Coach Sweeney walks 24 yards to the north along the sideline, pauses, and walks 11
yards back to the south. Determine Coach's resultant displacement.
Answers
Answer:
13 yards north.
Explanation:
Distance and Displacement
A moving object constantly travels for some distance at defined periods of time. The total moved distance is the sum of each individual distance the object traveled. It can be written as:
dtotal=d1+d2+d3+...+dn
This sum is obtained independently of the direction the object moves.
The displacement only takes into consideration the initial and final points of the path defined by the object in its moving. The displacement, unlike distance, is a vectorial magnitude and can be even zero if the object starts and ends the movement at the same point.
Coach Sweeney walks 24 yards north and 11 yards back south. If Coach Sweeney started at the origin, the first walk ends in point (0,24). After going back 11 yards, the final point is (0,13).
Since the displacement only takes the initial and final points, we can say the resultant displacement was 13 yards north.
Related Questions
The chart shows data for four moving objects. A 4 column table with 4 rows. The first column is labeled Object with entries, W, X, Y, Z. The second column is labeled Initial Velocity in meters per second with entries, 11, 10, 12, 20. The third column is labeled Final Velocity in meters per second with entries, 29, 34, 40, 28. The fourth column is labeled Change in Time in seconds with entries, 6, 12, 7, 8. Which object has the greatest acceleration? W X Y Z
Answers
Answer:
y
Explanation:
I took the test
Answer:
its c...
Explanation:
letter y
What do you mean by Tribology? Explain its significance in our daily life 2. Explain the role played by friction and wear in a tribological system 3. How do you define Wear? How it affects the properties of a surface?
Answers
(2.)Tribology is particularly important in today's world because so much energy is lost to friction in mechanical components. To use less energy, we need to minimize the amount that is wasted. Significant energy is lost due to friction in sliding interfaces.
(3.) Wear can be defined as an extremely short sliding motion and is executed within a short time interval.
(Idk how it effects the properties of surface sorry )
Escape velocity on Earth is 11.2 km/s. Find escape velocity on a planet whose mass is 3 times mass of earth and radius is two times radius of earth.
❌ᴅᴏɴ'ᴛ ꜱᴩᴀᴍ❌ ɪᴛ'ꜱ ᴜʀɢᴇɴᴛ ᴩʟꜱ ᴀɴꜱᴡᴇʀ ᴍᴇ ᴄᴏʀʀᴇᴄᴛ
Answers
V(escape) = 13727.6 m/s or 13.73 km/s. The formula for escape velocity is V = sqrt[ (2GM)/r], where G is the universal gravitational constant (6.67x10^-11),
M = mass of planet - in this case, 3 times mass of Earth, which is 6.0x10^24 kg, and r = radius of planet - in this case, 2 times radius of Earth, which is 6.371x10^6 m.
What is the origin of the escape velocity formula?Escape velocity is the minimal velocity necessary for a body to be ejected in order to transcend the earth's gravitational attraction. It is the smallest velocity necessary by an object to escape the gravitational field, i.e., to leave the land without ever falling back.
Using the Law of Conservation of Energy, we can get the equation for the escape velocity. According to this Law, the total of an object's potential and kinetic energy is a constant.
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the first law of thermodynamics states that the degree of disorder in the universe tends to increase
Answers
The degree of disorder in the universe tends to increase due to entropy.
ie. the second law of thermodynamic
First law of thermodynamics is the conservation of energy. Energy can change from one form to another form it neither created nor destroyed.
dQ = dU + dW
where
dQ is the heat transferred.
dW is the work done
dU is change in internal energy.
2nd law states entropy of an isolated system always increases.
S > 0
where s is the change in entropy in the universe.
the degree of disorder in the universe tends to increase due to entropy.
ie. the second law of thermodynamic.
The given question is incomplete
the first law of thermodynamics states that the degree of disorder in the universe tends to increase
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the volume of 1 mole of any gas at stp is 22.4 l. TRUE OR FALSE
Answers
The statement "the volume of 1 mole of any gas at STP is 22.4 L" is true because the volume of 1 mole of any gas at STP is 22.4 L. This is known as the molar volume of a gas. STP stands for Standard Temperature and Pressure, which is defined as 273.15 K (0°C) and 1 atm.
The statement is true. According to the ideal gas law, at Standard Temperature and Pressure (STP), which is defined as 0 degrees Celsius (273.15 Kelvin) and 1 atmosphere (101.3 kilopascals or 760 mmHg) of pressure, one mole of any gas occupies a volume of 22.4 liters. This relationship is known as the molar volume of a gas at STP.
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A person runs 15.0 km north then turns around and runs 10.0km south.
a) what is his distance?
b) what is the person's displacement?
Answers
Answer:
A. 25kmB. 15kmExplanation:
In this problem, we are expected to solve for the total distance covered by the person, and the person's displacement.
a) what is his distance?
this can be gotten by summing up all the individual distances covered by the person
total distance= 15+10
total diastance= 25 km
b) what is the person's displacement?
the displacement is the distance measured away from a point
this can be gotten by subtraction the final distance/point from the initial distance/point
displacement= 25-10
displacement= 15km
A 16.0 kg canoe moving to the left at 12.5 m/s makes an elastic head on collision with a 14.0 kg raft moving to the right at 16.0 m/s after the collision the raft moves to the left at 14.4 m/s assuming water simulates a frictionless surface, what is the final velocity of the canoe?
Answers
Answer:
The final velocity of the canoe is -14.1 m/s or 14.1 m/s to the right.
Hope you could get an idea from here.
Doubt clarification - use comment section.
A roller skater with a mass of 71.2 kg is moving along the ice with a speed of 6.01 m/s. She collides head-on with a stationary skater who has a mass of 55.9 kg After the collision, the two skaters grab onto each other (without spinning or losing their balance) and move together. What is their speed?
Answers
Therefore, the speed of the two skaters after the collision is 3.37 m/s. The total momentum of the system before the collision is equal to the total momentum of the system after the collision.
We can set up an equation to solve for the final velocity of the two skaters:
(mass of skater 1 x velocity of skater 1) + (mass of skater 2 x velocity of skater 2) = (total mass of skaters x final velocity of skaters)
(71.2 kg x 6.01 m/s) + (55.9 kg x 0 m/s) = (71.2 kg + 55.9 kg) x final velocity
428.672 + 0 = 127.1 x final velocity
final velocity = 3.37 m/s
Therefore, the speed of the two skaters after the collision is 3.37 m/s.
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A raven flies south for 100 seconds of 10m/s, then flies 0.50km north in 50 seconds. What is the total distance? What is the total distance? What is the average speed? What is the average velocity
Answers
Explanation:
given that the raven flies south for
time= 10 sec
speed= 10km/s
we know that speed=distance/time
distance=speed*time
distance=10*100
distance=1000m
distance=1km
also flies
distance=0.5km = 500m
time= 50 sec
speed= distance/time
speed=500/50
speed= 10m/s
speed= 0.01km/s
The average speed of an object is defined as the distance traveled divided by the time elapsed.
average speed= (1000+500)/10+50
average speed= (1500)/60
average speed= 25m/s
average velocity= (10km/s+0.01km/s)/2= 10.01/2= 5.005km/s
A molecule of water H2O and a molecule of methane CH4 have close to the same mass Which statement explains why water has much higher boiling point than methane?
A. There is hoydrogen bonding between water molecules?
B. There is ionic bonding between water molecules
C. There is hydrogen bonding between methane molecules
D. There is ionic bonding between methane molecules
Answers
Answer:
A. There is hydrogen bonding between water molecules
Explanation:
Boiling point is a physical property of matter. It is typically conditioned by the intermolecular forces present between the molecules of a compound.
The nature of the intermolecular forces between the molecules of water is very different from those of methane. Water molecules have hydrogen bonds within their molecules. These intermolecular bonds are very strong compared to the london dispersion forces in methane. Hydrogen bond forms when the hydrogen of one molecule binds with the oxygen of another molecule.Answer:
A)
Explanation:
There is hydrogen bonding between water molecules
What is the answer for the first part of a? In kN
Answers
We are asked to determine the magnitude of the force that acts parallel to the nail. To do that we will add the torque that acts on the point of contact. First, we draw a free-body diagram of the situation:
We have decomposed the force of the nail into its horizontal and vertical components. The horizontal component does no torque since there is no distance parallel to the force to the point of contact.
Now, we add the torques. We consider counterclockwise as positive:
\(\Sigma T=-(30cm)F+(5cm)(R_y)\)Since we consider the moment before there is no angular acceleration the sum of torques adds up to zero:
\(-(30cm)F+(5cm)(R_y)=0\)Now, we determine the value of Ry as a function of "R" using the trigonometric function cosine:
\(\cos \theta=\frac{R_y}{R}\)Now, we multiply both sides by "R":
\(R\cos \theta=R_y\)Now, we substitute in the sum of torques:
\(-(30cm)F+(5cm)(R\cos \theta_{})=0\)Now, we solve for "R". First, we add "30F" to both sides:
\((5cm)(R\cos \theta)=(30cm)F\)Now, we divide both sides by 5cm:
\((R\cos \theta)=\frac{(30cm)F}{5cm}\)Now, we divide both sides by cosine:
\(R=\frac{(30cm)F}{5cm\cos \theta}\)Now, we substitute the values:
\(R=\frac{(30cm)(155N)}{(5cm)\cos 26.9}\)Solving the operations:
\(R=1042.8N\)Therefore, the force on the nail is 1042.8 Newtons.
the total charge on each plate and the separation between the plated is held constant while the area of each plate is doubled. what happens to the electric field between the plates, the potential difference across the plates, ad the stored energy in the capacitor
Answers
When the area of each plate is doubled while keeping the charge and separation constant, the electric field decreases, the potential difference remains the same, and the stored energy in the capacitor increases four times.
When the area of each plate of a capacitor is doubled while keeping the total charge on each plate and the separation between the plates constant, the following changes occur:
1. Electric Field: The electric field between the plates decreases. The electric field (E) between the plates of a capacitor is inversely proportional to the area (A) of the plates. As the area is doubled, the electric field is halved, assuming the other factors remain constant.
2. Potential Difference: The potential difference (V) across the plates remains the same. The potential difference across the plates of a capacitor depends on the charge (Q) and the capacitance (C), which is determined by the geometric and material properties of the capacitor. Since the total charge and separation between the plates are held constant, the potential difference remains unchanged.
3. Stored Energy: The stored energy in the capacitor increases four times. The energy stored in a capacitor (U) is directly proportional to the area of the plates (A). When the area is doubled, the stored energy is quadrupled (increases by a factor of four).
Therefore, when the area of each plate is doubled while keeping the charge and separation constant, the electric field decreases, the potential difference remains the same, and the stored energy in the capacitor increases four times.
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The population numbers are estimates do you think that policy markers and scientist should assume that the estimates are higher or lower than the actual number of Tasmanian devils
Answers
Asky wave is incident on the ionosphere at an angle of 60°. The electron density of this ionosphere layer is N = 24.536 × 10¹¹ electrons/m³
a. For the point of reflection, determine the refractive index of the ionospheric layer. (3 Marks)
b. Identify the critical frequency for the communication link. (2 Marks)
c. Determine the maximum usable frequency (2 Marks)
d. Give reasons why the transmissions would fail the following frequencies if the frequencies were 10 MHz and 30 MHz respectively. (4 Marks)
e. The lonosphere bends high frequency radio waves towards Earth. Discuss this bending phenomenon.
Answers
We can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2). The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2)
(a) The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2), where n represents the refractive index, f_ce is the electron gyrofrequency, and f is the frequency of the incident wave.
The electron gyrofrequency (f_ce) can be calculated using the formula f_ce = 8.978 × √(N), where N is the electron density. Substituting the given electron density value, we have f_ce = 8.978 × √(24.536 × 10^11) ≈ 2.774 × 10^6 Hz.
Now, we can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2).
(b) The critical frequency for the communication link can be determined using the formula f_c = f_ce / sin(θ), where f_c represents the critical frequency and θ is the angle of incidence. Substituting the given angle of 60°, we have f_c = 2.774 × 10^6 Hz / sin(60°).
(c) The maximum usable frequency (MUF) can be calculated using the formula MUF = f_c / sin(θ). Substituting the critical frequency and angle of incidence given in parts (b) and (a), respectively, we can find the MUF.
(d) Transmissions would fail at the frequencies of 10 MHz and 30 MHz because they are below the critical frequency. The critical frequency represents the maximum frequency that can be reflected back to Earth by the ionospheric layer. If the frequency of the transmission is below the critical frequency, the wave would penetrate through the ionosphere and not be reflected back, leading to a failed transmission.
(e) The ionosphere bends high-frequency radio waves towards Earth due to the phenomenon of refraction. When a radio wave encounters the ionosphere, which is composed of charged particles, it experiences a change in speed and direction. This change in speed and direction is due to the varying density and composition of the ionosphere at different altitudes.
As the radio wave passes through the ionosphere, its path is curved downward towards the Earth's surface. This bending phenomenon occurs because the refractive index of the ionosphere is greater than that of the surrounding vacuum or atmosphere. The higher the frequency of the radio wave, the greater the bending effect due to the higher electron density in the ionosphere at higher altitudes.
This bending of high-frequency radio waves allows for long-distance communication by enabling the waves to travel beyond the line-of-sight. It plays a crucial role in long-distance radio communication, especially in areas where direct line-of-sight transmission is obstructed by the Earth's curvature or other obstacles.
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What will happen to the pitch when a car with a blowing horn is approaching, according to the doppler effect?
Answers
Answer: The sound will increase in pitch.
Explanation:
According to the Doppler Effect, sounds will increase in pitch as they are nearing the listener, and then decrease in pitch as the sound moves further away. This is because when sound waves travel a shorter distance, the waves are more compact (higher frequency), producing a higher pitch. The further a listener is from the sound, the lower the pitch because the sound waves are more spread apart (lower frequency).
a disabled empty cat 631g scraper is pulled up a road whose slope is 4% at a uniform speed. if the average tension in the cable is 9,216 lbs, what is the rolling resistance of the road in lbs per ton?
Answers
The rolling resistance of the road is 132.48 lbs per ton.
We can use the formula for the net force acting on the scraper to determine the rolling resistance of the road:
F_net = F_tension - F_rolling
where F_tension is the tension in the cable, and F_rolling is the rolling resistance force.
We know that the scraper is moving at a uniform speed, which means that the net force acting on it is zero. Therefore:
F_net = F_tension - F_rolling = 0
Solving for F_rolling:
F_rolling = F_tension = 9,216 lbs
To express the rolling resistance in lbs per ton, we need to convert the weight of the scraper to tons.
One ton is equal to 2000 pounds, so the weight of the scraper is:
W = mg = (63100 kg)(9.8 m/s^2) = 618,780 N
Converting to pounds and tons:
W = 618,780 N * 0.2248 lbs/N = 139,174.6 lbs
1 ton = 2000 lbs, so the weight of the scraper is:
W = 139,174.6 lbs / 2000 lbs/ton = 69.59 tons
Now we can calculate the rolling resistance in lbs per ton:
Rolling resistance = F_rolling / W = 9,216 lbs / 69.59 tons = 132.48 lbs/ton
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Would a glowing rod be hotter if it was white or red? Why?
Answers
Answer:
White
Explanation:
Red comes from the lowest energy range of and blue from the highest.
which of the following conditions does not lead to the breakdown of plastic water bottles?
Answers
However, there is one condition that does not lead to the breakdown of plastic water bottles, and that is being buried in landfills.
Plastic water bottles are made of polyethylene terephthalate (PET) and are widely used globally for their convenience and durability. However, environmental concerns have been raised due to the non-biodegradable nature of plastic bottles, which can take hundreds of years to decompose.
Plastic bottles can break down under certain conditions, including exposure to sunlight, high temperatures, and acidic or alkaline environments. Exposure to sunlight can cause photodegradation, leading to the breakdown of the plastic's molecular structure and causing it to become brittle and crumble. High temperatures can accelerate the breakdown process, and acidic or alkaline environments can cause hydrolysis, leading to the breakdown of the plastic's chemical bonds.
In landfills, plastic bottles are typically buried deep beneath the surface, where they are shielded from sunlight and exposure to high temperatures. As a result, plastic bottles in landfills may take hundreds of years to decompose, leading to the accumulation of plastic waste in the environment.
Therefore, it is important to recycle plastic bottles to reduce the amount of waste in landfills and prevent environmental pollution. Recycling plastic bottles can help to conserve natural resources, reduce greenhouse gas emissions, and support the circular economy.
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El bloque de 10 kg que se muestra en la figura está en contacto con el resorte que tiene una longitud natural de 25 cm. Cuando se suelta el bloque, éste comprime al resorte quedando estático a 15 cm del piso. Calcule el cambio de energía potencial elástica del resorte en Joules.
Answers
Answer:
9.81 J
Explanation:
The 10 kg block shown in the figure is in contact with the spring that has a natural length of 25 cm. When the block is released, it compresses the spring, remaining static 15 cm from the floor. Calculate the change in elastic potential energy of the spring in Joules
The given parameters are;
The mass of the block in contact with the spring = 10 kg
The natural length of the spring = 25 cm
The final height of the block after being released = 15 cm
Therefore;
The potential energy of the block = m·g·h
The initial potential energy of the block = 10 kg × 9.81 m/s² × 0.25 m = 24.252 J
The final potential energy of the block = 10 kg × 9.81 m/s² × 0.15 m = 14.715 J
By energy conservation principle
The change in potential energy of the block = The change in elastic potential energy of the spring = (1/2)·k·x² = 24.252 J - 14.715 J = 9.81 J
what’s the first change that occurs in your cookie dough after you put the pan in the oven?
Answers
At 310 degrees, the enzymes and sugars start to disintegrate and rearrange into rings that resemble molecules, which starts the maillard. These molecules' ring-like shapes reflect light, giving off a brown hue.
What is a straightforward explanation of molecules?
Pay attention to how it sounds. (MAH-leh-kyool) the smallest component of a molecule that possesses both its chemical and physical characteristics. One or maybe more atoms make up molecules.
How is a molecule created?
When a number of atoms come together and form bonds with one another, a molecule is created. Each atom shares an electron when a bond is formed between them. A molecule is created as a result of a covalent bond.
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When businesses calculate the costs to borrow money for capital budget projects they must be sure to include the _____ expenses for the debt used to finance the project.
Answers
When businesses calculate the costs to borrow money for capital budget projects, they must be sure to include the interest expenses for the debt used to finance the project.
One crucial component that must not be overlooked is the inclusion of interest expenses for the debt used to finance the project. Interest expenses represent the cost of borrowing capital, and they directly impact the overall financial feasibility of the project. By factoring in the interest expenses, businesses can assess the true cost of financing and make informed decisions regarding project viability and profitability. This comprehensive approach ensures that businesses have a realistic understanding of the financial implications and aids in effective capital allocation and financial planning.
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Explain type 1 and type 1a relay node in LTE-A?
Answers
In the context of LTE-A (Long-Term Evolution Advanced), Type 1 and Type 1a relay nodes are different deployment options for relay nodes in the LTE network. Relay nodes are used to extend the coverage and improve the performance of the network by relaying signals between the base station and user equipment (UE).
Type 1 Relay Node:
A Type 1 relay node in LTE-A operates in half-duplex mode, which means it can either transmit or receive data at a given time but not both simultaneously. It has two separate sets of antennas: one for receiving signals from the base station (downlink) and another for transmitting signals to the UE (uplink). This type of relay node introduces a relay-specific interface called the Relay Physical Interface (R-PHY) to connect with the base station.
The Type 1 relay node receives downlink signals from the base station, decodes them, and then re-encodes and retransmits them to the UE. Conversely, it receives uplink signals from the UE, decodes them, and re-encodes and retransmits them to the base station. Due to the half-duplex operation, it cannot receive and transmit simultaneously, which can result in increased latency and reduced throughput compared to other relay types.
Type 1a Relay Node:
A Type 1a relay node is an enhanced version of the Type 1 relay node, specifically designed to improve performance. It operates in full-duplex mode, allowing simultaneous transmission and reception. It achieves this by utilizing advanced self-interference cancellation techniques, which cancel out the interference caused by the transmitted signal, allowing the relay to receive signals while transmitting.
The Type 1a relay node also utilizes the Relay Physical Interface (R-PHY) to communicate with the base station. By supporting full-duplex operation, it can provide better throughput and lower latency compared to the Type 1 relay node. This makes it more suitable for scenarios where higher data rates and improved performance are desired.
Both Type 1 and Type 1a relay nodes can be deployed in LTE-A networks to extend coverage and improve performance in areas with challenging propagation conditions or limited backhaul connectivity. The choice between the two types depends on the specific requirements of the network deployment and the desired trade-offs between performance and complexity/cost.
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how is sonar used to map the surface of the ocean floor?
Answers
Sonar (Sound Navigation and Ranging) is utilized to map the surface of the ocean floor through a technique called bathymetry. A sonar system consists of a transmitter and receiver. The transmitter emits sound waves in the form of pulses, which travel through the water and reach the ocean floor. When these sound waves encounter objects or the seafloor, they reflect back towards the receiver.
By measuring the time it takes for the sound waves to travel to the seafloor and back, and knowing the speed of sound in water, the distance to the seafloor can be calculated. This process is repeated multiple times by emitting pulses at regular intervals as the vessel moves forward. The resulting data is then used to generate detailed maps of the ocean floor topography.
Modern multibeam sonar systems provide even more precise mapping by emitting multiple beams simultaneously, allowing for wider coverage and higher resolution. These sonar systems play a crucial role in mapping the unexplored areas of the ocean floor, providing valuable information for scientific research, navigation, and resource exploration.
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a truck starts from rest and accelerates for 25 seconds to reach a velocity of 60m/s . calculate the rate of acceleration for the truck
Answers
Answer:
2.4m/s²
Explanation:
Given parameters:
Initial velocity = 0m/s
Time 25s
Final velocity = 60m/s
Unknown:
Acceleration = ?
Solution:
Acceleration is the rate of change of displacement
Acceleration = \(\frac{Final velocity - Initial velocity}{time}\)
Acceleration = \(\frac{60 - 0}{25}\) = 2.4m/s³
true or false money difficult to carry around
Answers
Answer
yeard
Explanation:
cause it is
Answer:
The answer is true
a stone of mass 750 kg is thrown vertically upward with a velocity of 10m/s find the potential energy at the greatest height and kinetic energy on reaching the ground
Answers
Answer:
Potential Energy at the greatest point = 37.5 J
Explanation:
Given :
Mass is 750 g
In term of kg :
Mass is 0.75 kg .
Velocity ( v ) = 10 m / sec
We have formula for kinetic energy :
K.E. = 1 / 2 m v²
Putting values now :
K.E. = 1 / 2 × 0.75 × 10 × 10
K.E. = 1 / 2 × 75 J
K.E. = 37.5 J
Since K.E . = P.E.
Thus potential energy of stone is 37.5 J .
what is the acceleration of a car travelling at 15m/s if it is travelling at 27m/s, 5 s later?
Answers
Answer:
5.4
Explanation:
a=∆v/∆t
27/5 = 5.4
The centre of gravity of a homogeneous body is the point at which the wholeA. Volume of the body is assumed to be concentratedB. Area of the surface of the body is assumed to be concentratedC. Weight of the body is assumed to be concentratedD. All the above
Answers
Option C is correct. The center of gravity of a homogeneous body is the point at which the weight of the body can be assumed to be concentrated.
The focal point of gravity of a homogeneous body is the place where the whole weight of the body can be thought to be concentrated. A homogeneous body is one in which the thickness is uniform all through its volume.
The focal point of gravity is the place where the body will adjust when suspended starting there. It is additionally the place where the gravitational power following up on the body can be considered to act.
On account of a strong body, the focal point of gravity is commonly situated at the mathematical focus of the body. For unpredictably molded bodies, the focal point of gravity can be resolved utilizing numerical estimations that consider the conveyance of mass all through the body. The focal point of gravity is a significant idea in material science and is utilized in numerous applications, including the plan of designs and vehicles.
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Which action could a student take to produce a longitudinal wave with a large amplitude?
A. Drop a pebble in a pond.
B. Light a candle.
C. Bang on a drum.
D. Stand as still as possible.
Answers
Answer:
Bang on a drum.
Explanation:
Amplitude is making loud sounds
How can red giants be so bright when they are so cool
Answers
Answer:
The star's luminosity rises above its previous level. Because it is so cool, the surface will be red, and it will be much farther away from the center than it was during the earlier stages of star evolution. Despite its lower surface temperature, the red giant has a large surface area, which makes it very luminous.