Convert the following numbers

540,000

Answer:0.00004

its that because like it is

Answer:

[HI] = 0.264M

Explanation:

Based on the equilibrium:

2HI(g) ⇄ H₂(g) + I₂(g)

It is possible to define Kc of the reaction as the ratio between concentration of products and reactants using coefficients of each compound, thus:

Kc = 0.0156 = [H₂] [I₂] / [HI]²

As initial concentration of HI is 0.660mol / 2.00L = 0.330M, the equlibrium concentrations will be:

[HI] = 0.330M - 2X

[H₂] = X

[I₂] = X

Where X is reaction coefficient.

Replacing in Kc:

0.0156 = [X] [X] / [0.330M - 2X]²

0.0156 = X² / [0.1089 - 1.32X + 4X² ]

0.00169884 - 0.020592 X + 0.0624 X² = X²

0.00169884 - 0.020592 X - 0.9376 X² = 0

Solving for X:

X = - 0.055 → False solution, there is no negative concentrations

X = 0.0330 → Right solution.

Replacing in HI formula:

[HI] = 0.330M - 2×0.033M

The food caloric content of the candy bar in nutritional calories per gram is 135 Cal.

Calorimeter is used to measure the amount of heat energy (Q) produced during a certain reaction. It depends on the mass of the substance (m), heat capacity (c) and the change in temperature (ΔT) during the process.

Mathematically it could be represented as,

\(\rm Q\ =\ m\times c\times \Delta\ T\)

     \(\rm =\ 23.3\times 8.72\times 15.5\)

     \(\rm = 3149.228\ kcal\)

The heat released during the process is 3149.228 kcal.

To calculate the nutritional calories per gram, divide the heat released by the mass in grams.

\(\rm Calories\ per\ gram\ = \frac{3149.228}{23.3}\)

                            \(\rm = 135.16\ kcal\)

                            \(\rm = 135\ Cal\)

Therefore, The food caloric content of the candy bar in nutritional calories per gram is 135 Cal.

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Answer:

ionic bonds are the weakest bonds

Explanation:

Answer:

The C-N bond is a double bond.

There is no free rotation about the C-N bond

Explanation:

Linus Pauling and Robert Corey carried out a painstaking study of the bond lengths of peptide bonds as well as the stereo chemistry of atoms and groups around the peptide bonds in the crystal structures of molecules containing one or a few peptide bonds.

Their findings indicate that the bond length of the C-N bond in crystalline peptides is intermediate in length (1.32 Å) between a typical C—N single bond (1.49 Å) and a C=N double bond (1.27 Å). This is because the peptide bond has some double bond character as a result of resonance involving the C=O and -NH moieties of the amide.

As a result of resonance as shown above, the peptide bonds are found to be planar hence free rotation about the C-N bond is hindered. The peptide bond is mostly found in the trans configuration because it is more energetically favourable than the cis configuration.

Summarily, owing to the existence of a partial double bond character between the α carbon and the amine nitrogen in the peptide, there is no free rotation around the C-N bond.

1. The % concentration is 20.7% and the molar concentration, Cm, is 1.5 M.

2. 7.8 grams of potassium sulfate will be formed.

3. 10.7 grams of ammonium chloride will be formed.

4. The volume of hydrogen gas that will be produced is 3.86 liters.

5. 21.43 grams of the 70% acetic acid is needed to prepare 500 grams of 3% acetic acid solution.

1. Mass of potassium sulfate = 1.5 moles * (174.26 g/mol) = 261.39 g

Mass of water (H₂O) = 1000 g

% = (mass of solute/mass of solution) x 100

% = (261.39 g / (261.39 g + 1000 g)) x 100

% ≈ 20.7%

Cm = moles of solute / volume of solution

Moles of potassium sulfate (K2SO4) = 1.5 moles

Volume of water (H2O) = 1000 g / (density of water) = 1000 g / 1 g/mL = 1000 mL = 1 L

Cm = 1.5 moles / 1 L

Cm = 1.5 M

2. The balanced equation for the reaction is:

H₂SO₄ + 2 KOH → K₂SO₄ + 2 H₂O

Molar mass of sulfuric acid (H₂SO₄) = 98.09 g/mol

Moles of sulfuric acid = 10 g / 98.09 g/mol

Moles of sulfuric acid = 0.102 mol

Based on the mole ratio of the reaction, 0.102 moles of sulfuric acid will react to form 0.102 moles of potassium sulfate.

Molar mass of potassium sulfate = 174.26 g/mol

Mass of potassium sulfate = 0.102 mol x 174.26 g/mol

Mass of potassium sulfate ≈ 17.8 g

3. The balanced equation for the reaction is:

Molar mass of hydrochloric acid (HCl) = 36.46 g/mol

Moles of hydrochloric acid (HCl) = 7.3 g / 36.46 g/mol

Moles of hydrochloric acid ≈ 0.2 mol

Based on the mole ratio of the reaction, 0.2 moles of hydrochloric acid will react to form 0.2 moles of ammonium chloride.

Molar mass of ammonium chloride (NH₄Cl) = 53.49 g/mol

Mass of ammonium chloride = 0.2 mol x 53.49 g/mol

Mass of ammonium chloride ≈ 10.7 g

4. The balanced equation for the reaction is:

Molar mass of zinc (Zn) = 65.38 g/mol

Moles of zinc = 13 g / 65.38 g/mol

Moles of zinc ≈ 0.199 mol

Based on the mole ratio of the reaction, 0.199 moles of zinc will react to produce 0.199 moles of hydrogen gas.

Volume of sulfuric acid = 30 g / (density of H₂SO₄ )

The density of H₂SO₄ is 1.84 g/mL

Volume of sulfuric acid  = 30 g / 1.84 g/mL

Volume of sulfuric acid ≈ 16.3 mL or 0.0163 L

Using the ideal gas law, the volume of hydrogen gas produced will be:

V = nRT / P

V = (0.199 mol)(0.0821 L·atm/(mol·K))(273 K) / (1 atm)

V ≈ 3.86 L

5. Assuming that the concentrated original solution of acetic acid is 100% acetic acid (CH₃COOH).

Mass of acetic acid = 500 g x (3/100) = 15 g

The concentrated original solution, however, is 70% acetic acid.

70% acetic acid (mass) = 100% acetic acid (unknown mass)

0.7 * (unknown mass) = 15 g

Solving for the unknown mass:

unknown mass = 15 g / 0.7

unknown mass ≈ 21.43 g

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Mass of the pure silver deposited on a metal object made into the cathode of the cell is calculated to be 0.0217 gm.

The process of using electrodeposition to coat an object in a layer of metal is called electroplating .

As we know that, Q = I * t

=0.270 * 72

= 19.44 C

Here Q is quantity of electricity , I is current in amperes = 0.270 A (given)

t is time in seconds (72.0 sec)

As 96500 Coulomb of electricity electrolyzes 1 mole of Ag

then,19.44 C of electricity deposits,

=1/96500 * 19.44

= 0.000201 moles of Ag

Mass of Ag is = number of moles * molar mass

= 0.000201 * 108

= 0.0217 gm

Thus, mass of pure silver deposited on a metal object made into the cathode of the cell is  0.0217 gm.

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According to the reaction 8 mols of O2 produce 5 mols of CO2. Then we just need to write and use that as a conversion factor:

Answer:

its sodium hydroxide

Explanation:

Answer: The final temperature is \(38.0^0C\)

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

\(heat_{released}=heat_{absorbed}\)

\(Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})\)

\(-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)]\)

\(-[m_1\times (T_{final}-T_1)]=[m_2\times (T_{final}-T_2)]\)   (as \(c_1=c_2\))

Q = heat absorbed or released

\(m_1\) = mass of water at \(85.0^0C\) = \(volume\times density=41.0ml\times 1g/ml=41.0g\)

\(m_2\) = mass of water at \(26.0^0C\) = \(volume\times density=161.0ml\times 1g/ml=161.0g\)

\(T_{final}\)  = final temperature = ?

\(T_1\)   = temperature of 41.0 ml of water = \(85.0^0C\)

\(T_2\)   = temperature of 161.0 ml of water = \(26.0^0C\)

Now put all the given values, we get

\(-[41.0\times (T_f-85.0)^0C]=161.0\times (T_f-26.0)^0C\)

\(T_f=38.0^0C\)

Thus the final temperature is \(38.0^0C\)

The percent by mass of the fluorine in the compound is 46.472%.

We know that the percent by mass has to do with the ratio of the total mass of the atom that is part of the compound and the total molar mass of the compound multiplied by one hundred.

The question in this case has demanded that we ought to obtain the mass percent of fluorine from the compound that we can be able to identify from the formula of the compound that is shown here as xenon hexa fluoride.

Mass of the compound can be obtained from; 131 + 6(19)

= 245 g/mol

The total mass of the fluorine atom in the compound is 114 g

Thus we have the use of;  114 /245 * 100/1

= 46.472%

The percent  by mass is now gotten for the fluorine atom as 46.472%.

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It is stated in this query that p above p is the rule when using the Clausius-Claparon equation.

According to what I'm going to explain, p not will be our boiling point, and that value will be equal to delta minus. The boiling point is determined by the formula: H, vapor pressure over r 1 over t minus 1 over t not and again t not. Thus, a pressure line can be seen here. According to what we've been told, it is 1 o 9 miles per hour. 680 would enter there, followed by delta h, at a distance of 6080000000 meters from Mercury. The vapourization factor is 2.46. I'm not going to include the units in this section because ideal gas has a constant 8.314 joules per mole.

It is - 66 degrees Celsius when mole kelvin is subtracted from the initial temperature. Since our boiling point would be 2 o 7 kelvin minus 1 over t, that would convert to that value. This will be plugged into my equation using the solver here, which yields 237 kelvin when accounting for t. The boiling point at 680 millimeters of mercury would be minus 273, which gives me a result of minus 36 degrees celsius, and we then translated that to degrees celsius.

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The volume of the gold plates in cm₃ is 2.513274 cm₃

Volume is the space occupied by a three-dimensional object“”

Volume = {mass} {density}

Given that the thickness or height of medallion, h = 2 mm = 0.2 cm

Diameter of the medallion, d = 4 cm

Radius of medallion, r = d/2 = 2 cm⁻³

The thickness of the gold plating, x = 1 μm = 10⁻⁴ cm

The density of gold = 19.3 g cm

Now we know that the shape of a medallion is cylindrical.

Hence, the volume of the medallion before platting,

Vbefore = π.r2.h = π.(2)2.0.2 = 2.513274 cm₃

Therefore, the volume of the gold-plated is 2.513274 cm₃.

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The correct option is C Osmotic pressure

Only Osmotic pressure is a colligative property.

What is Osmotic pressure?

Osmosis is the process by which water moves from a region with a low concentration of solute to one with a greater concentration. Atoms, ions, or molecules dissolved in a liquid are known as solutes. The total amount of particles dissolved in the fluid determines the rate of osmosis. The rate of osmosis increases with the number of particles that dissolve.

Water will go to the region with the highest solute concentration if a membrane is present. The pressure produced by water across a membrane as a result of osmosis is known as osmotic pressure. The osmotic pressure rises in direct proportion to the amount of water crossing the membrane.

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Answer:

\(E=1.98\times 10^{-31}\ J\)

Explanation:

Given that,

The frequency of a wave, f = 300 Hz

We need to find the energy of a wave. The formula for the energy of a wave is given by :

E = hf,

Where h is Planck's constant

\(E=6.63\times 10^{-34}\times 300\\\\=1.98\times 10^{-31}\ J\)

So, the energy of the wave is \(1.98\times 10^{-31}\ J\).

Answer:

89.6 F

Explanation:

Brain-List?

A chemical reaction is started by adding the borax solution to the glue mixture. A elastic, springy new material is produced when the glue and borax molecules interact.

Although cleaning is borax's most well-known application, the substance is also included in a wide range of home goods, such as specialty toothpastes and mouthwashes. goods for treating acne, including lotions, skin creams, moisturizers, and sunscreen. Ceramic glaze and paint.

Borax (sodium tetraborate) is different from baking soda (sodium bicarbonate). Both salts and widely used as "green" home cleaners, baking soda and borax have pH values of 8 and 9.5, respectively.

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The number of electrons that enter the 3d subshell of an atom whose atomic number is 22​ is 2.

An atom with an atomic number of 22 is Titanium. It is a strong, lightweight metal that is resistant to corrosion and is used in a variety of applications, including aircraft, spacecraft, medical implants, and jewelry.

The 3d subshell can hold up to 10 electrons, but Titanium only has 2 electrons in the 3d subshell. This is because the 4s subshell is lower in energy than the 3d subshell, so the electrons are filled in the 4s subshell before they are filled in the 3d subshell.

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The atmospheric conditions at a particular time.

i did the test.

Answer:

the atmospheric conditions at a particulur time

Explanation:

Answer:

so so

Explanation:

this your question?? <_>

Answer: option d

Explanation: a p e x

One mole of HCl contains 6.022 × 10²³ molecules. 2 moles of HCl reacts with one mole of MgO. Thus, 1.2 × 10²⁴ molecules of HCl will reacts with one mole of MgO.

One mole of any compound contains 6.022 × 10²³ molecules. This number is called Avogadro number. Thus,one mole hydrochloric acid  contains 6.022 × 10²³  HCl  molecules. Similarly one mole of every compound is composed of 6.022 × 10²³ molecules that constitutes the compound.

One mole of hydrogen chloride  contains 6.022 × 10²³ molecules.

Then, 2 moles of HCl = 2 × 6.022 × 10²³ =  1.2 × 10²⁴ molecules

These much HCl  molecules would reacts with one mole of MgO

Therefore, there would be 1.2 × 10²⁴ molecules of HCl to react with one mole of MgO.

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According to this question, we must know that everything related to grams, means a mass of something.

So, we cannot use grams (g) or kilograms (kg) as a unit of volume.

For volume, we use liters (L), milliliters (mL), and cm^3 as we see on the written question. Also, we have plenty of units for volume in different systems used to measure.

Answer: milliliters (mL) or centimeters cubic (cm^3)

Magnesium ribbon dissolves in zinc nitrate and copper nitrate solutions.

Even though the question is incomplete and refers to your practical work, however, I will try to help you as much as I can.

Metals dissolves in solutions of other metals that are lower than them in the electrochemical series. Hence, copper strip will show no change in magnesium nitrate or zinc nitrate solution. A zinc strip will not show any change in magnesium nitrate or zinc nitrate.

However, a magnesium ribbon will dissolve very quickly in zinc nitrate and copper nitrate solutions.

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Look at the screenshot attached

The concentration of the HNO3 solution is 0.117 M.

To solve this problem, we can use the balanced chemical equation to determine the mole ratio of HNO3 to Ba(OH)2:

2HNO3(aq) + Ba(OH)2(aq) ⟶ 2H2O(l) + Ba(NO3)2(aq)

From the equation, we see that 2 moles of HNO3 react with 1 mole of Ba(OH)2 to produce 2 moles of H2O and 1 mole of Ba(NO3)2. Therefore, the moles of HNO3 in the unknown solution can be calculated from the volume and concentration of Ba(OH)2 used:

moles of Ba(OH)2 = concentration × volume = 0.150 M × 0.0411 L = 0.006165 mo

moles of HNO3 = 2 × moles of Ba(OH)2 = 2 × 0.006165 mol = 0.01233 mol

Finally, we can calculate the concentration of the HNO3 solution:

concentration = moles / volume = 0.01233 mol / 0.105 L = 0.117 M

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Answer:

heterogeneous and homogeneous

Explanation:

la po ba abc?