Consider the situation illustrated in the figure below. If θ = 35° and the masses of blocks B and A are, respectively, Mb and Ma= 0.4Mb, (a) what should be the minimum value of the static coefficient of friction μs between the table and block B so that the system remains in balance? (b) In this case, what will be the tension in the rope segment connected to (node) and the vertical wall?

1. The kinetic energy would be the same for the both balls.

2) As the ball gains potential energy, its speed will decrease.

Kinetic energy is the energy possessed by an object due to its motion. The amount of kinetic energy an object has is dependent on its mass and velocity. An object with a greater mass and a higher velocity will have a higher kinetic energy than an object with a smaller mass and lower velocity.

The increase in the potential energy as the ball reaches the maximum height would imply that the ball would become stationary for some time and the speed will decrease.

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Doppler radars work by using radio waves that bounce off objects and thus the object can be tracked.

Doppler radars work by emitting a beam of energy from an antenna known as radio waves. The energy they release when they collide with airborne objects scatters in all directions, with some of it returning directly to the radar.

The quantity of energy returned to the radar increases with object size. We can now perceive raindrops in the atmosphere because of this.

The amount of time it takes for the energy beam to be delivered and returned to the radar also gives us the object's distance.

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The amount of damping force that allow shortest possible time is called​ critical damping of the system.

Critical damping is the threshold between overdamping and underdamping  at which the oscillator returns to the position of equilibrium quickly as possible.

Critical damping is frequently desired because such a system returns to and maintains equilibrium quickly. Furthermore, a constant force applied to a critically damped system moves the system to a new equilibrium position as quickly as possible without overshooting or oscillating around the new position.

Critical damping thus provides the rapid approach to zero amplitude for a damped oscillator.

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The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.

The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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Answer: 4.97 years

Explanation: I got the answers right

By the use of the Kepler's laws, the period of the orbit is 5.22 years. Option D

We know that when we are dealing with the orbits that our mind would have to be turned to the Kepler's law. In the Keplers law, we see the relationship that cold be used in the attempt to connect the period of the orbit to the radius of the semi major axis of an orbiting body.

By the application of the Keplers third law;

T^2 = r^3

The statement of the law is that the square of the period of the objects orbit is equal to the cube of the length of the semi major axis.

We then know that;

T = period

r = distance

Hence;

T = r^3/2

T = (3.01 )^3/2

T = 5.22 years

The period of the object is seen to be 5.22 years from the calculation above.

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Answer: Negative

Explanation: The acceleration along the y-axis for any projectile motion will always be -9.8m/s^2.

The coil will align itself vertically, with one end (end b) pointing towards the Earth's surface and the other end (end a) pointing upwards, due to the interaction between the counterclockwise current flow and Earth's downward-pointing magnetic field lines in the northern hemisphere.

When a solenoid with a current-carrying coil is suspended by a thread in the horizontal plane, and the electrons move clockwise when viewed from end a toward end b, the coil will align itself in Earth's magnetic field based on the interaction between the current and the magnetic field.

Earth has a magnetic field that extends from its magnetic north pole to its magnetic south pole. The magnetic field lines form loops around the Earth. In the northern hemisphere, the magnetic field lines point downward into the Earth, while in the southern hemisphere, they point upward.

Based on the right-hand rule, which states that if you point your thumb in the direction of the current, the fingers will curl in the direction of the magnetic field, we can determine how the coil will align itself.

Given that the electrons in the coil move clockwise from end a to end b, the current flows in the opposite direction, counterclockwise, from end b to end a.

Using the right-hand rule, if we align our right hand with our thumb pointing in the counterclockwise direction (opposite to the current flow), the magnetic field lines from Earth would be represented by the direction in which our fingers curl.

Since the magnetic field lines in the northern hemisphere point downward into the Earth, the coil will align itself such that the bottom of the coil (end b) will be attracted towards the Earth's surface, while the top of the coil (end a) will point upwards.

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The kinetic energy of the book after it is slids a distance of 2 meters will be 10 Joules.

The work-energy theorem states that "the work done on an object is the change in its kinetic energy".

Hence;

Kinetic energy = work done

Note that: work-done is expressed as:

Work done = f × d

Where f is force applied and d is distance traveled.

Given that:

Force applied f = 5 newton

Distance d = 2 meters

Work done = ?

Plug these values into the above formula and solve for the workdone.

Work done = f × d

Work done = 5N × 2m

Work done = 10Nm

Work done = 10 Joules

Therefore, the kinetic energy is 10 Joules.

Option B) 10 J is the correct answer.

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Answer: In this scenario, we have two carts colliding with each other. One cart weighs 250 kg and is moving at a speed of 8 m/s, while the other cart weighs 100 kg and is initially at rest.

After the collision, the 250 kg cart continues moving forward, but at a slower speed of 3 m/s. We want to find out the speed at which the 100 kg cart moves after the collision.

To solve this, we use the principle that the total "push" or momentum before the collision should be the same as the total momentum after the collision.

Since the 100 kg cart is initially at rest, its momentum is zero. The momentum of the 250 kg cart before the collision is 250 kg * 8 m/s = 2000 kg·m/s.

After the collision, the momentum of the 250 kg cart becomes 250 kg * 3 m/s = 750 kg·m/s.

To find the momentum of the 100 kg cart after the collision, we subtract the momentum of the 250 kg cart after the collision from the total momentum before the collision: 2000 kg·m/s - 750 kg·m/s = 1250 kg·m/s.

Now, we divide this momentum by the mass of the 100 kg cart to find its velocity: 1250 kg·m/s / 100 kg = 12.5 m/s.

Therefore, the 100 kg cart moves at a velocity of 12.5 m/s after the collision, in the opposite direction of the 250 kg cart's motion.

Answer:

-15 as it inverse to gravity

the direction of big force

Answer: Hope this helps ;) don't forget to rate this answer !

Explanation:

There are two correct answers:

A) A corporation leader makes direct payment to the candidate.

D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.

Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.

Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.

I hope this helps! Let me know if you have any other questions.

Answer:

Component

Explanation:

All circuits have some basic parts, called components. One component is the power source, also called a voltage source. The power source is what pushes the electricity through the circuit.

A. The average speed you can use to pull the safe is 1.02 m/s

B. The time needed to pull the safe up is 17.65 s

First, we shall obtain the force. This is shown below:

F = mg

F = 60 × 9.8

F = 588 N

Finally, we shall obtain the average speed. Details below:

Power = force × average speed

600 = 588 × average speed

Divide both sides by 588

Average speed = 600 / 588

Average speed = 1.02 m/s

The time needed to pull the safe up can be obtained as follow:

Time = Total distance / average speed

Time = 18 / 1.02

Time = 17.65 s

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Complete question:

You know you can provide 600 W

of power to move large objects. You need to move a 60-kg

safe up to a storage loft, 18 m

above the floor.

Part A

With what average speed can you pull the safe straight up?

Part B

What is the time needed to pull the safe up?

Answer:

c

Explanation:

Answer:

F = M v^2 / R = M w^2 R      where w represents the angular frequency

Only 1 / R causes a reduction in centripetal force when increased

(B)   is the answer

Option B. The radius of curvature causes a reduction in centripetal force with an increase in the magnitude.

Centripetal force is a force that acts on the object that moves in a circular motion and is directed towards the center of the circular moving path. The mathematical representation of centripetal force is -

Where Fc = the centripetal force,

m = mass of the object,

v = velocity

and r = radius.

From the given explanation above, The centripetal force and radius of curvature are inversely proportional to each other,

that is, Fc = 1/r.

Therefore, an increase in the radius of curvature leads to a reduction in the centripetal force.

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Answer:

The graphic organizers help to keep track of the details. They are a visual representation of knowledge that rescue the important aspects of a concept using labels within a scheme. They also present information in a concise manner, highlighting the organization and the relationship of the concepts. Graphic organizers help students organize their thinking process and their writing.

Explanation:

The physical characteristics of sound and light waves explain why you can hear from behind a wall but not around it.

Mechanical waves called sound waves move through a medium like air or solid things. Some of the energy of a sound wave that hits a wall or other obstruction is absorbed by the barrier, but some of the energy also travels through the wall as vibrations. Some sound waves may be able to pass through a thin or sparse barrier and reach your ears on the other side.

On the other hand, light waves are electromagnetic waves that may travel through any material. Some of the energy of light waves is absorbed by a barrier like a wall, but the majority of the energy is reflected back or scattered in multiple directions. The majority of the light waves will be blocked by a thick or opaque wall, preventing you from seeing through it.

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Answer: NO, there are many examples of non-conservative forces.

Explanation: Conservatives forces are special forces whose work is zero in a closed path.

Complete question:

An air-filled parallel-plate capacitor has plates of area 2.90 cm2 separated by 2.50 mm. The capacitor is connected to a(n) 18.0 V battery. Find the value of its capacitance.

Answer:

The value of its capacitance is 1.027 x 10⁻¹² F

Explanation:

Given;

area of the plate, A = 2.9 cm² = 2.9 x 10⁻⁴ m²

separation distance of the plates, d = 2.5 mm = 2.5 x 10⁻³ m

voltage of the battery, V = 18 V

The value of its capacitance is calculated as;

\(C = \frac{k\epsilon_0A}{d} \\\\C = \frac{(1)(8.85\times 10^{-12})(2.9 \times 10^{-4})}{2.5 \times 10^{-3}} \\\\C = 1.027 \times 10^{-12} \ F\)

Therefore, the value of its capacitance is 1.027 x 10⁻¹² F

The quarterback is getting hit with a force of 100 Newtons.

We can use Newton's second law of motion:

Force = Mass * Acceleration

Given that the mass of the defensive lineman is 100 kg and the acceleration is 1 m/s², we can substitute these values into the equation:

Force = 100 kg * 1 m/s²

Force = 100 N

Therefore, the quarterback is getting hit with a force of 100 Newtons.

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Answer:

A. v = √2gh

B. No! The final velocity does not depend on the mass of the car.

C. Yes! the final velocity depends on the steepness of the hill

D. 3.28 m/s

Explanation:

A. Determination of the final velocity.

½mv² = mgh

Cancel out m

½v² = gh

Cross multiply

v² = 2gh

Take the square root of both side

v = √2gh

B. Considering the formula obtained for the final velocity i.e

v = √2gh

We can see that there is no mass (m) in the formula.

Thus, the final velocity does not depend on the mass of the car.

C. Considering the formula obtained for the final velocity i.e

v = √2gh

We can see that there is height (h) in the formula.

Thus, the final velocity depends on the steepness of the hill

D. Determination of the final velocity.

Height (h) = 0.55 m

Acceleration due to gravity (g) = 9.8 m/s²

Velocity (v) =?

v = √2gh

v = √(2 × 9.8 × 0.55)

v = √10.78

v = 3.28 m/s

Answer:

a

The  speed of  wave is   \(v_1 = 129.1 \ m/s\)

b

The new speed of the two waves is \(v = 129.1 \ m/s\)

Explanation:

From the question we are told that

    The mass of the string is  \(m = 60 \ g = 60 *10^{-3} \ kg\)

    The length is  \(l = 2.0 \ m\)

    The tension is  \(T = 500 \ N\)

Now the velocity of the first wave is mathematically represented as

     \(v_1 = \sqrt{ \frac{T}{\mu} }\)

Where  \(\mu\) is the linear density which is mathematically represented as

      \(\mu = \frac{m}{l}\)

substituting values    

     \(\mu = \frac{ 60 *10^{-3}}{2.0 }\)

     \(\mu = 0.03\ kg/m\)

So

   \(v_1 = \sqrt{ \frac{500}{0.03} }\)

   \(v_1 = 129.1 \ m/s\)

Now given that the Tension, mass and length are constant the velocity of the second wave will same as that of first wave (reference PHYS 1100 )

Answer:

dolphin= 7 meters/1 second      walrus= 5 meters/1 second

Explanation:

56 divided by 8 is 7

30 diviided by 6 is 5

a) The total surface area of tin G in terms of π is 170π cm².

b) The mass of tin H is 336 g.

To solve the given problem, we need to determine the total surface area of tin G in terms of π and the mass of tin H. Since the mass of an empty cylindrical tin is proportional to its surface area, we can use the given information to find the solutions.

a) Total surface area of tin G in terms of π:

The surface area of a cylinder consists of two circular bases and the lateral surface area. The formula for the lateral surface area of a cylinder is given by:

Lateral surface area = 2πrh

where r is the radius of the base and h is the height of the cylinder.

In the case of tin G, the given dimensions are a radius of 5 cm and a height of 12 cm. Substituting these values into the formula, we can calculate the lateral surface area:

Lateral surface area = 2π(5 cm)(12 cm)

Lateral surface area = 120π cm²

Since the total surface area of the cylinder includes the two circular bases as well, we need to add their areas. The area of a circle is given by:

Area of a circle = πr²

The radius of the circular base of tin G is 5 cm, so the area of each circular base is:

Area of each circular base = π(5 cm)²

Area of each circular base = 25π cm²

To find the total surface area of tin G, we sum the lateral surface area and the areas of the two circular bases:

Total surface area of tin G = Lateral surface area + 2 × Area of each circular base

Total surface area of tin G = 120π cm² + 2 × 25π cm²

Total surface area of tin G = 120π cm² + 50π cm²

Total surface area of tin G = 170π cm²

Therefore, the total surface area of tin G in terms of π is 170π cm².

b) Mass of tin H:

We are given that the surface area of tin H is 792π cm². We can assume that the same proportionality factor applies as in tin G, so we can set up the following proportion:

(surface area of tin G) / (mass of tin G) = (surface area of tin H) / (mass of tin H)

Using the given values, we have:

(170π cm²) / (72 g) = (792π cm²) / (mass of tin H)

Cross-multiplying and solving for the mass of tin H, we get:

(170π cm²) × (mass of tin H) = (72 g) × (792π cm²)

mass of tin H = (72 g) × (792π cm²) / (170π cm²)

mass of tin H = 336 g

Therefore, the mass of tin H is 336 g.

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(a) The centripetal force required to keep the car traveling on the curved road is  4914.15 N.

(b) The coefficient of friction between the car's wheels and the ground must be approximately 0.334

The centripetal force required to keep a car traveling in a curved path is given by the formula:

Fc = (mv^2) / r

where;

Given:

Plugging these values into the formula, we get:

Fc = (1500 kg) (18.1)² / 100 m

Fc = 4914.15 N

The friction force between the car's wheels and the ground provides the centripetal force. The friction force can be calculated using the formula:

f = μN

where;

Since the car is not accelerating vertically, the normal force N is equal to the weight of the car, which is given by:

N = mg

where;

Plugging in the values for m and g, we get:

N = (1500 kg) * 9.8 m/s^2

N = 14700 N

Now we can use the value of the centripetal force calculated earlier to find the coefficient of friction:

4904.38 N = μ * 14700 N

μ = 4914.15 N / 14700 N

μ ≈ 0.334

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The resultant of the displacement is 336.5m

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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The time that would be taken is 1.6 s.

We know that the speed would be the ratio of the distance to the time that have been taken and that is how we would be able to solve the problem that we have in the case that is ahead of us in this question

We have that the speed is; Distance/Time

= 91 m/29s

= 3.1 m/s

At the same speed;

Time = Distance/Speed

= 5 m / 3.1 m/s

= 1.6 s

Hence we k now that the spaghetti would be able to take a time that is about 1.6 s

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(a) The first block  moves at 4.0 m/s in the same direction right after colliding.

(b) the system's total kinetic energy changes by  28.75 J

(c) the system's total kinetic energy changes by -1.25 J

Given;

First block's mass, m1, is 5 kg.

u1 = 3.0 m/s is the first block's starting speed.

m2 weight of the second block is 10.0 kg.

u2 = 2.0 m/s is the second block's initial speed.

v2 = 2.5 m/s is the second block's final speed.

Immediately following the impact, the first block block's Part (A) velocity is as follows:

Apply the law of conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2, where v1 is the speed of the first block after it collides.

(5 x 3.0) + (10 x 2.0) = 5.0v₁ + (10 x 2.5) (10 x 2.5)

35= 2.5v₁ + 25

2.5v₁ = 35-25

2.5v₁ = 10

v₁ = 10/2.5

v₁ = 4

2.5 m/s in the same direction for v1.

Change in the system's overall kinetic energy, part (B):

Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.

ΔK = (1/2m1v1^2 + 1/2m2v2^2) - (1/2m1u1^2 + 1/2m2u2^2)

ΔK is equal to (1/2 x 5 x 4^2 + 1/2 x 10 x 2.5^2) – (1/2 x 5 x 3^2 + 1/2 x 10 x 2^2).

ΔK = 71.25 J - 42.5 J

ΔK = 28.75 J

Change in part (C) of the system's total kinetic energy if the second block accelerates to 5.2 m/s

Determine the final speed of the first block using the conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2 (5 x 3.0) + (10 x 2.0) = 5v1 + (10 x 4)

35 = 2.5v₁ + 40

2.5v₁ = -5

2.5v₁ = - 5 v₁ = - 5 / 2.5 \s v₁ = -2 m/s

Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.

K = (1/2m1v12 + 1/2m2v22) - (1/2m1u12 + 1/2m2u22)

K is equal to (1/2 x 5 x 22 + 1/2 x 10 x 2.52) - (1/2 x 5 x 3 + 1/2 x 10 x 2).

ΔK = 41.25 - 42.5 J

ΔK = -1.25 J

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