consider the following function. f x = cos 3x 4 find the derivative of the function.

Answer:

Graph A

Step-by-step explanation:

do you want an explanation?

btw, plz brainleist :)

Answer:

x<-15

Step-by-step explanation:

You switch the sides of the sign because you are dividing by a negative.

-3x - 42 > 3

Add 42 to both sides to get -3x > 45

Divide both sides by -3 (when you switch the direction of the sign) and get x < -15

Answer:

whatever 31-18 is i think

Step-by-step explanation:

Answer:

Here is the answer.

Step-by-step explanation:

Hope this helps!!

The vertical intercept for the table showing the relationship for Jada's grandparents starting a savings account for her is starting savings amount in the account of $ 600.

The vertical intercept in a graph is the point where a line intersects the vertical axis of the coordinate plane. It represents the value of the dependent variable (y) when the independent variable (x) is equal to zero.

The vertical intercept would therefore be first amount in the savings account by Jada's grandparents which is the $ 600.  This is the amount when x = 0 or rather when x was the starting year of 2006.

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Answer:

ok so first we add 10 plus 7 together since if you don't show up you fail

which is 17

so out of 100 students 17 failed both

now we subtract 71 from 80 to get 9

so we add that together with 17 so

17+9=26 so 26 students failed both

Hope This Helps!!!

The continuity equation is satisfied and the flow is incompressible.

To check if the continuity equation is satisfied, we need to take the partial derivatives of the stream function with respect to x and y and see if they satisfy the continuity equation

Continuity equation: ∂u/∂x + ∂v/∂y = 0

where u and v are the x and y components of the velocity field, respectively.

From the definition of the stream function, we have

u = ∂Ψ/∂y = -2

v = -∂Ψ/∂x = -(-2) = 2

Taking the partial derivatives of u and v with respect to x and y, we have

∂u/∂x = 0, ∂v/∂y = 0

Substituting these values into the continuity equation, we get

∂u/∂x + ∂v/∂y = 0 + 0 = 0

Since the continuity equation is satisfied (resulted in zero), the flow is incompressible.

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The given question is incomplete, the complete question is:

The stream function for a two-dimensional, nonviscous, incompressible flow field is given by Psi = -2(x-y) where the stream function has the units of ft^2/s with x and y in feet. (a) Is the continuity equation satisfied?

The coordinates of the resulting point "J'" are: (-4, -4),

What is coordinate?

Using the horizontal and vertical separations from the two reference axes, a coordinate is a pair of numbers that expresses a point's location on a coordinate plane. typically expressed by the x-value and y-value pair (x,y).

The point given in question,

J = (4,-4)

Now, We know that the rule of the reflection of points across the y-axis says:

(x, y) ⇒ (-x, y)

Therefore , The coordinate of the resulting point J' after reflection from the y - axis of point J(4, -4) is,

(4, -4) ⇒ (-4, -4)

Hence, The coordinate of the resulting point J' after reflection is (-4, -4).

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Answer:

\(\begin{bmatrix}-1 & 2 \\ \frac{3}{2} & -\frac{5}{2} \end{bmatrix}\)

Step-by-step explanation:

Inverse of a matrix is given by,

\(\begin{bmatrix}a & b\\ c & d\end{bmatrix}=\frac{1}{ad-bc}\begin{bmatrix}d & -b\\ -c & a\end{bmatrix}\)

By using this property,

\(\begin{bmatrix}5 & 4\\ 3 & 2\end{bmatrix}^{-1}=\frac{1}{(5\times 2-4\times 3)}\begin{bmatrix}2 & -4\\ -3 & 5\end{bmatrix}\)

              \(=-\frac{1}{2}\begin{bmatrix}2 & -4\\ -3 & 5\end{bmatrix}\)

              \(=\begin{bmatrix}-1 & 2 \\ \frac{3}{2} & -\frac{5}{2} \end{bmatrix}\)

Therefore, inverse of the given matrix will be \(\begin{bmatrix}-1 & 2 \\ \frac{3}{2} & -\frac{5}{2} \end{bmatrix}\)

Answer:

x + 46

Step-by-step explanation:

Step 1: Write expression

4(-8x + 5) - (-33x - 26)

Step 2: Distribute

-32x + 20 + 33x + 26

Step 3: Combine like terms

x + 46

Answer:

Step-by-step explanation:

1. arc length

2. semicircle

3. minor arc

4. arc measure

5. circumference

6. radius

7. diameter

HOPE THIS HELPS

Answer:arc length

2. semicircle

3. minor arc

4. arc measure

5. circumference

6. radius

7. diameter

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

The area of the shaded sector  of a circle with central angle rst radians is 8π sq. unit

The shaded area of the circle is half of the whole circle. If we can get the area of the circle, we will halve it, to get the area of the shaded sector

Area of circle A =πr² where r is the radius of the circle.

From the picture, the radius of the circle is r= 4

The area of the shaded sector is half the area of the full circle.

Area of Shaded = πr²/2 = π4²/2= 16π/2= 8π = 25.13 sq. units.

The area of the shaded sector of the circle is 8π sq. units

The picture of the circle is attached below

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77 is the value of Q in linear equation.

What in mathematics is a linear equation?

A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included. The variables in the previous sentence, y and x, are referred to as a "linear equation with two variables" at times.  

                                   Equations with power 1 variables are known as linear equations. One example with only one variable is where ax+b = 0, where a and b are real values and x is the variable.

P ∝ 1/Q

PQ = K

AT P= 11

Q = 28

11 * 28 = K

K = 308

AT P = 4

4Q = 308

Q = 77

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Answer:

10000

Step-by-step explanation:

100 x 100

1 x 100 = 100

Add 2 more zeros at the end of your answer

10000

(pretty sure this is a troll but there is your answer)

Answer: 10,000.

Step-by-step explanation:

If you get 100 then added 100 times itself 100 times you'll get 10,000

Answer:

226.08

Step-by-step explanation:

The number of non-similar 1000-pointed stars is

\($\frac{1000-600-2}{2}= \boxed{199}.$\)

If we join the adjacent vertices of the regular \($n$\)-star, we get a regular \($n$\)\(-gon\). We number the vertices of this \($n$\)\(-gon\) in a counter clockwise direction: \($0, 1, 2, 3, \ldots, n-1.$\)

A regular \($n$\)-star will be formed if we choose a vertex number m where \($0 \le m \le n-1$\), and then form the line segments by joining the following pairs of vertex numbers:\($(0 \mod{n}, m \mod{n}),$ $(m \mod{n}, 2m \mod{n}),$ $(2m \mod{n}, 3m \mod{n}),$ $\dots,$ $((n-2)m \mod{n}, (n-1)m \mod{n}),$ $((n-1)m \mod{n}, 0 \mod{n}).$\)

If \($\gcd(m,n) > 1$\), then the star degenerates into a regular \($\frac{n}{\gcd(m,n)}$-gon\) or a (2-vertex) line segment if \($\frac{n}{\gcd(m,n)}= 2$\). Therefore, we need to find all $m$ such that \($\gcd(m,n) = 1$.\)

Note that \($n = 1000 = 2^{3}5^{3}.$\)

\(Let $S = \{1,2,3,\ldots, 1000\}$, and $A_{i}= \{i \in S \mid i\, \textrm{ divides }\,1000\}$. The number of $m$'s that are not relatively prime to $1000$ is: $\mid A_{2}\cup A_{5}\mid = \mid A_{2}\mid+\mid A_{5}\mid-\mid A_{2}\cap A_{5}\mid$ $= \left\lfloor \frac{1000}{2}\right\rfloor+\left\lfloor \frac{1000}{5}\right\rfloor-\left\lfloor \frac{1000}{2 \cdot 5}\right\rfloor$ $= 500+200-100 = 600.$\)

\(Vertex numbers $1$ and $n-1=999$ must be excluded as values for $m$ since otherwise a regular n-gon, instead of an n-star, is formed.\)

The cases of a 1st line segment of (0, m) and (0, n-m) give the same star. Therefore we should halve the count to get non-similar stars.

Therefore, the number of non-similar 1000-pointed stars is

\($\frac{1000-600-2}{2}= \boxed{199}.$\)

\(Note that in general, the number of $n$-pointed stars is given by $\frac{\phi(n)}{2} - 1$ (dividing by $2$ to remove the reflectional symmetry, subtracting $1$ to get rid of the $1$-step case), where $\phi(n)$ is the Euler's totient function.\) \(It is well-known that $\phi(n) = n\left(1-\frac{1}{p_1}\right)\left(1-\frac{1}{p_2}\right)\cdots \left(1-\frac{1}{p_n}\right)$, where $p_1,\,p_2,\ldots,\,p_n$ are the distinct prime factors of $n$.\) \(Thus $\phi(1000) = 1000\left(1 - \frac 12\right)\left(1 - \frac 15\right) = 400$, and the answer is $\frac{400}{2} - 1 = 199$.\)

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Answer:

1. ∠1 = 120°

2. ∠2 = 60°

3. ∠3 = 60°

4. ∠4 = 60°

5. ∠5 = 75°

6. ∠6 = 45°

Step-by-step explanation:

From the diagram, we have;

1. ∠1 and the 120° angle are corresponding angles

Corresponding angles are equal, therefore;

∠1 = 120°

2. ∠2 and the 120° angle are angles on a straight line, therefore they are supplementary angles such that we have;

∠2 + 120° = 180°

∠2 = 180° - 120° = 60°

∠2 = 60°

3. Angle ∠3 and ∠2 are vertically opposite angles

Vertically opposite angles are equal, therefore, we get;

∠3 = ∠2 = 60°

∠3 = 60°

4. Angle ∠1 and angle ∠4 an=re supplementary angles, therefore, we get;

∠1 + ∠4 = 180°

∠4 = 180° - ∠1

We have, ∠1 = 120°

∴ ∠4 = 180° - 120° = 60°

∠4 = 60°

5. let the 'x' and 'y' represent the two angles opposite angles to ∠5 and ∠6

Given that the two angles opposite angles to ∠5 and ∠6 are equal, we have;

x = y

The two angles opposite angles to ∠5 and ∠6 and the given right angle are same side interior angles and are therefore supplementary angles

∴ x + y + 90° = 180°

From x = y, we get;

y + y + 90° = 180°

2·y = 180° - 90° = 90°

y = 90°/2 = 45°

y = 45°

Therefore, we have;

∠4 + ∠5 + y = 180° (Angle sum property of a triangle)

∴ ∠5 = 180 - ∠4 - y

∠5 = 180° - 60° - 45° = 75°

∠5 = 75°

6. ∠6 and y are alternate angles, therefore;

∠6 = y = 45°

∠6 = 45°.

1. The area and perimeter of the right triangle are 48units and 96units²

2. The area and perimeter of the dilated triangle are 12units and 6 units²

Dilation is a transformation, which is used to resize the object. Dilation is used to make the objects larger or smaller.

scale factor = new dimension / old dimension

therefore the new length of the dilated triangle will be ;

12/4, 16/4, 20/4 = 3, 4,5

therefore the perimeter of the triangle = 16+20+12 = 48 units

area = 1/2 × 16× 12

= 96units²

The perimeter of the dilated triangle = 3+4+5 = 12units

area = 1/2 × 3 × 4

= 6 units²

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Answer:

Step-by-step explanation:

7x + 1 + 10x - 9 = 19x - 18

17x - 8 = 19x - 18

-2x - 8 = -18

-2x = -10

x = 5 the solution

7(5)+1= 36

10(5) - 9 = 50 - 9 = 41

19(5) - 18 = 95 - 18 = 77

The product BC does not exist because the number of columns in matrix B (2) does not match the number of rows in matrix C (6).

For matrix multiplication to be possible, the number of columns in the first matrix must equal the number of rows in the second matrix.

To determine if the product BC exists, we need to check if the number of columns in matrix B matches the number of rows in matrix C. In this case, matrix B has 2 columns and matrix C has 6 rows.

In matrix multiplication, the number of columns in the first matrix must equal the number of rows in the second matrix. If this condition is not met, the product of the two matrices does not exist.

Since the number of columns in B (2) does not match the number of rows in C (6), the product BC cannot be calculated.

In matrix notation, the product BC is defined as:

BC = [b₁₁ b₁₂] * [c₁₁ c₁₂ c₁₃ c₁₄ c₁₅ c₁₆]

              [b₂₁ b₂₂]

To perform the multiplication, we would need to take the dot product of each row of matrix B with each column of matrix C. However, since the dimensions do not match, the multiplication cannot be carried out.

Therefore, the product BC does not exist.

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Answer:

dddddddddddddddddd

Step-by-step explanation:

dddd

Answerim sorry the answer is actually c

Step-by-step explanation:

Answer:

860.2

Step-by-step explanation:

880 x 0.15 = 132

880 - 132 = 748

748 x 0.15 = 112.2

748 + 112.2 = 860.2

Answer:

Domain: [0, 12.75]

Range: [0, 590.9]

Step-by-step explanation:

Your function is missing variables.

I think you mean

h(t) = -4.922t^2 + 17.69t + 575

as the function.

We can find the time the object hits the ground. At that time, h(t) = 0, so we set the equation equal to zero and solve for t.

-4.922t^2 + 17.69t + 575 = 0

\( t = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)

\( t = \dfrac{-17.69 \pm \sqrt{(-17.69)^2 - 4(-4.922)(575)}}{2(-4.922)} \)

\( t = \dfrac{-17.69 \pm \sqrt{11633.54}}{-9.844} \)

t = -9.16 s or t = 12.75 s

According to the parabola that is the path of the falling object, the object is at zero height at t = -9.16 s and t = 12.75 s. Since the object starts moving at time t = 0, the domain has to be limited to t = 0 till t = 12.75 s.

Domain: [0, 12.75]

The range is the height of the object. Maximum height occurs at the time that is the midpoint of the two times the parabola shows h(t) = 0.

tmax = (-9.16 + 12.75)/2 = 1.797

Now we use the time of maximum height to find the maximum height.

h(t) = -4.922t^2 + 17.69t + 575

h(tmax) = -4.922(1.797)^2 + 17.69(1.797) + 575

h(tmax) = 590.9

The maximum height is 590.9 m.

Range: [0, 590.9]

The probability that you deal the 7 of Spades followed by a King is 0.1.

Given is that you randomly shuffle a deck of cards and deal two cards from the top.

We can write the probability as -

P{E} = 1/52 + 4/51

P{E} = 0.02 + 0.08

P{E} = 0.1

Therefore, the probability that you deal the 7 of Spades followed by a King is 0.1.

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Answer:

4

Step-by-step explanation:

it is how many more

Option D. The numbers are 20 and 0.

Let the two nonnegative numbers be x and y such that x + y = 20. We know that the sum of the squares of the two nonnegative numbers x and y is as large as possible and as small as possible.

x + y = 20, or y = 20 - x (Since the numbers are non-negative, x, y ≥ 0)

Substituting y = 20 - x into x² + y² = P (for the sake of simplicity), we get x² + (20 - x)² = Px² + 400 - 40x + x² = P

We will take the first derivative with respect to x now: 2x - 40 = 0x = 20

Therefore, one of the nonnegative numbers is 20, and the other is zero. Consequently, the smallest possible sum of squares is 400 (since 20² + 0² = 400).Option D. The numbers are 20 and 0.

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Given, the sum of two nonnegative numbers is 20.

The problem asks us to find the numbers if the sum of their squares is as large as possible; as small as possible.

Therefore, let's find the sum of their squares at first.If 'x' and 'y' are two numbers, then the sum of their squares is given by:

\(x^2 + y^2\)

If the sum of two nonnegative numbers is 20, then one number can be written as x and the other number can be written as y in terms of x.

Thus,y = 20 − xNow, the sum of their squares:

\(x^2 + y^2 = x^2 + (20 - x)^2\)
= \(x^2 + 400 + x^2 - 40x\)
= \(2x^2 - 40x + 400\)
The above expression represents a parabola which opens upward because the coefficient of x^2 is positive.

Therefore, the sum of the squares of the two numbers will be maximum at the vertex of the parabola.

The x-coordinate of the vertex can be found as

:−b/2a = −(−40)/(2.2) = 10Hence, x = 10 and y = 10.

Substituting x = 10 and y = 10, we get

\(x^2 + y^2 = 200.\)

Now, to find the smallest value of the sum of their squares, we can observe that the smallest value of x is 0, and the largest value of y is 20.

Thus, if x = 0 and y = 20, we get x^2 + y^2 = 400.

Answer:  The numbers are 10 and 10. The numbers are 0 and 20.

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Given f(x) = 3x² - 2 and g(x) = 6 - a(a) (fog)(4)To find (fog)(4)

let us first find g(4),g(4) = 6 - a

Now we will calculate f(g(4)) = f(6 - a)f(6 - a) = 3(6 - a)² - 2= 3(36 - 12a + a²) - 2= 108 - 36a + 3a² - 2= 3a² - 36a + 106

Therefore (fog)(4) = 3a² - 36a + 106(b) (gof)(2)

To find (gof)(2) we need to find f(2) and then find g(f(2))f(2) = 3(2)² - 2= 12g(f(2)) = g(12)= 6 - a

Therefore (gof)(2) = 6 - a(c) (fof)(1)

To find (fof)(1) we need to find f(1) and then find f(f(1))f(1) = 3(1)² - 2= 1f(f(1)) = f(1)= 3(1)² - 2= 1

Therefore (fof)(1) = 1(d) (gog)(0)

To find (gog)(0) let us first find g(0),g(0) = 6 - 0= 6

Now we will calculate g(g(0)) = g(6)= 6 - a

Therefore (gog)(0) = 6 - a

Answer: (a) (fog)(4) = 3a² - 36a + 106(b) (gof)(2) = 6 - a(c) (fof)(1) = 1(d) (gog)(0) = 6 - a.

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