Compare these numbers.

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=
none of the above

9514 1404 393

Answer:

Step-by-step explanation:

The blanks you're to fill in explain the steps.

The y-intercept is the value of the function when x=0. It is where the graph crosses the y-axis.

  f(0) = a·b^0 = a·1 = a

Reading the y-intercept from the graph, we see ...

  The y-intercept is 3. The a-value of the function is 3.

__

The point when x=1 is ...

  f(1) = a·b^1 = 3b

Reading the value from the graph, we find the point to be (1, 6). This means ...

  3b = 6

  b = 2 . . . . . . . divide both sides by 3

 The point when x=1 is (1, 6). The b-value of the function is 2.

 The equation of the function is f(x) = 3·2^x.

Using the computational formula for the sample, the SS is 37.50, the variance is 5.36, and the standard deviation is 2.31.

The computational formula is given as follows:

SS = Sum of Squares = ΣX^2 - ((ΣX)^2 / n) ………………………. (1)

X = each value

n = number of values = 8

Therefore, we have:

ΣX^2 = 14^2 + 20^2 + 17^2 + 16^2 + 12^2 + 16^2 + 15^2 + 16^2 = 2,022

(ΣX)^2 = (14 + 20 + 17 + 16 + 12 + 16 + 15 + 16)^2 = 15,876

Substituting all the values into equation (1), we have:

SS = 2,022 - (15,876 / 8) = 37.50

Variance = S^2 = SS / (n – 1) = 37.50 / (8 – 1) = 5.35714285714286, or 5.36

Standard deviation = S = Variance^0.5 = 5.35714285714286^0.5 = 2.31

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The correct statement that F: "I agree. The ratios of consecutive x-values are constant, and the y-values are increasing at a constant rate."

To determine whether the function shown in the table is exponential, we need to analyze the relationship between the x-values and y-values.

The table shows x-values that are increasing by a power of 2 (1, 2, 4, 8, 16, 32, 64) and y-values that are increasing by a constant rate of 1 (0, 1, 2, 3, 4, 5, 6).

The constant ratio between consecutive x-values indicates exponential growth or decay.

In this case, the function is growing exponentially because the y-values are increasing at a constant rate.

Based on this information, we can conclude that the function is exponential.

Therefore, we agree with statement F: "I agree. The ratios of consecutive x-values are constant, and the y-values are increasing at a constant rate."

The other statements are incorrect because they do not accurately describe the relationship between the x-values and y-values in an exponential function.

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Answer:

(a) Null Hypothesis, \(H_0\) : \(\mu\) = 24  

    Alternate Hypothesis, \(H_A\) : \(\mu\neq\) 24  

(b) The​ P-value is 0.004.

(c) Reject Upper H 0 because the​ P-value is less than the alpha = 0.01 level of significance.

(d) There is sufficient evidence at the alpha equals 0.01 level of significance to conclude that the population mean is different from 24.

Step-by-step explanation:

We are given that a simple random sample of size n = 15 is drawn from a population that is normally distributed. The sample mean is found to be x overbar = 18.3 and the sample standard deviation is found to be s = 6.3.

Let \(\mu\) = population mean

(a) Null Hypothesis, \(H_0\) : \(\mu\) = 24      {means that the population mean is 24}

Alternate Hypothesis, \(H_A\) : \(\mu\neq\) 24     {means that the population mean is different from 24}

The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;

                               T.S.  =  \(\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }\)  ~ \(t_n_-_1\)

where, \(\bar X\) = sample mean = 18.3

            s = sample standard deviation = 6.3

            n = sample size = 15

So, the test statistics =  \(\frac{18.3-24}{\frac{6.3}{\sqrt{15} } }\)  ~ \(t_1_4\)

                                    =  -3.504

The value of t-test statistics is -3.504.

(b) Now, the P-value of the test statistics is given by;

               P-value = P( \(t_1_4\) < -3.504) = 0.002 or 0.2%

For the two-tailed test, the P-value is calculated as = \(2 \times 0.002\) = 0.004 or 0.4%.

(c) Since the p-value of the test statistics is less than the level of significance as 0.002 < 0.01, so we will reject our null hypothesis.

(d) This means that we have sufficient evidence at the alpha equals 0.01 level of significance to conclude that the population mean is different from 24.

Answer:-39

Step-by-step explanation:

The first thing is to open the bracket.

By doing that, the question becomes -37-2.

note that plus×minus=minus.

Hence,-39 as the final answer

Basic Proportionality Theorem (BPT): If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points then the other two sides are divided in the same ratio. This is also known as Thales theorem.

Given:

\(\angle Q= 90^\circ , XY \ || \ QR, PQ = 6 \ \text{cm}, PY = 4 \ \text{cm} \ \text{and} \ PX : XQ = 1 : 2\)

Since, \(XY \ || \ QR\),

\(PX/XQ = PY/YR\)

[ By Thales theorem (BPT)]

\(\dfrac{1}{2} = PY/YR\)      \([PX : XQ = 1 : 2]\)

\(\dfrac{1}{2} = 4 /(PR - PY)\)

\([YR= PR - PY]\)

\(\dfrac{1}{2} = 4 /(PR - 4)\)

\(PR - 4 = 2 \times 4\)

\(PR - 4 = 8\)

\(PR = 8 +4\)

\(PR = 12 \ \text{cm}\)

In right \(\Delta PQR\),

\(PR^2 = PQ^2 + QR^2\)

[ By Pythagoras theorem]

\(12^2 = 6^2 + QR^2\)    \([\text{Given} : PQ= 6 \ \text{cm}]\)

\(144 = 36 + QR^2\)

\(144 - 36 + QR^2\)

\(108= QR^2\)

\(QR =\sqrt{108} =\sqrt{3\times36} = 6\sqrt{3} \ \text{cm}\)

Hence, the lengths of PR and QR is 12 cm and \(6\sqrt{3}\) cm.

Answer:

2a+16

Step-by-step explanation:

Your first distribute 2(a+8) and get 2a+16.

Whenever a number is in front of a group of numbers in parenthesis, then it  is always multiplying. You have to multiply both numbers, and that's how I got 2a+16. Hopefully this helps!

The reflection line  that maps polygon ABCDE to polygon A' B' C' D' E' is the y-axis.

The image is reflected through a line known as a reflection line. A pattern is said to mirror another pattern, and then every point in the pattern is equidistant from every corresponding point in the other pattern. The reflected image must be the same shape and size, but the image is in the opposite direction.

In order to determine the line of reflection that maps  polygon ABCDE to polygon A' B' C' D' E', we must find a symmetrical line  equidistant from each corresponding pair of points. If you project the image across the x-axis, vertex A (-1, -4) is mapped to A' (13, -4) and vertex E (1, -6) is mapped to E'. (11, 6). Therefore, the reflection line must be the x-axis.

If we map the image to the cross x=6, vertex A (-1, -4) would correspond to A' (13, -4) and vertex E (1, -6) would correspond to E' (3, 6). ). Therefore, the reflection line cannot be x=6.

If we project the pattern perpendicular to y=-3, the point A (-1, -4) is opposite to the point A' (-7, -4) and the vertex E (1, -6)  to  the point E . (7, 6). Therefore, the reflection line  cannot be y=-3.

 If you project the image across the y-axis, point A (-1, -4) is mapped to point A' (-13, -4) and  vertex E (1, -6) is mapped to E. (-11 , 6). Therefore, the reflection line  must be the y-axis.

 Therefore, the reflection line  that maps  polygon ABCDE to polygon A' B' C' D' E' is the y-axis.

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Answer:

Area of the given sector = 130.9 cm²

Step-by-step explanation:

Area of a sector is given by the formula,

Area of the sector = \(\frac{\theta}{2\pi }\times (\pi r^{2})\)

Area of the sector of the circle given in the picture = \(\frac{\frac{5\pi }{6} }{2\pi }[\pi (10)^{2}]\)

                                                                               = \(\frac{5}{12}(100\pi )\)

                                                                               = 130.8996

                                                                               ≈ 130.9 cm²

The function for fine at every speed should be doubled in construction zones is f(n)= -8.75n+637.5.

Functions are the fundamental part of the calculus in mathematics. The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input x.

The coordinate points from the graph are (10, 550) and (30, 200).

Here, slope = (200-550)(30-10)

= -350/20

= -35/2

= -17.5

Substitute m= -17.5 and (x, y)=(10, 550) in y=mx+c, we get

550=-17.5(10)+c

c=550+175

c=725

So, the equation is y= -17.5x+725

Thus, f(n)= -17.5n+725

a) The fine at every speed should go up by $10.

So, the coordinates are (10, 560) and (30, 210)

New slope (m)= (210-560)(30-10)

= -350/20

= -35/2

= -17.5

Substitute m= -17.5 and (x, y)=(10, 560) in y=mx+c, we get

560=-17.5(10)+c

c=550+175

c=735

So, the equation is y= -17.5x+735

Thus, f(n)= -17.5n+735

b) The fine at every speed should be doubled in construction zones.

So, the coordinates are (20, 550) and (60, 200)

New slope (m)= (200-550)(60-20)

= -350/40

= -8.75

Substitute m= -8.75 and (x, y)=(20, 550) in y=mx+c, we get

550=-8.75(10)+c

c=550+87.5

c=637.5

So, the equation is y= -8.75x+637.5

Thus, f(n)= -8.75n+637.5

Therefore, the function for fine at every speed should be doubled in construction zones is f(n)= -8.75n+637.5.

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Answer:

To find the coordinates of A' after the translation, we need to apply the motion rule to the coordinates of A:

(x, y) → (x + 2y - 5, y - 6)

Substituting the coordinates of point A, which is (4, -4), into this motion rule, we get:

A' = (4 + 2(-4) - 5, -4 - 6) = (-3, -10)

Therefore, the coordinates of A' after the translation are (-3, -10).

Answer:

nope

Step-by-step explanation:

but it's probably better than where i am

Answer:

50%

Step-by-step explanation:

if 2/2 is a whole you see its 100% but when its one half its 50%

1/2 can be 5/10 which is 50%

I added a chart for you to look at and remember! <3

—————

Thank you so much! -Doodle

—————

Answer:

\(\frac{(x-2)^2}{16}+\frac{(y-1)^2}{36}=1\)

Step-by-step explanation:

Notice how the vertices are on the same x-coordinate and the endpoints of the minor axis are on the same y-coordinate. This indicates that the ellipse is vertical (meaning the ellipse has a vertical major axis of length \(2a\)).

The equation for a vertical ellipse is \(\frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1\) where \((h,k)\) is the center of the ellipse, \((h,k\pm a)\) represents the coordinates of the vertices, and \((h\pm b,k)\) represents the coordinates of the endpoints of the minor axis (also called co-vertices).

The value of \(h\) is listed out for us as \(h=2\).

The value of \(k\) can be determined from taking the midpoint of the vertices. Because \(k=\frac{-5+7}{2}=1\), then \(1-a=-5\)  and \(1+a=7\) give us \(a=6\).

Lastly, to figure out \(b\), we solve the equations \(2+b=-2\) and \(2-b=6\) which both give \(b=-4\) as the solution.

Now, plugging in all our values gives us \(\frac{(x-2)^2}{(-4)^2}+\frac{(y-1)^2}{6^2}=1\) which translates to \(\frac{(x-2)^2}{16}+\frac{(y-1)^2}{36}=1\).

Therefore, the final equation of the ellipse that satisfies the given conditions is \(\frac{(x-2)^2}{16}+\frac{(y-1)^2}{36}=1\).

I've attached a graph of the ellipse with labels to help you visualize it.

The parameters that are needed to calculate a probability are listed as follows:

Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes, hence it is the same as a relative frequency.

The total number of periods is given as follows:

5 + 6 + 4 = 15.

The frequency of each class is given as follows:

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Answer:

8.33% probability that she does, in fact, have the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

\(P(B|A) = \frac{P(A \cap B)}{P(A)}\)

In which

P(B|A) is the probability of event B happening, given that A happened.

\(P(A \cap B)\) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive test

Event B: Has the disease

Probability of a positive test:

10% of 100-1 = 99%

90% of 1%

So

\(P(A) = 0.1*0.99 + 0.9*0.01 = 0.108\)

Positive test and having the disease:

90% of 1%

\(P(A \cap B) = 0.9*0.01 = 0.009\)

What is the conditional probability that she does, in fact, have the disease

\(P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.009}{0.108} = 0.0833\)

8.33% probability that she does, in fact, have the disease

we have that

alternate exterior angles

< 1 and <5

<2 and <6

alternate interior angles

<3 and <7

<4 and <8

same side interior angles

<3 and <4

<7 and <8

corresponding angles

<1 and <7

<8 and <6

<2 and <4

<3 and <5

Pairs that are congruent------> all pairs are congruent except same side interior angles)

< 1 and <5

<2 and <6

<3 and <7

<4 and <8

<1 and <7

<8 and <6

<2 and <4

<3 and <5

pairs that are supplementary (same side interior angles)

<3 and <4

<7 and <8

Given:

(a)

Value of function then x is 10.

so:

(b)

Function at x = 50 then:

(c)

At x = 200.

By answering the presented question, we may conclude that Sales Rep: expression This entity maintains information about sales reps such as SalesRepID and SalesRepName.

An expression in mathematics is a collection of representations, numbers, and conglomerates that mimic a statistical correlation or regularity. A real number, a mutable, or a mix of the two can be used as an expression. Mathematical operators include addition, subtraction, fast spread, division, and exponentiation. Expressions are often used in arithmetic, mathematic, and form. They are used in the representation of mathematical formulas, the solution of equations, and the simplification of mathematical relationships.

The ER diagram above depicts the database entities and their connections. Here's a quick rundown of each entity and its characteristics:

Employee: This object contains information on employees such as EmployeeID, Name, DateOfBirth, and Dependents.

ProductID, ProductName, ManufacturingDate, ExpiryDate, and SupplierID are all stored in this object.

Supplier: This entity holds supplier-specific information such as SupplierID, SupplierName, ContactPerson, and ContactNumber.

CustomerID, CustomerName, ContactPerson, and ContactNumber are all stored in the Customer entity.

Sales Rep: This entity maintains information about sales reps such as SalesRepID and SalesRepName.

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Answer:

50.75

Step-by-step explanation:

We have:

\(E[g(x)] = \int\limits^{\infty}_{-\infty} {g(x)f(x)} \, dx \\\\= \int\limits^{1}_{-\infty} {g(x)(0)} \, dx+\int\limits^{6}_{1} {g(x)\frac{2}{x} } \, dx+\int\limits^{\infty}_{6} {g(x)(0)} \, dx\\\\= \int\limits^{6}_{1} {g(x)\frac{2}{x} } \, dx\\\\=\int\limits^{6}_{1} {(4x+3)\frac{2}{x} } \, dx\\\\=\int\limits^{6}_{1} {(4x)\frac{2}{x} } \, dx + \int\limits^{6}_{1} {(3)\frac{2}{x} } \, dx\\\\=\int\limits^{6}_{1} {8} \, dx + \int\limits^{6}_{1} {\frac{6}{x} } \, dx\\\\\)

\(=8\int\limits^{6}_{1} \, dx + 6\int\limits^{6}_{1} {\frac{1}{x} } \, dx\\\\= 8[x]^{^6}_{_1} + 6 [ln(x)]^{^6}_{_1}\\\\= 8[6-1] + 6[ln(6) - ln(1)]\\\\= 8(5) + 6(ln(6))\\\\= 40 + 10.75\\\\= 50.74\)

Answer:

y = x+2

Step-by-step explanation:

(x1,y1) is (-4,-2) and (x2,y2) is (2,4)

Slope intercept form is y = mx+b

m = slope

b = add on

Slope = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

Substitute numbers

Slope = \(\frac{4-(-2)}{2-(-4)}\)

Two negatives = one positive

Simplify

\(Slope = \frac{4+2}{2+4}=\frac{6}{6}=1\)

The slope is 1

We can substitute y, x, and the slope

4 = 2*1 + b

4 = 2+b

b = 2

Slope intercept form is y = mx+b

Answer is y = x+2

Hope this helps :)

Answer:

1. x1=15.75.

2. 24/48=0.5

3. 24/25=0.96

Step-by-step explanation:

1. 15.75/18=0.875

2. you multiply 48 times 0.5 to find 24.

3. multiply 0.96 with 25 to get 24.

Answer:

850

Step-by-step explanation:

Mackenzie has 3200 more red marbles than yellow,

(y + 3200 = r)

And she also has 3840 more blue marbles than the yellow marbles,

(y + 3840 = b)

Then let's assume that Mackenzie has 1 yellow marble.

1 + 3200 = 3201 red marbles

1 +3840 = 3841 blue marbles

If she gives away 1490 blue marbles away, then she is left with 2351 blue marbles.

(3841 - 1490 = 2351)

Now she's left with 2351 blue marbles, and 3201 red marbles.

r - b =?

3201 - 2351 = 850

Mackenzie has 850 more red marbles than blue marbles.

(If you want, you can change the number of yellow marbles, but it will be the same answer.)

Answer:

(0, 4)

Step-by-step explanation:

The y-intercept is defined as the point where the line intersects the y-axis. All we need to do is find where the line intersects the y-axis.

(0, 4) is the answer.

Answer:

A.) you multiply the 3 and 2

The endpoints of the image of AB after the reflection are A'=(2, -2) and B'=(0, -4).

What are the endpoints?

First, we need to find the equation of the line x=1, which is a vertical line passing through x=1. Since all the points on this line have an x-coordinate of 1, we can say that the equation of this line is x = 1.

Next, we need to reflect the line segment AB across the line x=1. To do this, we can use the following steps:

1.  Find the midpoint of the line segment AB.

The midpoint of AB ²can be found by averaging the x-coordinates of A and B, and averaging the y-coordinates of A and B. Therefore, the midpoint is:

(((-3) + 3)/2, (4 + (-2))/2) = (0, 1)

2.  Find the equation of the line that passes through the midpoint of AB and is perpendicular to x=1.

Since x=1 is a vertical line, any line perpendicular to it will be a horizontal line. The equation of a horizontal line passing through the point (0,1) is y = 1.

3.  Find the intersection point of x=1 and the line found in step 2.

The intersection point of x=1 and y=1 is (1,1).

4.  Find the distance between the midpoint of AB and the intersection point found in step 3.

The distance between the midpoint of AB and (1,1) is the same as the distance between the midpoint and the image of the midpoint after reflection across x=1. This distance can be found using the distance formula:

d = √((1 - 0)² + (1 - 1)²) = 1

5.  Find the image points of A and B.

The image of A is the same distance from (1,1) as A is from the midpoint of AB. Therefore, the image of A is:

(1 + (1-0), 1 + (1-4)) = (2, -2)

The image of B can be found in the same way:

(1 + (1-3), 1 + (-2-1)) = (0, -4)

Therefore, the endpoints of the image of AB after the reflection are A'=(2, -2) and B'=(0, -4).

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Complete question is: AB, with A(-3, 4) and B(3,-2), is reflected across the line x=1. the coordinates of the endpoints of the image after this transformation are A'=(2, -2) and B'=(0, -4).

For the fractions, the calculation of 3/5 of 2/3 of 3/4 of 560 is equal to 168.

To calculate 3/5 of 2/3 of 3/4 of 560, break it down step by step:

Step 1: Calculate 3/4 of 560:

3/4 × 560 = (3 × 560) / 4 = 1680 / 4 = 420

Step 2: Calculate 2/3 of the result from Step 1:

2/3 × 420 = (2 × 420) / 3 = 840 / 3 = 280

Step 3: Calculate 3/5 of the result from Step 2:

3/5 × 280 = (3 × 280) / 5 = 840 / 5 = 168

Therefore, 3/5 of 2/3 of 3/4 of 560 is equal to 168.

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Answer:

Scores of students:

Mean: 34.3

Mode: no mode

No. of students:

Mean: 8.3

Mode: no mode

Step-by-step explanation:

(for scores of students)

6, 30, 35, 40, 45, 50

Mean: 6 + 30 + 35 + 40 + 45 + 50 = 206/6 = 34.3

Mode: there are no mode in the set of data.

(for No. of students)

4, 5, 6, 8, 12, 15

Mean: 4 + 5 + 6 + 8 + 12 + 15 = 50/6 = 8.3

Mode: no mode