Answer:
$6,237 down payment
Step-by-step explanation:
calculated \(18,900\)×\(6.6%\)%×\(5 = $6,237\)
Patrice is taking surfing lessons. She wants to spend less than $150.Each lesson costs $35 and there is a one time registration fee of $40. How many lessons can she take?
Answer:
3 lessons
Step-by-step explanation:
150-40=110
110/35=3
she can take 3 lessons and it not cost more than $150
Which point is collinear with points E and Y?
Answer:
G
Step-by-step explanation:
Co linear means that a point is on the same line as some given point.
AY forms a line segment and is part of EG which is a diagonal of the base..
Therefore AY and G are all colinear. The answer you want is G.
Greg is a swimmer. He practices 1.3 hours on Monday, 11/2 hour on Tuesday and 2 hours on Saturday. How many hours will he practices if he keeps this scheduled for 2 weeks?
Answer:
7 hours 40 minutes in 2 weeks
Step-by-step explanation:
1.3 - 1 hour 20 minutes
1.5 - 1 and a half hours
2hours
add them all toghether = 3 hours 50 minutes
3 hours 50 minutes times 2 (2 weeks) = 7 hours 40 minutes
tour busload of 45 people attended two Florida theme parks on successive days. On Day 1 the entrance fee was $15 per adult, $8 per child, $12 per senior citizen and the total charge was $558. On Day 2 the entrance fee was $20 per adult, $12 per child, $17 per senior citizen and the total charge was $771. How many adults, children, and senior citizens were on this tour bus
Answer: There are 22 adults , 12 children and 11 senior citizens on the tour bus.
Step-by-step explanation:
Let adult = x
children = y
senior citizen = z
Given : Total busload (x+ y + z) = 45
Total charge on day 1 = 558 $ = \(15\times x+8\times y+12\times z\)
Total charge on day 2 = 771 $ = \(20\times x+12\times y+17\times z\)
Now we have 3 equations : x+ y+z =45
\(15\times x+8\times y+12\times z=558\)
\(20\times x+12\times y+17\times z=771\)
Solving for them we get: x= 22 , y = 12 and z= 11
Thus there are 22 adults , 12 children and 11 senior citizens.
3579
How do I write it out to solve the problem
Answer:
three thousand five hundred seventy nine
Step-by-step explanation:
Use the histogram to answer the following questions.
Frequency
The frequency of the class 90-93 is
The frequency of the class 94-97 is
This means that a total of
5.5
5
4.5
Your answers should be exact numerical values.
The frequency of the class 86-89 is
86
94
90
Duration of Dormancy (minutes)
dormancy periods were recorded.
The parameters that are needed to calculate a probability are listed as follows:
Number of desired outcomes in the context of a problem or experiment.Number of total outcomes in the context of a problem or experiment.Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes, hence it is the same as a relative frequency.
The total number of periods is given as follows:
5 + 6 + 4 = 15.
The frequency of each class is given as follows:
86 - 89: 5/15 = 1/3.90 - 93: 6/15 = 2/5.94 - 97: 4/15.Learn more about the concept of probability at https://brainly.com/question/24756209
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Please help me I don’t understand
If (x) = 5x - 7, what is (3)?
А. В
Ов, 1
Ос, 2
D. 22
Answer:
oc,2
Step-by-step explanation:
(__(_+)£)£(£886++17+£7+
Please explain your answer to this question! Thank you!
Answer:
B. Incorrectly applied the distributive property
Step-by-step explanation:
You want to find Maria's error in her solution of -2(3x -5) = 40.
StepsThe solution can proceed as follows:
-2(3x -5) = 40 . . . . . . . . given
-6x +10 = 40 . . . . . . . . . use the distributive property
-6x = 30 . . . . . . . . . . subtract 10
x = -5 . . . . . . . . . . divide by -6
Comparing this solution to Maria's, we find that Maria incorrectly applied the distributive property. (She multiplied (-2)(-5) and got -10 instead of +10.)
an item on sale costs 65% of the original price. The original price was $97. what is the sale price?
Answer:
The sale price of item is 63.05 dollars
Step-by-step explanation:
Given that the price of item is $97
Let P be the price
\(P = 97\)
It is also mentioned in the question that on sale the item costs 65% of the original price so we have to calculate 65% of the item's original price to find the sale price.
Mathematically,
\(Sale\ Price = 65\%\ of\ P\\= 0.65 * 97\\= 63.05\)
Hence,
The sale price of item is 63.05 dollars
Frederick, Josiah, and Shawnda each had 2 rolls of raffle tickets with 12 tickets in each roll.
Josiah hands out half of his tickets and Shawnda hands out one fourth of her tickets.
How many tickets do they have left altogether?
Answer:
they all have 52 left altogether
Step-by-step explanation:
they all have 2 rolls with 12 so that means they all have 24 if josiah hands out half of his tickets he would have 12 tickets left
If shawnda hands out 1 fourth of her tickets she will have 18 tickets
24 + 12 + 18 =54
In a time of t seconds, a particle moves a distance of s meters from its starting point, where s = 6t^2 + 4.
(a) Find the average velocity between t = 1 and t = 1 + k if (i) h = 0.1 (ii) h = 0.01 (iii) h = 0.001 Enter the exact answers.
(i) When h = 0.1, the average velocity between t = 1 and t = 1 + h is m/sec.
(ii) When h = 0.01, the average velocity between t = 1 and t = 1 + h is m/sec.
(iii) When h = 0.001, the average velocity between t = 1 and t = 1 + h is m/sec.
(b) Use your answers to part (a) to estimate the instantaneous velocity of the particle at time t = 1. Round your estimate to the nearest integer. The instantaneous velocity appears to be m/sec.
Answer:
(a)
i) \(V=12.6m/s\)
ii) \(V=12.06m/s\)
iii) \(V=12.006m/s\)
(b)
\(V = 10m/s\)
Step-by-step explanation:
Given
\(s = 6t^2 + 4\)
Solving (a): Average velocity between t = 1 and t = 1 + h
When t = 1
\(t_1 = 1\)
\(s_1 = 6t^2 + 4 = 6 * 1^2 + 4 = 6 + 4 =10\)
i) h = 0.1
When t = 1 + h
\(t_2 = 1 + 0.1 = 1.1\)
\(s_2= 6t^2 + 4 = 6 * (1.1)^2 + 4 = 11.26\)
Average velocity is then calculated as:
\(V = \frac{s_2 - s_1}{t_2 - t_1}\)
\(V = \frac{11.26 - 10}{1.1- 1} = \frac{1.26}{0.1} = 12.6\)
\(V=12.6m/s\)
ii) h = 0.01
When t = 1 + h
\(t_2 = 1 + 0.01 = 1.01\)
\(s_2= 6t^2 + 4 = 6 * (1.01)^2 + 4 = 10.1206\)
Average velocity is then calculated as:
\(V = \frac{s_2 - s_1}{t_2 - t_1}\)
\(V = \frac{10.1206 - 10}{1.01- 1} = \frac{0.1206}{0.01} = 12.06\)
\(V=12.06m/s\)
ii) h = 0.001
When t = 1 + h
\(t_2 = 1 + 0.001 = 1.001\)
\(s_2= 6t^2 + 4 = 6 * (1.001)^2 + 4 = 10.012006\)
Average velocity is then calculated as:
\(V = \frac{s_2 - s_1}{t_2 - t_1}\)
\(V = \frac{10.012006 - 10}{1.001- 1} = \frac{0.012006 }{0.001} = 12.006\)
\(V=12.006m/s\)
Solving (b): Instantaneous velocity at t = 1
When t = 1
\(t = 1\)
\(s = 6t^2 + 4 = 6 * 1^2 + 4 = 6 + 4 =10\)
Velocity is:
\(V = \frac{s}{t}\)
\(V = \frac{10}{1}\)
\(V = 10m/s\)
Solve (x+1)2 =13/4 using the square root property
Answer:
Starting with the equation:
(x + 1)^2 = 13/4
We can use the square root property, which states that if a^2 = b, then a is equal to the positive or negative square root of b.
Taking the square root of both sides, we get:
x + 1 = ±√(13/4)
Simplifying under the radical:
x + 1 = ±(√13)/2
Now we can solve for x by subtracting 1 from both sides:
x = -1 ± (√13)/2
Therefore, the solutions to the equation are:
x = -1 + (√13)/2 or x = -1 - (√13)/2
Step-by-step explanation:
If f(x)=x² – 4x, what is the value of 2f(a-1)?
The correct value of 2f(a-1) is 2a^2 - 12a + 10.
To find the value of 2f(a-1), we need to substitute (a-1) into the function f(x) and then multiply the result by 2.
Given: f(x) = x^2 - 4x
Substituting (a-1) into the function:
f(a-1) = (a-1)^2 - 4(a-1)
Expanding and simplifying:
f(a-1) = (a^2 - 2a + 1) - (4a - 4)
f(a-1) = a^2 - 2a + 1 - 4a + 4
f(a-1) = a^2 - 6a + 5
Now, we multiply the result by 2:
2f(a-1) = 2(a^2 - 6a + 5)
Expanding:
2f(a-1) = 2a^2 - 12a + 10
Therefore, the value of 2f(a-1) is 2a^2 - 12a + 10.
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Will give brainliest answer please help me
Lisa and Susan are driving to college together. They look at a map to find out how far they have to drive. On the map, Lisa measures the distance to be 4.5 inches. How many miles do they have to drive if the map scale is 1 in. = 35 mi?
Answer:157.5
Step-by-step explanation:becuase mutilpy 4.5x35 that equals 157.5
Graph the inequality on the number line.
3x−10>5
The solution of 3x−10>5 inequality is x>5 and is graphed with the image attached.
what is inequality?
Inequality is a declaration of an exact relation between two numerals or algebra expressions, such as greater at, above to, below than, or lesser than or equal to. Either questions or theorems can be used to express inequality problems, and both can be solved using methods similar to those used to solve equations.Given inequality,
3x−10>5
3x>5+10
3x>15
x> (15/3)
x>5
The solution of 3x−10>5 inequality is x>5 and is graphed with the image attached.
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3 Graph the function f (x) = x - 4 4. Use the line tool and select two points to graph. * Move Line Undo Redo X Reset у 10 9 8 7 6 5 4 3
The given function is
\(f(x)=\frac{3}{2}x-4\)To graph a linear equation we just need two points. Let's find the intercepts of the line.
Evaluate the function when x = 0.
\(f(0)=\frac{3}{2}(0)-4=-4\)The first point is (0,-4).
Evaluate the function when y = 0.
\(\begin{gathered} 0=\frac{3}{2}x-4 \\ 4=\frac{3}{2}x \\ x=\frac{4\cdot2}{3} \\ x=\frac{8}{3}=2.7 \end{gathered}\)The second point is 8/3 or 2.7.
Then, plot both points and draw a line through them.
A square-based, box-shaped shipping crate is designed to have a volume of 16 cubic ft. The material used to make the base costs twice as much (per square foot) as the material in the sides, and the material used to make the top costs half as much (per square foot) as the material in the sides. What are the dimensions of the crate that minimize the cost of materials
Answer:
Step-by-step explanation:
dimension
base=x, height =y, as they both are length so x, y >0
Volume of the crate= \(x^2y\) = \(16ft^3\)
cost
base=b unit money /\(ft^2\)
side material = b/2 unit money /\(ft^2\)
Top view= b/4 unit money /\(ft^2\)
Total Cost=\(bx^2 + \frac{b}{2} *4xy + \frac{b}{4} *x^2\) = \(2b( \frac{5}{8} *x^2 + xy)\)
function to be minimized = \(\frac{5}{8}*x^2 + xy\\\) , \(x^2y =16\)
put \(y=16/x^2\)
f(x) = \(\frac{5}{8}*x^2 + x*\frac{16}{x^2}\)
upon differentiating this equation
f'(x)=0
\(\frac{5}{4}*x -16x^-2 = 0\)
upon solving this we get \(x=4/\sqrt[3]{5}\) \(y= \sqrt[3]{25}\)
and further testing we get f"(\(\frac{4}{\sqrt[3]{5} }\)) >0 which proves that the point is local minimum.
Hence these are the dimensions of crate that minimizes the cost of material.
The dimensions that minimize the total cost of making the surface materials are \(2.3ft \text{ by } 2.3ft \text{ by }2.9ft\)
\(T=\text{Total cost of materials}\\m_b=\text{unit cost of materials used to construct the base}\\m_t=\text{unit cost of materials used to construct the top}\\m_s=\text{unit cost of materials used to construct the sides}\)
from the question, the crate has a square base and the volume is \(16ft^3\). So,
\(V=l^2h=16\\\implies h=\frac{16}{l^2}\)
Also,
\(m_b=2m_s\\m_t=\frac{m_s}{2}\)
Construct the formula for \(T\),
\(T=l^2\times m_b + l^2 \times m_t+4lh\times m_s\)
\(\text{where } l=\text{length of side of base/top}\\h=\text{height}\)
Eliminating \(h, m_b, \text{ and }m_t\), we have
\(T=m_s(\frac{5l^2}{2} + \frac{64}{l})\)
differentiating wrt \(l\) (\(m_s\) is a constant), we have
\(\frac{dT}{dl}=m_s(5l-\frac{64}{l^2})\)
The minimum total cost occurs when
\(m_s(5l-\frac{64}{l^2})=0\)
or, when
\(l=\frac{4}{\sqrt[3]{5}} \approx 2.3\)
(On carrying out the second derivative test, \(\frac{d^2T}{dl^2}>0\) when \(l=\frac{4}{\sqrt[3]{5}}\))
\(h=\frac{16}{l^2}=\sqrt[3]{5}^2\approx 2.9\)
Therefore, the dimensions that minimize the total cost of making the surface materials are \(2.3ft \text{ by } 2.3ft \text{ by }2.9ft\)
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3x - 1 = 5x + 10
I need help with the steps of the problem.
Answer:
x = -5.5 or -5 1/2
Step-by-step explanation:
3x = 5x + 11-2x = 112x = -11x = -11/2x = -5.5Damian works after school. Each
day he earns a set amount, plus
an hourly wage, as shown in the
table Write a linear function i
that Damian can use to determine
his pay.
Answer:
f(x) = 12x = 10
Step-by-step explanation:
We need a linear equation in the slope-intercept form.
y = mx + b
where y = total pay, m = hourly salary, x = number of hours worked, and b = y-intercept, or initial value
Let's look in the table.
1 hour: $22
2 hours: $34
The difference in pay between 1 hour and 2 hours is $34 - $22 = $12.
The difference in time between 1 hour and 2 hours is 1 hour.
In 1 hour he earns $12. That means the slope is 12.
We know he earns $22 for working a total of 1 hour.
Start at 1 hour and $22 on the table.
Subtract 1 hour from 1 hour to get 0 hours.
Subtract $12 form $22 to get $10.
That means for 0 hours he gets $10. b = 10
The equation is
y = 12x + 10
In function form, we have:
f(x) = 12x = 10
Here we want to find a linear relation with only using the data in a table, we will find that the line is:
\(y = 12\cdot x + 12\)
We know that Damian's earns a set amount plus an hourly wage, then this can be modeled with a linear equation:
\(y = a\cdot x + b\)
Where a is the slope, which in this case is the hourly wage, and b is the y-intercept, which in this case is the set amount.
Such that x is the number of hours and y is the pay.
We know that if the line passes through two points (x₁, y₁) and (x₂, y₂) the slope can be given as:
\(a = \frac{x_2 - x_1}{y_2 - y_1}\)
By looking at the table we can find two points of our line, for example, if we use the first and third points:
(1, 22) and (2, 34) then the slope will be:
\(a = \frac{34 - 22}{2 - 1} = 12\)
Then the line is something like:
\(y = 12\cdot x + b\)
To find the value of b, we can use one of the points, for example, the point (1, 22) means that when x = 1, we must have y = 22.
Replacing that in the above equation we have:
\(22 = 12\cdot1 + b\\\\22 = 12 + b\\\\22 - 12 = b = 12\)
Then the equation of the line is:
\(y = 12\cdot x + 12\)
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Given the cost function
C
(
x
)
=
0.85
x
+
51
,
230
and the revenue function
R
(
x
)
=
1.94
x
, find the break-even point.
Answer:
2.r=1.94
1. c=0.85x+51/x
Step-by-step explanation:
You want to create an orange color in order to paint the Oriole’s Bird. You have the colors yellow and red to make the orange paint. The recipe for Oriole’s orange paint is 1/2 cup yellow paint to 1/4 cup red paint. Using this ratio:
Part 1: How much yellow paint do you need to combine with one cup of red paint?
Part 2: How much red paint do you need to combine with one cup of yellow paint?
Each snap cube represents 1/4 cup of paint.
Answer:
Adult males are flame-orange and black, with a solid-black head and one white bar on their black wings. Females and immature males are yellow-orange on the breast, grayish on the head and back, with two bold white wing bars
which of the following graphs could describe the system of equations
a) blue
b)purple
c)green
d)pink
Answer:
It is purple
Step-by-step explanation:
Answer:
purple
because they interset each other
Step-by-step explanation:
Find a formula for the general term an of the geometric sequence:
{ 10/3, 10/9, 10/27, 10/81, 10/243}
Express the common ratio r as a fraction and place in parentheses!
an = __________
Answer: \(\displaystyle \frac{10}{3}\left(\frac{1}{3}\right)^{n-1}\)
======================================================
Explanation:
a = 10/3 is the first term
r = 1/3 is the common ratio
Multiply each term by r = 1/3 to get the next term.
Example:
(10/3)*(1/3) = 10/9
We then plug those two items into the formula
\(a_n = a(r)^{n-1}\)
to end up with the answer shown above.
The value of n is a positive integer.
Find the perioa
equation.
llowing
y = 2 cos(5x + 3) - 6
77
Period = [2]T
Give your answer in simplest form.
Answer:
In the equation y = 2 cos(5x + 3) - 6, we can ignore the coefficients 2 and -6 for the purposes of calculating the period because they do not change the period. They only change the amplitude (2) and vertical shift (-6) of the function.
The coefficient 5 in front of x inside the cosine function affects the period of the function. It is a horizontal compression/stretch of the graph of the function.
The period of the basic cosine function, y = cos(x), is 2π. When there is a coefficient (let's call it b) in front of x, such as y = cos(bx), the period becomes 2π/b.
So, in your case, b = 5, so the period T of the function y = 2 cos(5x + 3) - 6 is:
T = 2π / 5
This is the simplest form for the period of the given function.
Find the equation of a line parallel to y=x−1 that contains the point (−3,−2). Write the equation in slope-intercept form.
Answer:
y = x + 1
Step-by-step explanation:
Parallel lines have same slope.
y = x - 1
Compare with the equation of line in slope y-intercept form: y = mx +b
Here, m is the slope and b is the y-intercept.
m =1
Now, the equation is,
y = x + b
The required line passes through (-3 ,-2). Substitute in the above equation and find y-intercept,
-2 = -3 + b
-2 + 3 = b
\(\boxed{b= 1}\)
Equation of line in slope-intercept form:
\(\boxed{\bf y = x + 1}\)
The equation is :
↬ y = x + 1Solution:
We KnowIf two lines are parallel to each other, then their slopes are equal. The slope of y = x - 1 is 1. Hence, the slope of the line that is parallel to that line is 1.
We shouldn't forget about a point on the line : (-3, -2).
I plug that into a point-slope which is :
\(\sf{y-y_1=m(x-x_1)}\)
Slope is 1 so
\(\sf{y-y_1=1(x-x_1)}\)
Simplify
\(\sf{y-y_1=x-x_1}\)
Now I plug in the other numbers.
-3 and -2 are x and y, respectively.
\(\sf{y-(-2)=x-(-3)}\)
Simplify
\(\sf{y+2=x+3}\)
We're almost there, the objective is to have an equation in y = mx + b form.
So now I subtract 2 from each side
\(\sf{y=x+1}\)
Hence, the equation is y = x + 1Help pls I hacer 5 mins
Answer:
12.7 is the answer
Answer: 12.7
Step-by-step explanation:
If you like to round 12.654 to the nearest tenth, leaving only one number after the decimal point, then you have come to the right post
The local garden store sells bags of mulch for $4.98 each and will deliver the bags for a fee of $15 if Amber purchases 15 bags and has them delivered what is the total amount that Amber will pay?
Answer:
$89.70
Step-by-step explanation:
To solve this equation, let's formulate a linear equation.
Let \(b\) equal bags of mulch.
Let \(t\) equal the total amount.
We know the price of each bag of mulch ($4.98), so we can represent this as:
\(4.98b\)
We also know that there's a fee of $15, so we can just represent this as:
\(15\)
Let's put these values into an equation:
\(t=4.98b+15\)
Now with an equation, we know that she purchases a total of 15 bags, so let's substitute \(15\) for \(b\):
\(t=4.98(15)+15\)
Multiply:
\(t=74.70+15\)
Add:
\(t=89.70\)
_
Check your work by substituting the total amount into the initial equation:
\(89.70=4.98b+15\)
Subtract \(15\) from both sides of the equation:
\(74.70=4.98b\)
Divide both sides of the equation by the coefficient of \(b\), which is \(4.98\):
\(15=b\)
Amber did in fact purchase 15 bags, so we know our total amount is correct!
Can you explain to me how did we get the answer
The end behavior of the polynomials are as follows;
(a) y = x³ - 9·x² + 8·x - 14
End behavior; y → ∞ as x → ∞
\({}\) y → -∞ as x → -∞
(b) y = -8·x⁴ + 13·x + 800
End behavior; y → -∞ as x → -∞
\({}\) y → -∞ as x → ∞
What is the end behavior of a a polynomial?The end behavior of a polynomial is the characteristics of the graph of the polynomial as the input (x-values), tends to plus and minus infinity.
The factors that effect the end behavior of a polynomial are;
The degree of the polynomial, (even or odd)
The sign of the leading coefficient of the polynomial (positive or negative)
The leading coefficient is the coefficient of the term with the highest degree.
(a) The polynomial, function, y = x³ - 9·x² + 8·x - 14
The specified polynomial is a third degree polynomial, with a positive leading coefficient of 1, the end behavior is therefore;
y tends to positive infinity as x tends to positive infinity
y tends to negative infinity as x tends to negative infinity
End behavior;
y → ∞ as x → ∞
y → -∞ as x → -∞
(b) The polynomial function can be expressed as follows;
y = -8·x⁴ + 13·x + 800
The above polynomial of degree 4 is an even degree polynomial
The leading coefficient of the polynomial is -8, therefore, the leading coefficient is negative
The shape of the graph of the polynomial is therefore ∩ shaped, such that the end behavior is as follows;
y-values approaches negative infinity as x approaches negative infinity
y-values approaches negative infinity as x approaches positive infinity
End behavior;
y → -∞ as x → -∞
y → -∞ as x → ∞
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