Compute ∫c . dr along the curve 0 ≤t ≤ 1
Answers
The line integral of the function ∫c (xz + y²) along the curve C is equal to -9.
The line integral of ∫c (xz + y²) ds,
We need to parameterize the curve C
and then evaluate the integral using the parameterization.
The curve C is given by the vector function
r(t) = (-5-t)i + 2tj - 2tk, where 0 ≤ t ≤ 1.
To parameterize this curve in terms of s, the arc length parameter,
Find the speed or magnitude of the velocity vector r'(t), which is given by,
| r'(t) | = √( (-1)^2 + 2^2 + (-2)^2 )
= √(9)
= 3
So, the speed or magnitude of the velocity vector is a constant 3. Parameterize the curve C in terms of s as,
r(s)
= r(t(s))
= (-5-t(s))i + 2t(s)j - 2t(s)k,
where t(s) is the inverse function of the arc length function, which is given by,
s = ∫| r'(t) | dt
= ∫3 dt
= 3t + C
where C is a constant of integration that we can determine using the initial condition t(0) = 0,
C = s(0) = 0
⇒ t(s) = (s - C)/3
= s/3,
and the parameterization of the curve C in terms of s is,
r(s) = (-5-s/3)i + (2s/3)j - (2s/3)k, 0 ≤ s ≤ 3
Now ,evaluate the line integral along the curve C using this parameterization,
∫c (xz + y²) ds
= \(\int_{0}^{3}\) [(-5-s/3)(2s/3) + (2s/3)²] 3 ds
= \(\int_{0}^{3}\) (-10s/9 + 4s²/9) 3 ds
= \(\int_{0}^{3}\) (-10s + 4s²) ds
= [-5s² + (4/3)s³]\(|_{0}^{3}\)
= -45 + 36
= -9
Therefore, the value of the line integral is -9.
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The above question is incomplete, the complete question is:
Evaluate the line integral along the curve C
∫c (xz + y²) ds , C is the curve r(t) = ( -5 -t)i + 2tj -2tk , 0 ≤t ≤ 1
Related Questions
Use the figure below to find the missing sides and angles.
Answers
Answer:
AC = BC = 5
AB = 5√2
∠A = ∠B = 45
∠A = 90
Step-by-step explanation:
AC = 5 ( Reason : 5 squares are present in between A and C )
Similarly,
BC = 5
By Pythagoras theorem,
(AB)² = (AC)² + (BC)²
= 5² + 5²
= 2 * 5²
(AB)² = 2 * 5²
AB = 5√2
Since, sides AC and BC are equal,
∠A = ∠B = 45
Since, AC is perpendicular to BC,
∠A = 90
a professor at a local university noted that the exam grades of her students were normally distributed with a mean of 73 and a standard deviation of 11. students who made 59.99 or lower on the exam failed the course. what percent of students failed the course?
Answers
About 11.90% of students scored 59.99 or lower on the exam and failed the course (since this is a proportion, we can multiply it by 100 to get the percentage).
To determine the percentage of students who failed the course, we need to find the proportion of students who scored 59.99 or lower on the exam, and then convert this proportion to a percentage.
First, we need to standardize the cutoff score of 59.99 using the formula:
z = (x - μ) / σ
where x is the cutoff score, μ is the mean, and σ is the standard deviation.
Plugging in the values given in the question, we get:
z = (59.99 - 73) / 11 = -1.18
Next, we look up the proportion of scores below a z-score of -1.18 in a standard normal distribution table (or use a calculator or software). This proportion is approximately 0.1190.
Therefore, about 11.90% of students scored 59.99 or lower on the exam and failed the course (since this is a proportion, we can multiply it by 100 to get the percentage).
In other words, roughly 12% of the students failed the course based on the given criteria.
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The vertices of AABC are A(-5,5), B(-2,5), and C(-2,3). If AABC is reflected across the line y=1 to produce the image AA'B'C', find the coordinates of the vertex A after reflection of y=1
Answers
The coordinates point C are (x, y) = (-2, -1)
How do coordinates work?The graph's points for any line or polygonal form are referred to as coordinates. The points can be utilized for slope calculations, distance measurements, and other tasks.
The preimage and image's separations from the line of reflection are equal, according to the query.
After a reflection over the line y = 1, C's coordinates are (-2, -1)
The following reasons explain why the value above is accurate:
The ABC's provided vertices are A(-5, 5), B(-2, 5) and C. (-2,3)
The line y = 1 serves as the line of reflection to create the picture "A'B'C."
Required:
To get C"s coordinates following a reflection along the line y = 1,
Solution:
Assuming that (x, y) is the coordinate of point C and that its x-coordinate value is:
The x-value will not change as a result of a reflection across the x-axis since the line y = 1 is parallel to the x-axis.
if we consider it to be the mirror image of the point C(-2, 3), the x-coordinate of the point C' will be -2 .
Value for y-coordinate:
The difference between the reflecting line and the coordinates of the picture is the same as the difference between the coordinates of the pre-image and the reflecting line.
The point C(-2, 3) is located 3 y-values apart from the line y = 1, or 2 y-values away.
Consequently, the following is the distance of C"s y value from the reflecting line:
1 - y = 2
⇒ y = -1
Thus, (x, y) = is the coordinate system for the point C' (-2, -1)
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There were 5 Easter eggs hidden at a party. Kenny found 4 of them. What percent of the eggs did Kenny find ?
Answers
Answer:
Kenny found 80% of the eggs.
Step-by-step explanation:
(4 ÷ 5) × 100 = x
0.8 × 100 = x
80% = x
Kenny found 80% of the eggs.
Lindsay buys a bag of each size of bouncy ball she wants to put the same number of each size bouncy ball into five party favor bags how many of each size of bouncy ball well she put in a bag
Answers
Answer:
16 of each size of bouncy ball in a bag.
Step-by-step explanation:
Bouncy Balls mm = millimeters • Size Number in Bag • 27 mm 180 • 40 mm 80 • 45 mm 180
Since Lindsy wants to put the same number of each size of bouncy ball into 5 party favor bags.
Because, 40mm size of bouncy ball have the smallest number in a bag, we divide the number by 5. (i.e. 80 / 5 = 16)
Therefore, Lindsey should put 16 of each size of bouncy ball in a bag.
Hope this helps, have a nice day! :D
R-1.3 Algorithm A uses 10n log n operations, while algorithm B uses n2 operations. Determine the value n0 such that A is better than B for n ≥ n0.
R-1.4 Repeat the previous problem assuming B uses n √n operations.
I only need R-1.4!!
Answers
For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.
To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.
Algorithm A: 10n log n operations
Algorithm B: n√n operations
Let's set up the inequality and solve for n₀:
10n log n < n√n
Dividing both sides by n gives:
10 log n < √n
Squaring both sides to eliminate the square root gives:
100 (log n)² < n
To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.
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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.
R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.
R-1.3:
Algorithm A: \($10n \log n$\) operations
Algorithm B: \($n^2$\) operations
We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).
We need to compare the growth rates:
\($10n \log n < n^2$\)
\($10 \log n < n$\)
\($\log n < \frac{n}{10}$\)
To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.
By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.
R-1.4:
Algorithm A: \($10n \log n$\) operations
Algorithm B: \($n\sqrt{n}$\) operations
We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).
We need to compare the growth rates:
\($10n \log n < n\sqrt{n}$\)
\($10 \log n < \sqrt{n}$\)
\($(10 \log n)^2 < n$\)
\($100 \log^2 n < n$\)
To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).
Therefore, we can approximate that:
\($100 \log^2 n < n$\)
For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.
So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.
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If I took any two distinct prime numbers, and the number "1", would these numbers always be pairwise relatively prime? True O False
Answers
The statement is true. If we take any two distinct prime numbers, and the number "1", these numbers will always be pairwise relatively prime.
Two numbers are said to be pairwise relatively prime if their greatest common divisor (GCD) is equal to 1. In this case, since we are considering distinct prime numbers, their GCD will always be 1 since prime numbers have no common factors other than 1 and themselves. Therefore, any two distinct prime numbers will be relatively prime.
Similarly, when we consider the number "1", it is relatively prime to any other number because its only divisor is 1. Hence, when "1" is paired with any prime number, the GCD will be 1.
In summary, whether we consider two distinct prime numbers or pair them with the number "1", the resulting numbers will always be pairwise relatively prime.
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uppose that a certain data set contains the variable HEIGHT (giving a person's height) and the variable GENDER (coded O=female, 1=male). Then the y-intercept of the regression equation predicting HEIGHT from GENDER is given by: Select one: a. how much shorter females are than males, on average. b. how much taller males are than females, on average. c. the average height of females in the data set. d. the average height of males in the data set. e. the proportion of females in the data set. f. the proportion of males in the data set. g. it is not appropriate to interpret the y-intercept in this case.
Answers
The data set contains the variable height (giving a person's height) and the variable gender (coded O=female, 1=male). Then the y-intercept of the regression equation predicting height from gender is given by: option c) the average height of females in the data set.
The y- intercept of a direct retrogression relationship represents the value of one variable when the value of the other is zero. Non-linear retrogression models also live, but are far more complex. Retrogression analysis is a important tool for uncovering the associations between variables observed in data, but can not fluently indicate occasion. The data set contains the variable height (giving a person's height) and the variable gender (enciphered O = womanish, 1 = manly). also the y- intercept of the retrogression equation prognosticating height from gender is given by option c) the average height of ladies in the data set.
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I am having trouble figuring out this question, repost again...
A mountain climber ascends a mountain to its peak. The peak is 12,740 ft bone sea level. The climber then descends 200 ft to meet a fellow climber. Find the climber’s elevation above sea level after meeting the other climber.
Thank you I appreciate it
Answers
The ize of a rectangle i 25 cm by 16 cm. A quare ha the ame area a the rectangle. Find the
perimeter of the quare
Answers
The square has a 48 centimeter perimeter.
To find the perimeter of the square, we need to calculate its side length. The area of a rectangle is given by its length multiplied by its width, so we can use the given measurements of the rectangle to calculate its area: 25 cm x 16 cm = 400 cm². The area of a square is given by the square of its side length, so we can use the area of the rectangle to calculate the side length of the square: √400 cm² = 20 cm.
Thus, the perimeter of the square is equal to 4 times its side length, or 4 x 20 cm = 80 cm.
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Which is a prime number 63 , 7, 27, 33
Answers
Answer:
7
Step-by-step explanation:
63 can be divided by 3, 7, 9, 21
27 can be divided by 3, 9
33 can be divided by 3, 11
Answer:
The correct answer is 7.
Step-by-step explanation:
A prime number is a number whose factors only include 1 and that number itself, examples of prime numbers would be 2 (1; 2), 5 (1; 5), and 11 (1; 11). In order to find the prime number, you must calculate all factors in each number. 63 has the following factors: 1; 3; 7; 9; 21; 63, so it isn't a prime number. 27 has the following factors: 1; 3; 9; 27, so it isn't a prime number. 33 has the following factors: 1; 3; 11; 33, so it also isn't a prime number. 7 only has two factors, 1 and 7, meaning that it is a prime number. Hence, this would be the correct answer.
A sponge has a blue circle printed on it. The blue circle has a radius of 5 centimeters when the sponge is dry. When wet, the sponge expands, and the area of the blue circle increases by 44%. What is the radius, in centimeters, of the blue circle when the sponge is wet?
HELP PLSSS 59 POINTS!!!!
Answers
Answer:
7.20cm I think
........
A dataset is obtained in order to test a set of hypotheses concerning the population central location. A Q-Q plot is created and the data are shown to be normally distributed. Which procedure(s) are applicable?
Answers
When the data is shown to be normally distributed through a Q-Q plot, the following procedures are applicable for testing hypotheses concerning the population central location:
One-Sample t-test: This procedure can be used to test if the mean of the population is significantly different from a specified value. It assumes that the data is normally distributed.
Confidence Interval Estimation for the Mean: By constructing a confidence interval around the sample mean, we can estimate the range in which the population mean likely falls. This method relies on the assumption of normality.
Paired t-test: This procedure is used when comparing means of two related samples (e.g., before and after measurements) to determine if there is a significant difference. It assumes that the differences between pairs are normally distributed.
One-Way ANOVA: When comparing means across more than two groups, the one-way ANOVA can be used to test for significant differences. It assumes that the data in each group follows a normal distribution.
Repeated Measures ANOVA: This procedure is appropriate when analyzing data with repeated measures or within-subject designs. It tests for differences in means while considering the dependency between measurements and assumes normality.
In summary, when data is shown to be normally distributed through a Q-Q plot, procedures such as one-sample t-test, confidence interval estimation, paired t-test, one-way ANOVA, and repeated measures ANOVA can be applied to test hypotheses concerning the population central location.
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The circumference of a circular garden is 75.36 feet. What is the radius of the garden
Answers
Answer:
12 rounded to a whole number.
Step-by-step explanation:
75.36 divided by pi (3.14159) = 23.987. this is diameter (the length from one side of a circle to the other).
but we need to find the radius. the radius is half way across a circle.
23.987 divided by 2 = 11.993.
round this to a significant whole number and you get 12.
The radius of the garden is,
⇒ r = 12
We have to given that;
The circumference of a circular garden is,
⇒ C = 75.36 feet.
Since, We know that;
The circumference of a circle is,
⇒ C = 2πr
Substitute given values,
⇒ 75.36 = 2 × 3.14 × r
⇒ 75.36 = 6.28 r
⇒ r = 12
Thus, the radius of the garden is,
⇒ r = 12
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8. Which of the following equations has a
positive slope and a negative y-intercept?
A. y = 1.75x
B. y = 2/3x - 1
C. y = -4x + 7
D. y = -0.5-1
Answers
Answer:
B
Step-by-step explanation:
the 2/3x represents how much it will increase while the -1 represents the y-intercept
Given six pairs of non-identical twins, how many ways are there for six teachers to each choose two children with no one getting a pair of twins?
Answers
There are 66,295,011,200 ways for six teachers to each choose two children with no one getting a pair of twins.
The given problem deals with six pairs of non-identical twins and six teachers who need to choose two children each, ensuring that no teacher selects a pair of twins.
Let's begin by understanding the total number of ways the teachers can choose two children from the twelve available. To do this, we need to find the number of combinations of choosing two children from a set of twelve.
This can be calculated using the formula for combinations:
C(n, r) = n! / (r!(n-r)!)
Here, n represents the total number of items to choose from (in our case, 12 children), and r represents the number of items to be chosen at a time (2 children per teacher).
Substituting the values, we have:
C(12, 2) = 12! / (2!(12-2)!)
= 12! / (2! * 10!)
= (12 * 11 * 10!) / (2! * 10!)
= 12 * 11 / 2
= 66
Therefore, there are 66 different ways for each teacher to choose two children without any restrictions.
However, we need to account for the fact that no teacher should select a pair of twins. Let's consider the scenario where all six teachers choose two children without any restrictions. In this case, each teacher can choose from the available twelve children. The first teacher has twelve choices, the second teacher has eleven choices (as one child has been already selected), the third teacher has ten choices, and so on.
Using the multiplication principle, we can determine the total number of ways all six teachers can select two children without any restrictions:
Total ways without restrictions = 12 * 11 * 10 * 9 * 8 * 7
Now, let's consider the number of ways that result in a teacher selecting a pair of twins. Since there are six pairs of twins, each teacher has a 1/66 chance of selecting a specific pair of twins. Therefore, we need to subtract the number of ways a teacher can choose a pair of twins from the total ways without restrictions.
Number of ways a teacher can choose a pair of twins = 6 * (12 * 11 * 10 * 9 * 8 * 7) / 66
Finally, to find the number of ways for the six teachers to each choose two children with no one getting a pair of twins, we subtract the number of ways a teacher can choose a pair of twins from the total ways without restrictions:
Number of ways = Total ways without restrictions - Number of ways a teacher can choose a pair of twins
= (12 * 11 * 10 * 9 * 8 * 7) - (6 * (12 * 11 * 10 * 9 * 8 * 7) / 66)
= 66,355,443,200 - (3,991,680 / 66)
= 66,355,443,200 - 60,432,000
= 66,295,011,200
There are 66,295,011,200 ways for six teachers to each choose two children with no one getting a pair of twins.
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The price of Stock A at 9 A.M. was $14.89. Since then, the price has been increasing at the rate of $0.06 each hour. At noon the price of Stock B was $15.64. It begins to decrease at the rate of $0.16 each hour. If the two rates continue, in how many hours will the prices of the two stocks be the same?
In about __?__ hours, the prices of the two stocks will be the same.
Answers
Write an equation for each stock and set them to equal each other.
Stock a = 14.89 + 0.06h
Stock b = 15.64 - 0.16h
Set to equal each other:
14.89+ 0.06h = 15.64 -0.16h
Subtract 14.89 from both sides:
0.06h = 0.75 - 0.16h
Add 0.16h to both sides:
0.22h = 0.75
Divide both sides by 0.22:
H = 0.75/0.22
H = 3.409 hours round to 3.4 hours
Ken and Hamid run around a track.
It take Ken 80 seconds to complete a lap.
It take Hamid 60 seconds to complete a lap.
Ken and Hamid start running at the same time from the start line.
How many laps will they each have run when they next meet on the start line?
Answers
In a case whereby Ken and Hamid run around a track where it take Ken 80 seconds to complete a lap It take Hamid 60 seconds to complete a lap. the number of laps they will each have run when they next meet on the start line is that Ken will have run 3 laps and Hamid will have run 4.
How can the number of lapscalcluated?The LCM of 80 nd 60 seconnds can be written as 240, however when 240 seconds go then they will both be at the start line.
So the lap that Ken will covered in 240s = 240/80 = 3laps
So the lap that Hamid will covered in 240s = 240/60 = 4laps
Therefore, we can come into conclusion that Ken will have to run 3laps where Hamid will have run 4Laps.
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______ is when the beat is divided into smaller equal units of time.
A Syncopation
B : Meter
C: Tempo
D: Subdivision
Answers
D. Subdivision
"Subdivisions describe the division of the beat into evenly sized segments, denoted by a number. A two-note subdivision divides the beat into two (even) parts, while a six-note subdivision divides it into six." - Internet
Solve the equation for x.
x2 = 676
Answers
When solving for a variable, we try to get the variable (we are solving for) on one side, usually the left hand side, and have the rest of the equation on the other side, usually on the right hand side, and you get your answer!
When looking at the equation 2x = 676 what could we do to get the 'x' variable alone? The first thing that comes out to me is to divide the left hand side by two. This will result in just 'x'.
And make sure that any operation you do on one side, make sure to do the same on the opposite side.
2x = 676
x = 676 / 2
x = 338
Hope this answer helps you and your quest at getting better at mathematics!
We have learned that in a well-known military marathon, runners are not allowed to listen to their iPods during the race because sounds and images that delight the brain can lead to better body performance. With this in mind, what is one kind of place you could work out in to help your workout? What is one place that might make your workout harder? Explain.
Answers
The one place which could make the workout easier is the place which has a good nature.
The one place which could make the workout harder is the place which does not have good environment.
Given that,
In a well-known military marathon, runners are not allowed to listen to their iPods during the race because sounds and images that delight the brain can lead to better body performance.
If you like to work out in a good mood but is not allowed to listen to music, then the one place which is good for workout would be with good nature and environment.
The workout will get harder if the environment is not clean.
Hence good environment is required for a good workout and a bad environment makes workout harder.
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PLEASE I NEED THIS QUICK!!!!!
Susan wants to make pumpkin bread and zucchini bread for the school bake sale. She has 15 eggs and 16 cups of flour in her pantry. Her recipe for one loaf of pumpkin bread uses 2 eggs and 3 cups of flour. Her recipe for one loaf of zucchini bread uses 3 eggs and 4 cups of flour. She plans to sell pumpkin bread loaves for $5 each and zucchini bread loaves for $4 each. Susan wants to maximize the money raised at the bake sale. Let x represent the number of loaves of pumpkin bread and y represent the number of loaves of zucchini bread Susan bakes.
What is the objective function for the problem?
P = 15x + 16y
P = 5x + 7y
P = 5x + 4y
P = 4x + 5y
Answers
The amount of money raised can be calculated by multiplying the number of pumpkin bread loaves (x) by the selling price of each pumpkin bread loaf ($5), and adding it to the product of the number of zucchini bread loaves (y) and the selling price of each zucchini bread loaf ($4).
Therefore, the objective function for this problem is:
P = 5x + 4y
So, the correct option is:
P = 5x + 4y
Please answer please ASAP * please don’t answer if you don’t know please .
Answers
Answer:
x = 26
Step-by-step explanation:
1. Information
One can partition this figure into three different parts, two congruent triangles, and one rectangle. To find the value of x, one has to find the base of the two triangles, and then the base of the rectangle. Since opposite sides are congruent, the base of the rectangles is 10. To find the base of the triangle, one has to use the Pythagorean theorem.
2. Base of the rectangle
Again, opposite sides are congruent, hence the base of the rectangle is equivalent to the top part. Hence the base is 10.
3. Base of the triangle
Use the Pythagorean theorem;
\(a^{2}+b^{2} = c^{2}\\a-leg\\b-leg\\c-hypotenuse\)
Substitute in the given value and solve
\(a^{2}+15^{2} = 17^{2}\\a^{2} + 225 = 289\\a^{2} = 64\\a = 8\)
4. Finding x
There are two congruent trinagles, hence one has to add the base of the triangle twice. The equation will be
x = base_of_triangle + base_of_rectagle + base_of_triangle
x = 8 + 10 + 8
x = 26
Find the volume of radius 7 cm in diameter of 12 cm in 3.14
Answers
The volume of a sphere with a radius of 7 cm (or diameter of 12 cm) is 904.32 cubic centimeters.
To find the volume of a sphere with a radius of 7 cm, we can use the formula:
V = (4/3) * π * r^3
where V represents the volume and r represents the radius. However, you mentioned that the diameter of the sphere is 12 cm, so we need to adjust the radius accordingly.
The diameter of a sphere is twice the radius, so the radius of this sphere is 12 cm / 2 = 6 cm. Now we can calculate the volume using the formula:
V = (4/3) * π * (6 cm)^3
V = (4/3) * 3.14 * (6 cm)^3
V = (4/3) * 3.14 * 216 cm^3
V = 904.32 cm^3
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Three side lenghts of 5.2,6.3, and 10.5 units will form exactly one unique triangle
Answers
True, the three sides will form exactly one unique triangle.
What is a triangle?A triangle is three dimensional shape, whose third length is less than the sum of the first and second length.
let the first length = alet the second length = blet the third length = k(b - a) < k < (b + a)
(6.3 - 5.2 ) < k (6.3 + 5.2 )
1.1 units < k < 11.5 units
The third length = 10.5 units which is greater than 1.1 units and less than 11.5 units.
Thus, the three sides will form exactly one unique triangle.
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In a student president race student A received 9 votes received by student B if student A received 540 votes, how many votes did student B receive?
Answers
Answer: 60 Votes
Step-by-step explanation:
540 divded by 9 which equals 60 votes.
So Student B received 60 votes.
60 votes was received by student B.
540/9=60
1/5 divied by 2 as a fraction
Answers
The simplified form of the expression 1/5 divied by 2 as a fraction is 1/10.
What is 1/5 divied by 2 ?Given the expression in the question;
1/5 divied by 2
1/5 ÷ 2
To simplify, multiply 1/2 by the reciprocal of 2
1/5 ÷ 2
1/5 × 1/2
Simplify
( 1 × 1 ) / ( 5 × 2 )
( 1 ) / ( 5 × 2 )
Multiply 5 and 2
( 1 ) / ( 10 )
1/10
Therefore, the simplified form is 1/10.
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Having a bit of trouble. Would anyone mind helping me.
Answers
Explanation: 24/8 = 3
12/3 = 4
WILL ARK BRAINLY!
Evaluate.
5⋅4^0
Answers
Answer:
1
Step-by-step explanation:
$x$ $4$ $1$
$10$
$y$ $10$
Answers
9514 1404 393
Answer:
see attached
Step-by-step explanation:
The ratios in the table must be equivalent if it is to be filled in with something other than random numbers.
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The second row is 10/4 = 2.5 times the first.
The first row is 4/10 = 0.4 times the second.
