 Kg = 1000 g

1.09 × 1000 = 1090 g

For 1 cm = 10 mm

304 / 10 = 30.4 cm

0.019 / 10 =  0.0019 cm

Now we will put the values in formula:

d = m/ l× h× w

l = m / d × h× w

l = 1050 g / 2.7 g/cm³× 30.4 cm × 0.0019 cm

l = 1050 g/ 0.155952 g/cm

l = 6732.84 cm or 67.3284 m

The maximum length of foil will be 6732.84 cm or 67.3284 m

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Question:

If you push a bowling ball and a golf ball with an equal force what will happen

Answer:

B)

Explanation:

Larger than the force used to push the object that has less mass. A golf ball and a bowling ball are moving at the same velocity. When gravity and air resistance are equal, the object has drawn its terminal velocity.

The change in potential energy of the Mary-Earth system is approximately 2.78601 kilojoules.

The change in potential energy can be calculated using the formula:

ΔPE = m * g * h

where:

ΔPE = change in potential energy

m = mass of the object (Mary's weight divided by acceleration due to gravity, g)

g = acceleration due to gravity (approximately 9.8 m/s²)

h = height of the flight of stairs

First, let's calculate the mass of Mary:

m = weight / g

Given that Mary weighs 505 N:

m = 505 N / 9.8 m/s²

m ≈ 51.53 kg

Next, we can calculate the change in potential energy:

ΔPE = (51.53 kg) * (9.8 m/s²) * (5.50 m)

ΔPE ≈ 2,786.01 J (joules)

To convert joules to kilojoules, we divide by 1000:

ΔPE ≈ 2.786 kJ

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In the first scenario, the energy would be conserved in the system of the girl-wall, The correct answer is option c

In the second scenario, the energy would be conserved in the system of the person-trampoline-earth, The correct answer is option c

In the third scenario, the energy would be conserved in the system of the box-ramp-earth, The correct answer is option a

In the fourth scenario, in a realistic scenario, the energy would not be conserved in any of the given systems due to external work done on the system. The correct answer is option e

For the first scenario of a person wearing roller skates, assuming there is no external work done on the system, the system of the girl-wall would be the appropriate system to consider. The energy would not be conserved in any other system, as there would be external work done on the system due to forces acting on the girl, wall, or both. Therefore option c is correct.

For the second scenario of a person jumping on a trampoline, assuming there is no external work done on the system, the appropriate system to consider would be the system of the person-trampoline-earth, as the energy would be conserved within this closed system.

None of the other systems would conserve energy, as external work would be done on the system due to the forces acting on the person, trampoline, and/or Earth. Therefore option c is correct.

For the third scenario of pushing a box up a ramp, assuming there is no external work done on the system, the appropriate system to consider would be the system of the box-ramp-earth, as the energy would be conserved within this closed system.

None of the other systems would conserve energy, as external work would be done on the system due to the forces acting on the box, ramp, and/or Earth. Therefore option a is correct.

For the fourth scenario of two cars colliding and coming to a stop, it is important to note that in a realistic scenario, there would be external work done on the system due to forces such as friction, air resistance, and deformation of the cars.

Therefore, the energy would not be conserved in any of the given systems. However, if the scenario were simplified to only consider idealized, perfectly elastic collisions in a vacuum, then the system of both cars would conserve energy. Therefore option e is correct.

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Answer:If a hole is dug into the ground deep enough that it reaches a confined aquifer, the pressure can be great enough to shoot water up the well without any help from a pump. Such a well is called a flowing artesian well

Explanation:

Given that the balloon is negatively charged and it is touching a wooden wall, the ballon will perform all the actions given in the answer choices.

A negatively charged balloon will pull positive charge on the wall surface towards it, since opposite charges attract each other.

Also, the negatively charged balloon touching a wooden wall will push any negative charge in the wall away from it. This is because like charges repel each other.

The negatively charged balloon also polarizes the molecules on the wall. This is because in molecules, atoms are bonded together since protons in one atom attract the electrons in the cloud of another atom.

Therefore, the correct choice is All of the above

ANSWER:

All of the above

5.22N is the thrust of the thruster.

The thrust is the force that propels the rocket through the atmosphere and into space. Newton's third law of motion, which states that every action has an equal and opposite reaction, is used to generate thrust by the rocket's propulsion system.

\(m_{A}\) = 70kg

M = 110kg

a = 0.029m/s²

\(V_{N_{2} }\) = 490m/s

The gas (mass)\(d_{m}\) ejected by the thruster and the thrust can now be calculated using the two equations below F:

a = - \(V_{N_{2} }\)/m dm/dt (1)

F = - \(V_{N_{2} }\) dm/dt (2)

Where,

m = \(m_{A}\) +M

m = 70+110

m = 180kg

The entire mass of the astronaut-MMU system is 180 kg.

\(d_{m}\) is the fuel's ejected mass

dt =5sec is the window of time during which this occurs

Since the mass of the fuel is so small in relation to the total mass, we must separate from (1) here and assume it to be constant:

dm = -ma/\(V_{N_{2} }\) dt

dm = - (180)(0.029)/490 ×5

dm = -0.053kg

The reason for the negative sign is that the ejected mass is moving in the opposite direction from where the astronaut-MMU system is moving. The value of is 0.053 kg, though.

Use equation (2) and the results from the calculation in

F = -490× -0.0593/5

F = 5.22N.

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Answer:

animal and plant

Explanation:

1st is animal

mitochondria

cell membrane

nucleus

endoplasmic reticulum

golgi body

plant cell

cell wall

cell membrane

chloroplast

nucleus

vacuole

endoplasmic reticulum

mitochondria

golgi body

We can use the formula:v = u + atwhere:v = final velocity of the sprinter, which is 2.0 m/su = initial velocity of the sprinte, , the magnitude of the friction force is 300 N.

To determine the magnitude of the friction force, use the formula for force, F=ma, where m is the mass of the sprinter and a is the acceleration of the sprinter. The friction force is equal in magnitude and opposite in direction to the force of the sprinter's foot pushing backward against the ground.

Mass of the sprinter,

m = 60 kgTime the sprinter's foot is on the ground,

t = 0.40 sInitial velocity of the sprinter, u = 0 m/sFinal velocity of the sprinter,

v = 2.0 m/sWe need to calculate the friction force acting on the sprinter.To do this, we first need to calculate the acceleration of the sprinter. We can use the formula:v = u + where:

v = final velocity of the sprinter, which is 2.0 m/s

u = initial velocity of the sprinter, which is 0 m/st = time for which the foot is on the ground, which is 0.40 s

Substituting these values, we get:2.0

= 0 + a(0.40)Simplifying, we get:

2.0 = 0.4a

Dividing both sides by 0.4, we get:

a = 5 m/s² Substituting the values, we get:

F = 60 × 5F = 300 N

Therefore, the magnitude of the friction force is 300 N.

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Answer:

ms jones is a good song poggers

Explanation:

A market development strategy increases sales by introducing new products into new markets, while a product development strategy entails creating a new product targeted to its current customers.

In a market development strategy, a company seeks to expand its customer base by entering new markets or geographic regions. This involves identifying untapped market segments or regions where the company's existing products can be introduced to attract new customers. The goal is to increase sales by reaching a wider audience with existing products.

On the other hand, a product development strategy focuses on creating new products or improving existing ones to cater to the needs and preferences of the company's current customer base. This strategy aims to enhance customer loyalty and satisfaction by providing them with innovative or improved products that meet their evolving demands. The company leverages its understanding of its existing customers to develop products that will resonate with them and generate additional sales.

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The Diversification strategy is used by businesses to boost sales by introducing new products into unexplored markets, whereas a Product Development strategy involves creating new products for the company's existing customers.

A Diversification strategy increases sales by introducing new products into new markets. This involves entering into an area, both in terms of product and market, where the company hasn't ventured before. For instance, a computer manufacturing company choosing to produce smartphones for a global market.

On the other hand, a Product Development strategy entails creating a new product targeted to its current customers. This strategy focuses on introducing a new product or innovation to the company's existing market to leverage the customer base. For example, a bread company introducing a new flavor of bread to existing customers.

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The frequency of the travelling wave is found to be 20 Hertz.

The relationship between the frequency of the wave, the wavelength of the wave and the speed of the wave is given by

V = fy

Where,

V is the speed of the travelling wave,

F is the frequency of the travelling wave,

y is the wavelength of the travelling wave.

The speed of the travelling wave is given to be 500m/s and the wavelength of the travelling wave is 25m.

Now, putting all the values,

500 = f(25)

f = 500/25

f = 20Hz

So, the frequency of the travelling wave is 20Hz.

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Therefore, we cannot calculate the exact time for one cycle without more information.

The time for one cycle of a planet around the Sun is determined by its orbital period, which is related to the average distance of the planet from the Sun. In this case, if the average distance of the planet from the Sun is 21 astronomical units (A.U.), we can use Kepler's Third Law to calculate the orbital period.

Kepler's Third Law states that the square of the orbital period (T) is proportional to the cube of the average distance (r) between the planet and the Sun. Mathematically, it can be expressed as:

T^2 = k * r^3

Where k is a constant.

Given that the average distance is 21 A.U., we can set up the following equation:

T^2 = k * 21^3

To solve for T, we need the value of the constant k. However, without further information or additional equations, we cannot determine the specific value of k. Therefore, we cannot calculate the exact time for one cycle without more information.

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The displacement current in a parallel plate capacitor is related to the rate of change of the electric field between the plates. The formula for displacement current is: I_d = ε0 * A * (dE/dt)

Where:I_d is the displacement current (1.5 A in this case).ε0 is the vacuum permittivity (approximately 8.85 x 10^-12 F/m). A is the area of the capacitor plates.(dE/dt) is the rate of change of the electric field.
Given that the capacitance of the parallel plate capacitor is 2.2 µF (or 2.2 x 10^-6 F), the capacitance formula for a parallel plate capacitor is:
C = (ε0 * A) / d
Where:C is the capacitance (2.2 x 10^-6 F in this case).d is the distance between the plates.We can rearrange the formula to solve for A:
A = (C * d) / ε0
Now, we can substitute the given values into the displacement current formula:
1.5 A = (ε0 * A * (dE/dt))
1.5 A = (ε0 * ((C * d) / ε0) * (dE/dt))
1.5 A = (C * d * (dE/dt))
Rearranging the formula to solve for (dE/dt):
(dE/dt) = (1.5 A) / (C * d)
Substituting the given capacitance and solving for the rate of change of potential difference, we get:
(dE/dt) = (1.5 A) / ((2.2 x 10^-6 F) * d)
Therefore, the rate at which the potential difference between the plates of the parallel plate capacitor must change to produce a displacement current of 1.5 A depends on the distance between the plates (d).

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A hammer thrower accelerates the hammer from rest in four complete rotations (revolutions) and releases it with a speed of 26.5 m/s, then the angular acceleration is \(\alpha = (0 - 26.5 / 1.20) / [(4 \times 2\pi \times 1.20) / 26.5]\)

To solve this problem, we'll use the following equations:

(a) Angular acceleration (α) can be calculated using the formula:

\(\alpha = (\omega_f - \omega_i) / t\)

where

\(\omega_f\) is the final angular velocity,

\(\omega_i\) is the initial angular velocity, and

t is the time taken to accelerate.

\(\omega_f = 0\) (since the hammer is released)

\(t = (4 \times 2\pi \times 1.20) / 26.5\)

\(\alpha = (0 - 26.5 / 1.20) / [(4 \times 2\pi \times 1.20) / 26.5]\)

(b) Tangential acceleration \((a_t)\) is given by:

\(a_t = r \times \alpha\)

where

r is the radius of the circular path.

(c) Centripetal acceleration \((a_c)\) is given by:

\(a_c = r \times \omega^2\)

where

\(\omega\) is the angular velocity.

(d) Net force \((F_{net})\) is given by:

\(F_{net} = m \times a_t\)

where

m is the mass of the hammer.

(e) The angle \((\theta)\) can be calculated using the formula:

\(\theta = arctan(a_c / a_t)\)

Let's calculate each part step by step:

Given:

First, let's find the initial angular velocity (ω_i). In one complete revolution, an object covers a distance equal to the circumference of the circular path, so:

Circumference = \(2\pi r\)

Since the hammer completes four full turns, the distance traveled is 4 times the circumference. This distance is also equal to the linear distance traveled, which is v multiplied by the time taken (t) to accelerate:

\(4 \times 2\pi r = v \times t\\t = (4 \times 2\pi r) / v\)

Next, we can find the initial angular velocity:

\(\omega_i = 2\pi n / t\)

Substituting the values:

\(\omega_i = 2\pi \times 4 / [(4 \times 2\pi \times 1.20) / 26.5]\\= 2\pi \times 4 \times 26.5 / (4 \times 2\pi \times 1.20)\\= 26.5 / 1.20\)

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To most efficiently solve this problem, you should divide the rod into pieces of charge that consist of Thin slices of the rod cut perpendicular to the axes of the rod. Option C.

The electric potential is a magnitud used to obtain a measure of the electric field that a charge located at a point A can acquire.

The electric potential, V, of the electric field created by a point charge Q is obtained by means of the following expression,

V = k (Q/R)

Where

The electric potential can be created by one or many punctual charges.

If it is caused by many punctual charges in the electric field, the total electric potential, Vt, results from the addition of the electric potentials, Vn, at that point created by each of the charges separately.

Vt = V1 + V2 + V3 + .... + Vn

In the exposed example, there is a lineal distribution of charges along the rod.

So there is a rod of length L. This rod has a possitive charge Q distributed along its length.

There is an A point placed at a distance D from one of the rod extremes.

We need to find the way to calculate the Electric potential, V.

Vt = ∫ K dQ/R

where dQ is a charge differential = λ dL

So we need to place a charge differential, dQ, at any place along the rod. Then R will be the distance from the dQ to the point A.

The total V is the addition of many puntual V.

The best way to calculate it is option C. Thin slices of the rod cut perpendicular to the axes of the rod.

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The answer is true!!!!!!!!!!!

I think its "a dropped penny sinks at the bottom of a pond". Because, non-contact force is a force that you don't touch, like gravity or weight, that falls but you didn't drop it on purpose nature did or gravity itself did.

Your correct answers are:

B. A field that is perpendicular to the flow of charges

C. A magnetic field

When electric charges move through a conductor, two fields are formed: a magnetic field and an electric field. The correct answer is C. a magnetic field and D. an electric field.

A magnetic field is formed around the conductor when electric charges flow through it. This is due to the interaction between the moving charges and the magnetic field lines. The magnetic field is perpendicular to the flow of charges and its strength depends on the magnitude of the current flowing through the conductor.

An electric field is also formed around the conductor. This electric field is established due to the presence of charges and their interaction with each other. The electric field lines are typically radial, originating from the charged particles or the source of the electric field. The electric field exists both inside and outside the conductor.

So, the correct answer is C. a magnetic field and D. an electric field.

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The fundamental frequency of the tube is 50.44 Hz and the wavelength of the fundamental frequency is 6.8 m.

The fundamental frequency of a closed tube is given by:

f = (n * v) / (4 * L)

where n is the harmonic number (for the fundamental frequency, n = 1), v is the speed of sound, and L is the length of the tube.

The wavelength of the fundamental frequency in a closed tube is given by:

λ = 4 * L / n

Substituting the given values, we get:

f = (1 * v) / (4 * 1.7 m)

λ = 4 * 1.7 m / 1

The speed of sound in air at room temperature is approximately 343 m/s. Therefore, we can calculate:

f = (1 * 343 m/s) / (4 * 1.7 m)  = 50.44 Hz

λ = 4 * 1.7 m / 1 = 6.8 m

Therefore, the fundamental frequency of the tube is 50.44 Hz and the wavelength of the fundamental frequency is 6.8 m.

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Answer:

1

Explanation:

The correct answer is decreases in the troposphere and increases in the stratosphere.

For this reason, the density of gases decreases as the distance from Earth's surface increases. Put another way, air pressure (i.e., density) decreases as altitude increases.

The temperature of a place decreases with increasing altitude from the earth's surface.

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(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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Answer:

Explanation:

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