Consider the orbital diagram shown. Which electron rule is broken in the diagram?

A. Aufbau Principle
B. Hund's Rule
C. Pauli Exclusion Principle​

Answer:

1. Mechanical energy

2. Thermal energy

3. electric energy to mechanical energy

4. electrical energy to light

5. electric energy into sound energy and radiant energy

Explanation:

Answer:

Carbon dioxide and water I believe because it is a combustion reaction

ΔLatticeU = ΔLatticeH – pΔVm is the lattice energy of wurtzite.  Ionic compounds often have flat surfaces that meet at distinctive angles and are stiff, brittle, crystalline materials.

Remember that when a metal reacts with a nonmetal, often an ionic compound results from the transfer of electrons form the metal (the reductant) towards the nonmetal (the oxidant). Ionic compounds often have flat surfaces that meet at distinctive angles and are stiff, brittle, crystalline materials. They melt at rather high temperatures and are not easily distorted.   ΔLatticeU = ΔLatticeH – pΔVm is the lattice energy of wurtzite.

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Answer:

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Explanation:

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For this exercise we need the polarity of the bonds, for that, we need the electronegativity of the elements from the bonds.

These are nonmetals, so we have covalent bonds.

The 3 of the highlighted bonds are covalent.

-----------------------------------------------------------------------

-C-C-

We calculate the polarity as a subtraction:

Polarity (-C-C-) = 0 = 2.5 - 2.5

2.5 is the electronegativity for C

-----------------------------------------------------------------------

-C-O-

Polarity (-C-O-) = 3.5 (O) - 2.5 (C) = 1.0

-----------------------------------------------------------------------

-C-F-

Polarity (-C-F-) = 4.0 (F) - 2.5 (C) = 1.5

------------------------------------------------------------------------

The electronegativities can be obtained from the Pauling scale.

Now the answer:

Decreasing order of polarity:

-C-F (the most) = 1.5 > -C-O-(the next) = 1.0 > -C-C- (the less) = 0

Answer:

Anyone got the answers

Explanation:

Answer: A

Explanation: just do as I say

During a baseball game, the sound of the bat hitting the ball can be heard in most parts of the stadium. That sound is weaker at greater distances. The cause of this phenomenon is inverse-square law.

Sound is a physical disturbance from an equilibrium condition that travels via an elastoplastic medium. A completely subjective definition of sound, as perceived by the ear, is also viable, but it is not especially informative and is overly limited, because it is important to speak of noises which can be heard by the auditory system, such as those produced by dog whistles or sonar technology.

The inverse-square law, that states that the strength of a sound wave is inversely related to the square of the distance to the source, is the cause of this phenomena. The strength of such sound wave reduces as the distance to the source rises.

Therefore,  the cause of this phenomenon is inverse-square law.

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Charles's law of gases states that the density of an ideal gas is inversely proportional to its temperature at constant pressure.

The equation is as follows;

Va/Ta = Vb/Tb

Where;

0.67/362 = 1.12/Tb

0.00185Tb = 1.12

Tb = 605.41K

This temperature in °C is 605.41 - 273 = 332°C

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If a sample has an initial mass of 4.48 grams and undergoes decay until it has a mass of 0.140 grams, then option b 3 half-lifes  passed

The half-life of a substance is the amount of time it takes for half of the initial sample to decay. For cobalt-60, the half-life is 5.26 years. This means that if we start with 4.48 grams of cobalt-60, half of that (2.24 grams) will remain after 5.26 years.

The remaining 2.24 grams will then decay until half of that (1.12 grams) remains after another 5.26 years. Continuing this pattern, we can see that after 3 half-lives (15.78 years), we will be left with 0.140 grams of cobalt-60. Therefore, the sample underwent decay for 3 half-lives.

Half-life, in chemistry, is the time required for half of the original number of radioactive atoms in a sample to decay. The half-life of a radioactive substance is a measure of the stability of the nucleus of the atom.

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100.0 degrees Celsius = 100.0 + 273 = 373.0 K

\(\frac{750}{373.0}=\frac{V_{2}}{673.0} \\ \\ V_{2}=\frac{(673.0)(750)}{373.0} \approx \boxed{1350 \text{ mL}}\)

Answer:

Life in the Han Dynasty (206 BCE - 220 CE) differed significantly from today in family, government, social structure, religion, and trade. For example, the Han Dynasty emphasized a patriarchal family structure, where the eldest male held authority, and filial piety was highly valued. In contrast, contemporary societies embrace more egalitarian family dynamics with shared decision-making.

The government system of the Han Dynasty relied on a centralized bureaucracy and emphasized meritocracy, while modern societies often adopted democratic systems. Socially, the Han Dynasty followed a hierarchical model influenced by Confucian principles, whereas contemporary societies strive for greater equality and social mobility.

Religion in the Han Dynasty combined Confucianism, Taoism, and Buddhism, whereas modern societies exhibit diverse religious beliefs. Lastly, trade in the Han Dynasty thrived along the Silk Road, while modern trade was globally interconnected and facilitated by technological advancements. These differences highlight the evolution of society over time.

Explanation:

Given :

Mass of Ba(OH)₂ , m = 35.5 g.

Volume of mixture, V = 325 mL = 0.325 L.

To Find :

The molarity of a solution.

Solution :

We know, molarity of a solution is given by :

\(M = \dfrac{Given \ Weight}{Molecular\ Mass\times Volume( L ) }\)

We know, molecular mass of Ba(OH)₂ is given by :

M.M. = 171 g/mol

Putting all these values in given equation, we get :

\(M = \dfrac{35.5}{171\times 0.325}\ M\\\\M = 0.64\ M\)

Hence, this is the required solution.

Answer:A medication break can ease side effects. A lack of appetite, weight loss, sleep troubles, headaches, and stomach pain are common side effects of ADHD medication.

Explanation: It may boost your child’s growth. Some ADHD medications can slow a child’s growth in height, especially during the first 2 years of taking it. While height delays are temporary and kids typically catch up later, going off medication may lead to fewer growth delays.

It won’t hurt your child. Taking a child off ADHD medication may cause their ADHD symptoms to reappear. But it won’t make them sick or cause other side effects.

Answer:

\(\% H_2O=51.2\%\)

Explanation:

Hello!

In this case, since the percent water is computed by dividing the amount of water by the total mass of the hydrate; we infer we first need the molar mass of water and that of the hydrate as shown below:

\(MM_{MgSO_4* 7H_2O}=120.36 g/mol+7*18.02g/mol\\\\MM_{MgSO_4* 7H_2O}=246.5g/mol\)

Thus, the percent water is:

\(\% H_2O=\frac{7*MM_{H_2O}}{MM_{MgSO_4* 7H_2O}} *100\%\\\\\)

So we plug in to obtain:

\(\% H_2O=\frac{7*18.02}{246.5} *100\%\\\\\% H_2O=51.2\%\)

Best regards!

Answer:

Balanced Reaction

hope it helps pls mark BRAINLIST

an object becomes positively charged when it LOSES ELECTRONS.

* protons are positive, so losing protons means that it would be negatively charged.

* gaining electrons would make it more negatively charged.

* gaining neutrons changes nothing because neutrons are neutral.

Answer:

C. molten rock below Earth’s surface

Explanation:

Global warming brought on by rising carbon dioxide concentrations in the atmosphere is changing weather patterns and ocean temperatures. Changes in precipitation patterns are being brought on by the warming of the atmosphere.

Because it is one of the gases in the atmosphere that causes the greenhouse effect, which causes the Earth to warm, carbon dioxide is known as a greenhouse gas. Long-wavelength infrared radiation (heat) from the Earth is absorbed by carbon dioxide molecules in the atmosphere, and some of it is then radiated back downward.

Similarly, as air temperatures rise in response to rising carbon dioxide concentrations, more water vapor escapes into  the atmosphere—which then amplifies greenhouse heating

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An aqueous  KNO\(_3\) solution is made using 77.2 g of  KNO\(_3\) diluted to a total solution volume of 2.06 L. 3.33% is the mass percent of the solution.

Mass percent is the means to indicate a concentration. Furthermore, it describes the element in a certain composition. A mass percentage can be used to understand the solution's composition. It displays the amount of solute in a certain amount of solution. The solute's concentration is specified in terms of mass or moles.

In order to represent the mass percent of a solution, the kilograms of solute are split by the kilograms of solution, and the result is multiplied by 100.

Number of moles of  KNO\(_3\) = mass/molar mass =  77.2 /101 g= 0.72 moles

Molarity = Number of moles / volume =  0.72 / 2.06  = 0.36 mol/L

molality = Number of moles of solute/Mass of solution in kilograms

mass of solution =  1.05 g/mL × 2000 mL = 21000 g=2.1Kg

Mass percent of solution = mass of solute/mass of solution × 100

Mass percent of solution = 77.2 g/ (77.2 g + 2100 g) × 100

                                         = 3.33%

Therefore,  3.33% is the mass percent of the solution.

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There are 576 different ways to choose a meal.

Promotional offers. A promotional offer is a specific proposition to clients that specifies a reward and patron behavioral standards for earning a reward. the recognition and trouble of the praise are captured thru a retail transaction, purchaser order, rebate claim, rebate redemption, or different patron interplay. a discount is a difference between the unique charge and the lower charge it's far being bought at. a proposal is a deal wherein a product is normally bought at a reduction.

Calculation:-

There are 8 appetizers, 12 entrees, and 6 desserts.

Number of choices =  8 × 12 × 6

                                =  576

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The mass and charge must be balanced so that the compound formed is neutral. The limiting reactant determines the amount of the precipitate that can be formed.

When we talk about an ionic equation, we are talking about the kind of equation that is able to show the ions that are able to undergo a change in a given reaction. We know that in many cases the ionic reaction would lead to the formation of a precipitate and this is the solid product that is obtained when we happen to mix two solutions that are known to be aqueous solutions.

Having made all that introduction, we know that a compound is said to be neutral when the charges in the species that form the compound could be seen as being balanced. This is the reason why the mass and charge must be balanced when we are dealing with an ionic reaction equation.

The factor that determines the amount of precipitate that would form is the limiting reactant of the process.

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The reaction is endothermic since the energy level of the products have are higher than that of the reactants.

The activation energy (AE) is the energy difference between the reactants and the transition state.

The change in energy E and the energy difference between the reactants and the products

The data given is as follows:

Reactants: 0 kJ/mol

AE forward 125 kJ/mol

AE reverse: 86 kJ/mol

Products: 39 kJ/mol

The values of ΔE forward and ΔE reverse are as follows:

ΔE forward = (39 - 0) kJ/mol

ΔE forward = +39 kJ/mol

ΔE reverse = (0 - 39) kJ/mol

ΔE reverse =  -39 kJ/mol

3. Given that Ea = 154 kJ/mol and ΔE = 136 kJ/mol

AE reverse = ΔE - AE forward

E = 136 kJ/mol - 154 kJ/mol

E = -18 kJ/mol

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55.03 moles of KCI are produced when 6743 grams of \(KClO_{3}\) decomposes

To determine the number of moles of KCl produced when 6743 grams of \(KClO_{3}\) decomposes, we need to use the concept of molar mass and the balanced chemical equation.

First, let's calculate the molar mass of \(KClO_{3}\)

The molar mass of potassium (K) is approximately 39.10 g/mol.

The molar mass of chlorine (Cl) is approximately 35.45 g/mol.

The molar mass of oxygen (O) is approximately 16.00 g/mol.

So, the molar mass of \(KClO_{3}\) is:

(39.10 g/mol) + (35.45 g/mol) + (3 * 16.00 g/mol) = 122.55 g/mol.

Now, we need to calculate the number of moles of \(KClO_{3}\):

Number of moles = Mass / Molar mass

Number of moles = 6743 g / 122.55 g/mol = 55.03 mol.

According to the balanced chemical equation:

2\(KClO_{3}\) -> 2 KCl + 3 O2,

we can see that for every 2 moles of \(KClO_{3}\), we obtain 2 moles of KCl.

Therefore, the number of moles of KCl produced will be equal to the number of moles of \(KClO_{3}\) since the ratio is 1:1. Thus, 55.03 moles of KCl will be produced.

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The equilibrium quotient based on the following initial concentrations and predict whether the system with shift left or shift right is 3.10 x 10⁻⁴ right  

There are two types of gas-phase reactions: intramolecular and intermolecular. Precursor molecules are broken down into activated species in intramolecular reactions, which are then used in the CVD process.

Qc = [C] = equilibrium quotient ² / [A]² [B]³

Qc = (0.0383)² / (0.219)² (4.62) (4.62)³

Qc = 3.10 x 10⁻⁴

Kc = 5.00

Kc > Qc . so shifts to right

We use the ideal gas equation PV=nRT to account for these conditions, where P is the pressure in atmosphere (atm), V is the volume in liters (L), n is the number of moles, and R is the gas constant with a value of 08206 L atm mol-1 K-1, where T is the temperature in kelvin (K) and L is the atm.

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Answer:

A front is a weather system that is the boundary separating two different types of air. One type of air is usually denser than the other, with different temperatures and different levels of humidity.

Q methane = Q water

Q = mcΔt

mass water = V x ρ = 1 L x 1 kg/L = 1 kg

298 K to 373K = 25 °C to 100 °C

c water = 75.2 J/mol K = 4.2 J / g °C = 4200 J/kg °C

Q water = 1 x 4200 x (100 - 25)

Q water = 315000 J

Q methane = Q water = 315000 J = 315 KJ

n (mol) methane = ΔH/Q = 890.4 / 315 = 2.83

PV = nRT

V = nRT/P

V = 2.83 x 0.082 x 298/1

V = 69.15 L

1. The % concentration is 20.7% and the molar concentration, Cm, is 1.5 M.

2. 7.8 grams of potassium sulfate will be formed.

3. 10.7 grams of ammonium chloride will be formed.

4. The volume of hydrogen gas that will be produced is 3.86 liters.

5. 21.43 grams of the 70% acetic acid is needed to prepare 500 grams of 3% acetic acid solution.

1. Mass of potassium sulfate = 1.5 moles * (174.26 g/mol) = 261.39 g

Mass of water (H₂O) = 1000 g

% = (mass of solute/mass of solution) x 100

% = (261.39 g / (261.39 g + 1000 g)) x 100

% ≈ 20.7%

Cm = moles of solute / volume of solution

Moles of potassium sulfate (K2SO4) = 1.5 moles

Volume of water (H2O) = 1000 g / (density of water) = 1000 g / 1 g/mL = 1000 mL = 1 L

Cm = 1.5 moles / 1 L

Cm = 1.5 M

2. The balanced equation for the reaction is:

H₂SO₄ + 2 KOH → K₂SO₄ + 2 H₂O

Molar mass of sulfuric acid (H₂SO₄) = 98.09 g/mol

Moles of sulfuric acid = 10 g / 98.09 g/mol

Moles of sulfuric acid = 0.102 mol

Based on the mole ratio of the reaction, 0.102 moles of sulfuric acid will react to form 0.102 moles of potassium sulfate.

Molar mass of potassium sulfate = 174.26 g/mol

Mass of potassium sulfate = 0.102 mol x 174.26 g/mol

Mass of potassium sulfate ≈ 17.8 g

3. The balanced equation for the reaction is:

Molar mass of hydrochloric acid (HCl) = 36.46 g/mol

Moles of hydrochloric acid (HCl) = 7.3 g / 36.46 g/mol

Moles of hydrochloric acid ≈ 0.2 mol

Based on the mole ratio of the reaction, 0.2 moles of hydrochloric acid will react to form 0.2 moles of ammonium chloride.

Molar mass of ammonium chloride (NH₄Cl) = 53.49 g/mol

Mass of ammonium chloride = 0.2 mol x 53.49 g/mol

Mass of ammonium chloride ≈ 10.7 g

4. The balanced equation for the reaction is:

Molar mass of zinc (Zn) = 65.38 g/mol

Moles of zinc = 13 g / 65.38 g/mol

Moles of zinc ≈ 0.199 mol

Based on the mole ratio of the reaction, 0.199 moles of zinc will react to produce 0.199 moles of hydrogen gas.

Volume of sulfuric acid = 30 g / (density of H₂SO₄ )

The density of H₂SO₄ is 1.84 g/mL

Volume of sulfuric acid  = 30 g / 1.84 g/mL

Volume of sulfuric acid ≈ 16.3 mL or 0.0163 L

Using the ideal gas law, the volume of hydrogen gas produced will be:

V = nRT / P

V = (0.199 mol)(0.0821 L·atm/(mol·K))(273 K) / (1 atm)

V ≈ 3.86 L

5. Assuming that the concentrated original solution of acetic acid is 100% acetic acid (CH₃COOH).

Mass of acetic acid = 500 g x (3/100) = 15 g

The concentrated original solution, however, is 70% acetic acid.

70% acetic acid (mass) = 100% acetic acid (unknown mass)

0.7 * (unknown mass) = 15 g

Solving for the unknown mass:

unknown mass = 15 g / 0.7

unknown mass ≈ 21.43 g

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