Answer:
22.18mL147.42kg---637.14 lbs15.22mL--104 oz.12 g45.44 lbs3.59 pt43,000 mg105 tsp2,271.25 mL18tsp4 pt244.71 lbs219.99 kgs3.79 L3.96 g2,608.16 g145.4 tbsp99.22 g4.38 g10.57 pts135.26 oz1.73 LA ________ chart is a special type of scatter plot in which the data points in the scatter plot are connected with a line.
A line chart is a special type of scatter plot in which the data points in the scatter plot are connected with a line. A line chart is a graphical representation of data that is used to display information that changes over time. The line chart is also known as a line graph or a time-series graph. The data points are plotted on a grid where the x-axis represents time and the y-axis represents the value of the data.
The data points in the scatter plot are connected with a line to show the trend or pattern in the data. Line charts are commonly used to visualize data in business, economics, science, and engineering.Line charts are useful for displaying information that changes over time. They are particularly useful for tracking trends and changes in data. Line charts are often used to visualize stock prices,
sales figures, weather patterns, and other types of data that change over time. Line charts are also used to compare two or more sets of data. By plotting multiple lines on the same graph, you can easily compare the trends and patterns in the data.Overall, line charts are a useful tool for visualizing data and communicating information to others. They are easy to read, understand, and interpret, and can be used to display a wide range of data sets.
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The domestic violence study conducted in 1984 by Sherman and Berk had an ethical concern in that: O They financially profited from the research. O They did not adhere to special protections for vulnerable populations. O They potentially withheld a beneficial treatment. O They deceived their subjects.
In the 1984 domestic violence study conducted by Sherman and Berk, the ethical concern was that they potentially withheld a beneficial treatment.
The domestic violence study conducted by Sherman and Berk in 1984 raised an ethical concern in that they financially profited from the research. This raises the question of whether their motives were purely altruistic or whether they were driven by financial gain. Additionally, the study did not adhere to special protections for vulnerable populations such as women and children who may have been victims of domestic violence. This raises concerns about the validity and generalizability of the study's findings. Furthermore, the study potentially withheld a beneficial treatment, which raises questions about the ethical responsibility of researchers to ensure that their subjects receive the best possible care. Finally, there are also concerns that the researchers may have deceived their subjects, which raises questions about the integrity and transparency of the research process. In conclusion, the ethical concerns raised by this study highlight the need for researchers to carefully consider the impact of their research on vulnerable populations and to ensure that they adhere to the highest ethical standards.
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The points P(3,-2), Q(10,-2), and R(3,-8) are the vertices of a triangle.
What is the approximate length of side RQ?*
Help ASAP
Answer:
Option B
Step-by-step explanation:
Distance between two points \((x_1,y_1)\) and \((x_2,y_2)\) is defined by the formula,
Distance = \(\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\)
Distance between the given points R(3, -8) and Q(10, -2) will be
RQ = \(\sqrt{(3-10)^2+(-8+2)^2}\)
RQ = \(\sqrt{49+36}\)
RQ = \(\sqrt{85}\)
RQ = 9.22
RQ ≈ 9 units
Option B is the answer.
The approximate length of side RQ is 9 units
What is a Triangle ?
A polygon that has three sides , three angles and three vertices is called a triangle.
It is given that the vertices of the triangle is P(3,-2), Q(10,-2), and R(3,-8)
Length of RQ = ?
To determine the length , triangle should be plotted on the graph
After plotting we can determine
PQ = 7 units
PR =6 units
Applying Pythagoras theorem to determine RQ
RQ² = 7² +6²
RQ² = 49+36
RQ = approximately 9 units.
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John walks dogs to earn extra money. He earns $5 per dog he walks. Using the following equation y = 5x, where x =the number of dogs John walks
and y = the number of dollars John earns.
What is the number of dollars John earns if he walks 8 dogs?
A. $3
B. $13
C. $25
D. $40
8 dogs so 5*8= 40
so it's D
(NO LINKS PLEASE)
Melina performs an experiment in which she pulls a marble out of a bag, records its color, puts it back, and repeats. After completing 24 trials, she pulled a yellow marble 3 times.
What is the experimental probability of pulling a yellow marble from the bag?
Enter your answer as a fraction, like this: 42/53
Answer:
3/24 or 1/8 (either one)
Answer: 3/24
Step-by-step explanation:
the cost of 3 scarves is $65.25. what's the unit price?
Answer:
21.75
Step-by-step explanation:
65.25/3=21.75
Answer:
$21.75 per scarf
Step-by-step explanation:
Take the total cost and divide by the number of scarves
65.25 /3
21.75
Each scarf costs 21.75
$21.75 per scarf
Find the missing side of each triangle. Leave your answer in simplest radical form.
(Please show ur work)
Answer: \(7\sqrt{2\)
Step-by-step explanation:
a²+b²=c²
7²+7²=c²
49+49=c²
\(\sqrt{98}=\sqrt{c^2}\\\sqrt {49}\sqrt{2} =c\\ 7\sqrt{2} =c\)
Answer:
7\(\sqrt{2}\)
Step-by-step explanation:
To find the missing length of a right triangle use the Pythagorean theorem. This theorem is \(a^2+b^2=c^2\). The variables a and b are the legs (shorter sides) and c is the hypotenuse (longest side). In this case, the hypotenuse is the missing side. So, add and square 7. This looks like \(7^2+7^2=x^2\). So, \(98=x^2\). Finally, square root 98 to get the final answer, \(\sqrt{98}\). This can be simplified to \(7\sqrt{2}\).
Additionally, this is a special right triangle because the legs are of equal length. If the legs are equal then the hypotenuse with be equal to x\(\sqrt{2}\), where x is the length of the legs. So this problem can also be solved using this method.
A sample of bacteria taken from a river has an initial concentration of 2.1 million bacteria per milliliter and its concentration triples each week. (a) Find an exponential model that calculates the concentration after x weeks. (b) Estimate the concentration after 1.6 weeks. (a) B(x) = (Type an equation usingx as the variable.)
The exponential model that calculates the concentration of bacteria after x weeks can be represented by the equation B(x) = 2.1 million * (3^x), the concentration after 1.6 weeks would be approximately 14.87 million bacteria per milliliter.
This equation assumes that the concentration triples each week, starting from the initial concentration of 2.1 million bacteria per milliliter.
To estimate the concentration after 1.6 weeks, we can substitute x = 1.6 into the exponential model. B(1.6) = 2.1 million * (3^1.6) ≈ 14.87 million bacteria per milliliter. Therefore, after 1.6 weeks, the estimated concentration of bacteria in the river would be approximately 14.87 million bacteria per milliliter.
The exponential model B(x) = 2.1 million * (3^x) represents the concentration of bacteria after x weeks, where the concentration triples each week. By substituting x = 1.6 into the equation, we estimate that the concentration after 1.6 weeks would be approximately 14.87 million bacteria per milliliter.
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What is the domain and range of this function?
7x^6 - 2x^5 - 3x^4 - 2x^3 - 0x^2 - 0x - 7
What are the real and complex zeros?
7x^6 - 2x^5 - 3x^4 - 2x^3 - 0x^2 - 0x - 7
Royston's car had gallons of gas at the start of the trip. During the trip, he stopped at a gas station and refueled the car with gallons. If the car consumed gallons of gas during the trip, there are still gallons of gas remaining in the tank.
Answer:
3 gallons of gas are still remaining in the tank
Step-by-step explanation:
Royston's car had 15 1/5 gallons of gas at the start of the trip. During the trip, he stopped at a gas station and he refueled the car with 5 3/5 gallons. If the car consumed 17 4/5 gallons of gas during the trip, there are still ____________ gallons of gas remaining in the tank?
Given:
Initial gallons of gas=15 1/5
Refueled gallons of gas= 5 3/5
Used gallons of gas=17 4/5=89/5
Total gallons of gas available=
Initial + Refueled
=15 1/5 + 5 3/5
=76/5 + 28/5
=76+28/5
=104/5 gallons
Equivalent to
=20 4/5 gallons
Total remaining gallons of gas= Total gallons of gas available - Total gallons of gas used
=104/5 -89/5
= 104-89/5
=15/5
=3 gallons
Answer:
3 gallons
Step-by-step explanation:
a school district wants to justify building a new elementary school in the district because it believes that the expected number of students will start to exceed the capacity of the schools in the district. which statistical method would be most appropriate? group of answer choices binomial distribution confidence interval hypothesis test regression analysis
The answer is that regression analysis is the most appropriate method.
The most appropriate statistical method to justify building a new elementary school in the district would be regression analysis. This method can be used to examine the relationship between the expected number of students and the capacity of the schools in the district.
Regression analysis is a statistical method that helps to determine the relationship between two or more variables. In this case, the expected number of students would be the independent variable, while the capacity of the schools in the district would be the dependent variable. By analyzing the relationship between these variables, the school district can make predictions about how many students will need to be accommodated in the future and whether a new elementary school is necessary.
In contrast, binomial distribution is a statistical method that is used to calculate the probability of a specific number of successes in a set of trials, which would not be suitable for this situation. Confidence intervals and hypothesis tests are statistical methods used to draw conclusions about populations based on sample data, but may not be the most appropriate method for this situation.
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16) Consider the sequence of steps to solve the equation:
5(x - 3) =
2
7x
-
Step 1 => 10(x - 3) = 7x
Step 2 = 10x - 30 - 7x
Step 3 => 3x - 30 - 0
Step 4 => 3x = 30
Step 5 => x= 10
Identify the property of equality which gets us from Step 3 to Step 4.
A) Division Property
B) Addition Property
C) Subtraction Property
D) Multiplication Property
Answer:
B) addition property
Step-by-step explanation:
thinking that 3x - 30 - 0 should equal 0.
3x - 30 - 0 = 0
to get rid of numbers on side with variables, we have to add them to both sides (to make it 0 in side with variable.)
3x - 30 - 0 = 0
+30 +0 = +30 +0
3x = 30 <- step 4
increases in snow levels are recorded with positive numbers. decreases in snow levels are recorded with negative numbers.
In the context described, increases in snow levels are represented by positive numbers, while decreases in snow levels are represented by negative numbers.
Positive numbers are used to indicate upward or increasing quantities. Therefore, when snow levels rise or increase, they are recorded with positive numbers. This convention allows for a consistent and intuitive representation of data, where higher values correspond to larger amounts of snow. It simplifies comparisons and calculations, as positive numbers can be directly added or compared to determine the extent of the increase.
Conversely, negative numbers are used to denote downward or decreasing quantities. When snow levels decrease, they are recorded with negative numbers. This convention helps to maintain consistency in representing the direction and magnitude of changes in snow levels. It enables easy identification and distinction between increases (positive numbers) and decreases (negative numbers), facilitating the analysis of snowfall patterns over time.
By adopting this convention, researchers, meteorologists, and other professionals working with snowfall data can effectively communicate and interpret changes in snow levels using a standardized and easily understandable format.
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Scores turned in by an amateur golfer at the Bonita Fairways Golf Course in Bonita Springs, Florida, during 2014 and 2015 are as follows: 2014 Season: 72 76 77 75 73 71 73 75 2015 Season: 69 68 73 75 83 78 69 77 a. Calculate the mean (to the nearest whole number) and the standard deviation (to 2 decimals) of the golfer's scores, for both years. 2014 Mean Standard deviation 2015 Mean Standard deviation b. What is the primary difference in performance between 2014 and 2015? - Select your answer What improvement, if any, can be seen in the 2015 scores?
a) The mean and the standard deviation of the amateur golfer’s scores for both the years 2014 and 2015 are given below:2014 Season Mean of scores = (72+76+77+75+73+71+73+75) / 8
= 592 / 8 = 74
Standard Deviation (SD) of scores = 2.29 (rounded to 2 decimal places) 2015
Season Mean of scores
= (69+68+73+75+83+78+69+77) / 8
= 592 / 8
= 74
Standard Deviation (SD) of scores = 5.05 (rounded to 2 decimal places)b)
The primary difference in performance between 2014 and 2015 is that the standard deviation of the scores in 2015 is greater than that in 2014.
This indicates that the scores in 2015 were more spread out or varied than in 2014.
Improvement can be seen in the 2015 scores as the mean of scores in 2015 is less than the mean of scores in 2014. The lower mean score indicates an improvement in the performance of the amateur golfer.
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from a population of size 500, a random sample of 50 items is selected. the mode of the samplea. can be larger, smaller or equal to the mode of the population. b. must be equal to the mode of population, if the sample is truly random. c. must be equal to the mean of the population, if the sample is truly random. d. must be 500.
The mode of a sample is the value that appears most often in the data set. It can be larger, smaller or equal to the mode of the population, depending on the sample size and the distribution of the population.
The mode of a sample is not necessarily equal to the mode of the population if the sample is truly random, as there is no guarantee that the most frequent value in the population will appear in the sample.
For example, let’s say the population has a mode of 10. If the sample size is 50, the probability of the sample having a mode of 10 is 0.2. The probability of the sample having a mode of 11 or larger is 0.4. The probability of the sample having a mode of 9 or smaller is also 0.4.
This means that the mode of the sample can be larger, smaller or equal to the mode of the population. It does not have to be equal to the mean of the population, as the mean is an average of all the values in the population and is not necessarily the most frequent value. Furthermore, the mode of the sample cannot be 500, as this is the size of the population, not a value that appears in the data set.
The mode of the sample can be larger, smaller or equal to the mode of the population, and cannot be equal to the mean of the population or equal to the size of the population.
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The mean exam score for 49 male high school students is 239 and the population standard deviation is 47 The mean exam score for 53 female high school students is 21.1 and the population standard deviation is 4.3. At α=001, can you reject the claim that male and female high school students ha equal exam scores? Complete parts (a) through (e). Click here to view page 1 of the standard normal distribution table. Click here to view. page 2 of the standard normal distribution table. A. Male high school students have lower exam scores than female students B. Male and temale high school students have different exam scores. C. Male and female high school students have equal exam scores D. Male high school students have greater exam scores than female students
Comparing the means of the two samples, we find that the difference between the means is significant. Therefore, we can reject the claim and conclude that male and female high school students have different exam scores.
To perform the two-sample t-test, we first calculate the standard error of the difference between the means using the formula:
SE = sqrt((s1^2 / n1) + (s2^2 / n2))
Where s1 and s2 are the population standard deviations of the male and female students respectively, and n1 and n2 are the sample sizes. Plugging in the values, we have:
SE = sqrt((47^2 / 49) + (4.3^2 / 53))
Next, we calculate the t-statistic using the formula:
t = (x1 - x2) / SE
Where x1 and x2 are the sample means. Plugging in the values, we have:
t = (239 - 21.1) / SE
We can then compare the t-value to the critical t-value at α = 0.01 with degrees of freedom equal to the sum of the sample sizes minus 2. If the t-value exceeds the critical t-value, we reject the null hypothesis.
In this case, the t-value is calculated and compared to the critical t-value using the provided standard normal distribution table. Since the t-value exceeds the critical t-value, we can reject the claim that male and female high school students have equal exam scores.
Therefore, the correct answer is:
B. Male and female high school students have different exam scores.
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2x+5=2(x+3)
Solve for x?
Answer:
3 and 5
Step-by-step explanation:
order of operation
step 1
look at problem and see if there is a number that occurs like 2-3+x=4-3+x
step 2 your done
In the figure below, C is between A and D, and B is the midpoint of AC. If BC= 3 and BD=10, find AD.
The line segment AD measures 13 units.
What is a line segment?
A line segment in geometry has two different points on it that define its boundaries. A line segment is sometimes referred to as a section of a line that links two places. The difference between a line and a line segment is that a line has no endpoints and can go on forever in either direction.
A line segment AD is given.
Four points A, B, C and D are placed.
It is given that measurement of BC = 3 units.
Also, measurement of BD = 10 units.
Since, B is the midpoint of AC, so -
AB = BC
So, the measurement of AB = 3 units
The measurement of CD can be found as -
CD = BD - BC
CD = 10 - 3
CD = 7 units
So the measurement for line segment AD is -
AD = AB + BC + CD
AD = 3 + 3 + 7
AD = 13 units
Therefore, the measurement value is 13 units.
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A small object at rest on a frictionless surface is attached to a wall by a frictionless spring. The object is pulled away from the wall to stretch the spring and
then released. The graph shows the displacement d, in centimeters, of the object from its resting position as a function of time t, in seconds, as the object
oscillates. Which of the following statement(s) is/are true?
a pyramid has a surface area of 6400 square yards. if the new dimensions are 1/8 the original size, what is the surface area of the new pyramid
If the surface area of the original pyramid is 6400 square yards and the new dimensions are 1/8 of the original size, the surface area of the new pyramid will be 100 square yards.
Let's denote the original surface area of the pyramid as S1 and the new surface area as S2. We know that the new dimensions are 1/8 of the original size, which means the linear dimensions (height, base length, and base width) are also 1/8 of the original dimensions.
The surface area of a pyramid is given by the formula S = 2lw + lh + wh, where l, w, and h represent the base length, base width, and height, respectively.
Since the new dimensions are 1/8 of the original size, we can say that the new base length (l2), base width (w2), and height (h2) are equal to (1/8) * original base length (l1), (1/8) * original base width (w1), and (1/8) * original height (h1), respectively.
Therefore, the new surface area (S2) can be calculated as:
S2 = 2 * (1/8 * l1) * (1/8 * w1) + (1/8 * l1) * (1/8 * h1) + (1/8 * w1) * (1/8 * h1)
= 1/64 * (2l1w1 + l1h1 + w1h1)
Since we are given that S1 (the original surface area) is 6400 square yards, we can equate it to S2:
6400 = 1/64 * (2l1w1 + l1h1 + w1h1)
Simplifying the equation, we get:
2l1w1 + l1h1 + w1h1 = 6400 * 64
2l1w1 + l1h1 + w1h1 = 409600
Therefore, we can conclude that the surface area of the new pyramid (S2) is 100 square yards.
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Please does anyone know the answer to this question??
9514 1404 393
Answer:
126°
Step-by-step explanation:
To find the exterior angle, we need to know one of the acute angles. Those are found using the fact that they are complementary.
(5x -6) +(3x) = 90
8x = 96 . . . . . . . . . . . add 6, collect terms
x = 12 . . . . . . . . . . . . . divide by 8
3x° = 3·12° = 36° . . . . . . find the "remote" acute angle
exterior angle = 90° +36°
exterior angle = 126°
__
The exterior angle is the supplement of the one marked (5x-6)°. It is also the sum of the two remote interior angles, 90° and 3x°. Being lazy, we figure that 90 +3·12 is easier to compute than 180 - (5·12 -6). Either way, the exterior angle is 126°.
Which system of equations has the same solution as the system below?
Answer:
B.
Step-by-step explanation:
Answer:
B.
Step-by-step explanation:
'TIS BIG BRAIN TIME
Aliya buys p pounds of apples for $2 per pounds. Write an algebraic expression to find the total cost?
Answer:
Identify the terms and coefficients of each expression. 1. ... Frank buys p pounds of oranges for $2.29 per pound and the same number of pounds of apples for $1.69 per pound. ... .690 = total cost ... Write an expression to represent each situation. 9. Eliza earns $400 per week plus $15 for each new customer she signs up.
Step-by-step explanation:
Solve for x.
(Will be marked the brainliest for sure)
Answer:
15
Step-by-step explanation: if you look at 8 compared to its counterpart of 24 youll see the ratio is 1:3 and so you just multiply 5 by 3 tp get 15
Corrado has 27 books in his room that he has already read. He wants to give them away to his 3 younger siblings. How many books will each of Corrado's siblings receive?
If b represents the number of books each sibling receives, which equation could be used to solve the problem?
Answer:
3b = 27
Step-by-step explanation:
They will each receive 9 books
A bicycle repair shop offers two service packages to its customers: a tune up or a complete overhaul, which includes the tune up plus some additional services. All bicycles go through wheel balancing before leaving the shop. The repair shop is open 60 hours per week and receives an average of 180 bicycles each week. The shop employs three "tune up" technicians, one "additional services" technician, and two wheel balancing" specialists. Past data indicates that 25% of customers opt for the "additional services" option. Wheel Tune Up Balancing T = 75 T= 20 minutes minutes Additional Services T = 72 minutes a) Create a demand matrix for this process b) What will be the daily capacity at each stage of the process? c) Find the implied utilizations for each stage of the process. d) What will be the weekly capacity of the process? e) Is the flow rate of this process capacity-constrained or demand-constrained?
A bicycle repair shop that offers two service packages: a tune-up and a complete overhaul.
The shop operates for 60 hours per week and receives an average of 180 bicycles each week. To analyze the capacity and utilization of the process, we need to consider the time taken at each stage and the demand for each service option. We'll break down the problem into multiple parts and provide a detailed explanation using mathematical terms.
a) Creating the Demand Matrix:
To create a demand matrix, we need to determine the number of bicycles going through each stage of the process. Let's denote the demand for tune-up as T and the demand for additional services as A.
Given that the average number of bicycles received per week is 180 and 25% of customers opt for additional services, we can calculate the demands as follows:
Demand for tune-up (T) = Total demand - Demand for additional services
T = 180 - (0.25 * 180)
T = 180 - 45
T = 135
Demand for additional services (A) = 0.25 * Total demand
A = 0.25 * 180
A = 45
Now, we can create a demand matrix based on the demand for each service option:
Demand Matrix:
Tune-up Additional Services Wheel Balancing
Tune-up [135 0 0]
Additional [0 45 0]
Services
Total [ 135 45 0 ]
The demand matrix shows the number of bicycles flowing through each stage of the process.
b) Daily Capacity at Each Stage:
To calculate the daily capacity at each stage, we need to consider the time taken for each service option. Given that the shop operates for 60 hours per week, we can calculate the daily capacity at each stage:
Tune-up technician time per bicycle (\(T_{tuneup}\)) = 75 minutes
Additional services technician time per bicycle (\(T_{additional}\)) = 72 minutes
Wheel balancing specialist time per bicycle (\(T_{balancing}\)) = 20 minutes
Daily Capacity (C) = (60 hours * 60 minutes) / (\(T_{tuneup}\) + \(T_{additional}\) + \(T_{balancing}\))
Substituting the given values:
C = (60 * 60) / (75 + 72 + 20)
C = 21600 / 167
C ≈ 129.34 bicycles per day
Therefore, the daily capacity at each stage of the process is as follows:
Tune-up: 129 bicycles per day
Additional Services: 129 bicycles per day
Wheel Balancing: 129 bicycles per day
c) Implied Utilizations:
To find the implied utilizations, we need to compare the demand and the capacity at each stage of the process. Utilization can be calculated as the demand divided by the capacity.
Implied Utilization (U) = Demand / Daily Capacity
For the Tune-up stage:
\(U_{tuneup}\) = 135 / 129 ≈ 1.05
For the Additional Services stage:
\(U_{additional}\) = 45 / 129 ≈ 0.35
For the Wheel Balancing stage:
\(U_{balancing}\) = 0 / 129 = 0
The implied utilizations show how efficiently each stage of the process is being utilized. Utilization values greater than 1 indicate that the stage is operating beyond its capacity.
d) Weekly Capacity of the Process:
To calculate the weekly capacity of the process, we multiply the daily capacity by the number of days the shop is open per week:
Weekly Capacity = Daily Capacity * Number of days shop is open per week
Given that the shop is open for 60 hours per week, the number of days the shop is open per week can be calculated as follows:
Number of days shop is open per week = 60 hours / 24 hours per day = 2.5 days
Therefore, the weekly capacity of the process is:
Weekly Capacity = Daily Capacity * Number of days shop is open per week
Weekly Capacity = 129 bicycles per day * 2.5 days
Weekly Capacity = 322.5 bicycles per week
e) Flow Rate and Constraint Analysis:
To determine if the flow rate of the process is capacity-constrained or demand-constrained, we compare the weekly capacity to the demand for each service option.
Demand for Tune-up (\(T_{demand}\)) = 135 bicycles per week
Demand for Additional Services (\(A_{demand}\)) = 45 bicycles per week
Comparing the demands with the weekly capacity:
\(T_{demand}\) < Weekly Capacity (135 < 322.5)
\(A_{demand}\) < Weekly Capacity (45 < 322.5)
Since both the demands for tune-up and additional services are less than the weekly capacity, the flow rate of the process is demand-constrained. This means the shop has the capacity to handle the current demand without operating beyond its limits.
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mo
1.
\( \frac{5}{10} \div \frac{3}{2} \)
Answer:
The answer is 1/3.
Step-by-step explanation:
This is because when dividing you switch the sign to multiplication and flip the second fraction so that the denominator is the numerator and the numerator is the denominator. You would then just multiply as normal to get 1/3.
When constructing a perpendicular bisector why must the compass opening be greater than 1/2.
It is critical to open a compass with over half the way in order for the arcs formed to meet for perpendicular bisector.
What is perpendicular bisector?A perpendicular bisector would be a line that cuts a line segment in half and forms a 90-degree angle at the intersection point. In other words, a perpendicular bisector separates a line segment now at midpoint, forming a 90-degree angle.
Now, consider an example;
When you wish to build a perpendicular line on a line segment, like line AB, you do the following;
Set the compass on a radius more than half the length of the line AB.Using A as your center, draw an arc above and below line AB.With the same radius and B as our center, draw additional arcs on top or below line AB to join a first arcs on the both side of the line.Join the two arc intersections to cut line AB at M.A line AB appears to be bisected perpendicularly as a result. The arcs would not have met if the compass is opened less than half way down line AB.
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By rounding to 1 significant figure, estimate the answers to these questions:
346 x 904
Answer:
312 784
Step-by-step explanation:
if u need this answer, take
Significant figure can be defined in mathematics as the number of integers or digits in a number that tells us how significant and accurate the number is.
Rounding to 1 significant figure, 346 x 904 is 300000
When rounding a number to significant figures, the following rules are important.
Digits with no zeros in them are always significant Zeros between digits with no zeros in them are always significant The zero at the beginning of a number is not insignificant.
346 multiplied by 904 is calculated as:
346 x 904 = 312794
Converting 312794 to 1 significant figure is 300000
Therefore, rounding to 1 significant figure, 346 x 904 is 300000.
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If 3 – 5x = 2, then x =
3-5x=2
or, -5x=-1
or, x= 1/5
The value of x is 1/5 for equation 3 – 5x = 2
What is Equation?Two or more expressions with an Equal sign is called as Equation.
The given equation is 3 – 5x = 2
Three minus five times of x equal to two
We need to solve for x
3 – 5x = 2
Subtract 3 from both sides
3-3-5x=2-3
-5x=-1
Divide both sides by -5
x=-1/-5
x equal to one by five
x=1/5
Hence, the value of x is 1/5 for equation 3 – 5x = 2
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