Data Trial 1 Trial 2
Mass of empty crucible with lid 26.689 26.689
Length of ribbon cut 1 inch 1 inch
Mass of Mg metal, crucible, and lid 26.947 26.947
Mass of MgO, crucible, and lid 27.115 27.115










3. Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial using stoichiometry.
• Trial 1:

• Trial 2:

4. Determine the percent yield of MgO for your experiment for each trial.
• Trial 1:

• Trial 2:
5. Determine the average percent yield of MgO for the two trials.

The molar solubility of barium fluoride (BaF2) in a liquid or solution can be calculated using the Ksp value. So, the molar solubility of barium fluoride in the liquid or solution is approximately 1.83×10^-2 M.

The equation for the Ksp of BaF2
Ksp = [Ba2+][F-]^2
where [Ba2+] is the molar concentration of Ba2+ ions and [F-] is the molar concentration of F- ions in the solution.
To calculate the molar solubility of BaF2 in a liquid or solution, we need to determine the maximum concentration of Ba2+ and F- ions that can exist in equilibrium with solid BaF2 at a given temperature. This maximum concentration is the molar solubility of BaF2 in that liquid or solution.
For example, let's calculate the molar solubility of BaF2 in pure water at room temperature (25°C). From the K s p equation, we know that:
K s p = 2.45×10−5 = [Ba2+][F-]^2
Assuming that the initial concentration of Ba2+ and F- ions in pure water is zero, we can let x be the molar solubility BaF2. Then, we have:
Ksp = [Ba2+][F-]^2 = (x)(2x)^2 = 4x^3
Solving for x, we get:
x = (Ksp/4)^(1/3) = (2.45×10−5/4)^(1/3) = 0.0089 M
Therefore, the molar solubility of BaF2 in pure water at room temperature is 0.0089 M.

We can similarly calculate the molar solubility of BaF2 in other liquids or solutions by using the same method and plugging in the appropriate Ksp value.
To calculate the molar solubility of barium fluoride in a liquid or solution, you'll need to use the Ksp (solubility product constant) value provided (2.45×10^-5). Here's a step-by-step explanation:
1. Write the balanced dissociation equation for barium fluoride:
  BaF2(s) ↔ Ba^2+(aq) + 2F^-(aq)
2. Set up the solubility equilibrium expression using Ksp:
  Ksp = [Ba^2+][F^-]^2
3. Define the molar solubility (x) of barium fluoride in the liquid or solution:
  [Ba^2+] = x, [F^-] = 2x
4. Substitute the molar solubility values into the Ksp expression:
  2.45×10^-5 = (x)(2x)^2
5. Solve for x (molar solubility):
  2.45×10^-5 = 4x^3
  x^3 = (2.45×10^-5)/4
  x^3 = 6.125×10^-6
  x = (6.125×10^-6)^(1/3)
  x ≈ 1.83×10^-2 M
So, the molar solubility of barium fluoride in the liquid or solution is approximately 1.83×10^-2 M.

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Answer:

Mass = 82.11 g

Explanation:

Given data:

Mass of KCl = 50.0 g

Mass of O₂ = 50.0 g

Mass of KClO₃ produced = ?

Solution:

Chemical equation:

2KCl + 3O₂   →     2KClO₃

Number of moles of KCl:

Number of moles = mass /molar mass

Number of moles = 50.0 g/ 74.5 g/mol

Number of moles = 0.67 mol

Number of moles of O₂:

Number of moles = mass /molar mass

Number of moles = 50.0 g/ 32 g/mol

Number of moles = 1.56 mol

Now we will compare the moles of oxygen and KCl.

          O₂          :          KClO₃

            3           :             2

           1.56       :          2/3×1.56 = 1.04 mol

        KCl          :          KClO₃

            2           :             2

           0.67       :         0.67

Number of moles of KClO₃ formed by KCl are less thus, it will act as limiting reactant.

Mass of KClO₃:

Mass = number of moles × molar mass

Mass = 0.67 mol ×122.55 g/mol

Mass = 82.11 g

Answer:

Ice wedging

Explanation:

The rocks crack fill with water and then expand

Answer: Based on the stoichiometry 1 mole of carbon disulfide will produce 1 mole of carbon dioxide. Similarly we can apply the volume ratio, so 1.1L of carbon disulfide will produce 1.1L of carbon dioxide.

Answer: C. UVA rays cause premature aging and UVB rays cause burning

Explanation: Ultraviolet radiation causes DNA changes in the skin, leading to premature aging and skin cancer. There are three kinds of UV light: UVA light. This form of solar radiation damages skin at all levels—from the surface layer (epidermis) down deep into the dermis.

0.5 moles of carbon weigh 6.0055 grams.

One of the chemical elements is carbon. The letter C stands for carbon, and the letter g stands for grams. As a result, 0.5 moles of carbon per gram is equivalent to 0.5 moles of carbon per gram, 0.5 moles of carbon per gram, and 0.5 moles of C per gram.

Carbon has a 12.011 atomic mass. Thus, one mole of carbon has a mass of 12.011 grams (12.011 g/mol). We multiply 0.5 moles of carbon by 12.011 to get grams, and vice versa.

no. of Grams = Moles of Carbon x 12.011

                     =0.5 × 12.011 = 6.0055

0.5 moles of carbon equal 6.0055 grams.

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The complete question is

How many grams is 0.5 moles of carbon

The bond energy of each carbon-oxygen bond in carbon dioxide is d. 736 kJ

Since the chemical reaction is 2CO + O₂ → 2CO₂ and the total bond energy of the products carbon dioxide CO₂ is 1,472 kJ.

Since from the chemical reaction, we have 2 moles of CO₂ which gives 1,472 kJ and there are two carbon-oxygen, C-O bonds in CO₂, then

2 × C-O bond = 1,472 kJ

1 C-O bond = 1.472 kJ/2

C-O bond = 736 kJ

So, the bond energy of each carbon-oxygen bond in carbon dioxide is d. 736 kJ

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If you are on 4.16 Chemical Reactions and have 18 questions, then go to the following on Quizlet for further help. Thanks and good luck!

Quizlet - "4.6 Chemical Reactions UT"

h t t p s : / / q u i z l e t . c o m / _ c 7 3 1 u j ? x = 1 q q t & i = 3 8 n a a s

Answer:

10 400 N

Explanation:

A drag force is an oppositional or limiting force which must be overcome before an object must move wit a force. The lesser the drag force, the higher the probability that an object would move easily.

From the question give, the resultant force of the was is 600 N and force from the engine - 11 000 N.

Drag force = 11 000 - 600

                 = 10 400 N

The drag force on the car is 10 400 N.

This shows that the car would not move since the drag force (10 400 N) is far greater than the resultant force(600 N).

Answer:

P = 13.5 atm

Explanation:

Given that

No. of moles, n = 20 moles

Volume of nitrogen gas = 36.2 L

Temperature = 25°C = 298 K

We need to find the pressure of the gas. Using the ideal gas equation

PV = nRT

Where

R is gas constant, \(R=0.082057\ L-atm/K-mol\)

So,

\(P=\dfrac{nRT}{V}\\\\P=\dfrac{20\times 0.082057\times 298}{36.2 }\\\\P=13.5\ atm\)

so, the pressure of the gas is equal to 13.5 atm.

The cheese curds are formed due to the coagulation of the protein by acidic lemon juice.

We need to review the fundamental nature of the milk and the lemon juice. In this case, it must occur to us again that milk is made up of a protein and since it is a protein, we know that there is an optimum pH where a protein is able to function quite well. Outside that pH, the protein may not be able to function well.

Again the lemon juice is largely composed of acid since it is of the citrus family hence it contains the citric acid and this would cause the pH of the system to ow tilt towards the acid range.

Having laid these foundations, we can now see that when we do add the lemon juice to the milk the pH of the system is now outside the optimal and the protein in the milk would coagulate thus the cheese curds are formed.

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The density of the helium gas is: 0.147 g/l

It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.

The formulas and the procedures we will use are:

Where:

Information about the problem:

Applying the mole(n) formula and clearing the mass we get:

m(he) = 0.321 mol * 4.003 g/mol

n(he) = 1.284 g

Applying the density formula we get:

d = m /v

d = 1.284 g/8.73 l

d = 0.147 g/l

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The density of ammonia gas at 33°C and 758 mmHg is approximately: 0.68 grams per liter.

The density of ammonia gas at 33°C and 758 mmHg. To calculate the density of ammonia gas, we can use the Ideal Gas Law formula and the molar mass of ammonia:
1. Ideal Gas Law formula: PV = nRT
Where:
P = pressure (atm)
V = volume (L)
n = number of moles
R = gas constant (0.0821 L atm/mol K)
T = temperature (K)

2. Convert the given conditions:
Temperature: 33°C + 273.15 = 306.15 K
Pressure: 758 mmHg * (1 atm/760 mmHg) = 0.997368421 atm

3. Molar mass of ammonia (NH3) = 14.01 g/mol (N) + 3 * 1.01 g/mol (H) = 17.03 g/mol

4. Rearrange the Ideal Gas Law formula to solve for n/V, which will give us the moles of ammonia gas per liter:
n/V = P / (RT)

5. Substitute the values and solve for n/V:
n/V = 0.997368421 atm / (0.0821 L atm/mol K * 306.15 K) = 0.0399117 mol/L

6. To obtain the density in grams per liter, multiply n/V by the molar mass of ammonia:
Density = (0.0399117 mol/L) * (17.03 g/mol) = 0.679537 g/L

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The percent by mass of acetic acid in the vinegar is 2.33%.

Below are the steps to solve the given problem using the data table given below:

Step 1: Calculate the mass of the vinegar. Given,Mass of flask and vinegar solution- 25.17gMass of flask- 15.12gMass of vinegar solution = Mass of flask and vinegar solution - Mass of flask= 25.17 g - 15.12 g= 10.05 g

Step 2: Calculate the moles of NaOH used in the titration.Molarity of NaOH solution is 0.1 M.Moles of NaOH = Molarity × Volume of NaOH usedMoles of NaOH = 0.1 M × 39.00 mL (since the initial volume of NaOH is 0.00 mL)Moles of NaOH = 0.0039 moles

Step 3: Determine the moles of acetic acid used in the reaction.The balanced chemical equation for the reaction between NaOH and acetic acid (the main component of vinegar) is given below:CH3COOH + NaOH → CH3COONa + H2OMoles of NaOH = Moles of CH3COOH (since they react in a 1:1 ratio)Moles of CH3COOH = 0.0039 moles

Step 4: Calculate the mass of acetic acid used in the reaction.Molar mass of acetic acid is 60.05 g/mol.Mass of CH3COOH = Moles of CH3COOH × Molar mass of CH3COOH= 0.0039 moles × 60.05 g/mol= 0.234 gStep 5: Calculate the percent by mass of acetic acid in the vinegar.Percent by mass of acetic acid = (Mass of CH3COOH / Mass of vinegar solution) × 100%= (0.234 g / 10.05 g) × 100%= 2.33%.

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the drug concentration will not stabilize in the patient's bloodstream and will continue to increase indefinitely, which could have adverse effects on the patient.

The given drug concentration formula is C(t) = 0.2t + 2 + 1 mg/cm². To find lim C(t), we need to evaluate the limit as t approaches infinity. As t increases without bound, the 0.2t term dominates the equation, making the other two terms negligible. Therefore, lim C(t) = infinity. This means that the drug concentration in the patient's bloodstream will continue to increase indefinitely, which can be a cause for concern if the drug is not properly metabolized or excreted from the body. It is important for healthcare professionals to monitor drug concentrations in patients to avoid toxicity or adverse effects. To find the limit as t approaches infinity, lim C(t), we can analyze the function. As t increases, the 0.2t term will dominate the constant term, 2. Therefore, the concentration of the drug in the bloodstream will keep increasing without bounds as time goes on. Mathematically, lim (t→∞) C(t) = ∞. This result indicates that the drug concentration will not stabilize in the patient's bloodstream and will continue to increase indefinitely, which could have adverse effects on the patient.

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Answer:

Explained below.

Explanation:

From avogadro's number, we know that;

1 mole = 6.022 × 10^(23) atoms, molecules, protons e.t.c.

Now,to convert from atoms, compounds, formula units, etc to moles, what we will do is just to divide the amount of the particle value given in the specific units by avogadro's number.

For example, to convert 23 × 10^(20) atoms to moles, we will have;

Number of moles = (23 × 10^(20))/(6.022 × 10^(23)) moles = 0.00382 moles

Calculate the OH− concentration at 25°C, we can use the ion product of water (Kw) at 25°C, which is 1.0 × 10⁻¹⁴.

Kw = [OH−] * [H3O+]

1.0 × 10⁻¹⁴ = [OH−] * (1.33 × 10⁻⁴)

To find the OH− concentration, divide Kw by the H3O+ concentration:

[OH−] = (1.0 × 10⁻¹⁴) / (1.33 × 10⁻⁴)

[OH−] = 7.52 × 10⁻¹¹ M

(b) To find the OH− concentration at 50°C, we'll use the given value of Kw at 50°C, which is 5.48 × 10⁻¹⁴.

5.48 × 10⁻¹⁴ = [OH−] * [H3O+]

[OH−] = (5.48 × 10⁻¹⁴) / (1.33 × 10⁻⁴)

[OH−] = 4.12 × 10⁻¹⁰ M

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Answer:

2.38 g of oxygen (O2).

Explanation:

What is given?

Mass of potassium chlorate (KClO3) = 6.06 g.

Molar mass of KClO3 = 122.4 g/mol.

Molar mass of oxygen (O2) = 32 g/mol.

Step-by-step solution:

First, let's state the balanced chemical equation. Remember that the decomposition of a compound produces two or more products:

Now, let's convert 6.06 g of KClO3 to moles using its molar mass:

You can see in the chemical equation that 2 moles of KClO3 produce 3 moles of O2. By doing a rule of three with this data, we obtain that:

The final step is to convert from 0.0743 moles of O2 to grams using its molar mass, like this:

The answer is that we will produce 2.38 g of oxygen (O2) from the decomposition of 6.06 g of potassium chlorate (KClO3).

Answer:

These are all in order....

Explanation:

- closed system usually absorbs thermal energy from its surroundings, which is heat transfer into the system

- a solute is a substance dissolved in another substance, known as a solvent

- A solvent is a substance that dissolves a solute, resulting in a solution. A solvent is usually a liquid but can also be a solid, a gas, or a supercritical fluid

- a liquid mixture in which the minor component (the solute) is uniformly distributed within the major component (the solvent)

- a nuclear reaction in which a heavy nucleus splits spontaneously or on impact with another particle, with the release of energy

- a nuclear reaction in which atomic nuclei of low atomic number fuse to form a heavier nucleus with the release of energy.

- Half-life is the time required for a quantity to reduce to half of its initial value

- the determination of the age or date of organic matter from the relative proportions of the carbon isotopes carbon-12 and carbon-14 that it contains. The ratio between them changes as radioactive carbon-14 decays and is not replaced by exchange with the atmosphere.

- any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as the system's mass cannot change, so quantity can neither be added nor be removed

Aerobic organisms must have oxygen in order to develop, breathe, metabolize, and use other vital routes. At the end of the electron transport chain during respiration in these organisms.

oxygen acts as an electron acceptor. Hence, when an obligatory aerobe is incubated in anaerobic conditions, they are unable to grow because there is no oxygen present, which in turn restricts its respiration and metabolism.

An electron is a subatomic particle with a negative charge that orbits the nucleus of an atom. It has a relative mass of 9.109 x 10⁻³¹ kg, which is about 1/1836th the mass of a proton. Electrons are responsible for the chemical behavior of atoms, as they are involved in the formation of chemical bonds between atoms. They also play a crucial role in electricity and magnetism, as they are the carriers of electrical charge and can produce magnetic fields. Electrons exist in energy levels around the nucleus, and they can absorb or emit energy to move between energy levels, giving rise to the emission and absorption of light and other electromagnetic radiation. Electrons are also used in various technologies, including electronics, telecommunications, and medical imaging.

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Answer:

Explanation:

Find the molar mass of H2SO4

2H = 2 * 1 = 2

S  = 1 * 32 =32

O4 = 4*16 = 64

total             98

Find the number of mols in 71.5 grams

mols = given mass / molar mass.

given mass = 71.5

molar mass = 98

mols = 71.5/98

mols = 0.7296 mols of H2SO4

Find the moles of H2O

From the Balanced equation, every mol of H2SO4 produces 2 moles of H2O

mols water = 2 * 0.7296

mols water = 1.4592

That's as far as I can take you. I have to know a great deal more to get the volume of H2O

Answer:

-1

Explanation:

electrons are negative

A potassium atom's ground state electron configuration is 1s2, 2s2, 2p6, 3s2, 3p6, 4s1.

An atom's electron configuration is a picture of how electrons are arranged in relation to orbital shells and subshells. Consequently, this is potassium's electron configuration.

Making Electron Configurations in Writing. Write the energy level (the period) first, then the subshell that needs to be filled, and finally the superscript, which indicates how many electrons are in that subshell. The atomic number, Z, is the sum of all the electrons.

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Answer:

That is FALSE

Explanation:

If you go to a farm with 10 brown cows and milk them none of them will have chocolate milk coming out from them.

Specific heat capacity if the unknown metal is -0.450 J/(g°C).

The measure of heat complexity needed to increase the temperature of a single unit of substance mass by one degree Celsius is known as specific heat capacity. This factor is crucial in determining how much energy is required for temperature changes in a given substance.

q = mcΔT

where q is the change in thermal energy, m is the mass of the metal, c is its specific heat capacity, and ΔT is the change in temperature.

In this case, we have:

m = 150 g

ΔT = 22.4°C - 12.6°C = 9.8°C

q = -662 J

Plugging in the values,

-662 J = (150 g) c (9.8°C)

Solving for c, we get:

c = -662 J / (150 g × 9.8°C) = -0.450 J/(g°C)

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Isoelectronic species have the same number of electrons. To determine which option is isoelectronic with S^2-, let's first find the number of electrons in S^2-. Sulfur (S) has 16 electrons in its neutral state. With a 2- charge, it gains 2 extra electrons, making it have 18 electrons.

Now, let's compare the given options:

a. Ar (Argon) has 18 electrons in its neutral state, so it is isoelectronic with S^2-.

b. Ca2+ (Calcium ion) has 20 electrons in its neutral state. With a 2+ charge, it loses 2 electrons, making it have 18 electrons. Thus, it is isoelectronic with S^2-.

c. Al3+ (Aluminum ion) has 13 electrons in its neutral state. With a 3+ charge, it loses 3 electrons, making it have 10 electrons. It is not isoelectronic with S^2-.

d. K (Potassium) has 19 electrons in its neutral state. It is not isoelectronic with S^2-.

So, the species isoelectronic with S^2- are a. Ar and b. Ca2+.

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Answer:

no its not balanced because we have 2 N in the reactants while we have 1 in the product same for 0 we have 2 0 in the reactants and 1 in the products

for it to be balanced it should be NO + O2 → NO2

Explanation:

Answer:

Na 1s2 2s2 2p6 3s1

Ar 1s2 2s2 2p6 3s2 3p6

Explanation:

Answer:

1.44L

Explanation:

P1V1/T1=P2V2/T2

since the temperature didn’t change, stay at 20celsius, we can ignore T1 and T2.T1=T2

(1.00atm)(3.60L)=(2.50 atm)V2

V2=(1.00atm)(3.60L)/(2.50atm)

=1.44L

Given that the density of salt water is  1.027 g/ml, the unknown solid would sink in water.

We know that the density is referred to as the ratio of the mass to the volume of an object. This implies that if the density of an object is less than the density water then the object would float in water. On the contrary, if the density of an object is greater than that of water, the object would sink in water.

We can see from the table that;

Average mass of thee object = 57.1 + 57.4 + 53/3 = 55.8 g

Average volume of the object = 37 + 36 + 36.5/3 = 36.5 mL

Density of the solid = 55.8 g/36.5 mL

= 1.5 g/mL

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