Complete the pairs of corresponding parts if RST=TXY

The equation d=65t models the distance, d, that Malcolm's family travels after t hours. Malcolm's family travels 65 miles per hour faster than Theo's family.

The equation d=65t models the distance, d, that Malcolm's family travels after t hours. To calculate how much faster Malcolm's family travels than Theo's family, we must first know the speed of Theo's family. Let's say Theo's family travels at 25 miles per hour. To calculate the difference in speed between the two families, we must subtract 25 mph from 65 mph. The difference is then 40 mph, meaning Malcolm's family travels 40 mph faster than Theo's family.

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Answer:

50 oz because 15 is 30 percent of 50

Step-by-step explanation:

Answer:

there was 50oz of juice originally

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

gay by gay

Answer: 3/80 = 0.0375

Answer:

You subtracted 25 from both sides.

Step-by-step explanation:

To move one part of the equation to the other side, you need to do the opposite. 25 is already negative(or being subtracted) so you need to add it to both sides to cancel it out on the left.

10x=-75+25

10x=-50

then divide both sides by 10

x=-5

Answer:

It is C : 1/4 mile over 36 seconds

Step-by-step explanation:

Step-by-step explanation:

no this is a test I cant hlep i will tell ms.jules you are searching for the answers

The average of the sample ranges for the weight of packages of Skittles is 0.11. So, the correct answer is (e) 0.11.

To find the average of the sample ranges for the weight of packages of Skittles, we first calculate the range for each sample. The range is the difference between the maximum and minimum values in each sample.

Sample 1: Range\(= 3.62 - 3.58 = 0.04\)

Sample 2: Range\(= 3.65 - 3.49 = 0.16\)

Sample 3: Range \(= 3.65 - 3.45 = 0.20\)

Sample 4: Range \(= 3.64 - 3.54 = 0.10\)

Sample 5: Range\(= 3.62 - 3.49 = 0.13\)

Next, we calculate the average of these sample ranges:

A\(verage = (0.04 + 0.16 + 0.20 + 0.10 + 0.13) / 5 = 0.11\)

Therefore, the average of the sample ranges for the weight of packages of Skittles is \(0.11\). So, the correct answer is (e) \(0.11.\)

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Answer:

239 mm^2

Step-by-step explanation:

We will split the figure into 3 pieces

The bottom rectangle

A = l*w = 7*3 = 21 mm^2

The top rectangle

A = l*w = 5*10 = 50 mm^2

The right triangle

A = 1/2 b*h = 1/2 ( 16) * (16+5) = 8 * (21) = 168 mm^2

The total area is 21+50+168 =239

Multiplication operation is the inverse of the one in the given equation which is 9 = p/8.

What is an inverse?

The opposite of another operation is referred to as the "inverse" in mathematics. The operations that cancel out or are the opposite of one another are referred to as inverse operations. The work of a pair is reversed by an inverse operation.

We are given an equation as 9 = p/8.

In this equation,  we can see that the operation used is division.

We know that inverse of division is multiplication.

Hence, multiplication operation is the inverse of the one in the given equation.

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Answer: 29

Step-by-step explanation:

Uma is correct, because getting an even number is an event.

The term probability refers to the likelihood of an event occurring.

Given that;

Bridget says that when a standard number cube is rolled getting an even number is an outcome.

And, Uma says that getting an even number is an event.

Now,

We know that;

When a standard number cube is rolled then getting an even number is an event.

Hence, Uma statement is correct.

Thus, Uma is correct, because getting an even number is an event.

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The longest real-life distance is approximately 205.71 km.

To find the longest real-life distance, we need to determine which side of the triangle corresponds to the longest real-life distance.

Given that the shortest real-life distance is 120 km, we can use this information to set up a proportion between the lengths on the map and the real-life distances.

Let's assume that the longest side of the triangle corresponds to the longest real-life distance, which we'll call "x" km.

Using the proportion:
7 cm / 120 km = 12 cm / x km

We can cross multiply and solve for x:
7x = 120 * 12
7x = 1440
x = 1440 / 7
x ≈ 205.71 km

Therefore, the longest real-life distance is approximately 205.71 km.

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The mean of a observed values approaches the population mean more and more as the number of data points gathered rises.

The average calculated from the group members, distribution, or population is known as the population mean.

Thus, choose a population with a finite mean and a random sample of observations. The mean of a observed values approaches the population mean to a greater extent as the number of data gathered rises.

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Suppose that foreign citizens decide to purchase more U.S. pharmaceuticals and U.S. citizens decide to buy stock in foreign corporations. Other things being the same, these actions would lead to an increase in demand for U.S. pharmaceuticals and a decrease in demand for U.S. stocks, leading to changes in the relative prices of these assets.

An increase in demand for U.S. pharmaceuticals would lead to higher prices for these products, assuming that the supply of pharmaceuticals remains constant. This increase in demand could benefit U.S. pharmaceutical companies, as they would be able to charge higher prices for their products, resulting in increased revenues and profits. However, higher prices could also result in reduced affordability and access to these products for U.S. consumers.

On the other hand, a decrease in demand for U.S. stocks could lead to lower prices for these securities, assuming that the supply of foreign stocks remains constant. This decrease in demand could negatively impact U.S. investors who hold these stocks, as the value of their holdings would decline. However, it could also lead to increased investment in foreign corporations, potentially benefiting these companies and the economies in which they operate.

Overall, the actions of foreign and U.S. citizens can significantly affect the prices of different assets and the performance of various industries and economies. Understanding these relationships and dynamics is important for investors and policymakers in making informed decisions about investment and trade.

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Let's denote the ages of the two remaining men as x and x + 3 (since one is 3 years older than the other).

We know that the average age of 6 men is 35 years. So, the sum of their ages is 6 * 35 = 210 years.

We also know that the average age of four of them is 32 years. So, the sum of their ages is 4 * 32 = 128 years.

To find the sum of the ages of the two remaining men, we subtract the sum of the ages of the four men from the sum of the ages of all six men:

210 - 128 = 82 years.

Now, we can set up an equation to solve for the ages of the remaining two men:

x + (x + 3) = 82.

Combining like terms, we get:

2x + 3 = 82.

Subtracting 3 from both sides:

2x = 79.

Dividing both sides by 2:

x = 39.5.

So, one of the remaining men is 39.5 years old, and the other is 39.5 + 3 = 42.5 years old.

a. AB = FG, AC = FH, BC = GH

b. Remember that FG is the same as AB. This means that their values are equivalent. Therefore, FG = 9.

c. HG is the same as CB. If CB is 12, then HG must also be 12.

d. To solve for x, we'll need to set up an equation. We can do this by taking one of our known pairs of congruent sides and setting them equal to each other.

AB = FG

AB = 9

FG = 2x + 1

9 = 2x + 1

2x = 8

x = 4

Hope this helps!

Applying the physics of motion, the time now, when they are 111 miles apart, is 4:10 p.m.

Let the time taken for the trains to be 111 miles apart be T.

Then at that time, T, the faster train, which is 82 mph, should have traveled a distance of 82T miles.

D1 = 82T

At the same time, T, the slower train, which is 66 mph, should have traveled a distance of 66T miles.

D1 = 66T

The total distance traveled by both the trains is D1 + D2 = D = 82T + 66T.

D = 148T

From the data provided in the question, D = 111

Hence, 148T = 111

Solving the equation, the time T becomes

T = 111÷148

T = three and four hours

converting it into minutes,

T = 45 mins.

The current time = the time at which both the trains left + 45 mins.

The current time is 3:25 p.m. + 45 minutes.

The current time is 4:10 p.m.

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Answer:

x=1

Step-by-step explanation:

hope this helps and hope its correct

TCP provides error checking to ensure reliable data delivery, making option A the correct answer. Only the propagation delay is not caused by the store-and-forward strategy employed by switching devices.

TCP (Transmission Control Protocol) provides error checking as part of its services. It ensures reliable data delivery by using acknowledgments and sequence numbers to detect and recover from packet loss, errors, or out-of-order delivery. When a TCP receiver receives data, it sends an acknowledgment (ACK) back to the sender to confirm the successful reception of packets. If the sender does not receive an ACK for a particular packet within a specified timeout period, it assumes the packet was lost or damaged and retransmits it.

TCP provides error checking to ensure reliable data delivery, making option A the correct answer.

The propagation delay is the time it takes for a signal to travel from the source to the destination. It is determined by the physical distance between the devices and the speed of signal propagation in the transmission medium. The propagation delay is an inherent characteristic of the medium and cannot be eliminated by switching devices or other strategies.

The other three options—processing delay, queuing delay, and transmission delay—are all caused by the store-and-forward strategy used by switching devices. Processing delay refers to the time taken to examine and process the packet headers. Queuing delay occurs when packets have to wait in a queue before being transmitted. Transmission delay is the time it takes to push the bits onto the transmission medium.

Among the given options, only the propagation delay is not caused by the store-and-forward strategy employed by switching devices.

3. The correct answer is A. The system is very well-engineered.

In a statistical multiplexing system, the queuing delay is the delay experienced by packets waiting in a queue before being transmitted. If the average queuing delay is very close to zero, it indicates that the system is well-engineered and efficiently managing its resources. A well-designed system can minimize or eliminate queuing delays by appropriately allocating resources and ensuring efficient scheduling algorithms.

Traffic intensity, which represents the ratio of the average traffic load to the transmission capacity, does not directly determine the queuing delay. It is possible to have low queuing delays even with high traffic intensity if the system is well-designed.

When the average queuing delay is close to zero, it suggests that the system is well-engineered and efficiently utilizing its resources, as stated in option A.

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Answer:

-4.2c-6.9

Step-by-step explanation:

-6.5c-5.1+2.3c-1.8

combine like terms

-4.2c-6.9

32 miles. ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Answer:

Option C. is the correct answer

Step-by-step explanation:

Choose any value of x and find the values of y. Then plot a graph using all that points. These will neither parallel nor perpendicular.

The function has a global maximum at the vertex (2/5, 41/25), and there are no local maxima or minima.

To find the critical numbers of the function f(x) = 4 - 5x/4 + x, we first need to find its derivative:

f'(x) = -5/4 + 1

f'(x) = -1/4

To find the critical numbers, we set f'(x) equal to zero and solve for x:

-1/4 = 0

This is never true, so there are no critical numbers for f(x).

Since there are no critical numbers, there are no local maxima or minima for the function. Instead, we can analyze the behavior of the function to determine if it has any extrema.

One way to do this is to examine the end behavior of the function. As x approaches positive or negative infinity, the leading term of the function is -5x/4, which dominates the constant term. Therefore, as x becomes large in either direction, the function approaches negative infinity. This suggests that the function has a global maximum at its vertex.

To find the vertex, we can complete the square:

f(x) = 4 - 5x/4 + x

\(f(x) = -(5/4)x^2 + x + 4\)

\(f(x) = -(5/4)(x^2 - (4/5)x) + 4\)

\(f(x) = -(5/4)(x - 2/5)^2 + 4 + (5/4)(2/5)^2\\f(x) = -(5/4)(x - 2/5)^2 + 41/25\)

Therefore, the function has a global maximum at the vertex (2/5, 41/25), and there are no local maxima or minima.

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Answer:

\(T_{10} - T_7 = 112\)

Step-by-step explanation:

Given

\(T_9 = 63\)

Required

Find \(T_{10} - T_7\)

From the question, we have that:

Each sequence = 2 * Previous sequence + 1;

i.e.

\(T_n = 2 * T_{n - 1} + 1\)

Considering the 9th sequence;

\(T_9 = 2 * T_8 + 1\) ------ Equation 1

Considering the 8th sequence;

\(T_8 = 2 * T_7 + 1\)

Substitute \(2 * T_7 + 1\) for \(T_8\) in equation 1

\(T_9 = 2 * T_8 + 1\) becomes

\(T_9 = 2 * (2 * T_7 + 1) + 1\)

Open bracket

\(T_9 = 2 * 2 * T_7 + 2*1 + 1\)

\(T_9 = 4T_7 + 2 + 1\)

\(T_9 = 4T_7 + 3\)

Substitute 63 for \(T_9\)

\(63 = 4T_7 + 3\)

Subtract 3 from both sides

\(63 - 3 = 4T_3 + 3 - 3\)

\(60 = 4T_3\)

Divide both sides by 4

\(\frac{60}{4} = \frac{4T_3}{4}\)

\(15 = T_7\)

\(T_7 = 15\)

Considering \(T_{10}\)

\(T_1_0 = 2 * T_9 + 1\)

Substitute 63 for \(T_9\)

\(T_1_0 = 2 * 63 + 1\)

\(T_1_0 = 126 + 1\)

\(T_1_0 = 127\)

Calculating \(T_{10} - T_7\)

\(T_{10} - T_7 = 127 - 15\)

\(T_{10} - T_7 = 112\)

Hence, the 10th - 7th number is 112

Answer:

m = 0.666667*​x+​1 is the answer

Step-by-step explanation:

Answer:

x-intercept(s): (−6,0)

y-intercept(s): (0,8)

Step-by-step explanation:

By rearranging x = 7y - 5 to make y the subject, we get

x + 5 = 7y ( By transposition method )

or, \( \huge \purple {\tt {\frac{x + 5}{7} = y}} \)

\( \huge \pink {\tt {y = \frac{x + 5}{7}}} \)

The equation x = 7y - 5 can be rearranged as y = x/7 + 1/7 after making the subject as y.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

The equation is:

x = 7y - 5

To make the subject as y:

x + 5 = 7y

Or

7y = x + 5

y = 1/7[x + 5]

y = x/7 + 1/7

Thus, the equation x = 7y - 5 can be rearranged as y = x/7 + 1/7 after making the subject as y.

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Answer:

\((-1) \times (-2) \times (-3) \times (-4) \times (-5) = - 120\)

Step-by-step explanation:

By the rule of Integer multiplications,

\((-1) \times (-2) \times (-3) \times (-4) \times (-5) = [ (-1) \times (-2) ] \times [(-3) \times (-4)] \times (-5)\)

                                                      \(= [2] \times [12] \times (-5)\)

                                                      \(= -120\)

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