Consider the AIRLINE relational database schema shown in Figure 1, which describes a database for airline flight information. Each FLIGHT is identified by a Flight_number, and consists of one or more FLIGHT_LEGs with Leg_numbers 1, 2, 3, and so on. Each FLIGHT_LEG has scheduled arrival and departure times, airports, and one or more LEG_INSTANCEs-one for each Date on which the flight travels. FAREs are kept for each FLIGHT. For each FLIGHT_LEG instance, SEAT_RESERVATIONs are kept, as are the AIRPLANE used on the leg and the actual arrival and departure times and airports. An AIRPLANE is identified by an Airplane_id and is of a particular AIRPLANE_TYPE. CAN_LAND relates AIRPLANE_TYPEs to the AIRPORTs at which they can land. An AIRPORT is identified by an Airport_code. Consider an update for the AIRLINE database to enter a reservation on a particular flight or flight leg on a given date.

Answer:

Your cat may also be a risk of a taurine deficiency if he or she enjoys sampling your dog's food. Dog food doesn't contain taurine, as dogs can create their own supply of the amino acid. Although your cat may like the taste, a steady diet of dog food is a bad idea

hope this helps

these categories

THE NATURE OF MATERIALS

Review Questions

2.1

The elements listed in the Periodic Table can be divided into three categories. What are these categories and give an example of each?

Answer

. The three types of elements are metals (e.g., aluminum), nonmetals (e.g., oxygen), and semimetals

Bondtite Wood Adhesives is the best glue for pasting Acrylic Sheet to any wooden surface like Plywood , MDF, or WPC.

1. Make sure both surfaces are clear of dirt and other impurities (Oil, grease, dust, etc.).

2. Using a spreader, evenly apply Bondtite Acrylicfix on the plywood (base surface). Let the surface 8 to 10 minutes to dry.

3. Use a wet cloth to rub the acrylic sheet's backside on the second surface. Make sure there are no water droplets on the area that the adhesive will be sticking to. Avoid rubbing with wet towel during the rainy season.

4. To ensure a strong binding, bring the two surfaces together and apply uniform pressure using a roller, press machine, or dry cloth.

5. Use clamps, nails, tape, etc. to firmly hold the bonded surface together. Handling Strength can be attained in two to four hours.

Learn more about wood adhesive here:

https://brainly.com/question/15174119

#SPJ4

Answer:

c

Explanation:

:)

The annual quantity of welded assemblies that would have to be produced to reach the break-even point for the two methods is approximately 15,983.

To determine the break-even point between the manual arc welding cell and the robotic cell, we need to calculate the total costs for each method and then equate them.

For the manual arc welding cell:

Labor cost per hour = (welder's hourly rate x arc-on time) + (fitter's hourly rate x fitter's participation in the cycle) = ($30 x 0.25) + ($25 x 0.3) = $11.25

Labor cost per welded assembly = labor cost per hour x cycle time per assembly / 60 = $11.25 x 15.4 / 60 = $2.89

Overhead cost per welded assembly = (labor cost per hour x (1 - arc-on time - fitter's participation in the cycle)) x cycle time per assembly / 60 = ($30 x 0.45) x 15.4 / 60 = $4.68

Total cost per welded assembly = labor cost per welded assembly + overhead cost per welded assembly = $2.89 + $4.68 = $7.57

Total cost per hour = total cost per welded assembly x production rate = $7.57 x 8 = $60.56

Total cost per year = total cost per hour x hours of operation per year = $60.56 x 2,000 = $121,120

For the robotic arc welding cell:

Labor cost per hour = fitter's hourly rate x fitter's participation in the cycle = $25 x 0.62 = $15.50

Labor cost per welded assembly = labor cost per hour x cycle time per assembly / 60 = $15.50 x 15.4 / 60 = $3.97

Overhead cost per welded assembly = power and utility cost per hour + annual maintenance cost / production rate = $3.80 + $3,500 / (8 x 2,000) = $3.80 + $0.22 = $4.02

Total cost per welded assembly = labor cost per welded assembly + overhead cost per welded assembly + (installed cost / (production rate x service life)) = $3.97 + $4.02 + ($158,000 / (8 x 3)) = $3.97 + $4.02 + $6,208.33 = $14.19

Total cost per hour = total cost per welded assembly x production rate = $14.19 x 8 = $113.52

Total cost per year = total cost per hour x hours of operation per year = $113.52 x 2,000 = $227,040

To find the break-even point, we set the total cost of the manual arc welding cell equal to the total cost of the robotic arc welding cell and solve for the annual quantity of welded assemblies:

$121,120 + x($7.57) = $227,040 + x($14.19)

$7.57x - $14.19x = $227,040 - $121,120

$-6.62x = $105,920

x = $105,920 / $6.62

x = 15,982.7

Therefore, the annual quantity of welded assemblies that would have to be produced to reach the break-even point for the two methods is approximately 15,983.

Learn more about hourly rate here https://brainly.com/question/29335545

#SPJ4

The decrease in air pressure caused by friction between the air moving through a duct and the internal surfaces of the duct (p403) is a description of a static pressure drop.

How can we describe p403?

The description on p. 403 is of the static pressure drop caused by friction between the air moving through a duct and the internal surfaces of the duct.

This can be measured using instruments such as an inclined manometer or a U-tube manometer and is taken into account when using an equal friction chart to design duct systems.

to know more about friction:

https://brainly.com/question/28356847

#SPJ11

Answer:

To document your work and projects.

Explanation:

I hope I got the right meaning. :)

When thrust faults occur, the region undergoing stress is subject to compression stress.

Compressive stress is a force that causes a substance to deform in order to take up less space.

When thrust faults occur, the region undergoing stress is subject to compression stress. A substance is said to be under compression when it is subjected to compressive stress.

Learn more about Compressive Stress:

https://brainly.com/question/24227487

#SPJ1

The short notes on Design, operation and maintenance of hydraulic structures are given below.

Weirs are hydraulic structures used to measure or control water flow. The design of a weir depends on the flow rate, channel geometry, and hydraulic head. The operation and maintenance of weirs involve regular inspection, cleaning, and repair of any damage to ensure accurate flow measurement and control.

Canals are artificial waterways used for irrigation, navigation, and hydroelectric power generation. The design of canals involves determining the required discharge, channel geometry, and alignment. Canals require regular maintenance to prevent erosion, sedimentation, and vegetation growth, including dredging and bank stabilization.

Spillways are structures used to safely release excess water from a dam or reservoir. The design of spillways includes determining the required discharge capacity and selecting an appropriate type, such as an overflow, gated, or labyrinth spillway. Spillways require regular maintenance, including cleaning and repair of any damage.

Aqueducts are structures used to transport water over long distances, typically from a water source to a population center or irrigation system. The design of aqueducts involves determining the required flow rate, elevation changes, and material selection. Aqueducts require regular maintenance, including cleaning and repair of any damage.

Stilling basins are hydraulic structures used to dissipate the energy of rapidly flowing water, such as at the outlet of a spillway. The design of a stilling basin involves determining the required depth, length, and energy dissipation capacity. Maintenance of stilling basins involves regular inspection, cleaning, and repair of any damage.

Learn more about Hydraulic Structures:
https://brainly.com/question/5637653
#SPJ1

a. The farthest horizontal distance the jet will strike the ground is calculated using the formula:

D = √[(2gh)/C], where g = 9.81 m/s² is the acceleration due to gravity and C = 0.9 is the coefficient of discharge.

By substituting h = 4 - H (where H is the depth of water above the orifice) and d = 1.5 m into the formula, we can find:

D = √[(2g(4 - H))/C].

Therefore, the farthest horizontal distance the jet will strike the ground is given by:

D = √[(2 × 9.81 × 4)/0.9] = 8.22 meters (rounded off to 2 decimal places).

b. To find the value of "h" for the jet to strike the farthest point on the ground, we can use the formula:

D = √[(2gh)/C], where g = 9.81 m/s² is the acceleration due to gravity and C = 0.9 is the coefficient of discharge.

By substituting d = 8.22 meters and solving for H, we get:

H = 4 - (D²C/2g) = 4 - (8.22² × 0.9/(2 × 9.81)) = 0.653 meters (rounded off to 3 decimal places).

Therefore, the value of "h" for the jet to strike the farthest point on the ground is 4 - 0.653 = 3.347 meters (rounded off to 3 decimal places).

c. The velocity of the water as it goes out of the orifice for it to strike the farthest point on the ground can be calculated using the formula:

V = √[2gh].

By substituting d = 8.22 meters and h = 3.347 meters into the formula, we can find:

V = √[2g × 3.347] = 6.514 meters/second (rounded off to 3 decimal places).

The velocity of the water as it goes out of the orifice for it to strike the farthest point on the ground is 6.514 m/s.

To know more about velocity visit:

https://brainly.com/question/30559316

#SPJ11

Answer:

The answer is A

Explanation:

The correct answer is A

Answer:

b

Explanation:

Answer:

b

Explanation:

Answer:

they are used for electrical currents so that they can flow along the appropriate wires in the circuit

Explanation:

To ensure safety and reliable electrical connections, polarized electrical receptacles are employed.

It is frequently seen in both residential and commercial structures and has two slots, one of which is broader than the other.

In a polarised outlet, the neutral slot is broader than the hot slot, which is smaller. To ensure that electrical appliances or gadgets are connected correctly and consistently, this design was created.

By ensuring a steady flow of energy through the instrument, polarization lowers the chance of electric shock.

Thus, it's crucial to remember that not all electrical appliances need polarized plugs.

For more details regarding polarization, visit:

https://brainly.com/question/2264548

#SPJ6

Answer:

Explanation:

It appears that you are trying to solve a problem involving an insulated rigid tank containing saturated liquid water and water vapor. To determine the volume of the tank, you will need to know the mass of the liquid water and the mass of the water vapor. The mass of the liquid water can be calculated by multiplying the mass of the water and vapor mixture by the fraction of the mixture that is liquid water (1.4 kg * 0.25 = 0.35 kg). The mass of the water vapor can be calculated by subtracting the mass of the liquid water from the total mass of the mixture (1.4 kg - 0.35 kg = 1.05 kg).

To determine the final temperature of the tank, you will need to know the amount of heat added to the tank by the electric resistor and the specific heat capacity of the water and water vapor mixture. The specific heat capacity is a measure of the amount of heat required to raise the temperature of a substance by a certain amount. The specific heat capacity of water is 4.186 J/g°C, and the specific heat capacity of water vapor is 2.080 J/g°C.

To determine the electric power rating of the resistor, you will need to know the amount of heat added to the tank by the resistor and the time over which the heat was added. The power rating of the resistor is equal to the amount of heat added to the tank divided by the time over which the heat was added.

I hope this helps clarify the problem and provide some guidance on how to solve it. If you have any further questions or need additional help, please don't hesitate to ask.

Answer:

Configuration Management Process

Software functionality

Explanation:

Two important criteria that should be evaluated to determine the "maturity" of a software product include____

Answer:

25 mins into hours = 0.416667 hours

25 inches as mm = 635

Explanation:

Answer:

P1+1/2pv2/1+pgh1=P2+1/2pv2/2+pgh2

Answer:

tires

Explanation:

without tyres you can not drive.

Answer:

d spurving bearings

Explanation:

because IN a car you can't move without them.in the old days they were using wood as tires

The family should accept a minimum of Kshs.42,250,000.00 to avoid incurring a loss.

To obtain the total cost, the expenses for the land, trees and upkeep are summed up and subsequently reduced by 6. 5% using a discount rate.

Hence, it can be seen that a forced acquisition appraisal primarily focuses on three key factors: the land's market value, the expenses involved in replacing the property, and the potential harm caused to the owner's belongings.

Read more about yield rate here:

https://brainly.com/question/457082

#SPJ1

Answer:

2/4

7/2

92/1

83/1

9/1

93/0

Explanation:

R

K

K

R

K

R

I don't really know the answer

Answer:

a rock is made up of two or more minerals but a mineral is a natural substance with chemical and physical properties

Answer:

The dimension of the  square cross section is = 30mm * 30mm

Explanation:

Before proceeding with the calculations convert MPa to Kpsi

Sut ( ultimate strength ) = 770 MPa * 0.145 Kpsi/MPa = 111.65 Kpsi

the fatigue strength factor of Sut at 10^3 cycles for Se = Se' = 0.5 Sut

at 10^6 cycles" for 111.65 Kpsi  = f ( fatigue strength factor) = 0.83

To calculate the endurance limit  use  Se' = 0.5 Sut      since Sut < 1400 MPa

Se'( endurance limit ) = 0.5 * 770 = 385 Mpa

The surface condition modification factor

Ka = 57.7 ( Sut )^-0.718

Ka = 57.7 ( 770 ) ^-0.718

Ka = 0.488

Assuming the size modification factor (Kb) = 0.85 and also assuming all modifiers are equal to one

The endurance limit at the critical location of a machine part can be expressed as :

Se = Ka*Kb*Se'

Se = 0.488 * 0.85 * 385 = 160 MPa

Next:

Calculating the constants to find the number of cycles

α = \(\frac{(fSut)^2}{Se}\)

α =\(\frac{(0.83*770)^2}{160}\)  =  2553 MPa

b = \(-\frac{1}{3} log(\frac{fSut}{Se} )\)

b = \(-\frac{1}{3} log (\frac{0.83*770}{160} )\)  = -0.2005

Next :

calculating the fatigue strength using the relation

Sf = αN^b

N = number of cycles

Sf = 2553 ( 10^4) ^ -0.2005

Sf = 403 MPa

Calculate the maximum moment of the beam

M = 2000 * 0.6 = 1200 N-m

calculating the maximum stress in the beam

∝ = ∝max = \(\frac{Mc}{I}\)

Where c = b/2 and   I = b(b^3) / 12

hence ∝max = \(\frac{6M}{b^3}\)  =  6(1200) / b^3   =  7200/ b^3   Pa

note: b is in (meters)

The expression for the factor of safety is written as

n = \(\frac{Sf}{\alpha max }\)

Sf = 403, n = 1.5 and ∝max = 7200 / b^3

= 1.5 = \(\frac{403(10^6 Pa/Mpa)}{7200 / B^3}\)   making b subject of the formula in other to get the value of b

b = 0.0299 m * 10^3 mm/m

b = 29.9 mm therefore b ≈ 30 mm

since  the size factor  assumed is near the calculated size factor using this relation : de = 0.808 ( hb)^1/2

the dimension = 30 mm by 30 mm

A type of heating and air conditioning system that relies only on heated or cooled water to adjust the air temperature is known as a hydronic system.

To learn more about glycol  refer to:

https://brainly.com/question/11994953

#SPJ1

Answer:

Both Technicians A and B  are correct

Explanation:

If the fluid pressure will decrease quickly in a car when the ignition says that one or more has been switched off. One or two could be leaking or the source could be a faulty check mechanism in the catalytic converter.

Here's a function called Close Enough which takes a const reference to a vector of strings and an int. This function is used to check if there are two adjacent strings in a list that are very similar to each other by determining the number of characters that can be different between any two strings next to each other.

The function starts by iterating through the vector of strings from the first to the second to last string. For each string, it then counts the number of differences between it and the next string by comparing the characters at each position.

If the number of differences is less than or equal to the given integer n, the function returns the index of the current string. If there is no such index, the function returns -1.

To know more about vector visit:

https://brainly.com/question/24256726

#SPJ11