Corey and David both have lots of video games. The number of games Corey has can be represented by x . Ricky has 3 times as many games as Corey. The total number of games is 64 . What is x, the total number of games Corey has?

The cost per second to power such a circuit during the peak usage period is approximately \(2.376 x 10^-6\)$/s. The cost per second to power the circuit during the peak usage period can be calculated using the following steps:

Calculate the power consumption of the device-The power consumption of the device can be calculated using the formula: Power = Voltage x Current. P = V x I, Substituting the given values:

P = 110V x 0.12A

= 13.2 W

Calculate the cost per second-The cost per second can be calculated using the formula:

Cost per second = Power x Cost per Joule

C = P x CC

= 13.2 W x 1.8 x \(10^-7\) $/J

≈ 2.376 x 10^-6 $/s

Therefore, the cost per second to power such a circuit during the peak usage period is approximately 2.376 x\(10^-6\) $/s.

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Average speed of train B is 60 mph.

To find average speed of train B:

Let average speed of train B = x mph.

Based on information provided to us it is said average speed of train A is 20 mph more than B.

Average speed of train A = (x + 20) mph.

Speed = Distance/ Time

The time taken by both trains will be the same since they cover their respective distances in the same time.

For train A:

Speed of train A = (x + 20) mph

Distance covered by train A = 240 miles

Time taken by train A = Distance / Speed = 240 / (x + 20) hours

For train B:

Speed of train B = x mph

Distance covered by train B = 180 miles

Time taken by train B = Distance / Speed = 180 / x hours

Since the time taken by both trains is the same, we can set up an equation:

240 / (x + 20) = 180 / x

240x = 180(x + 20)

240x = 180x + 3600

240x - 180x = 3600

60x = 3600

x = 3600 / 60

x = 60

Therefore, the average speed of train B is 60 mph.

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Answer:

A. 5

Step-by-step explanation:

Given the area of the circle is 25pi. We will divide by pi. Then, the radius of the circle is r= 5.

The branch of statistics that uses sample statistics to estimate a population parameter or test a hypothesis about such a parameter is best referred to as inferential statistics.

Therefore, the branch of statistics that uses sample statistics to estimate a population parameter or test a hypothesis about such a parameter is best referred to as inferential statistics.

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The value of the expression using algorithm is 493.29 .

An algorithm is a finite sequence of exact instructions used to solve a class of particular problems or carry out a calculation in mathematics and computer science.

The given expression is 27.405 x 18

This can be computed using algorithm of multiplication to get the result 493.29 .

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The average rate of change of 2|x| on the interval [-3, 5] is 0.5

The function is given as

2|x|

Rewrite as

f(x) = 2|x|

The interval is given as

[-3, 5]

So, we have

f(-3) = 2|-3| = 6

f(5) = 2|5| = 10

The average rate of change of 2|x| on the interval [-3, 5] is then calculated as

Rate = (f(5) - f(-3))/(5 --3)

This gives

Rate = (10 - 6)/(5 --3)

Evaluate

Rate = 0.5

Hence, the average rate of change of 2|x| on the interval [-3, 5] is 0.5

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The number of students in the telescope club by $x$ and the number of students in the math club by $y$.

$y=2x$Now, suppose there are $z$ students who are members of both clubs. Then the total number of students who are in the math club or the telescope club (or both) is given by:$x + y - z$ Substituting $y=2x$ in the above expression, we get:$x + 2x - z=3x - z$ Hence, the expression for the total number of students who are in the math club or the telescope club (or both) is $3x - z$.b)The number of students who are in the math club but not in the telescope club is given by:$y-z$ And the number of students who are in the telescope club but not in the math club is given by:$x-z$ Adding these two expressions, we get the total number of students who are in the math club or the telescope club but not both:$ y-z+x-z $.

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Answer:

4 because I know it's right

Answer:

1, 2, 3, 6

Step-by-step explanation:

I don't really know how to explain this but if the only change between the two triangles is that it was reflected, then there was no change of any of the angles or side lengths, you just have to make sure you match up the rights angles and the right sides.

Answer:

Hi how are you doing today Jasmine

The range of the relation that is represented in the mapping shown in the diagram attached below is: {3, 5, 11, 21}.

If we are given a mapping that represents a relation, the input values (x-values) make up the domain of the relation while the output values (y-values) make up the range of the relation.

In the mapping shown in the diagram attached below, we have the following:

The domain of the relation is: {-1, 0, 1, 2, 3}

The range of the relation is: {3, 5, 11, 21}

Thus, we can conclude that, the range of the relation that is represented in the mapping shown in the diagram attached below is: {3, 5, 11, 21}.

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In this triangle it is clear that the unknown side x is the hypotenuse of both the triangles that are being formed . So , let us take any one of the triangles and with it's length let us find the length of their hypotenuse which is side x .

= 5² + 5² = x² ( according to the pythagorean theorem the square on the hypotenuse will be equal to the sum of the squares on the other two legs )

= 25 + 25 = x²

= 50 = x²

= 7.0710678119 = x

But they have given that we have to round it off to the nearest tenths , so ;

= 7.0710678119 will be equal to = 7.10

= 7.1 = x

Therefore , the length of the unknown side x = 7.1 .

The inequality expression of x is at least 8 is x ≥ 8

From the question, we have the following parameters that can be used in our computation:

x is at least 8

The term at least in inequality means greater than or equal to

i.e. ≥

using the above as a guide, we have the following:

x is at least 8 can be expressed as x ≥ 8

Hence, the inequality expression of x is at least 8 can be expressed as x ≥ 8

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The estimated monthly average daily radiation on a horizontal surface in June in Amman is approximately 7.35 kWh/m(^2)/day.

To estimate the monthly average daily radiation on a horizontal surface H in June in Amman, we can use the following equation:

\([H = S \times H_s \times \frac{\sin(\phi)\sin(\delta)+\cos(\phi)\cos(\delta)\cos(H_a)}{\pi}]\)

where:

S is the solar constant, which is approximately equal to 1367 W/m(^2);

\(H(_s)\) is the average number of sunshine hours per day in Amman in June, which is given as 10 hours;

(\(\phi\)) is the latitude of the location, which for Amman is approximately 31.9 degrees North;

(\(\delta\)) is the solar declination angle, which is a function of the day of the year and can be calculated using various methods such as the one given in the answer to Q1;

\(H(_a)\) is the hour angle, which is the difference between the local solar time and solar noon, and can also be calculated using various methods such as the one given in the answer to Q1.

Substituting the given values, we get:

\([H = 1367 \times 10 \times \frac{\sin(31.9)\sin(\delta)+\cos(31.9)\cos(\delta)\cos(H_a)}{\pi}]\)

Since we are only interested in the monthly average daily radiation, we can assume an average value for the solar declination angle and the hour angle over the month of June. For simplicity, we can assume that the solar declination angle (\(\delta\)) is constant at the value it has on June 21, which is approximately 23.5 degrees North. We can also assume that the hour angle \(H(_a)\) varies linearly from -15 degrees at sunrise to +15 degrees at sunset, with an average value of 0 degrees over the day.

Substituting these values, we get:

\([H = 1367 \times 10 \times \frac{\sin(31.9)\sin(23.5)+\cos(31.9)\cos(23.5)\cos(0)}{\pi}]\)

Simplifying the equation, we get:

\([H \approx 7.35 \text{ kWh/m}^2\text{/day}]\)

Therefore, the estimated monthly average daily radiation on a horizontal surface in June in Amman is approximately 7.35 kWh/m(^2)/day.

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Both the white longhair female cat (w/w; l/l) and the black shorthair male cat (w/w; l/l) are homozygous for the white coat color (w/w) and the longhair trait (l/l).

When these cats mate, all the kittens will inherit one allele for each trait from each parent. Since both parents are homozygous for the white coat color (w/w), all kittens will also inherit the white coat color gene from both parents, resulting in white kittens (w/w). Similarly, both parents are homozygous for the longhair trait (l/l), so all kittens will inherit the longhair allele from both parents, making them longhair kittens (l/l).

In conclusion, all 12 kittens will have a white coat color and long hair, just like their parents. They will look like white longhair kittens, with the genotype (w/w; l/l) for both traits. It is important to remember that being a responsible pet owner includes spaying or neutering your pets to prevent unwanted litters, and finding loving homes for any kittens or puppies that may be born.

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Answer:

B. (-3, -17)

Step-by-step explanation:

We can be 99% certain the baseball game will end by 5.22pm.

A cut-off Number is a number mentioned in the applicable Final Terms as such, or if no number is provided, the Specific Number is presumed to be five.

In binary classification, the threshold or cut-off represents the chance that the prediction is correct. It represents the cost of false positives or false negatives.

Let the cutoff be A.

so,

P(X ≤ A) = 0.99

\(P\left(\frac{X-\mu}{\sigma} \leq \frac{a-2.5}{0.37}\right)=0.99\)

\(P\left(Z \leq \frac{a-2.5}{0.37}\right)=0.99\)

\(\Phi\left(\frac{a-2.5}{0.37}\right)=\Phi(2.33)\\\)

(a - 2.5)/.37 = 2.33

a = 3.3621

a = 3hours and (0.3621 * 60) = 22 minutes

We can be 99% certain the baseball game will end by 5.22pm.

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I understand that the question you are looking for is:

The probability that the baseball game will cut into the program is 0.0885.

Can you provide a cut-off time by which you can be 99% sure that the baseball game would end?

Answer:

Angle 1: 127

Angle 2: 153

Step-by-step explanation:

First, let's find angle 1 by finding the angle that's supplementary to it.

To solve for it, we can set up an equation where the unknown angle and the other angles in the triangle it's in add up to 180:

x+95+32=180

x=53

Since angle 1 is supplementary to 53, that means that angle 1 is equal to 180-53 = 127.

Then, to find angle 2, we can find the angle that's supplementary to it.

To solve for that, we can set up an equation where that unknown angle and the other angles in the triangle it's in add up to 180:

26+127+x = 180

x = 27

Since angle 2 is supplementary to 27, that means that angle 2 is equal to 180-27 = 153.

The cylinder popcorn container will hold the most popcorn and the cone popcorn container has a better unit rate

For the cone, we have

Radius, r = 6 cm

Height, h = 19 cm

So, the volume is

V = 1/3 * 3.14 * 6^2 * 19

V = 715.92

For the cylinder, we have

Radius, r = 4 cm

Height, h = 15 cm

So, the volume is

V = 3.14 * 4^2 * 15

V = 753.6

The cylinder popcorn container will hold the most popcorn because it has a higher volume

For the cone, we have

Unit rate = 715.92/6.75 = 222222

For the cylinder, we have

Unit rate = 753.6/6.25 = 120.576

The container that has a better unit rate is the cone popcorn container

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There are at least two group means that are significantly different from one another, according to the alternative hypothesis (H a). The alternative hypothesis is adopted if the outcome is statistically significant.

You can use ANOVA to determine whether differences between data sets are statistically significant. It functions by examining the levels of variance present within each group using samples drawn from each.

The likelihood that the mean of a sample taken from the data will be different owing to chance increases if there is a lot of variance (spread of data away from the mean) among the data groups.

In addition to examining the variance within the data groups, ANOVA also considers sample size (the smaller the sample, the lower the likelihood that outliers will be randomly selected from it) and sample mean differences (the greater the difference between the sample means, the greater the likelihood that an outlier will be randomly selected from it).

hence, The alternative hypothesis is adopted if the outcome is statistically significant.

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The derivative of f(x) = 7x + 3 is f'(x) = 7. The equation of the tangent line to f(x) at x = 1 is y = 10.

The derivative of a function is the slope of its tangent line at any given point. In this case, the derivative of f(x) is 7, which means that the slope of the tangent line to f(x) at any point is 7. When x = 1, the value of f(x) is 10. Therefore, the equation of the tangent line to f(x) at x = 1 is y = 10.

Here is a more detailed explanation of how to find the derivative and the tangent line:

Finding the derivative: The derivative of a function can be found using the limit definition of the derivative. The limit definition of the derivative states that the derivative of a function at a point is equal to the limit of the difference quotient as the difference quotient approaches zero. In this case, the function is f(x) = 7x + 3, and the point is x = 1. The difference quotient is:

f'(x) = lim_{h->0} (f(x + h) - f(x)) / h

When x = 1, the difference quotient becomes:

f'(1) = lim_{h->0} (7(1 + h) + 3 - (7(1) + 3)) / h

Simplifying the difference quotient, we get:

f'(1) = lim_{h->0} (7h) / h

The limit of a constant as the variable approaches zero is the constant itself. Therefore, the derivative of f(x) at x = 1 is 7.

Finding the tangent line: The equation of the tangent line to a function at a point is equal to the slope of the tangent line at that point multiplied by the difference between the point and the x-coordinate of the tangent line. In this case, the slope of the tangent line is 7, the point is (1, 10), and the x-coordinate of the tangent line is 1. Therefore, the equation of the tangent line is:

y - 10 = 7(x - 1)

Simplifying, we get:

y = 7x + 3

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Answer:

1024 pages left

Step-by-step explanation:

19 pack  * 75 page/pack - 401 page =

(a) Total revenue in 2012, we substitute x = 2012 into the given function f(x) = 4190.00, where x = 7 corresponds to the year 2007.

(b) The value of x, when rounded up, will represent the first full year.

(a) To find the total revenue in 2012, we substitute x = 2012 into the given function f(x) = 4190.00.

f(2012) = 4190.00

Therefore, the total revenue in 2012 was approximately $4190 billion.

(b) To determine the first full year in which revenue exceeded $134 billion, we set the function f(x) = 134 and solve for x.

4190.00 = 134

This equation is not possible since 4190.00 is significantly larger than 134.

However, let's consider the correct equation:

134 = 4190.00

By solving this equation, we find:

x ≈ 0.03198

This means that the first full year in which revenue exceeded $134 billion was approximately 0.032 years after the year 2007.

To convert this to a full year, we can round up to the nearest whole number. Therefore, the first full year in which revenue exceeded $134 billion would be 2007 + 1 = 2008.

Therefore, the first full year in which revenue exceeded $134 billion was 2008.

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Hannah's debt-to-equity ratio when her liabilities was $30,000 (excluding her mortgage of $100,000 ) and her net worth is $45,000 is 0.75.

Debt-to-equity ratio is a financial ratio that measures the proportion of total liabilities to shareholders' equity. To calculate the debt-to-equity ratio for Hannah, we need to first calculate her total liabilities and shareholders' equity.

We are given that Hannah has liabilities of $30,000 excluding her mortgage of $100,000. Therefore, her total liabilities are $30,000 + $100,000 = $130,000.

We are also given that her net worth is $45,000. The net worth is calculated by subtracting the total liabilities from the total assets. Therefore, the shareholders' equity is $45,000 + $130,000 = $175,000.

Now we can calculate the debt-to-equity ratio by dividing the total liabilities by the shareholders' equity.

Debt-to-equity ratio = Total liabilities / Shareholders' equity = $130,000 / $175,000 = 0.74 (rounded to two decimal places)

Therefore, Hannah's debt-to-equity ratio is 0.74, which is closest to option 0.75.

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The probability that a randomly chosen light bulb lasts more than 10,500 hours is 0.0668 (rounded to four decimal places).

The probability that a randomly chosen light bulb lasts more than 10,500 hours is 0.0668(rounded to four decimal places).Here's how to calculate it:Given data mean μ = 9,000 and standard deviation σ = 1,000.To calculate the probability that a random light bulb lasts more than 10,500 hours, convert the problem to a standard normal distribution.

z = (10,500 - μ)/σ = (10,500 - 9,000)/1000 = 1.50

Here's the standard normal distribution curve with the shaded area representing the probability required: Standard normal distribution curve with the shaded area

Now, the area under the curve to the right of z = 1.5 is the probability that a randomly chosen light bulb will last more than 10,500 hours.

Using the Z table, we can look up the value corresponding to a z-score of 1.5. The table gives us a value of 0.9332.Now, the area to the left of z = 1.5 is 1 - 0.9332 = 0.0668, which is the probability that a randomly chosen light bulb lasts more than 10,500 hours, rounded to four decimal places.

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The distribution of X follows the characteristics of a normal distribution with a mean of 106 and a standard deviation of 18, reflecting the IQ distribution of the ruling species on the faraway planet. This can be denoted as X ~ N(106, 18), where "N" represents the normal distribution.

The distribution of X, representing the IQ of an individual from the ruling species on the faraway planet, is a normal distribution with a mean (μ) of 106 and a standard deviation (σ) of 18. This can be denoted as X ~ N(106, 18), where "N" represents the normal distribution.

In this distribution, the majority of IQ values will cluster around the mean of 106. The standard deviation of 18 indicates the average amount of variation or dispersion from the mean. The normal distribution is symmetric, which means that the probabilities of IQ values being above or below the mean are equal.

The shape of the normal distribution is bell-shaped, with the highest point being at the mean. As we move away from the mean, the probability of observing extreme values decreases. The spread of the distribution is determined by the standard deviation, where a larger standard deviation indicates a wider spread of IQ values.

the distribution of X follows the characteristics of a normal distribution with a mean of 106 and a standard deviation of 18, reflecting the IQ distribution of the ruling species on the faraway planet.

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On a planet far far away from Earth, IQ of the ruling species is normally distributed with a mean of 106 and a standard deviation of 18. Suppose one individual is randomly chosen. Let X = IQ of an individual.  What is the distribution of X? X ~ N( 106 , 18 )  

Answer:

32

Step-by-step explanation:

Answer:

Next you should multiply the numerators and denominators.

explanation:

i got 100% ;)

Answer:

Multiply The Numearters and Denomenators

Step-by-step explanation:

There are 23 quarters and 29 dimes in the bag.

Let's denote the number of quarters as "q" and the number of dimes as "d".

We can set up a system of two equations based on the given information:

The total number of coins is 52:

q + d = 52

The total value of the coins is $8.35, where each quarter is worth $0.25 and each dime is worth $0.10:

0.25q + 0.10d = 8.35

To solve this system of equations, we can use substitution, elimination, or any other appropriate method.

Let's use elimination to solve this system of equations.

0.10(q + d) = 0.10(52)

25q + 10d = 835

25q + 10d = 835

0.25q + 0.10d = 8.35 (multiply by 100)

Now, let's multiply both sides of the first equation by 2 and the second equation by 8 to make the coefficients of "q" the same:

50q + 20d = 1670

200q + 80d = 6680

Now, let's subtract the first equation from the second equation to eliminate "q":

200q + 80d - (50q + 20d) = 6680 - 1670

150q + 60d = 5010

Now, let's divide both sides of the resulting equation by 30 to solve for "q":

150q/30 + 60d/30 = 5010/30

5q + 2d = 167

After trying different values, we find that when "q" = 23 and "d" = 29, the equation is satisfied and the condition "q + d = 52" is also satisfied. Therefore, there are 23 quarters and 29 dimes in the bag.

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Answer:

21

Step-by-step explanation:

Since the girls have the same age, let their age be x.
Then, their average is

\(\frac{x+x}{2} = \frac{2x}{2} = x\)

Let \(S_{i}\) denote the age of 'i' girls.
Then, \(S_{8} = S_{6} + x + x - eq(1)\)

Also, we have,

\(\frac{S_{8}}{8} =15 - eq(2)\)

\(\frac{S_{6}}{6} =13 - eq(3)\)

Then eq(2):

(from eq(1) and eq(3))

\(\frac{S_{6} + 2x}{8} =15\\\\\frac{13*6 + 2x}{8} = 15\\\\78+2x = 120\\\\2x = 120-78\\\\x = 21\)

The average of the other two girls with equal age​ is 21