Could someone please help me out? ‘Preciate it

Answer:

43

Step-by-step explanation:

All the even numbers have a factor of 2, so we can eliminate 56 and 34. 75 ends in a 5, so that cannot be a prime number (ending in 5 is a multiple of 5). The sum of the digits of 63 (6+3) is 9, and that is divisible by 3, so that number is also not prime. 43 is a prime number.

Hello there. To solve this question, we want to determine an inequality that shows the relation between the total number of miles each of Jane and Kevin ran.

We know that Jane ran 3 miles each day for x days and Kevin ran 4 miles each day for y days.

The total number of miles Jane ran is given by the product of how many miles she ran each day and the number of days. It gives:

Next, the total number of miles Kevin ran is given by the product of how many miles he ran each day and the number of days. Then we get

Knowing that the total number of miles Jane ran is greater than the total number of miles Kevin ran, we simply have that

This is the inequality we're looking for.

Answer: which one

Step-by-step explanation:

All closed intervals of length 1 in which a function has a unique zero, we need to find all pairs of zeros that are exactly 1 unit apart and consider the intervals between them as described above.

To find all closed intervals of length 1 in which a function has a unique zero, we need to look for intervals where the function changes sign exactly once. This is because if a function has a unique zero, it must change sign from positive to negative or negative to positive at that point.

Let's call the function f(x). To find these intervals, we can use the Intermediate Value Theorem. This theorem states that if a function is continuous on a closed interval [a, b] and takes on values f(a) and f(b) at the endpoints, then it must also take on every value between f(a) and f(b) somewhere on the interval.

So, to apply this theorem, we need to find values of x such that f(x) = 0. Then, we can look at the intervals between these values and see if f(x) changes sign exactly once on any of them.

Let's say we find two zeros of the function at x = a and x = b, where a < b. Then, we can consider the intervals [a, a+1] and [b-1, b] (assuming these intervals have length 1). If f(x) is positive on the interval [a, a+1] and negative on the interval [b-1, b], or vice versa, then f(x) must change sign exactly once on each of these intervals and therefore has a unique zero in each interval.

In general, to find all closed intervals of length 1 in which a function has a unique zero, we need to find all pairs of zeros that are exactly 1 unit apart and consider the intervals between them as described above.

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Population: All American households.

Sample: The 1780 American households surveyed.

Individuals: The American households participating in the survey.

In the given scenario, we have a survey of 1780 American households that found 59% of the households own a computer. Let's identify the population, sample, and individuals in the study:

Population: The population refers to the entire group or larger set of individuals that we are interested in. In this case, the population would be all American households.

Sample: The sample is a subset of the population that is chosen to represent the population accurately. In this situation, the survey includes 1780 American households. Therefore, the sample is the 1780 households that were surveyed.

Individuals: The individuals in the study are the specific units or elements being surveyed or examined. In this case, the individuals are the American households that participated in the survey. Each household represents an individual within the study.

To summarize:

Population: All American households.

Sample: The 1780 American households surveyed.

Individuals: The American households participating in the survey.

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Step-by-step explanation:

ans...9days.......,........

Answer:

It's C 2x - 4

Step-by-step explanation:

The limit of the derivative of a function as x approaches c may exist even if the derivative of the function at c does not exist. If \($\lim_{x\to c}\) \(f'(x)$\) exists, then \($f'(c)$\) may or may not exist.

To see why, consider the function \(f(x) = |x|\), which has a sharp point at \(x=0.\) The derivative of \(f(x)\) is \(f'(x) = -1\) for \(x < 0\) and \(f'(x) = 1\)for \(x > 0\), but \(f'(0\)) does not exist since the left and right limits of the derivative at \(x=0\) are not equal.

Therefore, while the existence of the limit of the derivative as x approaches c is a necessary condition for the existence of the derivative at c, it is not a sufficient condition. Additional analysis is required to determine whether or not the derivative of the function exists at c.

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The cost of one computer is £600 and the cost of one printer is £800.

Computing equipment is bought from a supplier. The cost of 5 Computers and 4 Printers is £6,600, and the cost of 4 Computers and 5 Printers is £6,000. Form two simultaneous equations and solve them to find the costs of a Computer and a Printer.

Let the cost of a computer be x and the cost of a printer be y.

Then, the two simultaneous equations are:5x + 4y = 6600 ---------------------- (1)

4x + 5y = 6000 ---------------------- (2)

Solving equations (1) and (2) simultaneously:x = 600y = 800

Therefore, the cost of a computer is £600 and the cost of a printer is £800..

:Therefore, the cost of one computer is £600 and the cost of one printer is £800.

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Answer:

Answer D.

Step-by-step explanation:

Because all the other tables don't show enough lunch combinations for the students.

Answer:

Given function

#15 Find the inverse of h(x)

Substitute x with y and h(x) with x and solve for y:

The inverse is:

#16 The graph with both lines is attached.

The x- and y-intercepts of both functions have reversed values.

#17 Table of the inverse function  will contain same numbers with swapped domain and range.

Initial look is like this:

The rest of the table is filled in by finding the values:

Yes , there can be a Right triangle with two side lengths as simple fraction and other side length as an integer .

In the question ,

we have to find , whether a Right Triangle can be made by two fractions and an integer length .

yes, we can make a Right Triangle with two lengths as fractions and other length as integer .

let us prove it with the help of an example .

Consider the triplet 7 , 24 , 25 .

let the two fractions side be 7/25 and 24/25 , and the hypotnuse of the right triangle be  1 .

We know that for the Right Triangle

(side1)² + (side2)² = hypotnuse²

(7/25)² + (24/25)² = 1²

49/625 + 576/625 = 1

(49+576) / 625 =1

625/625 = 1

1 = 1

hence ,it is a Right Triangle .

Therefore , Yes , there can be a Right triangle with two side lengths as simple fraction s and other side length as an integer .

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Answer:

B

Step-by-step explanation:

Using the conversion

1 Kg = 1000 g , then

3745 ÷ 1000 = 3.745 Kg

The percentage of time he exceeds 13,000 steps is 2.28% or 0.0228.

Percentage

Use the percentage formula to express a number or percentage in terms of 100. % simply indicates one out of one hundred. An expression for a number between 0 and 1 can be made using the percentage formula. It is a number that is represented as a fraction of 100. The sign % is used to denote it and it is mostly used to compare and calculate ratios. The formula for percentage increases is the ratio of the increased value to the original value multiplied by 100. It is described in percentage form. If anything is valued more highly, both its value and proportion will rise.

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Answer:

Corresponding angles

Step-by-step explanation:

The name of these angels lying in the same position are called corresponding angle.

These angles are equal. When we talk of parallel lines, they are sets of lines that travel in the same direction but never meet. The third line that cuts through the two sets of parallel lines is referred to as the transversal line.

So the positions of these angles on each of the set of the parallel lines are equal in each of the cases and they are equal and are referred to as being corresponding to each other

Answer:5

Step-by-step explanation:

20/4=5

The equation of a line of best-fit that reflects a negative correlation is y = mx + b, where the slope m is negative.

When analyzing a scatter plot, a negative correlation indicates that as the independent variable increases, the dependent variable decreases. In the equation y = mx + b, the negative slope m represents the rate of decrease in the dependent variable for each unit increase in the independent variable. A negative slope means that as the x-values increase, the corresponding y-values decrease. The y-intercept b represents the value of the dependent variable when the independent variable is zero. Thus, the equation y = mx + b with a negative slope indicates a negative correlation between the variables being studied.

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"What is the equation of the line of best fit that represents a negative correlation between two variables?"

Given:

Speed to train = 200km/h

The train sets off from Station A at 12:24.

Reaches station B at 14:12.

To find:

The distance between both stations.

Solution:

We have,

Speed to train = 200km/h

Time taken by the train to cover the distance between station A and station B is the difference between 14:12 and 12:24.

Time = 1 hr 48 min

Time = 1.8 hours            [ 1 hr = 60 minutes]

Let d be the distance between both stations.

We know that,

\(Speed=\dfrac{Distance}{Time}\)

\(200=\dfrac{d}{1.8}\)

\(200\times 1.8=d\)

\(360=d\)

Therefore, the distance between the two stations is 360 km.

Answer:

Step-by-step explanation:

||y + 6|| = 10

Next, we can consider the two possible cases:

Case 1: y + 6 ≥ 0

If y + 6 is non-negative, then the absolute value of y + 6 is just y + 6 itself. So we have:

y + 6 = 10

y = 4

Case 2: y + 6 < 0

If y + 6 is negative, then the absolute value of y + 6 is the opposite of y + 6, which is -(y + 6). So we have:

-(y + 6) = 10

y + 6 = -10

y = -16

Therefore, the solutions to the equation 3||y + 6|| = 30 are y = 4 and y = -16.

The domain and range of the function are (-8, 9] and (-4, 4] respectively

What are domain and range of a function ?

The range of values that we are permitted to enter into our function is known as the domain of a function. In a function like f, this set represents the x values (x). The collection of values that a function can take on is known as its range. The values that the function outputs when we enter an x value are in this set.

Open dot represents, the value is not included

Closed dot represents, the value is included

The x values are taken from -8 to 9

-8 is not included

Domain is (-8, 9]

The y values are taken from -4 to 4

-4 is not included

Range is (-4, 4]

The domain and range of the function are (-8, 9] and (-4, 4] respectively

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The speed (v) of a wave is v = (3.5 / θ) * (88 / (2π)).

To determine the frequency, wavelength, and speed of the wave, we can analyze the given wave equation:

D(y,t) = (2.5 cm)sin(3.5y + 88t)

(a) Frequency:

The frequency (f) of a wave is the number of complete cycles it completes per unit time. In this case, the coefficient of t in the sine function argument is 88.

Since the argument of the sine function represents a complete cycle (2π) when it increases by 2π, we can equate it to 2π and solve for the frequency.

3.5y + 88t = 2π

From this equation, we can see that the frequency is given by f = 88 / (2π).

(b) Wavelength:

The wavelength (λ) of a wave is the distance between two consecutive points that are in phase, i.e., the distance between two adjacent crests or troughs. We can determine the wavelength by comparing the argument of the sine function to the general form of a sine wave.

In the given equation, the argument of the sine function is (3.5y + 88t). We can equate this to the phase angle (θ) times the wavelength (λ):

3.5y + 88t = θ * λ

Since the coefficient of y is 3.5, we can equate it to the phase angle (θ) multiplied by the wavelength (λ):

3.5 = θ * λ

Therefore, the wavelength is given by λ = 3.5 / θ.

(c) Speed:

The speed (v) of a wave is the rate at which it propagates through a medium. It can be calculated using the formula v = λ * f, where λ is the wavelength and f is the frequency.

Substituting the values, we obtained for wavelength and frequency:

v = (3.5 / θ) * (88 / (2π))

Simplifying this expression will give us the speed of the wave.

Please note that the value of the phase angle (θ) is not provided in the given equation, so the exact numerical values for frequency cannot be calculated, wavelength, and speed without that information.

However, the equations presented here provide a general method to determine these parameters based on the given wave equation.

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(a) The domain closed and bounded.

(b) The domain bounded.

(c) The domain closed.

(d) The domain bounded.

(e) The domain closed and bounded.

(f) The domain closed and bounded.

In this question, we have been given some domains.

We need to check which domains are closed and which are bounded.

A domain of function is said to be closed if the region R contains all boundary points.

A bounded domain is nothing but a domain which is a bounded set.

(a) {(x,y)∈R2:x^2+y^2≤1}

The domain of x^2+y^2≤1 contains set of all points (x, y) ∈R2

so, the domain closed and bounded.

(b) {(x,y)∈R2:x2+y2<1}

The domain of x^2+y^2 < 1 contains set of all points (x, y) ∈R2

so, the domain is bounded.

(c) {(x,y)∈R2: x ≥ 0}

The domain of x ≥ 0 is R2 - {x < 0}

So, the domain is closed.

(d) {(x, y) ∈ R2 : x > 0,y > 0}

The domain is R2 - {(x, y) ≥ 0}

So, the domain is bounded.

(e) {(x, y) ∈ R2 : 1 ≤ x ≤ 4, 5 ≤ y ≤ 10}

The domain is closed and bounded.

(f) {(x,y)∈R2:x>0,x^2+y^2≤10}

The domain is closed and bounded.

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Answer:

4.5611 m

Step-by-step explanation:

First we should find the area of the the total circle, which is 12.57, with a radius of 2 m. Next, we need to find the area of the square, which is 8.0089, given that both sides are 2.83 m. Finally, we subtract the square from the total, which is 12.57-8.0089 = 4.5611 m.

Hope this helps!

The height needed to reach the desired volume, 30,875.88 in³, of a rectangular prism shaped sandbox is equals to 8.4 inches.

We have a family a family is building a sandbox for their yard that is shaped like a rectangular prism. Let the dimensions of rectangular prism be l, w and h inches.

Volume of box = 30,875.88 in³

Length of box , l = 62.3 inches

Width of box, w = 59 inches

We have to determine value of h.

The volume of shape is the space covered by the shape. The volume of rectangular prism, V = l× w×h

Substitute the known values in above formula, so, 30,875.88 in³ = 62.3 × 59 in² × h

=> 30,875.88 in³ = 3,675.7 in² × h

=> h = 30,875.88 in³/3,675.7 in²

=> h = 8.4 inches

Hence, required value of height, h is 8.4 inches.

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These conversions can be carried out for any amount of mass given in grams.

0.379 g = 379 mg

787 g = 0.787 Mg

74.3 g = 0.0743 kg

1. To convert 0.379 g to mg, multiply 0.379 by 1000. 0.379 x 1000 = 379 mg.

2. To convert 787 g to Mg, divide 787 by 1000. 787 / 1000 = 0.787 Mg.

3. To convert 74.3 g to kg, divide 74.3 by 1000. 74.3 / 1000 = 0.0743 kg.

The 0.379 g was converted to 379 mg, 787 g was converted to 0.787 Mg, and 74.3 g was converted to 0.0743 kg.

The conversion of 0.379 g to mg is done by multiplying 0.379 by 1000. The result is 379 mg. To convert 787 g to Mg, divide 787 by 1000. The result is 0.787 Mg. To convert 74.3 g to kg, divide 74.3 by 1000. The answer is 0.0743 kg. In summary, 0.379 g was converted to 379 mg, 787 g was converted to 0.787 Mg, and 74.3 g was converted to 0.0743 kg. This demonstrates how to convert mass from grams to different derived units. These conversions can be carried out for any amount of mass given in grams.

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(a) g(-6) = 20, (b) g(-3) = -4, (c) g(1) = 8, (d) g(5) = 20, (e) The absolute maximum of g(x) occurs when x = 4 and its value is 20.

To determine the values of g(x), we need to evaluate the definite integral of f(t) from -4 to x. First, let's examine the function f(x) and its behavior on different intervals.

For x < -4, f(x) = 0.

For -4 ≤ x < 0, f(x) = -20.

For 0 ≤ x < 4, f(x) = 4.

For x ≥ 4, f(x) = 0.

By integrating f(t) over the given intervals, we can find the values of g(x).

(a) g(-6): Since x < -4, f(x) = 0. Therefore, g(-6) = ∫[-4, -6] f(t) dt = 0.

(b) g(-3): In this interval, f(x) = -20. So, g(-3) = ∫[-4, -3] -20 dt = -20.

(c) g(1): Here, f(x) = 4. Thus, g(1) = ∫[-4, 1] 4 dt = 8.

(d) g(5): For x ≥ 4, f(x) = 0. Thus, g(5) = ∫[-4, 5] 0 dt = 0.

(e) The absolute maximum of g(x) occurs when x = 4, and its value is 20, which is the integral of f(t) from -4 to 4.

By examining the graph of f(x), we can visualize the behavior of the function and better understand the values of g(x).

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In this stanza from Alfred, Lord Tennyson's poem "The Charge of the Light Brigade," the theme of duty is portrayed through the soldiers' unquestioning obedience to their orders.

Despite knowing that someone had made a mistake, the soldiers do not question or reason with their command; their responsibility is to "do and die."

This is significant considering the historical context of the poem, which is the Battle of Balaclava during the Crimean War.

The Light Brigade's blind obedience to their orders led them into a tragic and deadly charge against a heavily fortified enemy.

The stanza emphasizes the importance of duty in a soldier's life and the consequences it can have when orders are flawed.

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