Using the conversion factor that we have seen in the solution, the value obtained is 40.25 kilometers per hours
How do you convert miles/hour to kilometers per hour?To convert miles per hour (mph) to kilometers per hour (kph), you need to multiply the speed value in mph by a conversion factor of 1.61, which is the number of kilometers in one mile.
Given that;
1 miles/hour = 1.61 kilometer per hour
25 miles per hour = 25 * 1.61/1
= 40.25 kilometers per hours
Hence the value that we get is 40.25 kilometers per hours
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The convert unit of 25 miles per hour is equivalent to 40.2335 kilometers per hour
Convert units calculation.
Unit conversion is the process of converting a value expressed in one unit of measurement to another unit of measurement that is equivalent in terms of its value or quantity. This is done by using a conversion factor, which is a numerical factor that relates the two units of measurement.
To convert miles per hour (mph) to kilometers per hour (km/h), we need to multiply the speed in mph by 1.60934, which is the conversion factor from miles to kilometers.
So, to convert 25 mph to km/h:
25 mph × 1.60934 = 40.2335 km/h
Therefore, 25 miles per hour is equivalent to 40.2335 kilometers per hour.
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Many drivers' education books provide tables that relate a car's braking distance to the speed of the car. Utilize what you have learned about the stopping distance-velocity relationship tocomplete the table.
To solve this problem we must apply Torricelli equation:
\(v^2=v^2_o+2\times\alpha\times d^{}_{}\)where:
v = final velocity
vo = initial velocity
α = acceleration
d = distance
Lets use the information of the first row of the table to find a:
\(\begin{gathered} v^2=v^2_o+2\times\alpha\times d^{}_{} \\ 0^2=60^2+2\times\alpha\times240 \\ 0=3,600+480\times\alpha \\ -480\times\alpha=3,600 \\ \alpha=\frac{3,600}{-480} \\ \alpha=-7.5ft/s^2 \end{gathered}\)Now we can calculate distances a, b and c:
\(\begin{gathered} v^2=v^2_{^{}o^{}}+2\times\alpha\times d \\ 0^2=40^2+2\times(-7.5)\times d \\ 0=1,600-15\times d \\ 15\times d=1,600 \\ d=\frac{1,600}{15} \\ d\approx107ft \end{gathered}\)So distance a = 107 ft.
Now we have:
\(\begin{gathered} v^2=v^2_o+2\times\alpha\times d \\ 0^2=30^2+2^{}\times(-7.5)\times d \\ 0=900-15\times d \\ 15\times d=900 \\ d=\frac{900}{15} \\ d=60ft \end{gathered}\)So distance b = 60 ft.
Finally:
\(\begin{gathered} v^2=v^2_o+2\times\alpha\times d \\ 0^2=10^2+2\times(-7.5)\times d \\ 0=100-15\times d \\ 15\times d=100 \\ d=\frac{100}{15} \\ d\approx7ft \end{gathered}\)
So distance c = 7 ft.
soulve the plane polare eqestion in circular
Answer:
Explanation:
u
Will give brainliest!
A pair of fuzzy dice is hanging by a string from your rearview mirror. While you are accelerating from a stop-light to 28 m/s in 6.0 s, what angle theta does the string make with the vertical?
For the pair of fuzzy dice hanging by a string from the rearview mirror, while accelerating from a stop-light to 28 m/s in 6.0 s, the string makes an angle of 25.5 degrees with the vertical.
What is an angle?An angle is the figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle.
Parameters given include:
velocity: 28,/s time= 6.0 seconds
a = v/t = 28m/s / 6.0s = 4.667 m/s²
Taking into account the forces acting on the dice...there is a force of gravity acting straight down with a magnitude of mg.
so we have that
Angle = tan-1(a/g)
Angle = tan-1(4.667 / 9.8) = 25.5 degrees.
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An acetate rods rubs against a cloth. What type of charge will the rod end up with?
A. Positive
B. Negative
C. Not enough info
D. Neutral
Answer:
I believe it's A
Explanation:
........
A 4kg mass is placed on an inclined plane. A 5 N, a 4 N and a second 5 N force each act on the mass, as shown on the free body diagram below. There are no other forces acting.
Answer: A
Explanation:
A system has two possible energy states, E0 and E1 (with E1 > E0). If the difference between these energy states grows (E0 and E1 get further apart while the temperature stays constant), then the ratio of the number of particles in state E0 over the number of particles in state E1 will:__________
Answer:
The number of particles in state E0 over the number of particles in state E1 will reduce
Explanation:
E0 represents the ground level state when all the particles have same energy level.
E1 represents excited state in which only a few particle reaches
E0 and E1 get further apart means that the energy difference between the two level increases.
Thus, the number of particles in state E0 over the number of particles in state E1 will reduce.
can anyone write for me all the equation of linear motion
All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.
Equations of MotionIn terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.
s = ut + (1/2)at^2v = u + atv_avg = (u + v) / 2s = v_avg * ts = (u + v) / 2 * tv^2 = u^2 + 2asIn conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.
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Which of the following statements is falsifiable?
a. Henry Ford invented the first automobile.
b. Fords are the best automobiles.
c. Henry Ford did not invent the first automobile.
d. Fords are not the best automobiles.
e. An automobile is a self-propelled vehicle.
We have that the statements found falsifiable is
Henry Ford invented the first automobile.
Option A
Henry FordGenerally in as much Ford motor is a great vehicle company
He did not create the first automobile
Credit is give to Karl Benz for The first auto-mobile
Therefore
The statements found falsifiable is
Henry Ford invented the first automobile.
Option A
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Q1) Assertion : a vector can be resolved into maximum two components
Reason : in projectile motion the velocity is resolved into vertical and horizontal components
a) Both A and R are correct; R is the correct explanation of A
b) Both A and R are correct; R is not correct explanation of A
c) A is correct; R is not correct
d) A is not correct; R is correct
Q2) Assertion : speed is constant in uniform circular motion
Reason : acceleration is constant in uniform circular motion
a) Both A and R are correct; R is the correct explanation of A
b) Both A and R are correct; R is not correct explanation of A
c) A is correct; R is not correct
d) A is not correct; R is correct
Answer:
Explanation:
Q1) d) A is not correct; R is correct (sort of) but is not the reason for A.
A vector may be resolved into an infinite number of components.
Breaking a projectile motion into the vertical and horizontal components is the EASIEST way to solve it because acceleration can be assumed to be constant in both directions. Zero for horizontal and g(ravity) in the vertical. However it is not the ONLY way to do it. Other ways are much more complex.
Q2) a) Both A and R are correct; R is the correct explanation of A (sort of)
A is correct. Speed is constant in uniform circular motion.
R is correct if you call CENTRIPETAL acceleration constant. It is only constant in magnitude. The direction is always changing as the vector always points toward the center of rotation.
What characteristics determine how easily two substances change temperature? Check all that apply.
volume of the two substances in contact
amount of time the two substances are in contact
Oarea in contact between the two substances
specific heat of the material that makes up the substances
density of the two substances in contact
Answer:
The characteristics that determine how easily two substances change temperature are:
specific heat of the material that makes up the substancesarea in contact between the two substancesThe volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.
Explanation:
True or false? In a water ripple, the wave speed is the speed that the water particles are moving
Answer:
True
Explanation:
I am 99% this is the correct answer, I hope I help :)
The given statement "In a water ripple, the wave speed is the speed that the water particles are moving" is false because the water particles do not move at the same speed as the wave.
The wave speed is the speed at which the wave travels through a medium. In the case of a water ripple, the wave speed is the speed at which the disturbance in the water travels from one point to another. The water particle speed is the speed at which individual water particles move. The water particle speed is typically much slower than the wave speed.
The water particles move in a circular motion, while the wave travels in a straight line. This means that the water particles are moving much slower than the wave. For example, if you drop a pebble into a calm pond, you will see a ripple travel outward from the point where the pebble hit the water. The ripple will travel at a speed of about 3 feet per second. However, the water particles in the ripple will only move about 0.1 feet per second. This means that the wave speed is about 30 times faster than the water particle speed.
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An object of mass 3.0 kg starts from rest and moves along the x-axis. A net horizontal force is applied to the object in the +x direction. The Force-time graph is shown below. What is the net impulse delivered by the applied force?
Answer:
120
Explanation:
because it is horizontal
An object of mass 3.0 kg starts from rest and moves along the x-axis. A net horizontal force is applied to the object in the +x direction. The Force-time graph is shown below. The net impulse delivered by the applied force is 102 joule.
What is force ?A force is an influence that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Force is used to describe a body's tendency to modify or change its state as a result of an external cause. When force is applied, the body can also alter its size, shape, and direction. kicking a ball, pushing and pulling on the door, or kneading dough are a few examples.
We know the Impulse = Area of the Graph
= ( 6 × 4) + 0.5 × 2 × 6
= 30 sec
For First 4 sec
Acceleration = 6 ÷ 3
= 2 m/sec²
S = 0.5 × 2 × 4²
= 16 m
Therefore, work Done = 6 × 16
= 96 J
Then, Average force
= ( 6 - 0 ) ÷ 2
= 3 N
Acceleration = 1 m/sec²
S = 0.5 × 1 × 2²
= 2 m
Work = 3 × 2
= 6 J
Total Work = 96 + 6
= 102 J
Thus, The net impulse delivered by the applied force is 102 joule.
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What composes about 71% of Earth's outermost layer?
A
oceanic crust
B
asthenosphere
С
lithosphere
D
continental crust
Answer:
A. oceanic crust
Explanation:
I remember that the ocean is said to cover 71% of the Earth's surface. If you look at a globe, notice that most all the surface is blue like the ocean.
One other note: the surface is the Earth's outermost layer. Think of it this way: surface implies the top of something, something exposed to the outside.
Therefore, the answer is A. Hope this helps you understand the question more! Have a great day, 'kay?
A baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby weighs 20
kg. The carriage has
energy. Calculate it
Answer:
Energy in carriage (Potential energy) = 4,116 J
Explanation:
Given:
Mass of baby = 20 kg
Height = 21 m
Find:
Energy in carriage (Potential energy)
Computation:
The energy accumulated in an object as a result of its location relative to a neutral level is known as potential energy.
In carriage accumulated energy is potential energy.
Energy in carriage (Potential energy) = mgh
Energy in carriage (Potential energy) = (20)(9.8)(21)
Energy in carriage (Potential energy) = 4,116 J
Three objects are brought close to each other, two at a time. When objects A and B are brought together, they repel. When objects B and C are brought together, they also repel. Which of the following are true?
a. additional experiments must be performed to determine the signs of hte cahrges.
b. objects A and C possess charges of the samesign.
c. one object is neutral.
d. objects A and C possess charges of the oppostite sign.
e. all three objects possess charges of the same sign.
Answer:
option (e) = all three objects possess charges of the same sign.
Explanation:
To understand this particular problem or question, one has to take each point from the question/problem above with care;
=> "Three objects are brought close to each other, two at a time. "
Deduction: Only two are brought together at a time.
=> "When objects A and B are brought together, they repel."
DEDUCTIONS: A and B do not attract which is because A and B POSSESS THE SAME SIGN.
=> "When objects B and C are brought together, they also repel."
DEDUCTION: A and C POSSESS THE SAME SIGN.
CONCLUSION: Thus, If A and B do not attract and B and C also repel, then, it is possible that A, B and C are of the same sign. The law in which this follows is known as the law of transitivity.
Help me please I need it as soon as possible
Answer: B im sorry if its wrong
Explanation:
As shown in the diagram below, a rope attached to a 500.-kilogram crate is used to exert a force of 45 newtons at an angle of 65 degrees above the horizontal 45 N at an angle of 65 degrees above the horizontal.
500 kg
The horizontal component of the force acting on the crate is?
Answer:
19.01 N
Explanation:
F = Force being applied to the crate = 45 N
\(\theta\) = Angle at which the force is being applied = \(65^{\circ}\)
Horizontal component of force is given by
\(F_x=F\cos\theta\\\Rightarrow F_x=45\times \cos65^{\circ}\\\Rightarrow F_x=19.01\ \text{N}\)
The horizontal component of the force acting on the crate is 19.01 N.
POINTS + BRAINLIEST TO CORRECT ANSWER
In old Polaroid cameras, the image was projected on film that developed inside the camera. The developed image was then ejected from the camera as a printed photograph. The standard film size for one popular camera was 79 mm square. The film was 116 mm behind the lens.
If you wanted a picture of your 1.8-m-tall friend to fill half the frame, how far away from you did she need to stand?
100 points + Brainliest to correct answer
Answer:
5.3 m
Explanation:
Your friend is 1800 mm tall, and you want them to fill half the frame (79 mm / 2 = 39.5 mm).
The film is 116 mm behind the lens. Using similar triangles:
x / 1800 = 116 / 39.5
x = 5286
Rounded to two significant figures, your friend should stand 5.3 meters away.
If 25 kg of ice at 0°C is combined with 4 kg of steam at 100°C, what will be the final equilibrium temperature (in °C) of the system?
Answer:
The temperature of the final equilibrium temperature of the system is 19.7⁰C
Explanation:
Given;
mass of the ice, m₁ = 25 kg
temperature of the ice = 0°C
mass of the steam, m₂ = 4 kg
temperature of the steam, = 100 ⁰C
Let the temperature of the resulting mixture = t
Apply the principle of conservation of energy.
Heat required to melt the ice + Heat gained by the mixture = Heat required to convert the water to steam + Heat lost by the mixture
\(m_1L_f + m_1c (t - 0) = m_2L_v + m_2c(100 - t)\)
where;
Lf is the latent heat of fusion of ice = 3.33 x 10⁵ J/kg.
Lv is the latent heat of vaporization of water, = 2.260 x 10⁶ J/kg
c is the specific heat capacity of water = 4,200 J/kg
\(m_1L_f + m_1c (t - 0) = m_2L_v + m_2c(100 - t)\\\\25 \times 3.33\times 10^5 + 25\times 4,200 (t ) = 4\times 2.26\times 10^6 + 4\times 4,200(100 - t)\\\\8,325,000 + 105,000t = 9,040,000 + 1,680,000 - 16,800t\\\\105,000t + 16,800t = 10,720,000 - 8,325,000\\\\121,800t = 2,395,000\\\\t = \frac{2,395,000}{121,800} \\\\t = 19.7 \ ^0 C\)
The temperature of the final equilibrium temperature of the system is 19.7⁰C
What is the ratio of thicknesses of glycerine (refractive index 1.473) to crystalline quartz (refractive index 1.544) such that they would contain the same number of wavelengths of 646nm light
Answer: The ratio of thicknesses of glycerine (refractive index 1.473) to crystalline quartz (refractive index 1.544) is 0.954.
Explanation:
Given: Refractive index of glycerine = 1.473
Refractive index of crystalline quartz = 1.544
Formula used is as follows.
\(2nt = m \lambda\)
For crystalline quartz: \(2n_{q}t_{q} = m \lambda_{q}\)
For glycerine: \(2n_{g}t_{g} = n \lambda_{g}\)
Here, m = n and \(\lambda_{q} = \lambda_{g}\)
So, the ratio of both these values can be written as follows.
\(\frac{2n_{q}t_{q}}{2n_{g}t_{g}} = \frac{m \lambda_{q}}{n \lambda_{g}} = 1\)
So, \(n_{q}t_{q} = n_{g}t_{g}\)
\(\frac{t_{q}}{t_{g}} = \frac{n_{g}}{n_{q}} = \frac{1.473}{1.544}\)
\(\frac{t_{q}}{t_{g}} = 0.954\)
Thus, we can conclude that the ratio of thicknesses of glycerine (refractive index 1.473) to crystalline quartz (refractive index 1.544) is 0.954.
A rigid tank contains an ideal gas at 300 kPa and 600 K. Now half of the gas is withdrawn from the tank and the gas is found at 100 kPa at the end of the process. Determine (a) the final temperature of the gas and (b) the final pressure if no mass was withdrawn from the tank and the same final temperature was reached at the end of the process.
Which of the following describes the transformation of chemical energy to heat energy?
A.plugging in a blow dryer
B.making toast in a toaster
C.a rock hitting the ground
D.wood burning in a fireplace
Answer:
Burning wood in a fireplace
Explanation:
9. A blender with a 7 ohms resistance uses 350W of power. What is the current in the blender's circuit?
Question :-
A Blender with a 7 Ohms Resistance uses 350 Watt of Power . What is the Current in the Blender's Circuit ?Answer :-
Current in the Circuit is 50 Ampere .Explanation :-
As per the provided information in the given question, we have been given that the Resistance of the Blender is 7 Ohms . Its Power is given 350 Watt . And, we have been asked to calculate the Current in the Blender's Circuit .
For calculating the Current , we will use the Formula :-
\( \bigstar \: \: \: \boxed{ \sf{ \: Current \: = \: \dfrac{Voltage}{Resistance} \: }} \)
Therefore , by Substituting the given values in the above Formula :-
\( \dag \: \: \: \sf { Current \: = \: \dfrac{Voltage}{Resistance}} \\ \)
\( \longmapsto \: \: \: \sf { Current \: = \: \dfrac{350}{7}} \\ \)
\( \longmapsto \: \: \: \textbf {\textsf { Current \: = \: 50}} \\ \)
Hence :-
Current = 50 Ampere .\( \underline {\rule {180pt} {4pt}} \)
A heat engine does 200 J of work per cycle while exhausting 400 J of waste heat. what is the engine's thermal efficiency?
The engine thermal efficiency is 50%
The engine does 200 joules of work per cycle
It exhausts 400 j
The thermal efficiency can be calculated as follows
= 200/400
= 0.5 × 100
= 50 %
Hence the engine thermal efficiency is 50%
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1. What is the function of a lightning rod?
2. How is charge build-up reduced on airplanes?
3. Why is a ground strap a necessary safety feature when transferring fuel?
4. What are three different methods for reducing charge build-up in clothes dryers?
5. What are four different methods for reducing charge build-up in a computer room with a carpet?
Answer: 1. The function of a lightning rod is to protect buildings, structures, and people from lightning strikes by providing a path of least resistance for the electrical current to follow, directing it safely into the ground instead of through the structure or people.
2. Charge build-up is reduced on airplanes through various methods, such as using conductive materials in the airplane's structure, applying anti-static coatings on the airplane's surface, and installing static discharge wicks or similar devices on the airplane's trailing edges, which provide a way for any accumulated charge to safely dissipate into the air.
3. A ground strap is a necessary safety feature when transferring fuel because it provides an electrical connection between the fuel container and the receiving container, allowing any static charge to safely dissipate into the ground. Without a ground strap, the static charge could build up and potentially ignite the fuel.
4. Three different methods for reducing charge build-up in clothes dryers are: (1) using dryer sheets or fabric softeners, which can help neutralize static charges on the clothes, (2) adding a damp cloth to the dryer, which can help dissipate static charges, and (3) using metal dryer balls, which can physically separate clothes and prevent them from rubbing against each other and creating static charges.
5. Four different methods for reducing charge build-up in a computer room with a carpet are: (1) using conductive flooring or carpet tiles that can help dissipate static charges, (2) using anti-static mats or wrist straps for personnel who work in the room, (3) using air ionizers or humidifiers, which can help neutralize static charges in the air, and (4) grounding all equipment and devices in the room to prevent the buildup of static charges.
Explanation:
I hope this helps!
what are the greenhouse gasses in the earth that are primarily responsible for the greenhouse effect on Earth
Answer:
Water Vapour, Carbon dioxide, methane,nitrous oxide,ozone.
What is the magnitude of the total force exerted by these two charges on a negative point charge q3
= -5.95 nC
that is placed at the origin?
The force exerted between the charges q1 and q3 is -5.25 × 10⁻⁶ N and that between q2 and q3 is -2.93 × 10⁻⁶ N. Hence the net force is - 8.18 × 10⁻⁶ N .
What is Coulomb's law ?According to Coulomb's law of force, the electrostatic force between two charges separated by a distance of r is given as follows:
Fc = Ke q1 q2 /r²
where Ke = 8.9 × 10⁹ Nm²/C²
Given the charge of q1 = 3.97 × 10⁻⁹ C
charge of q3 = -5.95 × 10⁻⁹ C
distance r = 0.200 m
then Fc = 8.9 × 10⁹ Nm²/C² ( 3.97 × 10⁻⁹ C) (-5.95 × 10⁻⁹ C)/(0.200 m)² = -5.25 × 10⁻⁶ N
Similarly, the force on q3 by the charge q2 is calculated as follows:
distance to q2 = 0.30 m
charge of q2 = 4.99 × 10⁻⁹ C.
Then Fc = 8.9 × 10⁹ Nm²/C² (4.99 × 10⁻⁹ C ) (-5.95× 10⁻⁹ C)/(0.30 m)² = - -2.93 × 10⁻⁶ N
The net electric force acting on A = 3.9 × 10⁻⁵ N - (-1.9 × 10⁻⁵ N) = 5.8 × 10⁻⁵ N.
Therefore, the net electric force acting on q3 is 8.18 × 10⁻⁶ N.
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Your question is incomplete. But your complete question probably was:
Two point charges are placed on the x-axis as follows: charge 3.97 nC is located at 0.200 m (q1) and charge 4.99 nC (q3) is at -0.304 m .What is the magnitude of the total force exerted by these two charges on a negative point charge q3
= -5.95 nc that is placed at the origin?
What is the physiological response of the body when exercise is stopped instantaneously?
Blood flow rapidly decreases and blood pools in your feet
Blood flow rapidly decreases and lung capacity increases
Blood flow rapidly increases and heart rate decreases
Blood flow rapidly increases and blood pools in your hands
Answer:
Blood flow rapidly decreases and blood pools in your feet
Explanation:
Because I did the test and if u don't want to except my answer then ***** but if u do and get it right mark it the best. OK?
Answer:
The answer is A blood flows rapidly decreases blood pools in your feet
Explanation:
I hope the helps i just did the quiz/test and got it correct
Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105
. The figure illustrates the configuration.
A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.
The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.
The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.
The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.
The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.
The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).
The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).
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Why are theories constructed
A) During the experiment
B) after data is collected from an experiment
C) before the experiment
D) after there is numerous data collected
Answer:
The correct answer is d.
Theories are constructed after there is numerous data collected during the experiment.
Explanation:
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