Convert the measurements. Help me ASAP please!

Answer:

Paul should be wearing a light jacket appropriate for about 59 F or 15 °C

Step-by-step explanation:

If it is 4:00 a.m. in Honolulu when it is 2:00 p.m. in London, then the difference between times is:

\(d=14-4\\d=10\ hours\)

London is 10 hours ahead of Honolulu.

If Paul left Honolulu at 12:00 p.m, the corresponding time in London was:

\(t=12+10\\t=22 = 10:00\ p.m.\)

Since he arrived in London at 1:00 p.m. at Friday, the flight time was:

\(F= (24-22)+13\\F=15\ hours\)

The flight took 15 hours in total. If the temperature was 30°C when he boarded the flight and it decreases at a rate of 1°C per hour, the temperature when Paul arrives in London is:

\(T=30-(15*1)\\T=15^oC\)

Converting it to Fahrenheit

\(T=(15*\frac{9}{5})+32 \\T=59\ F\)

Paul should be wearing a light jacket appropriate for about 59 F or 15 °C

Answer:

d

Step-by-step explanation:

Answer:

P = 68.95

Step-by-step explanation:

Here, we want to get the measure of angle P

Please check the attachment for the diagram of the triangle

To get P, we use the cosine rule

p^2 = m^2 + n^2 - 2mn Cos P

60^2 = 51.4^2 + 54.5^2 -2(51.4)(54.5) Cos P

2012.21 = 5602.6 Cos P

cos P = 2012.21/5602.6

cos P = 0.3592

P = arc cos 0.3592

P = 68.95

2 + √3 is  a polynomial root,  then another root will be  2 - √3 for the polynomial .

For a given polynomial equation, where the degree of the equation is  1, it is said to be a quadratic equation. Since the given polynomial root is  2 + √3 ,the formula we refer to for  calculating the solution of  a quadratic formula  is  x = -b ± √(b² - 4ac) / 2a, which implies the roots be e [ -b + √(b² - 4ac) / 2a] and [ -b - √(b² - 4ac) / 2a].So, using the formula the root will be  2 - √3, here we can say that a complex root comes with conjugate pairs.

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Answer:

1

Step-by-step explanation:

S = {,10,11,12,13,14,15,16,17,18,19,}

n(s) = 10

P(a) = n(a) / n(s)

= 10 / 10

= 1 / 1

= 1

hope this helps.....

Answer:

if we assume that

tan = opp/adj

then we can find the hypotenus by using phytagoras law

h² = o² + a²

h² = (m-1)² + (2√m)²

h² = m² - 2m + 1 + 4m

h² = m² + 2m + 1

then we factorized become

h² = (m + 1)²

h = m+1

so for sin x = opp/hyp = (m-1)/(m+1)

hope this can help you.

We have shown that the expression is equal to 0.

To show that the given expression is equal to 0, we can simplify it algebraically. First, we can substitute 0 for the value of sin(θ0) in the expression. This results in:

0 sin θ0 √(0 sin θ0 )^2 2ℎ

Next, we can simplify the expression under the square root by squaring 0 sin(θ0), which results in:

0 sin θ0 √0 2ℎ

The square root of 0 is equal to 0, so the entire expression becomes:

0 * sin(θ0) * 0 / 2ℎ = 0

Therefore, we have shown that the expression is equal to 0. This result indicates that there is no contribution to the value of the expression from the terms in the numerator and denominator, and it is entirely dependent on the constant value of 0.

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Answer:

Step-by-step explanation:

3a+10-4q+7a-4q-6  combine terms

10a-8q+4

Answer:

10a - 8q + 4

General Formulas and Concepts:

Alg I

Step-by-step explanation:

Step 1: Define expression

3a + 10 - 4q + 7a - 4q - 6

Step 2: Simplify

The dimensions of a scale drawing of the flag using a scale 1:8 are 5 cm by 9 cm.

The correct option is B.

The ratio of the scale of an original thing to a new object that is a representation of it but of a different size is known as a scale factor (bigger or smaller).

Given:

A rectangular flag is 40 centimeters by 72 centimeters.

The scale factor is 1/8.

So, the dimensions of a scale drawing of the flag using the scale 1:8 is,

= 40/8 cm by 72/8 cm

= 5 cm by 9 cm.

Therefore, the dimensions are 5 cm by 9 cm.

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Answer:

(B) 5 cm by 9 cm

Step-by-step explanation:

I took the exam and got it right :)

Answer:

\( \boxed{ \bold{ \huge{ \boxed{ \text{ \: ( \: 5 \: , \: 7 \: )}}}}}\)

Step-by-step explanation:

\( \star{ \sf{ \: let \: the \: points \: be \: A \: and \: B}}\)

\( \star{ \sf{ \: Let \: A ( 2 , 10 ) \: be \: ( x1 , y1 ) \: and \: B ( 8 , 4 ) \: be \: ( x2 , y2 )

}}\)

\( \underline{ \sf{ \: Finding \: the \: midpoint}}\)

\( \boxed{ \sf{midpoint = ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}\)

\( \hookrightarrow{ \sf{Midpoint \: = \: ( \frac{2 + 8}{2} \: , \: \frac{10 + 4}{2}})} \)

\( \hookrightarrow{ \sf{Midpoint = ( \frac{10}{2} \: \: , \: \frac{14}{2} }})\)

\( \hookrightarrow{ \sf{Midpoint = (5 \: , \: 7}})\)

\( \text{Hope \: I \: helped !}\)

\( \text{Best \: regards !!}\)

~\( \text{TheAnimeGirl}\)

Answer:

a)  $498

b) $1052

c) $554

Step-by-step explanation:

to find the median of lower half of data:  find median of all the data, then find middle value from the minimum value to the median (not including median)

to find the median of upper half of data:  find median of all the data, then find middle value from the median to the maximum value (not including median)

interquartile range (IQR) is the difference of the two

Step-by-step explanation:

1. 16x ^ 12 ( to raise a product to a power , raise its factor to the power , evaluate the power, simplify the expressions by multiplying exponents)

2. 1 ( its a rule any non zero expression raised to power of 0 equals to 1)

3. 7/p^4

a) The given relation is function.

b) The function is, $x = 18.5 y

c) The value of (f+ g)(9) is 5.

d) The he original amount of her loan is 6000.

A function with one or two variables and no exponents is referred to as a linear function. It is a function with a straight line as its graph.

Given:

a) The given relation is function because is input have have output, no two outputs have same input.

b) After 8 hours, a person earned $148 in wages.

So, the unit rate change = 148/ 8

                                        = 18.5

So, if y represents the number of hour and $x the wages, then the function is $x = 18.5 y.

c)  Let f(x)=x and g(x)=x-13

(f+ g)(9)

= (x+  x-13) (9)

= 2x -13

= 2(9)- 13

= 5

d) The modeled function. P(m) = 6000 - 300m.

so, the original amount of her loan is 6000.

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Answer:

Student 2 only

Step-by-step explanation:

Given that:

The written antiderivatives formulas by the students for k sin (kx), where  k > 1 are:

Student 1 : \(\int (k \ sin (kx)) \ dx= k^2 \ cos (kx) + C\)

Student 2: \(\int (k \ sin (kx) ) \ dx = - cos (kx) + C\)

The student that wrote the correct anti-derivate formula is Student 2 only.

This is because:

Suppose:

\(I = \int (k \sin (kx) ) \ dx\) where; k > 1

This implies that:

\(I = \int (k \sin (kx) ) \ dx\)

\(I =k \bigg ( \dfrac{-cos (kx)}{k} \bigg) + C\)   because \(\int sin (ax) \ dx = \dfrac{-cos (ax)}{a}+C\)

here;

C = constant of the integration

∴

I = - cos (kx) + C  which aligns with the answer given by student 2 only.

The speed of the train moving through a tunnel 15.75 km for 0.015h is 291.67 m/s.

To find the speed of the train, we need to use the formula:
Speed = Distance / Time.
The distance traveled by the train is given as 15.75 km, and the time taken is given as 0.015 hours.

We need to convert the distance to meters and the time to seconds to get the answer in m/s.
Distance = 15.75 km = 15.75 x 1000 m = 15750 m
Time = 0.015 hours = 0.015 x 3600 s = 54 seconds.

Now, we can substitute these values in the formula:
Speed = 15750 m / 54 s = 291.67 m/s.

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Answer:

11 dimes and 16 quarters

Step-by-step explanation:

system of equations lol

Answer:

15

Step-by-step explanation:

y= 15 because 5 x 15 is 75 and 51+54+75= 180

Answer:

y=15

Step-by-step explanation:

51+54=105

180-105=75

75÷5=15

y=15

OR

5y+51+54=180⁰

5y+51=126

5y=75

y=75÷5

y=15

As currently written, solving for \(x\), we have

\(\sqrt{15} - x + \sqrt3 - x = 6\)

\(2x = \sqrt{15} + \sqrt3 - 6\)

\(x = \dfrac{\sqrt{15} +\sqrt3 - 6}2\)

I suspect you meant to write

\(\sqrt{15 - x} + \sqrt{3 - x} = 6\)

Move one of the roots to the other side, then take squares on both sides.

\(\sqrt{15 - x} = 6 - \sqrt{3 - x}\)

\(\left(\sqrt{15 - x}\right)^2 = \left(6 - \sqrt{3 - x}\right)^2\)

\(15 - x = 36 - 12 \sqrt{3 - x} + (3 - x)\)

\(12 \sqrt{3 - x} = 24\)

Take squares again

\(\left(12\sqrt{3-x}\right)^2 = 24^2\)

\(144 (3 - x) = 576\)

\(432 - 144x = 576\)

\(144x = -144\)

\(\boxed{x = -1}\)

Answer:

16,849,464 ft³

Step-by-step explanation:

subtract the two volumes of the pyramids.

Answer: The result of the conversion would be 1000 cubic meters.

Step-by-step explanation:

Answer:

The answer is A: 9/11

Answer: f(x) = 72-12x

Step-by-step explanation: Hope it helps

Answer:

m=5

Step-by-step explanation:

You use the slope formula to find your answer.

Answer:

`1/3

Step-by-step explanation:

So to find any last digit of 3^2011 divide 2011 by 4 which comes to have 3 as remainder. Hence the number in units place is same as digit in units place of number 3^3. Hence answer is 7.

X = 1

Because where the two lines intersect, they have the same x value, one

Answer:

x = 1

Step-by-step explanation:

Look at the graph to see where the lines intersect.

f(1) = 1

g(1) = 1

When x = 1, the output value of both functions is 1.

Answer: x = 1

The above Maximum Entropy Model is equivalent to the multi-class logistic regression model as Z(xi) = ∑y=1K exp(θj fj(xi)). This is the softmax function, which is the basis for the multi-class logistic regression model.

The maximum entropy model can be formulated as follows:

Maximize: H(p) = - ∑i=1n ∑y=1K p(y|xi) ln p(y|xi)

Subject to:

∑y=1K p(y|xi) = 1, for i = 1,...,n

∑y=1K p(y|xi) δ(y,yi) fj(xi) = ∑y=1K p(y|xi) fj(xi), for j = 1,...,d and i = 1,...,n

where δ(y,yi) is the Kronecker delta function.

Using the Lagrangian dual theory, we can rewrite the objective function as:

L = - ∑i=1n ∑y=1K p(y|xi) ln p(y|xi) + ∑i=1n λi(∑y=1K p(y|xi) - 1) + ∑i=1n ∑j=1d θj(∑y=1K p(y|xi) δ(y,yi) fj(xi) - ∑y=1K p(y|xi) fj(xi))

where λi and θj are the Lagrange multipliers.

Taking the derivative of L with respect to p(y|xi) and setting it to zero, we get:

p(y|xi) = exp(θj fj(xi)) / Z(xi)

where Z(xi) is the normalization factor:

Z(xi) = ∑y=1K exp(θj fj(xi))

Substituting this into the constraint ∑y=1K p(y|xi) = 1, we get:

∑y=1K exp(θj fj(xi)) / Z(xi) = 1

which can be simplified to:

Z(xi) = ∑y=1K exp(θj fj(xi))

This is the softmax function, which is the basis for the multi-class logistic regression model.

Therefore, we have shown that the maximum entropy model with feature function fj(xi)=[xi]j is equivalent to the multi-class logistic regression model without regularization.

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Answer:

D. y = 8.9 ÷ 0.4​

Step-by-step explanation:

I hope this helps

According to the question, the work done in stretching the spring from 3 ft. beyond its natural length to 7 ft. beyond its natural length is 8 lb·ft.

To calculate the work done, we need to use the formula:

\(\[ \text{Work} = \text{Force} \times \text{Distance} \]\)

Given that a force of 2 lb is required to hold the spring stretched 3 ft. beyond its natural length, we can consider this as the force applied to stretch the spring from 0 ft. to 3 ft. beyond its natural length.

Therefore, the work done in stretching the spring from 0 ft. to 3 ft. beyond its natural length is \(\(2 \, \text{lb} \times 3 \, \text{ft}\)\).

To find the work done in stretching the spring from 3 ft. beyond its natural length to 7 ft. beyond its natural length, we need to subtract the work done in stretching from 0 ft. to 3 ft. beyond its natural length.

Hence, the work done in stretching the spring from 3 ft. beyond its natural length to 7 ft. beyond its natural length is:

\(\[ \text{Work} = (2 \, \text{lb} \times 7 \, \text{ft}) - (2 \, \text{lb} \times 3 \, \text{ft}) \]\)

Simplifying the equation:

\(\[ \text{Work} = 14 \, \text{lb} \cdot \text{ft} - 6 \, \text{lb} \cdot \text{ft} \]\)

Therefore, the work done in stretching the spring from 3 ft. beyond its natural length to 7 ft. beyond its natural length is:

\(\[ \text{Work} = 8 \, \text{lb} \cdot \text{ft} \]\)

So, the answer is that the work done in stretching the spring from 3 ft. beyond its natural length to 7 ft. beyond its natural length is 8 lb·ft.

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