Dados los vectores a ⃗=6m y b ⃗=8m encontrar su resultante cuando Forman ángulo recto de 90° Son paralelos de igual sentido Son paralelos de sentido contrario

Celsius (°C) and Fahrenheit (°F) -273.15°C, or -459.67°F; -50°C, or -58.0°F; -40°C, or -40.0°F; -30°C, or -22.0°F; -20°C, or -4.0°F; and -10°C, or 14.0°F.

Incomplete: °

For reference, 48.89 °C, or 120 °F, is the temperature in Celsius.

To convert a degree in Fahrenheit to a degree in Celsius, use the Fahrenheit to Celsius formula. Celsius is calculated as [(°F-32)5]/9 in Fahrenheit. Add 32 and multiply the result by.5556 (or 5/9) to convert degrees Fahrenheit to Celsius. Simply multiply the result by 1.8 (or 9/5) and add 32 to get the temperature in Fahrenheit. As opposed to 180 degrees on the Fahrenheit scale, 100 degrees on the Celsius scale separates the freezing point and boiling point of water.

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If there were no friction and air resistance, an ideal coaster could go down and up hills at the same height eternally. If you want to round to one or two decimal places, look at the digit immediately decimal point.

Almost always, the start of a roller coaster is a vertical plummet. The automobiles are propelled by a motor to a top of a steep hill, after which gravity takes over completely. Typical vertical fall could be anywhere between 50 and 80 metres high.

When round a decimal value, there are a few guidelines to remember. To put it another way, it round previous digit down if the final digit is much less than 5. However, you just round the previous figure up if it is 5 or above. Thus, it round number up if 5, 6, 7, 8, or 9 come after the number we are about to round.

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Answer: 1) 40W

Explanation:

Power formula

In contrast to force itself, which is the primary result of an interaction between two things, power is a manifestation of energy invested over time (effort), of which force is a component.Thus, option A is correct.

Energy must be applied to help an object move, and this energy can take the form of force. Work or work done refers to the energy used to move any object by applying force. Work and energy are therefore directly related.

Any action that tends to change a body's state of rest or uniform motion is referred to as a force. In essence, this is the first Law of Motion from Newton. A system's ability to perform work is measured by the presence of energy. For instance, kinetic, potential.

Therefore, Power can be measured and described, but a force is a real physical entity, but power is not.

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Explanation:

When there is a constant unbalanced force applied in the same direction as the motion, speed will increase and acceleration will remain constant. When there is an increasing unbalanced force applied in the same direction as the motion, speed will increase and acceleration will increase.

According to newton's 2nd law

F = ma

F ∝ a

meaning when F increases , a increases and vice versa

On a level ice surface, a 55-kilogram skater glides over it while being subject to a friction force of 11 newtons. The skater's acceleration is -0.2 m/s^2.

The force of friction acting on the skater can be calculated as follows:

friction = μ * N

where

μ = coefficient of friction between the ice and skates (assumed to be constant)

N = normal force, which is equal to the weight of the skater

N = m * g

where

m = mass of the skater (55 kg)

g = acceleration due to gravity (9.8 m/s^2)

By substituting the values, we get:

friction = μ * m * g = 11 N

Finally, the net force acting on the skater can be calculated as follows:

net force = friction = -11 N (opposite direction to motion)

The acceleration of the skater can be calculated using Newton's second law of motion:

a = F / m

= -11 N / 55 kg

= -0.2 m/s^2

The acceleration of the skater is -0.2 m/s^2.

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Note: The correct question would be as bellow,

A 55-kilogram ice skater slides across a level ice surface and the force of friction acting on the skates has a magnitude of 11 newtons. Find the coefficients of static and kinetic friction between the skates and the ice.

Answer:

\(T=62.9*10^{-9}\)

Explanation:

From the question we are told that:

Index of refraction of Rinestones \(\gamma_1 =1.5\)

Index of refraction of silicon \(\gamma_2 =2.0\)

Wavelength  \(\lambda=576nm=576*10^{-9}\)

Let each layer have thickness T

Therefore

Total Thickness =2T

Generally the equation for  Constructive interference is mathematically given by

\(2T=(m+0.5)\frac{l\lambda}{\gamma_2}\)

Where

 \(M=0\)

 \(2T=(0+0.5)\frac{576*10^{-9}}{2*2.0}\)

 \(T=62.9*10^{-9}\)

Assuming that the "craft" refers to an early submersible craft, the tension in the cable, when it was being lowered to the seafloor, would be the tension when it was stationary minus the drag force.

Say, for example, the tension in the cable when an early submersible craft was 7000 N. When the craft was either lowered to or raised from the seafloor at a steady raid, the motion in through the water it experienced added a 1500 N drag force.

When it's being lowered, the tension in the cable would be the difference between the two forces = 7000 N - 1500 N = 5500 N.

When it's being raised, the tension in the cable would be the sum of the two forces = 7000 N + 1500 N = 8500 N.

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Answer:

Transverse waves are always characterized by particle motion being perpendicular to wave motion. A longitudinal wave is a wave in which particles of the medium move in a direction parallel to the direction that the wave moves.

Explanation:

The movement of the medium is different. In the longitudinal wave, the medium moves left to right, while in thee transverse wave, the medium moves vertically up and down. Longitudinal waves have a compression and rarefaction, while the transverse wave has a crest and a trough. Longitudinal waves have a pressure variation, transverse waves don't have pressure variation. Longitudinal waves can be propagated in solids, liquids and gases, transverse waves can only be propagated in solids and on the surfaces of liquids. Longitudinal waves have a change in density throughout the medium, transverse waves don't.

Answer:

D - Spectroscopic binaries

Answer:

a sense of industry

Explanation:

I just had this question and got it right

Answer:

✓ No work Explanation: Work is equal to a force times a displacement (parallel to the force) $$W=F*D$$ It is energy that causes a mass to be moved.

Explanation:

Answer: 35 m/s

Explanation: Gravitational acceleration only affects the vertical component of motion meaning the horizontal component never changes. This means 35 m/s is the correct answer.

A projectile is fired horizontally at an initial horizontal speed of 35 meters per second from a height of 65 meters, after falling 25 meters, the projectile's horizontal speed is 35 m/s.

The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar number.

Speed is calculated using the formula s=d/t, where s is the speed in m.s⁻¹, d is the distance in m, and t is the time in s.

Variable speed is when an object travels a different distance at the same time intervals, whereas uniform speed is when an item travels the same distance at the same time intervals.

Therefore, after falling 25 meters, the projectile's horizontal speed is 35 m/s.

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In microeconomics, both strong monotonicity and local non-satiation have different meanings and implications. Both terms refer to the preferences of the consumer. The two concepts are related but have some differences.

Let's define each term.

Strong monotonicity: Strong monotonicity is defined as a preference relation of a consumer, such that for any two bundles of goods, if bundle A has more of each good than bundle B, then the consumer strictly prefers A to B.

Local non-satiation: Local non-satiation implies that a consumer always prefers any bundle of goods that contains slightly more of any good than a different bundle, holding the other goods in the two bundles constant.

Now, we'll see that strong monotonicity implies local non-satiation but not vice versa.

Let's suppose a consumer has a preference for bundle A over bundle B if A has more of each good than B. This preference implies that if any good in bundle B is increased, the consumer will prefer the new bundle to the original bundle. This is a simple proof that strong monotonicity implies local non-satiation. If bundle A is preferred to bundle B due to monotonicity, then any bundle with a slightly higher quantity of any good in bundle A will also be preferred over B.

However, the reverse is not true. Local non-satiation does not imply strong monotonicity. Local non-satiation requires that the consumer prefers any bundle with slightly more of any good to a bundle with slightly less of any good. But this condition does not imply the monotonicity condition. For example, consider a preference relation such that the consumer prefers A to B and B to C, but prefers D to A.

This preference relation satisfies local non-satiation but not strong monotonicity because bundle D contains less of each good than A, but is preferred over A. Hence, strong monotonicity implies local non-satiation, but not vice versa.

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The time taken by the boat to accelerate from zero to 90 km/hr over 1 km is 11.11 seconds, and the acceleration is 8.1 m/s2.

The problem has provided the initial speed of the boat as zero, and the final speed as 90 km/hr.

We need to find the time taken by the boat to accelerate from zero to 90 km/hr over 1 km.

We can use the formula of acceleration to solve this problem.

The formula is:

v = u + at

where, v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

From the above formula, we can write:

90 = 0 + a * t

where acceleration is a, and time taken is t.

Therefore, a * t = 90...…..(1)

The boat has traveled 1 km, which is 1000 m.

We can use the formula of average speed to calculate acceleration.

The formula is:

v = d / t

where, v is the speed

d is the distance traveled

t is the time taken.

We can write this formula as:

t = d / v,

where distance traveled is d, and the speed is v.

Substituting the values in the above equation, we get:

t = 1000 / 90t = 11.11 seconds.

From equation 1, we get a = 90 / t,

substituting the value of t, we get:

a = 90 / 11.11

a = 8.1 m/s2

Therefore, the time taken by the boat to accelerate from zero to 90 km/hr over 1 km is 11.11 seconds, and the acceleration is 8.1 m/s2.

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(i) Switch k1 is closed:

The current passing through the circuit is:  0.25 amps

R_total = R1 + R2 = 3 + 5 = 8 ohms

The current passing through the circuit is:

i = V / R_total = 2 / 8 = 0.25 amps

(ii) Switches k1 and k2 are closed:

The current passing through the circuit is: 1.07 amps

1/R_total = 1/R1 + 1/(R2 + R3) = 1/3 + 1/(5 + 0) = 8/15

R_total = 15/8 ohms

The current passing through the circuit is:

i = V / R_total = 2 / (15/8) = 1.07 amps

(iii) Switch k1 is open and k2 is closed:

The current passing through the circuit is: 1.07 amps

1/R_total = 1/R2 + 1/(R1 + R3) = 1/5 + 1/(3 + 0) = 1/5 + 1/3 = 8/15

R_total = 15/8 ohms

The current passing through the circuit is:

i = V / R_total = 2 / (15/8) = 1.07 amps

So the current passing through the circuit depends on which switches are closed, and can range from 0.25 amps to 1.07 amps.

What is current?

Crrent refers to the flow of electric charge through a conductor, such as a wire. It is measured in amperes (A) and is defined as the rate at which electric charge flows past a given point in a circuit. current is caused by the movement of charged particles, such as electrons or ions, through a conductor.

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Answer:

Explanation:

1- incident ray

2- the substance through which the wave travels

Answer: the incident ray(the incident ray is the ray striking the mirror at the point of incidence while the refracted ray is the ray leaving the mirror)

The substance through which the ray or wave travels.

The hockey puck has an average velocity of 16.2 m/s in the westward direction, tilted 18 degrees northward from directly west. This means it is moving diagonally towards the west while slightly angled towards the north.

To calculate the average velocity, we need to find the total displacement and the total time taken by the puck.

The first displacement is given as 11 m [N], and the time taken is 0.55 s. The second displacement is given as 26 m [W 42° N], and the time taken is 1.2 s.

First, we need to find the horizontal and vertical components of the second displacement.

The horizontal component can be calculated as 26 m × cos(42°), which is approximately 19.6 m.

The vertical component can be calculated as 26 m × sin(42°), which is approximately 17.8 m.

Next, we find the total horizontal and vertical displacements by summing up the components from both displacements. The total horizontal displacement is 19.6 m - 0 m = 19.6 m [W], and the total vertical displacement is 17.8 m + 11 m = 28.8 m [N].

To find the total displacement, we use the Pythagorean theorem: the square root of (19.6 m)² + (28.8 m)², which is approximately 35.2 m.

The total time taken is 0.55 s + 1.2 s = 1.75 s.

Finally, we calculate the average velocity by dividing the total displacement by the total time taken: 35.2 m / 1.75 s, which gives us approximately 20.1 m/s.

Considering the direction, the average velocity is 20.1 m/s [W 38.6° N].

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The average velocity of the puck is 12.7 m/s.

The given distances and time for a hockey puck to travel are:

11 m [N] in 0. 55 s26 m [W 42° N] in 1. 2 s

Calculating the average velocity of the puck using the formula,average velocity = total displacement / total time

where the total displacement is the difference between the final position and the initial position of the puck.

The total displacement in the y-direction (North) is 11 m.

In the x-direction (West 42° N), the total displacement is:

26 cos(42°) m = 18.86 m (in the west direction)

The resultant displacement is calculated using the Pythagorean theorem:

√ (11² + 18.86²) m = 22.23 m

The total time taken by the puck to cover this distance is:0.55 s + 1.2 s = 1.75 s

Therefore, the average velocity of the puck can be calculated as:

average velocity = 22.23 m / 1.75 s ≈ 12.7 m/s

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Cumulus clouds often indicate Optiion C. possible turbulence.

Turbulence, associated with thunderstorms, may be extremely risky, having the ability to motivate overstressing of the aircraft or lack of manipulation. Thunderstorm vertical currents can be sturdy sufficient to displace a plane up or down vertically as plenty as 2000 to 6000 ft.

Turbulence is only one type of alternate in the air around your aircraft. Air is not nothingness; it's a fluid, like water. Currents of airflow up and down, ripple out, trade direction, and change speed. some of the things that reason turbulence are simpler to expect.

Turbulence is an unexpected and every-so-often violent shift in airflow. the ones irregular motions within the atmosphere create air currents that may purpose passengers on an aircraft to enjoy stressful bumps throughout a flight, or it is able to be extremely sufficient to throw an airplane out of manage.

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To achieve an exercise intensity that requires a heart rate (HR) of 75% of HRmax, the treadmill speed should be adjusted accordingly.

To determine the treadmill speed that corresponds to an exercise intensity of 75% of HRmax, we need to calculate the target heart rate (THR) based on the maximum heart rate (HRmax) and then determine the appropriate treadmill speed.

1. Calculate the target heart rate (THR):

HRmax is usually estimated using the formula: HRmax = 220 - age.

For example, if the individual's age is 30 years, HRmax would be 220 - 30 = 190 beats per minute (bpm).

THR is 75% of HRmax: THR = 0.75 * HRmax.

2. Determine the treadmill speed:

The appropriate treadmill speed for achieving the target heart rate depends on the individual's fitness level and preferences. It is typically recommended to start with a moderate intensity level and adjust accordingly. It is advisable to consult with a healthcare or fitness professional to determine the suitable speed based on the individual's capabilities and goals.

By following these steps, one can identify the target heart rate and adjust the treadmill speed accordingly to achieve an exercise intensity of 75% of HRmax.

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The magnitude of the net force acting on a soccer ball at an instant when it is in contact with the foot of the player kicking it can be determined based on its mass and the components of its acceleration in the x and y directions.

To find the magnitude of the net force, we can use Newton's second law, which states that the net force acting on an object is equal to the product of its mass and acceleration. In this case, the mass of the soccer ball is given as 0.30 kg. The acceleration has both horizontal (x) and vertical (y) components, which are 900 m/s^2 and 910 m/s^2, respectively.

To calculate the magnitude of the net force, we can use the Pythagorean theorem. The magnitude of the net force (F_net) can be found using the equation F_net = sqrt((F_x)^2 + (F_y)^2), where F_x is the horizontal component of the force and F_y is the vertical component of the force.

Substituting the given values, we can calculate the magnitude of the net force acting on the soccer ball at that instant.

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According to the given statement It takes 26.97 seconds to travel 7500 m with constant velocity 278 m/s.

Quickness of movement or activity is known as velocity. Speed is a shorter term and a substitute for celerity. The term "velocity" in mechanics especially refers to the measurement of an object's rate and direction of positional change. It is a vector number that describes a body's motion in term of both speed and direction.

Displacement of Object per unit time is called as Velocity.

velocity=displacement /time

v=s/t

Velocity of car

v=278m/s

Total Displacement

s=7500m

Hence Time

t=s/v

Displacement /Velocity

t=7500/278

t=26.97sec

It takes 26.97 seconds to travel 7500 m with constant velocity 278 m/s.

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Terrestrial planets are thought to have dense iron cores primarily due to their formation process and the differentiation of their materials.

During the early stages of planet formation, when dust and gas in a protoplanetary disk come together to form planets, heavier elements such as iron tend to sink towards the center due to their higher density. This process, called planetary differentiation, results in the formation of a dense metallic core at the center of the planet. Iron is one of the most abundant heavy elements in the universe, and its high density makes it more likely to sink towards the core during planetary formation. As the planet grows and accumulates more material, the iron-rich core becomes more prominent.

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the minimal energy of photons which can be absorbed at the edges of the visible radiation range are 4.97 eV and 2.83 eV for violet and red, respectively.

The edges of the visible radiation range lie at about 400nm (violet) and 700nm (red). The formula for calculating the minimal energy of photons in electron volts is given by:

E = h c/λ

where h is the Planck constant = 6.626 × 10^-34 Js; c is the speed of light = 3.00 × 10^8 m/s; λ is the wavelength of the photon in meters. So, for the edge of the visible range at 400nm (violet):

E = (6.626 × 10^-34 Js)(3.00 × 10^8 m/s)/(400 × 10^-9 m)= 4.97 × 10^-19 J/eV= 4.97 eV

And for the edge of the visible range at 700nm (red):E = (6.626 × 10^-34 Js)(3.00 × 10^8 m/s)/(700 × 10^-9 m)= 2.83 × 10^-19 J/eV= 2.83 eV

Therefore, the minimal energy of photons which can be absorbed at the edges of the visible radiation range are 4.97 eV and 2.83 eV for violet and red, respectively.

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The man moves across the ice with a velocity of -1 m/s.

Formula:

To calculate the velocity we would be using the formula,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Given:

After applying the law of linear momentum, we get the following value before the throw;

M₁ = Man's initial mass= 80kg,

U₁ = Initial velocity of Man = 0,

M₂= Initial mass of Book  = 4kg,

U₂= Initial velocity of Book = 0.

After the throw, the book's velocity will be

M₁ = Man final mass = 80kg,

V₁ = Man's final velocity = V.

M₂ = Final mass of Book = 4kg,

V₂ = Final velocity of Book = 20 m/s

After substituting the values in the formula, we get,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Or, (80 x 0) + (4 x 0) = (80V) + (4 x 20)

Or, 0 = 80V + 80

Or, 80V = -80

Or, V = -80/80

V= -1m/s

[Note: The -ve sign shows the opposite direction]

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Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 40 × 5

We have the final answer as

Hope this helps you