Consider three different means of supporting a weight W = 500 lb. say the material, steel, has an allowable normal stress of 12,000 psi (in tension or compression). (Don't) worry about the shear stress). In all cases, the structure is 0.25 in thick (into the page). For each case, determine the minimum allowable in-plane dimension of the bar or links, and from it determine the minimum possible volume of the structure. Also for each case, describe: the extent of the region(s) over which the allowable stress is reached, what is the lowest magnitude of the stress, and where the stress has this lowest magnitude. Notice that the minimum volume for support cases (i) and (ii) is much greater than for case (iii). Explain in a sentence or two how this is related to what you found for the extents of the regions where the allowable stress is reached and the stress is at its lowest magnitude.
Answers
The topic is analyzing different means of supporting a weight with a steel structure and determining minimum allowable dimensions and volumes while considering the allowable stress, as well as describing the extent of the region(s) where the allowable stress is reached and the lowest magnitude of stress for each case.
How to find the extent of the region(s) where the allowable stress is reached and the lowest magnitude of stress for each case?Case (i): A solid steel bar with a circular cross-section is used to support the weight W. To determine the minimum allowable in-plane dimension of the bar, we need to calculate the diameter of the bar. Using the formula for the normal stress in a bar subjected to tension or compression, we have:
σ = F / A
where F is the applied force (500 lb), A is the cross-sectional area of the bar (πd^2/4), and σ is the normal stress. Rearranging this equation to solve for the diameter, we get:
d = √(4F / πσ)
Substituting the given values of F and σ, we get:
d = √(4 x 500 lb / (π x 12,000 psi)) = 0.52 in
Therefore, the minimum allowable in-plane dimension of the bar is 0.52 in. The minimum possible volume of the structure is given by the volume of the cylinder with height equal to the thickness of the bar and diameter equal to the minimum allowable in-plane dimension, which is:
V = π x (0.25 in) x (0.52 in)^2 = 0.042 in^3
The extent of the region where the allowable stress is reached is over the entire length of the bar, and the lowest magnitude of stress is zero at the ends of the bar, and reaches a maximum of 12,000 psi at the center.
Case (ii): A truss structure made of steel links is used to support the weight W. To determine the minimum allowable in-plane dimension of the links, we can use the same formula as in case (i), but with the cross-sectional area of the links (b x t) instead of the cross-sectional area of a circular bar.
We are not given any information about the shape of the links, so we can assume that they are rectangular with the thickness equal to the thickness of the bar (0.25 in). Substituting the given values of F, σ, and t, we get:
b = 4F / (σt) = 4 x 500 lb / (12,000 psi x 0.25 in) = 5.3 in
Therefore, the minimum allowable in-plane dimension of each link is 0.25 in x 5.3 in. The minimum possible volume of the structure is given by the sum of the volumes of all the links in the truss structure.
The extent of the region where the allowable stress is reached is over the entire length of each link, and the lowest magnitude of stress is zero at the ends of each link, and reaches a maximum of 12,000 psi at the center.
Case (iii): A hollow steel pipe is used to support the weight W. To determine the minimum allowable in-plane dimension of the pipe, we can use the same formula as in case (i), but with the cross-sectional area of a hollow pipe. The minimum allowable in-plane dimension of the pipe is the inner diameter, which can be calculated as follows:
d = √(4F / (πσ)) + t
where t is the thickness of the pipe (0.25 in). Substituting the given values of F and σ
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Related Questions
a racer accelerates from rest at constant acceleration for 2 seconds and travels 25 meters. if they then accelerate at the same constant acceleration for an additional 8 seconds, what is their total distance traveled in meters over the entire 10 seconds?
Answers
Distance traveled in a given amount of time is equal to the average speed. utilizing the formula s=ut+21at2s=510+212102s=50+100=150m.
Why do we measure distance, exactly?By understanding how far an object is from us, we may calculate its actual size. It is possible to calculate the space that an object takes up in the sky. The actual size of an object can then be determined by taking into account its distance. The further away something is, the smaller it appears.
What is a meter example?A common metric length from around three feet, 3 inches is called a metre. This proves that in the metric system, a meter is a measuring unit. Objects up to one meter in length include yardsticks, baseball bats, and guitars. Distances in sporting events like run and swimming are also measured in meters.
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5. Emanuel Zacchini, the famous human cannonball of the Ringling Bros. and Barnum and Bailey Circus,
was fired out of a cannon with a speed of 24.0 m/s at an angle of 40.0° to the horizontal. If he landed in
a net 56.6 m away at the same height from which he was fired, how long was Zacchini in the air?
Answers
Explanation:
सिद्ध कीजिए किसी भी बराबर भुजाओं वाले त्रिभुज में उनके सामने के कोण बराबर होते है
El motor de una licuadora gira a 3600 rpm, disminuye su velocidad angular hasta 2000 rpm realizando 120 vueltas. Calcular: a) La aceleración angular b) El tiempo transcurrido
Answers
Answer:
a) α = -65,2 rad/s².
b) t = 2,57 s.
Explanation:
a) La aceleración angular se puede calcular usando la siguiente ecuación:
\( \omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \theta \)
En donde:
\(\omega_{f}\): es la velocidad angular final = 2000 rpm = 209,4 rad/s
\(\omega_{0}\): es la velocidad angular inicial = 3600 rpm = 377,0 rad/s
α: es la aceleración angular=?
θ: es el desplazamiento o número de vueltas = 120 rev = 754,0 rad
Las conversiones de unidades se hicieron sabiendo que 1 revolución = 2π radianes y que 1 minuto = 60 segundos.
Resolviendo la ecuación (1) para α, tenemos:
\(\alpha = \frac{\omega_{f}^{2} - \omega_{0}^{2}}{2\theta} = \frac{(209,4 rad/s)^{2} - (377,0 rad/s)^{2}}{2*754,0 rad} = -65,2 rad/s^{2}\)
Entonces, la aceleración angular es -65,2 rad/s². El signo negativo se debe a que el motor está desacelerando.
b) El tiempo transcurrido se puede encontrar como sigue:
\( \omega_{f} = \omega_{0} + \alpha t \)
Resolviendo para t, tenemos:
\(t = \frac{\omega_{f} - \omega_{0}}{\alpha} = \frac{209,4 rad/s - 377,0 rad/s}{-65,3 rad/s^{2}} = 2,57 s\)
Por lo tanto, el tiempo transcurrido fue 2,57 s.
Espero que te sea de utilidad!
A bicyclist pedaling up a hill is this a form of kinetic energy or potential energy?
Answers
Answer:
Kinetic
Explanation:
Its a moving action
When a bicyclist is pedaling up a hill, it is a form of potential energy. The correct option is option potential energy.
An object's position or configuration in relation to other things might provide it potential energy. The potential energy in this situation is gravitational potential energy.
Because they are being lifted against gravity as they ascend the hill, the cyclist gains gravitational potential energy. The potential energy of the cyclist increases as they ascend.
The potential energy will be transformed into kinetic energy once the cyclist begins pedaling or moving downward.
As a result of their increased height above the ground, cyclists are building up potential energy as they bike up a hill. They gain speed as they cycle downhill, transforming that potential energy into kinetic energy.
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A force, F, of 25 N is acting in the direction of a= [6, 1). a) Find a unit vector in the direction of a. b) Find the Cartesian vector representing the force, 7, using your answer from part a). c) The force f is exerted on an object moving from point (4,0) to point (15, 0), with distance in metres. Determine the mechanical work done.
Answers
a) The unit vector in the direction of a is (0.993, 0.117).
b) The Cartesian vector representing the force is (24.825, 2.925).
c) The mechanical work done is 275 Joules.
What is the unit vector in the direction of a? How can the force be represented in Cartesian vector form? What is the value of the mechanical work done?The unit vector in the direction of vector a can be found by dividing vector a by its magnitude. In this case, vector a = [6, 1], so the magnitude of a is √(6² + 1²) = √37. Dividing vector a by its magnitude yields (6/√37, 1/√37), which simplifies to approximately (0.993, 0.117).
To find the Cartesian vector representation of the force, we multiply the unit vector from part a) by the magnitude of the force, F = 25 N. The result is (0.993 * 25, 0.117 * 25), which simplifies to (24.825, 2.925).
To determine the mechanical work done, we use the formula W = F * d * cos(θ), where W is the work done, F is the force, d is the displacement, and θ is the angle between the force and displacement vectors.
In this case, the force is F = 25 N, and the displacement is the difference between the x-coordinates of the two points, which is 15 - 4 = 11 meters. Since the force and displacement are in the same direction (θ = 0°), cos(θ) = 1.
Plugging in the values, we get W = 25 * 11 * 1 = 275 Joules.
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What is the formula for net torque?
Answers
The formula for net torque is T=flsinФ which is the cross product of perpendicular force multiplied by distance.
When displaced from equilibrium, the system experiences a net force or torque in a direction opposite to the direction of the displacement. Equilibrium is independent of displacement from its original position
Energy is conserved so same amount of energy with or without machine Angular Momentum conserved if net external torque is zero Linear Momentum conserved if net external force is zero. Kinetic Energy conserved if elastic collision.
The first condition necessary to achieve equilibrium is the one already mentioned: the net external force on the system must be zero. Expressed as an equation, this is simply net F = 0 but Note that if net F is zero, then the net external force in any direction is zero. For example, the net external forces along the typical x- and y-axes are zero.
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if his eyes have a far point of 2.0 m , what is the greatest distance he can stand from the mirror and still see his image clearly? express your answer using two significant figures.
Answers
The greatest distance the person can stand from the mirror and still see their image clearly is 2.0 meters.
The far point of a person's eyes refers to the maximum distance at which they can see objects clearly without the aid of corrective lenses. If the far point is given as 2.0 m, it means that the person can see objects clearly up to a distance of 2.0 m.
To determine the greatest distance the person can stand from the mirror and still see their image clearly, we need to consider the concept of the virtual image formed by a mirror. When we look into a mirror, our eyes perceive a virtual image as if it were formed behind the mirror.
In this case, the person's eyes can focus clearly up to a distance of 2.0 m. To see their image clearly in the mirror, the person needs the virtual image formed by the mirror to be within this range.
Since the virtual image formed by a mirror is the same distance behind the mirror as the object is in front of it, the person needs to stand at a distance from the mirror equal to the maximum distance they can focus clearly.
Therefore, the greatest distance the person can stand from the mirror and still see their image clearly is 2.0 meters.
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What is the density of a sample of cork with a mass of 2.0 g and a volume of 10 cm³?
A.0.2 g/cm³
B.5 g/cm³
C.8 g/cm³
D.20 g/cm³
Answers
Answer:
A. 0.2 g/cm³
Explanation:
d=m/v
2.0g / 10cm³
0.2g/cm³
Shannon placed an uncooked egg on her desk.she gave the egg a gentle turn to start it spinning. she then stopped the egg from spinning for a moment and quickly released it.when she released the egg,the egg began to spin again.
what is the conclution?
Answers
Which energy from the choices given is the strongest
Visible Light
Microwaves
UV Light
X-Rays
Answers
Answer:
X-Rays
Explanation:
Abi is driving west along Steeles Avenue and slams on the breaks, causing an acceleration of 6.5 m/s² [East]. The car skids for 2.23 seconds, slowing to a speed of 3.5 m/s. What was the velocity of the car before the brakes were pressed?
Answers
The velocity of the car before the brakes were pressed was approximately 17.995 m/s. This velocity is obtained by subtracting the product of the acceleration and time from the final velocity using the kinematic equation.
To determine the velocity of the car before the brakes were pressed, we can use the kinematic equation that relates initial velocity (Vi), final velocity (Vf), acceleration (a), and time (t):
Vf = Vi + at
In this case, the final velocity (Vf) is given as 3.5 m/s, the acceleration (a) is -6.5 m/s² (negative sign indicates deceleration), and the time (t) is 2.23 seconds. We need to find the initial velocity (Vi).
Rearranging the equation, we have:
Vi = Vf - at
Substituting the given values, we get:
Vi = 3.5 m/s - (-6.5 m/s² * 2.23 s)
= 3.5 m/s + 14.495 m/s
= 17.995 m/s
Therefore, the velocity of the car before the brakes were pressed was approximately 17.995 m/s.
It's important to note that the direction of the velocity would be west since the car was initially driving west along Steeles Avenue and experienced acceleration in the east direction. However, since the problem does not explicitly mention the direction, we focus on the magnitude of the velocity.
The negative sign of the acceleration indicates deceleration, and the direction of the velocity is west based on the initial direction of the car.
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Each external force acts on the system for 10 seconds. Rank the change in momentum of each of the cart-cart systems from largest to smallest. (The label of “m” or “2 m” desginates the relative mass of each cart.)
It is possible to have some of the categories below BLANK since you may have items that are EQUAL to each other.
Put the largest as far up as you can, and the smallest as far down as you can
Answers
Answer:
thanks me later
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A car drives 10km with a speed of 72 km/hr and then runs out of gas. Then you walk 2km for the next 30 min
until you find a gas station.
Answers
Given :
A car drives 10 km with a speed of 72 km/hr and then runs out of gas.
Then you walk 2 km for the next 30 min until you find a gas station .
To Find :
The average speed of whole journey .
Solution :
Average speed is given by :
\(v_{avg}=\dfrac{\text{Total distance covered}}{\text{Total time taken}}\\\\v_{avg}=\dfrac{10+2}{\dfrac{10}{72}+\dfrac{1}{2}}\\\\\\v_{avg}=18.78\ km/hr\)
Hence , this is the required solution .
An auto dealer has 4 different cars and 6 different trucks. how many ways are there to select two vehicles?
Answers
There are C different ways to choose two different automobiles (12, 2).
In mathematics, a choice is made from a set of various components where the order of the choices is unimportant (unlike permutations).
For instance, there are three conceivable combinations of two given fruits, such as an apple, an orange, and a pear: an apple and a pear; an orange and an apple; or an orange and a pear. Formally speaking, a set S's k unique components make up a subset known as a k-combination. In other words, two combinations are same only if all of their members are the same.
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a super train is moving along a track at a speed close to the speed of light. you are watching the train from the ground. you observe lightning to strike in two places along the track, a mile apart, at precisely the same time. what would someone on the train say? view available hint(s)for part a a super train is moving along a track at a speed close to the speed of light. you are watching the train from the ground. you observe lightning to strike in two places along the track, a mile apart, at precisely the same time. what would someone on the train say? the two bolts of lightning struck at different times, and they struck at places that are more than a mile apart. the two bolts of lightning struck at different times, and they struck at places that are less than a mile apart. the two bolts of lightning struck at the same time, and they struck at places that are less than a mile apart. the two bolts of lightning struck at different times, and they struck at places that are precisely a mile apar
Answers
Someone on the train would also notice that both lightning strikes occurred at the exact same moment and would estimate that the distance between the two strikes was less than a mile.
This results from the special relativity phenomenon of time dilation and length contraction. Time appears to slow down for an object as it approaches the speed of light when compared to an observer at rest. In addition, from the viewpoint of an observer at rest, the length of objects moving in the same direction appears to decrease.
Therefore, compared to the observer on the ground, someone riding in a moving train would think that the two lightning bolts struck at the same time and closer together.
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Why is CH4 not a suitable proxy for the surface pressure?
Answers
Explanation:
Methane (CH4) is 30 times stronger than carbon dioxide as an absorber of infrared radiation.
Answer:
The main reasons why CH4 has a higher vapor pressure at a given temperature when compared to CH3Cl is that CH4.
And Is 30 Times Stronger than Carbon dioxide...
Explanation:
Hope It Helps!!!
Creating green spaces would be classified as a _____ human activity for the environment.
Negative or positive?
Answers
Explanation:
she human activity for
A Toddler got up from a nap and ran for 7.0 seconds and got tired and stopped on the spot. from beginning to end she was accelerating at 0.24m/s^2. What has her change in velocity in metres per second
Answers
The toddler's change in velocity in metres per second is 1.68 m/s
To answer the question, we need to know what acceleration is
What is aceleration?Acceleration is the change in velocity of an object with time. It is given by
a = Δv/Δt where
Δv = change in velocity and Δt = change in time The toddler's change in velocityMaking Δv subject of the formula, we have
Δv = aΔt
Since the toddler's accleration is 0.24 m/s² and got up from a nap and ran for 7.0 seconds,
a = 0.24 m/s² and Δt = 7.0 sSubstituting the values of the variables into the equation, we have
Δv = aΔt
Δv = 0.24 m/s² × 7.0 s
Δv = 1.68 m/s
So, the toddler's change in velocity in metres per second is 1.68 m/s
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in about 1915, henry sincosky of philadelphia suspended himself from a rafter by gripping the rafter with the thumb of each hand on one side and the fingers on the opposite side (fig. 6-21). sincosky’s mass was 79 kg. if the coefficient of static friction between hand and rafter was 0.70, what was the least magnitude of the normal force on the rafter from each thumb or opposite fingers? (after suspending himself, sincosky chinned himself on the rafter and then moved hand-over-hand along the rafter. if you do not think sincosky’s grip was remarkable, try to repeat his stunt
Answers
The least magnitude of the normal force on the rafter from each thumb or opposite fingers is 276.5 Newtons.
As we know, henry is suspended by using his hands.
If he not going upward or downwards. we can conclude that the magnitude of all forces should be cancelling each other.
The force that is stopping the thumbs and the finger is frictional force.
Friction force f is a kind of force that comes into play when their is an actual slipping or the tendency to slip between any two contacted surface.
f = μN
where N is the normal force.
The net friction force should be equal to the total weight if the body,
Frictional force f by the fingers can be distributed equally in four parts,
mg = 4f
mg = 4μN
Mass is 79 Kg. g is 9.8m/s² and the value of μ is 0.7.
79 x 9.8 = 4 x 0.7 x N
N = 276.5 newtons.
So the least normal force on the each thumb and fingers is 276.5 N.
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Two large parallel plates are 2.0 cm apart. the strength of the electric field between them is 50.0 n/c . what is the difference in voltage between the plates?
Answers
The difference in voltage between the two parallel plates is 1.0 Volt.
Voltage, also known as electric potential difference, is a measure of the electric potential energy per unit charge between two points in an electric field.
The difference in voltage between the two parallel plates can be determined using the formula:
ΔV = Ed
where ΔV is the voltage difference, E is the electric field strength, and d is the distance between the plates.
Substituting the given values into the formula, we have:
ΔV = (50.0 N/C) * (2.0 cm)
Before calculating the voltage difference, it's important to ensure that the units are consistent. Since the distance between the plates is given in centimeters (cm), we need to convert it to meters (m) for the equation. 1 cm is equal to 0.01 m, so the distance becomes:
d = 2.0 cm * (0.01 m/cm) = 0.02 m
Substituting this value back into the formula, we have:
ΔV = (50.0 N/C) * (0.02 m)
Calculating this expression, we find:
ΔV = 1.0 V
Therefore, the difference in voltage between the two parallel plates is 1.0 Volt.
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1,400 g
12 kg
Which is greater
Answers
Answer:
12kg is greater because 12kg is 12000g
Answer:
12kg is the answer cause if it wasn't 12 kg then 1,400 g would not be the answer so you would pick 12kg as the answer.
3. Since Aspeon is not expected togrow, Emily believes that the following equations can be used in the valuation analysis: (1) S=[EBIT−kd(D)](1−ks)
(2) V=S+D
(3) P=(V−D0)/n0
(4) n1=n0−D/P
(5) VL=VU+TD
Answers
The equations mentioned by Emily in the valuation analysis for Aspeon are as follows:
1) Equation (1): This equation represents the value of equity (S) and calculates it based on the EBIT (earnings before interest and taxes), the tax shield provided by debt (D), and the required return on debt (kd) and equity (ks). It implies that the value of equity is equal to the adjusted EBIT after deducting the tax shield from debt.
2) Equation (2): This equation calculates the total enterprise value (V) by adding the value of equity (S) and debt (D). It represents the total worth of the company, considering both equity and debt.
3) Equation (3): This equation calculates the price per share (P) by dividing the total enterprise value (V) minus the initial debt (D0) by the number of shares (n0). It represents the price per share based on the valuation of the company.
4) Equation (4): This equation calculates the new number of shares (n1) by subtracting the dividend (D) from the initial number of shares (n0) divided by the price per share (P). It represents the adjusted number of shares after the payment of dividends.
5) Equation (5): This equation calculates the levered value (VL) by adding the unlevered value (VU) with the tax shield value (TD). It represents the value of the company after considering the tax advantages of debt.
These equations provide a framework for valuation analysis, considering factors such as earnings, taxes, debt, and equity. They help assess the value and financial implications of Aspeon's growth prospects.
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Linear distance traveled per unit of time describes what? A.displacement B. velocity C. acceleration D. speed
Answers
The linear distance traveled per unit of time, also known as speed, describes how fast an object is moving without considering its direction.
The linear distance traveled per unit of time is commonly referred to as speed. Speed is a fundamental concept in physics that describes how fast an object is moving without considering its direction. It is a scalar quantity, which means it only has magnitude and no specific direction.
Speed is calculated by dividing the total distance traveled by the time taken to travel that distance. The formula for speed is:
Speed = Distance / Time
For example, if an object travels a distance of 100 meters in 10 seconds, its speed would be:
Speed = 100 meters / 10 seconds = 10 meters per second
Speed is an important concept in various fields, including physics, sports, and everyday life. It helps us understand how quickly objects move and allows us to compare the speeds of different objects.
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A metal sphere has a charge of 6.0 µC. What is the net charge after 7.0 x1013 electrons have been placed on it?
Answers
When electrons are added to a sphere, they will cause it to become negatively charged. As a result, the net charge will increase. A negative charge would be the charge on the sphere.
Coulomb's law states that the charge Q is equal to the product of the charge Q_0 on the metal sphere plus the product of the charge\(n_e\)on the electrons multiplied by the elementary charge, which is e.
Symbolically:\(Q=Q_0+ne*e\)
where e is the elementary charge.
It's equal to\(1.602×10^−19 C.µC\) (microcoulombs) must be converted to coulombs in the question.
Because one microcoulomb is one millionth of a coulomb,\(6.0 µC = 6.0 x 10^-6 C (coulombs).\)
Substitute the given values in the above Coulomb's law equation:
\(Q = (6.0 x 10^-6) + (7.0 x 10^13) x (1.602 x 10^-19)Q = 1.122 C\)
The net charge on the sphere is 1.122 C.
Therefore, the net charge of the sphere after \(7.0 x 10^13\)
electrons have been placed on it is 1.122 C.
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State which type of variable is plotted on the x-axis
and which type is plotted on the y-axis.
Answers
Answer:
Often the independent variable is plotted on the x-axis - and example might be time (an experiment where time is measured by a watch or an independent mechanical device)
The dependent variable is often plotted on the y-axis - and example here might be the velocity or the acceleration,
It may be the responsibility of the experimenter to determine the value of the dependent variable by some type of measurement
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Jose’s doctor recommends that he add more cardio to his exercise routine. Which exercise would be the BEST choice?
A.
ballet
B.
jogging
C.
bowling
D.
volleyball
PLEASE NO LINKS OR I WILL REPORT YOU
Answers
Explanation:
I learned in PE
Answer:
jogging
Explanation:
Jogging is often defined as running at a pace less than 6 miles per hour (mph), and it has some significant benefits for people who want to improve their health without overdoing it.
Which of the following is NOT an application of laser light?Select one:a.cutting materialb.precision surgeryc.satellite communication d.calibration of telescopes
Answers
Given:
The uses of LASER light
To find:
Which is not an application of LASER light
Explanation:
When cutting stainless steel or aluminium, LASER beams are used.
To remove warts, moles, sunspots, and tattoos in human bodies LASER lights are used.
LASER is used in communication also. Laser communication in space is the use of free-space optical communication in outer space.
One of the most important uses for lasers in astronomy is to reduce distortion on images taken with ground-based telescopes. So directly we cannot say that LASER is used for the calibration of telescopes.
Hence, calibration of telescopes is not an application of LASER light.
Plz i wanna those answers
Answers
H2O
Hydration
Ice
Liquid
Aqua
Rain
River
Sea
Lake
Pond
What causes the spinning tube of air created by winds moving in opposite directions to tip upwards and become vertical?
A
The updraft of wind in a supercell
B
Dust and debris picked up by a mesocyclone
C
The increasing speed of the tube’s rotation
D
A lack of gravity during stormy weather
Answers
The spinning tube of air created by winds moving in opposite directions to tip upwards and become vertical because of the updraft of wind in a supercell. Hence, option (A) is correct.
What is supercell?As a deep, continuously revolving updraft known as a mesocyclone, a supercell is a type of thunderstorm. This causes these storms to occasionally be called spinning thunderstorms.
Supercells, which are the least frequent and have the potential to be the most severe of the four types of thunderstorms (supercell, squall line, multi-cell, and single-cell), are the least common overall.
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What types of media can S-waves travel through
Answers
Answer:
The second type of body wave is the S wave or secondary wave, which is the second wave you feel in an earthquake. An S wave is slower than a P wave and can only move through solid rock, not through any liquid medium.