cubic centimeter (cm^3) has the same volume as a

I believe it's (C). Valence electron pairs will move as far apart from each other as possible.

Explanation:

The formal definition that is the basis for VSEPR is as follows:

Pairs of electrons in the valence shell of a central atom of a molecule repel each other and take up positions as far apart as possible.

Answer:

0.600

Explanation:

Hope this helps!

Explanation:

Chemistry is the scientific discipline involved with elements and compounds composed of atoms, molecules and ions: their composition, structure, properties, behavior and the changes they undergo during a reaction with other substances.

(c) 2AgNO3 + Ni --> Ni(NO3)2 + 2Ag

Al(oh)3 has a Ksp of 1.26 x \(10^{-33}\). Its molar solubility is 2.6 x \(10^{-9}\) M . So the correct option is (c).

With this knowledge, you may calculate the molar solubility, or the number of moles that can dissolve per liter of solution before the solution becomes saturated. Ksp is a function of temperature. The units are expressed in moles per liter, also abbreviated as mol/L or M.

The solubility and the solubility product constants are related in that one can be used to calculate the other. In other words, since Ksp is actually the product of the solubility of each ion in moles per liter, there is a link between the solute's molarity and the solubility of the ions.

Therefore, Al(oh)3 has a ksp of 1.26 x \(10^{-33}\). Its molar solubility is 2.6 x \(10^{-9}\) M . So the correct option is (c).

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The enthalpy of combustion can be determined using the heat transfer equation and the energy balance equation.
To determine the enthalpy of combustion, we can use the energy balance equation, which states that the energy released by combustion must be equal to the energy absorbed by the products and the surroundings.

First, we need to calculate the energy released by combustion. The power produced by the engine is given as 150 kW, and the heat loss from the engine is given as 205 kW. Therefore, the net energy released by combustion is 150 kW - 205 kW = -55 kW (negative sign indicates energy release).

Next, we need to calculate the energy absorbed by the products and the surroundings. This can be done by considering the enthalpy change of the reactants and products.

The air enters at 45°C and leaves at 750 K, resulting in an increase in temperature of 750 K - 45°C = 705 K.

The liquid Iso-octane fuel is burned with 50% excess air, which means that the amount of air used is 1.5 times the stoichiometric requirement.


Finally, we can calculate the enthalpy of combustion as the sum of the net energy released by combustion and the energy absorbed by the products and surroundings.

In summary, to determine the enthalpy of combustion, we need to calculate the energy released by combustion and the energy absorbed by the products and surroundings.

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The balanced chemical equation is:

0.5C7H16 + O2 → 0.5CO2 + H2O

For balancing the chemical equation C7H16 + O2 → CO2 + H2O, we can use linear algebraic techniques. We need to determine the coefficients that balance the number of atoms on both sides of the equation.

Let's denote the coefficients for C7H16, O2, CO2, and H2O as a, b, c, and d, respectively.

The balanced chemical equation can be written as:

aC7H16 + bO2 → cCO2 + dH2O

To balance the carbon (C) atoms, we have:

7a = c (Equation 1)

To balance the hydrogen (H) atoms, we have:

16a = 2d (Equation 2)

To balance the oxygen (O) atoms, we have:

2b = 2c + d (Equation 3)

We have three equations (Equations 1, 2, and 3) and four unknowns (a, b, c, d). To solve this system of equations, we can write it in matrix form and find the solution using linear algebraic techniques.

The augmented matrix for the system of equations is:

[ 7 0 -1 0 | 0 ]

[ 0 0 0 -2 | 0 ]

[ 0 -2 2 -1 | 0 ]

By performing row operations to row-reduce the augmented matrix, we can obtain the solution:

[ 1 0 -0.5 0 ]

[ 0 1 -1 -0.5 ]

[ 0 0 0 0 ]

The solution to the system of equations is:

a = 0.5

b = 1

c = 0.5

d = 1

Putting the values of a,b,c, and d we get the balanced chemical equation as:

0.5C7H16 + O2 → 0.5CO2 + H2O

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The experiment involving cations, CO32-, involves preparing a list of the cations that would not be present in a solution. Here, the following cations could not be present in a solution if carbonate ions, CO32-, were also present in the solution:Ag+, Ba2+, Ca2+, Co2+, Cu2+, Fe3+, Mg2+, Mn2+, Ni2+, Pb2+, Sr2+, and Zn2+.

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Here's the main answer to the question along with the explanation of how to arrive at the To prepare a list of cations that couldn't exist in a solution when carbonate ions are present in that solution, the first step is to identify the chemical reactions that are going .

to happen between the cations in solution and the carbonate ions (CO32-). The following reactions occur:CO32- + 2H+ → H2O + CO2↑CO32- + Ca2+ → CaCO3(s)CO32- + Ba2+ → BaCO3(s)The cations that react with carbonate ions to produce precipitates are:Ca2+, Ba2+, and Pb2+. If any of these cations are present in a solution with carbonate ions, they'll react with the carbonate ions and fall out of solution. Hence, these cations cannot exist in a solution where carbonate ions are present. A solution's pH can be adjusted by adding a buffer solution that resists changes in pH upon the addition of small amounts of acids or bases. A buffer solution, for example, could be added to keep the insoluble hydroxide from forming.

The buffer solution can be used to maintain a stable pH range, which will prevent the hydroxide ions from reacting with the H+ ions in the solution to form an insoluble hydroxide. This will ensure that the solution remains in a stable state without any precipitation occurring. In conclusion, the long answer is:If a solution contains carbonate ions (CO32-), certain cations will not be able to exist in that solution. When the carbonate ions (CO32-) react with Ca2+, Ba2+, or Pb2+, they'll produce precipitates and fall out of solution. As a result, Ca2+, Ba2+, and Pb2+ cations cannot exist in a solution containing carbonate ions. The addition of buffer solutions can be used to keep insoluble hydroxides from forming. Buffer solutions resist changes in pH upon the addition of small amounts of acids or bases. By keeping the pH in the correct range, hydroxide ions can be prevented from reacting with H+ ions to form an insoluble hydroxide, thus keeping the solution stable without any precipitation.

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The net ionic equation for the behavior of ethylamine (C₂H₅NH₂) as a Bronsted-Lowry base in water is:

C₂H₅NH₂ + H₂O → C₂H₅NH₃⁺ + OH⁻

The net ionic equation for the behavior of benzoic acid (C₆H₅COOH) as a Bronsted-Lowry acid in water is:

C₆H₅COOH + H₂O → C₆H₅COO⁻ + H₃O⁺

In water, ethylamine (C₂H₅NH₂) can act as a Bronsted-Lowry base by accepting a proton (H⁺) from water. The reaction can be represented by the net ionic equation: C₂H₅NH₂ + H₂O → C₂H₅NH₃⁺ + OH⁻. In this equation, ethylamine (C₂H₅NH₂) accepts a proton from water (H₂O) to form the ethylammonium ion (C₂H₅NH₃⁺) and hydroxide ion (OH⁻). This shows the base behavior of ethylamine as it accepts a proton.

On the other hand, benzoic acid (C₆H₅COOH) can act as a Bronsted-Lowry acid in water by donating a proton (H⁺) to water. The reaction can be represented by the net ionic equation: C₆H₅COOH + H₂O → C₆H₅COO⁻ + H₃O⁺.

In this equation, benzoic acid (C₆H₅COOH) donates a proton to water (H₂O) to form the benzoate ion (C₆H₅COO⁻) and hydronium ion (H₃O⁺). This demonstrates the acid behavior of benzoic acid as it donates a proton.

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Answer:

because of static energy that's why and gravity

Answer:

ice, air, ducks and fabric

Explanation:

its common sense

Answer: option c) the strongest base in aqueous solution is NaOH

Explanation:

the strongest base in aqueous solution is NaOH because strength of a base is determined by its ability to donate hydroxide ions (OH-) in solution. and NaOH dissociates completely in water to produce Na+ and OH- ions. The presence of a fully dissociated hydroxide ion makes NaOH a strong base.

While, HOC2H4OH and CH3OH are weak acids. HOC2H4OH is ethylene glycol and CH3OH is methanol are weak acid due to the presence of the   (-OH) group.

Also, NH3 (ammonia), is a weak base though it can accept H⁺ to form NH4+

Therefore, +17 + (-10) = +7 is the effective nuclear charge. Simply counting the number of electrons in the outer shell—without applying any charges—will get the same result. That would be the 3s2 3p5 for Cl, where 2 + 5 = 7.

Use the formula Zeff = Z - S, where Z is the atomic number and S is the number of shielding electrons, to calculate the effective nuclear charge of an atom. By deducting the number of valence electrons from the total number of electrons in the atom or ion, one can calculate the number of shielding electrons. Effective nuclear charge (Zeff) is an atom's net positive charge that attracts an electron. The closest estimate of this net charge is. Effective nuclear charge (Zeff) is calculated as Z minus Zcore.

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The car's displacement is 5 m downwards and the distance traveled is 5 m.

The displacement of the car is calculated as follows;

The displacement is the change in position of the car.

D = Δx

D = X2 - X1

D = 20 m - 15 m

D = 5 m downwards

The distance is path covered, and it has no direction.

Distance = 20 m  - 15 m = 5 m

Thus, the car's displacement is 5 m downwards and the distance traveled is 5 m.

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Answer:

The options that apply to the description of grid-lines of the map are;

They are measured in degrees

They set up a reference system

They divide Earth into four equal parts

FIRST OPTION , SECOND OPTION and FIFTH OPTION are correct.

Explanation:

FIRST OPTION gave the describtion that the grid-lines of the map are measure in degrees,this option is applied to the gridlines on a map because the grid are lined as a result of angular measurement which makes it to makes the unit to be measured degrees and angles.

SECOND OPTION described it as been set up by a reference system which let us know that the area that are plotted were all grid as a result of the size

FIFTH OPTION also applied to the

description of the gridlines on a map because the Earth is divided into 4 equal parts through the Prime Meridian i.e the latitudinal line and longitudinal line .

.

Answer:

They are measured in degrees.

They set up a reference system.

They divide Earth into four equal parts.

Explanation:

i took the test

Answer: bulbs

Explanation: Daffodils and tulips are examples of bulbs.

Answer: Bulbs

Explanation: When you plant daffodils or tulips, you will see that the "seeds" are onion-like. Onions are bulbs, and so are daffodils and tulips.

Hydrogen bonds exist in the water molecule below.

Only molecules in which hydrogen is covalently bound to either fluorine, oxygen, or nitrogen experience hydrogen bonding. These three elements are sufficiently electronegative that they remove the majority of the electron density from the hydrogen atom's covalent link, leaving the latter atom with an extremely low electron density.

A hydrogen atom that is connected to an electronegative atom moves toward another electronegative atom nearby to form hydrogen bonds, which are potent intermolecular forces. The hydrogen-bond strength will rise as the hydrogen bond acceptor's electronegativity increases.

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If we observed a weld that had a diameter of 235 that had a strength 1000,the residual is -79.

What is diameter?

The line through the Centre of a circle with two extremes on its circumference is referred to as a circle's diameter.

What is residual?

The residue refers to the insoluble (undissolved) contaminants that remain on the filter paper after filtration.

1) if the diameter is 201 then, we would expect the mean strength to be 864.

2) we should not use the least square regression line to calculate this value as value of diameter s¹ is out of given, range of diameter.

3) Δ= 941.6992+8.5988* 235

= 1079.0188

Residual = 1000- 1079.0188

= -79

Therefore, If we observed a weld that had a diameter of 235 that had a strength 1000,the residual is -79.

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To determine how long it will take for the concentration of XY to decrease to 12.5% of its initial concentration, we need to use the concept of reaction order and the rate equation.

Without information about the specific reaction and its rate constant, it is not possible to provide an exact time. However, I can explain the general approach to solving such a problem.

The rate equation for a reaction can be expressed as:

rate = k[A]^n

Where:

- k is the rate constant

- [A] is the concentration of the reactant

- n is the reaction order with respect to reactant A

In this case, we assume the reaction is first-order, meaning that the reaction rate is directly proportional to the concentration of the reactant.

If the concentration of XY decreases to 12.5% of its initial concentration, it means the concentration remaining is 0.125 times the initial concentration.

Using the exponential decay formula for a first-order reaction:

[A] = [A]₀ * e^(-kt)

Where:

- [A] is the concentration at time t

- [A]₀ is the initial concentration

- k is the rate constant

- t is the time

We can rearrange the equation to solve for time t:

t = (ln([A] / [A]₀)) / -k

Substituting the values, [A] = 0.125 [A]₀ and [A]₀ = 0.100 mm, we have:

t = (ln(0.125 * [A]₀) / -k

Without the specific rate constant (k) for the reaction, it is not possible to determine the exact time required for the concentration to decrease to 12.5% of its initial concentration. The rate constant can vary depending on the reaction and its conditions.

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The incorrect statement is, "reaction rate is the speed at which the reaction proceeds towards equilibrium".

The rate of the reaction is defined as the rate at which the reaction is taking place.

It is true that the rate of reaction is governed by the energy barrier between the reactant and the products.

Enzymes are special compounds which can accelerate the rate of reaction.

The rate of reaction is independent of the rate of temperature of the system. The rate of reaction depends on the concentration of the reactants.

Rate of the reaction is directly proportional to the increase in concentration of products.

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Answer: The percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.

Explanation:

Given: Volume of solute = 120 mL

Volume of solvent = 350 mL

Now, total volume of the solution is as follows.

\(V_{total} = V_{solute} + V_{solvent}\\= 120 mL + 350 mL\\= 470 mL\)

Let us assume that 100 mL of solution is taken and the amount of isopropyl alcohol present in it is as follows.

\(\frac{V_{solute}}{V_{total}} \times 100 mL\\\frac{120 mL}{470} \times 100 mL\\= 25.53 mL\)

Hence, there is 25.53 mL isopropyl alcohol is present in 100 mL of solution. Therefore, %v/v is calculated as follows.

\(Percent (v/v) = \frac{25.53 mL}{100 mL}\\= 25.5%\)

Thus, we can conclude that the percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.

Answer:

As blood travels through the body, oxygen is used up, and the blood becomes oxygen poor. Oxygen-poor blood returns from the body to the heart through the superior vena cava (SVC) and inferior vena cava (IVC), the two main veins that bring blood back to the heart.

Explanation:

The concentration of acetic acid in the original vinegar solution is 0.0435M.

Balanced chemical equation for the reaction between acetic acid (CH₃COOH) and sodium hydroxide (NaOH) is:

CH₃COOH + NaOH → CH₃COONa + H₂O

The number of moles of NaOH used in the titration will be calculated as;

moles NaOH = Molarity × Volume (in L)

moles NaOH = 0.1073 M × 0.02024 L

moles NaOH = 0.002174872

Therefore, the concentration of CH₃COOH in the diluted vinegar solution is;

C₁V₁ = C₂V₂

C₁ × 10.00 mL = C₂ × 50.00 mL

C₁ = (C₂ × 50.00 mL) ÷ 10.00 mL

C₁ = 5 × C₂

where C₁ is the concentration of CH₃COOH in the diluted vinegar solution, and C₂ is the concentration of CH₃COOH in the original vinegar solution.

The number of moles of CH₃COOH in the diluted vinegar solution is;

moles CH₃COOH = C₁ × V₁ (in L)

moles CH₃COOH = (5 × C₂) × 0.01000 L

moles CH₃COOH = 0.05000 × C₂

The concentration of CH₃COOH in the original vinegar solution can be calculated;

moles CH₃COOH in original vinegar = moles CH₃COOH in diluted vinegar

0.05000 × C₂ = 0.002174872

C₂ = 0.002174872 ÷ 0.05000

C₂ = 0.043

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Answer:

Hydrogen reacts with oxygen to form a compound called hydrogen peroxide so your answer is none of the above.

Explanation:

Hope it will help you :)

Answer:oxide

Explanation:

The reaction ofhydrogen and oxygen result on hydrgen peroxide which is a part is oxide

By taking these precautions, Kennedy can minimize the risk of being misled or misrepresented regarding the termite problem in Heather's home.

To reduce the risk of misrepresentation in this situation, Kennedy can take the following steps:

1. Request documentation: Kennedy can ask Heather to provide any documentation or proof of the pest control company's involvement. This may include receipts, invoices, or reports from the company.

2. Conduct an independent inspection: Kennedy can hire a professional inspector to assess the property for any signs of termite damage or infestation. This will help verify the accuracy of Heather's claim.

3. Research the pest control company: Kennedy can look up the pest control company that Heather mentioned to check its reputation and credibility. Reading reviews and checking for any licenses or certifications can provide additional assurance.

4. Consider a written agreement: If Kennedy decides to proceed with the purchase, he can include a clause in the agreement stating that Heather guarantees the absence of termites or any other pest-related issues. This way, he has legal protection if any misrepresentation is discovered later on.

By taking these precautions, Kennedy can minimize the risk of being misled or misrepresented regarding the termite problem in Heather's home.

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Answer:

Explanation:

Recall that the density of a gas is its mass to volume ratio,  

ρ

=

m

V

. Therefore, if we can determine the mass of some volume of a gas, we will get its density. The density of an unknown gas can used to determine its molar mass and thereby assist in its identification. The ideal gas law, PV = nRT, provides us with a means of deriving such a mathematical formula to relate the density of a gas to its volume

The given statement, Group 13 nitrides are isostructural and exhibit the layered graphite structure is true because Group 13 nitrides have a hexagonal close-packed layer of nitrogen atoms, with alternating layers of boron, aluminum, or gallium atoms, resulting in a layered structure that resembles graphite due to comparable atomic radii and electronegativities of the elements.

Group 13 nitrides, such as boron nitride (BN), aluminum nitride (AlN), and gallium nitride (GaN), are isostructural and exhibit the layered graphite structure. The basic building block of the crystal structure is a hexagonal close-packed layer of nitrogen atoms, with alternating layers of boron, aluminum, or gallium atoms. This results in a layered structure that resembles that of graphite. The similarities between the crystal structures of these materials can be attributed to the comparable atomic radii and electronegativities of the Group 13 elements.

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--The complete question is, Group 13 nitrides are isostructural and exhibit the layered graphite structure group of answer choices true false.--

Answer:

different types of waves are due to how and where they are formed

Explanation:

Don't give me brainliest I only know first part.

Answer:

An atom of Sulfur

Explanation:

i did a Quick search and im trying to get pass the "help a person first"

Answer:

• A collection of atoms of Sulfur

Explanation:

I'll assume the notation is written as \(S_{8}\).  A subscript after an element symbol represent the number of individual atoms of the symbol.  In this case \(S_{8}\) is telling us we have 8 sulfur atoms that are somehow connected to each other.  That is in contrast with 8S, which means we have 8 different sulfur atoms.  A chemical formaula, such as \(CH_{4}\) tells us we have a molecule containing 1 carbon atom and 4 hydrogen atoms.