Consider 0.150 M of KF solution.
A. Calculate the pH of the solution
B. Calculate the solubility of MgF2 in the 0.150 M KF solution
Answers
A. Calculation of pH of the solution:KF is a strong electrolyte. Solubility of MgF₂ in the 0.150 M KF solution is 2.64 × 10⁻⁴ M.
When dissolved in water, it ionizes completely to produce one potassium ion (K⁺) and one fluoride ion (F⁻).
So, the concentration of F⁻ ions is equal to the concentration of KF. Here, KF is acting as a source of F⁻ ions. Its ionization in water is given below:
KF (aq) → K⁺ (aq) + F⁻ (aq)
Thus, [F⁻] = 0.150 M
The hydrolysis reaction of fluoride ions isF⁻ (aq) + H₂O (l) ⇌ HF (aq) + OH⁻ (aq)
Initial Conc. 0.150 0 0Eqbm Conc. -x +x +x
Kb = Kw/Ka = 1.76 × 10⁻¹⁴ / 6.8 × 10⁻⁴
= 2.59 × 10⁻¹¹
Kb = [HF] [OH⁻] / [F⁻]x² / (0.150 - x)
= 2.59 × 10⁻¹¹
Now, as the concentration of F⁻ ions is much greater than 1 × 10⁻⁷ M, we can neglect the small amount of x from 0.150 M.
So, the final concentration of F⁻ ions is 0.150 M.x² / 0.150 = 2.59 × 10⁻¹¹
∴ x = 2.56 × 10⁻⁶ M
So, [HF] = [OH⁻] = 2.56 × 10⁻⁶ M
Now, pOH = -log[OH⁻] = -log(2.56 × 10⁻⁶)
= 5.59pH = 14 - pOH
= 14 - 5.59 = 8.41
The pH of the solution is 8.41.
B. Calculation of solubility of MgF2 in the 0.150 M KF solution:
Magnesium fluoride (MgF₂) is an insoluble salt.
Its solubility product is given by the expression
Ksp = [Mg²⁺][F⁻]²At 25°C,
the value of Ksp is 7.4 × 10⁻¹⁰.MgF₂(s) ⇌ Mg²⁺(aq) + 2F⁻(aq)
Now, the concentration of F⁻ ions is 0.150 M and that of Mg²⁺ is unknown.
Let the concentration of Mg²⁺ be x M.So, the equilibrium concentration of F⁻ ions will be 2x M.
Now, the solubility product expression can be written as 7.4 × 10⁻¹⁰ = x(2x)²
= 4x³
∴ x = (7.4 × 10⁻¹⁰ / 4)¹/³
= 2.64 × 10⁻⁴ M
Solubility of MgF₂ in the 0.150 M KF solution is 2.64 × 10⁻⁴ M.
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Related Questions
In the reaction 2Na+ Cl2 + 2NaCl, the products are O half the reactants. twice the reactants. the same as the reactants. o different from the reactants.
Answers
Answer:
It should be the same as the reactants. Because there is no loss or replacements.
Explanation:
Answer:
The same as the reactants
Explanation:
how many element are there on the periodic table?
Answers
Answer:118
Explanation: it’s right
Answer:
118 elements
Hope that helps
this is the chemical formula for cassiterite (tin ore): sno2 a geochemist has determined by measurements that there are 8.346 moles of tin in a sample of cassiterite. how many moles of oxygen are in the sample? round your answer to 4 significant digits.
Answers
There are approximately 16.692 moles of oxygen in the sample of cassiterite with 8.346 moles of tin.
The chemical formula for cassiterite (tin ore) is SnO2, indicating that each molecule of cassiterite contains one atom of tin (Sn) and two atoms of oxygen (O). According to the given information, the sample contains 8.346 moles of tin. Since the molar ratio between tin and oxygen in SnO2 is 1:2, we can calculate the number of moles of oxygen by multiplying the number of moles of tin by 2. Therefore, 8.346 moles of tin would correspond to
\(2 * 8.346 = 16.692 \\\) moles of oxygen in the sample.
It's important to round the answer to four significant digits as specified. Hence, the final result is approximately 16.692 moles of oxygen.
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a buffer solution contains 0.432 m c6h5nh3br and 0.373 m c6h5nh2 (aniline). determine the ph change when 0.106 mol koh is added to 1.00 l of the buffer.
Answers
The pH change when 0.106 mol KOH is added to 1.00 l of the buffer is 0.238
given that :
molarity of C₆H₅NH₃Br = 0.432 M
molarity of C₆H₅NH₂ = 0.373 M
pOH = pkb + log [acid] / [base]
pOH = 9.366 + log (0.432) / (0.373)
pOH = 9.366 + 0.0718
pOH = 9.437
pH = 14 - 9.437
pH = 4.563
after 0.106 mol of KOH is added to 1 L
[C₆H₅NH₃Br] = 0.432 - 0.106 = 0.326
[C₆H₅NH₂ ] = 0.373 + 0.106 = 0.479
pOH = pkb + log [salt] / [acid]
pOH = 9.366 + log (0.326) / 0.479)
pOH = 9.366 - 0.167
pOH = 9.199
pH = 14 - 0.199
pH = 4.801
the pH change is = 4.801 - 4.563
= 0.238
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Help Me ASAP! Looking at the picture above which images would be best classified as molecules?
Answers
Answer:
B
Explanation:
Answer:
C) B AND C
Explanation:
points
A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 197. mg of oxalic acid (H, C04), a diprotic acid that can be purchased inexpensively in high purity, and dissolves it in 250. mL of distilled water. The student then titrates the oxalic acid solution with her sodium hydroxide solution. When the titration reaches the equivalence point, the student finds she has used 45.3 mL of sodium hydroxide solution.
Calculate the molarity of the student's sodium hydroxide solution.
Answers
The molarity of the student's sodium hydroxide solution is 0.0689 M.
To determine the molarity of the sodium hydroxide solution, we can use the stoichiometry of the balanced equation between sodium hydroxide (NaOH) and oxalic acid (H2C2O4).
The balanced equation for the reaction between NaOH and H2C2O4 is:
2NaOH + H2C2O4 → Na2C2O4 + 2H2O
From the balanced equation, we can see that the ratio of NaOH to H2C2O4 is 2:1. This means that for every 2 moles of NaOH, 1 mole of H2C2O4 is consumed.
Given that the student used 45.3 mL of NaOH solution, we need to convert this volume to moles of NaOH. To do this, we need to know the molarity of the oxalic acid solution.
Using the given mass of oxalic acid (197 mg), we can calculate the number of moles of H2C2O4:
moles of H2C2O4 = mass of H2C2O4 / molar mass of H2C2O4
The molar mass of H2C2O4 is 126.07 g/mol.
moles of H2C2O4 = 0.197 g / 126.07 g/mol = 0.001561 mol
Since the stoichiometry of the reaction is 2:1, the number of moles of NaOH used is twice the number of moles of H2C2O4:
moles of NaOH = 2 * moles of H2C2O4 = 2 * 0.001561 mol = 0.003122 mol
Now we can calculate the molarity of the NaOH solution:
Molarity of NaOH = moles of NaOH / volume of NaOH solution in liters
Volume of NaOH solution = 45.3 mL = 45.3/1000 L = 0.0453 L
Molarity of NaOH = 0.003122 mol / 0.0453 L = 0.0689 M.
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What is the molality of a solution that has 14g of dissolved cao in 25kg of water?
Answers
Molality is the number of moles of solute dissolved in 1000 g of the solvent (mol/kg). The formula for molality is as follows:Molality (m) = moles of solute / kilograms of solventHere are the steps to calculate the molality of a solution that has 14 g of dissolved CaO in 25 kg of water:1. Convert the mass of CaO to moles. The molar mass of CaO is 56.077 g/mol.14 g CaO × (1 mol CaO / 56.077 g CaO) = 0.2495 mol CaO2. Convert the mass of water to kilograms.25 kg of water × 1000 g/kg = 25,000 g of water3. Calculate the molality of the solution.molality (m) = 0.2495 mol / 25 kg= 0.00998 mol/kgThe molality of the solution is 0.00998 mol/kg.
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identify the spectator ions in this reaction. check all that apply. 2h co32– 2na 2oh– 2na co32– 2h2o h co32– na oh– 2h2o
Answers
In the given reaction: 2H+ + CO32- + 2Na+ + 2OH- -> 2Na+ + CO32- + 2H2O, the spectator ions can be identified by examining which ions remain unchanged throughout the reaction.
Spectator ions are present in the reaction mixture but do not undergo any chemical change. Instead, they remain as ions on both sides of the equation. In this case, the Na+ and CO32- ions are present on both the reactant and product sides of the equation. Therefore, they are spectator ions. When the reaction occurs, the H+ and OH- ions combine to form water (H2O). The CO32- ion remains unchanged and does not participate in any chemical transformation. The Na+ ion also remains unchanged and is found on both sides of the equation. Spectator ions do not affect the overall outcome or result of the reaction. They are simply present to maintain charge balance. Therefore, in the given reaction, the spectator ions are Na+ and CO32-.
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A sample containing 27. 0 moles of propane gas at a temperature of 25. 0 °C is stored in a 12. 5 liter cylinder. What is the pressure of the gas inside the cylinder?
Answers
The pressure of the gas inside the cylinder is 52.90 atm
Given is the number of moles of gas, the temperature and the volume of the gas and we need to find the pressure of the gas inside the cylinder, for this we can use the ideal gas law equation:
PV = nRT
Where:
P = Pressure of the gas (in units of pressure, such as atm)
V = Volume of the gas (in liters)
n = Number of moles of the gas
R = Ideal gas constant (0.0821 L·atm/(mol·K))
T = Temperature of the gas (in Kelvin)
First, let's convert the temperature from Celsius to Kelvin:
T = 25.0 °C + 273.15 = 298.15 K
Now we can substitute the values into the ideal gas law equation:
P × 12.5 L = 27.0 moles × 0.0821 L·atm/(mol·K) × 298.15 K
Simplifying the equation:
P × 12.5 L = 661.2587 L·atm
Dividing both sides by 12.5 L:
P = 661.2587 L·atm / 12.5 L
P ≈ 52.90 atm
Therefore, the pressure of the gas inside the cylinder is approximately 52.90 atm.
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We can use the ideal gas law equation to determine the pressure of a gas within a cylinder:
PV = nRT
Where:
P is the pressure of the gas (in units of pressure, such as atm)
V is the volume of the gas (in units of volume, such as liters)
n is the number of moles of the gas
R is the ideal gas constant (0.0821 L·atm/(mol·K))
T is the temperature of the gas (in units of temperature, such as Kelvin)
we need to convert the temperature from Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 25.0 °C + 273.15
T(K) = 298.15 K
Now we can plug the data into the ideal gas law equation as follows:
P * 12.5 L = 27.0 moles * 0.0821 L·atm/(mol·K) * 298.15 K
Simplifying the equation:
P = (27.0 moles * 0.0821 L·atm/(mol·K) * 298.15 K) / 12.5 L
Calculating the pressure:
P ≈ 5.046 atm
As a result, the gas inside the cylinder is under a pressure of about 5.046 atm.
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Sam wants to know how fast his brother can run. He knows the time it took for his brother to run
from the starting line to the finish line. What else does he need to know in order to calculate the
speed of his brother?
O He needs to know what time his brother ate lunch.
O He needs to know the direction his brother ran.
O He needs to know the distance from the starting line to the finish line.
Answers
N2 + 3H2 2NH3
Using the balanced equation above for the production of ammonia from nitrogen and hydrogen, how many moles of NH3 are produced when 1.7 moles of nitrogen reacts with hydrogen?
Answers
Answer:Considering the N2 only, 3 mols of N2 could form 6 moles of NH3. Considering the Hydrogen only, 8 moles of H2 could make 16/3 or 5 1/3 moles of NH3. 5 1/3 is less than 6, so the reaction is limited by the hydrogen, and 5 1/3 is the correct answer. Note that in reality this reaction does not go to completion, and this is just a textbook exercise.
Explanation:
During cellular respiation, your cells release a. Energys , b. Glucose , c. Heat
- Add explanation
Answers
Answer:
b
Explanation:
glucose
During cellular respiration, a glucose molecule is gradually broken down into carbon dioxide and water. Along the way, some ATP is produced directly in the reactions that transform glucose. Much more ATP, however, is produced later in a process called oxidative phosphorylation. Oxidative phosphorylation is powered by the movement of electrons through the electron transport chain, a series of proteins embedded in the inner membrane of the mitochondrion.
Answer:
During cellular respiration, your cells release energy in the form of ATP (adenosine triphosphate), which is used as an energy source by the body. The energy released during cellular respiration comes from the breakdown of glucose, which is a type of sugar that is used by the body as a source of fuel. In addition to ATP, some heat is also released during cellular respiration, but this is not the primary product of the process. So the correct answer is a. Energy.
barium-122 has a half-life of 2.00 minutes. a fresh sample weighing 80.00 g was obtained. if it takes 10.00 minutes to set up an experiment using barium-122, how much barium-122 will be left when the experiment begins?
Answers
The amount of barium-122 remaining after 10.00 minutes, which includes 5 half-lives, will be approximately 2.50 g. This is because each half-life reduces the amount of barium-122 by half.
Barium-122 has a half-life of 2.00 minutes. This means that every 2.00 minutes, half of the barium-122 will decay.
To determine how much barium-122 will be left when the experiment begins, we need to calculate the number of half-lives that occur during the 10.00 minutes it takes to set up the experiment.
Since each half-life is 2.00 minutes, the number of half-lives that occur in 10.00 minutes is 10.00 minutes / 2.00 minutes = 5 half-lives.
Each half-life reduces the amount of barium-122 by half. So, after 1 half-life, we have 80.00 g / 2 = 40.00 g remaining. After 2 half-lives, we have 40.00 g / 2 = 20.00 g remaining.
After 3 half-lives, we have 20.00 g / 2 = 10.00 g remaining. After 4 half-lives, we have 10.00 g / 2 = 5.00 g remaining. And after 5 half-lives, we have 5.00 g / 2 = 2.50 g remaining.
Therefore, when the experiment begins, there will be approximately 2.50 g of barium-122 left.
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Some greenhouse gases, such as fluorocarbons (CFCs, HFCs, PFCs, etc. ), are human-made. Others, such as water, methane, and carbon dioxide, are naturally produced. Which type of greenhouse gas (human-made or natural) is more difficult to control and eliminate? Which types are easier? In three to five sentences, provide evidence for your argument
Answers
The green house gases are those gases that are known to prevent the escape of infrared rays.
What are green house gases?The green house gases are those gases that are known to prevent the escape of infrared rays and ultimately lead to an increase in the temperature of the earth.
These green house gases could be natural or artificial. The natural greenhouses gases are more difficult to control because they can alaso be produced in natural processess that are not subject to human control.
For instance, there are process in the ocean that produce methane and this gas is also produced by decomposition in nature. This makes the control of the gas not entirely within the control of man.
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Given the balanced equation representing a nuclear reaction
2 1 H+^ 3 1 H -> ^ 4 2 He + ^ 1 0n
Which phrase identifies and describes this reaction?
A) fission, mass converted to energy
B) fusion, energy converted to mass
C) fusion, mass converted to energy
D) fission, energy converted to mass
Answers
The right word to describe this chemical reaction is c) fusion mass converted into energy. When two lighter nuclei come together to form a heavier nucleus, a significant quantity of energy is released. Energy is released when two hydrogen nuclei (H) combine to generate helium-4 (He) and a neutron (n).
A nuclear event called fusion occurs when two lighter atomic nuclei join forces to create a heavier nucleus. This process takes place at incredibly high pressures and temperatures, which are often encountered in star cores or in experimental fusion reactors. When there is fusion, the atomic nuclei
There is a significant quantity of energy released as they conquer their attraction to one another and combine. Deuterium and tritium, two isotopes of hydrogen, combine with lighter atoms to generate helium and unleash a tremendous amount of energy, similar to that of nuclear fusion.
the power generated by the Sun. In order to accomplish practical fusion power generation, considerable scientific and engineering obstacles must be overcome. Fusion reactions have the potential to produce a clean, abundant, and sustainable source of energy.
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Question 14 (1 point)
A magnesium atom has 11 neutrons. What is the mass of this magnesium atom?
Answers
Answer:
Mass=23
Explanation:
Mass= Protons + neutrons
Atomic number is the number of protons in magnesium.
Atomic number =12...So there are 12 protons
12p + 11n = 23
How many moles of gas does it take to occupy 120 liters at a pressure of 2.3 atmospheres and a temperature of 350 K?
Remember:R=0.0821 L•atm/mol k
A. 9.6 mol
B. 3.4 mol
C. 4.7 mol
D.0.79 mol
Answers
Answer:
A - 9.6 mol.
Explanation:
Took the test.
Why is the mole important? Group of answer choices It can be applied to any type of object: molecules, atoms, ions, etc. It gives us a convenient way to express large numbers. It is useful when converting between grams and atoms or molecules. All of the above.
Answers
Answer: the mole
Explanation:
The mole is the unit of amount in Chemistry.
It provides a bridge between the atom and the macroscopic amounts of material that we work with in the laboratory.
At a pressure of 125 atm, a sample of a gas has a volume of 150 L. What pressure does it have when the gas is compressed to 40 L? show work
Answers
Answer:
???
Explanation:
I have no clue sorry
How many grams of NaCl are needed in order to make a liter of a 2.00 M NaCl solution? O 58.4 g O 117 g O 2.00 g
Answers
Answer:
B.) 117 g
Explanation:
(Step 1)
To find the mass, you need to first find the moles of NaCl using the molarity ratio.
Molarity = moles / volume (L)
2.00 M = moles / 1.0 L
2.00 = moles
(Step 2)
Now that you know the moles, you can convert it to grams using the molar mass.
Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol
Molar Mass (NaCl): 58.443 g/mol
2.00 moles NaCl 58.443 g
--------------------------- x ----------------- = 117 g NaCl
1 mole
which statement must be true when solution equilibrium occurs? * (1) the solution is at stp. (2) the solution is supersaturated. (3) the concentration of the solution remains constant. (4) the masses of the dissolved solute and the undissolved solute are equal.
Answers
When solution equilibrium occurs the concentration of the solution remains constant.
Equal forward and reverse reaction rates are required. There is no requirement that the amounts of reactants and products be equal. Nonetheless, the quantities of reactants and products will remain constant after equilibrium has been reached.
An object must satisfy two requirements of equilibrium in order to maintain static equilibrium. Initially, there must be no net force acting on the item. Second, there must be no net torque pulling on the object.
According to the equilibrium law, an equilibrium constant is equal to the product concentrations multiplied by the reactant concentrations multiplied by one another (K).
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find the pka of an acid which has an initial concentration of 1.497 m for the acid and an equilibrium ph of 2.546.
Answers
Answer:
From the equilibrium pH, we can find the concentration of H+ ions in solution using the relation:
[H+] = 10^(-pH)
[H+] = 10^(-2.546) = 2.177 × 10^(-3) M
Now we can use the fact that the acid is a weak acid and only partially dissociates to form H+ ions and its conjugate base. Therefore, we can assume that [HA] at equilibrium is equal to the initial concentration of the acid minus the concentration of H+ ions that were produced from the dissociation of the acid.
[HA] at equilibrium = initial concentration of acid - [H+]
[HA] at equilibrium = 1.497 M - 2.177 × 10^(-3) M
[HA] at equilibrium = 1.497 M (since the concentration of H+ ions is negligible compared to the initial concentration of the acid)
Now we can plug in the values we obtained into the Henderson-Hasselbalch equation:
2.546 = pKa + log([A-]/[HA])
2.546 = pKa + log(0/[HA])
2.546 = pKa - log([HA])
log([HA]) = pKa - 2.546
[HA] = 10^(pKa - 2.546)
Since we assumed that the concentration of the conjugate base at equilibrium is negligible, we can assume that [A-] ≈ 0.
Therefore, we have:
pKa = log([HA]/0) + 2.546
pKa = log([HA]) + 2.546
pKa = log(1.497) + 2.546
pKa = 0.174 + 2.546
pKa = 2.72
Therefore, the pKa of the acid is approximately 2.72.
although osha created no symbols or specific color designations as part of its hazard comunication standard whose hazard class symnbol
Answers
The Hazard Communication Standard (HCS) established by the Occupational Safety and Health Administration (OSHA) does not include specific symbols or color designations.
However, the HCS does require the use of hazard class symbols that are provided by other organizations, such as the Globally Harmonized System (GHS). The GHS hazard class symbols are internationally recognized and serve as a visual representation of the hazards associated with different chemicals. These symbols are in the form of pictograms, which are easily identifiable and provide quick information about the hazards involved.
They are used to convey specific information about the nature of the hazards, such as flammability, toxicity, or corrosiveness. These symbols are important for ensuring the safety of workers and providing consistent information about the potential risks of different substances.
While OSHA's Hazard Communication Standard does not create symbols or color designations, it does require the use of hazard class symbols provided by organizations like the GHS to communicate the hazards associated with different chemicals.
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The respiratory system is part of the excretory system because it
A
disposes of bodily wastes.
B
excretes liquid waste dioxide.
C
excretes sweat through the skin.
D
involves the kidneys.
Answers
The respiratory system is part of the excretory system because it disposes of bodily wastes (Option A).
What is the respiratory system?The respiratory system is an organ system composed of different structures that work together to obtain oxygen from the air in order to perform cellular respiration and also excrete carbon dioxide which is a by-product of this metabolic pathway (cellular respiration).
Therefore, with this data, we can see that the respiratory system functions to excrete harmful gases such as carbon dioxide from the organism, which is a byproduct of cellular respiration.
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How many electrons are in the calcium ion created by the calcium atom losing two electrons?
Answers
Calcium ion created by the calcium atom losing two electrons has 18 electrons.
A neutral calcium atom has 20 electrons. When it loses two electrons, it becomes a calcium ion with a +2 charge. Since electrons have a negative charge, a calcium ion with a +2 charge will have 2 fewer electrons than a neutral calcium atom.
The calcium ion is a positively charged ion that has lost two electrons from the neutral calcium atom. It has a 2+ charge and is represented as Ca2+. The electronic configuration of the calcium ion is 1s² 2s² 2p⁶ 3s² 3p⁶, which means it has a total of 18 electrons. Thus, a calcium ion with a +2 charge will have 18 electrons.
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draw the structure of two geometric isomers with the empirical formula c5h8o that give a positive iodoform test.
Answers
The positive iodoform test indicates the presence of a methyl ketone or a compound that can undergo oxidation to form a methyl ketone. In the case of C5H8O, two geometric isomers that can give a positive iodoform test are trans-2-pentene-1-ol and cis-3-penten-2-ol. Here are their structures:
Trans-2-pentene-1-ol:
H
|
H - C = C - C - C - OH
| |
H H
Cis-3-penten-2-ol:
H
|
H - C = C - C - OH
| |
H H
Both of these isomers have the empirical formula C5H8O and can undergo oxidation to form a methyl ketone, which will react with iodine and hydroxide ions to produce a yellow precipitate of iodoform.
It's important to note that the structures provided are examples of geometric isomers that fit the given empirical formula and can give a positive iodoform test. The actual arrangement of atoms in space may vary depending on the specific isomer.
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what is the purpose of the lower air dam in the front of the vehicle?
Answers
The purpose of the lower air dam in the front of a vehicle is to improve aerodynamics and increase fuel efficiency. The air dam, also known as a front spoiler or splitter, is typically a protruding lip or panel located at the bottom of the front bumper.
When the vehicle is in motion, the air dam helps to redirect the airflow underneath the vehicle. It creates a smoother flow of air, reducing turbulence and minimizing drag. By reducing aerodynamic drag, the vehicle experiences less resistance, allowing it to move more efficiently through the air.
The improved aerodynamics provided by the lower air dam can result in reduced fuel consumption, as the engine does not have to work as hard to overcome air resistance. This makes the vehicle more fuel-efficient and can contribute to better overall performance.
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calculate the number of moles of magnesium, chlorine, and oxygen atoms in 2.70 moles of magnesium perchlorate, mg(clo4)2 .
Answers
The number of moles of magnesium, chlorine, and oxygen atoms in 2.70 moles of magnesium perchlorate is 2.70, 5.40, 21.60.
The formula of the compound is Mg(ClO4)2.
From the formula, we can see that 1 molecule of Mg(ClO4)2 contains 1 atom of Mg, 2 atoms of Cl and 8 atoms of O.
So 2.70 mol Mg(ClO4)2 contains
1 * 2.70 mol Mg = 2.70 mol Mg
2 * 2.70 mol Cl = 5.40 mol Cl
8 * 2.70 mol O = 21.60 mol O
So, the required answer is 2.70, 5.40, 21.60.
Therefore, the number of moles of magnesium, chlorine, and oxygen atoms in 2.70 moles of magnesium perchlorate is 2.70, 5.40, 21.60.
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Imagine we are mining blueberries and the berry is the ore and potassium in the berry is the true valuable product.
Assuming that we could get perfect separation, what percentage of the blueberry is still a waste product (ending up in tailing pond or leach heap) for 500 Grams of blueberries if 148 grams of blueberries contains approximately 115 mg of potassium?
Answers
Approximately 499.61622 grams of the 500 grams of blueberries would be considered waste product, which is approximately 99.92% of the total weight.
To determine the percentage of the blueberry that is considered waste product, we need to calculate the amount of potassium in 500 grams of blueberries and subtract it from the total weight of the blueberries.
First, we can find the amount of potassium in 500 grams of blueberries using the given ratio:
148 grams of blueberries contain approximately 115 mg of potassium.
So, the amount of potassium in 500 grams of blueberries can be calculated as follows:
(115 mg / 148 g) * 500 g = 383.78 mg
Next, we subtract the amount of potassium from the total weight of the blueberries:
500 g - 383.78 mg = 499.61622 g
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what change would you expect on the rate of the sn2 reaction of 1-iodo-2-methylbutane with cyanide ion if the nucleophile concentration is unchanged and the alkyl halide concentration is doubled ? what change would you expect on the rate of the reaction of ethanol with 2-iodo-2-methylbutane if the nucleophile concentration is unchanged and the alkyl halide concentration is doubled ?
Answers
If the nucleophile concentration is unchanged and the alkyl halide concentration is doubled; the rate of reaction remains the same, it is unchanged.
The rate of reaction of tertiary alkyl halides with a nucleophile is independent of the concentration of the nucleopohile but depends only on the initial concentration of the alkyl halide, because tertiary alkyl halides reacts via SN1 mechanism.
For an SN2 reaction, the rate of reaction depends both on the alkyl halide concentration and the nucleophile concentration. If we unchange the concentration of the nucleophile and double the concentration of the alkyl halide, the rate of reaction just remains the same because the reaction is bimolecular.
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