Answer:
d = 15 kg/L
Step-by-step explanation:
The density d is the mass divided by the volume. But first let's convert volume to liters and mass to kilograms:
100 ml = 0.1 L
1500 g = 1.5 kg
d = m/v
d = 1.5/0.1
d = 15 kg/L
please help! this assgiment was due like a week ago and i’m missing so many more i just need help finishing this!
Answer:
17.5hrs
Step-by-step explanation:
Set they worked for x hours,
10x+35=210
10x=175
x=17.5
PLEASE ITS DUE IN 5 MINUTES I WILL MARK BRAINLIEST!
Answer: A. the first one wouldn't graph with the x^2 but with it I would say A. Hope this helps
how many ways are there to list the digits { 1 , 2 , 2 , 3 , 4 , 5 , 6 } so that identical digits are not in consecutive positions?
2880 ways are there to list the digits { 1, 2, 2, 3, 4, 5, 6 } so that identical digits are not in consecutive positions.
The list of the digits is: { 1, 2, 2, 3, 4, 5, 6 }
Here we have to determine how many ways are there to list the digits { 1, 2, 2, 3, 4, 5, 6 } so that identical digits are not in consecutive positions
We have one number in consecutive positions in this question
That is: (2, 2)
Number of ways that (2,2) are in consecutive positions = \($\frac{6!}{2!}\) = 360
The permutation of 1, (2, 2), 3, 4, 5, 6 = 6!
6! = 720
To get the total number of permutations
= \($\frac{7!}{2!}\)
= \($\frac{5040}{2}\)
= 2520
The number of ways that 2 identical digits are not consecutively positioned
= 2520 - 360 + 720
= 2880
There are 2880 ways to list the digits { 1, 2, 2, 3, 4, 5, 6 }.
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On Saturday, 73 people went to the two o’clock movie at the theater. Each person paid $4.00. How much money did the theater collect in all?
Answer:
$292.00
Step-by-step explanation:
Total amount collected= number of people×amount per each person
total amount= 73×$4.00
Total amount collected=$292.00
Answer:
$292
Step-by-step explanation:
its really easy, you just multiply 73 to 4
Which function’s graph has roots at x=−3 and x=2, and a y-intercept at y=−12?
Answer:
the last one
g(x)=(2x+6)(x-2)
Step-by-step explanation:
i drew graphs for all, that was my way of doing it or you can solve it
She dove 75 feet under the sea
Which of these is a correct expansion of (3x – 2)(2x2 + 5)?
A. 3x • 2x2 + 3x • 5 + (–2) • 2x2 + (–2) • 5
B. 3x • 2x2 + 3x • 5 + 2 • 2x2 + 2 • 5
C. 3x • 2x2 + (–2) • 2x2 + 2x2 • 5 + (–2) • 5
The correct expansion of (3x – 2)(2\(x^2\) + 5) is 3x * 2\(x^2\) + 3x * 5 + (–2) * 2\(x^2\) + (–2) * 5. Thus option A is the most appropriate option as the answer the above question
The expansion of the given algebraic expression follows the distributive rule of multiplication that is (a + b)(c + d) = ac + ad + bc + bd.
Thus the first term of the first expression which is 3x is multiplied by the the second expression and we get 3x • 2\(x^2\) + 3x • 5 + (–2)
Then the second term that is -2 is multiplied by the second expression and we get 5 + (–2) • 2\(x^2\) + (–2) • 5
Then we add both expressions and get the answer 3x * 2\(x^2\) + 3x * 5 –2 * 2\(x^2\) –2 * 5.
After further simplification of the above expression we get, 6\(x^3\) + 15x - \(4x^2\) - 10.
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Suppose a coin is flipped twice. The event of getting heads on the first toss and the event of getting heads on the second toss could be said to be mutually exclusive. (True or false)
The statement "Suppose a coin is flipped twice is false because the event of getting heads on the first toss and the event of getting heads on the second toss could be said to be mutually exclusive" is false.
Mutually exclusive events cannot occur at the same time, meaning if one event occurs, the other event cannot. In this case, getting heads on the first toss and getting heads on the second toss are not mutually exclusive because they can both occur in a single trial (i.e., flipping the coin twice).
You could have heads on the first toss and heads on the second toss as well, so these events are not mutually exclusive.
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What is the value of 1 − 2 × 3 + 4 ÷ 5 ?
Answer: -4.2
Step-by-step explanation:
=1-6+0.8
=-4.2
4. There are major chords built on what three notes (with all white notes and no accidentals)? O CFG O ABC GEB OCDE
The three major chords built on white notes without accidentals are:
1. C major chord (C, E, G)
2. F major chord (F, A, C)
3. G major chord (G, B, D)
These chords are formed by taking the root note, skipping one white note, and adding the next white note on top. For example, in the C major chord, the notes C, E, and G are played together to create a harmonious sound.
Similarly, the F major chord is formed by playing F, A, and C, and the G major chord is formed by playing G, B, and D. These three major chords are commonly used in various musical compositions and are fundamental building blocks in music theory.
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Let f(x) = -3x³ + 9x² - 5x + 15. Use the Factor Theorem to help answer the
following questions.
a) Is a
O Yes
O No
b) Is x + 1 a factor of f(x)?
O Yes
No
1 a factor of f(x)?
c) Is a 3 a factor of f(x)?
O Yes
O No
Answer:
See below. I added words tro the first question "Is a" so that I could answer it.
Step-by-step explanation:
f(x) = -3x³ + 9x² - 5x + 15
f(x) = -(x-3)(3x² + 5)
x((9-3x)x-5)+15
-3(x-1)\(x^{3}\) + 4(x-1) + 16
=======
a) Is a [ghost happy]?
O Yes Yes, as long as it can haunt.
O No
b) Is x + 1 a factor of f(x)?
O Yes Yes
No
1 a factor of f(x)?
Always
c) Is a 3 a factor of f(x)?
O Yes
O No No, as far as I can see.
The price of a sweater was reduced from $25 to &19. By what percentage was the sweater reduced by?
Answer:
24%
Step-by-step explanation:
Difference in price of sweater
=$25-$19
=$6
6/25×100%=24%
Find the length of the arc. Round to the nearest tenth.
10 cm
60°
Graph the system of equations on graph paper to answer the question.Please help me with this problem so I can help my son to understand better. {y=−3x+9y=−x−5}What is the solution for the system of equations?Enter your answer by filling in the boxes. (__,___)
Given the following system of equations:
y = -3x + 9
y = -x - 5
For us to be able to graph each of the equations, let's first determine the coordinates of its x and y-intercepts.
We get,
For y = -3x + 9,
At x = 0,
y = -3x + 9
y = -3(0) + 9
y = 9
Point 1 = 0, 9
At y = 0
y = -3x + 9
0 = -3x + 9
3x = 9
3x/3 = 9/3
x = 3
Point 2 = 3, 0
For y = -x - 5,
At x = 0,
y = -x - 5
y = 0 - 5
y = -5
Point 1 = 0, -5
At y = 0,
y = -x - 5
0 = -x - 5
x = -5
Point 2 = -5, 0
Let's now plot the two equations:
From the graph, it shows that the graph of the two equations intersects at 7, -12.
This point of intersection is also the solution for the system of equations.
Therefore, the answer is 7, -12.
The number of cans of soft drinks sold in a machine each week is recorded below. Develop forecasts for the period indicated and error calculations.
155, 145, 155, 162, 180, 165, 172, 149, 170, 172
Exponential smoothing. Use Excel Solver to determine the optimum alpha value to minimize MSE and answer:
What is the Mean Absolute Error (MAE)?
What is the Mean Squared Error (MSE)
The Mean Absolute Error (MAE) is [Insert value]. The Mean Squared Error (MSE) is [Insert value].
To calculate the Mean Absolute Error (MAE) and Mean Squared Error (MSE) using exponential smoothing, we need to find the optimum alpha value that minimizes the MSE. Excel Solver can be used to determine this value.
Organize the data: Arrange the given data in a column in Excel: 155, 145, 155, 162, 180, 165, 172, 149, 170, 172.
Set up the exponential smoothing model: Define the forecast for each period using the formula: Forecast = α * Actual + (1 - α) * Forecast(t-1)
Calculate the MAE and MSE: For each period, calculate the forecasted value using the exponential smoothing model. Then, calculate the absolute error by taking the absolute difference between the forecasted value and the actual value. Square each absolute error to obtain the squared error. Finally, calculate the average of the absolute errors to find the MAE and the average of the squared errors to find the MSE.
Use Excel Solver: To determine the optimum alpha value, you can set up Excel Solver to minimize the MSE by changing the alpha value. The objective is to find the alpha value that gives the lowest MSE.
After performing the calculations and using Excel Solver to find the optimum alpha value, you can obtain the Mean Absolute Error (MAE) and Mean Squared Error (MSE) for the given data. These values will provide a measure of the accuracy of the exponential smoothing forecast.
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solve for b and simplify -17=-3/2b
Answer:
b = 34/3
General Formulas and Concepts:
Pre-Alg
Order of Operations: BPEMDASEquality PropertiesStep-by-step explanation:
Step 1: Define equation
-17 = -3/2b
Step 2: Solve for b
Rewrite: -3/2b = -17Divide both sides by -3/2: b = 34/3Step 3: Check
Plug in b to verify it's a solution.
Substitute: -17 = -3/2(34/3)Multiply: -17 = -17im confuse gusy can u help me?
Answer:
11. 333... which can also be written as 11 1/3.
Step-by-step explanation:
Sure.
√(6c - 4) = 8
Squaring both sides:
6c - 4 = 64
6c = 64 + 4 = 68
c = 68/6
= 11. 333...
Answer:
\(c=\dfrac{34}{3}\)
Step-by-step explanation:
Given equation:
\(\sqrt{6c-4}=8\)
Square both sides:
\(\implies (\sqrt{6c-4})^2=8^2\)
\(\implies 6c-4=64\)
Add 4 to both sides:
\(\implies 6c-4+4=64+4\)
\(\implies 6c=68\)
Divide both sides by 6:
\(\implies \dfrac{6c}{6}=\dfrac{68}{6}\)
\(\implies c=\dfrac{34}{3}\)
Verify the solution by inputting the found value of c back into the equation:
\(\implies \sqrt{6\left(\dfrac{34}{3}\right)-4}\)
\(\implies \sqrt{\dfrac{204}{3}-4}\)
\(\implies \sqrt{68-4}\)
\(\implies \sqrt{64}\)
\(\implies \pm 8\)
Therefore, the solution of the found value of c is verified.
Carlos went to PetSmart to get his hamster an exercise ball. There was a small one with a 5 inch diameter and a 13 inch ball. How much more space (volume) is in the larger than the smaller? Round to the nearest tenth.
The amount of space (volume) that is in the larger spherical ball than the smaller = 1,084.8 in.³
What is the Volume of a Sphere/Spherical Solid?To find the volume of a sphere, which is the amount of space the solid contains, the formula used is given as: 4/3 πr³, where r is the radius of the sphere, which is half the measure of the diameter. Volume of sphere (V) = 4/3 πr³.
Diameter of the smaller spherical ball = 5 inches
Radius of the smaller spherical ball = 5/2 = 2.5 inches
Volume of the smaller spherical ball = 4/3 πr³ = 4/3 × π × 2.5³
Volume of the smaller spherical ball ≈ 65.5 in.³
Diameter of the larger spherical ball = 13 inches
Radius of the larger spherical ball = 13/2 = 6.5 inches
Volume of the larger spherical ball = 4/3 πr³ = 4/3 × π × 6.5³
Volume of the larger spherical ball ≈ 1,150.3 in.³
The amount of space (volume) that is in the larger spherical ball than the smaller = 1,150.3 - 65.5
The amount of space (volume) that is in the larger spherical ball than the smaller = 1,084.8 in.³
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Suppose log subscript a x equals 2, space log subscript a y equals 5, and log subscript a z equals short dash 3. Find the value of the following expression. log subscript a open parentheses fraction numerator x y cubed over denominator z squared end fraction close parentheses
The value of the logarithmic expression \(\log _a (\frac{x^3y}{z^4} )\) is 24.
Given the following logarithmic expressions \(\log _ax = 3, \log _ay = 7, \log _az = -2\) , we are to find the value of \(\log _a (\frac{x^3y}{z^4} )\)
from the above \(\log _ax = 3, x = a^3\)
\(\log _ay = 7, y = a^7\)
Substituting x = \(a^3\), y = \(a^7\) and z = \(a^{-2}\) into the log function\(\log _a (\frac{x^3y}{z^4} )\) we will have;
\(\log _a (\frac{x^3y}{z^4} )\\=\log _a (\frac{(a^3)^3 \times a^7}{(a^{-2})^4} )\\= \log _a (\frac{a^9 \times a^7}{a^-^8} )\\= \log _a (\frac{a^1^6}{a^-^8} )\\= \log _a (\frac{x^3y}{z^4} )\\= \log _a a^2^4\\= 24 \log _a a\\= 24 \times 1\\= 24\)
Hence, the value of the logarithmic expression is 24
What is logarithmic expression?In an exponential equation, the variable is expressed as an exponent. An equation using the logarithm of an expression containing a variable is referred to as a logarithmic equation.Check to determine if you can write both sides of the equation as powers of the same number before you attempt to solve an exponential equation.To learn more about logarithmic expression with the given link
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Mrs Anderson has 185 pieces of wood he sold 25 peacas of wood to his neighbor and distract the rest of the world into piles around his house each pile of wood contained 40 pieces of wood which equation can be used to find peat the number of piles of wood Mr. Anderson made?
Answer: Let x be the number of piles of wood that Mr. Anderson made.
We know that he sold 25 pieces of wood to his neighbor, and the rest of the pieces of wood were divided into piles around his house, with each pile containing 40 pieces of wood.
Therefore, we can set up the equation:
185 pieces - 25 pieces = x * 40 pieces
Simplifying the equation:
160 = x * 40
To find the value of x, we need to divide 160 by 40
160/40 = x
x = 4
Therefore, Mr. Anderson made 4 piles of wood after he sold 25 pieces of wood to his neighbor.
It's worth noting that this equation was used to find the number of piles of wood Mr. Anderson made after selling 25 pieces to his neighbor, and assuming that he didn't use the rest of the wood for anything else except for making the piles.
Step-by-step explanation:
a pharmaceutical company receives large shipments of ibuprofen tablets and uses an acceptance sampling plan. this plan randomly selects and tests 21 tablets, then accepts the whole batch if there is at most one that doesn't meet the required specifications. what is the probability that this whole shipment will be accepted if a particular shipment of thousands of ibuprofen tablets actually has a 15% rate of defects? (report answer as a decimal value accurate to four decimal places.) p(accept shipment)
0.9660 is the probability that this whole shipment will be accepted if a particular shipment of thousands of ibuprofen tablets actually has a 15% rate of defects
What is probability ?Probability turned into added into arithmetic to are expecting the possibility of an occasion occurring. Probability essentially approach how in all likelihood it's miles that some thing will happen. This is the fundamental principle of possibility and is likewise utilized in possibility distributions to examine feasible consequences of random experiments.
CalculationIf the number of tablets in a shipment is sufficiently large, we can consider the testing procedure you describe (selecting a random sample of 29 ibuprofen tablets and counting the number of defective tablets in the sample) to be a binomial probability experiment.
Let X = (Number of defective ibuprofen tablets in a random sample of 29 tablets.) Then we may reasonably assume that X follows a binomial distribution. For each "trial" (that is, each tablet selected), there are two possible outcomes, "success" (the tablet is defective), or "failure" (the tablet is not defective). Note that the word success as used in the binomial distribution does not carry the connotation of being a "good" outcome. A "success" is simply the outcome you are interested in counting, which in this case is the number of defectives in the sample. The important parameters for a binomial distribution are n (the number of trials) and p (the probability of success on any one trial.) For this situation, we have p = .01 (since we are told 1% of the tablets in the shipment are defective) and n = 29. The general formula for the binomial distribution is
P(x) = nCx·px·(1 - p)n-x
where x is the number of successes in n trials (In this problem, x is the number of defectives in a random sample of 29 tablets.) The symbol nCx is the "number of combinations of n things taken x at a time". This is the number ways of choosing x distinct objects from a set of n objects, without regard to order. It is given by
nCx = n!/[x!·(n-x)!]
where ! is the factorial symbol.
We want to find the probability that the shipment is accepted. We are told that a shipment will be accepted if at most one tablet doesn't meet the required specifications. That is, the number of defectives must be less than or equal to one.
P(Shipment accepted) = P(X ≤ 1). (In this case, X ≤ 1 if and only if X=0 or X=1)= P(0) + P(1).
So we calculate P(0) (the probability of 0 defective tablets in the shipment), and P(1) (the probability of 1 defective.) Using the formula for the binomial distribution, we have
P(0) = 29C0·(.01)0·(1 - .01)29 - 0.
But 29C0 = 1, so
P(0) = 1·(.01)0·(.99)29 ≅ .74717
Also,
P(1) = 29C1·(.01)1·(1 - .01)29 - 1.
Calculating 29C1, we have
29C1 = 29!/[1!·(29-1)!] = 29, so
P(1) = 29·(.01)1·(99)28
P(1) ≅ .21887
Finally, then, we have
P(Shipment accepted) ≅ .74717 + .21887 ≅ .9660 (to 4 decimal places.)
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evaluate s4 = 4∑k=1 2(3n-1)
Answer: It seems like there might be a mistake in the expression you provided. The variable "n" is not defined, and it does not appear in the summation. It seems like you might have meant to write:
s4 = 4∑k=1 2(3k-1)
Assuming that this is the correct expression, we can evaluate it as follows:
s4 = 4∑k=1 2(3k-1)
= 4 * [2(3(1)-1) + 2(3(2)-1) + 2(3(3)-1) + 2(3(4)-1)]
= 4 * [2(2) + 2(5) + 2(8) + 2(11)]
= 4 * [4 + 10 + 16 + 22]
= 4 * 52
= 208
Therefore, s4 = 208.
how many non zero terms should there be in a maclaurin series that is used to estimate the following with a n error of less than 0.0001
Using 5 non zero terms of the Maclaurin series for ln(1+x) will provide an estimation of ln(1.4) within an error of 0.001.
To estimate ln(1.4) within an error of 0.001 using the Maclaurin series for ln(1+x), we need to find the number of terms (n) required.
The Maclaurin series for ln(1+x) is given by:
ln(1+x) = x - \((x^2)/2 + (x^3)/3 - (x^4)/4 + ...\)
To estimate ln(1.4), we substitute x = 0.4 into the series:
ln(1.4) ≈ 0.4 - \((0.4^2)/2 + (0.4^3)/3 - (0.4^4)/4 + ...\)
We want to find the minimum number of terms needed to ensure that the error is within 0.001. To do this, we can calculate the absolute value of the remainder term for a given number of terms and check if it is less than 0.001.
The remainder term for the Maclaurin series of ln(1+x) is given by:
\(R_n(x) = (-1)^n * (x^{(n+1)})/(n+1)\)
We can start with a small value of n and increase it until |R_n(0.4)| < 0.001.
Let's calculate the remainder term for n = 4:
\(|R_4(0.4)| = |(-1)^4 * (0.4^{(4+1)})/(4+1)|\) = 0.00128
Since\(|R_4(0.4)|\)> 0.001, we need to include more terms.
Let's calculate the remainder term for n = 5:
\(|R_5(0.4)| = |(-1)^5 * (0.4^{(5+1)})/(5+1)|\) = 0.000256
Since\(|R_5(0.4)|\) < 0.001, we can conclude that we need to use at least 5 terms of the Maclaurin series to estimate ln(1.4) within 0.001.
Therefore, using 5 terms of the Maclaurin series for ln(1+x) will provide an estimation of ln(1.4) within an error of 0.001.
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The complete question is:
How many terms of the Maclaurin series for ln(1+x) do you need to use to estimate ln(1.4) to within 0.001 ?
can y’all help me I know it’s easy but still 2×5.6÷2.8+3.5
Answer:
7.5
Step-by-step explanation:
what does 739474×92937474748
16. Mr. Stevenson is ordering shirts and hats for his Boy Scout
troop. There are 45 scouts in the troop. Hats come in packs of 3,
and shirts come in packs of 5. What is the least number of packs
of each he should order so that each scout will have 1 hat
and 1 shirt, and none will be left over?
Answer:
5 packs of shirts
15 packs of hats
Step-by-step explanation:
you divide the total amount of scouts by the pack size
so to find the number of packs for the shirts
45/3=15
so 15 packs of hats
45/15=3
so 5 packs of shirts
The graph compares the scores earned by 100 students on a pre-test and a post-test.
Two box and whisker plots showing Pre-Test and Post-Test scores on a number line from 0 to 100. The upper plot represents the pre-test scores. For this upper plot, the minimum number is 0, the maximum number is 78, the right side of the box is 60, the left side of the box is 16, and the bar in the box is at 30. The lower plot represents the post-test scores. For this lower plot, the minimum number is 4, the maximum number is 100, the right side of the box is 83, the left side of the box is 30, and the bar in the box is at 45.
About how many more students scored greater than 30% on the post-test than on the pre-test?
15
Answer:
25 more studentsStep-by-step explanation:
30% mark represents:
50% on pre-test and 25% on post test.So
50% of 100 = 50 students scored greater than 30%75% of 100 = 75 students scored greater than 30%.The difference is:
75 - 50 = 25 studentsAnswer:
25 students
Step-by-step explanation:
Graph the line.
y=x-8
please hurry, 15 points
Answer:
graph your y intercept at negative 8 and then continue to go up one right one
Answer:
go down 8 then go up one over one the rest of the way. go to desmos to answer all your graphing questions.
Step-by-step explanation:
brainliest pls
What is the coefficient of x in the expression
1+x+xz
Answer:
the answer is an invisible 1
1.a. Consider a magnetic dipole with north and south poles, each of magnetic strength p/2, separated by a distance 2d. What is the magnitude of the magnetic field at a distance x from the middle of the dipole along the axis that connects the north and south poles?
b. Consider now a solenoid with N loops, length 2a, radius r and resistance R. Calculate the magnetic flux,Φ, of the magnetic field above through the area of the coil. In doing this, assume one-dimensional geometry in the (x-axis) only.
a. The magnitude of the magnetic field at a distance x from the middle of the dipole along the axis connecting the north and south poles is given by \(\[ B = \frac{{\mu_0}}{{4\pi}} \frac{{2p}}{{(x^2 + d^2)^{3/2}}} \]\).
b. The magnetic flux Φ through the area of the coil in the one-dimensional solenoid is \(\[ \Phi = \frac{{\mu_0 N^2 A}}{{2a}} \]\)), where N is the number of loops, A is the cross-sectional area, and a is the half-length of the solenoid.
a. To determine the magnitude of the magnetic field at a distance x from the middle of the dipole along the axis connecting the north and south poles, we can use the formula for the magnetic field due to a magnetic dipole.
The magnitude of the magnetic field B at that point is given by:
\(\[ B = \frac{{\mu_0}}{{4\pi}} \frac{{2p}}{{(x^2 + d^2)^{3/2}}} \]\)
where p is the magnetic strength of each pole, d is the distance between the poles, and μ0 is the permeability of free space.
b. For the solenoid, to calculate the magnetic flux Φ through the area of the coil, we can use the formula for the magnetic flux through a solenoid.
Assuming one-dimensional geometry along the x-axis, the magnetic flux Φ is given by:
\(\[ \Phi = \frac{{\mu_0 N^2 A}}{{2a}} \]\)
where N is the number of loops, A is the cross-sectional area of the solenoid, a is the half-length of the solenoid, and μ0 is the permeability of free space.
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