Consider a hypothetical consumer named Hayden who is shopping for bread and brie. The graph with bread and brie on the axes presents the utility‑maximizing combinations of bread and brie that Hayden chooses when the price of bread is $1.00 per loaf and the price of brie is $4.00 and $6.00 per wheel, respectively. The other graph shows Hayden's demand curve for brie.
The two points and associated values in the graph for bread and brie combinations correspond to points A and B in the graph of the demand curve for brie. What are the specific prices and quantities of brie associated with points A and B on Hayden's demand curve?
Answers
The graphical relationship of the demand and price of brie are given in the two graphs
At point A, the price is $4.00 and the quantity demanded is 23.84At point A, the price is $6.00 and the quantity demanded is 7.49Reason:
The given parameters are;
The graphs gives the utility-maximizing combinations of bread and brie chosen by Hayden
The price of the loaf = $1.00
The prices of the brie are $4.00 and $6.00 per wheel
Given that as the price increases from $4.00 to $6.00, the quantity
demanded increases, we have;
When the price is $4.00, the quantity of brie demanded 23.84 brie wheels,
and the quantity of bread demanded is 15.9 bread loaves
When the price increases to $6.00, the quantity of brie demanded
decreases to 7.49 brie wheels, while the quantity of bread demanded
increases to 25.2 loaves
Therefore; we have;
At point A, the price is $4.00 and the quantity demanded is 23.84
At point B, the price is $6.00 and the quantity demanded is 7.49
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Related Questions
what is the order biggest to least.
6/40 -4 3/4 -9/20
Answers
Answer:
.15, -.45, -4.75
Step-by-step explanation:
put all of them into a ti84 calculator and convert to decimals and then you get your answer.
Answer:
6/40, > -9/20, > -4 3/4
because positive numbers are greater, and the smaller the negative number, the greater it is.
a diver has to dive a depth of 200.2 ft go study
Answers
Answer:
The Diver has to dive 20.02 ft at every interval.
Step-by-step explanation:
10 intervals → 200.2
1 interval → 200.2/10
1 interval → 20.02
A parking lot is shaped like a parallelogram and bounded on four sides by streets, as shown in the figure to the right. How much asphalt (in square yards) is needed to pave the parking lot?
The amount of asphalt needed to pave the parking lot is __ yd^3, yd, or yd^2
Answers
Amount of Asphalt needed = 27000 square yards
The shape of the parking lot is a parallelogram.
In the figure, the base of the parking lot is of length 180 yd and the height of the parking lot is 150 yd.
If 'b' is the base of the parallelogram and 'h' its height, then area of the parallelogram, A = bh
So here, base length, b = 180 yd
and height, h = 150 yd.
Therefore, area of the parking lot which is parallelogram, A = bh
= 180 x 150
= 27000 yd² (square yards)
Amount of Asphalt needed to pave the parking lot = Area of the parking lot
= 27000 square yards
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Tell whether the equation has one, zero, or infinitely many solutions,8(x - 8) + 33 = 8x - 31This equation has (select)
Answers
Let's use the distributive property on the left-hand side to expand and then simplify the whole equation. The process is shown below:
\(\begin{gathered} 8(x-8)+33=8x-31 \\ 8x-64+33=8x-31 \\ 8x-31=8x-31 \end{gathered}\)As you can see, they are basically the same for both sides!
Hence, no matter what value(s) you put in for x, it will ALWAYS be true!
Thus, this equation has infinite many solutions.
Correct Answer:
Infinitely many solutions
HELP PLEASE!
Solve for m.
3.6m = 14.4
Answers
Answer:
4m
Step-by-step explanation:
Stem and Leaf Chart
Quiz Scores
Leaf
3
Stem
6
7
8
9
10
0047
2559
479
00
How many
students
scored 90% or
higher?
Answers
The value 12 would be represented by a stem value of 3 and a leaf value of 2, and so on.
A stem and leaf chart is a data representation tool used to organize and display data sets in an orderly and meaningful manner. The chart provides a way to quickly see the frequency of a particular set of values that occur in the data set.
The stem and leaf chart is a convenient way to display large data sets with small data intervals, such as height, weight, and exam scores.The stem and leaf chart divides the data into two parts, the stem and the leaf.
The stem is the digit or digits that represent the largest place value of the data, and the leaf is the digit or digits that represent the smallest place value of the data.
The stem is usually on the left side of the chart, and the leaves are listed in numerical order on the right side of the chart.A stem and leaf chart with a value of 10 higher is a modification of the traditional stem and leaf chart.
In a stem and leaf chart with a value of 10 higher, the stem represents the tens place value, and the leaves represent the ones place value. For example,
if the stem value is 2, then the leaves would be listed from 0 to 9. The value 10 would be represented by a stem value of 3 and a leaf value of 0. The value 11 would be represented by a stem value of 3 and a leaf value of 1.
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please help!! need it fast, will give brainliest!! and pls show work !!
Find the measure of angle AEB
Answers
Answer:
An acute angle
Step-by-step explanation:
An acute angle is smaller than an obtuse ad right angle.
hope this helps and hope it was right 'cause I really don't know what you meant. :)
What is the answer to 54<45+3
Answers
Answer:
54<48
Step-by-step explanation:
If you add 45+3, you get 45.
Hope this helped.
plzz help me asap i need help picture below
Which line has a slope of -?
line d
line b
line a
line c
Answers
Explanation: right two and down three since it’s a negative fraction
Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
A). (tan(x) − 4)(9 sin^2(x) − 1) = 0
B). 3 sin(2x) − 4 sin(x) = 0
Answers
Answer:
Step-by-step explanation:
A)\((tanx-4)(9sin^2x-1)=0\\\\\\\)
\(9sin^2x-1=0\\\\sin^2x=\frac{1}{9} sinx=\frac{1}{3}\) or \(sinx=\frac{-1}{3}\)
OR \(tanx=4\\\)
B)
\(3sin2x=3.2.sinx.cosx\\\\6.sinx.cosx-4.sinx= 2sinx.(3cosx-2)=0\\\\3.cosx=2 cosx=\frac{2}{3}\)
First term (n) = 10, (4 x 1 + 6)
Rule: multiply 4 with n and then add 6 ( or 4n+6)
Q. find the next 2 terms in the sequence
Answers
Answer:
soln,
we know that;
(n)=(4n+10)then;
(n)=13(4×2+6)
(n)=18(4 × 3 + 6)
What is equivalent to -2(x-5)?
Answers
Answer:
-2x+10
Step-by-step explanation:
-2(x-5)
Distribute
-2*x -2*-5
-2x+10
The area of a rectangle with a
length of 10 cm and a width of 3
cm.
Answers
Answer:
30 cm2
Hope this helps
Answer:
30
Step-by-step explanation:
A=w*l=3·10=30
BRAINILEST PLEASE
HELP PLZ PLZ HEEEEEEEEEEEEEEEEELP
Answers
Since there is 8 parts in between 1 and 2 on the number line the denominator is 8.
The most frequent measurement is right in the middle, which if you count to that line you can see it goes up to 4 parts.
And because it’s already past the whole number 1 it would be 1 4/8 or 1 ½
I hope this helps and is understandable!
There are 11 freshmen and 6 sophomores in a class. If three students are selected at random, find the probability that two are freshmen and one is a sophomore. (See Example 6. Round your answer to three decimal places.)
Answers
Write the equation of the line given the following slope and y-intercept
m = 2
b=-3
A. y = 3x + 2
B. y=3x-2
C. y=2x-3
D. y=-2x+3
Answers
I just did this one and got the answer C
Juan ramirez sells suits in a major department store on weekends he Ernst a commission of 5 percent on the first ten suits and he sells more than ten he Ernakulam additional 3 percent last weekend he sold thirteen 250 suits what was his commission?
Answers
Answer:
$185
Step-by-step explanation:
The first ten suits sold for 10×$250 = $2,500
commission = 5% of $2,500 = 0.05×$2,500 = $125
The next three suits sold for 3×$250 = $750
commission = 8% of $750 = 0.08×$750 = $60
Total commissions = $125+$60 = $185
There are several errors in the question. If you are using voice recognition, you are better off typing the question manually.
The following transactions were completed by Winklevoss Inc., whose fiscal year is the calendar year:
Year 1
July 1 Issued $71,900,000 of 20-year, 6% callable bonds dated July 1, Year 1, at a market (effective) rate of 7%, receiving cash of $64,222,669. Interest is payable semiannually on December 31 and June 30.
Oct. 1 Borrowed $420,000 by issuing a six-year, 5% installment note to Nicks Bank. The note requires annual payments of $82,747, with the first payment occurring on September 30, Year 2.
Dec. 31 Accrued $5,250 of interest on the installment note. The interest is payable on the date of the next installment note payment.
31 Paid the semiannual interest on the bonds. The bond discount amortization of $191,933 is combined with the semiannual interest payment.
Year 2
June 30 Paid the semiannual interest on the bonds. The bond discount amortization of $191,933 is combined with the semiannual interest payment.
Sept. 30 Paid the annual payment on the note, which consisted of interest of $21,000 and principal of $61,747.
Dec. 31 Accrued $4,478 of interest on the installment note. The interest is payable on the date of the next installment note payment.
31 Paid the semiannual interest on the bonds. The bond discount amortization of $191,933 is combined with the semiannual interest payment.
Year 3
June 30 Recorded the redemption of the bonds, which were called at 98. The balance in the bond discount account is $6,909,599 after payment of interest and amortization of discount have been recorded. Record the redemption only.
Sept. 30 Paid the second annual payment on the note, which consisted of interest of $17,913 and principal of $64,834.
Required:
1. Journalize the entries to record the foregoing transactions. Round all amounts to the nearest dollar. Refer to the Chart of Accounts for exact wording of account titles.
2. Indicate the amount of the interest expense in (a) Year 1 and (b) Year 2.
3. Determine the carrying amount of the bonds as of December 31, Year 2.
Answers
1. The journal entries recording the transactions for Winkelvoss Inc. are as follows:
Journal Entries:Year 1:
July 1: Debit Cash $64,222,669
Debit Bonds Discount $7,677,331
Credit Bonds Payable $71,900,000
Oct. 1: Debit Cash $420,000
Credit Bank Notes Payable $420,000
Dec. 31 Debit Interest Expense $5,250
Credit Installment Note Interest Payable $5,250
Dec. 31 Debit Interest Expense $2,708,433
Credit Cash $2,516,500
Credit Bond Amortization $191,933
Year 2:
June 30 Debit Interest Expense $2,516,500
Credit Cash $2,324,567
Credit Bond Amortization $191,933
Sept. 30 Debit Interest Expense $15,750
Debit Installment Note Interest Payable $5,250
Debit Notes Payable $61,747
Credit Cash $82,747
Dec. 31 Debit Interest Expense $4,478
Credit Installment Note Interest Payable $4,478
Dec. 31 Debit Interest Expense $2,708,433
Credit Cash $2,516,500
Credit Bond Amortization $191,933
Year 3:
June 30 Debit Bonds Payable $64,990,401
Debit Bond Redemption Premium $5,471,599
Credit Cash $70,462,000
Sept. 30 Debit Interest Expense $13,435
Debit Installment Note Interest Payable $4,478
Debit Notes Payable $64,834
Credit Cash $82,747
2. The amounts of the interest expense in Year 1 and Year 2 are as follows:
Year 1 Year 2
Total interest $2,713,683 $2,72,8661
3. The bond's carrying amount as of December 31, Year 2, is $64,798,468.
Transaction Analysis:Year 1:
July 1: Cash $64,222,669 Bonds Discount $7,677,331 Bonds Payable $71,900,000
Oct. 1: Cash $420,000 Bank Notes Payable $420,000
Dec. 31 Interest Expense $5,250 Installment Note Interest Payable $5,250
Dec. 31 Interest Expense $2,708,433 Cash $2,516,500 Bond Amortization $191,933
Year 2:
June 30 Interest Expense $2,516,500 Cash $2,324,567 Bond Amortization $191,933
Sept. 30 Interest Expense $15,750 Installment Note Interest Payable $5,250 Notes Payable $61,747 Cash $82,747
Dec. 31 Interest Expense $4,478 Installment Note Interest Payable $4,478
Dec. 31 Interest Expense $2,708,433 Cash $2,516,500 Bond Amortization $191,933
Year 3:
June 30: Bonds Payable $64,990,401 Bond Redemption Premium $5,471,599 Cash $70,462,000
Sept. 30 Interest Expense $13,435 Installment Note Interest Payable $4,478 Notes Payable $64,834 Cash $82,747
Interest Expenses:Year 1 Year 2
Bonds Payable $2,708,433 $2,708,433
Notes Payable $5,250 $15,750
Notes Payable $4,478
Total interest $2,713,683 $2,72,8661
Carrying amount of the bonds December 31, Year 2:July 1: $64,222,669
Dec. 31 Bond Amortization $191,933
June 30 Bond Amortization $191,933
Dec. 31 Bond Amortization $191,933
Dec. 31 Year 2 Carrying Amont = $64,798,468
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ratio of boys to gitirls was 4 to 5 if theirr was a 180
Answers
Answer:
144
Step-by-step explanation:
4/5=X/180
5x= 720
X= 144
please feel free to ask if you have any questions.make me BrainliestHow would you write "4/1000" In decimal form?
Answers
Answer:
0.004
Step-by-step explanation:
Since 4/10 is 0.4 and 4/100 is 0.04, 4/1000 must be 0.004
Answer:
0.004
Step-by-step explanation:
\(\frac{4}{1000}\) is basically \(4 \cdot 10^{-4\) (if you've learned scientific notation), so all you have to do is move the decimal to the left four times. That gives us
\(4.0\\0.4\\0.04\\\boxed{0.004}\)
More depth:
\(10^{-4\) also equals 0.001, so \(4 \cdot 0.001 = \boxed{0.004.}\)
*You may do division and find the answer too. However, these ways are quicker.
Help plzzzzz I need to finish this
Answers
Answer:
F i think
Step-by-step explanation:
it starts at 3 and goes up 2.50 each time so it is the most reasonable
2(x+3)=x - 4
What is the answer pls
Answers
Answer:
X= -10
Step-by-step explanation:
This is the answer wait I will show u the steps
3. Armen los siguientes prismas a partir de los que construyeron con su material recor
table. Después calculen el volumen de acuerdo con las dos formas que se indican
Prisma
Por et
en el fonda, near ty api
quen la foto da alisema cavab
en el fin de pana
tados con los de sus compañeros llegaron al misino resultado
Answers
Answer:
can you translate to english
Step-by-step explanation:
I can't understand
There are 7 teachers going to the museum. There are 8 times as many students going as teachers. They will need 1 van for every 6 people.
Answers
The sentence with proper subject-verb agreement is the student as well as the teacher want to go to the museum. In this sentence, the subject is what we call a compound subject, meaning that the verb refers and agrees with more than just one singular word.
The compound subject is "student" and "teacher" and they are connected by "as well as", which functions as a coordinating conjunction would. That's why the verb should conjugate in its plural form.
Option A is incorrect because the structure inside parentheses is not related to the verb and does not influence its conjugation. Options C and D have a verb in the singular form for a compound subject - that would demand a plural conjugation.
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Shameel has a flight to catch on Monday morning. His father will give him a ride to the airport. If it rains, the traffic will be bad and the probability that he will miss his flight is 0.06. If it doesn't rain, the probability that he will miss his flight is 0.01. The probability that it will rain on Monday is 0.30. Suppose that Shameel misses his flight. What is the probability that it was raining
Answers
Answer:
The probability that it was raining on Monday given that Shameel misses his flight is 0.5846.
Step-by-step explanation:
A stem and leaf plot shows data in _____ order.
alphabetical
numerical
reverse
Answers
this is for the extra letters lol
Please help I’m stuck and keep getting the wrong answer
Answers
The time spent higher than 26 meters above the ground is 0.42 minutes. Answer: 0.42
A Ferris wheel is 30 meters in diameter and boarded from a platform that is 4 meters above the ground.
The six o'clock position on the Ferris wheel is level with the loading platform.
The wheel completes 1 full revolution in 2 minutes.
We have to find how many minutes of the ride are spent higher than 26 meters above the ground.
So, let's start with some given data,Consider the height of a person at the six o'clock position = 4 meters
So, the height of a person at the highest point = 4 + 15 = 19 meters (since the diameter is 30 meters, the radius will be 15 meters)
Also, the height of a person at the lowest point = 4 - 15 = -11 meters
Therefore, the Ferris wheel completes one cycle from the lowest point to the highest point and back to the lowest point.
So, the total distance travelled will be = 19 + 11 = 30 meters.
Also, we are given that the wheel completes 1 full revolution in 2 minutes.
We need to calculate the time spent higher than 26 meters above the ground.
So, the angle between the 6 o'clock position and 2 o'clock position will be equal to the angle between the 6 o'clock position and the highest point.
This angle can be calculated as follows:
Angle = Distance travelled by the Ferris wheel / Circumference of the Ferris wheel * 360 degrees
Angle = 30 / (pi * 30) * 360 degrees
Angle = 360 degrees / pi
= 114.59 degrees
So, the total angle between the 6 o'clock position and the highest point is 114.59 degrees.
Now, we need to find out how much time is spent at an angle greater than 114.59 degrees.
This can be calculated as follows:
Time = (Angle greater than 114.59 degrees / Total angle of the Ferris wheel) * Total time taken
Time = (180 - 114.59) / 360 * 2 minutes
Time = 0.42 minutes
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Now write 12% as a fraction in simplest
Answers
Answer:
12/100
Step-by-step explanation:
Percent is basically per 100 so 12/100
Simplest is 3/25
3/25 in simplest form.
if 60 men do a piece of work in 27 days, then in how many days can 18 men do the same work?
Answers
if 60 men do a piece of work in 27 days, then 18 men can do the same work in 90 days.
What is unitary method?The unitary approach is a strategy for problem-solving that involves the first determining the value of a single unit, then multiplying that value to determine the required value.
Always write the items that need to be computed on the right side and the things that are known on the left side to simplify things. In the aforementioned issue, the number of apples is known, but it is unclear what they are worth. It should be highlighted that issues with this method are solved using the concepts of ratio and proportion.
From the unitary method:
Number of days required to complete a work by 60 men = 27 days
Number of days required to complete a work by 1 man = 27*60
Number of days required to complete a work by 18 men = \(\frac{27*60}{18}\)= 90days
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13 People fit comfortably in a 5 feet by 5 feet area. Use this value to estimate the size of a crowd that is
5 feet deep on both sides of the street along a 2.7-mile section of a parade route.
Answers
The size of the crowd that is 5 feet deep on both sides of the street along a 2.7 -mile section of a parade route is 74,131 people.
How to calculate the crowd?The number of people that can fit comfortably in a 5 feet by 5 feet area = 13.
Therefore;
The ratio of the number of people per unit area = 13/(5 × 5) = 13/25
The area A occupied by the crowd = 5 feet × 2.7 mile × 2
2.7 miles = 14,256 feet
∴ A = 5 feet × 14,256 feet × 2 = 1,42,560ft²
We then have:
\(\frac{number\ of\ people}{1,42,560} = \frac{13}{25}\)
∴Number of people = 13/25 × 1,42,560 = 74,131.2 ≈ 74,131 people
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