A 290-turn solenoid having a length of 32 cm and a diameter of 11 cm carries a current of 0.30 A. Calculate the magnitude of the magnetic field inside the solenoid.
The magnitude of the magnetic field inside the solenoid is 3.4×10^(-4) T.
To find the answer, we need to know about the magnetic field inside the solenoid.
What's the expression of magnetic field inside a solenoid?Mathematically, the expression of magnetic field inside the solenoid= μ₀×n×In = no. of turns per unit length and I = current through the solenoidWhat's is the magnetic field inside the solenoid here?Here, n = 290/32cm or 290/0.32 = 906I= 0.3 A
So, Magnetic field= 4π×10^(-7)×906×0.3 = 3.4×10^(-4) T.Thus, we can conclude that the magnitude of the magnetic field inside the solenoid is 3.4×10^(-4) T.
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Two 0.5 kg carts,one red and one green ,sits about half a meter apart on a low friction track. You push on the red with a constant force of 4N for 0.17m and then remove your hand. The cart moves 0.33 m on the track and then strikes the green cart. What is the work done by you on the two cart system?
Answer:
Work done on the two cart system is 2 N-m
Explanation:
Work done is equal to the product of force and displacement
Work done =4N * (0.17 +0.33)
work done = 4N * 0.5
Work done = 2 N -m
Work done on the two cart system is 2 N-m
pls help answer embed
Answer:
C = 1.01
Explanation:
Given that,
Mass, m = 75 kg
The terminal velocity of the mass, \(v_t=60\ m/s\)
Area of cross section, \(A=0.33\ m^2\)
We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,
Weight of the object = drag force
R = W
or
\(\dfrac{1}{2}\rho CAv_t^2=mg\)
Where
\(\rho\) is the density of air = 1.225 kg/m³
C is drag coefficient
So,
\(C=\dfrac{2mg}{\rho Av_t^2}\\\\C=\dfrac{2\times 75\times 9.8}{1.225\times 0.33\times (60)^2}\\\\C=1.01\)
So, the drag coefficient is 1.01.
Which one of these is NOT equal to linear velocity?a.v2/r b.displacement/time c.2πfrd.ωr
The linear velocity in terms of the angular velocity is,
\(v=\omega r\)where,
\(\omega\text{ is the angular velocity, r is the radius of the circular motion}\)The angular velocity in terms of the linear frequency is,
\(\omega=2\pi f\)Thus, the linear velocity in terms of linear frequency is,
\(v=2\pi fr\)The linear velocity in terms of the displacement and time is,
\(v=\frac{\text{displacement}}{\text{time}}\)The relation given in the first option is the expression for centripetal acceleration.
\(a_c=\frac{v^2}{r}\)Thus, option a is the correct answer.
A bullet travelling horizontally with speed of 30m/s strike a wooden plank normal it surface, passing through it with a speed of 10m/s. Find the time taken by the the bullet to pass through the wooden plank of 5cm thickness
The bullet takes 0.0025 seconds to pass through the wooden plank of 5 cm thickness when it is traveling horizontally with an initial speed of 30 m/s and a final speed of 10 m/s.
The time taken by the bullet to pass through the wooden plank can be determined using the equation of motion for constant acceleration.
Given:
Initial speed (u) = 30 m/s
Final speed (v) = 10 m/s
Distance (s) = 5 cm = 0.05 m
To find the time taken (t), we need to calculate the acceleration (a) first. We can use the equation:
v² = u² + 2as
Rearranging the equation, we have:
a = (v² - u²) / (2s)
Substituting the given values:
a = (10² - 30²) / (2 * 0.05)
Simplifying the expression:
a = (-800) / (0.1)
a = -8000 m/s²
The negative sign indicates that the acceleration is in the opposite direction of the initial velocity.
Next, we can use the equation of motion:
v = u + at
Substituting the values:
10 = 30 + (-8000) * t
Simplifying the equation:
-8000t = -20
Dividing by -8000:
t = 20 / 8000
t = 0.0025 s
Therefore, the time taken by the bullet to pass through the wooden plank of 5 cm thickness is 0.0025 seconds.
To find the time taken by the bullet to pass through the wooden plank, we need to calculate the acceleration first using the equation of motion.
By rearranging the equation and substituting the given values, we can find the acceleration.
Then, using the equation of motion again, we can solve for time.
The negative sign in the acceleration indicates that it is in the opposite direction of the initial velocity.
The resulting time is 0.0025 seconds.
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A person can jump out of an airplane at 5000 feet, without a parachute, AND land on the ground safely (without any injury), IF they can manage to do what physics trick?
Lengthen the moment/time of impact
Bend knees right before impact
Spread out arms and legs to slow down
Shorten the length/time of impact
Answer:
Momentum is equal to mass for velocity (p1=mv)
But momentum is also equal to Force for time of impact (p1=Ft). Hence the impact force is inversely proportional to the fall time and directly proportional to the mass and fall velocity : F=mv/t^2 or F=p1/t
If he slows down, v diminishes and F diminishes
Hence correct Answer is C
which of the following statements about the moons of the jovian planets is true? which of the following statements about the moons of the jovian planets is true? most of the moons have the potato-like shapes of asteroids, but a few are large enough to be spherical in shape. all of the moons are barren and essentially airless, like our own moon. the moons are made almost entirely of rock and metal. even the biggest moons are smaller than any of the planets or dwarf planets in our solar system.
The statement that most of the moons of the jovian planets have the potato-like shapes of asteroids, but a few are large enough to be spherical in shape is true. Option A.
Many of the moons of the jovian planets are irregularly shaped and most of them have heavily cratered surfaces, similar to asteroids. However, some of the larger moons, such as the four Galilean moons of Jupiter and Saturn's Titan, are large enough to be rounded by their own gravity, resulting in a spherical shape.
All of the moons are airless and barren and most of them are made up of rock and metal, with a few exceptions. Even the largest of the moons are smaller than any of the planets or dwarf planets in our solar system. For example, Jupiter's largest moon Ganymede is only 5262 km in diameter, while the planet Neptune is 49528 km in diameter.
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A moving electric charge is surrounded by:
no field
an electric field only
both an electric field and a magnetic field
a magnetic field only
Answer:
both an electric field and a magnetic field
Explanation:
The last quarter phase of the moon? rises at sunrise. rises at sunset. sets at sunset. crosses the meridian at sunrise. sets at sunrise.
The correct answer for the The last quarter phase of the moon is it crosses the meridian at sunrise .
A third quarter moon, or last quarter moon, rises around midnight and sets around noon. The Moon is nearly back to the point in its orbit where its dayside faces the Sun directly, and all we see from our vantage point is a thin curve.
The Last or Third Quarter is when we can see half of the Moon's illuminated portion and half of its shadow portion. This is why this phase is commonly referred to as Half Moon. We can only see half of the Moon because it is at a 90-degree angle to the Earth and Sun.
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A 2.6-kg silverware drawer does not slide readily. The owner gradually pulls with more and more force, and when the applied force reaches 5.8 N, the drawer suddenly opens, throwing all the utensils to the floor. What is the coefficient of static friction between the drawer and the cabinet?
A 2.6-kg silverware drawer does not slide readily. The owner gradually pulls with more and more force, and when the applied force reaches 5.8 N, the drawer suddenly opens, throwing all the utensils to the floor.The coefficient of static friction between the drawer and the cabinet is 0.227.
The coefficient of static friction between the drawer and the cabinet can be determined with the help of the following Identify the given and required values Given values:
Mass of the drawer, m = 2.6 kg Applied force, F = 5.8 N
Required values: Coefficient of static friction, μs
Determine the force of static friction The force of static friction can be calculated using the formula:Ff = μsFn where Ff is the force of static friction, μs is the coefficient of static friction, and Fn is the normal force acting on the object.As the drawer is at rest before the force is applied, the normal force acting on the drawer is equal to its weight.W = mg where W is the weight of the drawer and g is the acceleration due to gravity.Substituting the values in the above equation, we get:
W = 2.6 kg × 9.8 m/s²
= 25.48 N
The force of static friction can now be calculated as: Ff = 5.8 N
Calculate the coefficient of static friction Substituting the values in the formula:
Ff = μsFn we get:
5.8 N = μs × 25.48 Nμs
= 5.8 N / 25.48 Nμs
= 0.227
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The function of the thick outer coverings of insects and reptiles like rattlesnakes in desert biomes is to ____.
Answer:
Shed
Explanation:
Snakes have to shed, or else their skin will become really crusty and flaky. Especially the ones that live in a desert. The sun destroys their skin, as it isn't as strong as ours.
The energy of an electromagnetic wave is related to its amplitude.
Answer:
True
Explanation:
The energy carried by a wave is proportional to its amplitude squared. The larger the strength of the electric and magnetic fields, the more work they can do and the greater the energy the electromagnetic wave carries. A wave's energy is proportional to its amplitude squared (E2 or B2).
Your dog is begging for food while you eat dinner. Your mother gives him a morsel from her plate, and he stops barking. In
this situation, your dog has been and your mother has been
classically conditioned; punished
positively reinforced; negatively reinforced
negatively reinforced; punished
operantly conditioned; positively reinforced
Answer:
Explanation:
operantly conditioned; positively reinforced
(PLEASE HELP ASAP)
In what ways can you determine the number of valence electrons in an atom
using the periodic table? (select all that apply)
The number of valence electrons equals the number in the ones place for groups 3-12
The number of valence electrons equals the number in the ones place for groups 1,2 and 13-18
The number of valence electrons equals the number in the tens place for groups 1,2and 13-18
The number of valence electrons equals the number in front of the "A" for groups 1A-80
Answer:
The valency of atoms can be determined by looking at the groups of the periodic table. Hope this helps!
Explanation:
200g of water at 90 degree celsius is mixed with 100g of water at 30 degree celsius. What is the temperature
Answer:
For temperatures between the freezing and boiling point of water, the heating curve is linear. Thus, we can use:
((200 * 90) + (100* 30))/300
Or: ((200 * 90)(temperature of first sample weighted by mass) + (100 * 30)(temperature of second sample weighted by mass) / (300)(total mass)
to find the final temperature.
100 can be factored out to get (2 * 90) + (1 * 30)) / 3
3 can be factored out every term: (2 * 30) + (1 * 10)
(The factoring out just makes mental math easier; if a calculator is available doing so is unnecessary.)
And then just work through the order of operations.
60 + 10
=70.
So in mathematics, which assumes a perfect world, you get 70.
PLEASE HELP ME THIS IS VERY IMPORTANT!!!!!!!!!!!!! 20 points and I will give brainlyest
The diagram below shows a portion of the rock cycle.
Diagram of the rock cycle including 4 boxes labeled A, B, C, and D. There is an arrow labeled burial cementation extending from underwater sediment to box A. There is an arrow labeled deep burial, heating and pressure extending from underwater sediment to box B. There is an arrow labeled melting connecting box B to box D. There is an arrow labeled slow crystallization connecting box D to box C.
At what location in the diagram is granite most likely formed? (4 points)
Group of answer choices
Location A
Location B
Location C
Location D
Answer: I believe it’s location D. Or whichever is the location of slow crystallization.
Explanation: Slow crystallization of magma forms granite. Hope this helps. :)
Answer:
D
Explanation:
13) For each described liquid, determine the behavior of a hydrometer calibrated around the density of pure water.
a. In a liquid less than water
b. In a liquid that is more dense than water
c. In a liquid with the same density as water
For each described liquid, determine the behavior of a hydrometer calibrated around the density of pure water In a liquid less than water. In this case Option A is correct.
An hydrometer is what?
An hydrometer is a piece of equipment with graded lines that allow for the measurement of this fraction. uses a device known as a pressure gauge, which is a tubular structure that can float when submerged in a liquid and is closed at both ends. In 1790, he created the hydrometer, a device for determining the density of liquids.
A calibrated hydrometer is what?
A formal report is delivered along with calibrated hydrometers. Hydrometers can also be calibrated for particular applications. For instance, a saccharometer measures the thickness of sugar, a lactometer measures the thickness of milk, and an alcoholometer analyzes the density of alcohol.
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A car travels 100 kilo metre due east in 2 hours. it then travels 50 kilo metre south in hour. what is its average velocity?
in order for the average velocity to be different from the avergae speed, what has to be true of the object's motion?
Answer:
ok
Explanation:
Acceleration is defined as the rate of change of velocity.
Acceleration = (Change in velocity) / time taken
Acceleration = (Final velocity - initial velocity) / time
As the object velocity changes by the same amount in each second, it means the acceleration is constant.
Select the correct answer.
What happens to the acceleration of an object if the net force on it increases?
ОА. .
The acceleration increases.
OB.
The acceleration decreases.
Ос.
The acceleration becomes zero.
OD
The acceleration remains the same.
Answer:
A
Explanation:
According to Newton's second law, acceleration is directly proportional to the net force. As the acceleration increases (when mass is constant), the net force increases. This is represented in the following formula.
\(f = ma\)
\(a = \frac{f}{m} \)
a = acceleration
f = force
m = mass
Suppose a child swings around her straight arm about her shoulder joint at an angular velocity of 13 rad/s. If her arm is 40. 0 cm long, what is the speed of her hand?.
A child swings her 40 cm (0.4 meter) long, straight arm around her shoulder joint at a 13 rad/s angular velocity. So, her hand is moving at 5.2 m/s every second.
What does angular velocity mean?angular velocity is the speed where an object rotates or revolves around an axis or alters the angle between two bodies. The angle between a line solely on a single body and a line on the other in the illustration serves as a representation of this displacement.
In what way does angular velocity rise?The angular velocity increases with increasing rotational angle over a certain period of time. Degrees per second (o/s), radians per second (rad/s), or revolutions per minute (rpm), if appropriate, are the units for angular velocity. An element of a vector is angular velocity.
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\( \textbf{What do you mean by Refractive Index ?}\)
\( \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \)
\( \qquad \tiny{ \sf \: no \: \: classes \: \: today {}^{} . \: it \: feels \: so \: relaxing \: \sqrt{} }\)
Rarefaction is the reduction of an item's density, the opposite of compression.Rarefaction is the reduction of an item's density, the opposite of compression.
Answer:
The Refractive Index (RI) is defined as the ratio of the speed of light in a vacuum to its speed in the sample medium.
Formula:-
\(n = \displaystyle{ \frac{c}{v} }\)
Where,
c is the speed of light and v is the phase velocity of light.
As a woman holding her breath swims deeper and deeper beneath the water's surface, her density __________.
A) increases
B) remains the same
C) decreases
As a woman holding her breath swims deeper and deeper beneath the water's surface, her density (mass per unit volume) increases. This is because water pressure increases with depth, causing compression of the air in the lungs, making the lungs and the woman's body more compact.
The decreased volume of the lungs and the increased pressure on the body cause an increase in the woman's density, making it easier for her to sink. Once the woman reaches a certain depth, she will no longer be able to sink because her buoyancy force is equal to her weight. At this point, she will stop sinking and start to float.
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An issue the students encountered is that the marble doesn't land on the launch pad all of the time. To remedy this, they consider constructing a funnel to help direct the marble. How do you suggest the students move forward with their design process in order to find a solution?
A Test funnels of the same size and material with varying sized openings.
B Test funnels of the same shape and size with varying materials.
C Test funnels with identical openings and material with varying size.
D Test all of the above funnels and then construct a funnel with the best design elements from each.
I suggest that the students move forward with option A.
Test funnels of the same size and material with varying sized openings. This will allow them to determine the optimal size for the opening that will help direct the marble to the launch pad. Once they have determined the optimal size, they can move forward with constructing the funnel with that size opening.
1. A 3 bladed fan is spinning at 16.7 revs/sec in a very dark room. If a flashing light (called a strobe light) flashes at just the right frequency, the spinning blades look motionless. What is the shortest time, in seconds, between flashes that will make the fan appear to be stopped?
Answer:
P = 1 / f = 1 / 16.7 = .06 sec period of 1 revolution
Period of 1/3 revolution = .06 s / 3 = .02 sec
If the light flashes every .02 sec the fan will appear motionless
i really really need help with this so please help me for a better grade asap
Answer :
Imma just put it in the explanation
Explanation:
Electric to sound : Radio
Chemical to thermal+radiant+sound+kinetic : Fireworks
Gravitational to kinetic+sound : Waterfall
Chemical to thermal+kinetic : Drinking water (not sure what last answer is called but its supposed to match the girl drinking water lol)
hope this helps
32. If a ball is given a push so that it has an initial velocity of 2 m/s down a certain inclined plane, then the distance it has rolled after t seconds is s = 2t + t2. How long does it take for the velocity to reach 24 m/s? (a) 2 seconds (b) 4 seconds (c) 5 seconds (d) 11 seconds (e) 12 seconds
If a ball is given a push so that it has an initial velocity of 2 m/s down a certain inclined plane, then the distance it has rolled after t seconds is s = 2t + t². Then it takes 11 seconds for the velocity to reach 24 m/s. The correct option is D.
To find the time it takes for the velocity of the ball to reach 24 m/s, we need to solve for the time when the velocity function equals 24 m/s.
The velocity function is the derivative of the distance function, so we'll first find the derivative of the distance function s = 2t + t² with respect to time t:
ds/dt = d/dt(2t + t²)
ds/dt = 2 + 2t
Now we can set the velocity function equal to 24 m/s and solve for t:
2 + 2t = 24
Subtracting 2 from both sides:
2t = 22
Dividing both sides by 2:
t = 11
Therefore, it takes 11 seconds for the velocity to reach 24 m/s.
The correct answer is (d) 11 seconds.
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14. A load of bricks is being lifted by a crane at the steady velocity of 16ft/sec, but 20ft above the ground one brick falls off. Describe the motion of the free brick by sketching x(t). (a) What is the greatest height the brick reaches above the ground? (b) How long does it take to reach the ground? (c) What is its speed just before it hits the ground?
The maximum height reached by the brick above the ground is 20 ft. The time taken by the brick to reach the ground is 0 seconds. Free-fall motion (uniformly accelerated motion) after falling from a height of 20 feet. Further, the acceleration experienced by the free brick is equal to the acceleration due to gravity which is approximately 32ft/sec², downward.
Hence, we can write its acceleration as, a = g = 32ft/sec².
Here, u = 0 as the brick was not moving initially while it was at rest on the top of the load of bricks.
Now, the value of v(t) can be obtained by integrating the above expression w.r.t. time as shown below:v(t) = u + a.t = 0 + 32t = 32t ...(1)
The value of x(t) can be obtained by integrating the expression for v(t) w.r.t. time, i.e. t as shown below :x(t) = (1/2).a.t² + u.t + x₀ = (1/2).32t² + 0 + 20ft = 16t² + 20ft ...(2)
Here, x₀ = 20ft is the initial displacement of the brick above the ground.
Now, we can answer the questions as follows:
(a) Using the following relation: v = u + a.t = 0 when the brick is at its highest point.
Hence, the time taken to reach this point can be obtained as follows:0 = u + a.t ⇒ t = (-u/a) = (0/32) sec = 0 secThis means that the brick reaches its maximum height at t = 0 sec, which is the initial moment.
Thus, the maximum height reached by the brick above the ground is, x(0) = 16.0² + 20 = 20 ft
(b) The time taken by the brick to reach the ground can be obtained by using the following relation: x(t) = 0.
Here, we are interested in finding the value of t.
Hence, we can substitute x(t) from equation (2) above and equate it to 0 to obtain the value of t as shown below:16t² + 20 = 0 ⇒ t² = -(20/16) sec².
This means that the brick doesn't take any finite time to reach the ground from its maximum height.
This is because it falls vertically downwards from a height of 20 ft under the action of gravity.
Thus, it reaches the ground at t = 0 sec only.
(c) The speed of the brick just before it hits the ground can be obtained by using the expression for v(t) from equation (1) above and substituting t = 0 sec (just before it hits the ground) as shown below:
v(0) = 32(0) = 0 ft/sec.
Hence, the speed of the brick just before it hits the ground is 0 ft/sec.
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what must be the pressure difference between the two ends of a 1.6km section of pipe, 29 cm in diameter, if it is to transport oil (p= 950 kg/m3 ,n = 0.20 Pa. s) at a rate of 650 cm3/s?
Answer:
The pressure difference required between the two ends of the 1.6 km pipe section, with a diameter of 29 cm, to transport the oil at a rate of 650 cm^3/s, is approximately 0.398 Pa.
Explanation:
To calculate the pressure difference between the two ends of a pipe, we can use the Poiseuille's Law equation, which relates flow rate, viscosity, pipe length, diameter, and pressure difference.
The formula is as follows: ΔP = (8 * n * L * Q) / (π * r^4)
Where:
ΔP is the pressure difference,
n is the viscosity of the fluid,
L is the length of the pipe section,
Q is the flow rate,
and r is the radius of the pipe (half of the diameter).
Given:
L = 1.6 km = 1600 m (convert to meters)
Diameter = 29 cm
Radius (r) = 29 cm / 2 = 14.5 cm = 0.145 m (convert to meters)
Q = 650 cm^3/s = 650 * 10^-6 m^3/s (convert to cubic meters per second)
n = 0.20 Pa.s (viscosity)
p = 950 kg/m^3 (density)
ΔP = (8 * 0.20 * 1600 * 650 * 10^-6) / (π * (0.145)^4)
ΔP ≈ 0.398 Pa
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PLEASE HELP MEE PLEASE I BEG
Explanation: (I think)
Plug your values into the momentum equation.
So m1= 63kg
m2 = 10 kg
V1 = 12 m/s
And then plug in your values and solve for your unknown (v2)