Coenzyme A, NAD+, and FAD are coenzymes that are necessary for energy production. Determine whether the following phrases describe coenzyme A, NAD+, or FAD.

The pH of the solution after adding 0.050 moles of solid NaOH to 500 ml of a 0.2 M benzoic acid solution is 8.09.

pH of the solution after adding 0.050 moles of solid NaOH to 500 ml of a 0.2 M benzoic acid solution, we need to first determine the reaction that occurs between NaOH and benzoic acid.

NaOH (s) + C6H5COOH (aq) → C6H5COO-Na+ (aq) + H2O (l)

From this balanced equation, we can see that NaOH reacts with benzoic acid to form sodium benzoate and water.

pH of the resulting solution, we need to consider the initial concentration of benzoic acid and the concentration of the resulting sodium benzoate.

The initial concentration of benzoic acid is 0.2 M, which means that there are 0.2 moles of benzoic acid in 1 liter of solution.

When 0.050 moles of NaOH is added to the solution, it reacts with 0.050 moles of benzoic acid to form 0.050 moles of sodium benzoate.

The total volume of the resulting solution is 500 ml or 0.5 liters.

The new concentration of sodium benzoate is:

0.050 moles / 0.5 L = 0.1 M

To calculate the pH of the solution, we need to consider the dissociation of benzoic acid and the hydrolysis of sodium benzoate.

Benzoic acid is a weak acid that partially dissociates in water. Its dissociation constant, Ka, is 6.5 × 10⁻⁵.

C6H5COOH (aq) + H2O (l) ⇌ C6H5COO- (aq) + H3O+ (aq)

At equilibrium, we can use the following equation to calculate the concentration of H3O+:

Ka = [H3O+][C6H5COO-] / [C6H5COOH]

[H3O+] = Ka[C6H5COOH] / [C6H5COO-] = (6.5 × 10⁻⁵)(0.2) / 0.1 = 1.3 × 10⁻⁴ M

So the pH of the solution before adding NaOH is:

pH = -log[H3O+] = -log(1.3 × 10⁻⁴) = 3.89

After adding NaOH, the sodium benzoate will hydrolyze to form benzoic acid and NaOH.

C6H5COO- (aq) + H2O (l) ⇌ C6H5COOH (aq) + OH- (aq)

The hydrolysis of sodium benzoate produces hydroxide ions, which will react with any remaining benzoic acid to form water.

The concentration of OH- can be calculated using the Kb of sodium benzoate, which is the reverse of the Ka of benzoic acid:

Kb = Kw / Ka = 1.0 × 10⁻¹⁴/ 6.5 × 10⁻⁵ = 1.5 × 10⁻¹⁰

[OH-] = sqrt(Kb[C6H5COO-]) = sqrt((1.5 × 10⁻¹⁰)(0.1)) = 1.22 × 10⁻⁶ M

The concentration of H3O+ can be calculated using the ion product constant of water:

Kw = [H3O+][OH-] = 1.0 × 10⁻¹⁴

[H3O+] = Kw / [OH-] = 1.0 × 10⁻¹⁴ / 1.22 × 10⁻⁶ = 8.20 × 10⁻⁹ M

So the pH of the resulting solution is:

pH = -log[H3O+] = -log(8.20 × 10⁻⁹) = 8.09

The pH of the solution after adding 0.050 moles of solid NaOH to 500 ml of a 0.2 M benzoic acid solution is 8.09.

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To increase the equilibrium constant (K) of a reaction by a factor of 10, the change in Gibbs free energy (ΔG°) must decrease by approximately 5.708 kcal/mol. Whereas, the change in entropy (ΔS°) must increase by approximately 14.15 J/mol K.

This can be achieved by adjusting the reaction conditions or altering the concentrations of reactants and products.

If the change in entropy (ΔS°) is zero and the equilibrium constant of a reaction at 25°C is increased by a factor of 10, the change in enthalpy (ΔH°) must change by approximately 1.364 kcal/mol.

This implies a shift in the energy balance of the reaction, which can be influenced by adjusting temperature or introducing catalysts.

If the change in enthalpy (ΔH°) is zero and the equilibrium constant of a reaction at 25°C is increased by a factor of 10, the change in entropy (ΔS°) must increase by approximately 14.15 J/mol K.

This suggests that the reaction becomes more disordered or has an increased number of possible microstates, leading to a higher entropy value.

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Enzymes known as transfer RNA (tRNA) synthetases are responsible for joining a particular amino acid to its associated tRNA in order to produce proteins at the ribosome.

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The concentration of formic acid in the mixture is 1.2 x \(10^(^-^3^)\) M, and the pH of the mixture is 2.9.

Step 1: Calculating the concentration of formic acid

To determine the concentration of formic acid in the mixture, we need to consider the stoichiometry of the reaction between formic acid (HCOOH) and potassium hydroxide (KOH). The balanced equation is as follows:

HCOOH + KOH → HCOOK + H₂O

From the given information, we know that 15 mL of 0.1 M formic acid is added to 35 mL of 0.02 M KOH. By using the volume and molarity of the solutions, we can calculate the moles of formic acid and KOH.

Moles of formic acid = volume (L) × concentration (M) = 0.015 L × 0.1 M = 0.0015 moles

Moles of KOH = volume (L) × concentration (M) = 0.035 L × 0.02 M = 0.0007 moles

Since the stoichiometric ratio of HCOOH to KOH is 1:1, the moles of formic acid remaining after the reaction will be 0.0015 moles - 0.0007 moles = 0.0008 moles.

To find the concentration, we divide the moles by the total volume of the mixture:

Concentration of formic acid = moles/volume (L) = 0.0008 moles/(0.015 L + 0.035 L) = 1.2 x 10⁽⁻³⁾ M

Step 2: Calculating the pH of the mixture

The pH of a solution can be determined using the equation:

pH = pKa + log([A⁻]/[HA])

In this case, formic acid (HCOOH) acts as a weak acid and dissociates into H⁺ and HCOO⁻ ions. Since the concentration of formic acid is known, we can use the Henderson-Hasselbalch equation to calculate the pH.

pH = 3.75 + log([HCOO⁻]/[HCOOH])

The ratio [HCOO⁻]/[HCOOH] can be calculated as [KOH]/[HCOOH] since KOH is fully dissociated in solution.

pH = 3.75 + log([KOH]/[HCOOH]) = 3.75 + log(0.02/0.0012) = 2.9

Therefore, the pH of the mixture is 2.9.

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The balanced equation of Fe + \(H_{2} O\) → \(Fe_{3} O_{4}\) + \(H_{2}\) is given as ,

3 Fe + 4\(H_{2} O\) → \(Fe_{3} O_{4}\) + 4\(H_{2}\)

The balance equation is the equation in which number of atom in reactant side is equal to number of atom in product side .

The inclusion of stoichiometric coefficients to the reactants and products is necessary to balance chemical equations . This is significant because a chemical equation must adhere to the laws of conservation of mass and constant proportions , meaning that both the reactant and product sides of the equation must include the same amount of atoms of each element .

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Based on temperature changes, the phase changes that occur in water is from a solid at A to a liquid at B, and from liquid a B to gas at C.

Change of state is the process whereby a substance changes its state of matter from one form to another as as result of heat changes.

In the graph shown above, water exists in three states at different points.

Therefore, the phase changes that occur in water is from a solid at A to a liquid at B, and from liquid a B to gas at C.

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STEP 1: To solve this question, we must first find the number of moles in a 13g solution of NaNO3 (molar mass = 85g/mol):

moles of NaNO3 = mass / molar mass

moles of NaNO3 = (13g) / (85g/mol)

STEP 2: The ratios of the compound are 3 moles of oxygen, 1 mole of sodium, and 1 mole of nitrogen. As such, for every 1 mole of NaNO3, there are 3 moles of oxygen, and the answer is:

moles of oxygen = (3) x (13/85)

Molar mass can be defined as 'mass per mole.' In other words, molar mass is the sum of the mass of all the atoms found in one mole's worth of a substance. It is expressed in units of grams per mole.

Molar mass is depicted for elements or molecules. In the case of single elements or individual atoms, the molar mass would just be the element's mass expressed in atomic mass units. In other words, the atomic mass and the molar mass of an individual atom are exactly equal.

When individual atoms are bonded to form a molecule, the molar mass represents the mass of all the atoms. Molar mass is different from molecular mass in that molecular mass is the mass of a given molecule, whereas molar mass is the mass of one mole of the given molecule.

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3) orbitals can hold two electrons provided they are spinning in the same direction

We define an orbital in chemistry as a region in space where there is a high probability of finding an electron.

Each orbital holds a maximum of two electrons which spin in opposite direction according to Pauli exclusion principle.

According to this principle no two electrons can have the same set of quantum numbers. As a result, the spin quantum numbers of two electrons in the same orbital must differ hence they spin in opposite directions.

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The densities of the two samples would be equal as they are both composed of gold, and gold's density remains constant at 19.32 g/cm³.

To compare the densities of a 200 gram sample of gold and a 7 gram sample of gold, we need to understand that density is defined as mass divided by volume (density = mass/volume).

The densities of the two samples would be the same because density is a physical property of a substance that remains constant regardless of the amount or size of the sample
Gold has a consistent density of 19.32 grams per cubic centimeter (g/cm³) regardless of the mass of the sample. This means that the densities of the 200 gram sample and the 7 gram sample would be the same (19.32 g/cm³) because they are both made of gold.

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The flask that has the most acidic solution is b. Flask B with a pH of 2.31.

To determine which flask has the most acidic solution, we need to compare their pH values. Lower pH values indicate more acidic solutions. Here's the information we have for each flask:

a. Flask A: pOH = 8.9, so we need to find the pH. Since pH + pOH = 14, pH = 14 - 8.9 = 5.1
b. Flask B: [H⁺] = 4.9 x 10⁻³ M, we can use the formula pH = -log[H⁺], so pH = -log(4.9 x 10⁻³) ≈ 2.31
c. Flask C: [OH⁻] = 2.8 x 10⁻⁷ M, first we find the pOH using the formula pOH = -log[OH⁻], so pOH = -log(2.8 x 10⁻⁷) ≈ 6.55, and then find the pH: pH = 14 - 6.55 ≈ 7.45
d. Flask D: pH = 5.5

Now we can compare the pH values:
Flask A: pH = 5.1
Flask B: pH = 2.31
Flask C: pH = 7.45
Flask D: pH = 5.5

The most acidic solution has the lowest pH value, which is Flask B with a pH of 2.31. So, the answer is b. Flask B.

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Answer:

A chemical reaction is a process where two different substances or elements are mixed together. They then undergo some sort of chemical change to become a different substance altogether.

Explanation:

Answer:

electrons

Explanation:

The group number tells you the number of electrons in the element's outer shell (or valence shell).

Extra info: Elements with the same number of electrons on their outer shell are grouped together in the periodic table because they have similar properties.

Hope this helps!

Answer:

blue only

Explanation:

mark me as a brainlist

The total cooling performed by the coil is 29168.21 BTU/Hr and the sensible cooling performed by the coil is 1209.93 BTU/Hr.

Inlet Condition: TDB, in = 84 °F and TWB, in = 72 "F

Outlet Condition: TDB,

out = 55 F and TDP out = 50 'F

Flow Rate: CFM of air = 3000

Standard Density of Air = 0.075 lbm/ft³

Specific Heat of Air = 0.24 BTU/lbm-'F.

The total cooling performed by the coil can be calculated using the following formula;

Sensible Cooling = CFM x Density x Specific Heat x (TDB, in - TDB, out)

Latent Cooling = CFM x Density x (HFG x (W, in - W, out)

Total Cooling = Sensible Cooling + Latent Cooling

First, we need to calculate the density of air at the inlet condition and outlet condition using the formula:

Density = 0.075 x (460 + TDB) / (460 + TWB)  at inlet and outlet condition

Density at inlet condition = 0.075 x (460 + 84) / (460 + 72)Density at inlet condition = 0.0666 lbm/ft³

Density at outlet condition = 0.075 x (460 + 55) / (460 + 50)Density at outlet condition = 0.068 lbm/ft³

The sensible cooling performed by the coil is;

Sensible Cooling = CFM x Density x Specific Heat x (TDB, in - TDB, out)

Sensible Cooling = 3000 x 0.0666 x 0.24 x (84 - 55)

Sensible Cooling = 1209.93 BTU/Hr

The total cooling performed by the coil is;

Total Cooling = Sensible Cooling + Latent Cooling

Here, Latent Cooling = CFM x Density x (HFG x (W, in - W, out))

At the inlet condition; W, in = (0.62198 x PWS) / (PB - PWS)W,

in = (0.62198 x 0.6237) / (14.433 - 0.6237)W,

in = 0.0427

At the outlet condition; W, out = (0.62198 x PWS) / (PB - PWS)W,

out = (0.62198 x 0.315) / (14.266 - 0.315)W,

out = 0.0237

HFG at average of inlet and outlet air temperature = 1074 BTU/lbm

Latent Cooling = CFM x Density x (HFG x (W, in - W, out))

Latent Cooling = 3000 x 0.0666 x (1074 x (0.0427 - 0.0237))

Latent Cooling = 27958.28 BTU/Hr

Therefore, Total Cooling = Sensible Cooling + Latent Cooling

Total Cooling = 1209.93 + 27958.28

Total Cooling = 29168.21 BTU/Hr

Therefore, the total cooling performed by the coil is 29168.21 BTU/Hr and the sensible cooling performed by the coil is 1209.93 BTU/Hr.

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Answer:      31 (a) 4           32 (a) 5

                        (b) 7                 (b) 3

                        (c) 5                 (c) 5

                        (d) 3                 (d) 2

Significant Figures (sf) Rules:

1) Trailing zeroes are considered significant ONLY If a decimal point is provided.

2) Zeroes between the decimal point and number are NOT significant unless they are between numbers.

3) All digits in scientific notation are counted (disregard the exponent).

31 (a) 508.0              trailing zero so use rule 1  -->  sf = 4

   (b) 820,400.0      trailing zero so use rule 1  -->  sf = 7

   (c) 1.0200 x 10⁵   scientific notation so use rule 3 --> sf = 5

    (d) 807,000         no trailing zeroes so use rule 1 --> sf = 3

32 (a) 0.049450     zero between decimal point & #, use rule 2 --> sf = 5

    (b) 0.000482     zero between decimal point & #, use rule 2 --> sf = 3

    (c) 3.1587 x 10 ⁻⁸  scientific notation so use rule 3 --> sf = 5

    (d) 0.0084          zero between decimal point & #, use rule 2 --> sf = 2

The missing part of the equation is found to be 4/2He. Option A

The term nuclear equations have to do with the type of equation in which one type of nucleus is transformed into another sometimes by the bombardment or loss of a particle.

Now the full equation ought to be written as 7/3Li + 1/1H -----> 4/2He + 4/2He. This is because the total mass on the left is 8 and the total charge on the left is 4.

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At Ph 3.0, percentage of lactic acid that is in its deprotonated form (pka for lactic acid is 3.86) is 50%

As lactic acid has a pKa of 3.86, it will be half ionized at pH 3.86.

The degree of ionization (α) of an acid can be determined by the following formula:

α = [H+]/[HA], Where [H+] is the hydrogen ion concentration and [HA] is the undissociated acid concentration.

To figure out the percent ionization, multiply the fraction by 100 percent.

At pH 3.0, the formula would be:

α = [H+]/[HA]

At pH 3.0, the acid and its conjugate base are present in equal amounts; therefore, the pH is equal to the pKa.

So α can be calculated using the following formula:

pH = pKa + log([A-]/[HA]), where [A-] is the concentration of the conjugate base (lactate) and [HA] is the concentration of the acid (lactic acid).

At pH 3.0, [A-]/[HA] = 1,

so: pH = pKa + log([A-]/[HA])

pH = pKa + log(1)

pH = pKa

α = 0.50

This means that at pH 3.0, 50% of lactic acid is in its deprotonated form.

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The approximate balance in the account at the end of 6 years is $159,074. Rounded to the nearest dollar, it is $159,074.

Assuming that the annual rate of $20,000 is deposited at the beginning of each year, the total amount deposited over 6 years would be $120,000. With continuous compounding at 5% interest rate, the formula to calculate the balance in the account after 6 years is:
A = Pe^(rt)
Where A is the balance, P is the principal (amount deposited), e is the mathematical constant approximately equal to 2.71828, r is the interest rate in decimal form, and t is the time in years.
Plugging in the values, we get:
A = $120,000e^(0.05*6)
A = $159,073.51
Therefore, the approximate balance in the account at the end of 6 years is $159,074. Rounded to the nearest dollar, it is $159,074.

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Answer:

they had killed other animals

I believe your answer is carried a serious disease.

Explanation: Buffalo are known to carry a disease called brucellosis, which can spread to livestock a kill other animals/

Explanation:

K2CO3 ➖ K2O + CO2

it is itself balanced.

Answer:

1K2CO3 —> 1K2O + CO2

Explanation:

The equation is already balanced. We can check by counting the amount of each element on each side of the equation:

_K2CO3 —> _K2O + CO2

Products Side:

• K: 2

• C: 1

• O: 3

Reactants Side:

• K: 2

• C: 1

• O: 3

Since everything matches, we can just put a coefficient of 1 in front of each potassium.

1K2CO3 —> 1K2O + CO2

Answer:

Chemical reactions occur when chemical bonds between atoms are formed or broken. The substances that go into a chemical reaction are called the reactants, and the substances produced at the end of the reaction are known as the products.

Explanation:

hope it helps

Answer:

Adding an acid increases the concentration of H3O+ ions in the solution. Adding a base decreases the concentration of H3O+ ions in the solution. An acid and a base are like chemical opposites. If a base is added to an acidic solution, the solution becomes less acidic and moves toward the middle of the pH scale.

Answer: 145.84376 grams (i think)

Explanation: i searched it

The conditions that will increase the rate of a chemical reaction are:(4) Increased temperature and increased concentration of reactants. The correct answer is (4) Increased temperature and increased concentration of reactants.

Explanation: The rate of a chemical reaction depends on various factors. Some of the factors that increase the rate of a chemical reaction include the presence of catalysts, surface area, concentration, temperature, and pressure. Among these factors, temperature and concentration are the most significant factors.

Temperature: Temperature is a significant factor that influences the rate of a chemical reaction. It is observed that if the temperature is increased, the rate of reaction also increases. This is because an increase in temperature leads to an increase in kinetic energy. As the kinetic energy increases, the molecules move faster and collide more frequently. This, in turn, increases the rate of reaction.

Concentration: Another significant factor that affects the rate of a chemical reaction is concentration. When the concentration of reactants is increased, the rate of reaction also increases. This is because when the concentration of reactants is high, the number of molecules per unit volume is high, which leads to more frequent collisions between the reactant molecules.

Thus, increasing the concentration of reactants can increase the rate of a chemical reaction.

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The electrostatic force is also called the Coulomb's force. It is an example of a non-contact force. The number of electrons missing from each ion is 1.

The electrostatic force is defined as an attractive and repulsive force between the particles and are caused due to the electric charges. The electrostatic force between the stationary charged bodies is called the electrostatic force.

The equation of electrostatic force is:

F = kq²/r²

q = ne

F = k (ne)² / r²

n = √r²F / ke² = r/e √F/k

k = 9 × 10⁹ Nm²/c²

e = 1.6 × 10⁻¹⁹ C

n = 2.1 × 10⁻¹⁰ /  1.6 × 10⁻¹⁹ √ 5.4×10⁻⁹ / 9 × 10⁹

= 1 × 10²⁹

Thus the number of electrons missing from the ion is approximately 1.

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Answer:

flourine 19F-

Explanation:

because we have 1 extra electron so the charge should be negative, then check the number of protons to know the atomic number, and 9 is flourine

Answer:

378mL

Explanation:

The following data were obtained from the question:

Pressure (P) = 99.19 kPa

Temperature (T) = 28°C

Number of mole (n) = 0.015 mole

Volume (V) =...?

Next, we shall convert the pressure and temperature to appropriate units. This is illustrated below:

For Pressure:

101.325 KPa = 1 atm

Therefore, 99.19 kPa = 99.19/101.325 = 0.98 atm

For Temperature:

T(K) = T(°C) + 273

T(°C) = 28°C

T(K) = 28°C + 273 = 301K.

Next we shall determine the volume of N2. The volume of N2 can be obtained by using the ideal gas equation as shown below:

PV = nRT

Pressure (P) = 0.98 atm

Temperature (T) = 301K

Number of mole (n) = 0.015 mole

Gas constant (R) = 0.0821atm.L/Kmol.

Volume (V) =...?

0.98 x V = 0.015 x 0.0821 x 301

Divide both side by 0.98

V = (0.015 x 0.0821 x 301) /0.98

V = 0.378 L

Finally, we shall convert 0.378 L to millilitres (mL). This is illustrated below:

1L = 1000mL

Therefore, 0.378L = 0.378 x 1000 = 378mL

Therefore, the volume of N2 collected is 378mL

Answer:

3%

Explanation:

as error occurred is 1.5(error value) so 1.5 is 3%of 50(original value)

The major product for the given reaction is a mixture of two alcohol are propanol (CH3CH2CH2OH) and ethanol (CH3CH2OH).

The given reaction involves an ether (CH3CH2O) reacting with 1-bromopropane (CH3CH2CH2Br) in the presence of HCl and H2O under heat. The product of this reaction is 1-ethoxypropane (CH3CH2CH2OCH2CH3), which is an ether formed by the substitution of the bromine atom of 1-bromopropane with the ethoxy group (-OCH2CH3) from the ether. This is the major product of the reaction.
the major product will be formed through a nucleophilic substitution reaction followed by an acid-catalyzed hydrolysis.
1. Nucleophilic substitution: CH3CH2O- (ethoxide ion) acts as a nucleophile and attacks the CH3CH2CH2Br (1-bromopropane) molecule, replacing the bromine atom.
CH3CH2O- + CH3CH2CH2Br → CH3CH2CH2OCH2CH3
2. Acid-catalyzed hydrolysis: The newly formed ether (CH3CH2CH2OCH2CH3) reacts with HCl and H2O under heat, breaking the ether linkage and producing two alcohol products.
CH3CH2CH2OCH2CH3 + HCl + H2O (heat) → CH3CH2CH2OH + CH3CH2OH
The major product for the given reaction is a mixture of two alcohols: propanol (CH3CH2CH2OH) and ethanol (CH3CH2OH).

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Hi! I'd be happy to help with your question. When (CH3CH2O-) reacts with CH3CH2CH2Br in the presence of HCl and H2O under heat, a nucleophilic substitution reaction occurs, specifically an SN1 reaction. Here's a step-by-step explanation:

1. CH3CH2CH2Br, which is 1-bromopropane, reacts with the nucleophile (CH3CH2O-), and the bromine atom leaves as a leaving group, forming a carbocation intermediate: CH3CH2CH2(+).

2. The (CH3CH2O-) nucleophile attacks the carbocation, forming an ether: CH3CH2CH2-O-CH2CH3.

3. The presence of HCl and H2O under heat triggers an acid-catalyzed hydrolysis reaction. HCl protonates the ether oxygen, making it a better-leaving group.

4. A water molecule then acts as a nucleophile, attacking the protonated ether and displacing the CH3CH2O group, forming an alcohol as the major product.

The major product of this reaction is, therefore, CH3CH2CH2OH, which is propanol.

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