Consider two people on the surface of the earth. One is on the equator, and the other is at the north pole. Which person experiences the larger centripetal acceleration?.

Answers

Answer 1

Centripetal acceleration is the force that is directed toward the center of rotation. It is always directed toward the axis of rotation and always perpendicular to the velocity of the body moving in a circular path.

The equation for centripetal acceleration is a = v²/r.

The faster an object is moving and the smaller the radius of its circular path, the greater the centripetal acceleration experienced by the object.

Considering two people on the surface of the earth, one at the equator and the other at the North Pole, the person at the equator will experience a larger centripetal acceleration than the person at the North Pole.

This is because the person at the equator is traveling around the earth's axis of rotation at a higher velocity than the person at the North Pole. This is due to the fact that the equator is farther from the axis of rotation than the North Pole.

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Related Questions

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hey! please help ill give brainliest!

Answers

answer is : 2nd option!

if one of the 12v rails required 150 and the second needed 350, how much wattage would the first rail get?

Answers

The first rail would get 150 wattage power.

There are two rails, each requiring 150 watts of electricity and 350 watts of power. Even if two dual rails of 150 watts and 350 watts are available, the wattage offered on the back of the power supply will always be the maximum output power. There will also always be a voltage selection button on the back side of the power supply to pick between numerous voltages and powers. As a result, the first rail of 150 watts will always have a maximum output of 150 watts.

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*by hand, if possible*
Question 3 An experiment has been conducted to test the failure of aluminium under repeated alternating stress at 210000 psi and 18 cycles per second. The numbers of cycles to failure of n = 70 alumin

Answers

The experiment on failure of aluminium under repeated alternating stress shows that the mean number of cycles to failure of n = 70 aluminum specimens was 11400 cycles.

The experiment aimed to test the failure of aluminum under repeated alternating stress at 210000 psi and 18 cycles per second. The experiment was performed on 70 aluminium specimens, and it was found that the mean number of cycles to failure was 11400 cycles. The experiment shows that the number of cycles to failure is affected by various factors, including the material properties and the stress level.The experiment findings could be used to determine the suitability of aluminium in applications where it would be subjected to repeated alternating stress. The experiment could be repeated under different stress levels to determine the material's performance under various stress levels. The data collected in the experiment could be used to design materials that are better suited for applications that involve repeated alternating stress.

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A 1 liter jar contains 0.5 moles of gas at a pressure of 2 atm. What is the temperature of the gas?


What is the volume of a
container of 4 moles of gas at 200 K with a pressure of 3 atm?


Your scientist friend is trying to figure out how many molecules of gas are in a container. They know that the container has a volume of 5 liters, and they measured the pressure and temperature to be 3.5 atm and 275 K. From this information, what do you tell them the mole measurement should be?


Answers

Explanation:

A)   PV = n RT    

  2*  ( 1)  =  .5 (.082057)(T)       T is in Kelvin

    T = 48.7 K

B) PV = nRT

  3 *  V = 4 ( .082057)(200)

          V = 21.88 Liters

C) PV = nRT

   3.5 (5) = n (.082057)(275)    n = .776 moles

The gravitational force between the sun and every object in the solar system helps keep each object in its own unique orbit around the sun. Lesson 3. 03 Question 2 options: True False.

Answers

Answer:

True

Explanation:

i did the Quiz

Answer:

A: true

Explanation:

I took the test its right, trust me I got 100%

A bicycle wheel has a radius r = 0.25 m and rotates at a constant frequency of f = 98 rev/min. Calculate the period of rotation T of the wheel in seconds. What is the tangential speed of a point on the wheel's outer edge in m/s?

Answers

The period of rotation of the wheel is 0.6127 seconds.

The tangential speed of a point on the wheel's outer edge is 2.5624 m/s.

    To calculate the period of rotation T, we need to convert the frequency from revolutions per minute (rev/min) to revolutions per second (rev/s).

Given:

The radius of the wheel (r) = 0.25 m

Frequency of rotation (f) = 98 rev/min

First, let's convert the frequency to rev/s:

Frequency in rev/s = Frequency in rev/min / 60

f' = 98 rev/min / 60 = 1.6333 rev/s (rounded to four decimal places)

Now, we can calculate the period of rotation T:

T = 1 / f'

T = 1 / 1.6333 rev/s  = 0.6127 s (rounded to four decimal places)

The period of rotation (T) of the wheel is approximately 0.6127 seconds.

          To calculate the tangential speed of a point on the wheel's outer edge, we can use the formula:

Tangential speed = \(\frac{2\pi r}{T}\), where T is the time period

Substituting the given values:

Tangential speed = 2 * \(\pi\) * (0.25 m) / 0.6127 s

Tangential speed = 2 * 3.14 * 0.25  / 0.6127 s = 2.5624 m/s (rounded to four decimal places)

The tangential speed is 2.5624 m/s.

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A spring is compressed, increasing its tension. The work done compressing the spring is 1.32 J.While being compressed, the spring heats the hand of the person pushing on it by a net of 0.15 J.What is the change in the spring’s internal energy?

Answers

When a spring is compressed, its tension increases, and the potential energy stored in the spring also increases. The work done in compressing the spring is equal to the change in potential energy stored in the spring.

In this case, the work done is 1.32 J. Therefore, the change in potential energy is also 1.32 J. However, we know that the spring also heats the hand of the person pushing on it by a net of 0.15 J. This means that some of the potential energy stored in the spring is converted into thermal energy, and hence lost. This energy loss can be accounted for by the change in internal energy of the spring. Therefore, the change in the spring's internal energy is equal to the difference between the change in potential energy and the energy lost as heat. Change in internal energy = Change in potential energy - Energy lost as heat, Change in internal energy = 1.32 J - 0.15 J, Change in internal energy = 1.17 J. So, the change in the spring's internal energy is 1.17 J. To calculate the change in a compressed spring's internal energy, we need to consider the work done on the spring and the energy transferred as heat. In this case, the work done compressing the spring is 1.32 J, and the net heat transferred to the person's hand is 0.15 J.

The first law of thermodynamics states that the change in internal energy (ΔU) of a system is equal to the work done on the system (W) minus the heat transferred from the system (Q). Therefore, we can write the equation as: ΔU = W - Q. Substitute the given values into the equation: ΔU = 1.32 J - 0.15 J. ΔU = 1.17 J. The change in the spring's internal energy is 1.17 J.

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True or False: A balanced force acts on different objects, and action-
eaction forces act on the same object. *
A. True
B. False

Answers

Answer:

true

Explanation:

according to the Newton's third law

A 25.0 kg door is 0.925 m wide. A customer
pushes it perpendicular to its face with a 19.2
N force, and creates an angular acceleration
of 1.84 rad/s2. At what distance from the axis
was the force applied?
[?] m
Hint: Remember, the moment of inertia for a panel
rotating about its end is I = mr².

Answers

The distance from the axis of the force applied is 2.05 m.

What is the distance from the axis of the force applied?

The distance from the axis of the force applied is calculated as follows;

The formula for torque;

τ = Fr

where;

F is the applied forcer is the distance from the axis of the force applied

Another formula for torque is given as;

τ = Iα

where;

I is the moment of inertia of the doorα is the angular acceleration;

τ = (mr²)α

τ = (25 kg x (0.925 m)²) x (1.84 rad/s²)

τ = 39.36 Nm

The distance is calculated as;

r = τ/F

r = ( 39.36 Nm ) / (19.2 N)

r = 2.05 m

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If you slid down Splash Mountain you would eventually come to a big pool at the end. Which one of Newton's Laws is this?

Answers

Answer:

Gravity

Explanation:

Answer:

law of gravity

Explanation:

i think

The sun appears to move across the sky, because the earth spins on its axis. To a person standing on the earth, the sun subtends an angle of sun = 9.27 x 10-3 rad (see Conceptual Example 2). How much time (in seconds) does it take for the sun to move a distance equal to its own diameter?

Answers

It takes about 8.12 × 10^9 seconds for the sun to move a distance equal to its own diameter.

The diameter of the sun is 1.39 million kilometers. We know that the sun subtends an angle of 9.27 × 10^−3 rad. Therefore, the distance that the sun moves across the sky is:

d = rθ

where d is the distance,

r is the radius of the earth,

and θ is the angle in radians.

θ = 9.27 × 10^−3 radr

= 6.37 × 10^6 m

Therefore, d = 6.37 × 10^6 × 9.27 × 10^−3

= 58.992 km

To calculate the time it takes for the sun to move this distance, we need to use the formula for speed, which is:

s = d/twhere s is the speed, d is the distance, and t is the time.

t = d/swhere s is the speed of the sun across the sky.

We know that the earth takes 24 hours to complete one rotation, which means that it moves 360 degrees in that time. Therefore, its angular velocity is:

w = 360°/24 h = 15°/h = 0.004167°/s

The angular velocity of the sun is the same as that of the earth, so its speed across the sky is also 0.004167°/s.

Therefore, we have:

s = 0.004167°/s = 0.004167 × 2π/360 rad/s

= 7.27 × 10^−6 rad/s

Substituting this value of s into the formula for time, we get:

t = 58.992 km/(7.27 × 10^−6 rad/s)

= 8.12 × 10^9 s

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What are the 3 ideal gas laws?

Answers

Answer:

Boyle's law, Charles's law, and Avogadro's law

Explanation:

what are the conditions for a body to be at equilibrium

Answers

Conditions for equilibrium require that the sum of all external forces acting on the body is zero (first condition of equilibrium), and the sum of all external torques from external forces is zero (second condition of equilibrium). These two conditions must be simultaneously satisfied in equilibrium.

Answer:

Explanation:

Conditions for equilibrium require that the sum of all external forces acting on the body is zero (first condition of equilibrium), and the sum of all external torques from external forces is zero (second condition of equilibrium). These two conditions must be simultaneously satisfied in equilibrium

How does understanding momentum help you in your daily life?

Answers

Answer:

It is an essential concept of physics. In sports momentum term is commonly used. Like, if a team has the momentum then it is on the move and is going to take some effort to stop. But if a team has lot of momentum then it is really on the move and is going to be hard to stop

Explanation:

a worker aciddentally kicks a rock off of a roof of a 5m tall building at 2 m/s. what is the distance (range) x from the edge of the building where the rock will land?

Answers

Answer:
We can use the equations of motion to find the horizontal distance (range) x from the edge of the building where the rock will land. The vertical motion of the rock is governed by the acceleration due to gravity, which is constant and equal to 9.81 m/s^2.

First, we can find the time it takes for the rock to hit the ground using the vertical motion equation:

y = vi*t + (1/2)at^2

where y is the initial height of the rock (5 m), vi is the initial vertical velocity of the rock (0 m/s), a is the acceleration due to gravity (-9.81 m/s^2), and t is the time it takes for the rock to hit the ground.

Solving for t, we get:

t = sqrt((2*y)/a) = sqrt((2*5)/9.81) = 1.02 s

Now we can find the horizontal distance (range) x from the edge of the building using the horizontal motion equation:

x = vx*t

where vx is the horizontal velocity of the rock, which is constant and equal to 2 m/s.

Substituting the values we have, we get:

x = 2 m/s * 1.02 s = 2.04 m

Therefore, the distance (range) x from the edge of the building where the rock will land is 2.04 meters.

What is remote sensing

Answers

The process of acquiring information, monitoring, and detecting the characteristics of any phenomenon or an object is called Remote Sensing. This is done by measuring the radiation emitted or reflected by the said object or phenomenon from some distance. Remote Sensing is typically done via a satellite or an airplane to collect data on Earth and other planets in space.

There are some special cameras that are used to collect images through the process of remote sensing. The researchers then "sense" some inferences from these images to get the required data.These cameras capture images of large areas of the Earth's surface. This helps in screening and observing a lot more information than what would have been possible by simply standing on the ground.

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power is function of time . give reason ​

Answers

Reason: The quantity work has to do with a force causing a displacement. Work has nothing to do with the amount of time that this force acts to cause the displacement. Sometimes, the work is done very quickly and other times the work is done rather slowly. For example, a rock climber takes an abnormally long time to elevate her body up a few meters along the side of a cliff. On the other hand, a trail hiker (who selects the easier path up the mountain) might elevate her body a few meters in a short amount of time. The two people might do the same amount of work, yet the hiker does the work in considerably less time than the rock climber. The quantity that has to do with the rate at which a certain amount of work is done is known as the power. The hiker has a greater power rating than the rock climber.

Power is the rate at which work is done. It is the work/time ratio. Mathematically, it is computed using the following equation.

Power = Work / time

or  

P = W / t

What is the difference between zone coverage and man coverage, and how can the offense team read those coverages?

Answers

Answer:

zone coverage is about sensing what the offense is attempting to accomplish against the defense. Each defensive player reacts when the ball is in the air, whereas in man-to-man coverage, he simply plays the receiver.

Explanation:

How is AU different from a solar mass?
A. An AU is the distance from the black hole at the center of the galaxy to the closest planet, and solar mass represents a measurement equal to the mass of a black hole's quasar.
B. An AU is the smallest unit of measurement in quantum mechanics, and a solar mass is the largest unit of measurement in astronomy.
C. An AU is the distance from the event horizon to the singularity of a black hole, and solar mass is the distance between the two closest black holes in a galaxy.
D. An AU is the distance from the earth to the sun, and solar mass represents a measurement equal to the mass of our sun.

Answers

AU is the distance from the earth to the sun, and solar mass represents a measurement equal to the mass of our sun.

The units applied in astronomy is quite different from the units applied in daily life. The unit called astronomical units (AU) describes the distance from the earth to the sun. The unit solar mass represents the mass of the sun and is taken to be equal to 1.989 x 10^30 kilograms.

Therefore, the difference between the AU and solar mass is that; AU is the distance from the earth to the sun, and solar mass represents a measurement equal to the mass of our sun.

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Can anyone ask me how many protons, neutrons, and electrons I need and just explain where to put them.​

Can anyone ask me how many protons, neutrons, and electrons I need and just explain where to put them.

Answers

Answer:

on the first shell (ring) there will be 2 electrons

and on the 2nd shell there will be only one electron

while in the nucleus (the middle of the diagram) there will be 4 neutrons and 3 protons

Explanation:

 you can see the picture attached

Can anyone ask me how many protons, neutrons, and electrons I need and just explain where to put them.

A paperclip with the density of a neutron star would weigh (on the Earth)

Answers

A paperclip with the density of a neutron star would weigh approximately 0.0098 Newtons on Earth.

The density of a neutron star is incredibly high, estimated to be around \(10^{17\) to \(10^{18\) kilograms per cubic meter. Comparatively, the density of a typical paperclip made of metal is much lower, ranging from 6,000 to 9,000 kilograms per cubic meter.

To calculate the weight of a paperclip with the density of a neutron star on Earth, we need to consider the mass and gravitational acceleration. The gravitational acceleration on Earth is approximately 9.8 meters per second squared.

Let's assume the paperclip has a mass of 1 gram (0.001 kilograms) for simplicity. The weight can be calculated using the formula:

Weight = Mass x Gravitational acceleration

Weight = 0.001 kg x 9.8 m/s²

Weight = 0.0098 Newtons

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(b) What is the probability that the electron can be detected in the middle one third of well, region (b)

Answers

In order to determine the probability that an electron can be detected in the middle one-third of a well region, we need to take into account the wave function and the boundary conditions.The wave function represents the probability density of finding the electron in a particular location within the well. The boundary conditions are determined by the geometry of the well, which can be rectangular, triangular, or other shapes.

The Schrodinger equation is used to calculate the wave function and determine the probability density of finding the electron in a particular location. The wave function is a complex function that describes the position and momentum of the electron. It is also used to calculate the energy of the electron in the well.The probability of finding the electron in the middle one-third of the well can be determined by integrating the probability density over the middle one-third of the well region. This will give us the probability of finding the electron in that region. The integral can be evaluated using numerical methods or analytical methods, depending on the complexity of the wave function and the boundary conditions.In general, the probability of finding the electron in the middle one-third of the well will depend on the shape of the well, the energy of the electron, and the boundary conditions. For example, if the well is rectangular and the electron is in the ground state, then the probability of finding the electron in the middle one-third of the well will be high. However, if the well is triangular and the electron is in an excited state, then the probability of finding the electron in the middle one-third of the well will be lower.

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With what speed must a ball be thrown down for it to bounce 10m higher than its original level ? Neglect any loss of energy in striking the ground

Answers

The ball must be thrown down with a velocity of 14 meters per second in order to bounce 10 meters higher than its original level, neglecting any energy losses in striking the ground.

To determine the speed at which a ball must be thrown down to bounce 10 meters higher than its original level, we can use the principle of conservation of energy. Neglecting energy losses due to air resistance and assuming an idealized situation, we can equate the potential energy gained during the bounce to the kinetic energy of the ball before it hits the ground.

The potential energy gained by the ball during the bounce is equal to the gravitational potential energy at the new height, which can be calculated as mgh.

where

m = mass of the ball,

g = acceleration due to gravity (approximately 9.8 m/s²)

h = height gained (10 meters in this case).

The kinetic energy of the ball just before it hits the ground is given by (1/2)mv²,

where

v = velocity of the ball.

Equating these two energies, we have:

mgh = (1/2)mv²

Canceling out the mass (m) from both sides of the equation, we get:

gh = (1/2)v²

Simplifying further, we have:

v = √(2gh)

Substituting the values of g (9.8 m/s²) and h (10 meters), we can calculate the velocity (v):

v = √(2 * 9.8 * 10) ≈ √(196) ≈ 14 m/s

Therefore, the ball must be thrown down with a velocity of approximately 14 meters per second in order to bounce 10 meters higher than its original level, neglecting any energy losses in striking the ground.

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The output voltage of a 100.W ideal transformer is 12.0 V and the input current is 20.0 A.a) What is the input voltage?b) What is the output current?c) What kind of transformer is it? (step up or step down)

Answers

ANSWER:

a) 5 V

b) 8.33 A

c) step-up transformer

STEP-BY-STEP EXPLANATION:

a)

To calculate the input voltage it would be:

\(\begin{gathered} V_{\text{ in}}=\frac{P}{I} \\ V_{\text{ in}}=\frac{100}{20}=5\text{ V} \end{gathered}\)

b)

To calculate the output current it would be:

\(\begin{gathered} I_{\text{out}}=\frac{P}{V} \\ I_{\text{out}}=\frac{100}{12}=8.33\text{ A} \end{gathered}\)

c)

We have to:

Step-up transformer increase the output voltage.

Step-down transformer reduces the output voltage.

In this case, the voltage goes from being 5 V to being 12 V, therefore the output voltage increases, which means that it would be a step-up transformer.

a driver accelerates from 4.11 m/s to 5.51 m/s in 6.762 seconds. what is his acceleration in m/s2?

Answers

A driver accelerates from 4.11 m/s to 5.51 m/s in 6.762 seconds. The acceleration of the driver is 0.207 m/s².

In mechanics, acceleration refers to the rate at which an object's velocity with respect to time varies. These are accelerations and vector quantities. The direction of an object's acceleration is determined by the direction of the net force acting on it. When something moves faster or slower, it is considered to be accelerating.

The acceleration of the driver can be calculated using the formula:

a = (vf - vi) / t

Where:
a = acceleration
vf = final velocity
vi = initial velocity
t = time

Plugging in the given values:
a = (5.51 m/s - 4.11 m/s) / 6.762 s
a = 1.4 m/s / 6.762 s
a = 0.207 m/s²

Therefore, the acceleration of the driver is 0.207 m/s².

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a spring-mass system has a spring constant of 3 n/m. a mass of 2 kg is attached to the spring, and the motion takes place in a viscous fluid that offers a resistance numerically equal to one times the magnitude of the instantaneous velocity. if the system is driven by an external force of 3 cos(3t) n, determine the steady state response.

Answers

The steady-state response of the spring-mass system driven by an external force of 3 cos(3t) N does not exist in this case.

Start by finding the equation of motion for the system. Since there is a viscous fluid offering resistance numerically equal to the magnitude of the instantaneous velocity, we can use the equation of motion for a damped harmonic oscillator:

\(m * d²x/dt² + b * dx/dt + k * x = F(t)\)
Where m is the mass (2 kg), b is the damping coefficient (1), k is the spring constant (3 N/m), x is the displacement, and F(t) is the external force.

Plug in the values into the equation of motion:

\(2 * d²x/dt² + dx/dt + 3 * x = 3 * cos(3t)\)

To find the steady-state response, we assume that the solution can be represented as x(t) = X * cos(ωt + φ), where X is the amplitude, ω is the angular frequency, and φ is the phase shift.

Differentiate the assumed solution twice with respect to time to find the second derivative:

\(d²x/dt² = -ω²X * cos(ωt + φ)\)

Substitute the assumed solution and its derivatives into the equation of motion:

\(-4ω²X * cos(ωt + φ) + X * cos(ωt + φ) + 3X * cos(ωt + φ) = 3 * cos(3t)\)

Group the cosine terms and equate them to find the amplitude of the steady-state response:

\((-4ω² + 1 + 3)X * cos(ωt + φ) = 3 * cos(3t)-4ω² + 4 = 3-4ω² = -1ω² = 1/4ω = ±1/2\)

Since the system is driven by a force with angular frequency 3, we take ω = 3. Substituting this value into the equation gives:

-4(3)² + 4 = 3

-36 + 4 = 3

-32 = 3

This equation is not possible, indicating that the steady-state response does not exist for this system under the given conditions.

The steady-state response of the spring-mass system driven by an external force of 3 cos(3t) N does not exist in this case.

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A racing car can complete an 800 m long lap in 14 s. What is the speed of the
car?

Answers

Answer:

57.1 m/s

Explanation:

Speed = Distance/Time

Speed = 800/14

Speed = 57.1 m/s (3sf)

An AC circuit has a capacitive reactance of 30 ohms in addition to an inductive reactance of 40 ohms connected in series. What is the total reactance of the circuit

Answers

The total reactance of the circuit is 10 ohms. In an AC circuit, the total reactance is the algebraic sum of the capacitive reactance (Xc) and the inductive reactance (Xl).

Given that the capacitive reactance is 30 ohms and the inductive reactance is 40 ohms, we can calculate the total reactance as follows:

Total reactance = Xc + Xl = 30 ohms + (-40 ohms) = -10 ohms.

Since the capacitive and inductive reactances have opposite signs, we need to consider their algebraic sum. Therefore, the total reactance of the circuit is 10 ohms. This indicates that the circuit has a net inductive reactance.

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force (f) = ?
mass (m) = 75kg
gravity (g) = 9.8m/s^2

Answers

Answer:

735 N

Explanation:

A 1. 0\, \text {kg}1. 0kg1, point, 0, tart text, k, g, end text cart moving right at 5. 0\,\dfrac{\text m}{\text }5. 0

m

5, point, 0, tart fraction, tart text, m, end text, divided by, tart text, , end text, end fraction on a frictionle track collide with a econd cart moving right at 2. 0 \,\dfrac{\text m}{\text }2. 0

m

2, point, 0, tart fraction, tart text, m, end text, divided by, tart text, , end text, end fraction. The 1. 0\, \text {kg}1. 0kg1, point, 0, tart text, k, g, end text cart ha a final peed of 0. 50\,\dfrac{\text m}{\text }0. 50

m

0, point, 50, tart fraction, tart text, m, end text, divided by, tart text, , end text, end fraction to the right, and the econd cart ha a final peed of 2. 3\,\dfrac{\text m}{\text }2. 3

m

2, point, 3, tart fraction, tart text, m, end text, divided by, tart text, , end text, end fraction to the right

Answers

The total initial momentum of 7.0 kgm/s is 2.8 kgm/s,

This scenario describes an inelastic collision between two carts. In an inelastic collision, the total kinetic energy of the system is not conserved and some of it is converted into other forms of energy, such as heat or sound.

Using the principle of conservation of momentum, we can calculate the final velocities of the two carts after the collision. The initial momentum of the first cart is 1.0 kg * 5.0 m/s = 5.0 kgm/s. The initial momentum of the second cart is 1.0 kg * 2.0 m/s = 2.0 kgm/s. The total initial momentum of the system is 5.0 kgm/s + 2.0 kgm/s = 7.0 kg*m/s.

After the collision, the final momentum of the two carts is equal to the total initial momentum, since no external forces are acting on the system. Therefore, the final momentum of the first cart + the final momentum of the second cart = 7.0 kg*m/s.

We can use the final velocities given in the problem to solve for the final momentum of each cart.

The final momentum of the first cart is 1.0 kg * 0.50 m/s = 0.50 kgm/s

The final momentum of the second cart is 1.0 kg * 2.3 m/s = 2.3 kgm/s

And add them: 0.50 kgm/s + 2.3 kgm/s = 2.8 kgm/s, which is equal to the total initial momentum of 7.0 kgm/s.

We can also observe that the final velocity of the first cart is less than its initial velocity, while the final velocity of the second cart is greater than its initial velocity. This is expected in an inelastic collision as some of the kinetic energy of the system is converted into other forms of energy, causing the final velocities of the carts to be different from their initial velocities.

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(c) Write a chemical equation for the reaction between sodium and fluorine. A rod of length L and total charge Q is a distance D from a point charge q which lies along the perpendicular bisector of the rod. Find the force of the rod on the point charge. ou are the lucky winner of your state's lottery of $6 million after taxes. You invest your winnings in a five-year certificate of deposit (CD) at a local financial institution. The CD promises to pay 8 percent per year compounded annually. This institution also lets you reinvest the interest at that rate for the duration of the CD. How much will you have at the end of five years if your money remains invested at 7 percent for five years with no withdrawals? 19. what is creons attitude toward the chorus during the scene in which he delivers his edict? 14 Find the percent increase or decrease for each of the following values (indicate whether each is an increase or a decrease). a. 4x to x Decrease b. 0.25m to 0.5m 1 5 c. --2p to d. y to 0.68y 8p I Mother and Son2.1 This poem contains words that are not grammatically correct or are informal. Explain why this type of language is acceptable in certain poems and stories but not in formal language. How does the poem benefit from the use of such language? (10) 2.2 The above poem suggests that the speaker has not had an easy life. Explain how the writers choice of words influences the mood and feeling of the poem overall. Give three specific examples from the poem and elaborate on the feelings they generate. Nonrenwable resources are _____________1.replaces as quickly as they are user 2.are worse than renewable resources 3.not used as much as they used to be 4.consumed faster than they are replaced What is Pattersons attitude toward the black leather jacket? How does he use it to comment on popular culture? (How the Motorcycle Jacket Lost Its Cool and Found it Again) f(x)=4x^2-x-3, find x when f(x)= -3 x(x+7)=4x+10then needs to get the normal form of the equationx= ?, x=? what is a themeA.The life lesson the author teaches through the storyB.The decision the character makes to succeed in lifeC.The person who works against the protagonistD.The problems that occur throughout a piece of fiction TRY THIS Qs = 0.15 + P where Qs is the quantity of wheat produced per year (in billions of bushels) when P is the average price of wheat (in dollars per bushel). (a) What is the quantity of wheat supplied per year when the average price of wheat is $2 per bushel? When the price is $3? When the price is $4? (b) Sketch the supply curve for wheat. Does it obey the law of supply? . Consider the standard parametrization of the LDS model, with a new latent transition that depends on an observed sequence of inputs y1:T in the form:zt+1= Azt + Byt + wtwhere matrix B is an additional model parameter and yt is the observed input vector at time t. How dothe Kalman filtering and smoothing updates change for this variation? Use linear approximation, i.e. the tangent line, to approximate (25.4) as follows: Let f(x)=x The equation of the tangent line to f(x) at x=25 can be written in the form y=mx+b where m is:__________ and where b is _________Using this, we find our approximation for 25.4 is ___________________NOTE: For this part, give your answer to at least 9 significant figures or use fractions to give the exact answer.can please write out how you did it as well thank you in as much detail HELP PLEASE!!!6. A survey contains occupation and work hour information for 2,000 respondents. To be more specific, the categorical variable, occupation, can take four values:=1 for technical; = 2 for manager; = 3 A) Which option describes a main goal of the Ku Klux Klan after World War I?(1 point) to force African Americans to move north to prevent African Americans from gaining any power to let African Americans develop their own culture to end Reconstruction Suppose the interest rate is 8.8% APR with monthly compounding. What is the present value of an annuity that pays $85 every six months for five years? You cannot use a compound condition with an UPDATE command. T/F PLEASE HELP ME ASAP!!!! in a situation where it is impossible to include all possible input combinations for the module, what are the considerations when it comes to the test bench design to thoroughly and effectively test the verilog module?