Consider the following reaction: Cd (s) AgCl (aq) --> CdCl2 (aq) Ag (s) In this reaction, a. electrons are transferred from silver in AgCl (aq) to Cd (s) b. electrons are transferred from Cd (s) to silver in AgCl (aq) c. no electrons are transferred since the oxidation number of chlorine atoms does not change d. the oxidizing agent is Cd (s) e. the reducing agent is AgCl (aq)

Answer and Explanation:

If the future did not address global warming properly, then the world will become too hot faster than it should, and the days will get extremely hot, and in the distant future, lead to our extinction.

To address this problem, we can spread the awareness about it, get people to think open minded and not think that global warming is a joke, and plant trees, which takes in the carbon dioxide we exhale.

#teamtrees #PAW (Plant And Water)

Answer:

0.3927 grams

Explanation:

convert density from g/l to g/cm3

0.17 g/l = 0.00017 g/cm3

multiply volume and density to get mass

0.00017*2310=0.3927

The average number of internet services in an area of 5.0-kilometer square would be 0.36 internet services..

The average number of people per square mile = 710

1 square mile = 2.59 square kilometer

The average number of people per kilometer square = 710

Number of internet services per person = 0.72

The total number of people that would be in a 5.0-kilometer square = 710 x 5 = 3550 people.

710 people = 0.72 internet services

3550 people = 3550 x 0.72/710

                       = 3.6 internet services

in other words, the average number of internet services per person in an area of 5.0-kilometer square would be 0.36 internet services.

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The methyl orange indicator will change from red to yellow at the titration's endpoint.

An acid-base indicator called methyl orange changes color between the pH ranges of 3.1 and 4.4. In acidic and basic solutions it is red and yellow, respectively

In this instance, an acid, hydrochloric acid, is being used to titrate the barium hydroxide solution. The pH of the solution will fall as we add the acid since it will neutralize the base. The hue of the methyl orange indicator will vary when the pH ranges from 3.1 to 4.4

All of the barium hydroxide will have interacted with the hydrochloric acid by the time the titration is complete leaving a neutral solution. When the methyl orange indicator becomes yellow the solution's pH is in the basic range.

Therefore, the methyl orange indicator will change from red to yellow at the titration's endpoint.

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gold density = 19.3 g/cm³

mass = 16.5 kg = 16.5 x 10³ g

volume = 954 ml

gold density based on the experiments:

ρ = 16.5 x 10³ g / 954 ml(cm³) = 17.296 g/cm³ ( not of pure gold)

Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

The answer would be RCH2COCH2R is more polar than RCH2(OH)R

The formic acid ( RCH2COCH2R ) is more polar than Pyridinium Chlorochromate (PCC) (RCH2(OH)R) because formic acid is from aldehyde group and is a reagent from a carbonyl group and PCC is react to form carbonyl group it's also an reagent which reacts in oxidation of alcohols.

The polarity is more which is a carbonyl compound as their electrons are loosely prepared. And also the polarity of formic acid is 6.0.

Hence, the formic acid (RCH2COCH2R) is more polar than Pyridinium Chlorochromate (RCH2(OH)R) (PCC).

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The value of missing cell potential is - 0.04 V

The cell potential (Ecell), is the measure of the potential difference between two half cells in an electrochemical cell.

Fe(III) / Fe(II) potential involves different chemical species in acidic and basic solution.

2FeO²⁻ + 3ClO⁻  + 2OH⁻  -->  FeO₄²⁻ + 3Cl⁻  + H₂O

FeO₄²⁻ can easily oxidise water under acidic conditions.

Hence, The value of missing cell potential is - 0.04 V

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True;

The earth is currently in an interglacial period

Climate has changed naturally over the earth's history

False

The increase since 1860 is similar to previous increases

Atmospheric composition have remained the same throughout earth history.

Atmospheric carbon dioxide has increased significantly since 1860, primarily due to human activities such as burning of fossil fuels and deforestation.

There are also seasonal variations in CO2 concentrations, with higher concentrations in the winter months and lower concentrations in the summer months. This is because the majority of the world's vegetation is in the Northern Hemisphere, and during the winter months, there is less photosynthesis occurring to remove CO2 from the atmosphere.

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A chemist determines that a substance is composed of 30.4% nitrogen by mass and 69.6% oxygen by mass. The molar mass of the compound is 230.5 g/mol, the molecular formula is NO₂.

We must compute the empirical formula in order to ascertain the compound's chemical composition.

If we have 100 grams of the compound.

This suggests we have:

30.4 g of nitrogen

69.6 g of oxygen

Now, we have to convert the mass of each element to moles.

The molar mass of nitrogen (N) = 14.01 g/mol

the molar mass of oxygen (O)  =  16.00 g/mol.

Number of moles of nitrogen (N):

2.17 mol

Number of moles of oxygen (O):

4.35 mol

The simplest whole-number ratio between the moles of nitrogen and oxygen must now be determined. To calculate the ratio, we divide both numbers by the smaller value.

Moles N / moles O = 2.17 mol / 2.17 mol = 1.00

Moles O / moles O = 4.35 mol / 2.17 mol = 2.00

The ratio is approximately N₁O₂.

We divide the subscripts by their greatest common divisor to obtain the simplest ratio, since we are looking for the empirical formula. The empirical formula is NO₂ since the greatest common divisor in this situation is 1.

The molecular formula of the compound is NO₂.

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Answer:

The first thing you will need to do is find some information about your element. Go to the Periodic Table of Elements and click on your element. If it makes things easier, you can select your element from an alphabetical listing.

Number of Protons = Atomic Number

Number of Electrons = Number of Protons = Atomic Number

Number of Neutrons = Mass Number - Atomic Number

For krypton:

Number of Protons = Atomic Number = 36

Number of Electrons = Number of Protons = Atomic Number = 36

Number of Neutrons = Mass Number - Atomic Number = 84 - 36 = 48

Explanation:

hope this helps, have a good day :-)

Answer:

15%

85%

Explanation:

Let the natural abundance of Fe-55  = y

      the natural abundance of Fe - 56  = 1-y

Average atomic mass = 55.85

Unknown:

Percent abundances of each isotope = ?

Solution;

The average atomic mass of a substance is given as;

  Average atomic mass  =  (mass x abundance)Fe - 55 + (mass x abundance)Fe - 56

Now insert the parameters and solve;

55.85  = (55 x y) + [56 x(1-y)]

 55.85  = 55y + 56 - 56y

 55.85  = -y + 56

  55.85 - 56  = -y

  -0.15 = -y

     y  = 0.15

1-y  = 1 - 0.15  = 0.85

Percentage abundance;

   Fe - 55  = 0.15 x 100  = 15%

   Fe - 56  = 0.85 x 100  = 85%

The standard enthalpy change (∆H°rxn) for the given reaction is -38.0 kJ/mol. This negative value indicates that the reaction is exothermic, meaning that it releases heat to the surroundings.

The standard enthalpies of formation (∆Hf°) for the reactants and products involved in the reaction are: ∆Hf°[NO2(g)] = +33.2 kJ/mol. ∆Hf°[H2O(l)] = -285.8 kJ/mol. ∆Hf°[HNO3(aq)] = -207.2 kJ/mol. ∆Hf°[NO(g)] = +90.4 kJ/mol. We can use these values to calculate the standard enthalpy change (∆H°) for the reaction using the following equation:

∆H°rxn = Σn∆Hf°(products) - Σm∆Hf°(reactants) where n and m are the stoichiometric coefficients of the products and reactants, respectively. Substituting the values, we get:∆H°rxn = [2 × ∆Hf°(HNO3(aq))] + [∆Hf°(NO(g))] - [3 × ∆Hf°(NO2(g))] - [1 × ∆Hf°(H2O(l))]. ∆H°rxn = [2 × (-207.2 kJ/mol)] + [90.4 kJ/mol] - [3 × (+33.2 kJ/mol)] - [1 × (-285.8 kJ/mol)]. ∆H°rxn = -414.4 kJ/mol + 90.4 kJ/mol - 99.6 kJ/mol + 285.8 kJ/mol. ∆H°rxn = -38.0 kJ/mol

Therefore, the standard enthalpy change (∆H°rxn) for the given reaction is -38.0 kJ/mol. This negative value indicates that the reaction is exothermic, meaning that it releases heat to the surroundings.

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Answer: 3.44%

Explanation: try it for math

The bond energy of H-Br bond can be calculated using the following equation:

bond energy = ∆H(products) - ∆H(reactants)

where ∆H is the change in enthalpy for the reaction.

From the given data, we can calculate the bond energy of H-Br bond as follows:

bond energy = (2 HBr + 150 kJ) - (H₂ + Br₂)

= (2 HBr - H₂ - Br₂) + 150 kJ

= (2 HBr - H₂ - Br₂ - 430 kJ) + (150 kJ - 180 kJ)

= (-H₂ - Br₂ + 2 HBr - 430 kJ + 150 kJ - 180 kJ)

= (-H₂ - Br₂ + 2 HBr - 480 kJ)

= (-2H + 2 HBr - 480 kJ)

= (2 HBr - 2H - 480 kJ)

= (2 HBr - 2H + 2H₂ - 2H - 480 kJ)

= (2 HBr - 2H₂ - 480 kJ)

= (-2H₂ + 2 HBr - 480 kJ)

= (-2H₂ + 2 HBr + 430 kJ)

= (-2H₂ + 2 HBr + 2H₂ - 2H - 180 kJ)

= (-2H₂ + 2 HBr + 2H₂ - 2H + 430 kJ - 180 kJ)

= (2H₂ + 2 HBr - 2H + 250 kJ)

= (2H₂ + 2 HBr - 2H - 430 kJ + 680 kJ)

= (2H₂ + 2 HBr - 2H - 430 kJ + 2H₂ - 2H + 680 kJ)

= (4H₂ + 2 HBr - 430 kJ + 680 kJ)

= (4H₂ + 2 HBr + 250 kJ)

= (4H₂ + 2 HBr - 180 kJ + 430 kJ)

= (4H₂ + 2 HBr + 250 kJ - 180 kJ)

= (4H₂ + 2 HBr + 70 kJ)

Therefore, the bond energy of H-Br bond is 70 kJ.

The correct answer is therefore [d] 240 kJ.

Irrespective of the structure of the crystals, the dissolve in water.

Not all crystals are soluble in water, but many are because of the nature of their chemical bonds and the interactions between water molecules and the crystal structure.

When a crystal is placed in water, the water molecules surround the ions or molecules of the crystal and interact with them through hydrogen bonding, electrostatic attraction, and other intermolecular forces. These interactions weaken the bonds holding the crystal together, and eventually, the crystal breaks down and dissolves in water.

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A shortcoming of Rutherford’s model of the atom is it did not account for the fact that atoms have equal numbers of protons and electrons. Therefore, option C is correct.

Ernest Rutherford, a scientist who was born in New Zealand, developed the Rutherford model to explain an atom. Rutherford oversaw the Geiger-Marsden experiment, which, after Rutherford's analysis in 1911, indicated that J. J. Thomson's plum pudding model of the atom was flawed, in 1909.

The first person to recognize an atom's nucleus was Rutherford. He attacked gold with -particles and discovered that there was positively charged material inside the atom as a result.

It did not explain the distribution of the atom's negatively charged electrons around its positively charged nucleus.

Thus, option C is correct.

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Answer: 177.23 g.

Explanation:

the volume of the aluminum bar is

1.7 cm x 3.0 cm x 12.9 cm

= 65.61 cm^3

2.7 g/cm^3 x 65.61 cm^3

177.23g

The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.

The unbalanced equation is:

2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)

Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)

Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:

2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

To remove the fractional coefficient, we can multiply all coefficients by 2:

4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:

4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

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CuI2 is not a known compound. Copper compounds typically have different oxidation states for copper, resulting in various compound names.

Copper(II) oxide (CuO): It is a black solid compound where copper is in the +2 oxidation state. It is commonly used as a pigment and in catalytic reactions.

Copper(II) sulfate (CuSO4): It is a blue crystalline compound in which copper is in the +2 oxidation state. It is used in various applications such as agriculture, electroplating, and as a laboratory reagent.

Copper(I) oxide (Cu2O): It is a red crystalline compound in which copper is in the +1 oxidation state. It is used as a pigment, in solar cells, and as a catalyst.

Copper(II) chloride (CuCl2): It is a greenish-brown solid compound in which copper is in the +2 oxidation state. It is utilized in various chemical processes, including etching and catalyst synthesis.

Copper(II) nitrate (Cu(NO3)2): It is a blue crystalline compound where copper is in the +2 oxidation state. It is commonly used in the production of catalysts, as a coloring agent, and in electroplating.

These are just a few examples of copper compounds with different oxidation states and properties. It's important to note that the compound CuI2 mentioned in the question, if it exists, would be an exception to the typical nomenclature for copper compounds.

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The partial pressure of \(N_2\)is 165.6 kPa and the partial pressure of \(H_2\)is 434.4 kPa.

To calculate the partial pressures of \(H_2\)and \(N_2\)in the 10dmcube container, we need to use the ideal gas law equation, which states that the pressure of a gas is directly proportional to its number of moles and temperature, and inversely proportional to its volume.

First, we need to calculate the number of moles for each gas. Since we are given the volume of each gas and the volume of the container, we can use the formula:

Number of moles = Volume / Molar volume

The molar volume is the volume occupied by one mole of a gas at a given temperature and pressure. At standard temperature and pressure (STP), the molar volume is 22.4 L/mol.

For \(N_2\), the number of moles is 2 dmcube / 22.4 L/mol = 0.089 mol
For \(H_2\), the number of moles is 5 dmcube / 22.4 L/mol = 0.223 mol

Next, we can calculate the partial pressures of each gas using the formula:

Partial pressure = (Number of moles / Total number of moles) * Total pressure

The total pressure is the sum of the pressures of each gas:

Total pressure = Pressure of N2 + Pressure of \(H_2\)

Given that the pressure of N2 is 100 kPa and the pressure of \(H_2\)is 500 kPa, we have:

Total pressure = 100 kPa + 500 kPa = 600 kPa

Now we can calculate the partial pressure of \(N_2\):

Partial pressure of \(N_2\)= (0.089 mol / (0.089 mol + 0.223 mol)) * 600 kPa = 165.6 kPa

Similarly, we can calculate the partial pressure of \(H_2\):

Partial pressure of H2 = (0.223 mol / (0.089 mol + 0.223 mol)) * 600 kPa = 434.4 kPa

Therefore, the partial pressure of \(N_2\)is 165.6 kPa and the partial pressure of \(H_2\)is 434.4 kPa.

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The grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g. None of the options provided match the calculated value of 466.64 g.

To determine the grams of magnesium hydroxide (Mg(OH)2) needed to yield 8.00 moles of magnesium chlorate (Mg(ClO3)2), we need to consider the balanced chemical equation for the reaction between magnesium hydroxide and chlorine.

The balanced equation is as follows:

2 Mg(OH)2 + 6 Cl2 → 2 Mg(ClO3)2 + 2 H2O

From the balanced equation, we can see that 2 moles of Mg(OH)2 react with 6 moles of Cl2 to produce 2 moles of Mg(ClO3)2.

Therefore, the stoichiometric ratio is 2 moles of Mg(OH)2 : 2 moles of Mg(ClO3)2.

To calculate the grams of Mg(OH)2 needed, we can use the stoichiometric ratio and the given moles of Mg(ClO3)2.

Given:

Moles of Mg(ClO3)2 = 8.00 moles

Using the stoichiometric ratio, we have:

8.00 moles Mg(ClO3)2 × (2 moles Mg(OH)2 / 2 moles Mg(ClO3)2) = 8.00 moles Mg(OH)2

To convert moles to grams, we need to multiply by the molar mass of Mg(OH)2.

The molar mass of Mg(OH)2 = (24.31 g/mol) + (2 * 16.00 g/mol) = 58.33 g/mol

Grams of Mg(OH)2 = 8.00 moles Mg(OH)2 × 58.33 g/mol = 466.64 g

Therefore, the grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g.

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Answer:

C. aquifer

Explanation:

I just did a lesson on this

:)

Answer:

\([PH_3]=0.30M\) but see detailed explanation, please.

Explanation:

Hello there!

In this case, unfortunately, we are not given the rate constant but we can set up a reaction according to the information available on the internet:

\(4PH_3\rightarrow P_4+6H_2\)

Whose rate constant is 0.0375/s. In such a way, it is possible infer that this is first-order reaction whose integrated rate law is:

\([PH_3]=[PH_3]_0exp(-kt)\)

Thus, given the initial concentration, rate constant and elapsed time, the final concentration of PH3 would be:

\([PH_3]=(0.95M)exp(-30.50s*0.0375/s)\\\\\)

\([PH_3]=0.30M\)

However, it is important to keep in mind this result may vary according to your actual question.

Regards!

Answer:

\(\boxed {\boxed {\sf 7.89*10^{-4} \ mol \ Pb}}\)

Explanation:

To convert from moles to atoms, we must use Avogadro's Number. Avogadro's Number

1. Set up ratio

We can use Avogadro's Number as a fraction or ratio.

\(\frac{6.022*10^{23} \ atoms \ Pb}{1 \ mol \ Pb}\)

2. Convert atoms to moles

Multiply the given number of atoms by the ratio.

\(4.75 *10^{20} \ atoms \ Pb *\frac{6.022*10^{23} \ atoms \ Pb}{1 \ mol \ Pb}\)

Flip the fraction so that the atoms of lead can cancel each other out.

\(4.75 *10^{20} \ atoms \ Pb *\frac{1 \ mol \ Pb}{6.022*10^{23} \ atoms \ Pb}\)

\(4.75 *10^{20} *\frac{1 \ mol \ Pb}{6.022*10^{23} }\)

\(\frac{4.75 *10^{20} \ mol \ Pb}{6.022*10^{23} }\)

\(7.88774494*10^{-4} \ mol \ Pb\)

3. Round

The original measurement of 4.75 had 3 significant figures (4, 7, and 5).

We must round our answer to 3 sig figs, which is the hundredth place for the number found.

\(7.88774494*10^{-4} \ mol \ Pb\)

The 7 in the thousandth place tells us to round the 8 up to a 9 in the hundredth place.

\(7.89*10^{-4} \ mol \ Pb\)

There are 7.89*10⁻⁴ moles of lead in 4.75*10²⁰ atoms of lead.

Answer:

\(C_3H_6\)

Explanation:

Hello!

In this case, since the empirical formula is the smallest representation of the molecular formula, it is known that the times in which the empirical formula is into the molecular formula is a whole number and is computed by dividing the molar mass of the molecular formula by that of the empirical formula as shown below:

\(\frac{42.08g/mol}{12.01+1.01x2}= \frac{42.08g/mol}{14.03g/mol}=3\)

Thus, the molecular formula times the empirical formula by 3 to obtain:

\(C_3H_6\)

Regards!

Answer:

Florida's Global Pattern.

Explanation:

Because of where Florida sits, the weather in the Gulf of Mexico actually blows enough water to Create tidal waves, and also hurricanes. at least that's what I was told cause I live here :>