Consider that the SNR in dB is equal to 30 dB, what is the actual SNR value (not in dB) then the value is 1000.
What is SNR?It is defined as the ratio of signal power to noise power, often expressed in decibels. A ratio greater than 1:1 (greater than 0 dB) indicates more signal than noise.
Consider that the SNR in dB is equal to 30 dB, is the actual SNR value (not in dB) is 1000.
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PART OF WRITTEN EXAMINATION:
Anode beds are usually filled with what substance?
A) coke breeze
B) sawdust
C) earth
D) steel
Anode beds are usually filled with coke breeze, which is a byproduct of coal. Coke breeze is a substance that is used as a bed material in many electrochemical processes. This substance is made up of fine particles of coke, which are produced during the process of manufacturing coke from coal.
Coke breeze is used as a bed material in anode beds because it has several properties that make it ideal for this purpose.
Firstly, coke breeze is a good electrical conductor, which means that it can carry the electrical current that is needed for the electrochemical process. Secondly, it has a high porosity, which allows for good gas flow and distribution. Finally, it is chemically stable, which means that it will not react with the substances that are being processed in the anode bed.
In conclusion, anode beds are usually filled with coke breeze, which is a substance that has several properties that make it ideal for use as a bed material. Its good electrical conductivity, high porosity, and chemical stability make it the perfect substance for carrying out electrochemical processes.
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Your new team is working hard, but they are all less experienced than you and don't complete their tasks as quickly.What would you be most and least likely to do? (A). Reach out to your manager to discuss the situation.Try to identify the best way to support the new associates. (B).Remind your coworkers of performance expectations and that they need to be working harder to complete tasks. (C). Offer to help others complete their tasks; observe their work process and provide some tips that might help them. (D). Give your coworkers more time to figure out how to do the task; they likely just need more practice with what they've already learned.
seqeuning rule that will minimze average job completion timef or a set number of jobs to be procesed on one machine is
A sequencing rule that minimizes the average job completion time for a set number of jobs to be processed on one machine is crucial in ensuring efficient and effective production processes.
One such rule is the Shortest Processing Time (SPT) rule, which involves scheduling jobs based on their processing times, with the shortest job being processed first. This rule is effective in reducing the average job completion time as it minimizes the amount of time jobs spend waiting in the queue.
Another sequencing rule that can be used is the First-Come-First-Served (FCFS) rule, which schedules jobs in the order in which they arrive at the machine. However, this rule may not necessarily minimize the average job completion time as it does not take into account the processing times of the jobs.
The Earliest Due Date (EDD) rule is also another sequencing rule that can be used to minimize the average job completion time. This rule prioritizes jobs based on their due dates, with jobs that have earlier due dates being processed first. This rule is effective in ensuring that jobs are completed on time, but may not necessarily minimize the average job completion time.
In conclusion, selecting the appropriate sequencing rule is essential in ensuring that jobs are processed efficiently and effectively. The Shortest Processing Time (SPT) rule is a highly effective sequencing rule that minimizes the average job completion time. However, depending on the specific needs and requirements of the production process, other sequencing rules such as the First-Come-First-Served (FCFS) rule and the Earliest Due Date (EDD) rule may also be appropriate.
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Which characteristic would atoms of a ferromagnetic material have?A. A lack of electrons B. North and south poles C. A temporary magnetic field D. The ability to attract nonmagnetic materials
Answer:
Option B
Explanation:
Atoms of ferromagnetic materials have north and south pole but these atoms are oriented in random directions due to which they do no exhibit magnetic properties until unless they are brought into influence of any external temporary or permanent magnetic field.
Under the influence of external magnetic force, the atoms of the ferromagnetic material get oriented in a particular direction.
Hence, option B is correct
Which is a method of social engineering that could be used to deliver ransomware?.
The method of social engineering that could be used to deliver ransomware is; email phishing
What are methods of Social engineering?Ransomware is simply a type of social engineering that criminals use to steal data, infect computers, and infiltrate company networks.
Now, the most popular form of social engineering that could be used to deliver ransomware is email phishing. This is because email Phishing has become more pervasive and dangerous these days as it is used when attackers/criminals send fraudulent emails that either contain dangerous links or exploitative requests.
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What is in a catalytic converter that makes it so expensive?.
Answer:
A catalytic converter is expensive because it needs rhodium to reduce smog levels. Rhodium, at its current value, is extremely expensive which makes using it in a catalytic converter expensive. To make up for their cost, manufacturers have to increase the price of the catalytic converter.
Explanation:
In an occupied space, I have a 100 fluorescent luminaires. All luminaires are 277V single-phase 2’ x 2’ 2-bulb units, with a ballast dedicated to each bulb. The ballast and bulb combination use a combined 30 watts (25 for the lamp and 5 wasted as heat by the ballast) of power during operation.
a. In my space, 20% of my lights are designated as exit lighting. An exit luminaire keeps both bulbs on 100% of the time to provide a minimum level of illumination to move around the building. How much power am I using a year to keep these luminaires on?
b. A further 10% (apart from the exit lighting) of the total luminaires are used as egress lighting. These luminaires have a separate battery pack attached to a single ballast and bulb combination which provides illumination in the event of a total power outage. How much power do the battery packs need to provide during a power outage. If the lights must be kept on for 90 minutes after a power outage, how much energy to the battery packs need to supply during this period?
c. I want to install these same fixtures above a public, indoor swimming pool. What special considerations do I need to keep in mind to install these luminaires in this location? Cite your reasons.
a. Exit lighting power: 525.6 kWh/year (20% of 100 luminaires).
b. Egress lighting battery power: 0.45 kWh for 90 minutes.
c. Pool lighting considerations: Waterproof fixtures, safety compliance, proper mounting, electrical safety, maintenance.
a. To calculate the power used per year to keep the exit luminaires on:
Total number of luminaires: 10020% of luminaires designated as exit lighting: 20 luminairesPower consumption per luminaire: 30 watts (25 watts for the lamp + 5 watts wasted as heat by the ballast)Total power consumed by exit luminaires per year: 20 luminaires * 30 watts * 24 hours * 365 days = 525,600 watt-hours or 525.6 kilowatt-hours (kWh)b. To calculate the power needed by battery packs during a power outage:
Total number of luminaires: 10010% of luminaires used as egress lighting: 10 luminairesPower consumption per luminaire during power outage: 30 watts (25 watts for the lamp + 5 watts wasted as heat by the ballast)Energy needed during a power outage: 30 watts * 10 luminaires * 1.5 hours (90 minutes) = 450 watt-hours or 0.45 kilowatt-hours (kWh)c. Special considerations for installing luminaires above a public indoor swimming pool:
Waterproof and corrosion-resistant luminaires: Due to the presence of moisture and humidity in the pool area, the luminaires should be specifically designed to be waterproof and resistant to corrosion.Compliance with safety regulations: The luminaires need to meet safety standards and regulations for installation in wet locations. These standards may include proper grounding, insulation, and protection against water ingress.Proper mounting height: Luminaires should be mounted at an appropriate height to avoid direct contact with pool water and ensure sufficient illumination without causing glare or obstruction.Electrical safety measures: Electrical connections and wiring should be installed following appropriate safety guidelines to prevent electrical hazards in a wet environment.Maintenance and cleaning: Regular maintenance and cleaning of luminaires are necessary to ensure their performance and longevity in the challenging pool environment.These considerations are important to ensure the safety, durability, and proper functioning of the luminaires in a public indoor swimming pool setting.
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A simple voltage regulator is shown in the figure below (Figure 1) . The source voltage Vs varies from 8.3 to 11.7 V , and the load current iL varies from 50 to 160 mA . Assume that the Zener diode is ideal. Determine the largest value allowed for the resistance Rs so that the load voltage vL remains constant with variations in load current and source voltage.
The largest value allowed for the resistance Rs for the simple voltage regulator is 2.75 Ω.
How to calculate the valueFrom the information, the source voltage Vs varies from 8.3 to 11.7 V , and the load current iL varies from 50 to 160 mA .
The Zener diode has a fixed voltage drop of 5.1 V. The minimum load voltage is therefore 5.1 V, and the maximum load voltage is 10.6 V. The load current varies from 50 to 160 mA, so the maximum current through the resistor is 160 mA.
The largest value allowed for the resistance Rs is therefore
Rs = (Vmax - Vmin) / Imax
= (10.6 V - 5.1 V) / 160 mA
= 2.75 Ω
Therefore, the largest value allowed for the resistance Rs is 2.75 Ω.
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A contractor excavates 10,000 m3 soil at moist unit weight of 17.5 kN/m3 and moisture content of 10% from a borrow pit and transports it to a project site. The project has an area of 20,000 m2 to be filled with this compacted soil. If the required dry unit weight and moisture content of the compacted soil are 18.3 kN/m3 and 12.5% (assume there is no soil loss during transportation and compaction), what is the thickness of the compacted soil and how much water needs to be added?
Answer:
Part A
The thickness of the compacted soil is approximately 4.3467 × 10⁻¹ m
Part B
The weight of water to be added is approximately 19886.\(\overline{36}\) kN, the volume of the water added is approximately 2,027.77 m³
Explanation:
The parameters of the soil are;
The volume of sol the excavator excavates, \(V_T\) = 10,000 m³
The moist unit weight, W = 17.5 kN/m³
The moisture content = 10%
The area of the project, A = 20,000 m²
The required dry unit weight = 18.3 kN/m³
The required moisture content = 12.5%
Part A
Therefore, we have;
The moist unit weight = Unit weight = (\(W_s\) + \(W_w\))/\(V_T\)
The moisture content, MC = 10% = (\(W_w\)/\(W_s\)) × 100
∴ \(W_w\) = 0.1·\(W_s\)
∴ The moist unit weight = 17.5 kN/m³ = (\(W_s\) + 0.1·\(W_s\))/(10,000 m³)
1.1·\(W_s\) = 10,000 m³ × 17.5 kN/m³ = 175,000 kN
\(W_s\) = 175,000 kN/1.1 = 159,090.\(\overline{09}\) kN
For the required soil, we have;
The required dry unit weight = 18.3 kN/m³ = \(W_s\)/\(V_T\) = 159,090.\(\overline{09}\) kN/\(V_T\)
\(V_T\) = 159,090.\(\overline{09}\) kN/(18.3 kN/m³) ≈ 8,693.4923 m³
The total volume of the required soil ≈ 8,693.4923 m³
Volume \(V_T\) = Area, A × Thickness, d
∴ d = \(V_T\)/A
d = 8,693.4923 m³/(20,000 m²) ≈ 4.3467 × 10⁻¹ m
The thickness of the compacted soil ≈ 4.3467 × 10⁻¹ m
Part A
The moisture content, MC = 12.5% = (\(W_w\)/\(W_s\)) × 100
\(W_w\) = \(W_s\) × MC/100 = 159,090.\(\overline{09}\) kN × 12.5/100 = 19886.\(\overline{36}\) kN
The weight of water to be added, \(W_w\) = 19886.\(\overline{36}\) kN
Where the density of water, ρ = 9.807 kN/m³
Therefore, we have;
The volume of water, V = \(W_w\)/ρ
∴ V = 19886.\(\overline{36}\) kN/(9.807 kN/m³) ≈ 2027.77 m³
The volume of water, V ≈ 2027.77 m³
In what way do the 2-4-12 second visual leads apply?
The 2-4-12 second visual leads explain the time duration for delivering vital information in a movie or presentation, with 2 seconds for attention-getting, 4 seconds for the main message, and 12 seconds for details.
What are the visual leads at two, four, and twelve seconds?These three "lead times" are conceivable. the 4-second immediate path, the 12-second predicted path, and the 2-second following distance. The 2-second following distance serves as the beginning lead-time. When everything is perfect, that distance is regarded as the minimum.
The 12 second rule is what?To avoid colliding with such things, the Department of Motor Vehicles recommends all motorists to adhere to a single regulation. It advises motorists to scan the road at least 12 seconds in advance.
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Today is Cora's 60th birthday and she is retiring today. Her pension manager informs her that she could choose between two options. The first option is to receive a cash amount of P40,000 every month beginning in one month until her 100 th birthday. If she dies before that date, her chosen beneficiary will receive the monthly cash flows. The second option is to receive a lump sum equal to the present value of all the monthly cash flows specified in the first option with a rate of 12% compounded monthly as the discount rate. If Cora goes for the second option, how much will she receive? Did Cora make the right decision? Why? Why not?
The decision depends on Cora's financial circumstances, preferences, and future plans. we find that Cora would receive approximately P1,586,665.11 as a lump sum if she chooses the second option.
To calculate the lump sum amount Cora would receive if she chooses the second option, we need to find the present value of the monthly cash flows specified in the first option.
The cash flow of P40,000 occurs every month from Cora's 61st birthday until her 100th birthday, which is a total of 100 - 61 + 1 = 40 years or 480 months.
Using the formula for the present value of an ordinary annuity, the lump sum amount (L) can be calculated as:
L = C * [1 - (1 + r)^(-n)] / r
Where:
C = Cash flow per period = P40,000
r = Interest rate per period = 12% compounded monthly = 12%/12 = 1% = 0.01
n = Total number of periods = 480
Plugging in the values:
L = P40,000 * [1 - (1 + 0.01)^(-480)] / 0.01
Calculating this expression, we find that Cora would receive approximately P1,586,665.11 as a lump sum if she chooses the second option.
Now, whether Cora made the right decision depends on her personal financial goals, risk tolerance, and expected lifespan.
If Cora believes that she can invest the lump sum amount and achieve a higher rate of return than the 12% interest rate used for discounting, then taking the lump sum may be advantageous. She can potentially earn more through wise investment choices.
On the other hand, if Cora prefers the stability and security of guaranteed monthly income until her 100th birthday, and if she is uncertain about her ability to invest and manage the data of lump sum effectively, then choosing the first option of receiving monthly cash flows may be more suitable.
Ultimately, the decision depends on Cora's financial circumstances, preferences, and future plans.
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A heat engine with a thermal efficiency of 25% is connected to an electric generator with an efficiency of 95%. A liquid fuel providing heat is consumed at 2.29 litres per hour. What is the power output in kW from the generator?
Heat of Combustion: 43.7 MJ/kg
Density of the fuel: 0.749 g/ml
Answer:
4.94 kW
Explanation:
The heat energy produced by the fuel in one hour is ...
(2.29 L/h)(0.749 kg/L)(43.7 MJ/kg) = 74.954677 MJ/h
Then the power output is ...
(74.954677 MJ/h)(1 h)/(3600 s) = 20.8207 kJ/s
Multiplying this heat energy by the efficiencies of the processes involved, the output power is ...
(20.8207 kW)(0.25)(0.95) = 4.94 kW
Complete the following sentence.
Students who have excellent _______ skills and creativity might find engineering a promising career choice.
Answer:
Listening
Explanation:
Mom said it was right ¯\_(ツ)_/¯
Answer:
Listening
Explanation:
A noisy transmission channel has a per-digit error probability p = 0.01.
(a) Calculate the probability of more than one error in 10 received digits?
Answer:
The appropriate answer is "0.0043".
Explanation:
The given values is:
Error probability,
p = 0.01
Received digits,
n = 10
and,
\(x\sim Binomial\)
As we know,
⇒ \(P(x)=\binom{n}{x}p^xq^{n-x}\)
Now,
⇒ \(P(x >1) =1- \left \{ P(x=0)+P(x=1) \right \}\)
⇒ \(=1-\left \{\binom{10}{0}(0.01)^0(0.99)^{10-0}+\binom{10}{0}(0.01)^1(0.99)^{10-1} \right \}\)
⇒ \(=1-0.9957\)
⇒ \(=0.0043\)
Define hermetic compressor
Answer:
Hermetic compressors are ideal for small refrigeration systems, where continuous maintenance cannot be ensured.
Would you expect the correlation between High School GPA and College GPA to be higher when taken from your entire high school class or when taken from only the top 20 students? Why?
Answer:
Even though it has been found that there is a correlation between the specific high school a student attends and their college graduation rate, there is a much stronger correlation between a student's high school GPA, regardless of what high school they attended, and that student completing college.
Explanation:
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What is a radio wave made up of? Molecules? Electrons? Other?
Radio waves are radiated by charged particles when they are accelerated. They are produced artificially by time-varying electric currents, consisting of electrons flowing back and forth in a specially-shaped metal conductor called an antenna. ... Radio waves are received by another antenna attached to a radio receiver.
Answer: Wave Currents??
WIDE OPEN GUESS
2. a wheel tractor-scraper is operating on a level grade. assume no power derating is required for equipment condition, altitude, and temperature. use equipment data from figure 6.10. a) disregarding traction limitations, what is the maximum value of rolling resistance (in lb/ton) over which the fully loaded unit can maintain a speed of 15 mph? b) what minimum value of coefficient of traction between the tractor wheels and the traveling surface is needed to satisfy the requirements of part a? for the fully loaded condition, 52% of the weight is distributed to the drive axle. the operating weight of the empty scraper is 74,946 lb.
We can see here that the maximum value of rolling resistance over which a loaded scraper can maintain is: 780 lb/ton
What is a maximum rolling resistance?Rolling resistance is the force that resists the motion of a rolling object on a surface. Maximum rolling resistance refers to the highest level of resistance that an object can encounter while rolling on a particular surface.
For a fully loaded condition:
15mph speed, 52% resistanceGrade resistance = 0%The total resistance = (gross + rolling) resistance
52% = 0% - rolling resistance
rolling resistance = 52%
The maximum rolling resistance = rolling resistance percentage × speed
The maximum rolling resistance = 52% (15 lb/ton)/(1% resistance)
The maximum rolling resistance = 780 lb/ton
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in a machine shop, two camshafts are made: one of aluminum (al), one of iron (fe). if they both have the same mass, which is larger?
aluminum (Al)
Aluminum has an atomic mass of 26.98
Iron has an atomic mass of 55.85
If both have the same mass finished, the aluminum camshaft must be larger.
when making a force(FD) and momentum diagram(MD) to et up the equations for momentum equation problem, which of the follwing elements should be in the FD and which should be in MD?
a. Each mass stream with product movo or product mivi crossing a control surface boundary. FD/MD
b Reaction forces required to hold walls, vanes, or pipes in place. FD/MD
c. weight of a solid body that contains or contacts the fluid. FD/MD
d. weight of te fluid. FD/MD
e. Pressure force caused by a fluid flowing across a control surfance boundary Fd/MD
When making a force (FD) and momentum diagram (MD) to et up the equations for momentum equation problem, Pressure force caused by a fluid flowing across a control surface boundary should be in the momentum diagram (MD) while the rest of the elements should be in the force diagram (FD).
Explanation:Force diagram (FD) shows all the forces that are acting on the system. Momentum diagram (MD) shows the momenta entering and leaving the system. The momentum equation expresses the balance of linear momentum in the control volume, while the force equation expresses the balance of forces in the control volume. The control volume can be a fixed or a moving one and can encompass a single point or a finite volume of space.The correct answer is E) Pressure force caused by a fluid flowing across a control surface boundary.
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6. What is the largest commonly-used drill bit size?
A. 1.5 inches
B. 12 inch
C. 2 inches
D. 1 inch
The largest commonly-used drill bit size among the options provided is 2 inches.
The correct answer to the given question is option C.
Drill bits are used for creating holes in various materials, and their sizes are typically measured in inches. The size of a drill bit refers to its diameter, and larger drill bits are commonly used for specific applications that require larger holes.
While drill bits larger than 2 inches do exist, they are not as commonly used in typical DIY or commercial applications. In everyday projects, such as woodworking, construction, or metalworking, the majority of holes can be adequately drilled using smaller-sized bits.
Option A (1.5 inches) and option D (1 inch) represent smaller drill bit sizes that are more commonly used for general-purpose drilling tasks. Option B (12 inches) represents an extremely large drill bit size that is not commonly used in most standard applications.
It's important to note that drill bit sizes can vary depending on specific needs and industries. There may be specialized applications or industries that require even larger drill bits beyond the commonly-used range. However, in the context of commonly-used drill bits for general-purpose tasks, 2 inches represents a relatively large size.
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A single-threaded 25-mm power screw hasa pitch of 5 mm. The frictional diameter of the collar is 45 mm. The max load onvertical direction of the screw is5kN. The collar has a coefficients of friction of0.06, and he threads hasa coefficients of friction of0.09. Find the overall efficiency and the torque to "raise" and "lower" the load.
Answer:
torque to raise the load = 16.411 Nm
torque to lower the load = 8.40 Nm
overall efficiency = 0.24
Explanation:
Given:
max load on vertical direction of the screw = Force = F = 5kN
frictional diameter of the collar = 45 mm
Diameter = 25 mm
length of pitch = 5 mm
coefficient of friction for thread µ = 0.09
coefficient of friction for collar µ\(_{c}\) = 0.06
To find:
torque to "raise" the load
torque to and "lower"
overall efficiency
Solution:
Compute torque to raise the load:
\(T_{R} = \frac{ Fd_{m}}{2} (\frac{L+(\pi ud_{m}) }{\pi d_{m}-uL }) +\frac{Fu_{c} d_{c} }{2}\)
where
\(T_{R}\) is the torque
F is the load
\(d_{m}\) is diameter of thread
\(d_{c}\) is diameter of collar
L is the thread pitch distance
µ is coefficient of friction for thread
µ\(_{c}\) is coefficient of friction for collar
Putting the values in above formula:
\(T_{R}\) = 5(25) / 2 [5+ (π(0.09)(25) / π(25)-0.09(5)] + 5(0.06)(45) / 2
= 125/2 [5 + (3.14)(0.09)(25)/ 3.14(25)-0.45] + 13.5/2
= 62.5 [(5 + 7.065) / 78.5 - 0.45] + 6.75
= 62.5 [12.065 / 78.05 ] + 6.75
= 62.5 (0.15458) + 6.75
= 9.66125 + 6.75
= 16.41125
\(T_{R}\) = 16.411 Nm
Compute torque to lower the load:
\(T_{L} = \frac{ Fd_{m}}{2} (\frac{(\pi ud_{m}) - L }{\pi d_{m}-uL }) +\frac{Fu_{c} d_{c} }{2}\)
= 5(25) / 2 [ (π(0.09)(25) - L / π(25)-0.09(5) ] + 5(0.06)(45) / 2
= 125/2 [ ((3.14)(0.09)(25) - 5) / 3.14(25)-0.45 ] + 13.5/2
= 62.5 [ (7.065 - 5) / 78.5 - 0.45 ] + 6.75
= 62.5 [ 2.065 / 78.05 ] + 6.75
= 62.5 (0.026457) + 6.75
= 1.6535625 + 6.75
= 8.40 Nm
Since the torque required to lower the the load is positive indicating that an effort is applied to lower the load, Hence the thread is self locking.
Compute overall efficiency:
overall efficiency = F(L) / 2π \(T_{R}\)
= 5(5) / 2(3.14)( 16.411)
= 25/ 103.06108
overall efficiency = 0.24
If a circuit produces a phase shift of 45 degrees between the voltage and current curves and the apparent power is 100 VA, what is the TRUE power in the circuit?
50 W
70.7 VA
70.7 W
100 A
The true power is obtained as 70.7 VA.
What is the true power?We define the power a the rate of doing work, we know that the power in a circuit is the product of the current and the voltage. In this case, we want to find the true power thus we have to involve the use of the phase shift in degrees.
Thus;
True power = PcosΦ
P = 100 VA
Φ = 45 degrees
True power = 100 VA * cos 45 degrees
True power = 70.7 VA
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The aerodynamic force exerted on each blade of a wo-blade wind turbine is 1000N. At the given conditions, the lift coefficient is 0.9. If the center of gravity of the blade is at 20m from the hub, compute the following:
1. The torque generated by the two blades.
2. The blades' power at 30 r/min.
Aerodynamic lift:
It is a combination of the speed of the air over a surface, the curve of the surface, and the impact of the air motion under the surface of the wing form.
The power generated by the blades can be calculated using the equation: Power = Torque x Angular velocity. Therefore, the power generated by the blades at 30 r/min is 20,000Nm x 30r/min = 600,000W.
What is velocity?Velocity is a vector quantity that measures the rate of change of an object’s position over time. It is equal to the distance traveled divided by the time taken. The SI unit of velocity is meters per second (m/s). Velocity is a fundamental concept in kinematics, the branch of classical mechanics that describes the motion of objects. Velocity can also be calculated using the equation v = s/t, where v is velocity, s is the distance and t is the time taken. When an object’s direction of motion changes, its velocity changes even if its speed remains the same.
The torque generated by the two blades can be calculated using the equation: Torque = Aerodynamic force x Distance from hub. Therefore, the torque generated by the two blades is 1000N x 20m = 20,000Nm.
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please hurry i’ll give you 15 points
Answer:
measures, dissolves, liquid, carbon dioxide, evaporates, water vapor, mold, decompose
Vacancy diffusion statement refer to that a mechanism that
atom at lattice traveled to a vacant latblèe
• True
• False
Answer:
true
Explanation:
Hi, I am confused about whether this is considered not symmetric or symmetric.
Relation R = { (a, b), (a, c), (b, c), (b, d), (c, d), (d, c) }
I tried asking different people but they gave me two different answers, so which one is the correct one?
Symmetric since (c, d) ∈ R and (d, c) ∈ R
OR
NOT Symmetric since (a, b) ∈ R and (b, a) ∉ R
OR
is it both wrong or both right? Please explain, thank you!
The relation R is not symmetric because it violates the symmetry property for the pair (a, b).
Is the relation R = { (a, b), (a, c), (b, c), (b, d), (c, d), (d, c) } symmetric or not?The relation R = { (a, b), (a, c), (b, c), (b, d), (c, d), (d, c) } is considered NOT symmetric.
Symmetry in a relation means that if (a, b) is in the relation, then (b, a) must also be in the relation. In this case, we have (a, b) ∈ R, but (b, a) ∉ R, violating the symmetry property.
While it is true that (c, d) ∈ R and (d, c) ∈ R, satisfying the symmetry property for those specific pairs, the presence of (a, b) ∈ R and (b, a) ∉ R already establishes that the relation is not symmetric. Symmetry should hold for all pairs in the relation, not just a subset.
Therefore, the correct answer is NOT symmetric, based on the violation of the symmetry property for the pair (a, b).
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Design a circuit with BCD inputs as a, b, c and d, that generates an output X=1 if none of the binary inputs are 1 and implement it using a suitable decoder
Answer:
use it as a decimal and to. especially it by the time and divide by the speed k think
One kg of an idea gas is contained in one side of a well-insulated vessel at 800 kPa. The other side of the vessel is under vacuum. The two sides are separated by a piston that is initially held in place by the pins. The pins are removed and the gas suddenly expands until it hits the stops. What happens to the internal energy of the gas?
a. internal energy goes up
b. internal energy goes down
c. internal energy stays the same
d. we need to know the volumes to make the calculation
Answer:
Option C = internal energy stays the same.
Explanation:
The internal energy will remain the same or unchanged because this question has to do with a concept in physics or classical chemistry (in thermodynamics) known as Free expansion.
So, the internal energy will be equals to the multiplication of the change in temperature, the heat capacity (keeping volume constant) and the number of moles. And in free expansion the internal energy is ZERO/UNCHANGED.
Where, the internal energy, ∆U = 0 =quantity of heat, q - work,w.
The amount of heat,q = Work,w.
In the concept of free expansion the only thing that changes is the volume.
Thin cuts called Sipes allow the tread pattern blocks to flex during stops and starts? Group of answer choices True False
Answer:
I think its True
it should be True